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  • Refactoring an immediate drawing function into VBO, access violation error

    - by Alex
    I have a MD2 model loader, I am trying to substitute its immediate drawing function with a Vertex Buffer Object one.... I am getting a really annoying access violation reading error and I can't figure out why, but mostly I'd like an opinion as to whether this looks correct (never used VBOs before). This is the original function (that compiles ok) which calculates the keyframe and draws at the same time: glBegin(GL_TRIANGLES); for(int i = 0; i < numTriangles; i++) { MD2Triangle* triangle = triangles + i; for(int j = 0; j < 3; j++) { MD2Vertex* v1 = frame1->vertices + triangle->vertices[j]; MD2Vertex* v2 = frame2->vertices + triangle->vertices[j]; Vec3f pos = v1->pos * (1 - frac) + v2->pos * frac; Vec3f normal = v1->normal * (1 - frac) + v2->normal * frac; if (normal[0] == 0 && normal[1] == 0 && normal[2] == 0) { normal = Vec3f(0, 0, 1); } glNormal3f(normal[0], normal[1], normal[2]); MD2TexCoord* texCoord = texCoords + triangle->texCoords[j]; glTexCoord2f(texCoord->texCoordX, texCoord->texCoordY); glVertex3f(pos[0], pos[1], pos[2]); } } glEnd(); What I'd like to do is to calculate all positions before hand, store them in a Vertex array and then draw them. This is what I am trying to replace it with (in the exact same part of the program) int vCount = 0; for(int i = 0; i < numTriangles; i++) { MD2Triangle* triangle = triangles + i; for(int j = 0; j < 3; j++) { MD2Vertex* v1 = frame1->vertices + triangle->vertices[j]; MD2Vertex* v2 = frame2->vertices + triangle->vertices[j]; Vec3f pos = v1->pos * (1 - frac) + v2->pos * frac; Vec3f normal = v1->normal * (1 - frac) + v2->normal * frac; if (normal[0] == 0 && normal[1] == 0 && normal[2] == 0) { normal = Vec3f(0, 0, 1); } indices[vCount] = normal[0]; vCount++; indices[vCount] = normal[1]; vCount++; indices[vCount] = normal[2]; vCount++; MD2TexCoord* texCoord = texCoords + triangle->texCoords[j]; indices[vCount] = texCoord->texCoordX; vCount++; indices[vCount] = texCoord->texCoordY; vCount++; indices[vCount] = pos[0]; vCount++; indices[vCount] = pos[1]; vCount++; indices[vCount] = pos[2]; vCount++; } } totalVertices = vCount; glEnableClientState(GL_NORMAL_ARRAY); glEnableClientState(GL_TEXTURE_COORD_ARRAY); glEnableClientState(GL_VERTEX_ARRAY); glNormalPointer(GL_FLOAT, 0, indices); glTexCoordPointer(2, GL_FLOAT, sizeof(float)*3, indices); glVertexPointer(3, GL_FLOAT, sizeof(float)*5, indices); glDrawElements(GL_TRIANGLES, totalVertices, GL_UNSIGNED_BYTE, indices); glDisableClientState(GL_VERTEX_ARRAY); // disable vertex arrays glEnableClientState(GL_TEXTURE_COORD_ARRAY); glDisableClientState(GL_NORMAL_ARRAY); First of all, does it look right? Second, I get access violation error "Unhandled exception at 0x01455626 in Graphics_template_1.exe: 0xC0000005: Access violation reading location 0xed5243c0" pointing at line 7 Vec3f pos = v1->pos * (1 - frac) + v2->pos * frac; where the two Vs seems to have no value in the debugger.... Till this point the function behaves in exactly the same way as the one above, I don't understand why this happens? Thanks for any help you may be able to provide!

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  • Hybrid wireless network repeating

    - by Oli
    Summary: I'd like to use two Ubuntu computers to extend/compliment an existing wireless access point. I have a network which currently looks a bit like this: What the diagram doesn't show is the interference caused by our house. It's a wifi-blocking robot sent here from the past. The two wired computers are in areas where the signal is most blocked (not by design, just a happy co-incidence). Both wired computers have fairly good network cards. They're both Ubuntu machines and I would like to turn them into additional base stations. I know I could throw more networking hardware at this (network extenders or cable in additional, pure wireless access points) but I've got two Linux machines sitting in ideal places and I feel like they should be able to help me out. I've tried ad-hoc networks but I need something that is a lot more transparent (eg you can migrate from base to base without a connection dropping); it should look like one network to clients.

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  • What sort of security method is this called (if it has a name)?

    - by loosebruce
    I have thought of a way of securing access to an application interacting with another application. Using this method Application 1 - "What is the sum of 1+1?" Application 2 - "3" Application 1 - "Access granted" Is this method used a lot, does it have a classification in the programming world? The advantages for me of using this is that I do not have to spend more effort implementing security keys/certificates. Any unauthorized machine trying to interpret it would give the correct result and identify itself as untrusted. What sort of weaknesses are there to doing this?

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  • How to setup a wifi ap hotspot with ipv6 support?

    - by keyman
    How to setup a wifi ap (access point mode) hotspot, with IPv6 support? I've set up a hotspot according to the guide to wifi ap hotspot setup and it works fine. But via the hotspot I failed to visit IPv6 websites. How can I setup a hotspot able to share Ipv6 Internet access? Thanks! Further: Actually I've tried to setup IPv6 forwarding and masquerading. First enabling IPv6 forwarding: echo 1 | sudo tee net/ipv6/conf/default/forwarding Then I tried to execute: sudo ip6tables -t nat -A POSTROUTING -s 2001:db8:0:1::/64 -o eth0 -j MASQUERADE But it gave me an error: ip6tables v1.4.12: Couldn't load target `MASQUERADE':No such file or directory I searched through the Internet but I get confused. So I'm here for help. Thanks!

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  • using remote MS Access database which connects to remote SQL server

    - by Manjot
    Hi, We have a Microsoft Access database + application (on Server A) which connects to a remote SQL server (Server B) using System DSN ODBC connection (on Server A) to the SQL database server. The users are open this Access database remotely as it is on a shared location on the server A. They still have to create a local ODBC connection on their computers to connect to Server B. Is there anyway that they can access the Access database and not have to create a local ODBC connection? thanks in advance

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  • How to access an IP address as if on a different network using SSH

    - by NT3RP
    In preparation for a lengthy business trip, I set up my router such that I can access my home computer over the internet via port forwarding over SSH. One thing I neglected to do was setup access to my router remotely. Normally, I can just access the router configuration page via 192.168.1.1. I know that it's possible to tunnel traffic through SSH, but how do I access an IP address as if I were on my home network using SSH?

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  • Controling virtualbox internet access?

    - by HandyGandy
    Host: Linux/Debian/Ubuntu/Mint ( Helena/karmic koala ) Guest: XP SP2 and SP3 Problem: Relatively new copy of XP migrated to vbox-virus free. To detect biral infection it is desired that internet access is limited. Network access to the host is desired, but access to the internet should be limited to a select few sites. The added overhead of network access should be small when the guest vbox is running, 0 when it is not.

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  • IIS 7 Web service access

    - by Aharon Manne
    I am trying to debug a simple web service. I have IIS 7 installed on my development machine (Windows 7), and have installed the web service. I can access it from my development machine, but not from any other machine in the local network.I opened the firewall to HTTP access, and I can access the default website from other machines, so it is not the firewall.What security settings should I look at to try to allow devices on the LAN to access the web service?

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  • httpd.conf ruined - can't access my vps anymore

    - by Jazerix
    Okay, so this may be incredible stupid But I was configuring my httpd.conf file yesterday. After a server restart, I can no longer access it. Port 80 is working fine, and it displays my webpages, however when I access the site via ssh, it just says the connection was refused. I cannot access webmin which is port 10000 or access it via ftp :/ Do I need to recreate the whole site or is there a way to get into it? I think I messed up the virtual hosts :)

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  • httpd.conf ruined - cant access my vps anymore

    - by Jazerix
    Okay, so this may be incredible stupied But I was configuring my httpd.conf file yesterday. After a server restart, I can no longer access it. Port 80 is working fine, and it displays my webpages, however when I access the site via ssh, it just says the connection was refused. I cannot access webmin which is port 10000 or access it via ftp :/ Do I need to recreate the whole site or is there a way to get into it?

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  • Can't change pivot table's Access data source - bug in Excel 2000 SP3?

    - by Ron West
    I have a set of Excel 2000 SP3 worksheets that have Pivot Tables that get data from an Access 2000 SP3 database created by a contractor who left our company. Unfortunately, he did all his work on his private area on the company (Novell) network and now that he has left us, the drive spec has been deleted and is invalid. We were able to get the database files restored to our network area by our IT Service Desk people, but we now have to re-link everything to point to our group area instead of the now-nonexistent private area. If I follow the advice given elsewhere on this site (open wizard, click 'Back' to get to 'Step 2 of 3', click 'Get Data...' I get a message that the old filespec is an invalid path and I need to check that the path name is invalid and that I am connected to the server on which the file resides. I then click on OK and get a Login dialog with a 'Database...' button on the right. I click this and get a 'Select Database' dialog which allows me to choose the appropriate database in its correct new location. I then click OK, which takes me back to the 'Login' screen. I can confirm that it has accepted my new location by clicking on 'Database...' as before and the NEW location is still shown. So far so good - but if I then click on OK I get two unhelpful messages - first I get one saying that Excel 'Could not use '|'; file already in use.' - although no other files are in use. Clicking on OK takes me back to the 'Login' dialog. Clicking OK again gives me the same message as before telling me that the OLD filespec is invalid (as if I hadn't changed anything) - but clicking on the 'Database...' button shows that the correct (NEW) database location is still selected. Can anyone tell me a way of using VBA to change the link information without having to spend hours fighting the PivotTable Wizard - preferably similar to this way you update an Access Tabledef:- db.TableDefs(strLinkName).Connect = strNewLink db.TableDefs(strLinkName).RefreshLink Thanks!

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  • VBA: How go I get the total width from all controls in an MS-Access form?

    - by Stefan Åstrand
    Hi, This is probably very basic stuff, but please bear in mind I am completely new to these things. I am working on a procedure for my Access datasheet forms that will: Adjust the width of each column to fit content Sum the total width of all columns and subtract it from the size of the window's width Adjust the width of one of the columns to fit the remaining space This is the code that adjusts the width of each column to fit content (which works fine): Dim Ctrl As Control Dim Path As String Dim ClmWidth As Integer 'Adjust column width to fit content For Each Ctrl In Me.Controls If TypeOf Ctrl Is TextBox Then Path = Ctrl.Name Me(Path).ColumnWidth = -2 End If Next Ctrl How should I write the code so I get the total width of all columns? Thanks a lot! Stefan Solution This is the code that makes an Access datasheet go from this: To this: Sub AdjustColumnWidth(frm As Form, clm As String) On Error GoTo HandleError Dim intWindowWidth As Integer ' Window width property Dim ctrl As Control ' Control Dim intCtrlWidth As Integer ' Control width property Dim intCtrlSum As Integer ' Control width property sum Dim intCtrlAdj As Integer ' Control width property remaining after substracted intCtrSum 'Adjust column width to standard width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name frm(Path).ColumnWidth = 1500 End If Next ctrl 'Get total column width For Each ctrl In frm.Controls If TypeOf ctrl Is TextBox Or TypeOf ctrl Is CheckBox Or TypeOf ctrl Is ComboBox Then Path = ctrl.Name intCtrlWidth = frm(Path).ColumnWidth If Path <> clm Then intCtrlSum = intCtrlSum + intCtrlWidth End If End If Next ctrl 'Adjust column to fit window intWindowWidth = frm.WindowWidth - 270 intCtrlAdj = intWindowWidth - intCtrlSum frm.Width = intWindowWidth frm(clm).ColumnWidth = intCtrlAdj Debug.Print "Totalt (Ctrl): " & intCtrlSum Debug.Print "Totalt (Window): " & intWindowWidth Debug.Print "Totalt (Remaining): " & intCtrlAdj Debug.Print "clm : " & clm HandleError: GeneralErrorHandler Err.Number, Err.Description Exit Sub End Sub Code to call procedure: Private Sub Form_Load() Call AdjustColumnWidth(Me, "txtDescription") End Sub

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  • How to handle authenticated user access to resources in document oriented system?

    - by Jeremy Raymond
    I'm developing a document oriented application and need to manage user access to the documents. I have a module that handles user authentication, and another module that handles document CRUD operations on the data store. Once a user is authenticated I need to enforce what operations the user can and cannot perform to documents based upon the user's permissions. The best option I could think of to integrate these two pieces together would be to create another module that duplicates the data API but that also takes the authenticated user as a parameter. The module would delegate the authorization check to the auth module and delegate the document operation to the data access module. Something like: -module(auth_data_access). % User is authenticated (logged into the system) % save_doc validates if user is allowed to save the given document and if so % saves it returning ok, else returns {error, permission_denied} save_doc(Doc, User) -> case auth:save_allowed(Doc, User) of ok -> data_access:save_doc(Doc); denied -> {error, permission_denied} end end. Is there a better way I can handle this?

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  • How can you connect to a password protected MS Access Database from a Spring JdbcTemplate?

    - by Tim Visher
    I need to connect to a password protected MS Access 2003 DB using the JDBC-ODBC bridge. I can't find out how to specify the password in the connect string, or even if that is the correct method of connecting. It would probably be relevant to mention that this is a Spring App which is accessing the database through a JdbcTemplate configured as a datasource bean in our application context file. Some relevant snippets: from application-context.xml <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate"> <property name="dataSource" ref="legacyDataSource" /> </bean> <bean id="jobsheetLocation" class="java.lang.String"> <constructor-arg value="${jobsheet.location}"/> </bean> <bean id="legacyDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.legacy.driverClassName}" /> <property name="url" value="${jdbc.legacy.url}"/> <property name="password" value="-------------" /> </bean> from our build properties jdbc.legacy.driverClassName=sun.jdbc.odbc.JdbcOdbcDriver jdbc.legacy.url=jdbc:odbc:Driver\={Microsoft Access Driver (*.mdb)};Dbq\=@LegacyDbPath@;DriverID\=22;READONLY\=true Any thoughts?

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  • "Too many indexes on table" error when creating relationships in Microsoft Access 2010.

    - by avianattackarmada
    I have tblUsers which has a primary key of UserID. UserID is used as a foreign key in many tables. Within a table, it is used as a foreign key for multiple fields (e.g. ObserverID, RecorderID, CheckerID). I have successfully added relationships (with in the the MS Access 'Relationship' view), where I have table aliases to do the multiple relationships per table: *tblUser.UserID - 1 to many - tblResight.ObserverID *tblUser_1.UserID - 1 to many - tblResight.CheckerID After creating about 25 relationships with enforcement of referential integrity, when I try to add an additional one, I get the following error: "The operation failed. There are too many indexes on table 'tblUsers.' Delete some of the indexes on the table and try the operation again." I ran the code I found here and it returned that I have 6 indexes on tblUsers. I know there is a limit of 32 indexes per table. Am I using the relationship GUI wrong? Does access create an index for the enforcement of referential integrity any time I create a relationship (especially indexes that wouldn't turn up when I ran the script)? I'm kind of baffled, any help would be appreciated.

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  • Data Type Not Consistent In MS Access? (Set new field as "TEXT" but system treats it as "Yes/No" field)

    - by user3522506
    I already have an SQL command that will insert any string in the field. But it doesn't accept any string, giving me "No value given for one or more required parameters". But if my string is "Yes" or "No", it will update successfully. And in MS Access, will appear as 0 or -1 even though I set the field as text even in the beginning. Could there be any configuration I have made in my MS Access 2007? con = New OleDbConnection(cs) con.Open() Dim cb As String = "Update FS_Expenses set FS_Date=#" & dtpDate2.Text & "#,SupplierID='" & txtSupplierID.Text & "', TestField=" & Label1.Text & " where ID=" & txtID2.Text & "" cmd = New OleDbCommand(cb) cmd.Connection = con cmd.ExecuteReader() MessageBox.Show("Successfully updated!", "Record", MessageBoxButtons.OK, MessageBoxIcon.Information) con.Close() TestField is already a TEXT data type, Label1.Text value is "StringTest", will give the error. However, set Label1.Text value as = "Yes", SQL will execute successfully. Therefore, field must have not been saved as TEXT.

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  • iphone - direct link to iPhone review form from inside iphone

    - by Mike
    I am trying to link directly to the review link of one of my Apps. I know that it is possible because Appirater did it in the past, but some change in iTunes turned the API down. Appirater uses this URL NSString *templateReviewURL = @"itms-apps://itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?id=APP_ID&onlyLatestVersion=true&pageNumber=0&sortOrdering=1&type=Purple+Software"; where APP_ID is the ID of an application. running this from inside the APP gives me the message Cannot Connect to iTunes Store. This Page talks about another kind of link https://userpub.itunes.apple.com/WebObjects/MZUserPublishing.woa/wa/addUserReview?id=APP_ID&type=Purple+Software and also itms-apps://ax.itunes.apple.com/WebObjects/MZStore.woa/wa/viewContentsUserReviews?type=Purple+Software&id=APP_ID The first one works, but just from the desktop mac. The second gives me the same error as the first... Cannot Connect to iTunes Store. iTunes link maker is not helping too, because it has no tools for iPad links... Do you guys know how to link to an app's review form from inside an app? In case you don't know, what kind of package should I use to dig this? a package sniffer? thanks for any help.

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  • C++ Direct 2D How To Resize ID2D1Bitmap

    - by Nkosi Dean
    I'm making myself a simple GUI library for a game I'm making and each control needs to have a Bitmap to draw to when the control needs redrawing. When it does not need to be redrawn, it will have an already made bitmap ready to display to the screen. Since controls can be resized, this Bitmap also needs to be resized so the control can be fully drawn into it properly. How can I achieve this since it does not appear to be a Resize method to resize a bitmap, unlike an ID2D1HwndRenderTarget, which can be resized?

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  • Paypal Sandbox Do Direct Payment Internal Error 10001 Timeout Processing Request

    - by user552968
    This is what I'm sending to https://api-3t.sandbox.paypal.com/nvp: VERSION = 65.0 SIGNATURE = AFcWxV21C7fd0v3bYYYRCpSSRl31AxdW2pQp.tWHTjGNcHflR-LJhJ0t USER = seller_1283487740_biz_api1.gmail.com PWD = 1283487748 AMOUNT = 50.00 CREDITCARDTYPE = Visa ACCT = 4031477440127509 EXPDATE = 12/2015 CVV2 =123 IPADDRESS = 127.0.0.1 METHOD = DoDirectPayment I can GetBalance, I can produce other errors when I intentionally send something wrong, but DoDirectPayment or DoAuthorization returns this: TIMESTAMP = 2010-12-24T03:35:10Z CORRELATIONID = 2ca329fdbe3c0 ACK = Failure L_ERRORCODE0 = 10001 L_SHORTMESSAGE0 = Internal Error L_LONGMESSAGE0 = Timeout processing request

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  • Java web-app debugging not possible due to direct undeploy on debug

    - by Hendrik
    When i try to debug my webapp it starts up the tomcat server and the application, but shuts down the debugger shortly before the app gets usable. I see the debugging toolbar for a second before it vanishes again, though the app keeps running. Tomcat-log: Listening for transport dt_socket at address: 11555 23.03.2010 01:24:35 org.apache.catalina.core.AprLifecycleListener init INFO: The APR based Apache Tomcat Native library which allows optimal performance in production environments was not found on the java.library.path: .:/Library/Java/Extensions:/System/Library/Java/Extensions:/usr/lib/java 23.03.2010 01:24:35 org.apache.coyote.http11.Http11Protocol init INFO: Initializing Coyote HTTP/1.1 on http-8084 23.03.2010 01:24:35 org.apache.catalina.startup.Catalina load INFO: Initialization processed in 847 ms 23.03.2010 01:24:35 org.apache.catalina.core.StandardService start INFO: Starting service Catalina 23.03.2010 01:24:35 org.apache.catalina.core.StandardEngine start INFO: Starting Servlet Engine: Apache Tomcat/6.0.20 log4j:WARN No appenders could be found for logger (org.springframework.web.context.ContextLoader). log4j:WARN Please initialize the log4j system properly. 23.03.2010 01:24:41 org.apache.coyote.http11.Http11Protocol start INFO: Starting Coyote HTTP/1.1 on http-8084 23.03.2010 01:24:41 org.apache.jk.common.ChannelSocket init INFO: JK: ajp13 listening on /0.0.0.0:8009 23.03.2010 01:24:41 org.apache.jk.server.JkMain start INFO: Jk running ID=0 time=0/78 config=null 23.03.2010 01:24:41 org.apache.catalina.startup.Catalina start INFO: Server startup in 5855 ms 23.03.2010 01:24:42 org.apache.catalina.startup.HostConfig checkResources INFO: Undeploying context [] 23.03.2010 01:24:45 org.apache.catalina.core.StandardContext start INFO: Container org.apache.catalina.core.ContainerBase.[Catalina].[localhost].[/] has already been started Debugging log: Attached JPDA debugger to localhost:11555 Checking data source definitions for missing JDBC drivers... Deploying JDBC driver to /Applications/NetBeans/apache-tomcat-6.0.20/lib/mysql-connector-java-5.1.6-bin.jar Stopping Tomcat process... Waiting for Tomcat... Tomcat server stopped. Starting Tomcat process... Waiting for Tomcat... Tomcat server started. Undeploying ... OK - Undeployed application at context path / In-place deployment at /path/to/project/dir/build/web deploy?config=file%3A%2Fvar%2Ffolders%2FZP%2FZPbqxGrbHFaUlXzAfgWV1%2B%2B%2B%2BTQ%2F-Tmp-%2Fcontext734173871283203218.xml&path=/ OK - Deployed application at context path / start?path=/ Start is in progress... OK - Started application at context path / debug-display-browser: Browsing: http://localhost:8084/ connect-client-debugger: BUILD SUCCESSFUL (total time: 18 seconds) System is Netbeans 6.8 on MacOS 10.6.2. Thank you very much, guys!

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  • How to direct hibernate logger statements in different log files for differnet applications using jb

    - by Milind
    Hi, I am using JBOSS 4.2.2 server to deploy multiple web applications. Each application uses Hibernate and for each application there are saperate log files and saparate appendar. Now for Hibernate logging statements of one application should go in log file of that particular application. Does anybody has idea how to configure log4j.xml file to achieve this? Thanks and regards, Milind

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  • Rails routes direct index action to show action

    - by jspooner
    So I created some rspec_scaffold for an Exercise model and added "map.resource :exercises" to my routes file and I was surprised when the "/exercises" url rendered the show action. What the heck? Why doesn't that render the index action? rake routes new_exercises GET /exercises/new(.:format) {:controller=>"exercises", :action=>"new"} edit_exercises GET /exercises/edit(.:format) {:controller=>"exercises", :action=>"edit"} exercises GET /exercises(.:format) {:controller=>"exercises", :action=>"show"} PUT /exercises(.:format) {:controller=>"exercises", :action=>"update"} DELETE /exercises(.:format) {:controller=>"exercises", :action=>"destroy"} POST /exercises(.:format) {:controller=>"exercises", :action=>"create"}

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  • INSTEAD OF triggers do not support direct recursion

    - by senzacionale
    ALTER TRIGGER [dbo].[TRG_DeleteUser] ON [dbo].[Users] INSTEAD OF DELETE AS BEGIN SET NOCOUNT ON DECLARE @AspNetUserGuid UniqueIdentifier DECLARE @UserId NVARCHAR(36) BEGIN SET @AspNetUserGuid = (SELECT AspNetUserGuid FROM deleted) SET @UserId = (SELECT UserId FROM dbo.Users WHERE AspNetUserGuid = @AspNetUserGuid) IF @AspNetUserGuid IS NOT NULL AND @UserId IS NOT NULL BEGIN EXECUTE [dbo].UsersDelete @AspNetUserGuid, @UserId END END SET NOCOUNT OFF END problem is here: EXECUTE [dbo].UsersDelete @AspNetUserGuid, @UserId i need to call triger before row is actually deleted-

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  • ColdFusion structs Direct Assignment vs object literal notation.

    - by Tom Hubbard
    The newer versions of ColdFusion (I believe CF 8 and 9) allow you to create structs with object literal notation similar to JSON. My question is, are there specific benefits (execution efficiency maybe) to using object literal notation over individual assignments for data that is essentially static? For example: With individual assignments you would do something like this: var user = {}; user.Fname = "MyFirstnam"; user.Lname = "MyLastName"; user.titles = []; ArrayAppend(user.titles,'Mr'); ArrayAppend(user.titles,'Dr.'); Whereas with object literals you would do something like. var user = {Fname = "MyFirstnam", Lname = "MyLastName", titles = ['Mr','Dr']}; Now this limited example is admittedly simple, but if titles was an array of structures (Say an array of addresses), the literal notation becomes awkward to work with.

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