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  • Social Media Optimization and SEO Will Help You Dominate the Search Engines

    There are two techniques that are widely used to increase awareness of a company's website and dominate the Search engines. SMO (Social Media Optimization) refers to finding ways and means to attract visitors to a particular website. A website is a platform that is used to advertise services and products. It gives you information about what the company deals in, how to contact them, information about the products or services that they sell and different kinds of discounted offers.

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  • Factory Method Using Is/As Operator

    - by Swim
    I have factory that looks something like the following snippet. Foo is a wrapper class for Bar and in most cases (but not all), there is a 1:1 mapping. As a rule, Bar cannot know anything about Foo, yet Foo takes an instance of Bar. Is there a better/cleaner approach to doing this? public Foo Make( Bar obj ) { if( obj is Bar1 ) return new Foo1( obj as Bar1 ); if( obj is Bar2 ) return new Foo2( obj as Bar2 ); if( obj is Bar3 ) return new Foo3( obj as Bar3 ); if( obj is Bar4 ) return new Foo3( obj as Bar4 ); // same wrapper as Bar3 throw new ArgumentException(); } At first glance, this question might look like a duplicate (maybe it is), but I haven't seen one exactly like it. Here is one that is close, but not quite: http://stackoverflow.com/questions/242097/factory-based-on-typeof-or-is-a

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  • Is tertiary operator possible here?

    - by silow
    I'm trying to set $value1, $value2, $value3 entirely using tertiary operators. This is what it looks like without tertiary if ($chk1 == 20) { $value1 = true; if ($chk2 == 40) { $value2 = 100 ; $value3 = 300; } else { $value2 = 200 ; $value3 = 400; } } else { $value1 = false; } I can set $value2 and $value3, but not sure how to set $value1. Can it be done? if ($chk1 == 20) { $value1 = true; $value2 = ($chk2 == 40) ? 100 : 200; $value3 = ($chk2 == 40) ? 300 : 400; } else { $value1 = false; }

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  • Extended service set help [closed]

    - by Cygnus X
    Sorry, this is going to be long and rambly. So, at home my network is set up as such: I have a "master router" that handles DHCP, from there I have a basic 5 port switch, and coming off that, I have a second router that I put in access point mode so that I could have better wireless coverage in my house. I cant seem to access it through a web browser since the master router kicked in and assigned it an ip address. But, i told you all that story, so that i could tell you this story. At the company I work for, they are trying to set up wireless cameras, according to the manual for these, in order to connect these cameras to our network, we need to get into the wireless router and associate the router with the cameras, but the problem is, the network is setup like my home network. Theres a "master router" which is a windows 2003 server, and then a wireless router in AP mode dishing out wireless access. I cant get into the router (by the way I'm not the system admin for the company, nor do i know jack squat about windows server , nor can I easily get in contact with the system admin. (quite the cluster f*k, eh?)) I've tried using wireshark to find the routers ip, dug through arp tables, tried plugging straight into the router, but I cant seem to get into the damn thing. Any ideas/suggestions would be greatly appreciated.

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  • Operator & and * at function prototype in class

    - by Puyover
    I'm having a problem with a class like this: class Sprite { ... bool checkCollision(Sprite &spr); ... }; So, if I have that class, I can do this: ball.checkCollision(bar1); But if I change the class to this: class Sprite { ... bool checkCollision(Sprite* spr); ... }; I have to do this: ball.checkCollision(&bar1); So, what's the difference?? It's better a way instead other? Thank you.

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  • 3 Ways to Help Your Website Be Seen Online

    When it comes to conducting business online, having good search engine optimization (SEO) foundations is just as important as having a Web site in the first place. Whether you use your Web site to share information about your business, get customers, sell a product or service, or more, it's essential that you incorporate some tried and true SEO strategies if your Web site is going to successfully serve its purpose.

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  • Help reinstalling Ubuntu on macbook pro

    - by pipsqueaker117
    Ok. I recently installed ubuntu on my macbook pro. Unfortunately, while trying to install the nvidia graphics drivers the system wouldn't reboot, the screen grey for hours. I concluded that I had broken ubuntu, and proceeded to boot into osx and remove the ubuntu partitions. After I had done that, after a reboot, I noticed that "boot linux from hd" was still listed in the bootloader (i'm using rEFIT). I dismissed it. Now, I'm trying to reinstall ubuntu, using the same USB that I successfully installed with earlier. Now, however, when the ubuntu installer is on the "copying files" part this error (more or less) pops up. ERRNO 5: We're sorry, the installer crashed. This error frequently is caused by faulty installation media, the hard disk being too hot... and so on and so forth. I'm not sure what's causing the problem, but I have a hunch that whatever's the reason that's causing linux to show up in rEFIT is the root reason. If anyone could respond, that would be great. PS, and unfortunately no, i do not have a time machine backup.

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  • Java print binary number using bit-wise operator

    - by user69514
    Hi I am creating a method that will take a number and print it along with its binary representation. The problems is that my method prints all 0's for any positive number, and all 1's for any negative number private static void display( int number ){ System.out.print(number + "\t"); int mask = 1 << 31; for(int i=1; i<=32; i++) { if( (mask & number) != 0 ) System.out.print(1); else System.out.print(0); if( (i % 4) == 0 ) System.out.print(" "); } }

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  • Perl need the right grep operator to match value of variable

    - by iaintunderstand
    I want to see if I have repeated items in my array, there are over 16.000 so will automate it There may be other ways but I started with this and, well, would like to finish it unless there is a straightforward command. What I am doing is shifting and pushing from one array into another and this way, check the destination array to see if it is "in array" (like there is such a command in PHP). So, I got this sub routine and it works with literals, but it doesn't with variables. It is because of the 'eq' or whatever I should need. The 'sourcefile' will contain one or more of the words of the destination array. my @destination = ('hi', 'bye'); sub in_array { my ($destination,$search_for) = @_; return grep {$search_for eq $_} @$destination; } for($i = 0; $i <=100; $i ++) { $elemento = shift @sourcefile; if(in_array(\@destination, $elemento)) { print "it is"; } else { print "it aint there"; } } Well, if instead of including the $elemento in there I put a 'hi' it does work and also I have printed the value of $elemento which is also 'hi', but when I put the variable, it does not work, and that is because of the 'eq', but I don't know what else to put. If I put == it complains that 'hi' is not a numeric value.

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  • Ubuntu crashed during the update to 12.04, not I can't recover my files, help please

    - by mrah
    I'm pretty new to Linux and I've only installed Ubuntu as I couldn't afford to buy Windows, worked well and I liked it. But I chose to upgrade it to the newest version after a prompt. The update froze and the machine was unresponsive which forced me to hard reboot it. Now nothing seems to load and I've reached my wits end (mainly cos I'm lost in all the command lines). I've decided to try and recover my data from the hard drive, only two folders, by selecting the try Ubuntu option when I insert the OS CD into the machine. The problem I'm experiencing now is it won't let me copy my folders, I get a 'The folder contents could not be displayed. You do not have the permissions necessary to view the contents of "folder_name".' Does anyone know how I can recover this data?

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  • Your Blog Will Help You With SEO

    One of the factors that can greatly improve your rankings is constantly having updated content on your website. Due to the nature of blogs, you can easily have updated content by making a simple post. Most of you know that Google indexes blog content more frequently.

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  • Ternary operator or chosing from two arrays with the boolean as index

    - by ajax333221
    Which of these lines is more understandable, faster jsPerf, easier to maintain?: arr = bol ? [[-2,1],[-1,2]] : [[-1,0],[-1,1]]; //or arr = [[[-1,0],[-1,1]], [[-2,1],[-1,2]]][bol*1]; I usually write code for computers (not for humans), but this is starting to be a problem when I am not the only one maintaining the code and work for a team. I am unsure, the first example looks neat but are two different arrays, and the second is a single array and seem to transmit what is being done easier. I also considered using an if-else, but I don't like the idea of writing two arr = .... Or are there better options? I need serious guidance, I have never worried about others seeing my code.

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  • How Affordable SEO Hosting Services Can Help You Out

    When it comes to the world of making sure that your website can do well online, what you have to remember is that you need some sort of an affordable SEO hosting services company that has all the needed skills and other requirements to ensure that your website can do extremely well online. What you have to remember is that it is very important to ensure that you can be provided the very best in all services that you might need.

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  • Java Program help [migrated]

    - by georgetheevilman
    Okay I have a really annoying error. Its coming from my retainAll method. The problem is that I am outputting 1,3,5 in ints at the end, but I need 1,3,5,7,9. Here is the code below for the MySet and driver classes public class MySetTester { public static void main(String[]args) { MySet<String> strings = new MySet<String>(); strings.add("Hey!"); strings.add("Hey!"); strings.add("Hey!"); strings.add("Hey!"); strings.add("Hey!"); strings.add("Listen!"); strings.add("Listen!"); strings.add("Sorry, I couldn't resist."); strings.add("Sorry, I couldn't resist."); strings.add("(you know you would if you could)"); System.out.println("Testing add:\n"); System.out.println("Your size: " + strings.size() + ", contains(Sorry): " + strings.contains("Sorry, I couldn't resist.")); System.out.println("Exp. size: 4, contains(Sorry): true\n"); MySet<String> moreStrings = new MySet<String>(); moreStrings.add("Sorry, I couldn't resist."); moreStrings.add("(you know you would if you could)"); strings.removeAll(moreStrings); System.out.println("Testing remove and removeAll:\n"); System.out.println("Your size: " + strings.size() + ", contains(Sorry): " + strings.contains("Sorry, I couldn't resist.")); System.out.println("Exp. size: 2, contains(Sorry): false\n"); MySet<Integer> ints = new MySet<Integer>(); for (int i = 0; i < 100; i++) { ints.add(i); } System.out.println("Your size: " + ints.size()); System.out.println("Exp. size: 100\n"); for (int i = 0; i < 100; i += 2) { ints.remove(i); } System.out.println("Your size: " + ints.size()); System.out.println("Exp. size: 50\n"); MySet<Integer> zeroThroughNine = new MySet<Integer>(); for (int i = 0; i < 10; i++) { zeroThroughNine.add(i); } ints.retainAll(zeroThroughNine); System.out.println("ints should now only retain odd numbers" + " 0 through 10\n"); System.out.println("Testing your iterator:\n"); for (Integer i : ints) { System.out.println(i); } System.out.println("\nExpected: \n\n1 \n3 \n5 \n7 \n9\n"); System.out.println("Yours:"); for (String s : strings) { System.out.println(s); } System.out.println("\nExpected: \nHey! \nListen!"); strings.clear(); System.out.println("\nClearing your set...\n"); System.out.println("Your set is empty: " + strings.isEmpty()); System.out.println("Exp. set is empty: true"); } } And here is the main code. But still read the top part because that's where my examples are. import java.util.Set; import java.util.Collection; import java.lang.Iterable; import java.util.Iterator; import java.util.Arrays; import java.lang.reflect.Array; public class MySet implements Set, Iterable { // instance variables - replace the example below with your own private E[] backingArray; private int numElements; /** * Constructor for objects of class MySet */ public MySet() { backingArray=(E[]) new Object[5]; numElements=0; } public boolean add(E e){ for(Object elem:backingArray){ if (elem==null ? e==null : elem.equals(e)){ return false; } } if(numElements==backingArray.length){ E[] newArray=Arrays.copyOf(backingArray,backingArray.length*2); newArray[numElements]=e; numElements=numElements+1; backingArray=newArray; return true; } else{ backingArray[numElements]=e; numElements=numElements+1; return true; } } public boolean addAll(Collection<? extends E> c){ for(E elem:c){ this.add(elem); } return true; } public void clear(){ E[] newArray=(E[])new Object[backingArray.length]; numElements=0; backingArray=newArray; } public boolean equals(Object o){ if(o instanceof Set &&(((Set)o).size()==numElements)){ for(E elem:(Set<E>)o){ if (this.contains(o)==false){ return false; } return true; } } return false; } public boolean contains(Object o){ for(E backingElem:backingArray){ if (o!=null && o.equals(backingElem)){ return true; } } return false; } public boolean containsAll(Collection<?> c){ for(E elem:(Set<E>)c){ if(!(this.contains(elem))){ return false; } } return true; } public int hashCode(){ int sum=0; for(E elem:backingArray){ if(elem!=null){ sum=sum+elem.hashCode(); } } return sum; } public boolean isEmpty(){ if(numElements==0){ return true; } else{ return false; } } public boolean remove(Object o){ int i=0; for(Object elem:backingArray){ if(o!=null && o.equals(elem)){ backingArray[i]=null; numElements=numElements-1; E[] newArray=Arrays.copyOf(backingArray,backingArray.length-1); return true; } i=i+1; } return false; } public boolean removeAll(Collection<?> c){ for(Object elem:c){ this.remove(elem); } return true; } public boolean retainAll(Collection<?> c){ MySet<E> removalArray=new MySet<E>(); for(E arrayElem:backingArray){ if(arrayElem!= null && !(c.contains(arrayElem))){ this.remove(arrayElem); } } return false; } public int size(){ return numElements; } public <T> T[] toArray(T[] a) throws ArrayStoreException,NullPointerException{ for(int i=0;i<numElements;i++){ a[i]=(T)backingArray[i]; } for(int j=numElements;j<a.length;j++){ a[j]=null; } return a; } public Object[] toArray(){ Object[] newArray=new Object[numElements]; for(int i=0;i<numElements;i++){ newArray[i]=backingArray[i]; } return newArray; } public Iterator<E> iterator(){ setIterator iterator=new setIterator(); return iterator; } private class setIterator implements Iterator<E>{ private int currIndex; private E lastElement; public setIterator(){ currIndex=0; lastElement=null; } public boolean hasNext(){ while(currIndex<=numElements && backingArray[currIndex]==null){ currIndex=currIndex+1; } if (currIndex<=numElements){ return true; } return false; } public E next(){ E element=backingArray[currIndex]; currIndex=currIndex+1; lastElement=element; return element; } public void remove() throws UnsupportedOperationException,IllegalStateException{ if(lastElement!=null){ MySet.this.remove((Object)lastElement); numElements=numElements-1; } else{ throw new IllegalStateException(); } } } } I've been able to reduce the problems, but otherwise this thing is still causing problems.

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  • Help with selecting objects on a map

    - by Dave
    I have a object selection function by checking the mouse click and getting the relevant object. How ever there is a rare situation where if one object is partially behind the other then both objects are in the given area so im wondering how i can make the game know which one was selected, as currently my method does not know. This is my function that works it out: function getobj(e){ mx = e.pageX - curleft; //mouse click x my = e.pageY - curtop; //mouse click y function searchSprites(sprites, x, y) { var matches = [], i = 0, data = null; for (i = 0; i < spritea.length; ++i) { data = spritea[i].data; if (x > data[0] && y > data[1] && x < data[2] && y < data[3]) { var imageData = ctx2.getImageData(x, y, 1, 1); if(imageData.data[3] !== 0){ return [spritea[i].id]; i = spritea.length; } } } } res = searchSprites(spritea, mx, my); bid = res[0]; if(bid === '1'){ alert('You selected the skyscraper in front!'); }else if(bid === '3'){ alert('You selected the skyscraper behind!'); } } Image of the map: http://i.imgur.com/qcKij.jpg It keeps telling me i clicked the skyscraper behind which is not necessarily what the user is trying to do... how can i improve the accuracy of this ?

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