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  • SSH Connection Refused - Debug using Recovery Console

    - by olrehm
    Hey everyone, I have found a ton of questions answered about debugging why one cannot connect via SSH, but they all seem to require that you can still access the system - or say that without that nothing can be done. In my case, I cannot access the system directly, but I do have access to the filesystem using a recovery console. So this is the situation: My provider made some kernel update today and in the process also rebooted my server. For some reason, I cannot connect via SSH anymore, but instead get a ssh: connect to host mydomain.de port 22: Connection refused I do not know whether sshd is just not running, or whether something (e.g. iptables) blocks my ssh connection attempts. I looked at the logfiles, none of the files in /var/log contain any mentioning on ssh, and /var/log/auth.log is empty. Before the kernel update, I could log in just fine and used certificates so that I would not need a password everytime I connect from my local machine. What I tried so far: I looked in /etc/rc*.d/ for a link to the /etc/init.d/ssh script and found none. So I am expecting that sshd is not started properly on boot. Since I cannot run any programs in my system, I cannot use update-rc to change this. I tried to make a link manually using ln -s /etc/init.d/ssh /etc/rc6.d/K09sshd and restarted the server - this did not fix the problem. I do not know wether it is at all possible to do it like this and whether it is correct to create it in rc6.d and whether the K09 is correct. I just copied that from apache. I also tried to change my /etc/iptables.rules file to allow everything: # Generated by iptables-save v1.4.0 on Thu Dec 10 18:05:32 2009 *mangle :PREROUTING ACCEPT [7468813:1758703692] :INPUT ACCEPT [7468810:1758703548] :FORWARD ACCEPT [3:144] :OUTPUT ACCEPT [7935930:3682829426] :POSTROUTING ACCEPT [7935933:3682829570] COMMIT # Completed on Thu Dec 10 18:05:32 2009 # Generated by iptables-save v1.4.0 on Thu Dec 10 18:05:32 2009 *filter :INPUT ACCEPT [7339662:1665166559] :FORWARD ACCEPT [3:144] :OUTPUT ACCEPT [7935930:3682829426] -A INPUT -i lo -j ACCEPT -A INPUT -p tcp -m tcp --dport 25 -j ACCEPT -A INPUT -p tcp -m tcp --dport 993 -j ACCEPT -A INPUT -p tcp -m tcp --dport 22 -j ACCEPT -A INPUT -p tcp -m tcp --dport 143 -j ACCEPT -A INPUT -m conntrack --ctstate RELATED,ESTABLISHED -j ACCEPT -A INPUT -p tcp -m tcp --dport 80 -j ACCEPT -A INPUT -p tcp --dport 8080 -s localhost -j ACCEPT -A INPUT -m limit --limit 5/min -j LOG --log-prefix "iptables denied: " --log-level 7 -A INPUT -j ACCEPT -A FORWARD -j ACCEPT -A OUTPUT -j ACCEPT COMMIT # Completed on Thu Dec 10 18:05:32 2009 # Generated by iptables-save v1.4.0 on Thu Dec 10 18:05:32 2009 *nat :PREROUTING ACCEPT [101662:5379853] :POSTROUTING ACCEPT [393275:25394346] :OUTPUT ACCEPT [393273:25394250] COMMIT # Completed on Thu Dec 10 18:05:32 2009 I am not sure this is done correctly or has any effect at all. I also did not find any mentioning of iptables in any file in /var/log. So what else can I do? Thank you for your help.

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  • How do you backup 40+ Centos5.5 servers?

    - by John Little
    We are embarrassed to ask this question. Apologies for our lack of UNIX expertise. We have inherited 40+ centos 5.5 servers, and don't know how to back them up. We need low level clone type images so that we could restore the servers from scratch if we had to replace the HDs etc. We have used the "dd" command, but we assume this only works if you want to back up one local disk to another, not 40 servers to one server with an external USB HD attached. All 40 servers have a pair of mirrored disks (dont know if its HW or SW raid). Most only have 100MB used. SErvers are running apache, zend, tomcat, mysql etc. Ideally we dont want to have to shut them down to backup (but could). We assume that standard unix commands like tar, cpio, rsync, scp etc. are of no use as they only copy files, not partitions, all attributes, groups etc. i.e. do not produce a result which can simply be re-imaged to a new HD to get the serer back from dead. We have a large SAN, a spare windows box and spare unix boxes, but these are only visible to one layer in the network. We have an unused Dell DL2000 monster tape unit, but no sw or documentation for it. WE have a copy of symantec backup exec, but we have no budget for unix client licenses. (The company has negative amounts of money). We need to be able to initiate the backup remotely, as we can only access the servers in person in an emergency (i.e. to restore) Googling returns some applications to do this, e.g. clonezilla - looks difficult to install and invasive. Mondo, only seems to support backup if you are local to the machine. Amanda might be an option, but looks like days/weeks of work to learn and setup? Is there anything built into Centos, or do we have to go the route of installing, learning and configuring a set of backup softwares? Any ideas? This must be a pretty standard problem which goggling doesnt give an obvious answer.

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  • only removing index.php rule works on my NginX and CodeIgniter as rewrite. Why?

    - by Atomei Cosmin
    I am very new in rewriting in nginx but although I've spent 2 days reading on forums, I still can't get some Codeigniter rewrites working ... server { listen *:80; server_name artademy.com www.artademy.com; root /var/www/artademy.com/web; index index.html index.htm index.php index.cgi index.pl index.xhtml; if (!-e $request_filename) { rewrite ^/(.*)$ /index.php?/$1; } if (!-e $request_filename) { rewrite ^/(index.php\?)/(.*)$ /$1/mobile_app last; break; } error_log /var/log/ispconfig/httpd/artademy.com/error.log; access_log /var/log/ispconfig/httpd/artademy.com/access.log combined; ## Disable .htaccess and other hidden files location ~ /\. { deny all; access_log off; log_not_found off; } location = /favicon.ico { log_not_found off; access_log off; } location = /robots.txt { allow all; log_not_found off; access_log off; } location /stats { index index.html index.php; auth_basic "Members Only"; auth_basic_user_file /var/www/clients/client0/web3/.htpasswd_stats; } location ^~ /awstats-icon { alias /usr/share/awstats/icon; } location ~ \.php$ { try_files $uri =404; include /etc/nginx/fastcgi_params; fastcgi_pass 127.0.0.1:9012; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_param PATH_INFO $fastcgi_script_name; fastcgi_intercept_errors on; } } Codeigniter settings are: well for uri_protocol: REQUEST_URI; What i noticed is that from this rule: rewrite ^/(.)$ /index.php?/$1; it works ever if i write it like this: rewrite ^/(.)$ /index.php?; It might be a wild guess but it stops at the question mark... Anyhow what I need are rules as these from .htaccess: RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{QUERY_STRING} ^lang=([a-z]{2})$ RewriteRule ^([a-z]{2})$ index.php?/home_page?lang=$1 [L,QSA] RewriteRule ^([a-z]{2})$ index.php?/home_page?lang=$1 [L,QSA] #how_it_works RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^how-it-works/(en)$ index.php?/how_it_works?lang=en [L,QSA] #order_status RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^order-status/(en)$ index.php?/order_status?lang=en [L,QSA] Can anyone tell me what i'm doing wrong and show me a proper way for at least one rule? It would be more than helpful. Thank you in advance! ^^ PS: I made it work on apache by using Path_info for uri_protocol.. if this info is of any help, and i remember having kind of the same problem there too but switching to path_info made it all good.

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  • NGINX rewrite rules help. Redirect not working and want to get rid of index.php in urls

    - by Tamerax
    hey! I have 2 questions for nginx users. 1) I'm trying to setup my joomla server onto my new linode running NGINX and after much (like days) of searching and testing, I finally have a config that works with with SEF url plugins...sorta. I was using an apache system on the old server and it used mod_rewrite and life was fine in terms of SEF. Since NGINX doesn't have mod_rewrite, I found something that works BUT it constantly leaves index.php in the urls. ex: http://mysite.com/index.php/forum i want it to be just http://mysite.com/forum but without mod_rewrite it doesn't seem to be possible in joomla that i'm aware of. I know in wordpress it IS possible but I have to use a plugin. Here is my config file: server { listen 80; server_name mysite.com www.mysite.com; access_log /home/public_html/mysite.com/log/access.log; error_log /home/public_html/mysite.com/log/error.log; root /home/public_html/mysite.com/public/; large_client_header_buffers 4 8k; # prevent some 400 errors index index.php index.html; fastcgi_index index.php; location / { expires 30d; error_page 404 = @joomla; log_not_found off; } # Rewrite location @joomla { rewrite ^(.*)$ /index.php?q=last; } # Static Files location ~* ^.+.(jpg|jpeg|gif|css|png|js|ico)$ { access_log off; expires 30d; } # PHP location ~ \.php { keepalive_timeout 0; fastcgi_pass 127.0.0.1:9000; fastcgi_index index.php; include /usr/local/nginx/conf/fastcgi_params; fastcgi_param SCRIPT_FILENAME /home/public_html/mysite.com/public /$fastcgi_script_name; } } 2) second question should be easy but i can't get it to work. I want to use the same config I posted above and have either mysite.com or www.mysite.com both forward to mysite.com/portal. Basically when you hit up the front page with or without the www, it all gets forwarded to a sub directory on the server I called Portal. I have tried several variations of: rewrite ^/(.*) http://www.example.com/portal/$1 permanent; but it usually ends with firefox telling me there is some crazy loop happening the address bar saying something like mysite.com/portalportalportalportalportal.........on and on. So, any help on either of these issues would be awesome!! Thanks!!

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  • turn off disable the performance cache

    - by jessie
    OK I run a streaming website and my CMS is giving me an error when uploading videos "Failed To Find Flength File" ok so I did some research. The answer I got from the coder was below. I did do all that, but the only thing I could not do is turn off what he refers to as performance cache, talked about in the last sentence... I am on a Cent OS Assuming the script is set up properly, you are probably dealing with some kind of write-caching. Some servers perform write-caching which prevents writing out the flength file or the entire CGITemp file during the upload. The flength file or the CGITemp file do not actually hit the disk until the upload is complete, making it worthless for reporting on progress during the upload. This may be fixed using a .htaccess file assuming your host supports them. Here is a link to an excellent tutorial on using .htaccess files. I strongly recommend giving it a quick read before attempting to install your own .htaccess file. 1. A mod_security module for Apache. To fix it just create a file called .htaccess (that's a period followed by "htaccess") and put the following lines in that file. Upload the file into the directory where the Uber-Uploader CGI ".pl" scripts resides, or in some directory above it (like your server's DOCUMENT_ROOT, i.e. the top-level of your webspace). htaccess files must be uploaded as ASCII mode, not BINARY. You may need to CHMOD the htaccess file to 644 or (RW-R--R--). # Turn off mod_security filtering. SecFilterEngine Off # The below probably isn't needed, # but better safe than sorry. SecFilterScanPOST Off If the above method does not work, try putting the following lines into the file SetEnvIfNoCase Content-Type \ "^multipart/form-data;" "MODSEC_NOPOSTBUFFERING=Do not buffer file uploads" mod_gzip_on No 2. "Performance Cache" enabled on OS X SERVER. If you're running OS X Server and the progress bar isn't working, it could be because of "performance caching." Apparently if ANY of your hosted sites are using performance caching, then by default, all sites (domains) will attempt to. The fix then is to disable the performance cache on all hosted sites.

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  • Repeated requests on our server?

    - by pitty.platsch
    I encountered something strange in the access log of our Apache server which I cannot explain. Requests for webpages that I or my colleagues do from the office's Windows network get repeated by another IP (that we don't know) a couple of seconds later. The user agent repeating our requests is Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 5.1; Trident/4.0; .NET CLR 2.0.50727; .NET CLR 3.0.04506.648; .NET CLR 3.5.21022; .NET CLR 3.0.4506.2152; .NET CLR 3.5.30729; InfoPath.2) Has anyone an idea? Update: I've got some more information now. The referrer of the replicate is set to the URL I requested before and it's not the exact same request as the protocol version is changed from 'HTTP/1.1' to 'HTTP/1.0'. The IP is not just one, it's just one of a subnet (80.40.134.*). It's just the first request to a resource that's get repeated, so it seems the "spy" is building up some kind of cache of visited places. The repeater is also picky. I tried randomly URLs with different HTTP status codes and different file patterns. 301s and 200s are redone, 404s not. Image extensions seem to be ignored. While doing my tests I discovered that this behavior seems to be common as I found other clients visiting just after the first requests: 66.249.73.184 - - [25/Oct/2012:10:51:33 +0100] "GET /foobar/ HTTP/1.1" 200 10952 "-" "Mediapartners-Google" 50.17.125.180 - - [25/Oct/2012:10:51:33 +0100] "GET /foobar/ HTTP/1.1" 200 41312 "-" "Mozilla/5.0 (compatible; proximic; +http://www.proximic.com/info/spider.php)" I wasn't aware about this practice, so I don't see it that much as a threat anymore. I still want to find out who this is, so any further help is appreciated. I'll try later if this also happens if I query some other server where I have access to the access logs and will update here then.

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  • What is the difference between running a Windows service vs. running through shell?

    - by Zack
    I am trying to troubleshoot an issue on a Windows 2008 server where running attempting to connect to a "Timberline Data Source" ODBC driver crashes if the call is in a "service" context, but succeeds if the call is initiated manually in a Remote Desktop session. I have set the service to run as my user. I'm wondering if, all else being equal (user, machine, etc), are there any fundamental security/environment differences between running a process as a service vs manually? --- Implementation Details --- In case it is helpful for anyone, I had a system that started as an attempt to connect to a Timberline Database using ODBC and a Python CGI script called via IIS 7. The script itself works fine, however, as soon as I attempt to perform the ODBC connect function, the script crashes without throwing an exception. The script was able to connect fine when executed via command line. The same thing happened when using a C#/.net service, attempting to run via Apache, Windows Scheduler or even a 3rd party scheduling tool. With the last option (the 3rd party scheduling tool, pycron) I set the service up log in as my user and had the same issue (I confirmed via Task Manager that the process running user was, in fact, me). It just doesn't make sense to me why a service, which should be running as my user, appears to still be operating in a different security context or environment. Also, if it's important, the Timberline database is referenced by computer name on the network ("\\timberline-server\Timberline Office\Accounts\AT" or something to that effect) I also realized that, as Joel pointed out, the server DOES have a mapped drive ("Y:" which is mapped to "\\timberline-server\Timberline Office") The DSN is set up at the "System DSN" level which, according to the ODBC Administration Tool, means that the DSN is available to users and services Since I'm not allowed to answer this question yet, I'll post the solution that I arrived on: As Joel Coel mentioned, there actually was a mapped drive scenario. I didn't realize this because the DSN specified a path using UNC. However, it seems as though the actual Timberline Driver referred to a mapped drive. Since services don't start with the mapped drive, I was forced to add the drive mapping code into my service. Since it was written in python, I used code from a Stackoverflow answer that was able to map the drive on the fly.

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  • Tips for maximizing Nginx requests/sec?

    - by linkedlinked
    I'm building an analytics package, and project requirements state that I need to support 1 billion hits per day. Yep, "billion". In other words, no less than 12,000 hits per second sustained, and preferably some room to burst. I know I'll need multiple servers for this, but I'm trying to get maximum performance out of each node before "throwing more hardware at it". Right now, I have the hits-tracking portion completed, and well optimized. I pretty much just save the requests straight into Redis (for later processing with Hadoop). The application is Python/Django with a gunicorn for the gateway. My 2GB Ubuntu 10.04 Rackspace server (not a production machine) can serve about 1200 static files per second (benchmarked using Apache AB against a single static asset). To compare, if I swap out the static file link with my tracking link, I still get about 600 requests per second -- I think this means my tracker is well optimized, because it's only a factor of 2 slower than serving static assets. However, when I benchmark with millions of hits, I notice a few things -- No disk usage -- this is expected, because I've turned off all Nginx logs, and my custom code doesn't do anything but save the request details into Redis. Non-constant memory usage -- Presumably due to Redis' memory managing, my memory usage will gradually climb up and then drop back down, but it's never once been my bottleneck. System load hovers around 2-4, the system is still responsive during even my heaviest benchmarks, and I can still manually view http://mysite.com/tracking/pixel with little visible delay while my (other) server performs 600 requests per second. If I run a short test, say 50,000 hits (takes about 2m), I get a steady, reliable 600 requests per second. If I run a longer test (tried up to 3.5m so far), my r/s degrades to about 250. My questions -- a. Does it look like I'm maxing out this server yet? Is 1,200/s static files nginx performance comparable to what others have experienced? b. Are there common nginx tunings for such high-volume applications? I have worker threads set to 64, and gunicorn worker threads set to 8, but tweaking these values doesn't seem to help or harm me much. c. Are there any linux-level settings that could be limiting my incoming connections? d. What could cause my performance to degrade to 250r/s on long-running tests? Again, the memory is not maxing out during these tests, and HDD use is nil. Thanks in advance, all :)

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  • What else can I do to secure my Linux server?

    - by eric01
    I want to put a web application on my Linux server: I will first explain to you what the web app will do and then I will tell you what I did so far to secure my brand new Linux system. The app will be a classified ads website (like gumtree.co.uk) where users can sell their items, upload images, send to and receive emails from the admin. It will use SSL for some pages. I will need SSH. So far, what I did to secure my stock Ubuntu (latest version) is the following: NOTE: I probably did some things that will prevent the application from doing all its tasks, so please let me know of that. My machine's sole purpose will be hosting the website. (I put numbers as bullet points so you can refer to them more easily) 1) Firewall I installed Uncomplicated Firewall. Deny IN & OUT by default Rules: Allow IN & OUT: HTTP, IMAP, POP3, SMTP, SSH, UDP port 53 (DNS), UDP port 123 (SNTP), SSL, port 443 (the ones I didn't allow were FTP, NFS, Samba, VNC, CUPS) When I install MySQL & Apache, I will open up Port 3306 IN & OUT. 2) Secure the partition in /etc/fstab, I added the following line at the end: tmpfs /dev/shm tmpfs defaults,rw 0 0 Then in console: mount -o remount /dev/shm 3) Secure the kernel In the file /etc/sysctl.conf, there are a few different filters to uncomment. I didn't know which one was relevant to web app hosting. Which one should I activate? They are the following: A) Turn on Source Address Verification in all interfaces to prevent spoofing attacks B) Uncomment the next line to enable packet forwarding for IPv4 C) Uncomment the next line to enable packet forwarding for IPv6 D) Do no accept ICMP redirects (we are not a router) E) Accept ICMP redirects only for gateways listed in our default gateway list F) Do not send ICMP redirects G) Do not accept IP source route packets (we are not a router) H) Log Martian Packets 4) Configure the passwd file Replace "sh" by "false" for all accounts except user account and root. I also did it for the account called sshd. I am not sure whether it will prevent SSH connection (which I want to use) or if it's something else. 5) Configure the shadow file In the console: passwd -l to lock all accounts except user account. 6) Install rkhunter and chkrootkit 7) Install Bum Disabled those services: "High performance mail server", "unreadable (kerneloops)","unreadable (speech-dispatcher)","Restores DNS" (should this one stay on?) 8) Install Apparmor_profiles 9) Install clamav & freshclam (antivirus and update) What did I do wrong and what should I do more to secure this Linux machine? Thanks a lot in advance

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  • Nginx common configuration that I might have missed

    - by ApPeL
    I recently moved from Apache Mod_wsgi to Nginx, and I have seen a major improvement on speed a lowering on memory usage and I am generally very happy with the it. I am not a server expert, so please be gentle. I am wondering if there are any small configuration that I might have missed, that will cause me some issues in the long run... Please see my nginx.conf file user nginx nginx; worker_processes 4; error_log /var/log/nginx/error_log info; events { worker_connections 1024; use epoll; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] ' '"$request" $status $bytes_sent ' '"$http_referer" "$http_user_agent" ' '"$gzip_ratio"'; client_header_timeout 10m; client_body_timeout 10m; send_timeout 10m; connection_pool_size 256; client_header_buffer_size 1k; large_client_header_buffers 4 2k; request_pool_size 4k; gzip on; gzip_min_length 1100; gzip_buffers 4 8k; gzip_types text/plain; output_buffers 1 32k; postpone_output 1460; sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 75 20; ignore_invalid_headers on; index index.html; server { listen 80; server_name localhost; location /media/ { root /www/django_test1/myapp; # Notice this is the /media folder that we create above } location /mediaadmin/ { alias /opt/python2.6/lib/python2.6/site-packages/django/contrib/admin/media/; # Notice this is the /media folder that we create above } location / { # host and port to fastcgi server fastcgi_pass 127.0.0.1:8080; fastcgi_param SERVER_ADDR $server_addr; fastcgi_param SERVER_PORT $server_port; fastcgi_param SERVER_NAME $server_name; fastcgi_param SERVER_PROTOCOL $server_protocol; fastcgi_param PATH_INFO $fastcgi_script_name; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param QUERY_STRING $query_string; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_pass_header Authorization; fastcgi_intercept_errors off; client_max_body_size 100M; } access_log /var/log/nginx/localhost.access_log main; error_log /var/log/nginx/localhost.error_log; } }

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  • unable to connect site to different port

    - by JohnMerlino
    I have a domain was registered at godaddy named http://mysite.com/. I logged into godaddy and I went to All Products Domains Domain Management. I clicked on the appropriate domain and it took me to the Domain Details page. I clicked Launch under DNS Manager and it took me to the Zone File Editor. I noticed that notify.mysite.com was pointing to an IP address pointing to a dead server, so I switched it to an operating server. Then I pinged the domain to see where it was pointing to and it was correctly pointing to the working server. So I copied the default configuration under sites-available: sudo cp default notify.mysite.com. And then I made some edits to it to have it point to a different document root to serve files at a different port: Listen 1740 Listen 64.135.xx.xxx:1740 #I also tried this as well: NameVirtualHost 64.135.xx.xxx:1740 <VirtualHost 64.135.xx.xxx:1740> ServerAdmin [email protected] ServerName notify.mysite.com DocumentRoot /var/www/test/public <Directory /var/www/test/public> Order allow,deny allow from all </Directory> ErrorLog ${APACHE_LOG_DIR}/error.log LogLevel warn CustomLog ${APACHE_LOG_DIR}/access.log combined </VirtualHost> Then I enabled the virtual host. Then I went to the document root and added an index.html file with some text in it. Then I restarted apache. The restart gave no errors. Then I type the correct domain in URL: http://notify.mysite.com:1740/ and I get: Oops! Google Chrome could not connect to notify.mysite.com:1740 Somehow it took out all my other sites. Now even the ones that were responding on port 80 are no longe responding, even though I did not touch the virtual hosts for them. I get this message now: Oops! Google Chrome could not connect to mysite.com However, ping responds: ping mysite.com PING mysite.com (64.135.12.134): 56 data bytes 64 bytes from 64.135.12.134: icmp_seq=0 ttl=49 time=20.839 ms 64 bytes from 64.135.12.134: icmp_seq=1 ttl=49 time=20.489 ms The result of telnet: $ telnet guarddoggps.com 80 Trying 64.135.12.134... telnet: connect to address 64.135.12.134: Connection refused telnet: Unable to connect to remote host

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  • Implements EAN13 and UPC-A barcode in PDF using fpdf in classic ASP

    - by Jeremy N
    /* FPDF library for ASP can be downloaded from: http://www.aspxnet.it/public/default.asp INFORMATIONS: Translated by: Jeremy Author: Olivier License: Freeware DESCRIPTION: This script implements EAN13 and UPC-A barcodes (the second being a particular case of the first one). Bars are drawn directly in the PDF (no image is generated) function EAN13(x,y,barcode,h,w) -x = x coordinate to start drawing the barcode -y = y coordinate to start drawing the barcode -barcode = code to write (must be all numeric) -h = height of the bar -w = the minimum width of individual bar function UPC_A(x,y,barcode,h,w) Same parameters An EAN13 barcode is made up of 13 digits, UPC-A of 12 (leading zeroes are added if necessary). The last digit is a check digit; if it's not supplied or if it is incorrect, it will be automatically computed. USAGE: Copy all of this text and save it in a file called barcode.ext file under fpdf/extends folder EXAMPLE: Set pdf=CreateJsObject("FPDF") pdf.CreatePDF "P","mm","letter" pdf.SetPath("fpdf/") pdf.LoadExtension("barcode") pdf.Open() pdf.AddPage() 'set the fill color to black pdf.setfillcolor 0,0,0 pdf.UPC_A 80,40,"123456789012",16,0.35 pdf.Close() pdf.NewOutput "" , true, "test.pdf" */ this.EAN13=function (x,y,barcode,h,w) { return this.Barcode(x,y,barcode,h,w,13); }; this.UPC_A=function (x,y,barcode,h,w) { return this.Barcode(x,y,barcode,h,w,12); }; function GetCheckDigit(barCode) { bc = barCode.replace(/[^0-9]+/g,''); total = 0; //Get Odd Numbers for (i=bc.length-1; i=0; i=i-2) { total = total + parseInt(bc.substr(i,1)); } //Get Even Numbers for (i=bc.length-2; i=0; i=i-2) { temp = parseInt(bc.substr(i,1)) * 2; if (temp 9) { tens = Math.floor(temp/10); ones = temp - (tens*10); temp = tens + ones; } total = total + temp; } //Determine the checksum modDigit = (10 - total % 10) % 10; return modDigit.toString(); } //Test validity of check digit function TestCheckDigit(barcode) { var cd=GetCheckDigit(barcode.substring(0,barcode.length-1)); return cd==parseInt(barcode.substring(barcode.length-1,1)); } this.Barcode=function Barcode(x,y,barcode,h,w,len) { //Padding while(barcode.length < len-1) { barcode = '0' + barcode; } if(len==12) {barcode='0' + barcode;} //Add or control the check digit if(barcode.length==12) { barcode += GetCheckDigit(barcode); } else { //if the check digit is incorrect, fix the check digit. if(!TestCheckDigit(barcode)) { barcode = barcode.substring(0,barcode.length-1) + GetCheckDigit(barcode.substring(0,barcode.length-1)); } } //Convert digits to bars var codes=[['0001101','0011001','0010011','0111101','0100011','0110001','0101111','0111011','0110111','0001011'], ['0100111','0110011','0011011','0100001','0011101','0111001','0000101','0010001','0001001','0010111'], ['1110010','1100110','1101100','1000010','1011100','1001110','1010000','1000100','1001000','1110100'] ]; var parities=[[0,0,0,0,0,0], [0,0,1,0,1,1], [0,0,1,1,0,1], [0,0,1,1,1,0], [0,1,0,0,1,1], [0,1,1,0,0,1], [0,1,1,1,0,0], [0,1,0,1,0,1], [0,1,0,1,1,0], [0,1,1,0,1,0] ]; var code='101'; var p=parities[parseInt(barcode.substr(0,1))]; var i; for(i=1;i<=6;i++) { code+= codes[p[i-1]][parseInt(barcode.substr(i,1))]; } code+='01010'; for(i=7;i<=12;i++) { code+= codes[2][parseInt(barcode.substr(i,1))]; } code+='101'; //Draw bars for(i=0;i<code.length;i++) { if(code.substr(i,1)=='1') { this.Rect(x+i*w,y,w,h,'F'); } } //Print text uder barcode. this.SetFont('Arial','',12); //Set the x so that the font is centered under the barcode this.Text(x+parseInt(0.5*barcode.length)*w,y+h+11/this.k,barcode.substr(barcode.length-len,len)); }

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  • Point in polygon OR point on polygon using LINQ

    - by wageoghe
    As noted in an earlier question, How to Zip enumerable with itself, I am working on some math algorithms based on lists of points. I am currently working on point in polygon. I have the code for how to do that and have found several good references here on SO, such as this link Hit test. So, I can figure out whether or not a point is in a polygon. As part of determining that, I want to determine if the point is actually on the polygon. This I can also do. If I can do all of that, what is my question you might ask? Can I do it efficiently using LINQ? I can already do something like the following (assuming a Pairwise extension method as described in my earlier question as well as in links to which my question/answers links, and assuming a Position type that has X and Y members). I have not tested much, so the lambda might not be 100% correct. Also, it does not take very small differences into account. public static PointInPolygonLocation PointInPolygon(IEnumerable<Position> pts, Position pt) { int numIntersections = pts.Pairwise( (p1, p2) => { if (p1.Y != p2.Y) { if ((p1.Y >= pt.Y && p2.Y < pt.Y) || (p1.Y < pt.Y && p2.Y >= pt.Y)) { if (p1.X < p1.X && p2.X < pt.X) { return 1; } if (p1.X < pt.X || p2.X < pt.X) { if (((pt.Y - p1.Y) * ((p1.X - p2.X) / (p1.Y - p2.Y)) * p1.X) < pt.X) { return 1; } } } } return 0; }).Sum(); if (numIntersections % 2 == 0) { return PointInPolygonLocation.Outside; } else { return PointInPolygonLocation.Inside; } } This function, PointInPolygon, takes the input Position, pt, iterates over the input sequence of position values, and uses the Jordan Curve method to determine how many times a ray extended from pt to the left intersects the polygon. The lambda expression will yield, into the "zipped" list, 1 for every segment that is crossed, and 0 for the rest. The sum of these values determines if pt is inside or outside of the polygon (odd == inside, even == outside). So far, so good. Now, for any consecutive pairs of position values in the sequence (i.e. in any execution of the lambda), we can also determine if pt is ON the segment p1, p2. If that is the case, we can stop the calculation because we have our answer. Ultimately, my question is this: Can I perform this calculation (maybe using Aggregate?) such that we will only iterate over the sequence no more than 1 time AND can we stop the iteration if we encounter a segment that pt is ON? In other words, if pt is ON the very first segment, there is no need to examine the rest of the segments because we have the answer. It might very well be that this operation (particularly the requirement/desire to possibly stop the iteration early) does not really lend itself well to the LINQ approach. It just occurred to me that maybe the lambda expression could yield a tuple, the intersection value (1 or 0 or maybe true or false) and the "on" value (true or false). Maybe then I could use TakeWhile(anontype.PointOnPolygon == false). If I Sum the tuples and if ON == 1, then the point is ON the polygon. Otherwise, the oddness or evenness of the sum of the other part of the tuple tells if the point is inside or outside.

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  • Java: micro-optimizing array manipulation

    - by Martin Wiboe
    Hello all, I am trying to make a Java port of a simple feed-forward neural network. This obviously involves lots of numeric calculations, so I am trying to optimize my central loop as much as possible. The results should be correct within the limits of the float data type. My current code looks as follows (error handling & initialization removed): /** * Simple implementation of a feedforward neural network. The network supports * including a bias neuron with a constant output of 1.0 and weighted synapses * to hidden and output layers. * * @author Martin Wiboe */ public class FeedForwardNetwork { private final int outputNeurons; // No of neurons in output layer private final int inputNeurons; // No of neurons in input layer private int largestLayerNeurons; // No of neurons in largest layer private final int numberLayers; // No of layers private final int[] neuronCounts; // Neuron count in each layer, 0 is input // layer. private final float[][][] fWeights; // Weights between neurons. // fWeight[fromLayer][fromNeuron][toNeuron] // is the weight from fromNeuron in // fromLayer to toNeuron in layer // fromLayer+1. private float[][] neuronOutput; // Temporary storage of output from previous layer public float[] compute(float[] input) { // Copy input values to input layer output for (int i = 0; i < inputNeurons; i++) { neuronOutput[0][i] = input[i]; } // Loop through layers for (int layer = 1; layer < numberLayers; layer++) { // Loop over neurons in the layer and determine weighted input sum for (int neuron = 0; neuron < neuronCounts[layer]; neuron++) { // Bias neuron is the last neuron in the previous layer int biasNeuron = neuronCounts[layer - 1]; // Get weighted input from bias neuron - output is always 1.0 float activation = 1.0F * fWeights[layer - 1][biasNeuron][neuron]; // Get weighted inputs from rest of neurons in previous layer for (int inputNeuron = 0; inputNeuron < biasNeuron; inputNeuron++) { activation += neuronOutput[layer-1][inputNeuron] * fWeights[layer - 1][inputNeuron][neuron]; } // Store neuron output for next round of computation neuronOutput[layer][neuron] = sigmoid(activation); } } // Return output from network = output from last layer float[] result = new float[outputNeurons]; for (int i = 0; i < outputNeurons; i++) result[i] = neuronOutput[numberLayers - 1][i]; return result; } private final static float sigmoid(final float input) { return (float) (1.0F / (1.0F + Math.exp(-1.0F * input))); } } I am running the JVM with the -server option, and as of now my code is between 25% and 50% slower than similar C code. What can I do to improve this situation? Thank you, Martin Wiboe

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  • building median for each string in IList<IDictionary<string, double>>

    - by Oliver
    Actually i have a little brain bender and and just can't find the right direction to get it to work: Given is an IList<IDictionary<string, double>> and it is filled as followed: Name|Value ----+----- "x" | 3.8 "y" | 4.2 "z" | 1.5 ----+----- "x" | 7.2 "y" | 2.9 "z" | 1.3 ----+----- ... | ... To fill this up with some random data i used the following methods: var list = CreateRandomPoints(new string[] { "x", "y", "z" }, 20); This will work as followed: private IList<IDictionary<string, double>> CreateRandomPoints(string[] variableNames, int count) { var list = new List<IDictionary<string, double>>(count); list.AddRange(CreateRandomPoints(variableNames).Take(count)); return list; } private IEnumerable<IDictionary<string, double>> CreateRandomPoints(string[] variableNames) { while (true) yield return CreateRandomLine(variableNames); } private IDictionary<string, double> CreateRandomLine(string[] variableNames) { var dict = new Dictionary<string, double>(variableNames.Length); foreach (var variable in variableNames) { dict.Add(variable, _Rand.NextDouble() * 10); } return dict; } Also i can say that it is already ensured that every Dictionary within the list contains the same keys (but from list to list the names and count of the keys can change). So that's what i got. Now to the things i need: I'd like to get the median (or any other math aggregate operation) of each Key within all the dictionaries, so that my function to call would look something like: IDictionary<string, double> GetMedianOfRows(this IList<IDictionary<string, double>> list) The best would be to give some kind of aggregate operation as a parameter to the function to make it more generic (don't know if the func has the correct parameters, but should imagine what i'd like to do): private IDictionary<string, double> Aggregate(this IList<IDictionary<string, double>> list, Func<IEnumerable<double>, double> aggregator) Also my actual biggest problem is to do the job with a single iteration over the list, cause if within the list are 20 variables with 1000 values i don't like to iterate 20 times over the list. Instead i would go one time over the list and compute all twenty variables at once (The biggest advantage of doing it that way would be to use this also as IEnumerable<T> on any part of the list in a later step). So here is the code i already got: public static IDictionary<string, double> GetMedianOfRows(this IList<IDictionary<string, double>> list) { //Check of parameters is left out! //Get first item for initialization of result dictionary var firstItem = list[0]; //Create result dictionary and fill in variable names var dict = new Dictionary<string, double>(firstItem.Count); //Iterate over the whole list foreach (IDictionary<string, double> row in list) { //Iterate over each key/value pair within the list foreach (var kvp in row) { //How to determine median of all values? } } return dict; } Just to be sure here is a little explanation about the Median.

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  • Visual C++ 2010 Winform Errors C2238, C2059, C1075.

    - by tracelez
    It errors when I try compile. I cut the code out of the program and the program works and complies correctly. Not sure why it doesn't like this. This part of the code does single digit math with numeric strings that are converted into a char arrays. ** Error 2 error C2238: unexpected token(s) preceding ';' C:\Users\Alpha\documents\visual studio 2010\Projects\Win32 Form c++\Win32 Form c++\Win32 Form c++.cpp 10 1 Win32 Form c++ ** Error 1 error C2059: syntax error : 'namespace' C:\Users\Alpha\documents\visual studio 2010\Projects\Win32 Form c++\Win32 Form c++\Win32 Form c++.cpp 10 1 Win32 Form c++ ** Error 3 error C1075: end of file found before the left brace '{' at 'c:\users\alpha\documents\visual studio 2010\projects\win32 form c++\win32 form c++\Form1.h(40)' was matched C:\Users\Alpha\documents\visual studio 2010\Projects\Win32 Form c++\Win32 Form c++\Win32 Form c++.cpp 23 1 Win32 Form c++ ////// ////// // chX[] and chY[] are char arrays from functional part of program std::reverse( chX, &chX[ strlen( chX ) ] ); std::reverse( chY, &chY[ strlen( chY ) ] ); // makes sure x is larger or equal to y...makes looping logic easier if (strlen(chX) < strlen(chY)) { char *chZ = chX; chX = chY; chY = chZ; } //Variables for this part of the program char chX2; char chY2; std::string strSum; int sum = 0; bool carryth1 = false; int x=0; int y=0; for (int i = 0; i <= (strlen(chX)-1); i++) { if (i <= strlen(chY)-1) { chX2= chX[i]; chY2= chY[i]; x = atoi(chX2); y = atoi(chY2); //x = atoi(chX[i]); sum = x+y+(int)carryth1; carryth1 = false; if (sum > 9) { if(i == 0) { sum -=10; strSum = itoa(sum); carryth1 = true; } else { sum -=10; strSum += itoa(sum); carryth1 = true; } } else { if(i == 0) { strSum = itoa(sum); } else { strSum += itoa(sum); } } else { y = 0; chX2= chX[i]; x = atoi(chX2); sum = x+y+(int)carryth1; if((i == strlen(chX)-1)&& (carryth1 == true) && (x == 9)) { strSum += "10"; } else { strSum = itoa(sum); } } std::reverse( strSum, &strSum[ strlen( strSum ) ] ); //Creates new string for txtDisplay this simplifies conversions String^ strDisplay = "X is " + gcnew String((strX1.c_str())) + " Y is " +gcnew String((strY1.c_str())) + " \r\n " ; strDisplay += "The sum of the X + Y = "; txtDisplay->Text = gcnew String((strSum.c_str())) ;

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  • Interactive Data Language, IDL: Does anybody care?

    - by Alex
    Anyone use a language called Interactive Data Language, IDL? It is popular with scientists. I think it is a poor language because it is proprietary (every terminal running it has to have an expensive license purchased) and it has minimal support (try searching for IDL, the language, right now on stack) . I am trying to convince my colleagues to stop using it and learn C/C++/Python/Fortran/Java/Ruby. Does anybody know about or even care about IDL enough to have opinions on it? What do you think of it? Should I tell my colleagues to stop wasting their time on it now? How can I convince them? Edit: People are getting the impression that I don't know or use IDL. Also, I said IDL has minimal support which is true in one sense, so I must clarify that the scientific libraries are indeed large. I use IDL all the time, but this is exactly the problem: I am only using IDL because colleagues use it. There is a file format IDL uses, the .sav, which can only be opened in IDL. So I must use IDL to work with this data and transfer the data back to colleagues, but I know I would be more efficient in another language. This is like someone sending you a microsoft word file in an email attachment and if you don't understand how wrong that is then you probably write too many words not enough code and you bought microsoft word. Edit: As an alternative to IDL Python is popular. Here is a list of The Pros of IDL (and the cons) from AstroBetter: Pros of IDL Mature many numerical and astronomical libraries available Wide astronomical user base Numerical aspect well integrated with language itself Many local users with deep experience Faster for small arrays Easier installation Good, unified documentation Standard GUI run/debug tool (IDLDE) Single widget system (no angst about which to choose or learn) SAVE/RESTORE capability Use of keyword arguments as flags more convenient Cons of IDL Narrow applicability, not well suited to general programming Slower for large arrays Array functionality less powerful Table support poor Limited ability to extend using C or Fortran, such extensions hard to distribute and support Expensive, sometimes problem collaborating with others that don’t have or can’t afford licenses. Closed source (only RSI can fix bugs) Very awkward to integrate with IRAF tasks Memory management more awkward Single widget system (useless if working within another framework) Plotting: Awkward support for symbols and math text Many font systems, portability issues (v5.1 alleviates somewhat) not as flexible or as extensible plot windows not intrinsically interactive (e.g., pan & zoom) Pros of Python Very general and powerful programming language, yet easy to learn. Strong, but optional, Object Oriented programming support Very large user and developer community, very extensive and broad library base Very extensible with C, C++, or Fortran, portable distribution mechanisms available Free; non-restrictive license; Open Source Becoming the standard scripting language for astronomy Easy to use with IRAF tasks Basis of STScI application efforts More general array capabilities Faster for large arrays, better support for memory mapping Many books and on-line documentation resources available (for the language and its libraries) Better support for table structures Plotting framework (matplotlib) more extensible and general Better font support and portability (only one way to do it too) Usable within many windowing frameworks (GTK, Tk, WX, Qt…) Standard plotting functionality independent of framework used plots are embeddable within other GUIs more powerful image handling (multiple simultaneous LUTS, optional resampling/rescaling, alpha blending, etc) Support for many widget systems Strong local influence over capabilities being developed for Python Cons of Python More items to install separately Not as well accepted in astronomical community (but support clearly growing) Scientific libraries not as mature: Documentation not as complete, not as unified Not as deep in astronomical libraries and utilities Not all IDL numerical library functions have corresponding functionality in Python Some numeric constructs not quite as consistent with language (or slightly less convenient than IDL) Array indexing convention “backwards” Small array performance slower No standard GUI run/debug tool Support for many widget systems (angst regarding which to choose) Current lack of function equivalent to SAVE/RESTORE in IDL matplotlib does not yet have equivalents for all IDL 2-D plotting capability (e.g., surface plots) Use of keyword arguments used as flags less convenient Plotting: comparatively immature, still much development going on missing some plot type (e.g., surface) 3-d capability requires VTK (though matplotlib has some basic 3-d capability)

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  • Trouble calculating correct decimal digits.

    - by Crath
    I am trying to create a program that will do some simple calculations, but am having trouble with the program not doing the correct math, or placing the decimal correctly, or something. Some other people I asked cannot figure it out either. Here is the code: http://pastie.org/887352 When you enter the following data: Weekly Wage: 500 Raise: 3 Years Employed: 8 It outputs the following data: Year Annual Salary 1 $26000.00 2 $26780.00 3 $27560.00 4 $28340.00 5 $29120.00 6 $29900.00 7 $30680.00 8 $31460.00 And it should be outputting: Year Annual Salary 1 $26000.00 2 $26780.00 3 $27583.40 4 $28410.90 5 $29263.23 6 $30141.13 7 $31045.36 8 $31976.72 Here is the full description of the task: 8.17 ( Pay Raise Calculator Application) Develop an application that computes the amount of money an employee makes each year over a user- specified number of years. Assume the employee receives a pay raise once every year. The user specifies in the application the initial weekly salary, the amount of the raise (in percent per year) and the number of years for which the amounts earned will be calculated. The application should run as shown in Fig. 8.22. in your text. (fig 8.22 is the output i posted above as what my program should be posting) Opening the template source code file. Open the PayRaise.cpp file in your text editor or IDE. Defining variables and prompting the user for input. To store the raise percentage and years of employment that the user inputs, define int variables rate and years, in main after line 12. Also define double variable wage to store the user’s annual wage. Then, insert statements that prompt the user for the raise percentage, years of employment and starting weekly wage. Store the values typed at the keyboard in the rate, years and wage variables, respectively. To find the annual wage, multiply the new wage by 52 (the number of weeks per year) and store the result in wage. Displaying a table header and formatting output. Use the left and setw stream manipulators to display a table header as shown in Fig. 8.22 in your text. The first column should be six characters wide. Then use the fixed and setprecision stream manipulators to format floating- point values with two positions to the left of the decimal point. Writing a for statement header. Insert a for statement. Before the first semicolon in the for statement header, define and initialize the variable counter to 1. Before the second semicolon, enter a loop- continuation condition that will cause the for statement to loop until counter has reached the number of years entered. After the second semicolon, enter the increment of counter so that the for statement executes once for each number of years. Calculating the pay raise. In the body of the for statement, display the value of counter in the first column and the value of wage in the second column. Then calculate the new weekly wage for the following year, and store the resulting value in the wage variable. To do this, add 1 to the percentage increase (be sure to divide the percentage by 100.0 ) and multiply the result by the current value in wage. Save, compile and run the application. Input a raise percentage and a number of years for the wage increase. View the results to ensure that the correct years are displayed and that the future wage results are correct. Close the Command Prompt window. We can not figure it out! Any help would be greatly appreciated, thanks!

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  • Openlayers - LayerRedraw() / Feature rotation / Linestring coords

    - by Ozaki
    TLDR: I have an Openlayers map with a layer called 'track' I want to remove track and add track back in. Or figure out how to plot a triangle based off one set of coords & a heading(see below). I have an image 'imageFeature' on a layer that rotates on load to the direction being set. I want it to update this rotation that is set in 'styleMap' on a layer called 'tracking'. I set the var 'stylemap' to apply the external image & rotation. The 'imageFeature' is added to the layer at the coords specified. 'imageFeature' is removed. 'imageFeature' is added again in its new location. Rotation is not applied.. As the 'styleMap' applies to the layer I think that I have to remove the layer and add it again rather than just the 'imageFeature' Layer: var tracking = new OpenLayers.Layer.GML("Tracking", "coordinates.json", { format: OpenLayers.Format.GeoJSON, styleMap: styleMap }); styleMap: var styleMap = new OpenLayers.StyleMap({ fillOpacity: 1, pointRadius: 10, rotation: heading, }); Now wrapped in a timed function the imageFeature: map.layers[3].addFeatures(new OpenLayers.Feature.Vector( new OpenLayers.Geometry.Point(longitude, latitude), {rotation: heading, type: parseInt(Math.random() * 3)} )); Type refers to a lookup of 1 of 3 images.: styleMap.addUniqueValueRules("default", "type", lookup); var lookup = { 0: {externalGraphic: "Image1.png", rotation: heading}, 1: {externalGraphic: "Image2.png", rotation: heading}, 2: {externalGraphic: "Image3.png", rotation: heading} } I have tried the 'redraw()' function: but it returns "tracking is undefined" or "map.layers[2]" is undefined. tracking.redraw(true); map.layers[2].redraw(true); Heading is a variable: from a JSON feed. var heading = 13.542; But so far can't get anything to work it will only rotate the image onload. The image will move in coordinates as it should though. So what am I doing wrong with the redraw function or how can I get this image to rotate live? Thanks in advance -Ozaki Add: I managed to get map.layers[2].redraw(true); to sucessfully redraw layer 2. But it still does not update the rotation. I am thinking because the stylemap is updating. But it runs through the style map every n sec, but no updates to rotation and the variable for heading is updating correctly if i put a watch on it in firebug. If I were to draw a triangle with an array of points & linestring. How would I go about facing the triangle towards the heading. I have the Lon/lat of one point and the heading. var points = new Array( new OpenLayers.Geometry.Point(lon1, lat1), new OpenLayers.Geometry.Point(lon2, lat2), new OpenLayers.Geometry.Point(lon3, lat3) ); var line = new OpenLayers.Geometry.LineString(points); Looking for any way to solve this problem Image or Line anyone know how to do either added a 100rep bounty I am really stuck with this.

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  • Is it bad practice to apply class-based design to JavaScript programs?

    - by helixed
    JavaScript is a prototyped-based language, and yet it has the ability to mimic some of the features of class-based object-oriented languages. For example, JavaScript does not have a concept of public and private members, but through the magic of closures, it's still possible to provide the same functionality. Similarly, method overloading, interfaces, namespaces and abstract classes can all be added in one way or another. Lately, as I've been programming in JavaScript, I've felt like I'm trying to turn it into a class-based language instead of using it in the way it's meant to be used. It seems like I'm trying to force the language to conform to what I'm used to. The following is some JavaScript code I've written recently. It's purpose is to abstract away some of the effort involved in drawing to the HTML5 canvas element. /* Defines the Drawing namespace. */ var Drawing = {}; /* Abstract base which represents an element to be drawn on the screen. @param The graphical context in which this Node is drawn. @param position The position of the center of this Node. */ Drawing.Node = function(context, position) { return { /* The method which performs the actual drawing code for this Node. This method must be overridden in any subclasses of Node. */ draw: function() { throw Exception.MethodNotOverridden; }, /* Returns the graphical context for this Node. @return The graphical context for this Node. */ getContext: function() { return context; }, /* Returns the position of this Node. @return The position of this Node. */ getPosition: function() { return position; }, /* Sets the position of this Node. @param thePosition The position of this Node. */ setPosition: function(thePosition) { position = thePosition; } }; } /* Define the shape namespace. */ var Shape = {}; /* A circle shape implementation of Drawing.Node. @param context The graphical context in which this Circle is drawn. @param position The center of this Circle. @param radius The radius of this circle. @praram color The color of this circle. */ Shape.Circle = function(context, position, radius, color) { //check the parameters if (radius < 0) throw Exception.InvalidArgument; var node = Drawing.Node(context, position); //overload the node drawing method node.draw = function() { var context = this.getContext(); var position = this.getPosition(); context.fillStyle = color; context.beginPath(); context.arc(position.x, position.y, radius, 0, Math.PI*2, true); context.closePath(); context.fill(); } /* Returns the radius of this Circle. @return The radius of this Circle. */ node.getRadius = function() { return radius; }; /* Sets the radius of this Circle. @param theRadius The new radius of this circle. */ node.setRadius = function(theRadius) { radius = theRadius; }; /* Returns the color of this Circle. @return The color of this Circle. */ node.getColor = function() { return color; }; /* Sets the color of this Circle. @param theColor The new color of this Circle. */ node.setColor = function(theColor) { color = theColor; }; //return the node return node; }; The code works exactly like it should for a user of Shape.Circle, but it feels like it's held together with Duct Tape. Can somebody provide some insight on this?

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  • How do I handle calls to AudioTrack from jni without crashing?

    - by icecream
    I was trying to write to an AudioTrack from a jni callback, and I get a signal 7 (SIGBUS), fault addr 00000000. I have looked at the Wolf3D example for odroid and they seem to use a android.os.Handler to post a Runnable that will do an update in the correct thread context. I have also tried AttachCurrentThread, but I fail in this case also. It works to play the sound when running from the constructor even if I wrap it in a thread and then post it to the handler. When I do the "same" via a callback from jni it fails. I assume I am braeaking some rules, but I haven't been able to figure out what they are. So far, I haven't found the answer here on SO. So I wonder if anyone knows how this should be done. EDIT: Answered below. The following code is to illustrate the problem. Java: package com.example.jniaudiotrack; import android.app.Activity; import android.media.AudioFormat; import android.media.AudioManager; import android.media.AudioTrack; import android.os.Bundle; import android.os.Handler; import android.util.Log; public class JniAudioTrackActivity extends Activity { AudioTrack mAudioTrack; byte[] mArr; public static final Handler mHandler = new Handler(); /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); mArr = new byte[2048]; for (int i = 0; i < 2048; i++) { mArr[i] = (byte) (Math.sin(i) * 128); } mAudioTrack = new AudioTrack(AudioManager.STREAM_MUSIC, 11025, AudioFormat.CHANNEL_CONFIGURATION_MONO, AudioFormat.ENCODING_PCM_8BIT, 2048, AudioTrack.MODE_STREAM); mAudioTrack.play(); new Thread(new Runnable() { public void run() { mHandler.post(new Runnable() { public void run() { mAudioTrack.write(mArr, 0, 2048); Log.i(TAG, "*** Handler from constructor ***"); } }); } }).start(); new Thread(new Runnable() { public void run() { audioFunc(); } }).start(); } public native void audioFunc(); @SuppressWarnings("unused") private void audioCB() { mHandler.post(new Runnable() { public void run() { mAudioTrack.write(mArr, 0, 2048); Log.i(TAG, "*** audioCB called ***"); } }); } private static final String TAG = "JniAudioTrackActivity"; static { System.loadLibrary("jni_audiotrack"); } } cpp: #include <jni.h> extern "C" { JNIEXPORT void Java_com_example_jniaudiotrack_JniAudioTrackActivity_audioFunc(JNIEnv* env, jobject obj); } JNIEXPORT void Java_com_example_jniaudiotrack_JniAudioTrackActivity_audioFunc(JNIEnv* env, jobject obj) { JNIEnv* jniEnv; JavaVM* vm; env->GetJavaVM(&vm); vm->AttachCurrentThread(&jniEnv, 0); jclass cls = env->GetObjectClass(obj); jmethodID audioCBID = env->GetMethodID(cls, "audioCB", "()V"); if (!audioCBID) { return; } env->CallVoidMethod(cls, audioCBID); } Trace snippet: I/DEBUG ( 1653): pid: 9811, tid: 9811 >>> com.example.jniaudiotrack <<< I/DEBUG ( 1653): signal 7 (SIGBUS), fault addr 00000000 I/DEBUG ( 1653): r0 00000800 r1 00000026 r2 00000001 r3 00000000 I/DEBUG ( 1653): r4 42385726 r5 41049e54 r6 bee25570 r7 ad00e540 I/DEBUG ( 1653): r8 000040f8 r9 41048200 10 41049e44 fp 00000000 I/DEBUG ( 1653): ip 000000f8 sp bee25530 lr ad02dbb5 pc ad012358 cpsr 20000010 I/DEBUG ( 1653): #00 pc 00012358 /system/lib/libdvm.so

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  • Deadlock problem

    - by DoomStone
    Hello i'm having a deadlock problem with the following code. It happens when i call the function getMap(). But i can't reealy see what can cause this. using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Drawing; using System.Drawing.Imaging; using System.Threading; using AForge; using AForge.Imaging; using AForge.Imaging.Filters; using AForge.Imaging.Textures; using AForge.Math.Geometry; namespace CDIO.Library { public class Polygon { List<IntPoint> hull; public Polygon(List<IntPoint> hull) { this.hull = hull; } public bool inPoly(int x, int y) { int i, j = hull.Count - 1; bool oddNodes = false; for (i = 0; i < hull.Count; i++) { if (hull[i].Y < y && hull[j].Y >= y || hull[j].Y < y && hull[i].Y >= y) { try { if (hull[i].X + (y - hull[i].X) / (hull[j].X - hull[i].X) * (hull[j].X - hull[i].X) < x) { oddNodes = !oddNodes; } } catch (DivideByZeroException e) { if (0 < x) { oddNodes = !oddNodes; } } } j = i; } return oddNodes; } public Rectangle getRectangle() { int x = -1, y = -1, width = -1, height = -1; foreach (IntPoint item in hull) { if (item.X < x || x == -1) x = item.X; if (item.Y < y || y == -1) y = item.Y; if (item.X > width || width == -1) width = item.X; if (item.Y > height || height == -1) height = item.Y; } return new Rectangle(x, y, width-x, height-y); } public Point[] getMap() { List<Point> points = new List<Point>(); lock (hull) { Rectangle rect = getRectangle(); for (int x = rect.X; x <= rect.X + rect.Width; x++) { for (int y = rect.Y; y <= rect.Y + rect.Height; y++) { if (inPoly(x, y)) points.Add(new Point(x, y)); } } } return points.ToArray(); } public float calculateArea() { List<IntPoint> list = new List<IntPoint>(); list.AddRange(hull); list.Add(hull[0]); float area = 0.0f; for (int i = 0; i < hull.Count; i++) { area += list[i].X * list[i + 1].Y - list[i].Y * list[i + 1].X; } area = area / 2; if (area < 0) area = area * -1; return area; } } }

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  • Explain the Peak and Flag Algorithm

    - by Isaac Levin
    EDIT Just was pointed that the requirements state peaks cannot be ends of Arrays. So I ran across this site http://codility.com/ Which gives you programming problems and gives you certificates if you can solve them in 2 hours. The very first question is one I have seen before, typically called the Peaks and Flags question. If you are not familiar A non-empty zero-indexed array A consisting of N integers is given. A peak is an array element which is larger than its neighbours. More precisely, it is an index P such that 0 < P < N - 1 and A[P - 1] < A[P] A[P + 1] . For example, the following array A: A[0] = 1 A[1] = 5 A[2] = 3 A[3] = 4 A[4] = 3 A[5] = 4 A[6] = 1 A[7] = 2 A[8] = 3 A[9] = 4 A[10] = 6 A[11] = 2 has exactly four peaks: elements 1, 3, 5 and 10. You are going on a trip to a range of mountains whose relative heights are represented by array A. You have to choose how many flags you should take with you. The goal is to set the maximum number of flags on the peaks, according to certain rules. Flags can only be set on peaks. What's more, if you take K flags, then the distance between any two flags should be greater than or equal to K. The distance between indices P and Q is the absolute value |P - Q|. For example, given the mountain range represented by array A, above, with N = 12, if you take: two flags, you can set them on peaks 1 and 5; three flags, you can set them on peaks 1, 5 and 10; four flags, you can set only three flags, on peaks 1, 5 and 10. You can therefore set a maximum of three flags in this case. Write a function that, given a non-empty zero-indexed array A of N integers, returns the maximum number of flags that can be set on the peaks of the array. For example, given the array above the function should return 3, as explained above. Assume that: N is an integer within the range [1..100,000]; each element of array A is an integer within the range [0..1,000,000,000]. Complexity: expected worst-case time complexity is O(N); expected worst-case space complexity is O(N), beyond input storage (not counting the storage required for input arguments). Elements of input arrays can be modified. So this makes sense, but I failed it using this code public int GetFlags(int[] A) { List<int> peakList = new List<int>(); for (int i = 0; i <= A.Length - 1; i++) { if ((A[i] > A[i + 1] && A[i] > A[i - 1])) { peakList.Add(i); } } List<int> flagList = new List<int>(); int distance = peakList.Count; flagList.Add(peakList[0]); for (int i = 1, j = 0, max = peakList.Count; i < max; i++) { if (Math.Abs(Convert.ToDecimal(peakList[j]) - Convert.ToDecimal(peakList[i])) >= distance) { flagList.Add(peakList[i]); j = i; } } return flagList.Count; } EDIT int[] A = new int[] { 7, 10, 4, 5, 7, 4, 6, 1, 4, 3, 3, 7 }; The correct answer is 3, but my application says 2 This I do not get, since there are 4 peaks (indices 1,4,6,8) and from that, you should be able to place a flag at 2 of the peaks (1 and 6) Am I missing something here? Obviously my assumption is that the beginning or end of an Array can be a peak, is this not the case? If this needs to go in Stack Exchange Programmers, I will move it, but thought dialog here would be helpful. EDIT

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  • round off and displaying the values

    - by S.PRATHIBA
    Hi all, I have the following code: import java.io.; import java.sql.; import java.math.; import java.lang.; public class Testd1{ public static void main(String[] args) { System.out.println("Sum of the specific column!"); Connection con = null; int m=1; double sum,sum1,sum2; int e[]; e=new int[100]; int p; int decimalPlaces = 5; for( int i=0;i< e.length;i++) { e[i]=0; } double b2,c2,d2,u2,v2; int i,j,k,x,y; double mat[][]=new double[10][10]; try { Class.forName("com.mysql.jdbc.Driver"); con = DriverManager.getConnection ("jdbc:mysql://localhost:3306/prathi","root","mysql"); try{ Statement st = con.createStatement(); ResultSet res = st.executeQuery("SELECT Service_ID,SUM(consumer_feedback) FROM consumer1 group by Service_ID"); while (res.next()){ int data=res.getInt(1); System.out.println(data); System.out.println("\n\n"); int c1 = res.getInt(2); e[m]=res.getInt(2); if(e[m]<0) e[m]=0; m++; System.out.print(c1); System.out.println("\t\t"); } sum=e[1]+e[2]+e[3]+e[4]+e[5]; System.out.println("\n \n The sum is" +sum); for( p=21; p<=25; p++) { if(e[p] != 0) e[p]=e[p]/(int)sum; //I have type casted sum to get output BigDecimal bd1 = new BigDecimal(e[p]); bd1 = bd1.setScale(decimalPlaces, BigDecimal.ROUND_HALF_UP); // setScale is immutable e[p] = bd1.intValue(); System.out.println("\n\n The normalized value is" +e[p]); mat[4][p-21]=e[p]; } } catch (SQLException s){ System.out.println("SQL statement is not executed!"); } } catch (Exception e1){ e1.printStackTrace(); } } } I have a table named consumer1.After calculating the sum i am getting the values as follows mysql select Service_ID,sum(consumer_feedback) from consumer1 group by Service_ ID; Service_ID sum(consumer_feedback) 31 17 32 0 33 60 34 38 35 | 38 In my program I am getting the sum for each Service_ID correctly.But,after normalization ie while I am calculating 17/153=0.111 I am getting the normalized value is 0.I want the normalized values to be displayed correctly after rounding off.My output is as follows C:javac Testd1.java C:java Testd1 Sum of the specific column! 31 17 32 0 33 60 34 38 35 38 The sum is153.0 The normalized value is0 The normalized value is0 The normalized value is0 The normalized value is0 The normalized value is0 But,after normalization i want to get 17/153=0.111 I am getting the normalized value is 0.I want these values to be rounded off.

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  • In XSLT is it possible to use the value of an xpath expression in a call to a template using an par

    - by Cell
    I am performing an xsl transform and in it I call a template with a param using the following code <xsl:call-template name="GenerateColumns"> <xsl:with-param name="curRow" select="$curRow"/> <xsl:with-param name="curCol" select="$curCol + 1"/> </xsl:call-template> This calls a template function which outputs part of a table element in HTML. The curRow and curCol are used to determine which row and column we are in the table. gbl_maxCols is set to the number of columns in an html table <xsl:template name="GenerateColumns"> <xsl:when test="$curCol &lt;= $gbl_maxCols"> <td> <xsl:attribute="colspan"> <xsl:value-of select="/page/column/@skipColumns"/> </xsl:attribute> </xsl:when> </xsl:template> The result of this function is a set of td elements, however some of these elements (those with a skipColumn attribute greater than 1 span more than 1 column, I need to skip this many columns with the next call to generateColumns. this works just like I would expect in the case where I simply increment the curCol param but I have a case where I need to use the value from the xml attribute skipColumns in the math to calculate the value for curCol. In the above case I iterate through all the columns and this works for the majority of my use cases. However in same cases I need to skip over some of the columns and need to pass in that value from the xml attribute to calculate how many columns I need to skip. My naive first attempt was something like this <xsl:call-template name="GenerateColumns"> <xsl:with-param name="curRow" select="$curRow"/> <xsl:with-param name="curCol" select="$curCol + /page/column/@skipColumns"/> </xsl:call-template> But unforutnately this does not seem to work. Is there any way to use an attribute from an xml page in the calculation for the value of a param in xsl. My xml page is something like this (edited heavily since the xml file is rather large) <page> <column name="blank" skipColumns="1"/> <column name="blank" skipColumns="1"/> <column name="test" skipColumns="3"/> <column name="blank" skipColumns="1"/> <column name="test2" skipColumns="6"/> </page> after all of this I would like to have a set of td elements like the following <td></td><td></td><td colSpan="3"></td><td></td><td colSpan="6"></td> if I just iterate through the columns I instead end up with something like this which gives me more td elements than I should have <td></td><td></td><td colSpan="3"></td><td></td><td colSpan="6"></td><td></td><td></td><td></td><td></td><td></td><td></td><td></td> Edited to provide more information

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