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  • Passing Data of WebView to Another Activity

    - by meygraph
    I've designed a training program and Html texts and image put into training. I want to address my html file by an activity to sent another activity. This is MainActivity /* * ListView item click listener. So we'll have the do stuff on click of * our ListItem */ listViewArticles.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View view, int position, long id) { switch (position) { case 0: Intent newActivity0 = new Intent(TrickPage.this,a_Dotted_Lines.class); startActivity(newActivity0); break; case 1: Intent newActivity1 = new Intent(TrickPage.this,TutorialsPage.class); startActivity(newActivity1); break; case 2: Intent newActivity2 = new Intent(TrickPage.this,TutorialsPage.class); startActivity(newActivity2); break; case 3: Intent newActivity3 = new Intent(TrickPage.this,TutorialsPage.class); startActivity(newActivity3); break; default: // Nothing do! } and this SecondActivity (show WebView) public class a_Dotted_Lines extends Activity { private WebView webView; @SuppressLint("SetJavaScriptEnabled") @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.a_dotted_lines); // Button HOME ImageButton ImageButton_home = (ImageButton) findViewById(R.id.ImageButton_home); ImageButton_home.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Intent intent = new Intent(); intent.setClass(a_Dotted_Lines.this, Main.class); startActivity(intent); overridePendingTransition(R.anim.fadein, R.anim.fadeout); } }); //Button Previous ImageButton ImageButton_previus = (ImageButton) findViewById(R.id.ImageButton_previus); ImageButton_previus.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { //Closing SecondScreen Activity finish(); } }); webView = (WebView) findViewById(R.id.webview_compontent); webView.getSettings().setJavaScriptEnabled(true); webView.loadUrl("file:///android_asset/html/article.htm"); } } I want Send "file:///android_asset/html/article.htm" or other addres from MainActivity Is it possible? Sorry My English is not good

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  • Java inheritance and super() isn't working as expected

    - by dwwilson66
    For a homework assignment, I'm working with the following. It's an assigned class structure, I know it's not the best design by a long shot. Class | Extends | Variables -------------------------------------------------------- Person | None | firstName, lastName, streetAddress, zipCode, phone CollegeEmployee | Person | ssn, salary,deptName Faculty | CollegeEmployee | tenure(boolean) Student | person | GPA,major So in the Faculty class... public class Faculty extends CollegeEmployee { protected String booleanFlag; protected boolean tenured; public Faculty(String firstName, String lastName, String streetAddress, String zipCode, String phoneNumber,String ssn, String department,double salary) { super(firstName,lastName,streetAddress,zipCode,phoneNumber, ssn,department,salary); String booleanFlag = JOptionPane.showInputDialog (null, "Tenured (Y/N)?"); if(booleanFlag.equals("Y")) tenured = true; else tenured = false; } } It was my understanding that super() in Faculty would allow access to the variables in CollegeEmployee as well as Person. With the code above, it compiles fine when I ONLY include the Person variables. As soon as I try to use ssn, department, or salary I get the following compile errors. Faculty.java:15: error: constructor CollegeEmployee in class CollegeEmployee can not be applied to the given types: super(firstName,lastName,streetAddress,zipCode,phoneNumber,ssn,department,salary); ^ Required: String,String,String,String,String Found: String,String,String,String,String,String,String,String reason: actual and formal argument lists differ in length I'm completely confused by this error...which is the actual and formal? Person has five arguments, CollegeEmployee has 3, so my guess is that something's funky with how the parameters are being passed...but I'm not quite sure where to begin fixing it. What am I missing?

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  • Highlighting Manu Item : urlQuery

    - by phpExe
    I want to highlight menu item with url query. But in my function, all items will be "currentt". I think there is a logic bug in my function: function channel() { if (is_numeric($_GET['kanalID'])) { $kanalID = $_GET['kanalID']; } if ($_GET['kanalID'] == "") { $kanalID = 1;} $tv = array(1 => 'tv1', 3 => 'tv2', 7 => 'tv3', 8 => 'tv4', 25 => 'tv5', 26 => 'tv6', 39 => 'tv7', 41 => 'tv8'); $channel = '<ul class="channeList">'; foreach ($tv as $id => $kanal) { if($kanalID = $id){$class= "currentt";} $channel .= '<li> <a href="http://mysite.com/menu.php?kanalID='.$id.'" class="'.$class.'">'.$kanal.'</a> </li>'; } $channel .= '</ul>'; $channel .= '<div class="ply"><iframe src="http://mysite.com/index.php?id='.$kanalID.'&w=500&h=320" frameborder="0" width="500" height="320" ></iframe></div>'; return $channel; } echo channel(); How can I fix this? Thanks alot

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  • what is this 'content_type' mean..

    - by zjm1126
    content_type = ContentType.objects.get_for_model(Map) maps = maps.extra(select=SortedDict([ ('member_count', MEMBER_COUNT_SQL), ('topic_count', TOPIC_COUNT_SQL), ]), select_params=(content_type.id,)) and the ContentType is: class ContentType(models.Model): name = models.CharField(max_length=100) app_label = models.CharField(max_length=100) model = models.CharField(_('python model class name'), max_length=100) objects = ContentTypeManager() class Meta: verbose_name = _('content type') verbose_name_plural = _('content types') db_table = 'django_content_type' ordering = ('name',) unique_together = (('app_label', 'model'),) def __unicode__(self): return self.name def model_class(self): "Returns the Python model class for this type of content." from django.db import models return models.get_model(self.app_label, self.model) def get_object_for_this_type(self, **kwargs): """ Returns an object of this type for the keyword arguments given. Basically, this is a proxy around this object_type's get_object() model method. The ObjectNotExist exception, if thrown, will not be caught, so code that calls this method should catch it. """ return self.model_class()._default_manager.using(self._state.db).get(**kwargs) def natural_key(self): return (self.app_label, self.model) i want to know: what is the 'content_type' used for ??

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  • Is this a bug or something I am doing wrong?

    - by Brian Gideon
    I cannot imagine how this is anything other than a bug, but since I do not currently have a login for the MS Connect website I will ask here first. I have Visual Studio 2008 SP 1 with all post SP1 hotfixes I could find relating to the crash installed. Can you reproduce the following crash? 1) Create a new "WPF Application" project using VB as the language (though I suspect it will happen in C# as well). 2) Enter the following code in the Window1.xaml.vb file. Friend MustInherit Class A End Class Friend MustInherit Class A(Of T) Inherits A End Class 3) Add a namespace declaration the Window1.xaml file so that it looks like the following. <Window x:Class="Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:local="clr-namespace:WpfApplication1" Title="Window1" Height="300" Width="300"> <Grid> </Grid> </Window> 4) Now attempt to edit the xaml file by opening a new xml tag via the < character. 5) CRASH! Edit: Microsoft has confirmed this bug. The issue still exists in VS2010 beta 2, but will be fixed in the next release.

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  • DataContractSerializer and XSLT

    - by Russ Clark
    I've got a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers">, but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

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  • Strange inheritance behaviour in Objective-C

    - by Smikey
    Hi all, I've created a class called SelectableObject like so: #define kNumberKey @"Object" #define kNameKey @"Name" #define kThumbStringKey @"Thumb" #define kMainStringKey @"Main" #import <Foundation/Foundation.h> @interface SelectableObject : NSObject <NSCoding> { int number; NSString *name; NSString *thumbString; NSString *mainString; } @property (nonatomic, assign) int number; @property (nonatomic, retain) NSString *name; @property (nonatomic, retain) NSString *thumbString; @property (nonatomic, retain) NSString *mainString; @end So far so good. And the implementation section conforms to the NSCoding protocol as expected. HOWEVER, when I add a new class which inherits from this class, i.e. #import <Foundation/Foundation.h> #import "SelectableObject.h" @interface Pet : SelectableObject <NSCoding> { } @end I suddenly get the following compiler error in the Selectable object class! SelectableObject.h:16: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'interface' This makes no sense to me. Why is the interface declaration for the SelectableObject class suddenly broken? I also import it in a couple of other classes I've written... Any help would be very much appreciated. Thanks! Michael

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  • [iPhone]Objective C, objects which do not conform to NSCoding. How to write them to a file.

    - by Noah
    Hi, I am using an Objective c class, a subclass of NSObject. This class cannot be modified. I have an instance of this class that I wish to write to a file which can be retrieved and later reinstate. The object does not conform to NSCoding. To sum up, I need to save an instance of a class to a file which can be retrieved later, without using any of the NSCoding methods such as NSKeyedArchiving encodeWithCoder ... Using them returns this... NSInvalidArgumentException ...encodeWithCoder:] unrecognised selector sent to instance... Is there any other way I can store this object for later use Thank you

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  • PHP can be exclusively accessed by SWF

    - by brett
    I'm not sure how to describe this, but basically I have a PHP class file: class HelloHello { public function getSomeData($input_parameter){ // code to retrieve data from the database } public function deleteSomeData($input_parameter){ // code to delete data from the database } } This class is on the server and is part of the backend that connects with a database, and it's meant to be accessed by the frontend SWF only (not to be directly accessed). I've setup Flex to read this class and access it. But how do I make sure that someone doesn't develop a script that can call this php file directly and access its methods? For example using a script to add data in a fast automated way, or use the delete method directly, ouch. Is this a legitimate concern, or this can't be done?

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  • Trouble with setting entry point for GWT service

    - by Xorty
    Hello. I've followed serveral tutorials and read official docs at code.google.com, but still didn't manage to resolve this thing. I am creating simple service that'll check if user can be logged. CLIENT SIDE: public interface LoginService extends RemoteService { /** * Checks, if user has valid login. * @param user User's login. * @return True if such a login is in the database. */ boolean isValidUser(User user); } And here is Async interface: public interface LoginServiceAsync { /** * Checks, if user has valid login. * @param user User's login. * @param callback the callback to return True if such a login is in the database. */ void isValidUser(User user, AsyncCallback<Boolean> callback); } SERVER SIDE: public class LoginServiceImpl extends RemoteServiceServlet implements LoginService { /** * serial version UID */ private static final long serialVersionUID = 1044980345057997696L; /**{@inheritDoc} */ @Override public boolean isValidUser(User user) { boolean success = true; //TODO change } } Now I have entry point class MailClient.java. I append here widget like: CustomWidgets.getLoginWidget(this); // access rootPanel and append widget Now I need to make actual call to my service, and here is problem: LoginServiceAsync loginService = (LoginServiceAsync) GWT.create(LoginService.class); User user = new User(boxName.getText(), boxPassword.getText()); AsyncCallback<Boolean> callback = new AsyncCallback<Boolean>() { @Override public void onFailure(Throwable caught) { Window.alert(caught.getMessage()); //TODO change } @Override public void onSuccess(Boolean result) { Window.alert("success"); //TODO change } }; ((ServiceDefTarget) loginService).setServiceEntryPoint(GWT.getModuleBaseURL()+"login"); // dunno what should be here So to recap, I don't know how to set service's entry point. Here's my MailClient.gwt.xml file: <module> <inherits name="com.google.gwt.user.User"/> <inherits name="com.google.gwt.user.theme.standard.Standard"/> <entry-point class="com.xorty.mailclient.client.MailClient"/> <servlet path="/login" class="com.xorty.mailclient.server.servlets.LoginServiceImpl" /> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> <inherits name="com.xorty.mailclient.MailClient"/> </module> My web.xml file: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <!-- Default page to serve --> <welcome-file-list> <welcome-file>MailClient.html</welcome-file> </welcome-file-list> <servlet> <servlet-name>LoginService</servlet-name> <servlet-class>com.xorty.mailclient.server.servlets.LoginServiceImpl</servlet-class> </servlet> <servlet-mapping> <servlet-name>LoginService</servlet-name> <url-pattern>/com.xorty.mailclient.MailClient/login</url-pattern> </servlet-mapping> </web-app> And here is screenshot of project structure:

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  • Python and the self parameter

    - by Svend
    I'm having some issues with the self parameter, and some seemingly inconsistent behavior in Python is annoying me, so I figure I better ask some people in the know. I have a class, Foo. This class will have a bunch of methods, m1, through mN. For some of these, I will use a standard definition, like in the case of m1 below. But for others, it's more convinient to just assign the method name directly, like I've done with m2 and m3. import os def myfun(x, y): return x + y class Foo(): def m1(self, y, z): return y + z + 42 m2 = os.access m3 = myfun f = Foo() print f.m1(1, 2) print f.m2("/", os.R_OK) print f.m3(3, 4) Now, I know that os.access does not take a self parameter (seemingly). And it still has no issues with this type of assignment. However, I cannot do the same for my own modules (imagine myfun defined off in mymodule.myfun). Running the above code yields the following output: 3 True Traceback (most recent call last): File "foo.py", line 16, in <module> print f.m3(3, 4) TypeError: myfun() takes exactly 2 arguments (3 given) The problem is that, due to the framework I work in, I cannot avoid having a class Foo at least. But I'd like to avoid having my mymodule stuff in a dummy class. In order to do this, I need to do something ala def m3(self,a1, a2): return mymodule.myfun(a1,a2) Which is hugely redundant when you have like 20 of them. So, the question is, either how do I do this in a totally different and obviously much smarter way, or how can I make my own modules behave like the built-in ones, so it does not complain about receiving 1 argument too many.

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  • Parsing a dynamic value with Lift-JSON

    - by Surya Suravarapu
    Let me explain this question with an example. If I have a JSON like the following: {"person1":{"name": "Name One", "address": {"street": "Some Street","city": "Some City"}}, "person2":{"name": "Name Two", "address": {"street": "Some Other Street","city": "Some Other City"}}} [There is no restriction on the number of persons, the input JSON can have many more persons] I could extract this JSON to Persons object by doing var persons = parse(res).extract[T] Here are the related case classes: case class Address(street: String, city: String) case class Person(name: String, address: Address, children: List[Child]) case class Persons(person1: Person, person2: Person) Question: The above scenario works perfectly fine. However the need is that the keys are dynamic in the key/value pairs. So in the example JSON provided, person1 and person2 could be anything, I need to read them dynamically. What's the best possible structure for Persons class to account for that dynamic nature.

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  • selecting the first of multiple classes

    - by gleddy
    Not sure if you can do this, but I want to select the first of two classes of an element with jQuery and return it's first class only. <div class="module blue"> I want to return 'module'. tried this: var state = $('body').attr('class').first(); but none of that seems to work, thanks for any advice.

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  • How to create a true singleton in java?

    - by rjoshi
    I am facing a problem with my singleton when used across multiple class loaders. E.g Singleton accessed by multiple EJBs. Is there any way to create a singleton which has only one instance across all class loader? I am looking for pure java solution either using custom class loader or some other way.

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  • WPF custom DependencyProperty notify changes

    - by morsanu
    Hey guys I have a class called MyComponent and it has a DependencyProperty caled BackgroundProperty. public class MyComponent { public MyBackground Background { get { return (MyBackground)GetValue(BackgroundProperty); } set { SetValue(BackgroundProperty, value); } } public static readonly DependencyProperty BackgroundProperty = DependencyProperty.Register("Background", typeof(MyBackground), typeof(MyComponent), new FrameworkPropertyMetadata(default(MyBackground), new PropertyChangedCallback(OnPropertyChanged))); } MyBackground is a class that derives from DependencyObject and it has some DependencyProperties. public class MyBackground : DependencyObject { public Color BaseColor { set { SetValue(BaseColorProperty, value); } get { return (Color)GetValue(BaseColorProperty); } } public static readonly DependencyProperty BaseColorProperty = DependencyProperty.Register("BaseColor", typeof(Color), typeof(MyBackground ), new UIPropertyMetadata(Colors.White)); [...] } Now, what I want is when a property from MyBackground is changed, MyComponent to be notified that MyBackground has changed and the PropertyChangedCallback named OnPropertyChanged to be called.

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  • Why download popup window in browser not showing up when using JAX-RS v.s. standard servlet?

    - by masato-san
    When I try using standard servlet approach, in my browser the popup window shows up asking me whether to open .xls file or save it. I tried the exactly same code via JAX-RS and the browser popup won't show up somehow. Has anyone encounter this mystery? Standard servlet that works: package local.test.servlet; import java.io.IOException; import java.net.URL; import java.net.URLDecoder; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import local.test.jaxrs.ExcellaTestResource; import org.apache.poi.ss.usermodel.Workbook; import org.bbreak.excella.core.BookData; import org.bbreak.excella.core.exception.ExportException; import org.bbreak.excella.reports.exporter.ExcelExporter; import org.bbreak.excella.reports.exporter.ReportBookExporter; import org.bbreak.excella.reports.model.ConvertConfiguration; import org.bbreak.excella.reports.model.ReportBook; import org.bbreak.excella.reports.model.ReportSheet; import org.bbreak.excella.reports.processor.ReportProcessor; @WebServlet(name="ExcelServlet", urlPatterns={"/ExcelServlet"}) public class ExcelServlet extends HttpServlet { @Override protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { try { //C:\Users\m-takayashiki\.netbeans\6.9\config\GF3\domain1 // ================== ?????? ======================= URL templateFileUrl = ExcellaTestResource.class.getResource("?????????.xls"); // /C:/Users/m-takayashiki/Documents/NetBeansProjects/KogaAlpha/build/web/WEB-INF/classes/local/test/jaxrs/?????????.xls System.out.println(templateFileUrl.getPath()); String templateFilePath = URLDecoder.decode(templateFileUrl.getPath(), "UTF-8"); String outputFileDir = "MasatoExcelHorizontalOutput"; ReportProcessor reportProcessor = new ReportProcessor(); ReportBook outputBook = new ReportBook(templateFilePath, outputFileDir, ExcelExporter.FORMAT_TYPE); ReportSheet outputSheet = new ReportSheet("??????"); outputBook.addReportSheet(outputSheet); // ======================================================== // --------------- ?????? ------------------------- reportProcessor.addReportBookExporter(new OutputStreamExporter(response)); System.out.println("wtf???"); reportProcessor.process(outputBook); System.out.println("done!!"); } catch(Exception e) { System.out.println(e); } } //end doGet() @Override protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { } }//end class class OutputStreamExporter extends ReportBookExporter { private HttpServletResponse response; public OutputStreamExporter(HttpServletResponse response) { this.response = response; } @Override public String getExtention() { return null; } @Override public String getFormatType() { return ExcelExporter.FORMAT_TYPE; } @Override public void output(Workbook book, BookData bookdata, ConvertConfiguration configuration) throws ExportException { System.out.println(book.getFirstVisibleTab()); System.out.println(book.getSheetName(0)); //TODO write to stream try { response.setContentType("application/vnd.ms-excel"); response.setHeader("Content-Disposition", "attachment; filename=masatoExample.xls"); book.write(response.getOutputStream()); response.getOutputStream().close(); System.out.println("booya!!"); } catch(Exception e) { System.out.println(e); } } }//end class JAX-RS way that won't display popup: package local.test.jaxrs; import java.net.URL; import java.net.URLDecoder; import javax.servlet.ServletOutputStream; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import javax.ws.rs.core.Context; import javax.ws.rs.core.UriInfo; import javax.ws.rs.Path; import javax.ws.rs.GET; import javax.ws.rs.Produces; import org.apache.poi.ss.usermodel.Workbook; import org.bbreak.excella.core.BookData; import org.bbreak.excella.core.exception.ExportException; import org.bbreak.excella.reports.exporter.ExcelExporter; import org.bbreak.excella.reports.exporter.ReportBookExporter; import org.bbreak.excella.reports.model.ConvertConfiguration; import org.bbreak.excella.reports.model.ReportBook; import org.bbreak.excella.reports.model.ReportSheet; import org.bbreak.excella.reports.processor.ReportProcessor; @Path("excellaTest") public class ExcellaTestResource { @Context private UriInfo context; @Context private HttpServletResponse response; @Context private HttpServletRequest request; public ExcellaTestResource() { } @Path("horizontalProcess") @GET //@Produces("application/vnd.ms-excel") @Produces("application/vnd.ms-excel") public void getProcessHorizontally() { try { //C:\Users\m-takayashiki\.netbeans\6.9\config\GF3\domain1 // ================== ?????? ======================= URL templateFileUrl = this.getClass().getResource("?????????.xls"); // /C:/Users/m-takayashiki/Documents/NetBeansProjects/KogaAlpha/build/web/WEB-INF/classes/local/test/jaxrs/?????????.xls System.out.println(templateFileUrl.getPath()); String templateFilePath = URLDecoder.decode(templateFileUrl.getPath(), "UTF-8"); String outputFileDir = "MasatoExcelHorizontalOutput"; ReportProcessor reportProcessor = new ReportProcessor(); ReportBook outputBook = new ReportBook(templateFilePath, outputFileDir, ExcelExporter.FORMAT_TYPE); ReportSheet outputSheet = new ReportSheet("??????"); outputBook.addReportSheet(outputSheet); // ======================================================== // --------------- ?????? ------------------------- reportProcessor.addReportBookExporter(new OutputStreamExporter(response)); System.out.println("wtf???"); reportProcessor.process(outputBook); System.out.println("done!!"); } catch(Exception e) { System.out.println(e); } //return response; return; } }//end class class OutputStreamExporter extends ReportBookExporter { private HttpServletResponse response; public OutputStreamExporter(HttpServletResponse response) { this.response = response; } @Override public String getExtention() { return null; } @Override public String getFormatType() { return ExcelExporter.FORMAT_TYPE; } @Override public void output(Workbook book, BookData bookdata, ConvertConfiguration configuration) throws ExportException { //TODO write to stream try { response.setContentType("application/vnd.ms-excel"); response.setHeader("Content-Disposition", "attachment; filename=masatoExample.xls"); book.write(response.getOutputStream()); response.getOutputStream().close(); System.out.println("booya!!"); } catch(Exception e) { System.out.println(e); } } }//end class

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  • top rounded corners in my jquery

    - by Sohail
    Hello everybody, I have this jquery for my menu buttons, what I want is to get top-corner rounded for my menu, this is a whole code: <html> <style type="text/css"> #menuBarHolder { width: 860px; height:45px; background-color:#000; color:#fff; font-family:Arial; font-size:14px; margin-top:20px;} #menuBarHolder ul{ list-style-type:none; display:block;} .firstchild { border-left:1px solid #ccc;} #container { margin-top:10px;} #menuBar li{ float:left; padding:15px; height:16px; width:70px; border-right:1px solid #ccc; } #menuBar li a{color:#fff; text-decoration:none; letter-spacing:-1px; font-weight:bold;} .menuHover { background-color:#999;} .menuInfo { cursor:hand; background-color:#000; color:#fff; width:74px; font-size:11px;height:100px; padding:3px; display:none; position:absolute; margin-left:-15px; margin-top:0px; -moz-border-radius-bottomright: 5px; -moz-border-radius-bottomleft: 5px; -webkit-border-bottom-left-radius: 5px; -webkit-border-bottom-right-radius: 5px; -khtml-border-radius-bottomright: 5px; -khtml-border-radius-bottomleft: 5px; border-radius-bottomright: 5px;border-radius-bottomleft: 5px; } </style> <!--[if IE]> <style type="text/css"> #menuBar li a{width:50px;} .menuInfo { margin-left:-65px; width:80px;} </style> <![endif]--> <script src="http://jqueryjs.googlecode.com/files/jquery-1.2.6.js"></script> <script type="text/javascript"> $(document).ready(function() { $('#menuBar li').click(function() { var url = $(this).find('a').attr('href'); document.location.href = url; }); $('#menuBar li').hover(function() { $(this).find('.menuInfo').slideDown(); }, function() { $(this).find('.menuInfo').slideUp(); }); }); </script> <center> <div id="menuBarHolder"> <ul id="menuBar"> <li class="firstchild"><a href="javascript:#">Home</a><div class="menuInfo">I am some text about the home section</div></li> <li><a href="javascript:#">About Us</a><div class="menuInfo">I am some text about the services section</div></li> <li><a href="javascript:#">News</a><div class="menuInfo">I am some text about the clients section</div></li> <li><a href="javascript:#">Equipment</a><div class="menuInfo">I am some text about the portfolio section</div></li> <li><a href="javascript:#">Services</a><div class="menuInfo">I am some text about the about section</div></li> <li><a href="javascript:#">Project</a><div class="menuInfo">I am some text about the blog section</div></li> <li><a href="javascript:#">Contact Us</a><div class="menuInfo">I am some text about the follow section</div></li> </ul> </div> </div> </center> </html> Thanks for your help.

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  • PHP: OOP and methods

    - by Pirkka
    Hello I`ve been wondering how to implement methods in a class. Could someone explain me what means if one does OOP in procedural style? Here is an example: class Fld extends Model { private $file; private $properties = array(); public function init($file) { $this->file = $file; $this->parseFile(); } private function parseFile() { // parses the file foreach($this->file as $line)...... .................. $this->properties = $result; } } I mean is it a good thing to have methods like these that do operations for the class properties like that. Or should I pass the class property as method parameter... I mean this would cause error if the file property wouldnt be declared.

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  • problems with extended classes and overwrite with methods

    - by Marco
    I have a .net website written in C# and will make functionalities that other developers can use. So i will make some default implementation and a developer can overwrite some methods Example: i have a class ShoppingCart and a class Product the class product haves a method getProductPrice the shoppingcart will call the method getProductPrice for calculating the total price of cart The Shoppingcart and Product are in the same project and i will give the developers the .dll so they can't change the source code so we can update the assembly later So they need to make a other project and extend the product class and overwrite the method getProductPrice so they can implement there own logic The problem is that the shoppingcart will not call the extended method but the original If we make already a extended project for the developers and the shoppingcart will call the extended method then we have a circular reference because the extended product needs a reference to product and the shopping cart to the extended product partial classes also don't works because we only can use partials within the same assembly anyone a suggestion ? thanks in advance

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  • Jquery cant get dynamic data

    - by Napoleon Wai Lun Wong
    i am a noob to using the jQuery i have a problem about the Uncaught SyntaxError: Unexpected token i am using the 1.9.0 version of jqery i am creating a dynamic number of record, each record would create a "tr" in a table ,also i want to add some dynamic coding into the textbox part of Html coding : <-tbody<-tr id="row_1"<-input id="1" name="collections[appearance][headersubcolor][entity_id1][name]" value="0" class="Root Catalog input-text" type="text" Click inside to change a color of each Category <-tr id="row_2"<-td class="label"<-td class="value"<-input id="2" name="collections[appearance][headersubcolor][entity_id2][name]" value="0" class="Default Category input-text" type="text".... jQuery coding : $('tr[id^="row_"]'.each(function(){ var rowid = parsInt(this.id.replace("row_","")); console.lof("id:"+ rowid); var ??? = new jscolor.color(document.getElementById('???'), {}) }); $('tr[id^="row_"]'.each(function() <--- i cant getting the DATA

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  • sql statement "into outfile" not working with jdbc

    - by Celeste Berus
    I am attempting to add an "export to CSV" feature to a webapp that displays data from a MySQL database. I have a written a "queryExecuter" class to execute queries from my servlet. I have used this to successfully execute insert queries so I know the connection works etc however queries with the "into outfile" statement are simply not executing. Here is my code, the java class... import java.sql.Connection; import java.sql.DriverManager; import java.sql.Statement; import java.sql.ResultSet; public class queryExecuter { public void exportToCSV(String query) { DBase db = new DBase(); Connection conn = db.connect( mydatabaseurl ,"myusername","mypassword"); db.exportData(conn,query); } } class DBase { public DBase() { } public Connection connect(String db_connect_str, String db_userid, String db_password) { Connection conn; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); conn = DriverManager.getConnection(db_connect_str, db_userid, db_password); } catch(Exception e) { e.printStackTrace(); conn = null; } return conn; } public void exportData(Connection conn,String query) { Statement stmt; try { stmt = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE); stmt.execute(query); } catch(Exception e) { e.printStackTrace(); stmt = null; } } }; The servlet... import java.io.IOException; import java.io.PrintWriter; import java.sql.SQLException; import java.util.logging.Level; import java.util.logging.Logger; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import javax.servlet.*; import javax.servlet.http.*; import java.io.*; public class MyExportServlet extends HttpServlet { public void doPost(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { String query = "select into outfile 'theoutfile.txt' * from mytable;"; request.setAttribute("query", query); queryExecuter mydata = new queryExecuter(); mydata.exportToCSV(query); RequestDispatcher view = request.getRequestDispatcher("ConfirmationPage.jsp"); view.forward(request, response); } } Any help would be greatly appreciated. Thank you

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  • php OOP function declarations

    - by kris
    I'm a big fan of OOP in php, but i feel like defining class methods gets disorganized so fast. I have a pretty good background in OOP in C++, and i am pretty comfortable with how it is handled there, and am curious if there are ways to do it similarly in php. To be more specific, here is what i mean. I like how in C++ you can define a class header (myclass.h) and then define the actual details of the functions in the implementation file (myclass.cc). Ive found that this can easily be replicated using interfaces in php, but i havent found a good solution for the following: I like to organize my code in C++ in different files based on how they are accessed, so for example, public methods that can be called outside of the class would be in 1 place, and private methods would be organized somewhere else - this is personal preference. Ive tried to define class methods in php like: private function MyPHPClass::myFunction(){ } when the definition isnt directly inside the class block( { } ), but i havent had any success doing this. Ive been through all of the pages on php.net, but couldnt find anything like this. Im assuming that there is no support for something like this, but thought i would ask anyway. thanks

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  • Jquery - Move Div around

    - by Chris
    Hi there guys, I am using Jquery Drag and drop to move divs across a page and this works perfectly. however what i would like is on each one of the div containers is to have a close button which when clicks removes the div from where it is and places it in a pre-defined div at the bottom like a widget gallery. How would this be accomplished? - below is my html.. thanks Chris <div class='column' id='leftcolumn'></div> <div class='column' id='rightcolumn'> <div class='dragbox'> <span class='close'>Close</span> Content In here </div> </div> <div class='column' id='widgetgallery></div>

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  • setting actionscript 3 superclass variables

    - by jedierikb
    In AS3, if I have a class such: public class dude { //default value for a dude protected var _strength:Number = 1; public function dude( ):void { super( ); //todo... calculate abilities of a dude based on his strength. } } and a subclass public class superDude extends dude { public function superDude( ):void { _strength = 100; super( ); trace( "strength of superDude: " + _strength ); } } This will trace strength of superDude is 1. I expected the variable I set in the subclass (prior to calling the superclass constructor) to remain. Is there a way to assign class variables in subclass constructors which are not over-written by the superclass construtor? Or should I pass them up as constructor variables?

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