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  • Set a session hash outside of RoR program?

    - by Sindri Guðmundsson
    Hi, I have had my new rails program up for a few days now. I'm running it on Ubuntu 10.4 with apache2 in another location than the website it's made for (it's a standalone database application for physiotherapists). The people I made it for now want me to deploy it to the public part of their website, only with one change. Those who open it via the link in the public-part should not be able to click one button! I was thinking of doing something like this in my view: <% if session[:inside]%> <%=button_to 'Sækja mælitæki', @link_to_mt%> <%end%> How could I set session[:inside] only to true if the program was started from within the private part of the webpage? I thought of creating two new actions, the other would set session[:inside] to true and the other to false, but that seems to me like a security risk, is it not? BR, Sindri

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  • How do I quiet image_submit_tag from params hash?

    - by Alan S
    Does anyone know how to eliminate the x and y params when you use image_submit_tag with a get method? I have a simple search form, and using get to pass the value in the url. When I use image_submit_tag, it also appends the x and y coords, so I get urls like http://example.com?q=somesearchterm&x=15&y=12 When I have used submit_tag, I can use the :name = nil attribute (was in one of Ryan Bates' Railscasts), but it doesn't seem to work for image_submit_tag. Granted it doesn't affect functionality, but I don't need them and would like them quieted.

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  • Birthday effect - clarification needed plz.

    - by Mark
    Please help interpret the Birthday effect as described in Wikipedia: A birthday attack works as follows: 1) Pick any message m and compute h(m). 2) Update list L. Check if h(m) is in the list L. 3) if (h(m),m) is already in L, a colliding message pair has been found. else save the pair (h(m),m) in the list L and go back to step 1. From the birthday paradox we know that we can expect to find a matching entry, after performing about 2^(n/2) hash evaluations. Does the above mean 2^(n/2) iterations through the above entire loop (i.e. 2^(n/2) returns to step 1), OR does it mean 2^(n/2) comparisons to individual items already in L.

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  • What hash/map based programming language exist?

    - by Davorak
    Much like lisp is often considered a list based programming language what languages are considered map based? I remember reading about one a few years back, but can not longer find a reference to it. It looked something like: [if:test then:<code> else:<more code>] edit: and more where quoted code blocks which would be conditional evaluated. In this fashion if/cond and others would not be special form as they are in lisp/scheme.

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  • Can someone please clarify the Birthday Effect for me?

    - by Mark
    Please help interpret the Birthday effect as described in Wikipedia: A birthday attack works as follows: Pick any message m and compute h(m). Update list L. Check if h(m) is in the list L. if (h(m),m) is already in L, a colliding message pair has been found. else save the pair (h(m),m) in the list L and go back to step 1. From the birthday paradox we know that we can expect to find a matching entry, after performing about 2^(n/2) hash evaluations. Does the above mean 2^(n/2) iterations through the above entire loop (i.e. 2^(n/2) returns to step 1), OR does it mean 2^(n/2) comparisons to individual items already in L.

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  • When should I define an hash code function for my types?

    - by devoured elysium
    Is there any other reason for implementing an hash code function for my types other than allowing for good use of hash tables? Let's say I am designing some types that I intend to use internally. I know that types are "internal" to the system, and I also know I will never use those types in hash tables. In spite of this, I decide I will have to redefine the equals() method. Theory says I should also redefine the hash code method, but I can't see any reason why, in this case, I should do it. Can anyone point me out any other reason? This question can be rephrased to : in which situations should we implement a hash code method in our types. PS : I am not asking how to implement one. I am asking when.

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  • Union of two or more (hash)maps

    - by javierfp
    I have two Maps that contain the same type of Objects: Map<String, TaskJSO> a = new HashMap<String, TaskJSO>(); Map<String, TaskJSO> b = new HashMap<String, TaskJSO>(); public class TaskJSO { String id; } The map keys are the "id" properties. a.put(taskJSO.getId(), taskJSO); I want to obtain a list with: all values in "Map b" + all values in "Map a" that are not in "Map b". What is the fastest way of doing this operation? Thanks EDIT: The comparaison is done by id. So, two TaskJSOs are considered as equal if they have the same id (equals method is overrided). My intention is to know which is the fastest way of doing this operation from a performance point of view. For instance, is there any difference if I do the "comparaison" in a map (as suggested by Peter): Map<String, TaskJSO> ab = new HashMap<String, TaskJSO>(a); ab.putAll(b); ab.values() or if instead I use a set (as suggested by Nishant): Set s = new Hashset(); s.addAll(a.values()); s.addAll(b.values());

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  • How can I determine if a given git hash exists on a given branch?

    - by pinko
    Background: I use an automated build system which takes a git hash as input, as well as the name of the branch on which that hash exists, and builds it. However, the build system uses the hash alone to check out the code and build it -- it simply stores the branch name, as given, in the build DB metadata. I'm worried about developers accidentally providing the wrong branch name when they kick off a build, causing confusion when people are looking through the build history. So how can I confirm, before passing along the hash and branch name to the build system, that the given hash does in fact come from the given branch?

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  • What would a compress method do in a hash table?

    - by Bradley Oesch
    For an assignment I have to write the code for a generic Hash Table. In an example Put method, there are two lines: int hash = key.hashCode(); // get the hashcode of the key int index = compress(hash); // compress it to an index I was of the understanding that the hashCode method used the key to return an index, and you would place the key/value pair in the array at that index. But here we "compress" the hash code to get the index. What does this method do? How does it "compress" the hash code? Is it necessary and/or preferred?

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  • Join with three tables

    - by John
    Hello, For the join query below, I would like to pull some data from a third MySQL table called "comment." Each s.title has a corresponding s.submissionid. The field "submissionid" is also the in the table "comment." For each "submissionid" in the table "comment," I would like to count a field called "commentid." How can I do this? Thanks in advance, John $sqlStr = "SELECT s.loginid, s.title, s.url, s.displayurl, l.username FROM submission AS s, login AS l WHERE s.loginid = l.loginid ORDER BY s.datesubmitted DESC LIMIT 10";

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  • Counting and joining two tables

    - by Eikern
    Eventhosts – containing the three regular hosts and an "other" field (if someone is replacing them) eventid | host (SET[Steve,Tim,Brian,other]) ------------------------------------------- 1 | Steve 2 | Tim 3 | Brian 4 | other 5 | other Event id | other | name etc. ---------------------- 1 | | … 2 | | … 3 | | … 4 | Billy | … 5 | Irwin | … This query: SELECT h.host, COUNT(*) AS hostcount FROM host AS h LEFT OUTER JOIN event AS e ON h.eventid = e.id GROUP BY h.host Returns Steve | 1 Tim | 1 Brian | 1 other | 2 I want it to return Steve | 1 Tim | 1 Brian | 1 Billy | 1 Irwin | 1 OR Steve | | 1 Tim | | 1 Brian | | 1 other | Billy | 1 other | Irwin | 1 Can someone tell me how I can achieve this or point me in a direction?

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  • LEFT OUTER JOIN SUM doubles problem

    - by Michael
    Hi I've got two tables: Table: Shopping shop_id shop_name shop_time 1 Brian 40 2 Brian 31 3 Tom 20 4 Brian 30 Table:bananas banana_id banana_amount banana_person 1 1 Brian 2 1 Brian I now want it to print: Name: Tom | Time: 20 | Bananas: 0 Name: Brian | Time: 101 | Bananas: 2 I used this code: $result = dbquery("SELECT tz.*, tt.*, SUM(shop_time) as shoptime, count(banana_amount) as bananas FROM shopping tt LEFT OUTER JOIN bananas tz ON tt.shop_name=tz.banana_person GROUP by banana_person LIMIT 40 "); while ($data5 = dbarray($result)) { echo 'Name: '.$data5["shop_name"].' | Time: '.$data5["shoptime"].' | Bananas: '.$data5["bananas"].'<br>'; } The problem is that I get this instead: Name: Tom | Time: 20 | Bananas: 0 Name: Brian | Time: 202 | Bananas: 6 I just don't know how to get around this.

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  • Codeigniter active record select, left join, count

    - by sea_1987
    Hi There, I have a form that shows results from a database query, these results can have many other assets ajoined to them and I wanting to find a way of showing how many assets each elemement has. For example my table is of areas of england an other table has where the users live I current have this code, $this->db->select('*'); $this->db->from('places'); $this->db->join('users, places.place_id = user.place_id, left'); $this->db->get(); The issue I am having is getting the query to return the place name and the number of users living in that place, it is possible?

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  • Rails 2.3.x, named_scope chaining with INNER JOIN complication

    - by randombits
    I have two hypothetical classes, Foo and Bar. Foo contains many Bars. Bar can only belong to one Foo. Ultimately the SQL query I'm trying to make happen looks like the following: SELECT * from bar INNER JOIN foo ON bar.foo_id = foo.id where bar.in_use = 0 and bar.customer_id = 1 and foo.category = 0 That query does what I need. Now I'm trying to break the problem down in Rails using chained named_scopes. First, the straight forward in_use and customer_id scopes I have set: named_scope :available, :conditions => { :in_use => 0 } named_scope :not_available, :conditions => { :in_use => 1 } named_scope :customer, lambda { |num| { :conditions => { :customer_id => num } } } Now the part I'm stuck at, is I'm trying to do something like this in my code: abar = Bar.available.customer(1).category(0) how and where do I put the category named_scope to make this work?

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  • How to Stich to Image objects in Java

    - by Imran
    Hi, I have a scenario in which i`m getting a number of tiles (e.g.12) from my mapping server. Now for buffering and offline functions I need to join them all back again so that we have to deal with 1 single image object instead of 12. I ve tried to do it without JAI my code is below. package imagemerge; import java.awt.*; import java.awt.image.*; import java.awt.event.*; public class ImageSticher extends WindowAdapter { Image tile1; Image tile2; Image result; ColorModel colorModel; int width,height,widthr,heightr; //int t1,t2; int t12[]; public ImageSticher() { } public ImageSticher (Image img1,Image img2,int w,int h) { tile1=img1; tile2=img2; width=w; height=h; colorModel=ColorModel.getRGBdefault(); } public Image horizontalStich() throws Exception { widthr=width*2; heightr=height; t12=new int[widthr * heightr]; int t1[]=new int[width*height]; PixelGrabber p1 =new PixelGrabber(tile1, 0, 0, width, height, t1, 0, width); p1.grabPixels(); int t2[]=new int[width*height]; PixelGrabber p2 =new PixelGrabber(tile2, 0, 0, width, height, t1, 0, width); p2.grabPixels(); int y, x, rp, rpi; int red1, red2, redr; int green1, green2, greenr; int blue1, blue2, bluer; int alpha1, alpha2, alphar; for(y=0;y<heightr;y++) { for(x=0;x<widthr;x++) { //System.out.println(x); rpi=y*widthr+x; // index of resulting pixel; rp=0; //initializing resulting pixel System.out.println(rpi); if(x<(widthr/2)) // x is less than width , copy first tile { //System.out.println("tile1="+x); blue1 = t1[rpi] & 0x00ff; // ERROR occurs here green1=(t1[rpi] >> 8) & 0x00ff; red1=(t1[rpi] >> 16) & 0x00ff; alpha1 = (t1[rpi] >> 24) & 0x00ff; redr = (int)(red1 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye redr = (redr < 0)?(0):((redr>255)?(255):(redr)); greenr = (int)(green1 * 1.0); // redr = (int)(red1 * 1.0); // greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr)); bluer = (int)(blue1 * 1.0); bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer)); alphar = 255; //resulting pixel computed rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff); } else // index is ahead of half way...copy second tile { blue2 = t2[rpi] & 0x00ff; // blue band bit of first tile green2=(t2[rpi] >> 8) & 0x00ff; red2=(t2[rpi] >> 16) & 0x00ff; alpha2 = (t2[rpi] >> 24) & 0x00ff; redr = (int)(red2 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye redr = (redr < 0)?(0):((redr>255)?(255):(redr)); greenr = (int)(green2 * 1.0); // redr = (int)(red2 * 1.0); // greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr)); bluer = (int)(blue2 * 1.0); bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer)); alphar = 255; //resulting pixel computed rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff); } t12[rpi] = rp; // copying resulting pixel in the result int array which will be converted to image } } MemoryImageSource mis; if (t12!=null) { mis = new MemoryImageSource(widthr, heightr, colorModel, t12, 0, widthr); result = Toolkit.getDefaultToolkit().createImage(mis); return result; } return null; } } now to check the my theory Im trying to join or stich two tiles horizontaly but im getting the error : java.lang.ArrayIndexOutOfBoundsException: 90000 at imagemerge.ImageSticher.horizontalStich(ImageSticher.java:69) at imageStream.ImageStream.getImage(ImageStream.java:75) at imageStream.ImageStream.main(ImageStream.java:28) is there some kind of limitation because when stiching two images of 300 x 300 horizontally it means the resulting image will be 600 x 300 ... that would make 180000 index size but its giving error at 90000, what am I doing wrong here

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  • Join Query returns empty result, unexpected result

    - by Abs
    Hello all, Can anyone explain why this query returns an empty result. SELECT * FROM (`bookmarks`) JOIN `tags` ON `tags`.`bookmark_id` = `bookmarks`.`id` WHERE `tag` = 'clean' AND `tag` = 'simple' In my bookmarks table, I have a bookmark with an id of 70 and in my tags table i have two tags 'clean' and 'simple' both that have the column bookmark_id as 70. I would of thought a result would have been returned? How can I remedy this so that I have the bookmark returned when it has a tag of 'clean' and 'simple'? Thanks all for any explanation and solution to this.

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  • Feeding a Drill Down Menu with categories, subcategories and subSubcategories from a database

    - by Hassan
    Hi everyone, I have a Drill Down menu and I want to have it gets its elements from a database, I am using php and MySQL and the table (categories) looks like this : http://yfrog.com/jctablehsj I can't figure out how I can extract these information in a way I could put it inside the Drill Down Menu ! I found the recursive method (with LEFT JOINs) and the nested method which I barely understood and again I couldn't apply it to the Drill Down Menu. I found that some people found out a solution with left join and group by but couldn't understand or copy their example ! I would be more than gratefull if you could give me the extact of the query. Thanks a lot for your hard work, Hassan

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  • Multiple join query in eSql

    - by Syma
    Hi guys, This is my first question in stackoverflow but really not the first time to get solution here. I am struggling with multiple join in entity framework 4. I have three tables (Accounts, Users and AccountUsers) that am finding difficult to query. What I want is to get all the users for the provided accountId including the account creator. I can get all the account users with no problem but the hard side for me is getting the account creator since it's not added to AccountUsers table. below is a quick preview how the tables are related. Accounts AccountId UserId (account creator) ...other columns Users UserId ...other columns AccountUsers AccountId UserId I would prefer the query to be esql, but Linq to Entities will do. I trust you guys on stackoverflow, so I know this won't take long to get the 'Answer' mark. Thanks for even reading.

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  • Drupal join on taxonomy terms

    - by ciscoheat
    I have a Drupal setup like this: Content type: Apartments Vocabulary: Areas, that can be used with Apartments. Content type: User profile, with a Content Taxonomy Field for Areas so users can select what areas they are interested in. I would like a view that shows all the user profiles that matches the apartments in their area. A "User profile <- Areas <- Apartments" join in other words. I've been mucking around with the views interface for a while but it's not clear to me how the relations can be setup to achieve this. Can someone give me a hint? In case this cannot be easily solved with views, what is a good way of doing it otherwise? Thanks for your help.

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  • Different ways to query this search in SQL?

    - by Bart Terrell
    I am teaching myself MS-SQL and I am trying to find different ways to find the Count of Paid and Unpaid Claims for 2012 grouped by Region from these 3 tables. If there is a returned date, the claim is unpaid if the returned date is null then the claim is paid. I will attach the code I have ran, but I am not sure if there are better ways to do it. Thanks. Here is the code: SET dateformat ymd; CREATE TABLE Claims ( ClaimID INT, SubID INT, [Claim Date] DATETIME ); CREATE TABLE Phoneship ( ClaimID INT, [Shipping Number] INT, [Claim Date] DATETIME, [Ship Date] DATETIME, [Returned Date] DATETIME ); CREATE TABLE Enrollment ( SubID INT, Enrollment_Date DATETIME, Channel NVARCHAR(255), Region NVARCHAR(255), Status FLOAT, Drop_Date DATETIME ); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (102, 201, '2011-10-13 00:00:00', '2011-10-14 00:00:00', NULL); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (103, 202, '2011-11-02 00:00:00', '2011-11-03 00:00:00', '2011-11-20 00:00:00'); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (103, 203, '2011-11-02 00:00:00', '2011-11-22 00:00:00', NULL); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (105, 204, '2012-01-16 00:00:00', '2012-01-17 00:00:00', NULL); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (106, 205, '2012-02-15 00:00:00', '2012-02-16 00:00:00', '2012-02-26 00:00:00'); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (106, 206, '2012-02-15 00:00:00', '2012-02-27 00:00:00', '2012-03-06 00:00:00'); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (107, 207, '2012-03-12 00:00:00', '2012-03-13 00:00:00', NULL); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (108, 208, '2012-05-11 00:00:00', '2012-05-12 00:00:00', NULL); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (109, 209, '2012-05-13 00:00:00', '2012-05-14 00:00:00', '2012-05-28 00:00:00'); INSERT INTO [Phoneship] ([ClaimID], [Shipping Number], [Claim Date], [Ship Date], [Returned Date]) VALUES (109, 210, '2012-05-13 00:00:00', '2012-05-30 00:00:00', NULL); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (101, 12345678, '2011-03-06 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (102, 12347190, '2011-10-13 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (103, 12348723, '2011-11-02 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (104, 12349745, '2011-11-09 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (105, 12347190, '2012-01-16 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (106, 12349234, '2012-02-15 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (107, 12350767, '2012-03-12 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (108, 12350256, '2012-05-11 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (109, 12347701, '2012-05-13 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (110, 12350256, '2012-05-15 00:00:00'); INSERT INTO [Claims] ([ClaimID], [SubID], [Claim Date]) VALUES (111, 12350767, '2012-06-30 00:00:00'); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12345678, '2011-01-05 00:00:00', 'Retail', 'Southeast', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12346178, '2011-03-13 00:00:00', 'Indirect Dealers', 'West', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12346679, '2011-05-19 00:00:00', 'Indirect Dealers', 'Southeast', 0, '2012-03-15 00:00:00'); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12347190, '2011-07-25 00:00:00', 'Retail', 'Northeast', 0, '2012-05-21 00:00:00'); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12347701, '2011-08-14 00:00:00', 'Indirect Dealers', 'West', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12348212, '2011-09-30 00:00:00', 'Retail', 'West', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12348723, '2011-10-20 00:00:00', 'Retail', 'Southeast', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12349234, '2012-01-06 00:00:00', 'Indirect Dealers', 'West', 0, '2012-02-14 00:00:00'); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12349745, '2012-01-26 00:00:00', 'Retail', 'Northeast', 0, '2012-04-15 00:00:00'); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12350256, '2012-02-11 00:00:00', 'Retail', 'Southeast', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12350767, '2012-03-02 00:00:00', 'Indirect Dealers', 'West', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12351278, '2012-04-18 00:00:00', 'Retail', 'Midwest', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12351789, '2012-05-08 00:00:00', 'Indirect Dealers', 'West', 0, '2012-07-04 00:00:00'); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12352300, '2012-06-24 00:00:00', 'Retail', 'Midwest', 1, NULL); INSERT INTO [Enrollment] ([SubID], [Enrollment_Date], [Channel], [Region], [Status], [Drop_Date]) VALUES (12352811, '2012-06-25 00:00:00', 'Retail', 'Southeast', 1, NULL); And Query1 SELECT Count(ClaimID) AS 'Paid Claim', (SELECT Count(ClaimID) FROM dbo.phoneship WHERE [returned date] IS NOT NULL) AS 'Unpaid Claim' FROM dbo.Phoneship WHERE [Returned Date] IS NULL GROUP BY claimid Query2 SELECT Count(*) AS 'Paid Claims', (SELECT Count(*) FROM dbo.Phoneship WHERE [Returned Date] IS NOT NULL) AS 'Unpaid Claims' FROM dbo.Phoneship WHERE [Returned Date] IS NULL; Query3 Select Distinct(C.[Shipping Number]), Count(C.ClaimID) AS 'COUNT ClaimID', A.Region, A.SubID From dbo.HSEnrollment A Inner Join dbo.Claims B On A.SubId = B.SubId Inner Join dbo.Phoneship C On B.ClaimID = C.ClaimID Where C.[Returned Date] IS NULL Group By A.Region, A.Subid, C.ClaimID, C.[Shipping Number] Order By A.Region

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  • SQL Server 2005 script with join across Database Servers

    - by Robin Day
    I have the following script which I use to give me a simple "diff" between tables on two different databases. (Note: In reality my comparison is on a lot more than just an ID) SELECT MyTableA.MyId, MyTableB.MyId FROM MyDataBaseA..MyTable MyTableA FULL OUTER JOIN MyDataBaseB..MyTable MyTableB ON MyTableA.MyId = MyTableB.MyId WHERE MyTableA.MyId IS NULL OR MyTableB.MyId IS NULL I now need to run this script on two databases that exist on different servers. At the moment my solution is to backup the database from one server, restore it to the other and then run the script. I'm pretty sure this is possible, however, is this likely to be a can of worms? This is a very rare task I need to perform and if it involves a large number of DB setting changes then I will probably stick to my backup method.

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  • Display user name in reference to user id in django template

    - by Ed
    I expect this is an easy question. For some reason, I don't have a solution yet. I have an object set from django reversion: version_list. Each object in the set has a user id attached to it. How do I grab the user names that correspond to the user ID's? To try to be clearer, if each object in version_list has a name, date, and user id, how can I join the version_list set with the user table to figure out what user id goes with which name? This is done in the view, or the template?

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  • Help with SQL Join on two tables

    - by bladefist
    I have two tables, one is a table of forum threads. It has a last post date column. Another table has PostID, UserId, and DateViewed. I want to join these tables so I can compare DateViewed and LastPostDate for the current user. However, if they have never viewed the thread, there will not be a row in the 2nd table. This seems easy but I cant wrap my head around it. Advice please. Thanks in advance.

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  • What is the problem with the logic in my UPDATE statement?

    - by Stefan Åstrand
    Hello, I would appreciate some help with an UPDATE statement. I want to update tblOrderHead with the content from tblCustomer where the intDocumentNo corresponds to the parameter @intDocumentNo. But when I run the my statement, the order table is only updated with the content from the first row of the customer table. What is the problem with my logic? I use Microsoft SQL Server. Thanks, Stefan UPDATE dbo.tblOrderHead SET dbo.tblOrderHead.intCustomerNo = @intCustomerNo , dbo.tblOrderHead.intPaymentCode = dbo.tblCustomer.intPaymentCode, dbo.tblOrderHead.txtDeliveryCode = dbo.tblCustomer.txtDeliveryCode, dbo.tblOrderHead.txtRegionCode = dbo.tblCustomer.txtRegionCode, dbo.tblOrderHead.txtCurrencyCode = dbo.tblCustomer.txtCurrencyCode, dbo.tblOrderHead.txtLanguageCode = dbo.tblCustomer.txtLanguageCode FROM dbo.tblOrderHead INNER JOIN dbo.tblCustomer ON dbo.tblOrderHead.intOrderNo = @intDocumentNo

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