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  • session is lost after successful login?

    - by sword101
    greetings all um using spring security 3.0.2,all the application pages are secured to see them you must be authenticated um using https protocol i have a strange problem that after successful login and got to the requested page when try to open any link to other pages in the application the session is invalidated or lost or what happened i don't know and the user become anonymous,and redirected to the login page and i got this from debugging: No HttpSession currently exists No SecurityContext was available from the HttpSession: null. A new one will be created. after reviewing the coe many times,nothing in the code is invalidating the session,any ideas why something like this might happen?

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  • Remote Server access/login problem

    - by shamim
    My OS is Windows Server 2008 Enterprise. I have installed SqlServer 2008. In network i want to access Other users Server,i have already enable remote access,when i try to login show bellow error **Connection can not TITLE: Connect to Server ------------------------------ Cannot connect to TECHNO009. ------------------------------ ADDITIONAL INFORMATION: Login failed for user 'TECHNO009\Guest'. (Microsoft SQL Server, Error: 18456) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&EvtSrc=MSSQLServer&EvtID=18456&LinkId=20476 ------------------------------ BUTTONS: OK ------------------------------** Several times i try to connect as windows and sqlServer Authentication mode.But i failed,Other users also try to connect with my server they also failed and get the same message. Why error occur ,How to solve it?

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  • Removing the email validation requirement - Login Toboggan

    - by Rob Orr
    I'm building a premium membership site where a visitor can purchase a role and gain access to the privileged content using ubercart. I've got all that working fine, but the last tiny snag that my client wants to remove is to remove the validation email requirement that's fired when someone signs up on the site in Login Toboggan (6.1.9). I've got nothing set that is forcing this extra step and I've come to believe that this may be a feature in Drupal (acquia distro 6.22) core for any user that registers. I was hoping that this module (login toboggan) would eliminate that step but I've not as of yet been able to do so. I can allow the newly registered user access by setting that in the module, but the notification and validation email requirement still remains. Can anyone recommend a way around this? I just want them to be able to come to the site purchase their membership without any validation/confirmation email. Is this possible? Thanks - Rob

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  • Script SQL Server login with Windows authentication without machine name

    - by Evgeny
    I want to write a SQL 2005 script to create a new login that uses Windows authentication. The Windows user is a local account (not a domain one). A local account with the same name exists on many SQL Server machines and I want to run the same script on all of them. It seemed simple enough: CREATE LOGIN [MyUser] FROM WINDOWS However, that doesn't work! SQL returns an error, saying Give the complete name: <domain\username>. Of course, I can do that for one machine and it works, but the same script will not work on other machines.

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  • how to check the login information for remote website with jQuery

    - by alhoseany
    hi, i have a form with 2 fields username: password: and a submit button. the user will enter his username and password for a remote website(not my website or my domain. eg. Gmail.com). i want once he click the submit button.a jQuery script check these login info on gmail.com and return back the result.they are wrong or working logins. and notify the user if it is wrong logins but if it is good working login info the form will submit. i don't know much jQuery but i am good with php. my search find that in order to do that i need to make cross-domain scripting by using php proxy between my jQuery script and the remote domain. i found also the simple php proxy. which looks great.but i dont know how to make the jQuery thing that connects all this together.

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  • FOSUserBundle: embedding the login form and choosing its template

    - by tirengarfio
    i want to insert the login form of FOSUserBundle in my template like this: <div id="sidebar"> {% render "FOSUserBundle::Security::login" %} </div> but not to render the template that is been calling in the code of loginAction() originally. I have thought I'd find useful the possibility of passing the template I want to render as a parameter as 'max' in this example: <div id="sidebar"> {% render "AcmeArticleBundle:Article:recentArticles" with {'max': 3} %} </div> Is that possible in symfony2? If not.. should I create another action for my bundle with the same code inside of loginAction? or should I modify the original loginAction code and write control structures? if(currentPage == 'home') renderResponse('template1') else renderResponse('template2')

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  • Login Functionality For Silverlight Application

    - by peter
    Hi All, I have a silverlight application that requires the user to login. The problem is when you hit the refresh button on the web page it reloads the site, and requires the user to login again. What I want it to do is act like ASP .NET where the user will remain logged in for 20 minutes even if they hit the refresh button. What mechanism is ASP .NET using to achieve this? Does it use session variables for instance, and how does it expire after 20 minutes? Thanks.

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  • .Net LoginControls - User can't logout in Firefox

    - by Jordan Foreman
    Basically, the logout link doesn't do anything, but only in Firefox. (I can login and out freely from other browsers) There really isn't a whole lot of information I can really give other than that, since I'm still new to this project and .net as a whole, and know almost nothing about the login controls. So if someone else has experienced a similar issue in the past, and can recognize the issue with the little info I have, that would be great! If not, sorry for the lack of depth, but its all I have. If it helps, here is the code for where the logout link is: <LoggedInTemplate> ... <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Anonymous/Login.aspx" /> </LoggedInTemplate>

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  • Struts2 Hibernate Login with User table and group table

    - by J2ME NewBiew
    My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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  • Ajax twice + facbook login/logout

    - by Devenv
    Hi, I have a very specific problem. The site I'm developing loads the FB connect button by ajax (it loads the box that includes FBC button). And when user logs in it loads instead of it the box with FB logout link. The problem is that FB requires to call FB.init() at the end of the body (when all the FB stuff is already on the page) and you can't do it twice as the second time is ignored. So what happens is - I do FB.init() inside the login box and FBC button works perfectly, but the logout link doesn't as FB.init() doesn't work there. The only solution I came up with is to place the login and logout buttons outside of ajax boxes and show them in the right places after ajax boxes are loaded. I'm pretty much sure this will work but I don't like the solution (which looks more like hack).

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • Can not login Magento admin page after move to my localhost

    - by Xinrui Ma
    I just move my Magento store to my localhost environment for testing use, I also using Git to maintain code, but after I move all the files to my local environment, I can't login my admin page, but I can still see my frontend pages, and the git, the database, seems works well. When I type a wrong admin/password to my admin page, it still gives me "Invalid password". But when I enter the right one, it just refresh the page and stay at the login page, nothing happens. Does anyone has met this problem before? Has any ideas? Thanks in advance!

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  • SQL Server Mapping a user to a login and adding roles programmatically

    - by user163457
    In my SQL Server 2005 server I create databases and logins using Management Studio. My application requires that I give a newly created user read and write permissions to another database. To do this I right-click the newly created login, select properties and go to User Mapping. I put a check beside the database to map this login to the db and select db_datareader and db_datawriter as the roles to map. Can this be done programmatically? I've read about using Alter User and sp_change_users_login but I'm having problems getting these to work, since sp_change_users_login has been deprecated so I'd prefer to use Alter User. Please note my understanding of SQL Server database users/logins/roles is basic

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  • Get the count of login datetime and username from the textfile

    - by user2897388
    I am having a textfile with usename, userid, login and logout time. From this textfile I need to get the userid and howmany times that user logged in on that particular date. I am doing this one using C# (.NET) in windows applications. I tried this code but I am getting the whole text into the string strRead. In that strRead I need to get the count of user login basing on date. StreamReader strmrdr = new StreamReader("Logfiles.txt"); string strRead = strmrdr.ReadToEnd(); Username:Rajini||UserId:abc||Userlogintime:10/19/13 12:33:29 PM||UserLogoutTime:10/19/13 12:33:57 PM Username:Rajini||UserId:abc||Userlogintime:10/19/13 12:35:29 PM||UserLogoutTime:10/19/13 12:36:57 PM

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  • HttpWebRequest POST and retrieve data from php script after login

    - by KenaGT
    Hello guys i am newbie to this stuff so i'll try to explain my problem.I am building application that retrieve data after login to php script that looks like this: https://zamger.etf.unsa.ba/getrssid.php (see the page source for php scirpt definition) and definition(source) here: Korisnicko ime (UID): Šifra: After i login it shows me data that i must collect like this: RSSID: 1321B312 (this is only data that it shows and nothing else) I must do this with httpwebrequest but don't know how i tried to do it with POST(data) but it always give me the defnition of php script as response.But i need response to be like "RSSID: 1321B312" not as script definition mentioned above...please heeelp ASAP....

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  • Django: HTTPS for just login page?

    - by Mark
    I just added this SSL middleware to my site http://www.djangosnippets.org/snippets/85/ which I used to secure only my login page so that passwords aren't sent in clear-text. Of course, when the user navigates away from that page he's suddenly logged out. I understand why this happens, but is there a way to pass the cookie over to HTTP so that users can stay logged in? If not, is there an easy way I can use HTTPS for the login page (and maybe the registration page), and then have it stay on HTTPS if the user is logged in, but switch back to HTTP if the user doesn't log in? There are a lot of pages that are visible to both logged in users and not, so I can't just designate certain pages as HTTP or HTTPS.

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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