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  • Problems with this stack implementation

    - by Andersson Melo
    where is the mistake? My code here: typedef struct _box { char *dados; struct _box * proximo; } Box; typedef struct _pilha { Box * topo; }Stack; void Push(Stack *p, char * algo) { Box *caixa; if (!p) { exit(1); } caixa = (Box *) calloc(1, sizeof(Box)); caixa->dados = algo; caixa->proximo = p->topo; p->topo = caixa; } char * Pop(Stack *p) { Box *novo_topo; char * dados; if (!p) { exit(1); } if (p->topo==NULL) return NULL; novo_topo = p->topo->proximo; dados = p->topo->dados; free(p->topo); p->topo = novo_topo; return dados; } void StackDestroy(Stack *p) { char * c; if (!p) { exit(1); } c = NULL; while ((c = Pop(p)) != NULL) { free(c); } free(p); } int main() { int conjunto = 1; char p[30]; int flag = 0; Stack *pilha = (Stack *) calloc(1, sizeof(Stack)); FILE* arquivoIN = fopen("L1Q3.in","r"); FILE* arquivoOUT = fopen("L1Q3.out","w"); if (arquivoIN == NULL) { printf("Erro na leitura do arquivo!\n\n"); exit(1); } fprintf(arquivoOUT,"Conjunto #%d\n",conjunto); while (fscanf(arquivoIN,"%s", p) != EOF ) { if (pilha->topo == NULL && flag != 0) { conjunto++; fprintf(arquivoOUT,"\nConjunto #%d\n",conjunto); } if(strcmp(p, "return") != 0) { Push(pilha, p); } else { p = Pop(pilha); if(p != NULL) { fprintf(arquivoOUT, "%s\n", p); } } flag = 1; } StackDestroy(pilha); return 0; } The Pop function returns the string value read from file. But is not correct and i don't know why.

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  • 2d array, using calloc in C

    - by BigBirdy
    Hi, I'm trying to create a 2D array of chars to storage lines of chars. For Example: lines[0]="Hello"; lines[1]="Your Back"; lines[2]="Bye"; Since lines has to be dynamically cause i don't know how many lines i need at first. Here is the code i have: int i; char **lines= (char**) calloc(size, sizeof(char*)); for ( i = 0; i < size; i++ ){ lines[i] = (char*) calloc(200, sizeof(char)); } for ( i = 0; i < size; i++ ){ free(lines[i]); } free(lines); I know that each line can't go over 200 chars. I keep getting errors like "error C2059: syntax error : 'for'" and such. Any ideas of what i did wrong?

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  • QT- QImage and multi-threading problem.

    - by umanga
    Greetings all, Please refer to image at : http://i48.tinypic.com/316qb78.jpg We are developing an application to extract cell edges from MRC images from electron microscope. MRC file format stores volumetric pixel data (http://en.wikipedia.org/wiki/Voxel) and we simply use 3D char array(char***) to load and store data (gray scale values) from a MRC file. As shown in the image,there are 3 viewers to display XY,YZ and ZX planes respectively. Scrollbars on the top of the viewers use to change the image slice along an axis. Here is the steps we do when user changes the scrollbar position. 1) get the new scrollbar value.(this is the selected slice) 2) for the relavant plane (YZ,XY or ZX), generate (char* slice;) array for the selected slice by reading 3D char array (char***) 3) Create a new QImage* (Format_RGB888) and set pixel values by reading 'slice' (using img-setPixel(x,y,c);) 4) This new QImage* is painted in the paintEvent() method. We are going to execute "edge-detection" process in a seperate thread since it is an intensive process.During this process we need to draw detected curve (set of pixels) on top of above QImage*.(as a layer).This means we need to call drawPoint() methods outside the QT thread. Is it the best wayto use QImage for this case? What is the best way to execute QT drawing methods from another thread? thanks in advance,

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  • Sax Parser Character Array to Integer??

    - by Andy Barlow
    Hello, I am trying to get the contents of tags into variables in my java Sax parser. However, the Characters method only returns Char arrays. Is there anyway to get the Char array into an Int??? public void characters(char ch[], int start, int length) { if(this.in_total_results) { // my INT varialble would be nice here! } } Can anyone help at all? Kind regards, Andy

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  • Overloading *(iterator + n) and *(n + iterator) in a C++ iterator class?

    - by exscape
    (Note: I'm writing this project for learning only; comments about it being redundant are... uh, redundant. ;) I'm trying to implement a random access iterator, but I've found very little literature on the subject, so I'm going by trial and error combined with Wikpedias list of operator overload prototypes. It's worked well enough so far, but I've hit a snag. Code such as exscape::string::iterator i = string_instance.begin(); std::cout << *i << std::endl; works, and prints the first character of the string. However, *(i + 1) doesn't work, and neither does *(1 + i). My full implementation would obviously be a bit too much, but here's the gist of it: namespace exscape { class string { friend class iterator; ... public: class iterator : public std::iterator<std::random_access_iterator_tag, char> { ... char &operator*(void) { return *p; // After some bounds checking } char *operator->(void) { return p; } char &operator[](const int offset) { return *(p + offset); // After some bounds checking } iterator &operator+=(const int offset) { p += offset; return *this; } const iterator operator+(const int offset) { iterator out (*this); out += offset; return out; } }; }; } int main() { exscape::string s = "ABCDEF"; exscape::string::iterator i = s.begin(); std::cout << *(i + 2) << std::endl; } The above fails with (line 632 is, of course, the *(i + 2) line): string.cpp: In function ‘int main()’: string.cpp:632: error: no match for ‘operator*’ in ‘*exscape::string::iterator::operator+(int)(2)’ string.cpp:105: note: candidates are: char& exscape::string::iterator::operator*() *(2 + i) fails with: string.cpp: In function ‘int main()’: string.cpp:632: error: no match for ‘operator+’ in ‘2 + i’ string.cpp:434: note: candidates are: exscape::string exscape::operator+(const char*, const exscape::string&) My guess is that I need to do some more overloading, but I'm not sure what operator I'm missing.

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  • Concat wchar_t Unicode strings in C?

    - by Doori Bar
    I'm a beginner, I play with FindFirstFileW() of the winapi - C. The unicoded path is: " \\?\c:\Français\", and I would like to concat "*" to this path of type wchar_t (then I will use it as an arg for FindFirstFileW()). I made two test cases of mine, the first is ansi_string() which seem to work fine, the second is unicode_string() - which I don't quite understand how should I concat the additional "*" char to the unicoded path. I write the strings to a file, because I'm not able to print Unicoded characters to stdout. Note: my goal is to learn, which means I'll appreciate guidance and references to the appropriate resources regards my scenario, I'm very much a beginner and this is my first attempt with Unicode. Thanks, Doori Bar #include <stdio.h> #include <stdlib.h> #include <wchar.h> #include <string.h> #include <errno.h> void *error_malloc(int size); void ansi_string(char **str1, char **str2); void unicode_string(wchar_t **wstr1, wchar_t **wstr2); void unicode_string(wchar_t **wstr1, wchar_t **wstr2) { /* assign wstr1 with the path: \\?\c:\Français\ */ *wstr1 = error_malloc((wcslen(L"\\\\?\\c:\\Français\\")+1) *sizeof(**wstr1)); wcscpy(*wstr1,L"\\\\?\\c:\\Français\\"); /* concat wstr1+"*" , assign wstr2 with: \\?\c:\Français\* */ *wstr2 = error_malloc((wcslen(*wstr1) + 1 + 1) * sizeof(**wstr1)); /* swprintf(*wstr2,"%ls*",*wstr1); */ /* how should I concat wstr1+"*"? */ wcscpy(*wstr2,L"\\\\?\\c:\\Français\\"); } void ansi_string(char **str1, char **str2) { /* assign str1 with the path: c:\English\ */ *str1 = error_malloc(strlen("c:\\English\\") + 1); strcpy(*str1,"c:\\English\\"); /* concat str1+"*" , assign str2 with: c:\English\* */ *str2 = error_malloc(strlen(*str1) + 1 + 1); sprintf(*str2,"%s*",*str1); } void *error_malloc(int size) { void *ptr; int errornumber; if ((ptr = malloc(size)) == NULL) { errornumber = errno; fprintf(stderr,"Error: malloc(): %d; Error Message: %s;\n", errornumber,strerror(errornumber)); exit(1); } return ptr; } int main(void) { FILE *outfile; char *str1; char *str2; wchar_t *wstr1; wchar_t *wstr2; if ((outfile = fopen("out.bin","w")) == NULL) { printf("Error: fopen failed."); return 1; } ansi_string(&str1,&str2); fwrite(str2, sizeof(*str2), strlen(str2), outfile); printf("strlen: %d\n",strlen(str2)); printf("sizeof: %d\n",sizeof(*str2)); free(str1); free(str2); unicode_string(&wstr1,&wstr2); fwrite(wstr2, sizeof(*wstr2), wcslen(wstr2), outfile); printf("wcslen: %d\n",wcslen(wstr2)); printf("sizeof: %d\n",sizeof(*wstr2)); free(wstr1); free(wstr2); fclose(outfile); return 0; }

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  • Wingding chars in sql server 2005

    - by Savvas Sopiadis
    Hi everybody! In a winforms application i 'm storing one Wingdings char in a SQL Server 2005 field of type NVARCHAR(1). Storing, retrieving and showing up this char in a control works fine. The problem i'm facing is this: how to search for records which have a specific wingding char value: for example Select * from table where FieldWithWingding = valueOfLeftArrowChar How to achieve this? Thanks in advance

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  • c - strncpy issue

    - by Joe
    Hi there, I am getting segmentation fault when using strncpy and (pointer-to-struct)-(member) notation: I have simplified my code. I initialise a struct and set all of it's tokens to an empty string. Then a declare a pointer to a struct and assign the address of the struct to it. I pass the pointer to a function. I can print out the contents of the struct at the beginning of the function, but if I try to use the tp - mnemonic in a strncpy function, I get seg fault. Can anyone tell me what I am doing wrong? typedef struct tok { char* label; char* mnem; char* operand; }Tokens; Tokens* tokenise(Tokens* tp, char* line) { // This prints fine printf("Print this - %s\n", tp -> mnem); // This function gives me segmentation fault strncpy(tp -> mnem, line, 4); return tp; } int main() { char* line = "This is a line"; Tokens tokens; tokens.label = ""; tokens.mnem = "load"; tokens.operand = ""; Tokens* tp = &tokens; tp = tokenise(tp, line); return 0; } I have used printf statements to confirm that the code definitely stops executing at the strncpy function. Can anyone tell me where I am going wrong? Many thanks Joe

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  • Insert date to database

    - by simon
    I'm trying to insert the current date to the database and i allways get the massage(when i pres the button on the form to save to my access database), that the data type is incorect in the conditional expression. the code: string conString = "Provider=Microsoft.Jet.OLEDB.4.0;" + "Data Source=C:\Users\Simon\Desktop\save.mdb"; OleDbConnection empConnection = new OleDbConnection(conString); string insertStatement = "INSERT INTO obroki_save " + "([ID_uporabnika],[datum],[ID_zivila],[skupaj_kalorij]) " + "VALUES (@ID_uporabnika,@datum,@ID_zivila,@skupaj_kalorij)"; OleDbCommand insertCommand = new OleDbCommand(insertStatement, empConnection); insertCommand.Parameters.Add("@ID_uporabnika", OleDbType.Char).Value = users.iDTextBox.Text; insertCommand.Parameters.Add("@datum", OleDbType.Char).Value = DateTime.Now; insertCommand.Parameters.Add("@ID_zivila", OleDbType.Char).Value = iDTextBox.Text; insertCommand.Parameters.Add("@skupaj_kalorij", OleDbType.Char).Value = textBox1.Text; empConnection.Open(); try { int count = insertCommand.ExecuteNonQuery(); } catch (OleDbException ex) { MessageBox.Show(ex.Message); } finally { empConnection.Close(); textBox1.Clear(); textBox2.Clear(); textBox3.Clear(); textBox4.Clear(); textBox5.Clear(); } i tried to change the oleDbType.char to oleDbType.Dbdate and others but it doesnt work. I can save other stuff with that code but im stuck here when i wan't to save the date. Please help !

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  • image scaling with C

    - by sa125
    Hi - I'm trying to read an image file and scale it by multiplying each byte by a scale its pixel levels by some absolute factor. I'm not sure I'm doing it right, though - void scale_file(char *infile, char *outfile, float scale) { // open files for reading FILE *infile_p = fopen(infile, 'r'); FILE *outfile_p = fopen(outfile, 'w'); // init data holders char *data; char *scaled_data; // read each byte, scale and write back while ( fread(&data, 1, 1, infile_p) != EOF ) { *scaled_data = (*data) * scale; fwrite(&scaled_data, 1, 1, outfile); } // close files fclose(infile_p); fclose(outfile_p); } What gets me is how to do each byte multiplication (scale is 0-1.0 float) - I'm pretty sure I'm either reading it wrong or missing something big. Also, data is assumed to be unsigned (0-255). Please don't judge my poor code :) thanks

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  • How do you dynamically allocate a contiguous 3D array in C?

    - by Derek
    In C, I want to loop through an array in this order for(int z = 0; z < NZ; z++) for(int x = 0; x < NX; x++) for(int y = 0; y < NY; y++) 3Darray[x][y][z] = 100; How do I create this array in such a way that 3Darray[0][1][0] comes right before 3Darray[0][2][0] in memory? I can get an initialization to work that gives me "z-major" ordering, but I really want a y-major ordering for this 3d array This is the code I have been trying to use: char *space; char ***Arr3D; int y, z; ptrdiff_t diff; space = malloc(X_DIM * Y_DIM * Z_DIM * sizeof(char)) Arr3D = malloc(Z_DIM * sizeof(char **)); for (z = 0; z < Z_DIM; z++) { Arr3D[z] = malloc(Y_DIM * sizeof(char *)); for (y = 0; y < Y_DIM; y++) { Arr3D[z][y] = space + (z*(X_DIM * Y_DIM) + y*X_DIM); } }

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  • Is this a memory leak?

    - by Ben
    char *pointer1; char *pointer2; pointer1 = new char[256]; pointer2 = pointer1; delete [] pointer1; In other words, do I have to do delete [] pointer2 as well? Thanks!

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  • C++: Declaration of template class member specialization

    - by Ziv
    When I specialize a (static) member function/constant in a template class, I'm confused as to where the declaration is meant to go. Here's an example of what I what to do - yoinked directly from IBM's reference on template specialization: ===IBM Member Specialization Example=== template<class T> class X { public: static T v; static void f(T); }; template<class T> T X<T>::v = 0; template<class T> void X<T>::f(T arg) { v = arg; } template<> char* X<char*>::v = "Hello"; template<> void X<float>::f(float arg) { v = arg * 2; } int main() { X<char*> a, b; X<float> c; c.f(10); // X<float>::v now set to 20 } The question is, how do I divide this into header/cpp files? The generic implementation is obviously in the header, but what about the specialization? It can't go in the header file, because it's concrete, leading to multiple definition. But if it goes into the .cpp file, is code which calls X::f() aware of the specialization, or might it rely on the generic X::f()? So far I've got the specialization in the .cpp only, with no declaration in the header. I'm not having trouble compiling or even running my code (on gcc, don't remember the version at the moment), and it behaves as expected - recognizing the specialization. But A) I'm not sure this is correct, and I'd like to know what is, and B) my Doxygen documentation comes out wonky and very misleading (more on that in a moment a later question). What seems most natural to me would be something like this, declaring the specialization in the header and defining it in the .cpp: ===XClass.hpp=== #ifndef XCLASS_HPP #define XCLASS_HPP template<class T> class X { public: static T v; static void f(T); }; template<class T> T X<T>::v = 0; template<class T> void X<T>::f(T arg) { v = arg; } /* declaration of specialized functions */ template<> char* X<char*>::v; template<> void X<float>::f(float arg); #endif ===XClass.cpp=== #include <XClass.hpp> /* concrete implementation of specialized functions */ template<> char* X<char*>::v = "Hello"; template<> void X<float>::f(float arg) { v = arg * 2; } ...but I have no idea if this is correct. Any ideas? Thanks much, Ziv

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  • array of pointers

    - by tushar
    char *a[]={"diamonds","clubs","spades","hearts"}; char **p[]={a+3,a+2,a+1,a}; char ***ptr=p; cout<<*ptr[2][2]; why does it display h and please explain how is the 2d array of ptr implementing and its elements

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  • Creating my own Stack

    - by Malaken
    I am creating my own stack for my data structures class. For our assignment we are using the assignment to convert a real-time infix equation into a postfix equation. I thought my program: took input determines if it was digit or number(operand) prints it out determines if input is operator (+,-,/,*) adds to stack or prints out, depending on stack precedence Instead it prints out the operands as expect, but I get this error when I enter an operator .../dorun.sh line 33: 4136 Segmentation fault sh "$" [code] #include using namespace std; class DishWell{ public: char ReturnEnd(){ return Well.back(); } void Push(char x){ Well.push_back(x); } void Pop(){ Well.pop_back(); } bool IsEmpty(){ return Well.empty(); } private: vector<char> Well; }; #include <iostream> bool Precidence(char Input, char Stack){ int InputPrecidence,StackPrecidence; switch (Input){ case '*': InputPrecidence = 4; break; case '/': InputPrecidence = 4; break; case '+': InputPrecidence = 3; break; case '-': InputPrecidence = 3; break; case '(': InputPrecidence = 2; break; default: InputPrecidence = 0; } switch (Stack){ case '*': StackPrecidence = 4; break; case '/': StackPrecidence = 4; break; case '+': StackPrecidence = 3; break; case '-': StackPrecidence = 3; break; case '(': StackPrecidence = 2; break; default: StackPrecidence = 0; } if(InputPrecidence>StackPrecidence) return true; else return false; } int main(int argc, char** argv) { DishWell DishTray; char Input; bool InputFlag; InputFlag = true; while(InputFlag){ cin>>Input; if((((Input>='a'&&Input<='z')||(Input>='A'&&Input<='Z'))|| (Input>='0'&&Input<='9')))//If Digit or Number cout<<Input; if((Input=='*'||Input=='/'||Input=='+'||Input=='-')){//if operand if(Precidence(Input,DishTray.ReturnEnd())) DishTray.Push(Input); else if(!Precidence(Input,DishTray.ReturnEnd())) cout<<Input; } else if(!((((Input>='a'&&Input<='z')||(Input>='A'&&Input<='Z'))|| (Input>='0'&&Input<='9')))||((Input=='*'||Input=='/'||Input=='+'||Input=='-')))//if not digit/numer or operand InputFlag = false; } while(!DishTray.IsEmpty()){ cout<<DishTray.ReturnEnd(); DishTray.Pop(); } return 0; [code] My code is very length, I know, but I appreciate help. Especially any times for efficency or future coding. Thanks again P.S. Dr. Zemoudeh, this is your student Macaire

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  • Attempting to convert an if statement to assembly

    - by Malfist
    What am I doing wrong? This is the assmebly I've written: char encode(char plain){ __asm{ mov al, plain ;check for y or z status cmp al, 'y' je YorZ cmp al, 'z' je YorZ cmp al, 'Y' je YorZ cmp al, 'Z' je YorZ ;check to make sure it is in the alphabet now mov cl, al sub cl, 'A' cmp cl, 24 jl Other sub cl, '6' ;there are six characters between 'Z' and 'a' cmp cl, 24 jl Other jmp done ;means it is not in the alphabet YorZ: sub al, 24 jmp done Other: add al, 2 jmp done done: leave ret } } and this is the C code it's supposed to replace, but doesn't char encode(char plain){ char code; if((plain>='a' && plain<='x') || (plain>='A' && plain <='X')){ code = plain+2; }else if(plain == 'y' || plain=='z' || plain=='Y' || plain == 'y'){ code = plain - 24; }else{ code = plain; } return code; } It seems to convert every character that isn't an y,z,Y,Z into a plus 2 equivalent instead of just A-Xa-x. Any ideas why?

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  • undefined symbols when compiling libjingle for Mac OS X

    - by wwh37
    Compiling libjinge-0.4.0 on my Leopard returned the following errors: /bin/sh ../../../libtool --silent --tag=CXX --mode=link g++ -g -o login login-login_main.o login-xmppsocket.o login-xmppthread.o login-xmpppump.o login-xmppauth.o ../../../talk/xmpp/libcricketxmpp.la ../../../talk/xmllite/libcricketxmllite.la ../../../talk/base/libcricketbase.la -lexpat -lpthread -lssl -lcrypto Undefined symbols: "_BIO_clear_flags", referenced from: socket_read(bio_st*, char*, int)in libcricketbase.a(openssladapter.o) socket_write(bio_st*, char const*, int)in libcricketbase.a(openssladapter.o) "_BIO_set_flags", referenced from: socket_read(bio_st*, char*, int)in libcricketbase.a(openssladapter.o) socket_write(bio_st*, char const*, int)in libcricketbase.a(openssladapter.o) Any ideas? I couldn't find an answer... Thanks!

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  • Displaying map stl

    - by BSchlinker
    Declared a map early on: map<char*,char*> rtable; // used to store routing information Now I'm attempting to display the contents of the map: void Routes::viewroutes(){ typedef map<char*, char*>::const_iterator iter; for (iter=rtable.begin(); iter != rtable.end(); ++iter) { cout << iter->second << " " << iter->first << endl; } } Receiving the error "expected primary-expression before '!=' token and for '-' token. Can't seem to understand the error I'm making here. Any ideas?

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  • Endian check in C

    - by webgenius
    Got this code snippet from some website: int num = 1; if(*(char *)&num == 1) { printf("\nLittle-Endian\n"); } else { printf("Big-Endian\n"); } Can anyone explain this step-by-step? &num - Adress of a (char *)&num - Type-cast address of a into a string *(char *)&num - Points to the first character of the string Am I missing anything here?

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  • How to make the tokenizer detect empty spaces while using strtok()

    - by Shadi Al Mahallawy
    I am designing a c++ program, somewhere in the program i need to detect if there is a blank(empty token) next to the token used know eg. if(token1==start) { token2=strtok(NULL," "); if(token2==NULL) {LCCTR=0;} else {LCCTR=atoi(token2);} so in the previous peice token1 is pointing to start , and i want to check if there is anumber next to the start , so I used token2=strtok(NULL," ") to point to the next token but unfortunattly the strtok function cannot detect empty spaces so it gives me an error at run time"INVALID NULL POINTER" how can i fix it or is there another function to use to detect empty spaces #include <iostream> #include<string> #include<map> #include<iomanip> #include<fstream> #include<ctype.h> using namespace std; const int MAX=300; int LCCTR; int START(char* token1); char* PASS1(char*token1); void tokinizer() { ifstream in; ofstream out; char oneline[MAX]; in.open("infile.txt"); out.open("outfile.txt"); if(in.is_open()) { char *token1; in.getline(oneline,MAX); token1 = strtok(oneline," \t"); START (token1); //cout<<'\t'; while(token1!=NULL) { //PASS1(token1); //cout<<token1<<" "; token1=strtok(NULL," \t"); if(NULL==token1) {//cout<<endl; //cout<<LCCTR<<'\t'; in.getline(oneline,MAX); token1 = strtok(oneline," \t"); } } } in.close(); out.close(); } int START(char* token1) { string start("START"); char*token2; if(token1 != start) {LCCTR=0;} else if(token1==start) { token2=strchr(token1+2,' '); cout<<token2; if(token2==NULL) {LCCTR=0;} else {LCCTR=atoi(token2); if(atoi(token2)>9999||atoi(token2)<0){cout<<"IVALID STARTING ADDRESS"<<endl;exit(1);} } } return LCCTR; } char* PASS1 (char*token1) { map<string,int> operations; map<string,int>symtable; map<string,int>::iterator it; pair<map<string,int>::iterator,bool> ret; char*token3=NULL; char*token2=NULL; string test; string comp(" "); string start("START"); string word("WORD"); string byte("BYTE"); string resb("RESB"); string resw("RESW"); string end("END"); operations["ADD"] = 18; operations["AND"] = 40; operations["COMP"] = 28; operations["DIV"] = 24; operations["J"] = 0X3c; operations["JEQ"] =30; operations["JGT"] =34; operations["JLT"] =38; operations["JSUB"] =48; operations["LDA"] =00; operations["LDCH"] =50; operations["LDL"] =55; operations["LDX"] =04; operations["MUL"] =20; operations["OR"] =44; operations["RD"] =0xd8; operations["RSUB"] =0x4c; operations["STA"] =0x0c; operations["STCH"] =54; operations["STL"] =14; operations["STSW"] =0xe8; operations["STX"] =10; operations["SUB"] =0x1c; operations["TD"] =0xe0; operations["TIX"] =0x2c; operations["WD"] =0xdc; if(operations.find("ADD")->first==token1) { token2=strtok(NULL," "); //test=token2; cout<<token2; //if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} //else{LCCTR=LCCTR+3;} } /*else if(operations.find("AND")->first==token1) { token2=strtok(NULL," "); test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("COMP")->first==token1) { token2=token1+5; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("DIV")->first==token1) { token2=token1+4; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("J")->first==token1) { token2=token1+2; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JEQ")->first==token1) { token2=token1+5; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JGT")->first==token1) { token2=strtok(NULL," "); test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JLT")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("JSUB")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDA")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDCH")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDL")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("LDX")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("MUL")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("OR")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("RD")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("RSUB")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STA")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STCH")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STL")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STSW")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("STX")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("SUB")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("TD")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("TIX")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} } else if(operations.find("WD")->first==token1) { token2=token1+6; test=token2; if(test.empty()){cout<<"MISSING OPERAND"<<endl;exit(1);} else{LCCTR=LCCTR+3;} }*/ //else if( if(word==token1) {LCCTR=LCCTR+3;} else if(byte==token1) {string test; token2=token1+7; test=token2; if(test[0]=='C') {token3=token1+10; test=token3; if(test.length()>15) {cout<<"ERROR"<<endl; exit(1);} } else if(test[0]=='X') {token3=token1+10; test=token3; if(test.length()>14) {cout<<"ERROR"<<endl; exit(1);} } LCCTR=LCCTR+test.length(); } else if(resb==token1) {token3=token1+5; LCCTR=LCCTR+atoi(token3);} else if(resw==token1) {token3=token1+5; LCCTR=LCCTR+3*atoi(token3);} else if(end==token1) {exit(1);} /*else { test=token1; int last=test.length(); if(token1==start||test[0]=='C'||test[0]=='X'||ispunct(test[last])||isdigit(test[0])||isdigit(test[1])||isdigit(test[2])||isdigit(test[3])){} else { token2=strtok(NULL," "); //test=token2; cout<<token2; if(token2!=NULL) { symtable.insert( pair<string,int>(token1,LCCTR)); for(it=symtable.begin() ;it!=symtable.end() ;++it) {/*cout<<"symbol: "<<it->first<<" LCCTR: "<<it->second<<endl;} } else{} } }*/ return token3; } int main() { tokinizer(); return 0; }

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  • C++/CLI .ToString() returning error

    - by George Johnston
    I am a beginner to C++/CLI as I come from a C# background. I am currently writing a wrapper for some native C++ code. I have the following methods: void AddToBlockList(System::String^ address) { char* cAddress = (char*)(void*)Marshal::StringToHGlobalAnsi(address); _packetFilter->AddToBlockList(cAddress); } void AddToBlockList(IPAddress^ address) { char* cAddress = (char*)(void*)Marshal::StringToHGlobalAnsi(address.ToString()); _packetFilter->AddToBlockList(cAddress); } ...The first method works fine and converts my string into the character array. However, the second function with the IPAddress object as the signiture gives me the following error: error C2228: left of '.ToString' must have class/struct/union ...When I type ? address.ToString() ...in the command window, the IP Address prints. Not sure where I'm going wrong. Any ideas?

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  • C: sprintf and recursion

    - by Shinka
    In C, is it possible to use recursion within the sprintf function ? For some reason I get a segmentation fault when I do it: inline char *TreeNode_toString(const TreeNode *node) { char *out; if(TreeNode_isExternal(node)) // If the node has no children... { sprintf(out, "%s:%.2f", node->name, node->distance); } else // The node is strictly binary, so it will have two non-null children { char *l = TreeNode_toString(node->l); // l = left child char *r = TreeNode_toString(node->r); // r = right child sprintf(out, "(%s,%s):%.2f", l, r, node->distance); } return out; }

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  • A couple questions using fwrite/fread with data structures

    - by Nazgulled
    Hi, I'm using fwrite() and fread() for the first time to write some data structures to disk and I have a couple of questions about best practices and proper ways of doing things. What I'm writing to disk (so I can later read it back) is all user profiles inserted in a Graph structure. Each graph vertex is of the following type: typedef struct sUserProfile { char name[NAME_SZ]; char address[ADDRESS_SZ]; int socialNumber; char password[PASSWORD_SZ]; HashTable *mailbox; short msgCount; } UserProfile; And this is how I'm currently writing all the profiles to disk: void ioWriteNetworkState(SocialNetwork *social) { Vertex *currPtr = social->usersNetwork->vertices; UserProfile *user; FILE *fp = fopen("save/profiles.dat", "w"); if(!fp) { perror("fopen"); exit(EXIT_FAILURE); } fwrite(&(social->usersCount), sizeof(int), 1, fp); while(currPtr) { user = (UserProfile*)currPtr->value; fwrite(&(user->socialNumber), sizeof(int), 1, fp); fwrite(user->name, sizeof(char)*strlen(user->name), 1, fp); fwrite(user->address, sizeof(char)*strlen(user->address), 1, fp); fwrite(user->password, sizeof(char)*strlen(user->password), 1, fp); fwrite(&(user->msgCount), sizeof(short), 1, fp); break; currPtr = currPtr->next; } fclose(fp); } Notes: The first fwrite() you see will write the total user count in the graph so I know how much data I need to read back. The break is there for testing purposes. There's thousands of users and I'm still experimenting with the code. My questions: After reading this I decided to use fwrite() on each element instead of writing the whole structure. I also avoid writing the pointer to to the mailbox as I don't need to save that pointer. So, is this the way to go? Multiple fwrite()'s instead of a global one for the whole structure? Isn't that slower? How do I read back this content? I know I have to use fread() but I don't know the size of the strings, cause I used strlen() to write them. I could write the output of strlen() before writing the string, but is there any better way without extra writes?

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  • printf field width : bytes or chars?

    - by leonbloy
    The printf/fprintf/sprintf family supports a width field in its format specifier. I have a doubt for the case of (non-wide) char arrays arguments: Is the width field supposed to mean bytes or characters? What is the (correct-de facto) behaviour if the char array corresponds to (say) a raw UTF-8 string? (I know that normally I should use some wide char type, that's not the point) For example, in char s[] = "ni\xc3\xb1o"; // utf8 encoded "niño" fprintf(f,"%5s",s); Is that function supposed to try to ouput just 5 bytes (plain C chars) (and you take responsability of misalignments or other problems if two bytes results in a textual characters) ? Or is it supposed to try to compute the length of "textual characters" of the array? (decodifying it... according to the current locale?) (in the example, this would amount to find out that the string has 4 unicode chars, so it would add a space for padding).

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  • F# exercise help - Beginner

    - by bobjink
    I hope you can help me with these exercises I have been stuck with. I am not in particular looking for the answers. Tips that help me solve them myself are just as good :) 1. Write a function implode : char list - string so that implode s returns the characters concatenated into a string: let implode (cArray:char list) = List.foldBack (+) 0 cArray;; Error. I am thinking that i need to cast every char to strings before I do the above. I bet however, that there is a much simpler and better solution. 2. Write a function palindrome : string - bool, so that palindrome s returns true if the string s is a palindrome let isIdentical cArray1 cArray2 = (cArray1 = cArray2);; let palinDrome (word:string) = isIdentical(word.ToCharArray(), Array.rev(word.ToCharArray()));; I get the value: val palinDrome : string - (char [] * char [] - bool), which is not what I want. 3. Write a function combinePair : int list - int list so that combinePair xs returns the list with elements from xs combined into pairs. If xs contains an odd number of elements, then the last element is thrown away: I have no idea for this one.

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