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  • PHP code displayed in browser

    - by Drake
    so, I'm working on a databases project, and i'm trying to code incrementally. the problem is, when i go to test the php in browser, it displays the php code after my use of "-". the html printing is displayed properly, which is AFTER the point where the - is. here is the php: <?php function getGraphicNovel(){ include_once("./connect.php"); $db_connection = new mysqli($SERVER, $USERNAME, $PASSWORD, $DATABASE); if (mysqli_connect_errno()) { echo("Can't connect to MySQL Server. Error code: " . mysqli_connect_error()); return null; } $stmt = $db_connection->stmt_init(); $returnValue = "invalid"; if($stmt.prepare("select series from graphic_novel_main natural join graphic_novel_misc")) { $stmt->execute(); $stmt->bind_result($series); while ($stmt->fetch()) { echo "<tr><td>" . $series . "</td></tr>"; } $stmt->close(); } $db_connection->close(); } getGraphicNovel(); ?> here is a link to the page. hopefully it works for people outside the school's network. http://plato.cs.virginia.edu/~paw5k/cainedb/viewall.html if anyone knows why this is happening, your input would be great!

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  • [Database] How to model this one-to-one relation?

    - by pbean
    I have several entities which respresent different types of users who need to be able to log in to a particular system. Additionally, they have different types of information associated with them. For example: a "general user", which has an e-mail address and "admin user", which has a workstation number (note that this a hypothetical case). Both entities also share common properties like first name, surname, address and telephone number. Finally, they naturally need to have a (unique) user name and a password to log in. In the application, the user just has to fill in his user name and password, and the functionality of the application changes slightly according to the type of the user. You can imagine that the username needs to be unique for this work. How should I model this effectively? I can't just create two tables, because then I can't force a unique constaint on the user name. I also can't put them all in just one table, because they have different types of specific information associated to them. I think I might need 3 seperate tables, one for "users" (with user name and password), one for the "general users" and another one for the "admin users", but how would the relations between these work? Or is there another solution? (By the way, the target DBMS is MySQL, so I don't think generalization is supported in the database system itself).

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • Retrieve values from multimdimensional array

    - by vincentlerry
    I have a great difficulty. I need to retrieve [title], [url] and [abstract] values ??from this multidimensional array. Also, I have to store those values in mysql database. thanks in advance!!! Array ( [bossresponse] = Array ( [responsecode] = 200 [limitedweb] = Array ( [start] = 0 [count] = 20 [totalresults] = 972000 [results] = Array ( [0] = Array ( [date] = [clickurl] = http://www.torchlake.com/ [url] = http://www.torchlake.com/ [dispurl] = www.torchlake.com [title] = Torch Lake, COLI Inc, Highspeed, Dial-up, Wireless ... [abstract] = Welcome to COLI Inc. Chain O' Lake Internet. Local Northern Michigan ISP, offering Dialup Internet access, Wireless access, Web design, and T1 services in Northern ... ) [1] = Array ( [date] = [clickurl] = http://en.wikipedia.org/wiki/Torch_Lake_(Antrim_County,_Michigan) [url] = http://en.wikipedia.org/wiki/Torch_Lake_(Antrim_County,_Michigan) [dispurl] = en.wikipedia.org/wiki/Torch_Lake_(Antrim_County,_Michigan) [title] = Torch Lake (Antrim County, Michigan) - Wikipedia, the free ... [abstract] = Torch Lake at 19 miles (31 km) long is Michigan's longest lake and at approximately 18,770 acres (76 km²) is Michigan's second largest lake. Within it are several ... ) this is the entire code that generates this array: require("OAuth.php"); $cc_key = ""; $cc_secret = ""; $url = "http://yboss.yahooapis.com/ysearch/limitedweb"; $args = array(); $args["q"] = "car"; $args["format"] = "json"; $args["count"] = 20; $consumer = new OAuthConsumer($cc_key, $cc_secret); $request = OAuthRequest::from_consumer_and_token($consumer, NULL,"GET", $url, $args); $request-sign_request(new OAuthSignatureMethod_HMAC_SHA1(), $consumer, NULL); $url = sprintf("%s?%s", $url, OAuthUtil::build_http_query($args)); $ch = curl_init(); $headers = array($request-to_header()); curl_setopt($ch, CURLOPT_HTTPHEADER, $headers); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); $rsp = curl_exec($ch); $results = json_decode($rsp, true);

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  • JoinColumn name not used in sql

    - by Vladimir
    Hi! I have a problem with mapping many-to-one relationship without exact foreign key constraint set in database. I use OpenJPA implementation with MySql database, but the problem is with generated sql scripts for insert and select statements. I have LegalEntity table which contains RootId column (among others). I also have Address table which has LegalEntityId column which is not nullable, and which should contain values referencing LegalEntity's "RootId" column, but without any database constraint (foreign key) set. Address entity is mapped: @Entity @Table(name="address") public class Address implements Serializable { ... @ManyToOne(fetch=FetchType.LAZY, optional=false) @JoinColumn(referencedColumnName="RootId", name="LegalEntityId", nullable=false, insertable=true, updatable=true, table="LegalEntity") public LegalEntity getLegalEntity() { return this.legalEntity; } } SELECT statement (when fetching LegalEntity's addresses) and INSERT statment are generated: SELECT t0.Id, .., t0.LEGALENTITY_ID FROM address t0 WHERE t0.LEGALENTITY_ID = ? ORDER BY t0.Id DESC [params=(int) 2] INSERT INTO address (..., LEGALENTITY_ID) VALUES (..., ?) [params=..., (int) 2] If I omit table attribute from mentioned statements are generated: SELECT t0.Id, ... FROM address t0 INNER JOIN legalentity t1 ON t0.LegalEntityId = t1.RootId WHERE t1.Id = ? ORDER BY t0.Id DESC [params=(int) 2] INSERT INTO address (...) VALUES (...) [params=...] So, LegalEntityId is not included in any of the statements. Is it possible to have relationship based on such referencing (to column other than primary key, without foreign key in database)? Is there something else missing? Thanks in advance.

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  • Why do I get "mysql_query(): supplied argument is not a valid"

    - by Brian Ojeda
    Why do I get a "mysql_query(): supplied argument is not a valid" for the first... $r = mysql_query($q, $connection); In the following code... $bId = trim($_POST['bId']); $title = trim($_POST['title']); $story = trim($_POST['story']); $q = "SELECT * "; $q .= "FROM " . DB_NAME . ".`blog` "; $q .= "WHERE `blog`.`id` = {$bId}"; $r = mysql_query($q, $connection); //confirm_query($r); if (mysql_num_rows($r) == 1) { $q = "UPDATE " . DB_NAME . ".`blog` SET `title` = '{$title}', `story` = '{$story}' WHERE `id` = {$bId}"; $r = mysql_query($q, $connection); if (mysql_affected_rows() == 1) { //Successful $data['success'] = true; $date['errors'] = false; $date['message'] = "You are the Greatest!"; } else { //Fail $data['success'] = false; $data['error'] = true; $date['message'] = "You can't do it fool!"; } } I also get an "mysql_num_rows(): supplied argument is not a valid MySQL result resource" error too. Side notes: I am using 1&1 Hosting (worst hosting ever), custom .htaccess file with one line text to enable PHP 5.2 (only why with 1&1 Hosting).

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  • Finding users whose birtday is today with JPA

    - by Jeduan Cornejo
    Hi, I have a table with users and are trying to get a list with the people who have birthday today so the app can send an email. The User is defined as @Entity public class User { @Size(max = 30) @NotNull private String name; [...] @Temporal(TemporalType.DATE) @DateTimeFormat(style = "S-") protected Date birthday; } and I've got a method which returns the people which were born today like so @SuppressWarnings("unchecked") public static List<User> findUsersWithBirthday() { List<User> users = entityManager().createQuery("select u from User u where u.birthday = :date") .setParameter("date", new Date(), TemporalType.DATE) .getResultList(); return users; } This is fine and all for finding people which were born today, however tha's not really that useful, so I've been struggling for a way to find all the users that were born today, independent of the year. Using MySQL there's functions I can use like select month(curdate()) as month, dayofmonth(curdate()) as day However I've been struggling to find a JPA equivalent to that. I'm using Spring 3.0.1 and Hibernate 3.3.2

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  • Best approach for Java/Maven/JPA/Hibernate build with multiple database vendor support?

    - by HDave
    I have an enterprise application that uses a single database, but the application needs to support mysql, oracle, and sql*server as installation options. To try to remain portable we are using JPA annotations with Hibernate as the implementation. We also have a test-bed instance of each database running for development. The app is building nicely in Maven, and I've played around with the hibernate3-maven-plugin and can auto-generate DDL for a given database dialect. What is the best way to approach this so that individual developers can easily test against all three databases and our Hudson based CI server can build things propertly. More specifically: 1) I thought the hbm2ddl goal in the hibernate3-maven-plugin would just generate a schema file, but apparently it connects to a live database and attempts to create the schema. Is there a way to have this just create the schema file for each database dialect without connecting to a database? 2) If the hibernate3-maven-plug insists on actually creating the database schema, is there a way to have it drop the database and recreate it before creating the schema? 3) I am thinking that each developer (and the hudson build machine) should have their own separate database on each database server. Is this typical? 4) Will developers have to run Maven three times...once for each database vendor? If so, how do I merge the results on the build machine? 5) There is a hbm2doc goal within hibernate3-maven-plugin. It seems overkill to run this three times...I gotta believe it'd be nearly identical for each database.

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  • Doing coding in Linux through a virtual machine on Windows VS partitioning

    - by ihaveitnow
    I already have experience with setting up virtual machines, running them and other minor tasks. Im a gamer, so I wont get rid of windows (for now at least...) but I do want to be a great programmer and to be involved with the Open-Source community. Id like to know if its a good idea to do my programming in linux through a virtual machine, vs giving it a partitioned section of the HDD. Id like to know about performance pros and cons and functionality. All responses are appreciated, thanks in advance. The type of programming I intend to dive into : Android Dev, Web Dev, Desktop Dev...More Android and Web right now though. So im looking at C#,C,C++,Java,PHP,HTML,MySQL...Off the top of the dome. I do web designing as well, so dreamweaver is added as an "essential". But im sure I can do dreamweaver files and upload them to the server after programming in Linux...Right? And any info on IDE's in Linux for the above mentioned are appreciated, but i would prefer going the coding route and understanding the essence of whats happening "under the covers" Thanks to all for reading, I appreciate it. Hope this isnt confusing :S

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  • php syntax confusion accessing database result

    - by Babak
    I am trying to do the following: <?php foreach($sqlResult as $row): ?> <tr> <?php foreach($formdata['columns'] as $column): ?> <td><?php echo $row->$column['name']; ?></td> <?php endforeach; ?> </tr> <?php endforeach; ?> This does not work. $row is returned by my mysql query, it has the following : row-id, row-author, row-name and these work as they echo fine. $columns is the following array: 'columns' => array ( 1 => array ( 'name' => 'id' ), 2 => array ( 'name' => 'author' ), 3 => array ( 'name' => 'date' ), 4 => array ( 'name' => 'title' ) it also works fine as $column['name'] echoes id, author, date, title my question is how would it be possible for me to access the $row-method (is it a method?) by passing it a name from the array??

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  • Advice needed: cold backup for SQL Server 2008 Express?

    - by Mikey Cee
    What are my options for achieving a cold backup server for SQL Server Express instance running a single database? I have an SQL Server 2008 Express instance in production that currently represents a single point of failure for my application. I have a second physical box sitting at the installation that is currently doing nothing. I want to somehow replicate my database in near real time (a little bit of data loss is acceptable) to the second box. The database is very small and resources are utilized very lightly. In the case that the production server dies, I would manually reconfigure my application to point to the backup server instead. Although Express doesn't support log shipping, I am thinking that I could manually script a poor man's version of it, where I use batch files to take the logs and copy them across the network and apply them to the second server at 5 minute intervals. Does anyone have any advice on whether this is technically achievable, or if there is a better way to do what I am trying to do? Note that I want to avoid having to pay for the full version of SQL Server and configure mirroring as I think it is an overkill for this application. I understand that other DB platforms may present suitable options (eg. a MySQL Cluster), but for the purposes of this discussion, let's assume we have to stick to SQL Server.

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  • If we make a number every millisecond, how much data would we have in a day?

    - by Roger Travis
    I'm a bit confused here... I'm being offered to get into a project, where would be an array of certain sensors, that would give off reading every millisecond ( yes, 1000 reading in a second ). Reading would be a 3 or 4 digit number, for example like 818 or 1529. This reading need to be stored in a database on a server and accessed remotely. I never worked with such big amounts of data, what do you think, how much in terms of MBs reading from one sensor for a day would be?... 4(digits)x1000x60x60x24 ... = 345600000 bits ... right ? about 42 MB per day... doesn't seem too bad, right? therefor a DB of, say, 1 GB, would hold 23 days of info from 1 sensor, correct? I understand that MySQL & PHP probably would not be able to handle it... what would you suggest, maybe some aps? azure? oracle? ... Thansk!

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  • Bootstrap - Typehead on multiple inputs

    - by Clem
    I have two text intputs, both have to run an autocompletion. The site is using Bootstrap, and the « typeahead » component. I have this HTML : <input type="text" class="js_typeahead" data-role="artist" /> <input type="text" class="js_typeahead" data-role="location" /> I'm using the « data-role » attribute (that is sent to the Ajax controller as a $_POST index), in order to determine what kind of data has to be retrieved from the database. The Javascript goes this way : var myTypeahead = $('input.js_typeahead').typeahead({ source: function(query, process){ var data_role; data_role = myTypeahead.attr('data-role'); return $.post('/ajax/typeahead', { query:query,data_role:data_role },function(data){ return process(data.options); }); } }); With PHP, I check what $_POST['data-role'] contains, an run the MySQL query (in this case, a query either on a list of Artists, or a list of Locations). But the problem is the second "typeahead" returns the same values than the first one (list of Artists). I assume it's because the listener is attached to the object « myTypeahead », and this way the "data-role" attribute which is used, will always be the same. I think I could fix it by using something like : data_role = $(this).attr('data-role'); But of course this doesn't work, as it's a different scope. Maybe I'm doing it all wrong, but at least maybe you people could give me a hint. Sorry if this has already been discussed, I actually searched but without success. Thanks in advance, Clem (from France, sorry for my english)

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  • How to organize and manage multiple database credentials in application?

    - by Polaris878
    Okay, so I'm designing a stand-alone web service (using RestLET as my framework). My application is divided in to 3 layers: Data Layer (just above the database, provides APIs for connecting to/querying database, and a database object) Object layer (responsible for serialization from the data layer... provides objects which the client layer can use without worrying about database) Client layer (This layer is the RestLET web service... basically just creates objects from the object layer and fulfills webservice request) Now, for each object I create in the object layer, I want to use different credentials (so I can sandbox each object...). The object layer should not know the exact credentials (IE the login/pw/DB URL etc). What would be the best way to manage this? I'm thinking that I should have a super class Database object in my data layer... and each subclass will contain the required log-in information... this way my object layer can just go Database db = new SubDatabase(); and then continue using that database. On the client level, they would just be able to go ItemCollection items = new ItemCollection(); and have no idea/control over the database that gets connected. I'm asking this because I am trying to make my platform extensible, so that others can easily create services off of my platform. If anyone has any experience with these architectural problems or how to manage this sort of thing I'd appreciate any insight or advice... Feel free to ask questions if this is confusing. Thanks! My platform is Java, the REST framework I'm using is RestLET, my database is MySQL.

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  • Weird character at start of json content type

    - by Nek
    Hi, I'm trying to return json content read from MySQL server. This is supposed to be easy but, there is a 'weird' character that keeps appearing at start of the content. I have two pages for returning content: kcb433.sytes.net/as/test.php?json=true&limit=6&input=d this test.php is from a script written by Timothy Groves, which converts an array to json output http://kcb433.sytes.net/k.php?k=4 this one is supposed to do the same I tried to validate it here jsonformatter.curiousconcept.com but just page 1 gets validated, page 2 says that it does not contain JSON data. If accessed directly both pages has no problems. Then what is the difference, why both don't get validated? Then I found this page jsonformat.com and tried the same thing. Page 1 was ok and page 2 wasn't but, surprisingly the data could be read. At a glance, {"a":"b"} may look good but there is a character in front. According to a hex editor online, this is the value of the string above (instead of 9 values, there are 10): -- 7B 22 61 22 3A 22 62 22 7D The code to echo json in page 2 is: header("Content-Type: application/json"); echo "{\"a\":\"b\"}";

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  • BasicDBObject or QueryBuilder and some newbie questions of Java and mongo

    - by Kevin Xu
    hi I'm a fresh newbie to mongodb Q1 using query=new BasicDBObject(); query.put("i", new BasicDBObject("$gt",13)); and query=new QueryBuilder().put("i").Greaterthan(13).get() is there any difference inside of the system? Q2 I've created a class class findkv extends BasicDBObject{ //is gt gte lt lte public findkv(String fieldname,String op,Object tvalue) { if (op=="") this.put(fieldname,tvalue); else this.put(fieldname, new BasicDBObject(op,tvalue)); } } shall I use it or shall I just use original function? Q3 I've used mongo shell for a few weeks, and was customed to it, and find writing in mongo shell faster and shorter, which side has more advantage, writing in mongo or in java? I shall dump them from mongo to mysql Q4 I've an if (statement==true) return else dowhat; seems can't be compiled I know I can write if (statement!=true) dowhat else return, but can I still write in first style? q5 my eclipse is Eclipse Java EE IDE for Web Developers. Version: Juno Release Build id: 20120614-1722 I'd like to install Perl which I haven't learned yet I choose Install Update http://e-p-i-c.sf.net/updates/testing but it doesn't work, any method to install perl to eclipse manually?

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  • Using HABTM relationships in cakephp plugins with unique set to false

    - by Dean
    I am working on a plugin for our CakePHP CMS that will handle blogs. When getting to the tags I needed to set the HABTM relationship to unique = false to be able add tags to a post without having to reset them all. The BlogPost model looks like this class BlogPost extends AppModel { var $name = 'BlogPost'; var $actsAs = array('Core.WhoDidIt', 'Containable'); var $hasMany = array('Blog.BlogPostComment'); var $hasAndBelongsToMany = array('Blog.BlogTag' => array('unique' => false), 'Blog.BlogCategory'); } The BlogTag model looks like this class BlogTag extends AppModel { var $name = 'BlogTag'; var $actsAs = array('Containable'); var $hasAndBelongsToMany = array('Blog.BlogPost'); } The SQL error I am getting when I have the unique = true setting in the HABTM relationship between the BlogPost and BlogTag is Query: SELECT `Blog`.`BlogTag`.`id`, `Blog`.`BlogTag`.`name`, `Blog`.`BlogTag`.`slug`, `Blog`.`BlogTag`.`created_by`, `Blog`.`BlogTag`.`modified_by`, `Blog`.`BlogTag`.`created`, `Blog`.`BlogTag`.`modified`, `BlogPostsBlogTag`.`blog_post_id`, `BlogPostsBlogTag`.`blog_tag_id` FROM `blog_tags` AS `Blog`.`BlogTag` JOIN `blog_posts_blog_tags` AS `BlogPostsBlogTag` ON (`BlogPostsBlogTag`.`blog_post_id` = 4 AND `BlogPostsBlogTag`.`blog_tag_id` = `Blog`.`BlogTag`.`id`) As you can see it is trying to set the blog_tags table to 'Blog'.'BlogTag. which isn't a valid MySQL name. When I remove the unique = true from the relationship it all works find and I can save one tag but when adding another it just erases the first one and puts the new one in its place. Does anyone have any ideas? is it a bug or am I just missing something? Cheers, Dean

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  • How to develop Online Shopping Portal Application using PHP ?

    - by Sarang
    I do not know PHP & I have to develop a Shopping Portal with following Definition : Scenario: Online Shopping Portal XYZ.com wants to create an online shopping portal for managing its registered customers and their shopping. The customers need to register themselves first before they do shopping using the shopping portal. However, everyone, whether registered or not, can view the various products along with the prices listed in the portal. The registered customers, after logging in, are allowed to place order for one or more products from the products listed in the portal. Once the order is placed, the customer gets a reference order number and the order status should be “order in process”. The customers can track their order using the given reference number. The management of XYZ.com should be able to modify the order status of a particular reference order number to “shipped” once the products are shipped to the shipping address entered by the customer at the time of placing the order. The Functionalities required are : Create the interface for the XYZ.com shopping portal using HTML/XHTML and CSS. Implement the client side validations using JavaScript. Create the tables using MySQL. Implement the functionality using the server side scripting language, PHP. Integrate all the above tasks and make the XYZ.com shopping portal functional. How do I develop this application with following proper steps of development ?

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  • What's the next steps for moving from appengine to full django?

    - by tomcritchlow
    Hey guys, I'm super new to programming and I've been using appengine to help me learn python and general coding. I'm getting better quickly and I'm loving it all the way :) Appengine was awesome for allowing me to just dive into writing my app and getting something live that works (see http://www.7bks.com/). But I'm realising that the longer I continue to learn on appengine the more I'm constraining myself and locking myself into a single system. I'd like to move to developing on full django (since django looks super cool!). What are my next steps? To give you a feel for my level of knowledge: I'm not a unix user I'm not familiar with command line controls (I still use appengine/python completely via the appengine SDK) I've never programmed in anything other than python, anywhere other than appengine I know the word SQL, but don't know what MySQL is really or how to use it. So, specifically: What are the skills I need to learn to get up and running with full django/python? If I'm going to host somewhere else I suppose I'll need to learn some sysadmin type skills (maybe even unix?). Is there anywhere that offers easy hosting (like appengine) but that supports django? I hear such great things about heroku I'm considering switching to RoR and going there I appreciate that I'm likely not quite ready to move away from appengine just yet but I'm a fiercely passionate learner (http://www.7bks.com/blog/179001) and would love it if I knew all the steps I needed to learn so I could set about learning them. At the moment, I don't even know what the steps are I need to learn! Thank you very much. Sorry this isn't a specific programming question but I've looked around and haven't found a good how-to for someone of my level of experience and I think others would appreciate a good roadmap for the things we need to learn to get up and running. Thanks, Tom PS - if anyone is in London and fancies showing me the ropes in person that would be super awesome :)

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  • PHP/Javascript limiting amount of checkboxes

    - by Carl294
    Hi everyone Im trying to limit the amount of checkboxes that can be checked, in this case only 3 can be checked. When using plain HTML this works fine. The code can be seen below. HTML example <td ><input type=checkbox name=ckb value=2 onclick='chkcontrol()';></td><td>Perl</td> Javascript Function <script type="text/javascript"> function chkcontrol(j) { var total=0; for(var i=0; i < document.form1.ckb.length; i++){ if(document.form1.ckb[i].checked){ total =total +1;} if(total > 3){ alert("Please Select only three") document.form1.ckb[j].checked = false; return false; } } } </script> The problem appears when replacing the fixed HTML values with values from a MYSQL database. All the information appears correctly, and can be posted to another page via a submit button. However, it seems like the 'value' assigned to each record from the database is not making its way too the javascript function. <td><input name="checkbox[]" type="checkbox" value="<?php echo $rows['TCA_QID'];?>" onclick="chkcontrol();"></td> I have tried changed the name in the javascript function to match the 'checkbox' name.Any advice would be greatly appreciated Thanks

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  • rails not recognizing project

    - by tipu
    I can create a new project using rails and I can use stuff like rails migration ... and i (correctly) get a error because the sqlite gem is missing. but when i try using rails migration ... with a project i checked out from github, it doesn't recognize that it is a rails project i get: Usage: rails new APP_PATH [options] Options: -d, [--database=DATABASE] # Preconfigure for selected database (options: mysql/oracle/postgresql/sqlite3/frontbase/ibm_db) # Default: sqlite3 -O, [--skip-active-record] # Skip Active Record files [--dev] # Setup the application with Gemfile pointing to your Rails checkout -J, [--skip-prototype] # Skip Prototype files -T, [--skip-test-unit] # Skip Test::Unit files -G, [--skip-git] # Skip Git ignores and keeps -b, [--builder=BUILDER] # Path to an application builder (can be a filesystem path or URL) [--edge] # Setup the application with Gemfile pointing to Rails repository -m, [--template=TEMPLATE] # Path to an application template (can be a filesystem path or URL) -r, [--ruby=PATH] # Path to the Ruby binary of your choice # Default: /usr/bin/ruby1.8 [--skip-gemfile] # Don't create a Gemfile and it goes on. any ideas? edit: it's probably an important detail that earlier my rails wasn't working at all. i had to cp /usr/bin/ruby to /usr/bin/local/ruby

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  • Multidimensional array (parent and childs)

    - by Juan
    I have a category system in a MySQL database with parents and childs. The database only stores the id of it''s immediate parent (or 0 if on root). Since the system allows multiple subcategories there are cases of multiple childs. For example [98] Storage [1] External [3] Pendrives [4] Portable hhdds [2] Internal [5] Sata hhdd [6] IDE hhdd [...] [99] Clothing The database would be id parent_id name 1 98 External 2 98 Internal 3 1 Pendrives 4 1 Portable 5 2 Sata 6 2 IDE 98 0 Storage 99 0 Clothing I also have a products table with a category id and I need to get a list of all the products in the first level of categories. For example: Product Category A 3 B 4 C 5 D 6 E 74 Should return 98: A, B, C, D 99: X, Y, Z... I'm stuck and I can't think of the logic to retrieve it in that way. I started by getting the IDs of all the categories that aren't in the first level by: while ($row = mysql_fetch_assoc($result)) { if ($row['parent_id'] != 0) { $level1[$i]['name'] = utf8_encode($row['categories_name']); $level1[$i]['id'] = $row['categories_id']; } $i++; } but I'm having a burnout and can't think of a way that would nest them. I thought some kind of while but it's infinite :P Any ideas please?

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  • Hibernate collection mapping Problem

    - by Geln Yang
    Hi, There is a table Item like, code,name 01,parent1 02,parent2 0101,child11 0102,child12 0201,child21 0202,child22 Create a java object and hbm xml to map the table.The Item.parent is a Item whose code is equal to the first two characters of its code : class Item{ String code; String name; Item parent; List<Item> children; .... setter/getter.... } <hibernate-mapping> <class name="Item" table="Item"> <id name="code" length="4" type="string"> <generator class="assigned" /> </id> <property name="name" column="name" length="50" not-null="true" /> <many-to-one name="parent" class="Item" not-found="ignore"> <formula> <![CDATA[ (select i.code,r.name from Item i where (case length(code) when 4 then i.code=SUBSTRING(code,1,2) else false end)) ]]> </formula> </many-to-one> <bag name="children"></bag> </class> </hibernate-mapping> I try to use formula to define the many-to-one relationship,but it doesn't work!Is there something wrong?Or is there other method? Thanks! ps,I use mysql database.

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  • What is the best practice for including third party jar files in a Java program?

    - by ZoFreX
    I have a program that needs several third-party libraries, and at the moment it is packaged like so: zerobot.jar (my file) libs/pircbot.jar libs/mysql-connector-java-5.1.10-bin.jar libs/c3p0-0.9.1.2.jar As far as I know the "best" way to handle third-party libs is to put them on the classpath in the manifest of my jar file, which will work cross-platform, won't slow down launch (which bundling them might) and doesn't run into legal issues (which repackaging might). The problem is for users who supply the third party libraries themselves (example use case, upgrading them to fix a bug). Two of the libraries have the version number in the file, which adds hassle. My current solution is that my program has a bootstrapping process which makes a new classloader and instantiates the program proper using it. This custom classloader adds all .jar files in lib/ to its classpath. My current way works fine, but I now have two custom classloaders in my application and a recent change to the code has caused issues that are difficult to debug, so if there is a better way I'd like to remove this complexity. It also seems like over-engineering for what I'm sure is a very common situation. So my question is, how should I be doing this?

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  • install barnyard2 ubuntu 12.04

    - by Muhammad Ardiansyah
    I trying to install barnyard2 in ubuntu 12.04 32-bit I'm configure using syntax: ./configure --with-mysql-libraries=/usr/lib/x86_64-linux-gnu and when I trying to compile daq-1.1.1 using a makefile, I encountered the following errors: make[3]: Leaving directory /root/snortinstall/barnyard2/src' make[2]: Leaving directory/root/snortinstall/barnyard2/src' Making all in etc make[2]: Entering directory /root/snortinstall/barnyard2/etc' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/etc' Making all in doc make[2]: Entering directory/root/snortinstall/barnyard2/doc' make[2]: Nothing to be done for all'. make[2]: Leaving directory /root/snortinstall/barnyard2/doc' Making all in rpm make[2]: Entering directory /root/snortinstall/barnyard2/rpm' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/rpm' Making all in schemas make[2]: Entering directory/root/snortinstall/barnyard2/schemas' make[2]: Nothing to be done for all'. make[2]: Leaving directory /root/snortinstall/barnyard2/schemas' Making all in m4 make[2]: Entering directory /root/snortinstall/barnyard2/m4' make[2]: Nothing to be done forall'. make[2]: Leaving directory /root/snortinstall/barnyard2/m4' make[2]: Entering directory /root/snortinstall/barnyard2' make[2]: Nothing to be done for all-am'. make[2]: Leaving directory/root/snortinstall/barnyard2' make[1]: Leaving directory `/root/snortinstall/barnyard2'

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