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  • PHP Infine Loope Problem

    - by Ashwin
    function httpGet( $url, $followRedirects=true ) { global $final_url; $url_parsed = parse_url($url); if ( empty($url_parsed['scheme']) ) { $url_parsed = parse_url('http://'.$url); } $final_url = $url_parsed; $port = $url_parsed["port"]; if ( !$port ) { $port = 80; } $rtn['url']['port'] = $port; $path = $url_parsed["path"]; if ( empty($path) ) { $path="/"; } if ( !empty($url_parsed["query"]) ) { $path .= "?".$url_parsed["query"]; } $rtn['url']['path'] = $path; $host = $url_parsed["host"]; $foundBody = false; $out = "GET $path HTTP/1.0\r\n"; $out .= "Host: $host\r\n"; $out .= "User-Agent: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1) Gecko/20061010 Firefox/2.0\r\n"; $out .= "Connection: Close\r\n\r\n"; if ( !$fp = @fsockopen($host, $port, $errno, $errstr, 30) ) { $rtn['errornumber'] = $errno; $rtn['errorstring'] = $errstr; } fwrite($fp, $out); while (!@feof($fp)) { $s = @fgets($fp, 128); if ( $s == "\r\n" ) { $foundBody = true; continue; } if ( $foundBody ) { $body .= $s; } else { if ( ($followRedirects) && (stristr($s, "location:") != false) ) { $redirect = preg_replace("/location:/i", "", $s); return httpGet( trim($redirect) ); } $header .= $s; } } fclose($fp); return(trim($body)); } This code sometimes go infinite loop. What's wrong here?

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  • Recommended approach for error handling with PHP and MYSQL

    - by iama
    I am trying to capture database (MYSQL) errors in my PHP web application. Currently, I see that there are functions like mysqli_error(), mysqli_errno() for capturing the last occurred error. However, this still requires me to check for error occurrence using repeated if/else statements in my php code. You may check my code below to see what I mean. Is there a better approach to doing this? (or) Should I write my own code to raise exceptions and catch them in one single place? What is the recommended approach? Also, does PDO raise exceptions? Thanks. function db_userexists($name, $pwd, &$dbErr) { $bUserExists = false; $uid = 0; $dbErr = ''; $db = new mysqli(SERVER, USER, PASSWORD, DB); if (!mysqli_connect_errno()) { $query = "select uid from user where uname = ? and pwd = ?"; $stmt = $db->prepare($query); if ($stmt) { if ($stmt->bind_param("ss", $name, $pwd)) { if ($stmt->bind_result($uid)) { if ($stmt->execute()) { if ($stmt->fetch()) { if ($uid) $bUserExists = true; } } } } if (!$bUserExists) $dbErr = $db->error(); $stmt->close(); } if (!$bUserExists) $dbErr = $db->error(); $db->close(); } else { $dbErr = mysqli_connect_error(); } return $bUserExists; }

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  • how to find missing rows in oracle

    - by user203212
    Hi, I have a table called 2 tables create table ORDERS ( ORDER_NO NUMBER(38,0) not null, ORDER_DATE DATE not null, SHIP_DATE DATE null, SHIPPING_METHOD VARCHAR2(12) null, TAX_STATUS CHAR(1) null, SUBTOTAL NUMBER null, TAX_AMT NUMBER null, SHIPPING_CHARGE NUMBER null, TOTAL_AMT NUMBER null, CUSTOMER_NO NUMBER(38,0) null, EMPLOYEE_NO NUMBER(38,0) null, BRANCH_NO NUMBER(38,0) null, constraint ORDERS_ORDERNO_PK primary key (ORDER_NO) ); and create table PAYMENTS ( PAYMENT_NO NUMBER(38,0) NOT NULL, CUSTOMER_NO NUMBER(38,0) null, ORDER_NO NUMBER(38,0) null, AMT_PAID NUMBER NULL, PAY_METHOD VARCHAR(10) NULL, DATE_PAID DATE NULL, LATE_DAYS NUMBER NULL, LATE_FEES NUMBER NULL, constraint PAYMENTS_PAYMENTNO_PK primary key (PAYMENT_NO) ); I am trying to find how many late orders each customer have. the column late_days in PAYMENTS table has how many days the customer is late for making payments for any particular order. so I am making this query SELECT C.CUSTOMER_NO, C.lname, C.fname, sysdate, COUNT(P.ORDER_NO) as number_LATE_ORDERS FROM CUSTOMER C, orders o, PAYMENTS P WHERE C.CUSTOMER_NO = o.CUSTOMER_NO AND P.order_no = o.order_no AND P.LATE_DAYS>0 group by C.CUSTOMER_NO, C.lname, C.fname That means, I am counting the orders those have any late payments and late_days0. But this is giving me only the customers who have any orders with late_days0, but the customers who does not have any late orders are not showing up. so if one customer has 5 orders with late payments then it is showing 5 for that customer, but if a customer have 0 late orders,that customer is not selected in this query. Is there any way to select all the customers , and if he has any late orders, it will show the number and also if he does not have any late orders, it will show 0.

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  • How many websites can my server potentially hold?

    - by Daniel Kindler
    Sorry for the "noob" question, but... About how many medium-sized websites with average traffic could this server hold? Just like the average website, kind of like a small business site. How many sites could this server hold, but still maintain nice, decent speed? PowerEdge R510 PE R510 Chassis for Up to Four 3.5" Cabled Hard Drives, LED edit Processor Intel® Xeon® E5630 2.53Ghz, 12M Cache,Turbo, HT, 1066MHz Max Mem edit Memory 8GB Memory (4x2GB), 1333MHz Single Ranked UDIMMs for 1 Procs, Optimized edit Operating System SUSE Linux Enterprise Server 10, SP3, Up To 32 CPU Lic, 1 YR Sub, DIB, Media edit Red Hat Enterprise Linux Licensing Hard Drives 250GB 7.2K RPM SATA 3.5" Cabled Hard Drive edit Hard Drives 1TB 7.2K RPM SATA 3.5" Cabled Hard Drive edit Hard Drives 2 X 2TB 7.2K RPM SATA 3.5in Cabled Hard Drive Hard Drive Configuration No RAID, Embedded SATA Controller for x4 Chassis edit Power Supply 480 Watt Non-Redundant Power Supply edit Thank you!

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  • Jail user to home directory while still allowing permission to create and delete files/folders

    - by Sevenupcan
    I'm trying to give a client SFTP access to the root directory of their site on my server (Ubuntu 10.10) so they can manager their website themselves. While I have been successful in jailing a user to a directory and giving them SFTP access; they are only allowed to create and delete new files in sub directories (the directories they own). This means that I must give them access to the parent directory to the root of their site. How can I limit them to the root of their site (for example public_html) while still allowing them the ability create and delete files. All the tutorials I have read suggest that the root must be the owner of the user's home directory, which prevents them from write access inside that directory. I'm relatively new to managing my own server so any advice would be very grateful. Many thanks.

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  • Elements of website don't work in IE

    - by mjcuva
    On the site I'm working on for my high school basketball team, certain elements don't work in Internet Explorer. The site is hermantownbasketball.com. The boys basketball sidebar should have nested drop down menus, one when you mouse over the team, such as "High School" and then another when you mouse over the grade under the team, such as 9th grade. This works perfectly fine in chrome, however, I can't get it to work in any version of Internet Explorer. Below is the part of the html and the corresponding css I am using. Unfortunately, I don't know enough css to know which part of my code IE doesn't like or how to fix it. Any help is greatly appreciated! HTML <span class = "boyItem"> <h3>High School</h3> <li class="group"> <h4>9th Grade</h4> <div class = "nested">Schedule</div> <div class = "nested">Events</div> <div class ="nested">Forms</div> <div class ="nested">Calendar</div> </li> <li class="group"> <h4>JV/Varsity</h4> <div class = "nested">Schedule</div> <div class = "nested">Events</div> <div class = "nested">Forms</div> <div class = "nested">Calendar</div> </li> </span> /* Creates the box around the title for each boy section. */ .boyItem h3 { background:#1C23E8; color:#EFFA20; padding-right:2px; padding:10px; font-size:18px; margin-left:-30px; margin-top:-10px; } ###CSS .boyItem h3:hover { background:#2A8FF5; } /* Prevents the boy sub-sections from being visable */ .boyItem li h4 { position: absolute; left:-9999px; font-size:15px; list-style-type:none;} /* Shows the boy sub-sections when user mouses over the section title. */ .boyItem:hover li h4 { position:relative; left:10px; background:#1C23E8; color:#EFFA20; padding-left:20px; padding:5px; } .boyItem:hover li h4:hover { background:#2A8FF5;} .nested { position:absolute; left:-9999px; background:#352EFF; color:#EFFA20; padding-right:2px; padding:4px; font-size:14px; margin:2px; margin-left:30px; margin-top:0px; margin-right:0px; margin-bottom:-2px;} .group:hover .nested {position:relative; left:0px; } .group:hover .nested:hover { background:#2A8FF5}

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  • WSS 3.0 fails to hide quick launch items for which the current user does not have access

    - by Nils
    I'm running a Small Business Server 2008 with Windows Sharepoint Services 3.0 (WSS 3.0). I thought WSS was supposed to hide menu items for which the current logged in user don't have access? Apparently, all users can see all links, regardless of whether they have access. This applies to both links to newly created sub-sites as well as document libraries/lists. Is this expected behaviour, or is there a misconfiguration somewhere that causes the links to stay visible even for users without access? Thanks!

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  • PHP Foreach statement issue. Multiple rows are returned

    - by Daniel Patilea
    I'm a PHP beginner and lately i've been having a problem with my source code. Here it is: <html> <head> <title> Bot </title> <link type="text/css" rel="stylesheet" href="main.css" /> </head> <body> <form action="bot.php "method="post"> <lable>You:<input type="text" name="intrebare"></lable> <input type="submit" name="introdu" value="Send"> </form> </body> </html> <?php //error_reporting(E_ALL & ~E_NOTICE); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("robo") or die(mysql_error()); $intrebare=$_POST['intrebare']; $query = "SELECT * FROM dialog where intrebare like '%$intrebare%'"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); ?> <div id="history"> <?php foreach($row as $rows){ echo "<b>The robot says: </b><br />"; echo $row['raspuns']; } ?> </div> It returns me the result x6 times. This problem appeared when I've made that foreach because I wanted the results to stuck on the page one by one after every sql querry. Can you please tell me what seems to be the problem? Thanks!

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  • How do I iterate through hierarchical data in a Sql Server 2005 stored proc?

    - by AlexChilcott
    Hi, I have a SqlServer2005 table "Group" similar to the following: Id (PK, int) Name (varchar(50)) ParentId (int) where ParentId refers to another Id in the Group table. This is used to model hierarchical groups such as: Group 1 (id = 1, parentid = null) +--Group 2 (id = 2, parentid = 1) +--Group 3 (id = 3, parentid = 1) +--Group 4 (id = 4, parentid = 3) Group 5 (id = 5, parentid = null) +--Group 6 (id = 6, parentid = 5) You get the picture I have another table, let's call it "Data" for the sake of simplification, which looks something like: Id (PK, int) Key (varchar) Value (varchar) GroupId (FK, int) Now, I am trying to write a stored proc which can get me the "Data" for a given group. For example, if I query for group 1, it returns me the Key-Value-Pairs from Data where groupId = 1. If I query for group 2, it returns the KVPs for groupId = 1, then unioned with those which have groupId = 2 (and duplicated keys are replaced). Ideally, the sproc would also fail gracefully if there is a cycle (ie if group 1's parent is group 2 and group 2's parent is group 1) Has anyone had experience in writing such a sproc, or know how this might be accomplished? Thanks guys, much appreciated, Alex

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  • Large Product catalog with statistics - alternatives to Sql Server?

    - by Eric P
    I am building UI for a large product catalog (millions of products). I am using Sql Server, FreeText search and ASP.NET MVC. Tables are normalized and indexed. Most queries take less then a second to return. The issue is this. Let's say user does the search by keyword. On search results page I need to display/query for: First 20 matching products (paged, sorted) Total count of matching products for paging List of stores only of matching products List of brands only of matching products List of colors only of matching products Each query takes about .5 to 1 seconds. Altogether it is like 5 seconds. I would like to get the whole page to load under 1 second. There are several approaches: Optimize queries even more. I already spent a lot of time on this one, so not sure it can be pushed further. Load products first, then load the rest of the information using AJAX. More like a workaround. Will need to revise UI. Re-organize data to be more Report friendly. Already aggregated a lot of fields. I checked out several similar sites. For ex. zappos.com. Not only they display the same information as I would like in under 1 second, but they also include statistics (number of results in each category). The following is the search for keyword "white" http://www.zappos.com/white How do sites like zappos, amazon make their results, filters and stats appear almost instantly?

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  • accordion tab open at different times

    - by user3279193
    I am using an asp classic and on the page I have a J-Query accordion. I want one tab to be open if the value that the asp prints out is greater than zero, if not , I want them all to be closed, this is an example of what I've got: J-Query: $(function() { $( "#accordion" ).accordion({ heightStyle: "content", collapsible: true, active: false }); }); HTML/ASP: <div id="accordion"> <h3>Tab1</h3> <div> <p>Hello World</p> </div> <h3>Tab2</h3> <div> <p>Hello World</p> </div> <h3>Tab3</h3> <div> <p>Hello World</p> </div> <h3>Results (<%=number%>)</h3> <!--if number > 0 then open tab else close all tabs--> <div> <p>Hello World</p> </div> </div>

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  • How to run a command in a process that is not a child of the current process?

    - by amicitas
    I am having a library conflict issue with calling an external program from within a interpreted programming environment (IDL). The issue seems to be that since the program I am calling ends up as a child of IDL, libraries are not being reloaded. From within IDL I can launch sub-processes either directly or using a shell. Is there a good way that I can cause my program to be run without ending up as a child process? The only solution I have found so far is to use ssh localhost my_program. This works perfectly but I would like a more direct solution.

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  • Can I use php SESSIONS in spotify apps?

    - by user1593846
    since PHP can't be used in Spotify apps directly I am using it on my server only, but I am having problems getting the sessions to work, is it possible to use sessions even? I want to use it to see if a user is registered in my database or not so I am doing it like this: session_start(); $query="SELECT * FROM user WHERE facebookID = {$fbid}"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result); $num_results = mysql_num_rows($result); if ($num_results > 0) { echo"THERE IS A USER!"; $row['facebookID'] = $_SESSION[fid]; } else { echo"THERE IS NO USER!"; } the authentication to the server works fine but the session does not seem to be working, on another PHP page witch is being called after the above code has been called with some ajax code I simply wanted to try this: session_start(); if(isset($_SESSION['fid'])) { echo"SESSION EXIST"; } else { echo"NO SESSION"; } anyways is there a special way to do this in Spotify apps or do I have to do this in some other way?

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  • What's the best way to access a MS Access database using PHP?

    - by Jack Roscoe
    Hi, I need to access some data from an MS Access database and retrieve some data from it using PHP. I've looked around the web, and found the following line which seems to correctly connect to the database: $conn->Open("DRIVER={Microsoft Access Driver (*.mdb)}; DBQ=C:\wamp\www\data\MYDB.mdb"); However, I have tried to retrieve some data in the following way: $query = "SELECT pageid FROM pages_table"; $result = mysqli_query($conn, $query); $amount_of_pages = 0; if(mysqli_num_rows($result) <= 0) echo "No results found."; else while($row = mysqli_fetch_array($result, MYSQL_ASSOC)) $amount_of_pages++; And was presented with the following errors: Warning: mysqli_query() expects parameter 1 to be mysqli, object given in C:\wamp\www\data\index.php on line 19 Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, null given in C:\wamp\www\data\index.php on line 23 No results found. I don't really understand the connection to the Access database, is there something I should be doing differently? Thanks in advance for any help.

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  • nextgen gallery order issue

    - by mro
    Hi, wonder if anyone can help. I think what I'm after won't be solved by any exsiting code in nextgen plugin (in wordpress) due to the custom way I'm using it hence I come to stackoverflow for some opnions. Bascially - I am only really using the admin of nextgen to work with the gallerys etc. The actual meat of the functionality I'm querying the nextgen DB's direct from my code, I would have loved to use the inbuilt gallerys in nextgen, but my spec specifics were so custom I couldn't. My issue is, I need to pull the images from the DB's in the order it is in the admin (ie if a user pulls the sort order around in the drag and drop area). I have noticed however this doesn't affect the image id order in the DB, and wouldn't expect it to - that would be some complex shifting around just to reorder everytime surely. So obviously when I query the DB the order it's looking at is when it was created, by image id, with my filtering on top. I'm wondering though if there is a way I can query that sort order that's determined in the admin somehow, then at least I could sort the array somehow in the code ? does next gen store it's user custom sort order somewhere ? Hope this makes sense :) any thoughts appreciated. Thanks

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  • Linux virtual disk stripping or multi-path samba share?

    - by wachpwnski
    I am trying to build a file storage box for media. It needs to span two or more directories or partitions as one share. There are a few solutions but reasons why I want to avoid them, among these are: Using LVM2 for stripping. I don't really have the resources to back up everything on the volumes incase one HDD goes south. I would end up loosing everything. Maybe there is a better option for this to prevent data loss with hot swappable drives or some kind of raid. Using symbolic links in the share. This will get tedious every time a new sub-directory is added. Is there some kind of software raid I can use to merge two directories virtually? I am aware of the issue where /dev/hda1/media/file.1 and /dev/hdb1/media/file.1 both exist. But I'm sure there are some creative solutions for this.

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  • MySQL updating a field to result of a function

    - by jdborg
    mysql> CREATE FUNCTION test () -> RETURNS CHAR(16) -> NOT DETERMINISTIC -> BEGIN -> RETURN 'IWantThisText'; -> END$$ Query OK, 0 rows affected (0.00 sec) mysql> SELECT test(); +------------------+ | test() | +------------------+ | IWantThisText | +------------------+ 1 row in set (0.00 sec) mysql> UPDATE `table` -> SET field = test() -> WHERE id = 1 Query OK, 1 row affected, 1 warning (0.01 sec) Rows matched: 1 Changed: 1 Warnings: 1 mysql> SHOW WARNINGS; +---------+------+----------------------------------------------------------------+ | Level | Code | Message | +---------+------+----------------------------------------------------------------+ | Warning | 1265 | Data truncated for column 'test' at row 1 | +---------+------+----------------------------------------------------------------+ 1 row in set (0.00 sec) mysql> SELECT field FROM table WHERE id = 1; +------------------+ | field | +------------------+ | NULL | +------------------+ 1 row in set (0.00 sec) What I am doing wrong? I just want field to be set to the returned value of test() Forgot to mention field is VARCHR(255)

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  • Mixing together Connect by, inner join and sum with Oracle

    - by François
    Hey there, I need help with a oracle query. Excuse me in advance for my english. Here is my setup: I have 2 tables called respectively "tasks" and "timesheets". The "tasks" table is a recursive one, that way each task can have multiple subtasks. Each timesheet is associated with a task (not necessarily the "root" task) and contains the number of hours worked on it. Example: Tasks id:1 | name: Task A | parent_id: NULL id:2 | name: Task A1 | parent_id: 1 id:3 | name: Task A1.1 | parent_id: 2 id:4 | name: Task B | parent_id: NULL id:5 | name: Task B1 | parent_id: 4 Timesheets id:1 | task_id: 1 | hours: 1 id:2 | task_id: 2 | hours: 3 id:3 | task_id:3 | hours: 1 id:5 | task_id:5 | hours:1 ... What I want to do: I want a query that will return the sum of all the hours worked on a "task hierarchy". If we take a look at the previous example, It means I would like to have the following results: task A - 5 hour(s) | task B - 1 hour(s) At first I tried this SELECT TaskName, Sum(Hours) "TotalHours" FROM ( SELECT replace(sys_connect_by_path(decode(level, 1, t.name), '~'), '~') As TaskName, ts.hours as hours FROM tasks t INNER JOIN timesheets ts ON t.id=ts.task_id START WITH PARENTOID=-1 CONNECT BY PRIOR t.id = t.parent_id ) GROUP BY TaskName Having Sum(Hours) > 0 ORDER BY TaskName And it almost work. THe only problem is that if there are no timesheet for a root task, it will skip the whole hieararchy... but there might be timesheets for the child rows and it is exactly what happens with Task B1. I know it is the "inner join" part that is causing my problem but I'm not sure how can I get rid of it. Any idea how to solve this problem? Thank you

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  • Blurred refurbished TFT

    - by PeterMmm
    I got 3 refurbished PC+TFT 19". All TFT shows a very blurry image. I estimate the TFT's are 2-3 yrs old. The PC's running Windows7 Pro. The resolution is set to the TFT native values. It could be possible that all TFT's are broken but I have similiar models that are up to 5 yrs old, without any issue. I still think it could be a config issue but from the hardware it is possible that a TFT get broken I shows up a very blurry image. Update TFT HP 2035, grafic Intel Q35/GMA 3100, analog D-SUB connector, Manuf. date Sep 2005. Config. resolution 1600x1200, PPP 150% Without ClearType it is worst. Desktop Icon titles seems to be good and clear. But in Notepad for example the effect is that on the right of the characters is a pinky shadow.

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  • multiple-to-one relationship mysql, submissions

    - by Yulia
    Hello, I have the following problem. Basically I have a form with an option to submit up to 3 images. Right now, after each submission it creates 3 records for album table and 3 records for images. I need it to be one record for album and 3 for images, plus to link images to the album. I hope it all makes sense... Here is my structure. TABLE `albums` ( `id` int(11) NOT NULL auto_increment, `title` varchar(50) NOT NULL, `fullname` varchar(40) NOT NULL, `email` varchar(100) NOT NULL, `created_at` datetime NOT NULL, `theme_id` int(11) NOT NULL, `description` int(11) NOT NULL, `vote_cache` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; TABLE `images` ( `id` int(11) NOT NULL auto_increment, `album_id` int(11) NOT NULL, `name` varchar(30) NOT NULL, and my code function create_album($params) { db_connect(); $query = sprintf("INSERT INTO albums set albums.title = '%s', albums.email = '%s', albums.discuss_url = '%s', albums.theme_id = '%s', albums.fullname = '%s', albums.description = '%s', created_at = NOW()", mysql_real_escape_string($params['title']), mysql_real_escape_string($params['email']), mysql_real_escape_string($params['theme_id']), mysql_real_escape_string($params['fullname']), mysql_real_escape_string($params['description']) ); $result = mysql_query($query); if(!$result) { return false; } $album_id = mysql_insert_id(); return $album_id; } if(!is_uploaded_file($_FILES['userfile']['tmp_name'][$i])) { $warning = 'No file uploaded'; } elseif is_valid_file_size($_FILES['userfile']['size'][$i])) { $_POST['album']['theme_id'] = $theme['id']; create_album($_POST['album']); mysql_query("INSERT INTO images(name) VALUES('$newName')"); copy($_FILES['userfile']['tmp_name'][$i], './photos/'.$original_dir.'/' .$newName.'.jpg');

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  • problem in variables in jquery

    - by Alvin
    Hi, I don't understand why I'm not getting the message as "username already exits" if type the username which is already in database. If the username in a server, then it is returning the value as "1" otherwise empty, and despite of successfully getting the value from the server based on username is present or not, and assigning the value to variable "x", I'm unable to get message when I pass already exist username. May I know? $(document).ready(pageInit); function pageInit() { $('#1').bind('blur',go); } function go() { var value = $('#1').val(); var x = 0; $.post('just.do',{username:value},function(data){ x = data; } ); if(x) { $('#para').show(); $('#para').html("Username already exits"); return false; } else { $('#para').hide(); return true; } }; EDIT: This is what I'm doing in post request in servlets: String user1 = request.getParameter("username"); if(user != null) { String query = "Select * from users where user_name="+"\""+user+"\""; b = db.doExecuteQuery(stmt,query); if(b) { out.write("1"); } }

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  • JavaScript date suffix formatting

    - by TexasB
    I have done my due diligence in investigating this and not had any success yet. Being rather green with JavaScript I am seeking some help. I am wanting to display the date NOV2012<br> 2<sup>nd</sup><br> 5:00 PM I have everything working (not my script) except being able to get the date suffix to change to st, nd, rd, or th as the case may be. This is what I have: <pre> <abbr title="Month"> <script type="text/javascript"> var d=new Date(); var month=new Array(12); month[0]="Jan"; month[1]="Feb"; month[2]="Mar"; month[3]="Apr"; month[4]="May"; month[5]="Jun"; month[6]="Jul"; month[7]="Aug"; month[8]="Sep"; month[9]="Oct"; month[10]="Nov"; month[11]="Dec"; document.write(month[d.getMonth()]); </script></abbr> <script type="text/javascript"> var d = new Date() document.write(d.getDate()) ordinal : function (number) { var d = number % 10; return (~~ (number % 100 / 10) === 1) ? 'th' : (d === 1) ? 'st' : (d === 2) ? 'nd' : (d === 3) ? 'rd' : 'th'; } }); </script> <sup>%</sup> <abbr><script type="text/javascript"> var d = new Date() document.write(d.getFullYear()) </script></abbr> <sub> <script type="text/javascript"> <!-- var currentTime = new Date() var hours = currentTime.getHours() var minutes = currentTime.getMinutes() if (minutes < 10){ minutes = "0" + minutes } document.write(hours + ":" + minutes + " ") if(hours > 11){ document.write("PM") } else { document.write("AM") } //--> </script> </sub> </pre> I know the issue is with this part: <pre> <script type="text/javascript"> var d = new Date() document.write(d.getDate()) ordinal : function (number) { var d = number % 10; return (~~ (number % 100 / 10) === 1) ? 'th' : (d === 1) ? 'st' : (d === 2) ? 'nd' : (d === 3) ? 'rd' : 'th'; } }); </script> < sup > % < /sup > </pre> but I can't seem to work out the right fix. This is where it is sitting: http://www.bcreativeservices.com/ Thank you as always. B

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  • Fixing an SQL where statement that is ugly and confusing

    - by Mike Wills
    I am directly querying the back-end MS SQL Server for a software package. The key field (vehicle number) is defined as alpha though we are entering numeric value in the field. There is only one exception to this, we place an "R" before the number when the vehicle is being retired (which means we sold it or the vehicle is junked). Assuming the users do this right, we should not run into a problem using this method. (Right or wrong isn't the issue here) Fast forward to now. I am trying to query a subset of these vehicle numbers (800 - 899) for some special processing. By doing a range of '800' to '899' we also get 80, 81, etc. If I cast the vehicle number into an INT, I should be able to get the right range. Except that these "R" vehicles are kicking me in the butt now. I have tried where vehicleId not like 'R%' and cast(vehicleId as int) between 800 and 899 however, I get a casting error on one of these "R" vehicles. What does work is where vehicleId not between '800' and '899' and cast(vehicleId as int) between 800 and 899', but I feel there has to be a better way and less confusing way. I have also tried other variations with HAVING and a sub-query all producing a casting error.

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  • MySQL Datefields: duplicate or calculate?

    - by Konerak
    We are using a table with a structure imposed upon us more than 10 years ago. We are allowed to add columns, but urged not to change existing columns. Certain columns are meant to represent dates, but are put in different format. Amongst others: * CHAR(6): YYMMDD * CHAR(6): DDMMYY * CHAR(8): YYYYMMDD * CHAR(8): DDMMYYYY * DATE * DATETIME Since we now would like to do some more complex queries, using advanced date functions, my manager proposed to d*uplicate those problem columns* to a proper FORMATTED_OLDCOLUMNNAME column using a DATE or DATETIME format. Is this the way to go? Couldn't we just use the STR_TO_DATE function each time we accessed the columns? To avoid every query having to copy-paste the function, I could still work with a view or a stored procedure, but duplicating data to avoid recalculation sounds wrong. Solutions I see (I guess I prefer 2.2.1) 1. Physically duplicate columns 1.1 In the same table 1.1.1 Added by each script that does a modification (INSERT/UPDATE/REPLACE/...) 1.1.2 Maintained by a trigger on each modification 1.2 In a separate table 1.2.1 Added by each script that does a modification (INSERT/UPDATE/REPLACE/...) 1.2.2 Maintained by a trigger on each modification 2. On-demand transformation 2.1 Each query has to perform the transformation 2.1.1 Using copy-paste in the source code 2.1.2 Using a library 2.1.3 Using a STORED PROCEDURE 2.2 A view performs the transformation 2.2.1 A separate table replacing the entire table 2.2.2 A separate table just adding the date-fields for the primary keys Am I right to say it's better to recalculate than to store? And would a view be a good solution?

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  • Regex working in RedHat is not giving any result in Ubuntu

    - by Supratik
    My goal is to match specific files from specific sub directories. I have the following folder structure `-- data |-- a |-- a.txt |-- b |-- b.txt |-- c |-- c.txt |-- d |-- d.txt |-- e |-- e.txt |-- org-1 | |-- a.org | |-- b.org | |-- org.txt | |-- user-0 | | |-- a.txt | | |-- b.txt I am trying to list the files only inside the data directory. I am able to get the correct result using the following command in RHEL find ./testdir/ -iwholename "*/data/[!/].txt" a.txt b.txt c.txt d.txt e.txt If I run the same command in Ubuntu it is not working. Can anyone please tell me why it is not working in Ubuntu ?

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