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  • Gerrit ssh key setup on windows server

    - by hotpotato
    I am attempting to configure google's 'Gerrit' code review web app on a Windows server 2008 virtual machine on our internal network. We are using Apache Tomcat (6.0.36) to host the web app and have deployed the gerrit.war to tomcats webapp folder, setup the context.xml, web.xml etc for the web app correctly i believe. However when i startup Tomcat using the $CATALINA_HOME/bin/startup.bat i get the following message in the tomcat logs: *Dec 07, 2012 1:03:54 PM org.apache.catalina.core.StandardContext listenerStart SEVERE: Exception sending context initialized event to listener instance of class com.google.gerrit.httpd.WebAppInitializer com.google.inject.CreationException: Guice creation errors:* 1) No SSH keys under C:\Gerrit\config\etc while locating com.google.gerrit.sshd.HostKeyProvider at com.google.gerrit.sshd.SshModule.configure(SshModule.java:90) I have created a is_rsa.pub SSH key and placed it in the specified directory to no avail. I have been googling this for about a week now and can't seem to find any information about the file or format it is expecting... documentation on setting gerrit up on windows seems hard to come by! Can anyone provide useful information about how to correctly configure a host SSH key in this context?

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  • Access keystore on Sun ONE Webserver 6.1 for 2048 bit key length SSL

    - by George Bailey
    We want to get 2048 bit key length CSR requests. The browser based GUI provides us with a 1024 bit CSR and I don't know how to change that. It seems that 1024 bit key lengths will no longer supported by SSL companies. (Lower cost options only support 2048 bit. Thawte who is much more expensive say they accept 1024 for only one or two year certificates, but not 3). The legacy systems in question are running Sun ONE Webserver 6.1. Upgrading would be time consuming and we would rather not have to do that right now. We will be phasing these out but it will take awhile, so... Got it!! http://middlewarekb.wordpress.com/2010/06/30/how-to-generate-2048-bit-keypair-using-sun-one-or-iplanet-6-1-servers/ It is for the same version webserver I am using. /opt/SUNWwbsvr/bin/https/admin/bin/certutil -R -s "CN=sub.domain.ext,OU=org unit,O=company name,L=city,ST=spelled state,C=US,E=email" -a -k rsa -g 2048 -v 12 -d /opt/SUNWwbsvr/alias -P https-sub.domain.ext-hostname- -Z SHA1 Previous efforts edited out.

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  • Touchpad does not respond when I am holding key on the keyboard

    - by Tadeck
    I am experiencing strange problem with using my touchpad and keyboard simultaneously under Windows 7. I have HP tx2550ew (convertible tablet), and when I hold some key under Windows 7 (eg. space, a, s etc.), the touchpad seems to be blocking. I spotted this while playing Counter Strike. I am not playing much games, and I haven't been playing CS since January, so I am not sure when it started behaving like that. I have tested it also outside the game - when I hold space (eg. when on some web page and entering text into input field) or some letter key, the cursor is not able to move. The problem seems to not be occuring when I hold Shift, Ctrl nor Alt. Did any of you experience similar problem? Do you know what may have caused this? Is there any way I could check what is wrong with my laptop? I have been looking for a solution, but it seems I haven't been looking in right places. This is why I ask question here. Ps. I am unable to test whether this is touchpad-specific, because I have no mouse at my disposal at the moment (got used to touchpad so much I even find it more efficient and haven't been using a mouse with my laptop for months).

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  • Is this a legitimate registry key? (windows 7)

    - by Keyes
    In hkey_local_machine/software/classes I found some registry keys named msime.taiwan, msime.japan and a couple others with similar names, except with a number at the end of, so there was 4 keys altogether. From what I know itmcoulc be associated with a thing in windows that lets you write japanese characters or whatever. I also found a macaffee page, , which seemed dated but it said the key is created by a virus named w32 virut. Just wondering is this a legit key? I found it on another pc and both pcs show when exported to a .txt show it was last written to in 2009. Here is the reg query for the 4 keys. (added lines to differentiate them.) HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Japan (Default) REG_SZ Microsoft IME (Japanese) HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Japan\CLSID (Default) REG_SZ {6A91029E-AA49-471B-AEE7-7D332785660D} HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Japan\CurVer (Default) REG_SZ MSIME.Japan.11 HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Japan.11 (Default) REG_SZ Microsoft IME (Japanese) HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Japan.11\CLSID (Default) REG_SZ {6A91029E-AA49-471B-AEE7-7D332785660D} HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Taiwan\CLSID (Default) REG_SZ {F407D01A-0BCB-4591-9BD6-EA4A71DF0799} HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Taiwan\CurVer (Default) REG_SZ MSIME.Taiwan.8 HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Taiwan.8 (Default) REG_SZ IMTCCORE HKEY_LOCAL_MACHINE\Software\Classes\MSIME.Taiwan.8\CLSID (Default) REG_SZ {F407D01A-0BCB-4591-9BD6-EA4A71DF0799}

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  • NHibernate Legacy Database Mappings Impossible?

    - by Corey Coogan
    I'm hoping someone can help me with mapping a legacy database. The problem I'm describing here has plagued others, yet I was unable to find a real good solution around the web. DISCLAIMER: this is a legacy DB. I have no control over the composite keys. They suck and can't be changed no matter much you tell me they suck. I have 2 tables, both with composite keys. One of the keys from one table is used as part of the key to get a collection from the other table. In short, the keys don't fully match between the table. ClassB is used everywhere I would like to avoid adding properties for the sake of this mapping if possible. public class ClassA { //[PK] public string SsoUid; //[PK] public string PolicyNumber; public IList<ClassB> Others; //more properties.... } public class ClassB { //[PK] public string PolicyNumber; //[PK] public string PolicyDateTime; //more properties } I want to get an instance of ClassA and get all ClassB rows that match PolicyNumber. I am trying to get something going with a one-to-many, but I realize that this may technically be a many-to-many that I am just treating as one-to-many. I've tried using an association class but didn't get far enough to see if it works. I'm new to these more complex mappings and am looking for advice. I'm open to pretty much any ideas. Thanks, Corey

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  • Save has_and_belongs_to_many link in basic RoR app

    - by Stéphane V
    I try to learn the has_and_belongs_to_many relationship between my 2 fresh new and simple models Product and Author, where a Product can have many authors and where author can have a lots of products. I wrote this : class Author < ActiveRecord::Base has_and_belongs_to_many :products end class Product < ActiveRecord::Base has_and_belongs_to_many :authors end In the partial form of view for the products, I have : <p>Products</p> <%= collection_select(:product, :author_ids, @authors, :id, :name, :prompt => " ", :multiple => true) %> but when I hit the update button, I get this strange message I can't resolve myself : NoMethodError in ProductsController#update undefined method `reject' for "1":String Rails.root: /home/stephane/www/HABTM Application Trace | Framework Trace | Full Trace app/controllers/products_controller.rb:63:in block in update' app/controllers/products_controller.rb:62:inupdate' Request Parameters: {"utf8"="✓", "_method"="put", "authenticity_token"="2GlTssOFjTVZ9BikrIFgx22cdTOIJuAB70liYhhLf+4=", "product"={"title"="Le trésor des Templiers", "original_title"="", "number"="1", "added_by"="", "author_ids"="1"}, "commit"="Update Product", "id"="1"} What's wrong ? Is there a problem with :product_ids... I saw on internet I had to pu a "s" but I'm not sure of what it represents.... How can I link the table authors_products to the key which is given back by the drop-down menu ? (here "author_ids"="1") Thx !

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  • Encrypting Files with AES, Encrypting Key with RSA - Am I on the right track?

    - by Shawn Steward
    Overview: I'm trying to design an application that will encrypt files to safely send through the mail. I'm planning on using AES/RijndaelManaged encryption from .Net to encrypt the files initially, using a randomly generated key using RNGCryptoServiceProvider. I'm then encrypting this random AES key with a RSA Public key. The receiver of the data is the only one with the RSA Private key to decrypt it. My question: Is this the proper way to do something like this? If so, is it safe to send this RSA-Encrypted key with the data since it requires the private key to decrypt? Also - when having the end user generate their Public/Private key pair, what is the best way to save the Private key? I do not want it to be only accessible from one machine, so I am trying to avoid using the user's key store. But MSDN says it is not safe to save the key to a file, so how else can you accomplish this?

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  • pass an ID with hyperlik but cant get this ID value from a fk in one table when i click in insert

    - by susan
    Something strange happened in my codes, actually I have a hyperlink that pass ID value in a query string to second page.in second page i have 2 sql datasource that both these sql datasources should get this id value and pass it to a filter parameter to show sth in datalist. so in another word I have a first page that has an hyperlink read ID value from a datasource and pass it to second page.its like below: <asp:HyperLink ID="HyperLink1" runat="server" NavigateUrl='<%# "~/forumpage.aspx?ID="+Eval("ID")%>'><%#Eval("title")%> </asp:HyperLink> then in second page i have one sql datasource with a query like this ...where ID=@id and get this id in query string from db.it work great . but i have problem with second sql datasource in second page it has a query sth like below:...forms.question_id=@id then in sql reference both to query string as ID that get by first page in hyperlink. but when i click in insert button show me error with fk. error:Error:The INSERT statement conflicted with the FOREIGN KEY constraint "FK_forumreply_forumquestions". The conflict occurred in database "forum", table "dbo.forumquestions", column 'ID'. The statement has been terminated. my tables (question(ID,user_id(fk),Cat_id(fk),title,bodytext) (reply(ID,userr_id(fk),questionn_id(fk),titlereply,bodytestreply); When by hand in cb i gave a number in questionn_id like 1 it show me successful but when it want read from a filter by datasource this field face with problem. plzzzz help i really need skip from this part.and cause i am new i guess I cant understand the logic way clearly. <asp:SqlDataSource ID="sdsreply" runat="server" ConnectionString="<%$ ConnectionStrings:forumConnectionString %>" SelectCommand="SELECT forumreply.ID, forumreply.userr_id, forumreply.questionn_id, forumreply.bodytextreply, forumreply.datetimereply, forumquestions.ID AS Expr1, forumusers.ID AS Expr2, forumusers.username FROM forumquestions INNER JOIN forumreply ON forumquestions.ID = forumreply.questionn_id INNER JOIN forumusers ON forumquestions.user_id = forumusers.ID AND forumreply.userr_id = forumusers.ID where forumreply.questionn_id=@questionn_id"> <SelectParameters> <asp:QueryStringParameter Name="questionn_id" QueryStringField="ID" /> </SelectParameters> </asp:SqlDataSource> it is cb for second page in insert button: { if (Session["userid"] != null) { lblreply.Text = Session["userid"].ToString(); } else { Session["userid"]=null; } if (HttpContext.Current.User.Identity.IsAuthenticated) { lblshow.Text = string.Empty; string d = HttpContext.Current.User.Identity.Name; lblshow.Text =d + "???? ??? ?????." ; foreach (DataListItem item in DataList2.Items) { Label questionn_idLabel = (Label)item.FindControl("questionn_idLabel"); Label userr_idLabel = (Label)item.FindControl("userr_idLabel"); lbltest.Text = string.Empty; lbltest.Text = questionn_idLabel.Text; lblreply.Text = string.Empty; lblreply.Text = userr_idLabel.Text; } } else { lblshow.Text = "??? ??? ??? ??? ?? ?? ?????? ???? ???? ???? ????? ??? ??? ? ??? ????? ???????."; } } { if(HttpContext.Current.User.Identity.IsAuthenticated) { if (Page.IsValid) { SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["forumConnectionString"].ConnectionString); try { con.Open(); SqlCommand cmd = new SqlCommand("insert into forumreply (userr_id,questionn_id,bodytextreply,datetimereply)values(@userr_id,@questionn_id,@bodytextreply,@datetimereply)", con); cmd.Parameters.AddWithValue("userr_id",lblreply.Text); cmd.Parameters.AddWithValue("questionn_id",lbltest.Text); cmd.Parameters.AddWithValue("bodytextreply",txtbody.Text); cmd.Parameters.AddWithValue("datetimereply",DateTime.Now ); cmd.ExecuteNonQuery(); } catch (Exception exp) { Response.Write("<b>Error:</b>"); Response.Write(exp.Message); } finally { con.Close(); } lblmsg.Text = "???? ??? ?? ?????? ??? ?????.thx"; lblshow.Visible = false; //lbltxt.Text = txtbody.Text; txtbody.Text = string.Empty; } } else { lblmsg.Text = string.Empty; Session["rem"] = Request.UrlReferrer.AbsoluteUri; Response.Redirect("~/login.aspx"); } }

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  • [PHP] Kohana-v3 ORM parent relationship

    - by VDVLeon
    Hi all, I just started with the version 3 of the Kohana Framework. I have worked a little with the $_has_many etc. Now I have the table pages. The primary key is pageID. The table has a column called parentPageID. Now I want to make a ORM model who, when accesed like this $page->parent->find() returns the page identified by parentPageID. I have the following already: // Settings protected $_table_name = 'pages'; protected $_primary_key = 'pageID'; protected $_has_one = array( 'parent' => array( 'model' => 'page', 'foreign_key' => 'parentPageID', ), ); But that does not work, it simply returns the first page from the table. Last query says this: SELECT `pages`.* FROM `pages` ORDER BY `pages`.`pageID` ASC LIMIT 1 Does somebody know how to solve this? I know this can: $parent = $page->parent->find($page->parentPageID); but it must be and can be cleaner (I think).

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  • Restricting Input in HTML Textboxes to Numeric Values

    - by Rick Strahl
    Ok, here’s a fairly basic one – how to force a textbox to accept only numeric input. Somebody asked me this today on a support call so I did a few quick lookups online and found the solutions listed rather unsatisfying. The main problem with most of the examples I could dig up was that they only include numeric values, but that provides a rather lame user experience. You need to still allow basic operational keys for a textbox – navigation keys, backspace and delete, tab/shift tab and the Enter key - to work or else the textbox will feel very different than a standard text box. Yes there are plug-ins that allow masked input easily enough but most are fixed width which is difficult to do with plain number input. So I took a few minutes to write a small reusable plug-in that handles this scenario. Imagine you have a couple of textboxes on a form like this: <div class="containercontent"> <div class="label">Enter a number:</div> <input type="text" name="txtNumber1" id="txtNumber1" value="" class="numberinput" /> <div class="label">Enter a number:</div> <input type="text" name="txtNumber2" id="txtNumber2" value="" class="numberinput" /> </div> and you want to restrict input to numbers. Here’s a small .forceNumeric() jQuery plug-in that does what I like to see in this case: [Updated thanks to Elijah Manor for a couple of small tweaks for additional keys to check for] <script type="text/javascript"> $(document).ready(function () { $(".numberinput").forceNumeric(); }); // forceNumeric() plug-in implementation jQuery.fn.forceNumeric = function () { return this.each(function () { $(this).keydown(function (e) { var key = e.which || e.keyCode; if (!e.shiftKey && !e.altKey && !e.ctrlKey && // numbers key >= 48 && key <= 57 || // Numeric keypad key >= 96 && key <= 105 || // comma, period and minus key == 190 || key == 188 || key == 109 || // Backspace and Tab and Enter key == 8 || key == 9 || key == 13 || // Home and End key == 35 || key == 36 || // left and right arrows key == 37 || key == 39 || // Del and Ins key == 46 || key == 45) return true; return false; }); }); } </script> With the plug-in in place in your page or an external .js file you can now simply use a selector to apply it: $(".numberinput").forceNumeric(); The plug-in basically goes through each selected element and hooks up a keydown() event handler. When a key is pressed the handler is fired and the keyCode of the event object is sent. Recall that jQuery normalizes the JavaScript Event object between browsers. The code basically white-lists a few key codes and rejects all others. It returns true to indicate the keypress is to go through or false to eat the keystroke and not process it which effectively removes it. Simple and low tech, and it works without too much change of typical text box behavior.© Rick Strahl, West Wind Technologies, 2005-2011Posted in JavaScript  jQuery  HTML  

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  • How do I store the OAuth v1 consumer key and secret for an open source desktop Twitter client without revealing it to the user?

    - by Justin Dearing
    I want to make a thick-client, desktop, open source twitter client. I happen to be using .NET as my language and Twitterizer as my OAuth/Twitter wrapper, and my app will likely be released as open source. To get an OAuth token, four pieces of information are required: Access Token (twitter user name) Access Secret (twitter password) Consumer Key Consumer Secret The second two pieces of information are not to be shared, like a PGP private key. However, due to the way the OAuth authorization flow is designed, these need to be on the native app. Even if the application was not open source, and the consumer key/secret were encrypted, a reasonably skilled user could gain access to the consumer key/secret pair. So my question is, how do I get around this problem? What is the proper strategy for a desktop Twitter client to protect its consumer key and secret?

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  • Caesar Cipher Program In C++ [migrated]

    - by xaliap81
    I am trying to write a caesar cipher program in c++. This is my codes template: int chooseKEY (){ //choose key shift from 1-26 } void encrypt (char * w, char *e, int key) { //Encryption function, *w is the text in the beginning, the *e is the encrypted text //Encryption in being made only in letters noy in numbers and punctuations // *e = *w + key } void decrypt (char * e, char *w, int key) { // Decryption function, *e is the text in the beginning, the *w is the decrypted text //Dencryption in being made only in letters no numbers and punctuations // *w = *e - key } void Caesar (char * inputFile, char * outputFile, int key, int mode) { // Read the inputfile which contains some data. If mode ==1 then the data is being //encrypted else if mode == 0 the data is being decrypted and is being written in //the output file } void main() { // call the Caesar function } The program has four functions, chooseKey function have to return an int as a shift key from 1-26. Encrypt function has three parameters, *w is the text in the beginning, *e is the encrypted text and the key is from the choosekey function.For encryption : Only letters have to be encrypted not numbers or punctuation and the letters are counting cyclic. Decrypt function has three parameters *e is the encrypted text, *w is the beginning text and the key. Caesar function has four parameters, inputfile which is the file that contains the beginning text, output file which contains the encrypted text, the key and the mode (if mode==1) encryption, (mode ==0) decryption. This is my sample code: #include <iostream> #include <fstream> using namespace std; int chooseKey() { int key_number; cout << "Give a number from 1-26: "; cin >> key_number; while(key_number<1 || key_number>26) { cout << "Your number have to be from 1-26.Retry: "; cin >> key_number; } return key_number; } void encryption(char *w, char *e, int key){ char *ptemp = w; while(*ptemp){ if(isalpha(*ptemp)){ if(*ptemp>='a'&&*ptemp<='z') { *ptemp-='a'; *ptemp+=key; *ptemp%=26; *ptemp+='A'; } } ptemp++; } w=e; } void decryption (char *e, char *w, int key){ char *ptemp = e; while(*ptemp){ if(isalpha(*ptemp)) { if(*ptemp>='A'&&*ptemp<='Z') { *ptemp-='A'; *ptemp+=26-key; *ptemp%=26; *ptemp+='a'; } } ptemp++; } e=w; } void Caesar (char *inputFile, char *outputFile, int key, int mode) { ifstream input; ofstream output; char buf, buf1; input.open(inputFile); output.open(outputFile); buf=input.get(); while(!input.eof()) { if(mode == 1){ encryption(&buf, &buf1, key); }else{ decryption(&buf1, &buf, key); } output << buf; buf=input.get(); } input.close(); output.close(); } int main(){ int key, mode; key = chooseKey(); cout << "1 or 0: "; cin >> mode; Caesar("test.txt","coded.txt",key,mode); system("pause"); } I am trying to run the code and it is being crashed (Debug Assertion Failed). I think the problem is somewhere inside Caesar function.How to call the encrypt and decrypt functions. But i don't know what exactly is. Any ideas?

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  • New ZFS Encryption features in Solaris 11.1

    - by darrenm
    Solaris 11.1 brings a few small but significant improvements to ZFS dataset encryption.  There is a new readonly property 'keychangedate' that shows that date and time of the last wrapping key change (basically the last time 'zfs key -c' was run on the dataset), this is similar to the 'rekeydate' property that shows the last time we added a new data encryption key. $ zfs get creation,keychangedate,rekeydate rpool/export/home/bob NAME PROPERTY VALUE SOURCE rpool/export/home/bob creation Mon Mar 21 11:05 2011 - rpool/export/home/bob keychangedate Fri Oct 26 11:50 2012 local rpool/export/home/bob rekeydate Tue Oct 30 9:53 2012 local The above example shows that we have changed both the wrapping key and added new data encryption keys since the filesystem was initially created.  If we haven't changed a wrapping key then it will be the same as the creation date.  It should be obvious but for filesystems that were created prior to Solaris 11.1 we don't have this data so it will be displayed as '-' instead. Another change that I made was to relax the restriction that the size of the wrapping key needed to match the size of the data encryption key (ie the size given in the encryption property).  In Solaris 11 Express and Solaris 11 if you set encryption=aes-256-ccm we required that the wrapping key be 256 bits in length.  This restriction was unnecessary and made it impossible to select encryption property values with key lengths 128 and 192 when the wrapping key was stored in the Oracle Key Manager.  This is because currently the Oracle Key Manager stores AES 256 bit keys only.  Now with Solaris 11.1 this restriciton has been removed. There is still one case were the wrapping key size and data encryption key size will always match and that is where they keysource property sets the format to be 'passphrase', since this is a key generated internally to libzfs and to preseve compatibility on upgrade from older releases the code will always generate a wrapping key (using PKCS#5 PBKDF2 as before) that matches the key length size of the encryption property. The pam_zfs_key module has been updated so that it allows you to specify encryption=off. There were also some bugs fixed including not attempting to load keys for datasets that are delegated to zones and some other fixes to error paths to ensure that we could support Zones On Shared Storage where all the datasets in the ZFS pool were encrypted that I discussed in my previous blog entry. If there are features you would like to see for ZFS encryption please let me know (direct email or comments on this blog are fine, or if you have a support contract having your support rep log an enhancement request).

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  • How to set ExecutionPolicy: access to registry key denied

    - by jrara
    I'm running Windows Server 2008 as admin and I tried to set ExecutionPolicy as Remotesigned for PowerShell v2 like this: Set-ExecutionPolicy RemoteSigned But I got this error: Set-ExecutionPolicy : Access to the registry key 'HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\PowerShell\1\ShellIds\Microsoft .PowerShell' is denied. At line:1 char:20 + Set-ExecutionPolicy <<<< RemoteSigned + CategoryInfo : NotSpecified: (:) [Set-ExecutionPolicy], UnauthorizedAccessException + FullyQualifiedErrorId : System.UnauthorizedAccessException,Microsoft.PowerShell.Commands.SetExecutionPolicyComma nd How to fix this?

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  • Invalid mak key Microsoft Office 2010 beta

    - by user23950
    I've registered a new email address on windows live just to get an activation key for Microsoft office 2010 beta. And I have downloaded the installer before. Do I have to download the installer that comes with the new activation just for me to be able to use it?

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  • Remapping the Windows key in Parallels

    - by Kaji
    I'm running XP on Parallels 4 for Mac, and it's working well enough, however one thing that's bothering me more and more as I go along is the way it constantly assumes every press of the command key means I want the start menu to come up. I've tried to remap it in the Parallels preferences, but all that does is allow me to create additional ways to call the start menu. Is there a setting either within XP or somewhere outside that I can set to discourage this behavior?

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  • Change Bitlocker to use the TPM plus a USB key and a PIN

    - by Christopher Edwards
    I have bitlocker running on Windows 7 (x86) on a Dell D630 laptop (it has a 1.2 TPM). It is running in transparent mode. I'd like to know how to configure it to use a PIN and a USB key as well, but I can't find anything that looks like it does this in the UI. Does anyone know how to do this? Do I have to remove bitlocker and re-enable it?? (This should be possible according to this - http://en.wikipedia.org/wiki/BitLocker_Drive_Encryption)

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  • What is the § ± key for on Mac keyboards?

    - by Pat Wallace
    Apple's keyboards have a new key, with § and ± symbols on it. Can somebody tell me what these keys are for, and where I should use them? I am aware the symbols have mathematical uses, but I assume they must do something important as well to be on the core keyboard. Or are they just the 'Scroll Lock' of the Apple world?

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  • ssh: "Agent admitted failure to sign using the key"

    - by takeshin
    I'm trying to set up password-less login with ssh on Ubuntu Server, but I keep getting: Agent admitted failure to sign using the key and prompt for password. I have generated new rsa keys. Before the system reboot it worked just fine. All the links lead me to this bug, but nothing works. SSH Agent is still not running. How to fix that? Maybe the files need specific permissions?

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  • Scan all domain workstations for specific registry key/environmental variable

    - by Trevor
    I'm looking for scripts or software that can scan workstations on a domain for a particular environmental variable (for interest, it was used to store the SOE build version) and generate a report. Accuracy is key, I don't want any workstations skipped or missed. And considering workstations will need to be powered on for anything to remotely read from the registry (and there's no guarantee they will be), that means something that can sit and run continuously for a while, updating its own records as it goes. Does anyone know of such a beast?

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  • Debian 7: "Failure of key exchange and association"

    - by pyrogoggles
    I'm installing Debian using the Live CD with GNOME and the non-free packages. The internet works just fine when using the live CD, but when you try to open the installer and select a network, it gives me the error of "Failure of key exchange and association". I've put everything in right, and tried multiple times. However, it never works. Am I just going to have to use ethernet to install? Thanks, people.

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  • what is PrintScreen Key of Mac?

    - by George2
    Hello everyone, I am using a MacBook Pro running Mac OS X 10.5. I am new to this development environment, and previously worked on Windows. I am wondering what is the PrintScreen key (generate a static image for screen snapshot) on the Mac? thanks in advance, George

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  • Ubuntu log in dialog hot key

    - by bguiz
    Hi, I am having trouble starting up Ubuntu (Karmic). Bascially I get to the bit where the log in dialog is supposed to appear, but it doesn't. Is there a hot key of some sort to force the login dialog to appear? Thanks! Full details here: http://ubuntuforums.org/showthread.php?p=9290145#post9290145

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