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• How to prevent ssh git push to set file ownership?

  - by e-satis

  I have a remote bare git repository on an Ubuntu server, where the file are owned by the user my_project and the group my_project, with permissions set accordingly. All commiters are themself in the group my_project. When somebody commit then push from my Ubuntu laptop with the user my_user to the server via SSH, some files in the remote repository are created (updated?) so they now belong to the user and group my_user. Of course, when somebody else want to commit, he is now unable to do so because he doesn't have write permissions. I could set permission to 777 but it's not the best option. Is there any way I can solve this problem while keeping restricted write permissions.

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• How Ubuntu cloud version enforces the "no root login" over ssh ?

  - by Maxim Veksler

  Hello, I'm looking to tweak ubuntu cloud version default setup where is denies root login. Attempting to connect to such machine yields: maxim@maxim-desktop:~/workspace/integration/deployengine$ ssh [email protected] The authenticity of host 'ec2-204-236-252-95.compute-1.amazonaws.com (204.236.252.95)' can't be established. RSA key fingerprint is 3f:96:f4:b3:b9:4b:4f:21:5f:00:38:2a:bb:41:19:1a. Are you sure you want to continue connecting (yes/no)? yes Warning: Permanently added 'ec2-204-236-252-95.compute-1.amazonaws.com' (RSA) to the list of known hosts. Please login as the ubuntu user rather than root user. Connection to ec2-204-236-252-95.compute-1.amazonaws.com closed. I would like to know where this is setup and how I can change the printed message? Thank you, Maxim.

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• Why do I get "Permission denied (publickey)" when trying to SSH from local Ubuntu to a Amazon EC2 se

  - by Vorleak Chy

  I have an instance of an application running in the cloud on Amazon EC2 instance, and I need to connect it from my local Ubuntu. It works fine on one of local ubuntu and also laptop. I got message "Permission denied (publickey)" when trying to access SSH to EC2 on another local Ubuntu. It's so strange to me. I'm thinking some sort of problems with security settings on the Amazon EC2 which has limited IPs access to one instance or certificate may need to regenerate. Does anyone know a solution?

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• How to port forward https traffic via ssh and/or remote desktop to through several networks and PCs?

  - by donttellya

  I have the following environment: In company X I develop a application on a pc A in network A with ip address 192.168.100.50 which has to do an https request to an http server located in the intranet of company Y In company X is another pc B in network B with ip address 192.168.200.100 pc B (of company X) can access the intranet from company Y via ssh tunnel (putty) pc A (of company X) can ping pc B (of company X) note: pc A can also do a remote desktop connection to pc B) pc B can ping the http sever pc A can not ping the http server How can the https request from pc A of company X get to the http server of company Y? On which pc must be putty configured? And which settings for host, port forwarding etc. has to be done in putty? So finally the https request should go from PC A - PC B - Http Server in company Y.

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• Is it possible to have zsh+keychain+tmux not ask for keys?

  - by Wayne Werner

  I'm using tmux and zsh, and I've recently been learning about ssh-agent and keychain. From the manpage for zsh, it says that it will source .zlogin only if the shell is, well, a login shell. Following advice I read, I stuck keychain --clear in my .zlogin, which worked perfectly. When I logged into the box I had to unlock my key. However, each time I create a new window in tmux, it clears/makes me re-add my key. This is a little annoying... but I can understand it if, in fact, each new tmux window is a login window. I haven't been able to find much help outside of the manpages on this topic. So is each new tmux window a login shell, or is there any way that I can make it not clear my keys only when I create a tmux window?

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• The cd command using variable to mapped NFS volume within ssh in linux script is not working

  - by Bhavya Maheshwari

  I have to do the following from within a bash script. The /VMNFS/ folder is present on linux box, from where script is run, and is mapped to the machine into which i am ssh'ing, as an NFS at /vmfs/volumes/VMNFS/. The second cd command doesn't work, neither with symbolic path name nor physical pathname. Why? and How to rectify this? #!/bin/bash ssh -2 [email protected] /bin/sh <<\EOF vmfile_path=`grep / vmvar_file` datastore_path=/vmfs/volumes/VMNFS/ cd $datastore_path && echo "The present working directory is" `pwd -P` esxi_vmfile_path_sub=`pwd -P` && echo "variable value is" $esxi_vmfile_path_sub esxi_vmfile_path=`echo $vmfile_path | sed "s:/VMNFS:$esxi_vmfile_path_sub:"` cd "$esxi_vmfile_path" EOF ***Output***: The current working directory is /vmfs/volumes/65335ec4-46d12e41 variable value is /vmfs/volumes/65335ec4-46d12e41 can't cd to /vmfs/volumes/65335ec4-46d12e41/TPAE7.5/

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• How can I remove the ssh last login info?

  - by Gnijuohz

  Whenever I log into a server using ssh. The prompt gives me "last login" information. I was wondering where this information comes from. How can I remove this record so when someone else log into the same server, the person would see my login info with my ip in it? So how can I do this? For the record, I am not hacking someone's computer and the server runs Ubuntu 12.04. EDIT: which file logs this kind of information? If I find the file, then I can do anything to it as root. Thanks.

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• SSH from Windows hangs when using insert mode in vim on Dreamhost: Why?

  - by cletus

  I have SSH set up using Cygwin on Windows XP SP3 to Dreamhost. It works fine except that when I edit a file with vi and use insert mode (eg press 'i' and type in some stuff). I then try and hit escape and ZZ to save/exit and it hangs instead. My edits aren't saved and I have to kill the session (locally) and kill the vi process on Dreamhost. This is highly annoying. It's not reliable either. Sometimes it does work. Also, this happens with PuTTY too.

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• Is it possible to connect these machines with ssh tunnels or another mechanism?

  - by frankc

  I am physically on a machine that is behind a firewall and cannot be ssh'd into. Let's call that PC. PC can connect out to two machines, one on AWS and one that is part of a vpn connection, call them A and V, respectively. A and V cannot talk to each other directly. I need to frequently move files between A and V and have been doing this by scp'ing to PC and then scp'ing from pc. Is there a better way to do this? A and V are linux but PC has cygwin.

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• Get name (address) of computer from which from which SSH login was made.

  - by amicitas

  After logging onto a linux machine via SSH, I would like to be able to retrieve the name of the computer from which the connection was made. Ideally I am looking for some command like hostname or uname but that would retrieve the name of the client instead of the host. This information must be accessible somewhere, since when I log on I get a message that contains the clinent name from the last login: Last login: Thu Mar 11 18:42:01 2010 from my.address.com The reason for wanting to do this is to be able to take different action in my .login file depending on which computer I am using for connection is from.

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• Started an application through SSH, command line now gone, what happens next?

  - by Chris Dutrow

  Context: This is a very basic question Using Putty and SSH for the first time to do some serious server setup and run into the situation where I have started a process that I do not want to stop. The process is the gunicorn WSGI HTTP Server (running on Centos 6.3). The command I used to start the process is (as per their Quick Start): gunicorn -w 4 myapp:app At this point in the work session, I have lost the command prompt. This must be such a non-issue that it doesn't even enter into an experienced user's consciousness. But unfortunately at my level of experience, I am left with several fundamental questions: Does the fact that I have lost the command prompt mean that the process is still running? How do I get back to the command prompt without killing the process? How do I come back and monitor the process later? How do I eventually kill the process? Any help is appreciated, thanks so much!

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• Can I store multiple private keys in one Putty PPK file?

  - by RedGrittyBrick

  I have multiple accounts on a server, say for example red webadmin testuser At the moment I have private keys for these in separate PPK files. I have shortcuts to these on the desktop - so clicking the desktop icon launches Pageant and prompts for a password. After doing this for each PPK file, I can log in and out of the server(s) multiple times during the day using various user-ids without entering passwords. So far so good. Could I streamline this further by somehow combining all these PPK files into a single PPK file? If so how?

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• how to know which display number for the variable DISPLAY to be exported when ssh to server

  - by insidepower

  When i ssh to server using -X, i always confuse about which display number i should export. It seems to me sometimes the display number has been used by something, so what i can do is only export DISPLAY=localhost:0 && xclock export DISPLAY=localhost:1 && xclock export DISPLAY=localhost:2 && xclock export DISPLAY=localhost:... until the clock appear. Then i will use that display number. Each time log in to the server, the display number which is able to tunnel the gui data correct would be different. I know many of such similar questions has been asked and answer. However I couldn't find answer to my question, anyone know about it? Thanks!

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• accessing external mysql server through "ssh tunnel" - any drawbacks?

  - by Max

  In an upcoming project I have a two server setup: one is the application server and another, already existing runs the mysql server with databases I need to access. I contacted the server admin of the mysql server and the only way I can access the remote mysql databases is via "SSH tunnel". I have never done this before and never heard of it so far, so my question, are there any drawbacks, e. g. performance wise? Isnt it rather slow compared to directly accessing the mysql server on its default port?

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• Is it possible to log a user in a remote computer using ssh?

  - by El_Hoy

  I want to connect to a server via ssh and log in (remotely) a user in X11 (gdm). A little context: I need to install a wine application in 30 computers, but wine require X11, there is nobody loged there, so wine does not work properly. I want to remotely login in display=:0.0 a user so this user receive the window (it only start and close), there i need to ()neThere is no one logged on there. I need to start a graphical app there (wine installer) but I cannot because it needs a display with X11 (to open a wineconsole). Resumen: Is it posible to log a user remotely on X11

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• Multiple foreign keys in one table to 1 other table in mysql

  - by djerry

  Hey guys, I got 2 tables in my database: user and call. User exists of 3 fields: id, name, number and call : id, 'source', 'destination', 'referred', date. I need to monitor calls in my app. The 3 ' ' fields above are actually userid numbers. now i'm wondering, can i make those 3 field foreign key elements of the id-field in table user? Thanks in advance...

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• Sqlite / SQLAlchemy: how to enforce Foreign Keys?

  - by Nick Perkins

  The new version of SQLite has the ability to enforce Foreign Key constraints, but for the sake of backwards-compatibility, you have to turn it on for each database connection separately! sqlite> PRAGMA foreign_keys = ON; I am using SQLAlchemy -- how can I make sure this always gets turned on? What I have tried is this: engine = sqlalchemy.create_engine('sqlite:///:memory:', echo=True) engine.execute('pragma foreign_keys=on') ...but it is not working!...What am I missing?

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• sql foreign keys

  - by Paul Est

  I was create tables with the syntax in phpmyadmin: DROP TABLE IF EXISTS users; DROP TABLE IF EXISTS info; CREATE TABLE users ( user_id int unsigned NOT NULL auto_increment, email varchar(100) NOT NULL default '', pwd varchar(32) NOT NULL default '', isAdmin int(1) unsigned NOT NULL, PRIMARY KEY (user_id) ) TYPE=INNODB; CREATE TABLE info ( info_id int unsigned NOT NULL auto_increment, first_name varchar(100) NOT NULL default '', last_name varchar(100) NOT NULL default '', address varchar(300) NOT NULL default '', zipcode varchar(100) NOT NULL default '', personal_phone varchar(100) NOT NULL default '', mobilephone varchar(100) NOT NULL default '', faxe varchar(100) NOT NULL default '', email2 varchar(100) NOT NULL default '', country varchar(100) NOT NULL default '', sex varchar(1) NOT NULL default '', birth varchar(1) NOT NULL default '', email varchar(100) NOT NULL default '', PRIMARY KEY (info_id), FOREIGN KEY (email) REFERENCES users(email) ON UPDATE CASCADE ON DELETE CASCADE ) TYPE=INNODB; But shows the error "#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'TYPE=INNODB' at line 11 " If i remove the TYPE=INNODB in the end of create the tables, it will show the error "#1005 - Can't create table 'curriculo.info' (errno: 150) ".

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• Problems getting foreign keys working in MySQL

  - by thehuby

  I've been trying to get a delete to cascade and it just doesn't seem to work. I'm sure I am missing something obvious, can anyone help me find it? I would expect a delete on the 'articles' table to trigger a delete on the corresponding rows in the 'article_section_lt' table. CREATE TABLE articles ( id INTEGER UNSIGNED PRIMARY KEY AUTO_INCREMENT, url_stub VARCHAR(255) NOT NULL UNIQUE, h1 VARCHAR(60) NOT NULL UNIQUE, title VARCHAR(60) NOT NULL, description VARCHAR(150) NOT NULL, summary VARCHAR(150) NOT NULL DEFAULT "", html_content TEXT, date DATE NOT NULL, updated TIMESTAMP DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP )ENGINE=INNODB; CREATE TABLE article_sections ( /* blog, news etc */ id INTEGER UNSIGNED PRIMARY KEY AUTO_INCREMENT, url_stub VARCHAR(255) NOT NULL UNIQUE, h1 VARCHAR(60) NOT NULL, title VARCHAR(60) NOT NULL, description VARCHAR(150) NOT NULL, summary VARCHAR(150) NOT NULL DEFAULT "", html_content TEXT NOT NULL DEFAULT "" )ENGINE=INNODB; CREATE TABLE article_section_lt ( fk_article_id INTEGER UNSIGNED NOT NULL REFERENCES articles(id) ON DELETE CASCADE, fk_article_section_id INTEGER UNSIGNED NOT NULL )ENGINE=INNODB;

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• SQL - Two foreign keys that have a dependency between them

  - by Brian

  The current structure is as follows: Table RowType: RowTypeID Table RowSubType: RowSubTypeID FK_RowTypeID Table ColumnDef: FK_RowTypeID FK_RowSubTypeID (nullable) In short, I'm mapping column definitions to rows. In some cases, those rows have subtype(s), which will have column definitions specific to them. Alternatively, I could hang those column definitions that are specific to subtypes off their own table, or I could combine the data in RowType and RowSubType into one table and work with a single ID, but I'm not sure either is a better solution (if anything, I'd lean towards the latter, as we mostly end up pulling ColumnDefs for a given RowType/RowSubType). Is the current design SQL Blasphemy? If I keep the current structuree, how do I maintain that if RowSubTypeID is specified in ColumnDef, that it must correspond to the RowType specified by RowTypeID? Should I try to enforce this with a trigger or am I missing a simple redesign that would solve the problem?

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• How to make the arrows keys act as another keys ? C#

  - by le.shep20

  Hi. How to make the left arrow act like . (dot), when a user press the left arrow in a textbox it will type . and also in the same way how to make the right arrow act like - ( dash) And I want to use the Contol key to switch between 2 modes: . and dash, regular arrows behavior, mean when a user press Control the tow arrows will act as . and dash. And when a user press agian the control the 2 arrows will act as usual arrows. Thanks,

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• Creating Two Cascading Foreign Keys Against Same Target Table/Col

  - by alram

  I have the following tables: user (userid int [pk], name varchar(50)) action (actionid int [pk], description nvarchar(50)) being referenced by another table that captures the relationship: <user1> <action>'s <user2>. I did this with the following table: userAction (userActionId int [pk], actionid int [fk: action.actionid], **userId1 int [fk ref's user.userid; on del/update cascade], userId2 int [fk ref's user.userid; on del/update cascade]**). However, when I try to save the userAction table i get an error because I have two cascading fk's against user.userid. Is there any way to remedy this or must I use a trigger?

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• How to make the arrows keys act as another keys ?

  - by le.shep20

  How to make the left arrow act like . (dot), when a user press the left arrow in a textbox it will type . and also in the same way how to make the right arrow act like - ( dash) And I want to use the Control key to switch between 2 modes: . and dash, regular arrows behavior, mean when a user press Control the tow arrows will act as . and dash. And when a user press agian the control the 2 arrows will act as usual arrows.

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• How to get array keys in Javascript?

  - by DisgruntledGoat

  I have an array created with this code: var widthRange = new Array(); widthRange[46] = { sel:46, min:0, max:52 }; widthRange[66] = { sel:66, min:52, max:70 }; widthRange[90] = { sel:90, min:70, max:94 }; I want to get each of the values 46, 66, 90 in a loop. I tried for (var key in widthRange) but this gives me a whole bunch of extra properties (I assume they are functions on the object). I can't use a regular for loop since the values are not sequential.

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• PHP find array keys

  - by Jens Törnell

  In PHP I have an array that looks like this: $array[0]['width'] = '100'; $array[0]['height'] = '200'; $array[2]['width'] = '150'; $array[2]['height'] = '250'; I don't know how many items there are in the array. Some items can be deleted which explains the missing [1] key. I want to add a new item after this, like this: $array[]['width'] = '300'; $array[]['height'] = '500'; However the code above don't work, because it adds a new key for each row. It should be the same for the two rows above. A clever way to solve it? An alternative solution would be to find the last key. I failed trying the 'end' function.

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