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  • Error in Getting Youtube Video Title, Description and thumbnail

    - by Muhammad Ayyaz Zafar
    I was getting youtube title and youtube description form the same code but now its not working I am getting following error: Warning: DOMDocument::load() [domdocument.load]: http:// wrapper is disabled in the server configuration by allow_url_fopen=0 in /home/colorsfo/public_html/zaroorat/admin/pages/addSongProcess.php on line 16 Warning: DOMDocument::load(http://gdata.youtube.com/feeds/api/videos/Y7G-tYRzwYY) [domdocument.load]: failed to open stream: no suitable wrapper could be found in /home/colorsfo/public_html/zaroorat/admin/pages/addSongProcess.php on line 16 Warning: DOMDocument::load() [domdocument.load]: I/O warning : failed to load external entity "http://gdata.youtube.com/feeds/api/videos/Y7G-tYRzwYY" in /home/colorsfo/public_html/zaroorat/admin/pages/addSongProcess.php on line 16 .................................... Following Coding is used to get Youtube Video Data: $url = "http://gdata.youtube.com/feeds/api/videos/".$embedCodeParts2[0]; $doc = new DOMDocument; @$doc->load($url); $title = $doc->getElementsByTagName("title")->item(0)->nodeValue; $videoDescription = $doc->getElementsByTagName("description")->item(0)->nodeValue; It was working before (This coding is working fine in Local server but on internet its not working) but now its not working. Please guide me how to fix this error. Thanks for your time.

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  • make quantaplus a default editor for php files in ubuntu

    - by diEcho
    In Ubuntu, how can I make Quanta Plus the default editor for PHP files? In Windows we just use the open with context menu the first time for any new types of files and check use this application for these type of files. After that the files always open up in checked application. I want to know if Ubuntu has a similar feature. Also, if I open 2 PHP files then two instance of Quanta Plus opens up. How can I get the secondary PHP files to open on another tab instead?

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  • mysql to xml (DOM question)

    - by Jerry
    Hello guys I am new to php dom and trying to get the mysql data transfer into xml. My current xml output is like this <markers> <city> <name>Seattle</name> <size>medium</size> <name>New York</name> <size>big</size> <city> <markers> but I want to change it to <markers> <city> <name>Seattle</name> <size>medium</size> <city> <city> <name>New York</name> <size>big</size> </city> <city> <markers> my php $dom=new DOMDocument("1.0"); $node=$dom->createElement("markers"); $parnode=$dom->appendChild($node); $firstElement=$dom->createElement("city"); $parnode->appendChild($firstElement); $getLocationQuery=mysql_query("SELECT * FROM location",$connection); header("Content-type:text/xml"); while($row=mysql_fetch_assoc($getLocationQuery)){ foreach ($row as $fieldName=>$value){ $child=$dom->createElement($fieldName); $value=$dom->createTextNode($value); $child->appendChild($value); $firstElement->appendChild($child); } } I can't figure out how to change my php code. Please help me about it. Thanks a lot.

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  • How can I use JSONP to download client-side javascript objects?

    - by Alex Mcp
    I'm trying to get client-side javascript objects saved as a file locally. I'm not sure if this is possible. The basic architecture is this: Ping an external API to get back a JSON object Work client-side with that object, and eventually have a "download me" link This link sends the data to my server, which processes it and sends it back with a mime type application/json, which (should) prompt the user to download the file locally. Right now here are my pieces: Server Side Code <?php $data = array('zero', 'one', 'two', 'testing the encoding'); $json = json_encode($data); //$json = json_encode($_GET['']); //eventually I'll encode their data, but I'm testing header("Content-type: application/json"); header('Content-Disposition: attachment; filename="backup.json"'); echo $_GET['callback'] . ' (' . $json . ');'; ?> Relevant Client Side Code $("#download").click(function(){ var json = JSON.stringify(collection); //serializes their object $.ajax({ type: "GET", url: "http://www.myURL.com/api.php?callback=?", //this is the above script dataType: "jsonp", contentType: 'jsonp', data: json, success: function(data){ console.log( "Data Received: " + data[3] ); } }); return false; }); Right now when I visit the api.php site with Firefox, it prompts a download of download.json and that results in this text file, as expected: (["zero","one","two","testing the encoding"]); And when I click #download to run the AJAX call, it logs in Firebug Data Received: testing the encoding which is almost what I'd expect. I'm receiving the JSON string and serializing it, which is great. I'm missing two things: The Actual Questions What do I need to do to get the same prompt-to-download behavior that I get when I visit the page in a browser (much simpler) How do I access, server-side, the json object being sent to the server to serialize it? I don't know what index it is in the GET array (silly, I know, but I've tried almost everything)

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  • Load an html table from a mysql database when an onChange event is triggered from a select tag

    - by Crew Peace
    So, here's the deal. I have an html table that I want to populate. Specificaly the first row is the one that is filled with elements from a mysql database. To be exact, the table is a questionnaire about mobile phones. The first row is the header where the cellphone names are loaded from the database. There is also a select tag that has company names as options in it. I need to trigger an onChange event on the select tag to reload the page and refill the first row with the new names of mobiles from the company that is currently selected in the dropdown list. This is what my select almost looks like: <select name="select" class="companies" onChange="reloadPageWithNewElements()"> <?php $sql = "SELECT cname FROM companies;"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['cname']."\">".$row['cname']."</option>\n "; } ?> </select> So... is there a way to refresh this page with onChange and pass the selected value to the same page again and assign it in a new php variable so i can do the query i need to fill my table? <?php //$mobileCompanies = $_GET["selectedValue"]; $sql = "SELECT mname FROM ".$mobileCompanies.";"; $rs = mysql_query($sql); while ($row = mysql_fetch_array($rs)) { echo "<td><div class=\"q1\">".$row['mname']."</div></td>"; } ?> something like this. (The reloadPageWithNewElements() and selectedValue are just an idea for now)

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  • How to send array by post method

    - by GanChinHock.com
    Following is my sample form. <form METHOD="post" METHOD="post" ACTION="index.php" METHOD="post" METHOD="post" METHOD="post"> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="text" NAME="array[]" /> <input TYPE="submit" NAME="submit" VALUE="Submit" /> </form> Basically I have 10 inputs of array. Assume my domain is http://domain.com and the file above is index.php. I am trying to fill the form automatically by using the following method. http://domain.com/index.php?array[]=John&array[]=Kelly ... & array[]=Steven Unfortunately, it is not working. :(

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  • Zend_Cache save from command line and access from browser

    - by Krishna Sunuwar
    May be I am this is super-easy but I couldnt' figure out way. I have script running in command line which save cache using Zend_Cache $frontendOptions = array( 'lifetime' => NULL, 'automatic_serialization' => true ); $backendOptions = array( 'cache_dir' => "/home/tmp/cache" ); $cache = Zend_Cache::factory('Core', 'File', $frontendOptions, $backendOptions); $vars = Array("id1" => "12121", "id2" => "2232"); $cache->save($vars, "p_11"); I can access saved cache from command line: $cache->load("p_11"); In above both case, I have app.php file that run in command line using php-cli. Now, I want to access p_11 cache using browser something like http://mytestserve.lan/test_cache.php I have create object with cache factory like above. All the parameters are same as above. However when I try to load cache p_11, i do not variables set from command line. What went wrong?

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  • Using MRTG's threshold feature to execute a php script

    - by Dan Fried
    I've set up mrtg using the online manual and the only online tutorial I found on the subject of thresholds, and the threshold just isn't firing. In my mrtg.cfg file, the relevant lines are ThreshDir: /path/to/mrtg/thresh ThreshMaxI[performance]: 1 ThreshMaxO[performance]: 1 ThreshProgI[performance]: /path/to/mrtg/scripts/alert.php ThreshProgO[performance]: /path/to/mrtg/scripts/alert.php The paths are right, because if I enter the paths wrong I get an error on executing mrtg. websitePerformance checks how long it takes to download the homepage, in milliseconds, so it should be exceeding the max every time. Alert.php is working fine when invoked directly from the shell, and when I point to a nonexistent script it tells me the script is not executable. No error messages are being generated, that I can find. The thresh directory is always empty. Why isn't the threshold being triggered by results that are greater than 1? Anyone have any suggestions?

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  • Sorting by custom field and fetching whole tree from DB

    - by Niaxon
    Hello everyone, I am trying to do file browser in a tree form and have a problem to sort it somehow. I use PHP and MySQL for that. I've created mixed (nested set + adjacency) table 'element' with the following fields: element_id, left_key, right_key, level, parent_id, element_name, element_type (enum: 'folder','file'), element_size. Let's not discuss right now that it is better to move information about element (name, type, size) into other table. Function to scan specified directory and fill table work correctly. Noteworthy, i am adding elements to tree in specific order: folders first and then files. After that i can easily fetch and display whole table on the page using simple query: SELECT * FROM element WHERE 1=1 ORDER BY left_key With the result of that query and another function i can generate correct html code (<ul><li>... and so on). to display tree. Now back to the question (finally, huh?). I am struggling to add sorting functionality. For example i want to order my result by size. Here i need to keep in my mind whole hierarchy of tree and rule: folders first, files later. I believe i can do that by generating in PHP recursive query: SELECT * FROM element WHERE parent_id = {$parentId} ORDER BY element_type (so folders would be first), size (or name for example) asc/desc After that for each result which has type = 'folder' i will send another query to get it's content. Also it's possible to fetch whole tree by left_key and after that sort it in PHP as array but i guess that would be worse :) I wonder if there is better and more efficient way to do such a thing?

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  • Shell script for replacing string in all PHP-files, for each user

    - by Mads Skjern
    Each user has some php-files using a shared database commondb. I want to iterate over all users (in users.csv), and in their home folder (e.g. /home/joe) find all php files recursively, and replace each occurrence of "commondb" with their own databasename, e.g. "joedb" for "joe". I have tried the following: #!/bin/bash # Execute like this: # bash localize.bash users.csv OLDIFS=$IFS IFS="," while read name dummy do echo $name find /home/${name} -name '*.php' -exec sed -i '' 's/commondb/${name}db/g' "{}" \; done < $1 IFS=$OLDIFS for users.csv joe, Joe J george, George G It does not fail, but the files are unchanged. I am quite weak in bash, and I can't figure out how to debug it :/ Can my script be fixed to work?

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  • AJAX Post Not Sending Data?

    - by Jascha
    I can't for the life of me figure out why this is happening. This is kind of a repost, so forgive me, but I have new data. I am running a javascript log out function called logOut() that has make a jQuery ajax call to a php script... function logOut(){ var data = new Object; data.log_out = true; $.ajax({ type: 'POST', url: 'http://www.mydomain.com/functions.php', data: data, success: function() { alert('done'); } }); } the php function it calls is here: if(isset($_POST['log_out'])){ $query = "INSERT INTO `token_manager` (`ip_address`) VALUES('logOutSuccess')"; $connection->runQuery($query); // <-- my own database class... // omitted code that clears session etc... die(); } Now, 18 hours out of the day this works, but for some reason, every once in a while, the POST data will not trigger my query. (this will last about an hour or so). I figured out the post data is not being set by adding this at the end of my script... $query = "INSERT INTO `token_manager` (`ip_address`) VALUES('POST FAIL')"; $connection->runQuery($query); So, now I know for certain my log out function is being skipped because in my database is the following data: if it were NOT being skipped, my data would show up like this: I know it is being skipped for two reasons, one the die() at the end of my first function, and two, if it were a success a "logOutSuccess" would be registered in the table. Any thoughts? One friend says it's a janky hosting company (hostgator.com). I personally like them because they are cheap and I'm a fan of cpanel. But, if that's the case??? Thanks in advance. -J

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  • Website. AJAX and FIREFOX problems. I dont think Firefox likes ajax..?

    - by DJDonaL3000
    Working on an AJAX website (HTML,CSS,JavaScript, AJAX, PHP, MySQL). I have multiple javascript functions which take rows from mysql, wrap them in html tags, and embed them in the HTML (the usual usage of AJAX). THE PROBLEM: Everything is working perfect, except when I run the site with Firefox (for once its not InternetExplorer causing the trouble). The site is currently in the developmental stage, so its offline, but running on the localhost (WampServer, apache, Windows XP SP3,VISTA,7). All other cross-browser conflicts have been removed, and works perfectly on all major browsers including IE, Chrome, Opera and Safari, but I get absolutely nothing from the HTTPRequest (AJAX) if the browser is Firefox. All browsers have the latest versions. THE CODE: I have a series of javascript functions, all of which are structured as follows: function getDatay(){ var a = document.getElementById( 'item' ).innerHTML; var ajaxRequest; try{//Browser Support Code: // code for IE7+, Firefox, Chrome, Opera, Safari: ajaxRequest = new XMLHttpRequest(); } catch (e){ // code for IE6, IE5: try{ ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try{ ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e){ // Something went wrong alert("Your browser is not compatible - Browser Incompatibility Issue."); return false; } } } // Create a function that will receive data sent from the server ajaxRequest.onreadystatechange = function(){ if(ajaxRequest.readyState < 4){ document.getElementById( 'theDiv' ).innerHTML = 'LOADING...'; } if(ajaxRequest.readyState == 4){ document.getElementById( 'theDiv' ).innerHTML = ajaxRequest.responseText; } } //Post vars to PHP Script and wait for response: var url="01_retrieve_data_7.php"; url=url+"?a="+a; ajaxRequest.open("POST", url, false);//must be false here to wait for ajaxRequest to complete. ajaxRequest.send(null); } My money is on the final five lines of code being the cause of the problem. Any suggestions how to get Firefox and AJAX working together are most welcome...

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  • Jquery unidentified data return when post

    - by Nhat Tuan
    <?php //load.php $myid = $_POST['id']; if($myid == 1){ echo '1'; }else if($myid == 0){ echo '0'; } ?> <html> <input id="id" /> <div id="result"></div> <input type="button" id="submit" /> <script type="text/javascript"> $('#submit').click( function(){ var send = 'id=' + $('#id').val(); $.post('load.php', send, function(data){ if(data == 1){ $('#result').html('Success'); }else if(data == 0){ $('#result').html('Failure'); }else{ $('#result').html('Unknow'); } }); }); </script> </html> I test this script in some free host and it work but in my real host jquery unidentified data return and it alway show 'Unknow'. When i change if(data == '1') it show 'Unknow' too EX: input id = 1 click submit & data return is 'Unknow' Why ?? I think this error from host, because i test it in some free host and it work, but now in my real host i got this error, how i can fix it ?

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  • jQuery pagination without all the rows of data before hand

    - by Aaron Mc Adam
    Hi guys, I'm trying to find a solution for paginating my search results. I have a built the links and everything works without jQuery. I've also got AJAX working for the links, but I just need a way of tidying up the list of links, as some search results return up to 60 pages and the links spread to two rows in my template. I am searching the Amazon API, and can only return 10 results at a time. Upon clicking the pagination links, the next 10 results are returned. I have access to the total results number from the XML, but not all the data at once, so I can't put all the data into a "hiddenResults" div that the jQuery Pagination plugin needs. Here is the jQuery I have for the pagination: var $pagination = $("#pagination ul"); $pagination.delegate('.pagenumbers', 'click', function() { var $$this = $(this); $$this.closest('li').addClass('cached'); $pagination.find("#currentPage").removeAttr('id').wrapInner($('<a>', {'class':'pagenumbers', 'href':'book_data.php?keywords='+keywords})); $$this.closest('li').attr('id','currentPage').html( $$this.text() ); $.ajax({ type : "GET", cache : false, url : "book_data.php", data : { keywords : keywords, page : $$this.text() }, success : show_results }); return false; }); function show_results(res) { $("#searchResults").replaceWith($(res).find('#searchResults')).find('table.sortable tbody tr:odd').addClass('odd'); detailPage(); selectForm(); if ( ! ( $pagination.find('li').hasClass('cached') ) ) { $.get("book_data.php", { keywords : keywords, page : ( $pagination.find("#currentPage").text() + 1 ) } ); } }

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  • Still don't understand file upload-folder permissions

    - by Camran
    I have checked out articles and tutorials. I don't know what to do about the security of my picture upload-folder. It is pictures for classifieds which should be uploaded to the folder. This is what I want: Anybody may upload images to the folder. The images will be moved to another folder, by another php-code later on (automatic). Only I may manually remove them, as well as another php file on the server which automatically empties the folder after x-days. What should I do here? The images are uploaded via a php-upload script. This script checks to see if the extension of the file is actually a valid image-file. When I try this: chmod 755 images the images wont be uploaded. But like this it works: chmod 777 images But 777 is a security risk right? Please give me detailed information... The Q is, what to do to solve this problem, not info about what permissions there are etc etc... Thanks If you need more info let me know...

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  • How to keep form items selected after post request?

    - by Ole Jak
    I have a simple html form. On php page. A simple list is placed on form. I submit this form (selected list items) to this page so it gives me page refresh. I want items which were POSTED to be selected after form was submited. How to do such thing? For my form I use such code: <form action="FormPage.php" method="post"> <select id="Streams" class="multiselect ui-widget-content ui-corner-all" multiple="multiple" name="Streams[]"> <?php $query = " SELECT s.streamId, s.userId, u.username FROM streams AS s JOIN user AS u ON s.userId = u.id LIMIT 0 , 30 "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ echo '<option value="' , $row['streamId'] , '"> ' , $row['username'] , ' (' , $row['streamId'] ,')' ,'</option> '; } ?> </select> <br/> <input type="submit" class="ui-state-default ui-corner-all" name="submitForm" id="submitForm" value="Play Stream from selected URL's!"/> </fieldset> </form>

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  • htmlspecialchars() - How and when to use and avoid multiple use

    - by naescent
    Hi, I'm building a PHP intranet for my boss. A simple customer, order, quote system. It will be denied access from the Internet and only used by 3 people. I'm not so concerned with security as I am with validation. Javascript is disables on all machines. The problem I have is this: Employee enters valid data into a form containing any of the following :;[]"' etc. Form $_POSTS this data to a validationAndProcessing.php page, and determines whether the employee entered data or not in to the fields. If they didn't they are redirected back to the data input page and the field they missed out is highlighted in red. htmlspecialchars() is applied to all data being re-populated to the form from what they entered earlier. Form is then resubmitted to validationAndProcessing.php page, if successful data is entered into the database and employee is taken to display data page. My question is this: If an employee repeatedly enters no data in step 1, they will keep moving between step 1 and 4 each time having htmlspecialchars() applied to the data. So that:- & becomes:- &amp; becomes:- &amp;amp; becomes:- &amp;amp;amp; etc.. How can I stop htmlspecialchars() being applied multiple times to data that is already cleaned? Thanks, Adam

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  • Ajax: strange behaviour while checking a textfield

    - by ilnur777
    I have a registration form with checking the available name for username field through ajax. Inputing a username into username field and pushing the "Check!" button, the script sends value to php script. Then php script replaces the username field with the username field + style like this: <input type="text" name="login" value="'.$_GET["user"].'" style="width:205; height:22; border-width:1; border-color:red; border-style:solid; background-color:rgb(255,232,230);"> So when replacing the username field in the form with its equivalent from php script and then submitting a form, it is then get to script on the page that checks whether the username field is empty or not. And it returns an error that it is empty, though after checking through ajax the username field it has value. I don't understand why it gets to empty field checking script, having the same field name and having value?

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • link clickable and wordwrap

    - by newinjs
    hi, i'm using php wordwrap for my comment box. This is my clickable function, function clickable_link($text) { $ret = ' ' . $text; $ret = preg_replace("#(^|[\n ])([\w]+?://[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a class=\"hrefLink\" href=\"\\2\" target=\"_blank\">\\2</a>", $ret); $ret = preg_replace("#(^|[\n ])((www|ftp)\.[\w\#$%&~/.\-;:=,?@\[\]+]*)#is", "\\1<a class=\"hrefLink\" href=\"http://\\2\" target=\"_blank\">\\2</a>", $ret); $ret = preg_replace("#(^|[\n ])([a-z0-9&\-_.]+?)@([\w\-]+\.([\w\-\.]+\.)*[\w]+)#i", "\\1<a href=\"mailto:\\2@\\3\">\\2@\\3</a>", $ret); $ret = substr($ret, 1); return $ret; } and this is my wordwrap for comment $comment = clickable_link($comment); $comment = wordwrap($comment, 25, "\n", false); so, once the word limit for 25 is reached, my comment box break my link http://www.websitetitle.com/showthread.php?t=2000 link become like this http://www.websitetitle.com/showthread.php? <br> t=2000 The link is broken. so is it possible to fix the link or any other workaround? Thank you

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  • Session variables not getting set but only in Internet Explorer and not on all machines

    - by gaoshan88
    Logging into a site I'm working on functions as expected on my local machine but fails on the remote server but ONLY in Internet Explorer. The kicker is that it works in IE locally, just not on the remote machine. What in the world could cause this? I have stepped through the code on the remote machine and can see the entered login values being checked in the database, they are found and then a login function is called. This sets two $_SESSION variables and redirects to the main admin page. However, in IE only (and not when run on local machine... this is key) the $_SESSION variables are not present by the time you get to the main admin page. var_dump($_SESSION) gives me what I expect on every browser when I am running this in my local environment and in every browser except IE 6, 7 and 8 when run on the remote server (where I get a null value as if nothing has been set for $_SESSION). This really has me stumped so any advice is appreciated. For an example... in IE, run locally, var_dump gives me: array 'Username' => string 'theusername' length=11 'UserID' => string 'somevalue' length=9 Run on the remote server (IE only... works fine in other browsers) var_dump gives me: array(0){} Code: $User = GetUser($Username, $Password); if ($User->UserID <> "") { // this works so we call Login()... Login($User); // this also works and gives expected results. on to redirect... header("Location: index.php"); // a var_dump at index.php shows that there is no session data at all in IE, remotely. } else { header("Location: login.php"); } function Login($data) { $_SESSION['Username'] = $data->Username; $_SESSION['UserID'] = $data->UserID; // a var dump here gives the expected data in every browser }

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  • CakePHP: Interaction between different files/classes

    - by Alexx Hardt
    Hey, I'm cloning a commercial student management system. Students use the frontend to apply for lectures, uni staff can modify events (time, room, etc). The core of the app will be the algortihm which distributes the seats to students. I already asked about it here: How to implement a seat distribution algorithm for uni lectures Now, I found a class for that algorithm here: http://www.phpclasses.org/browse/file/10779.html I put the 'class GA' into app/vendors. I need to write a 'class Solution', which represents one object (a child, and later a parent for the evolutionary process). I'll also have to write functions mutate(), crossover() and fitness(). fitness calculates a score of a solution, based on if there are overbooked courses etc; crossover() is the crazy monkey sex function which produces a child from two parents, and mutate() modifies a child after crossover. Now, the fitness()-function needs to access a few related models, and their find()-functions. It evaluates a solution's fitness by checking e.g. if there are overbooked courses, or unfulfilled wishes, and penalizes that. Where would I put the ga.php, solution.php and the three functions? ga.php has to access the functions, but the functions have to access the models. I also don't want to call any App::import()'s from within the fitness()-function, because it gets called many thousand times when the algorithm runs. Hope someone can help me. Thanks in advance =)

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  • Why NOT use POST method here?

    - by Camran
    I have a classifieds website. In the main page (index) I have several form fields which the user may or may not fill in, in order to specify a detailed search of classifieds. Ex: Category: Cars Price from: 3000 Price to: 10000 Color: Red Area: California The forms' action is set to a php page: <form action='query_sql.php' method='post'> In query_sql.php I fetch the variables like this: category=$_POST['category']; etc etc... Then query MySql: $query="SELECT........WHERE category='$category' etc etc.... $results = mysql_query($query); Then I simply display the results of the query to the user by creating a table which is filled in dynamically depending on the results set. However, according to an answer by Col. Shrapnel in my previous Q I shouldn't use POST here: http://stackoverflow.com/questions/3004754/how-to-hide-url-from-users-when-submitting-this-form The reason I use post is simply to hide the "one-page-word-document" long URL in the browsers adress bar. I am very confused, is it okay to use POST or not? It is working fine both when I use GET or POST now... And it is already on a production server... Btw, in the linked question, I wasn't referring to make URL invisible (or hide it) I just wanted it too look better (which I have accomplished with mod_rewrite). UPDATE: If I use GET, then how should I make the url better looking (beautiful)? Check this previous Q out: http://stackoverflow.com/questions/3000524/how-to-make-this-very-long-url-appear-short

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  • making clean page via page.tpl.php

    - by user360051
    I have a Drupal module creating a page via hook_menu(). I am trying to make it so the page has no extraneous html output, only what I want. You can view the page here, http://www.thomashansen.me/chat/thomas. If you look at the source, you can see a strange script tag at the end. My page-chat.tpl.php looks like this, <?php // $Id$ ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="<?php print $language->language ?>" lang="<?php print $language->language ?>" dir="<?php print $language->dir ?>"> <head> </head> <body> <?php print $content; ?> </body> </html> Where is that script tag coming from? and how do I get rid of it? If you need more information just ask.

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  • Variable not implementing correctly from if statement

    - by swiftsly
    I have an if statement that is supposed to set the variable $pc162v to a link specified in the MySQL table if content exists in the $vid column of the row. The problem is, the PHP is detecting that there's a link in the MySQL, but isn't setting the $pc162v variable correctly. Here's the variable declarations: $pc162v = ""; $vid162 = '<embed width="420" height="236" src="'.$pc162v.'" type="application/x-shockwave-flash"></embed>'; Here's the section of the if statement: if (empty($row[7])) { $vid162 = ''; } else { $pc162v = $row[7]; } In my web browsers, the part of the code where the variable $vid162 is used, shows up as the following: <embed width="420" height="236" src="" type="application/x-shockwave-flash"> I have also tried setting $vid162 to: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"></embed> and that just makes the code in my web browser: <embed width="420" height="236" src="<?php echo $pc162v; ?>" type="application/x-shockwave-flash"> Hope someone has a solution! Thanks in advance.

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