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  • Pass a datatable model to controller action in MVC

    - by user2906420
    Code: @model System.Data.DataTable <button type="submit" class="btn btn-primary" data-dismiss="modal" aria-hidden="true"> Download</button> [HttpPost] public void getCSV(DataTable dt) { MemoryStream stream = Export.GetCSV(dt); var filename = "ExampleCSV.csv"; var contenttype = "text/csv"; Response.Clear(); Response.ContentType = contenttype; Response.AddHeader("content-disposition", "attachment;filename=" + filename); Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.BinaryWrite(stream.ToArray()); Response.End(); } I want to allow the user to export a CSV file when the button is clicked on. the datatable should be passed to the method getCSV. Please can someone help me. thanks I do not mind using Tempdata to store the datatable and then access it in the controller

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  • Third party library not working with angular js

    - by sarvesh
    I am using navgoco.js and angular js in an application and I have following html <div id="demo"> <ul > <li ng-repeat ... > <a href="#"> ... </a> ...... </li> </ul> </div> js code $j("#demo1").navgoco({accordion: false}); It is supposed to do some expand-collapse of menus. the problem is that navgoco events are not performing on clicking on anchor. It simply adds # to url. In the rendered html of anchor tag, anuglar is adding ng-binding that may be the problem. Please help.

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  • Problem in building a tab bar inside navigation controller

    - by Heba
    Hello Everyone! I am really frustrated and I rally hope that you will help me to solve this problem! I'm trying to build a tab bar inside a navigation controller. I used this template provided by WiredBob. My problem is that I want to add more bar items to the tab bar, but I keep getting crash! From the log: 2010-05-24 00:15:43.469 NavTab[9315:207] * Terminating app due to uncaught exception 'NSInternalInconsistencyException', reason: '-[UITableViewController loadView] loaded the "AnnView" nib but didn't get a UITableView.' Also, I tried to fix the size of the a view in IB to fit in with the tab bar, but I couldn't! It was unchangeable. Thanks in advance :-)

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  • rootview controller in Interface builder?

    - by senthilmuthu
    hi, i have done in didapplicationfinishing function tabBarController = [[UITabBarController alloc] init] ; tabBarController.navigationItem.title = @"News"; SimpleTableViewController *rtbfViewController = [[SimpleTableViewController alloc] init]; //initWithStyle:UITableViewStyleGrouped]; rtbfViewController.tabBarItem.title = @"News1"; rtbfViewController.tabBarItem.image = [UIImage imageNamed:@"home.png"];; UINavigationController *table2NavController = [[[UINavigationController alloc] initWithRootViewController:rtbfViewController] autorelease]; [rtbfViewController release]; it works fine .suppose if i have Navigation controller in Interface Builder,how can i set initWithRootViewController in Interface builder?

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  • Vew not updating after scope update

    - by bsparacino
    Here is a very simple example of what I am trying to do Athlete.save(athlete,function(result) { $scope.athlete = result.athlete; }); The issue is that the $scope.athlete variable does not update in my view. In order to get it to update I have to do this Athlete.save(athlete,function(result) { $scope.athlete.fname = result.athlete.fname; $scope.athlete.lname= result.athlete.lname; $scope.athlete.gender= result.athlete.gender; .... }); This gets annoying very quickly. With the first block of code it's as if angular does not know that my $scope.athlete variable has been updated. This function is triggered from an ng-click, not some jquery call, I am doing it the angular way as far as I know. here is a simpler case I made: http://plnkr.co/edit/lMCPbzqDOoa5K4GXGhCp

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  • What happens with $q.all() when some calls work and others fail?

    - by Alan
    What happens with $q.all() when some calls work and others fail? I have the following code: var entityIdColumn = $scope.entityType.toLowerCase() + 'Id'; var requests = $scope.grid.data .filter(function (rowData, i) { return !angular.equals(rowData, $scope.grid.backup[i]); }) .map(function (rowData, i) { var entityId = rowData[entityIdColumn]; return $http.put('/api/' + $scope.entityType + '/' + entityId, rowData); }); $q.all(requests).then(function (allResponses) { //if all the requests succeeded, this will be called, and $q.all will get an //array of all their responses. console.log(allResponses[0].data); }, function (error) { //This will be called if $q.all finds any of the requests erroring. var abc = error; var def = 99; }); When all of the $http calls work then the allResponses array is filled with data. When one fails the it's my understanding that the second function will be called and the error variable given details. However can someone help explain to me what happens if some of the responses work and others fail?

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  • Codeigniter: Using data in a controller

    - by Kevin Brown
    I'm new to php and CI, and I'm having some trouble in my controller. I feel that I'm doing this the wrong way, and it could be easier, I just don't know the syntax: $data['members'] = $this->home_model->getUser($id); $credit = $this->home_model->getCredit($id); if ($credit == '0'){stuff...} So I'm getting the user's data that has their the same information as "getCredit" does, but I don't know how to get the single variable that I need for my if statement... How can I just use the "getUser" function so that I'm not pulling redundant information?

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  • Connecting SceneBuilder edited FXML to Java code

    - by daniel
    Recently I had to answer several questions regarding how to connect an UI built with the JavaFX SceneBuilder 1.0 Developer Preview to Java Code. So I figured out that a short overview might be helpful. But first, let me state the obvious. What is FXML? To make it short, FXML is an XML based declaration format for JavaFX. JavaFX provides an FXML loader which will parse FXML files and from that construct a graph of Java object. It may sound complex when stated like that but it is actually quite simple. Here is an example of FXML file, which instantiate a StackPane and puts a Button inside it: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml"> <children> <Button mnemonicParsing="false" text="Button" /> </children> </StackPane> ... and here is the code I would have had to write if I had chosen to do the same thing programatically: import javafx.scene.control.*; import javafx.scene.layout.*; ... final Button button = new Button("Button"); button.setMnemonicParsing(false); final StackPane stackPane = new StackPane(); stackPane.setPrefWidth(200.0); stackPane.setPrefHeight(150.0); stacPane.getChildren().add(button); As you can see - FXML is rather simple to understand - as it is quite close to the JavaFX API. So OK FXML is simple, but why would I use it?Well, there are several answers to that - but my own favorite is: because you can make it with SceneBuilder. What is SceneBuilder? In short SceneBuilder is a layout tool that will let you graphically build JavaFX user interfaces by dragging and dropping JavaFX components from a library, and save it as an FXML file. SceneBuilder can also be used to load and modify JavaFX scenegraphs declared in FXML. Here is how I made the small FXML file above: Start the JavaFX SceneBuilder 1.0 Developer Preview In the Library on the left hand side, click on 'StackPane' and drag it on the content view (the white rectangle) In the Library, select a Button and drag it onto the StackPane on the content view. In the Hierarchy Panel on the left hand side - select the StackPane component, then invoke 'Edit > Trim To Selected' from the menubar That's it - you can now save, and you will obtain the small FXML file shown above. Of course this is only a trivial sample, made for the sake of the example - and SceneBuilder will let you create much more complex UIs. So, I have now an FXML file. But what do I do with it? How do I include it in my program? How do I write my main class? Loading an FXML file with JavaFX Well, that's the easy part - because the piece of code you need to write never changes. You can download and look at the SceneBuilder samples if you need to get convinced, but here is the short version: Create a Java class (let's call it 'Main.java') which extends javafx.application.Application In the same directory copy/save the FXML file you just created using SceneBuilder. Let's name it "simple.fxml" Now here is the Java code for the Main class, which simply loads the FXML file and puts it as root in a stage's scene. /* * Copyright (c) 2012, Oracle and/or its affiliates. All rights reserved. */ package simple; import java.util.logging.Level; import java.util.logging.Logger; import javafx.application.Application; import javafx.fxml.FXMLLoader; import javafx.scene.Scene; import javafx.scene.layout.StackPane; import javafx.stage.Stage; public class Main extends Application { /** * @param args the command line arguments */ public static void main(String[] args) { Application.launch(Main.class, (java.lang.String[])null); } @Override public void start(Stage primaryStage) { try { StackPane page = (StackPane) FXMLLoader.load(Main.class.getResource("simple.fxml")); Scene scene = new Scene(page); primaryStage.setScene(scene); primaryStage.setTitle("FXML is Simple"); primaryStage.show(); } catch (Exception ex) { Logger.getLogger(Main.class.getName()).log(Level.SEVERE, null, ex); } } } Great! Now I only have to use my favorite IDE to compile the class and run it. But... wait... what does it do? Well nothing. It just displays a button in the middle of a window. There's no logic attached to it. So how do we do that? How can I connect this button to my application logic? Here is how: Connection to code First let's define our application logic. Since this post is only intended to give a very brief overview - let's keep things simple. Let's say that the only thing I want to do is print a message on System.out when the user clicks on my button. To do that, I'll need to register an action handler with my button. And to do that, I'll need to somehow get a handle on my button. I'll need some kind of controller logic that will get my button and add my action handler to it. So how do I get a handle to my button and pass it to my controller? Once again - this is easy: I just need to write a controller class for my FXML. With each FXML file, it is possible to associate a controller class defined for that FXML. That controller class will make the link between the UI (the objects defined in the FXML) and the application logic. To each object defined in FXML we can associate an fx:id. The value of the id must be unique within the scope of the FXML, and is the name of an instance variable inside the controller class, in which the object will be injected. Since I want to have access to my button, I will need to add an fx:id to my button in FXML, and declare an @FXML variable in my controller class with the same name. In other words - I will need to add fx:id="myButton" to my button in FXML: -- <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> and declare @FXML private Button myButton in my controller class @FXML private Button myButton; // value will be injected by the FXMLLoader Let's see how to do this. Add an fx:id to the Button object Load "simple.fxml" in SceneBuilder - if not already done In the hierarchy panel (bottom left), or directly on the content view, select the Button object. Open the Properties sections of the inspector (right panel) for the button object At the top of the section, you will see a text field labelled fx:id. Enter myButton in that field and validate. Associate a controller class with the FXML file Still in SceneBuilder, select the top root object (in our case, that's the StackPane), and open the Code section of the inspector (right hand side) At the top of the section you should see a text field labelled Controller Class. In the field, type simple.SimpleController. This is the name of the class we're going to create manually. If you save at this point, the FXML will look like this: -- <?xml version="1.0" encoding="UTF-8"?> <?import java.lang.*?> <?import java.util.*?> <?import javafx.scene.control.*?> <?import javafx.scene.layout.*?> <?import javafx.scene.paint.*?> <StackPane prefHeight="150.0" prefWidth="200.0" xmlns:fx="http://javafx.com/fxml" fx:controller="simple.SimpleController"> <children> <Button fx:id="myButton" mnemonicParsing="false" text="Button" /> </children> </StackPane> As you can see, the name of the controller class has been added to the root object: fx:controller="simple.SimpleController" Coding the controller class In your favorite IDE, create an empty SimpleController.java class. Now what does a controller class looks like? What should we put inside? Well - SceneBuilder will help you there: it will show you an example of controller skeleton tailored for your FXML. In the menu bar, invoke View > Show Sample Controller Skeleton. A popup appears, displaying a suggestion for the controller skeleton: copy the code displayed there, and paste it into your SimpleController.java: /** * Sample Skeleton for "simple.fxml" Controller Class * Use copy/paste to copy paste this code into your favorite IDE **/ package simple; import java.net.URL; import java.util.ResourceBundle; import javafx.fxml.FXML; import javafx.fxml.Initializable; import javafx.scene.control.Button; public class SimpleController implements Initializable { @FXML // fx:id="myButton" private Button myButton; // Value injected by FXMLLoader @Override // This method is called by the FXMLLoader when initialization is complete public void initialize(URL fxmlFileLocation, ResourceBundle resources) { assert myButton != null : "fx:id=\"myButton\" was not injected: check your FXML file 'simple.fxml'."; // initialize your logic here: all @FXML variables will have been injected } } Note that the code displayed by SceneBuilder is there only for educational purpose: SceneBuilder does not create and does not modify Java files. This is simply a hint of what you can use, given the fx:id present in your FXML file. You are free to copy all or part of the displayed code and paste it into your own Java class. Now at this point, there only remains to add our logic to the controller class. Quite easy: in the initialize method, I will register an action handler with my button: () { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... -- ... // initialize your logic here: all @FXML variables will have been injected myButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { System.out.println("That was easy, wasn't it?"); } }); ... That's it - if you now compile everything in your IDE, and run your application, clicking on the button should print a message on the console! Summary What happens is that in Main.java, the FXMLLoader will load simple.fxml from the jar/classpath, as specified by 'FXMLLoader.load(Main.class.getResource("simple.fxml"))'. When loading simple.fxml, the loader will find the name of the controller class, as specified by 'fx:controller="simple.SimpleController"' in the FXML. Upon finding the name of the controller class, the loader will create an instance of that class, in which it will try to inject all the objects that have an fx:id in the FXML. Thus, after having created '<Button fx:id="myButton" ... />', the FXMLLoader will inject the button instance into the '@FXML private Button myButton;' instance variable found on the controller instance. This is because The instance variable has an @FXML annotation, The name of the variable exactly matches the value of the fx:id Finally, when the whole FXML has been loaded, the FXMLLoader will call the controller's initialize method, and our code that registers an action handler with the button will be executed. For a complete example, take a look at the HelloWorld SceneBuilder sample. Also make sure to follow the SceneBuilder Get Started guide, which will guide you through a much more complete example. Of course, there are more elegant ways to set up an Event Handler using FXML and SceneBuilder. There are also many different ways to work with the FXMLLoader. But since it's starting to be very late here, I think it will have to wait for another post. I hope you have enjoyed the tour! --daniel

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  • If a raid controller changes, are the drives still usable without re-formatting?

    - by Jeremy
    I've been wanting to do a raid 1 setup in my home with a pair of sata drives. Someone told me that if the controller fails, you can't just get a new controller because you'll have to reformat the drives. Or is that true only in some implementations? I was originally just looking at an onboard raid controller, or an entry level nas drvice like the intel SS4200-E, but If the hardware (controller) ever fails, will I be out of luck accessing the data if I can't get the exact same hardware to replace it?

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  • MVC : Does Code to save data in cache or session belongs in controller?

    - by newbie
    I'm a bit confused if saving the information to session code below, belongs in the controller action as shown below or should it be part of my Model? I would add that I have other controller methods that will read this session value later. public ActionResult AddFriend(FriendsContext viewModel) { if (!ModelState.IsValid) { return View(viewModel); } // Start - Confused if the code block below belongs in Controller? Friend friend = new Friend(); friend.FirstName = viewModel.FirstName; friend.LastName = viewModel.LastName; friend.Email = viewModel.UserEmail; httpContext.Session["latest-friend"] = friend; // End Confusion return RedirectToAction("Home"); } I thought about adding a static utility class in my Model which does something like below, but it just seems stupid to add 2 lines of code in another file. public static void SaveLatestFriend(Friend friend, HttpContextBase httpContext) { httpContext.Session["latest-friend"] = friend; } public static Friend GetLatestFriend(HttpContextBase httpContext) { return httpContext.Session["latest-friend"] as Friend; }

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  • UITabbar without controller

    - by Etienne
    Hello. I have a simple app where the only view controller has an outlet to a UITabBar. It also implements UITabBarDelegate and is set as the delegate for the UITabBar: @interface TheMainViewController : UIViewController <UITabBarDelegate> { IBOutlet UITabBar *theTabBar; } I implemented the following method Which gets called whenever any of my 4 UITabBarItems get tapped. I tried just doing something really simple: - (void)tabBar:(UITabBar *)tabBar didSelectItem:(UITabBarItem *)item { tabBar.selectedItem = [tabBar.items objectAtIndex:0]; return; } In theory, it should always stay selected on my first tab and it works perfectly when I just tap any UITabBarItem (nothing happens, the first one always stays selected). But when I touch a UITabBarItem and hold it (not taking my finger off) the selection changes anyway ! Debugging, everything gets called properly. It's like changing the selectedItem property doesn't have any effect is the user still has the item "down" (with his finger on it). What would be a good workaround? I tried overloading UITabBar and messing with touchesBegan and touchesEnd but they don't even get called. Same with UITabBarItem. Oh and please don't suggest using a UITabBarController as it is not flexible enough for my application. So frustrating....thanks!

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  • Android custom media controller using vidtry

    - by Mathias Lin
    I want to use a custom media controller in my Android app and therefore looking at the vidtry code (http://github.com/commonsguy/vidtry), especially Player.java: The sample works fine as it comes. But I want the sample to play the fixed video automatically on app startup (so I don't want to enter a URL). I added: @Override public void onStart() { super.onStart(); address.setText("/sdcard/mydata/category/1/video_agkkr6me.mp4"); go.setEnabled(true); onGo.onClick(go); } Strange thing here is that if I run the app, the audio of the video plays but the image doesn't show. Everything else works fine (progress bar, etc.). I can't figure out the difference between the manual click on the go-button and the programmatic one. I looked at the code and didn't see any difference that might occur between manual and programmatic click. I checked if any elements (esp. surface) might be hidden, but it's not. I even tried a surface.setVisibility(View.INVISIBLE); surface.setVisibility(View.VISIBLE); in case some issue with the redrawing, but no difference. The video image does show when I manually hit the go button, but just not on start up automatically.

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  • How Can i reload data in tableview in view controller in iphone

    - by Pugal Devan
    Hi, I am new to iphone development. I have created 5 buttons in the view. On clicking the buttons it navigates to the corresponding views. On clicking the "News" button it navigates and displayed the parsing details in the table view.(This table view, I have created View controller and added table view using Interface Builder and i have set all the properties.) and i go to another button and comes back to the "News" button, every time parsing will happened.How to avoid the multiple parsing when i come back to the button. i have tried this one and my code is, - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; static int i; if(i == 0) { NSString * path = @"http://www.AAAAAAAAAAAAAAAA.com"; [self parseXMLFileAtURL:path]; i++; } [self.newsTable reloadData]; } } Now the parsing is happened only time but the datas are doesnt displayed. My problem is the tableview doesnot reload. newsTable is the instance of the Tableview. How can i achieve this. Please help me out. Thanks.

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  • Implement System.Web.Caching.Cache Object in a controller to cache specific query

    - by Julien
    Hello World! I'm Julien and I have a question is it correct to implement my caching object like this in my controller : public class HomeController : BaseController { public static Cache cachingControl = new Cache(); ... And I Use it like this : public ActionResult Home() { IndexViewData view = new IndexViewData(); view.UserId = UserId; if (cachingControl.Get("viewHome") != null) { view = (IndexViewData)cachingControl.Get("viewHome"); } else { view.allAdsList = AllAds(5000, 0); if (Request.QueryString["voirTous"] != null) view.loadGeneral(true); else view.loadGeneral(false); cachingControl.Insert("viewHome", view); } view.adsList = SetupSearch(5, false, 0); return View(view); } But When I Call this line : if (cachingControl.Get("viewHome") != null) { They trow me the error NullErrorException But I know it can be null this is why i'm put this condition to Do you have an alternative or a tips for me thank you! P.S.: I Know that the code is weird :P but I must to support it ... Julien

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  • iphone cannot rotate views in TabBar controller

    - by Luc
    Hello, I am working on an application that consists of a TabBar controller. Within on of its tab, I have a subclass of UITableViewController, within this list I have a Core-plot graph in the first cell and some other data in the 4 following cells. When I return YES in the shouldAutorotateToInterfaceOrientation method, I would expect the autoresizing of the list view to happen, but... nothing. When I add some log in the willRotateToInterfaceOrientation method, they are not displayed. Is there something I missed ? Thanks a lot, Luc // Override to allow orientations other than the default portrait orientation. - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { // Return YES for supported orientations //return (interfaceOrientation == UIInterfaceOrientationPortrait); NSLog(@"Orientation"); return YES; } - (void)willRotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation duration:(NSTimeInterval)duration { [super willRotateToInterfaceOrientation:toInterfaceOrientation duration:duration]; NSLog(@"Rotating"); if (toInterfaceOrientation == UIInterfaceOrientationLandscapeRight) { NSLog(@"view land:%@", self.view); } if (toInterfaceOrientation == UIInterfaceOrientationPortrait) { NSLog(@"view portrait:%@", self.view); } }

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  • Nav Controller, UITableViewController, UITextField to become firstResponder?

    - by Daniel Granger
    I have a core data application which uses a navigation controller to drill down to a detail view and then if you edit one of the rows of data in the detail view you get taken to an Edit View for the that single line, like in Apples CoreDataBooks example! The edit view is a UITableviewController which creates its table with a single section single row and a UITextfield in the cell, programatically. What I want to happen is when you select a row to edit and the edit view is pushed onto the nav stack and the edit view is animated moving across the screen, I want the textfield to be selected as firstResponder so that the keyboard is already showing as the view moves across the screen to take position. Like in the Contacts app or in the CoreDataBooks App. I currently have the following code in my app which causes the view to load and then you see the keyboard appear (which isn't what I want, I want the keyboard to already be there) - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; [theTextField becomeFirstResponder]; } You can't put this in -viewWillAppear as the textfield hasn't been created yet so theTextField is nil. In the CoreDataBooks App where they achieve what i want they load there tableview from a nib so they use the same code but in -viewWillAppear as the textfield has already been created! Is there anyway of getting around this without creating a nib, I want to keep the implementation programatic to enable greater flexibility. Many Thanks

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  • .net mvc pass dictionary data from view to controller

    - by Wei Ma
    A while ago, I was trying to pass a dictionary data from my view to my controller. And I was able to do so after googling on the net(remember it was one of scott hanselman's posts). The solution I had was something like <%for(int index=0; index<Model.Count(); index++){ var property= Model.ElementAt(index);%> <input type="hidden" name="<%="properties["+index+"].Key"%>"/> <input type="hidden" name="<%="properties["+index+"].Value"%>"/> <%}%> public ActionResult Process(IDictionary<string,string> properties) { doSomething(); return View(); } The code worked for awhile and then I did some refactoring and got rid of this chunk of code. Today, I ran into a situation in which I would like to pass a dictionary again. But no matter how hard I try, the properties parameter received by the action was always null. I tried the above code and <%for(int index=0; index<Model.Count(); index++){ var property= Model.ElementAt(index);%> <input type="hidden" name="<%="properties.Keys["+index+"]"%>"/> <input type="hidden" name="<%="properties.Values["+index+"]"%>"/> <%}%> Neither code worked. I googled again but couldn't find the post that helped me before. Can someone point out what I did wrong? thanks a million.

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  • Backbone Model fetched from Lithium controller is not loaded properly in bb Model

    - by Nilesh Kale
    I'm using backbone.js and Lithium. I'm fetching a model from the server by passing in a _id that is received as a hidden parameter on the page. The database MongoDB has stored the data correctly and can be viewed from console as: { "_id" : ObjectId("50bb82694fbe3de417000001"), "holiday_name" : "SHREE15", "description": "", "star_rating" : "3", "holiday_type" : "family", "rooms" : "1", "adults" : "2", "child" :"0", "emails" : "" } The Lithium Model class is so: class Holidays extends \lithium\data\Model { public $validates = array( 'holiday_name' => array( array( 'notEmpty', 'required' => true, 'message' => 'Please key-in a holiday name! (eg. Family trip for summer holidays)' ))); } The backbone Holiday model is so: window.app.IHoliday = Backbone.Model.extend({ urlRoot: HOLIDAY_URL, idAttribute: "_id", id: "_id", // Default attributes for the holiday. defaults: { }, // Ensure that each todo created has `title`. initialize: function(props) { }, The code for backbone/fetch is: var Holiday = new window.app.IHoliday({ _id: holiday_id }); Holiday.fetch( { success: function(){ alert('Holiday fetched:' + JSON.stringify(Holiday)); console.log('HOLIDAY Fetched: \n' + JSON.stringify(Holiday)); console.log('Holiday name:' + Holiday.get('holiday_name')); } } ); Lithium Controller Code is: public function load($holiday_id) { $Holiday = Holidays::find($holiday_id); return compact('Holiday'); } PROBLEM: The output of the backbone model fetched from server is as below and the Holiday model is not correctly 'formed' when data returns into backbone Model: HOLIDAY Fetched: {"_id":"50bb82694fbe3de417000001","Holiday":{"_id":"50bb82694fbe3de417000001","holiday_name":"SHREE15","description":"","star_rating":"3","holiday_type":"family","rooms":"1","adults":"2","child":"0","emails":""}} iplann...view.js (line 68) Holiday name:undefined Clearly there is some issue when the data is passed/translated from Lithium and loaded up as a model into backbone Holiday model. Is there something very obviously wrong in my code?

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  • Getting a "No default module defined for this application" exception while running controller unit t

    - by Doron
    I have an application with the default directory structure, for an application without custom modules (see structure figure at the end). I have written a ControllerTestCase.php file as instructed in many tutorials, and I've created the appropriate bootstrap file as well (once again, see figures at the end). I've written some model tests which run just fine, but when I started writing the index controller test file, with only one test in it, with only one line in it ("$this-dispatch('/');"), I'm getting the following exception when running phpunit (but navigating with the browser to the same location - all is good and working): 1) IndexControllerTest::test_indexAction_noParams Zend_Controller_Exception: No default module defined for this application Why is this ? What have I done wrong ? Appendixes: Directory structure: -proj/ -application/ -controllers/ -IndexController.php -ErrorController.php -config/ -layouts/ -models/ -views/ -helpers/ -scripts/ -error/ -error.phtml -index/ -index.phtml -Bootstrap.php -library/ -tests/ -application/ -controllers/ -IndexControllerTest.php -models/ -bootstrap.php -ControllerTestCase.php -library/ -phpunit.xml -public/ -index.php (Basically I have some more files in the models directory, but that's not relevant to this question.) application.ini file: [production] phpSettings.display_startup_errors = 0 phpSettings.display_errors = 0 includePaths.library = APPLICATION_PATH "/../library" bootstrap.path = APPLICATION_PATH "/Bootstrap.php" bootstrap.class = "Bootstrap" appnamespace = "My" resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" resources.frontController.params.displayExceptions = 0 resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts/" resources.view[] = phpSettings.date.timezone = "America/Los_Angeles" [staging : production] [testing : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 [development : production] phpSettings.display_startup_errors = 1 phpSettings.display_errors = 1 resources.frontController.params.displayExceptions = 1 tests/application/bootstrap.php file <?php error_reporting(E_ALL); // Define path to application directory defined('APPLICATION_PATH') || define('APPLICATION_PATH', realpath(dirname(__FILE__) . '/../../application')); // Define application environment defined('APPLICATION_ENV') || define('APPLICATION_ENV', (getenv('APPLICATION_ENV') ? getenv('APPLICATION_ENV') : 'testing')); // Ensure library/ is on include_path set_include_path(implode(PATH_SEPARATOR, array( realpath(APPLICATION_PATH . '/../library'), // this project' library get_include_path(), ))); /** Zend_Application */ require_once 'Zend/Application.php'; require_once 'ControllerTestCase.php';

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  • Java JSP/Servlet: controller servlet throwing the famous stack overflow

    - by NoozNooz42
    I've read several docs and I don't get it: I know I'm doing something wrong but I don't understand what. I've got a website that is entirely dynamically generated: there's hardly any static content at all. So, trying to understand JSP/Servlet, I've written my own "front controller" intercepting every single query, it looks like this: <servlet-mapping> <servlet-name>defaultservlet</servlet-name> <url-pattern>/*</url-pattern> </servlet-mapping> Basically I want any user request, like: example.org example.org/bar example.org/foo.html to all go through a default servlet which I've written. The servlet then examines the URI and find to which .jsp the request must be dispatched, and then does, after having set all the attributes correctly, a: RequestDispatcher dispatcher = getServletContext().getRequestDispatcher("/WEB-INF/jsp/index.jsp"); dispatcher.forward(req, resp); When I'm using a url-pattern (in web.xml) like, say, *.html, everything works fine. But when I change it to /* (to really intercept everything), I enter an endless loop and it ends up with a... StackOverflow :) When the request is dispatched, is the URI ".../WEB-INF/jsp/index.jsp" itself matched by the web.xml filter /* that I set? How should I do if I want to intercept everything using a /* url-pattern and yet be able to dispatch/forward/? I'm not asking about specs/Javadocs here: I'm really confused about the bigger picture and I'd need some explanation as to what could be going on. Am I not supposed to intercept really everything? If I can intercept everything, what should I be aware of regarding forwarding/dispatching?

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  • How to get error text in controller from BindingResult

    - by Mike
    I have an controller that returns JSON. It takes a form, which validates itself via spring annotations. I can get FieldError list from BindingResult, but they don't contain the text that a JSP would display in the tag. How can I get the error text to send back in JSON? @RequestMapping(method = RequestMethod.POST) public @ResponseBody JSONResponse submit(@Valid AnswerForm answerForm, BindingResult result, Model model, HttpServletRequest request, HttpServletResponse response) { if (result.hasErrors()) { response.setStatus(HttpServletResponse.SC_BAD_REQUEST); JSONResponse r = new JSONResponse(); r.setStatus(JSONResponseStatus.ERROR); //HOW DO I GET ERROR MESSAGES OUT OF BindingResult??? } else { JSONResponse r = new JSONResponse(); r.setStatus(JSONResponseStatus.OK); return r; } } JSONREsponse class is just a POJO public class JSONResponse implements Serializable { private JSONResponseStatus status; private String error; private Map<String,String> errors; private Map<String,Object> data; ...getters and setters... } Calling BindingResult.getAllErrors() returns an array of FieldError objects, but it doesn't have the actual errors.

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  • Optimizing C# code in MVC controller

    - by cc0
    I am making a number of distinct controllers, one relating to each stored procedure in a database. These are only used to read data and making them available in JSON format for javascripts. My code so far looks like this, and I'm wondering if I have missed any opportunities to re-use code, maybe make some help classes. I have way too little experience doing OOP, so any help and suggestions here would be really appreciated. Here is my generalized code so far (tested and works); using System; using System.Configuration; using System.Web.Mvc; using System.Data; using System.Text; using System.Data.SqlClient; using Prototype.Models; namespace Prototype.Controllers { public class NameOfStoredProcedureController : Controller { char[] lastComma = { ',' }; String oldChar = "\""; String newChar = "&quot;"; StringBuilder json = new StringBuilder(); private String strCon = ConfigurationManager.ConnectionStrings["SomeConnectionString"].ConnectionString; private SqlConnection con; public StoredProcedureController() { con = new SqlConnection(strCon); } public string do_NameOfStoredProcedure(int parameter) { con.Open(); using (SqlCommand cmd = new SqlCommand("NameOfStoredProcedure", con)) { cmd.CommandType = CommandType.StoredProcedure; cmd.Parameters.AddWithValue("@parameter", parameter); using (SqlDataReader reader = cmd.ExecuteReader()) { while (reader.Read()) { json.AppendFormat("[{0},\"{1}\"],", reader["column1"], reader["column2"]); } } con.Close(); } if (json.Length.ToString().Equals("0")) { return "[]"; } else { return "[" + json.ToString().TrimEnd(lastComma) + "]"; } } //http://host.com/NameOfStoredProcedure?parameter=value public ActionResult Index(int parameter) { return new ContentResult { ContentType = "application/json", Content = do_NameOfStoredProcedure(parameter) }; } } }

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  • Custom back button click event on pushed view controller

    - by TechFusion
    Hello, I have pushed view controller and load WebView and Custom rectangular rounded button on right down left corner into view using programmatic way. -(void)loadView { CGRect frame = CGRectMake(0.0, 0.0, 480, 320); WebView = [[[UIWebView alloc] initWithFrame:frame] autorelease]; WebView.backgroundColor = [UIColor whiteColor]; WebView.scalesPageToFit = YES; WebView.autoresizingMask = (UIViewAutoresizingFlexibleWidth | UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleLeftMargin | UIViewAutoresizingFlexibleTopMargin); WebView.autoresizesSubviews = YES; WebView.exclusiveTouch = YES; WebView.clearsContextBeforeDrawing = YES; self.roundedButtonType = [[UIButton buttonWithType:UIButtonTypeRoundedRect] retain]; self.roundedButtonType.frame = CGRectMake(416.0, 270.0, 44, 19); [self.roundedButtonType setTitle:@"Back" forState:UIControlStateNormal]; self.roundedButtonType.backgroundColor = [UIColor grayColor]; [self.roundedButtonType addTarget:self action:@selector(back:) forControlEvents:UIControlEventTouchUpInside]; self.view = WebView; [self.view addSubview: self.roundedButtonType ]; [WebView release]; } This is action that I have added as back button of navigation. -(void)back:(id)sender{ [self.navigationController popViewControllerAnimated:YES]; } -(void)viewDidUnload{ self.WebView = nil; self.roundedButtonType = nil; } -(void)dealloc{ [roundedButtonType release]; [super dealloc]; } Here, When Back button click then it is showing previous view but application got stuck in that view and GDB shows Program received signal :EXC_BAD_ACCESS message. how resolve this issue? Thanks,

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  • Problem pushing multiple view controllers onto navigation controller stack

    - by Jim
    Hi, I am trying to push three view controllers onto the navigation controller. [self.navigationController pushViewController:one animated:YES]; [self.navigationController pushViewController:two animated:YES]; [self.navigationController pushViewController:three animated:YES]; The desired behavior is that view three will show, and when the back button is pressed it will go to view two and then to view one... What actually happens is that view one is visible and pressing back goes to view two and then back again it goes to view one. Which is to say that view one is shown instead of view three. Very strangely, looking at the viewController array of the navigationController after the calls above show the right entries, and looking at the visibleViewController property shows that it has view three in it... even though view one is visible. If i navigate to a sub view from the visible view one (that shows in the place of view three) and press back from that sub view... it goes to view three. It looks like it is showing view one, but knows it is on view three... I am completely confused... any ideas? Jim

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  • Controller with unknown number of parameters?

    - by StackPointer
    Greetings! I'm doing a Form on ASP.NET MVC 2, in my view I have a TextBox for the name, and two buttons. One of the buttons is for submit, and the other one have a function in JS, that add's another textbox, and a drop down list. In the post controller action method, how do I get all the parameters? Here is the View Code: <body> <div> <%using (Html.BeginForm()) { %> New Insurance Type Name: <%=Html.TextBox("InsuranceName") %> <div id="InsuranceDetails"/> </div> <div id="Buttons"> <input type="button" onclick="AddFieldForm()" value="Add Field" /> <p /> <input type="submit" value="Submit" /> <%} %> </div> </body>

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