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  • django admin how to limit selectbox values

    - by SledgehammerPL
    model: class Store(models.Model): name = models.CharField(max_length = 20) class Admin: pass def __unicode__(self): return self.name class Stock(Store): products = models.ManyToManyField(Product) class Admin: pass def __unicode__(self): return self.name class Product(models.Model): name = models.CharField(max_length = 128, unique = True) parent = models.ForeignKey('self', null = True, blank = True, related_name='children') (...) def __unicode__(self): return self.name mptt.register(Product, order_insertion_by = ['name']) admin.py: from bar.drinkstore.models import Store, Stock from django.contrib import admin admin.site.register(Store) admin.site.register(Stock) Now when I look at admin site I can select any product from the list. But I'd like to have a limited choice - only leaves. In mptt class there's function: is_leaf_node() -- returns True if the model instance is a leaf node (it has no children), False otherwise. But I have no idea how to connect it I'm trying to make a subclass: in admin.py: from bar.drinkstore.models import Store, Stock from django.contrib import admin admin.site.register(Store) class StockAdmin(admin.ModelAdmin): def queryset(self, request): qs = super(StockAdmin, self).queryset(request).filter(ihavenoideawhatfilter) admin.site.register(Stock, StockAdmin) but I'm not sure if it's right way, and what filter set.

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  • User authentication in Django. Problems with is_authenticated

    - by tim
    I have one problem with users menu. So, I want, that authenticated user can see his/her profile page and logout (links) in menu. It works (when I logging in) on index page: index, page1, profile, logout ,but, if I go to the, for example, page1 I can see in menu: index, page1, login, not profile and logout. How to fix it? in urls: url(r'^accounts/login/$', 'django.contrib.auth.views.login' ), url(r'^accounts/logout/$', 'django.contrib.auth.views.logout_then_login' ), url(r'^accounts/profile/$', 'my_app.views.profile' ), in views: def profile(request): if not request.user.is_authenticated(): return HttpResponseRedirect("/accounts/login/") else: user = request.user.is_authenticated() return render_to_response('profile.html',locals()) Part of index.html: {% if user.is_authenticated or request.user.is_authenticated %} <li><a href="/accounts/profile/">Profile</a></li> <li><a href="/accounts/logout/">logout</a></li> {% else %} <li><a href="/accounts/login/">login</a></li> {% endif %} login.html: {% extends "index.html" %} {% load url from future %} {% block application %} {% if form.errors %} <p>Try one more time</p> {% endif %} <form method="post" action="{% url 'django.contrib.auth.views.login' %}"> {% csrf_token %} <table> <tr> <td>{{ form.username.label_tag }}</td> <td>{{ form.username }}</td> </tr> <tr> <td>{{ form.password.label_tag }}</td> <td>{{ form.password }}</td> </tr> </table> <input type="submit" value="Login" /> <input type="hidden" name="next" value="{{ next }}" /> </form> {% endblock %} profile.html: {% extends "index.html" %} {% block application %} {% if request.user.is_authenticated %} <p>Welcome, {{ request.user.username }}. Thanks for logging in.</p> {% else %} <p>Welcome, new user. Please log in.</p> {% endif %} {% endblock %}

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  • I'm an experienced PHP programmer, how would it be for me to learn and use Django and Ruby on Rails?

    - by João Paulo Apolinário Passos
    I'm an experienced PHP programmer, I still have lots to learn but I consider myself experienced. I sometimes use pure PHP and sometimes some framework like CodeIgniter. I always wanted to learn new technologies like Python and Ruby, and their best frameworks for web are Django and Ruby on Rails, but I want to ask to persons like me who migrated from PHP to some of this technologies if is it worth it; Thank you

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  • python manage.py runserver fails

    - by Randy Simon
    I am trying to learn django by following along with this tutorial. I am using django version 1.1.1 I run django-admin.py startproject mysite and it creates the files it should. Then I try to start the server by running python manage.py runserver but here is where I get the following error. Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 362, in execute_manager utility.execute() File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 213, in execute translation.activate('en-us') File "/Library/Python/2.6/site-packages/django/utils/translation/__init__.py", line 73, in activate return real_activate(language) File "/Library/Python/2.6/site-packages/django/utils/translation/__init__.py", line 43, in delayed_loader return g['real_%s' % caller](*args, **kwargs) File "/Library/Python/2.6/site-packages/django/utils/translation/trans_real.py", line 205, in activate _active[currentThread()] = translation(language) File "/Library/Python/2.6/site-packages/django/utils/translation/trans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/Library/Python/2.6/site-packages/django/utils/translation/trans_real.py", line 172, in _fetch for localepath in settings.LOCALE_PATHS: File "/Library/Python/2.6/site-packages/django/utils/functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'LOCALE_PATHS' Now, I can add a LOCALE_PATH atribute and set to an empty tuple to my settings.py file but then it just complains about another setting and so on. What am I missing here?

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  • Maven antrun with sequential ant-contrib fails to run

    - by codevour
    We have a special routine to explode files in a subfolder into extensions, which will be copied and jared into single extension files. For this special approach I wanted to use the maven-antrun-plugin, for the sequential iteration and jar packaging through the dirset, we need the library ant-contrib. The upcoming plugin configuration fails with an error. What did I misconfigured? Thank you. Plugin configuration <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-antrun-plugin</artifactId> <version>1.6</version> <executions> <execution> <phase>validate</phase> <goals> <goal>run</goal> </goals> <configuration> <target> <for param="extension"> <path> <dirset dir="${basedir}/src/main/webapp/WEB-INF/resources/extensions/"> <include name="*" /> </dirset> </path> <sequential> <basename property="extension.name" file="${extension}" /> <echo message="Creating JAR for extension '${extension.name}'." /> <jar destfile="${basedir}/target/extension-${extension.name}-1.0.0.jar"> <zipfileset dir="${extension}" prefix="WEB-INF/resources/extensions/${extension.name}/"> <include name="**/*" /> </zipfileset> </jar> </sequential> </for> </target> </configuration> </execution> </executions> <dependencies> <dependency> <groupId>ant-contrib</groupId> <artifactId>ant-contrib</artifactId> <version>1.0b3</version> <exclusions> <exclusion> <groupId>ant</groupId> <artifactId>ant</artifactId> </exclusion> </exclusions> </dependency> <dependency> <groupId>org.apache.ant</groupId> <artifactId>ant-nodeps</artifactId> <version>1.8.1</version> </dependency> </dependencies> </plugin> Error [ERROR] Failed to execute goal org.apache.maven.plugins:maven-antrun-plugin:1.6:run (default) on project extension-platform: An Ant BuildException has occured: Problem: failed to create task or type for [ERROR] Cause: The name is undefined. [ERROR] Action: Check the spelling. [ERROR] Action: Check that any custom tasks/types have been declared. [ERROR] Action: Check that any <presetdef>/<macrodef> declarations have taken place. [ERROR] -> [Help 1] [ERROR] [ERROR] To see the full stack trace of the errors, re-run Maven with the -e switch. [ERROR] Re-run Maven using the -X switch to enable full debug logging. [ERROR] [ERROR] For more information about the errors and possible solutions, please read the following articles: [ERROR] [Help 1] http://cwiki.apache.org/confluence/display/MAVEN/MojoExecutionException

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  • Django: A Result Specific Numeration for Pagination.

    - by TheLizardKing
    Simply put I want what http://www.reddit.com/ and http://news.ycombinator.com/ have to the left of every link. A numerated link starting with 1 and continuing to the next page by means of pagination. I really enjoy using generic views and their built-in pagination for Django and it seems to allow me access to these values if I was on page 3 with 2 items per page. {'MEDIA_URL': ''} {'LANGUAGES': '<<languages>>', 'LANGUAGE_BIDI': False, 'LANGUAGE_CODE': 'en-us'} {'debug': True, 'sql_queries': '<<sql_queries>>'} {'messages': [], 'perms': <django.core.context_processors.PermWrapper object at 0xadedeec>, 'user': <User: thelizardking>} {'first_on_page': 5, 'has_next': True, 'has_previous': True, 'hits': 7, 'is_paginated': True, 'last_on_page': 6, 'links_list': [<Link: Funky Town>, <Link: Apple Jax>], 'next': 4, 'page': 3, 'page_obj': <Page 3 of 4>, 'page_range': [1, 2, 3, 4], 'pages': 4, 'paginator': <django.core.paginator.Paginator object at 0xadf914c>, 'previous': 2, 'results_per_page': 2} I know there is an add filter for templates but that's as close as I think I can get and that really doesn't do what I want. Am I going to have to use a custom template filter here or is there something I am not seeing?

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  • django customizing form labels

    - by Henri
    I have a problem in customizing labels in a Django form This is the form code in file contact_form.py: from django import forms class ContactForm(forms.Form): def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) The view I am using this in looks like: def contact(request, product_id=None): . . . if request.method == 'POST': form = contact_form.ContactForm(request.POST) if form.is_valid(): . . else: form = contact_form.ContactForm( subject_label = "Subject", message_label = "Your Message", email_label = "Your email", cc_myself_label = "Cc myself") The strings used for initializing the labels will eventually be strings dependent on the language, i.e. English, Dutch, French etc. When I test the form the email is not sent and instead of the redirect-page the form returns with: <QueryDict: {u'cc_myself': [u'on'], u'message': [u'message body'], u'email':[u'[email protected]'], u'subject': [u'test message']}>: where the subject label was before. This is obviously a dictionary representing the form fields and their contents. When I change the file contact_form.py into: from django import forms class ContactForm(forms.Form): """ def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label """ subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) i.e. disabling the initialization then everything works. The form data is sent by email and the redirect page shows up. So obviously something the the init code isn't right. But what? I would really appreciate some help.

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  • Django "login() takes exactly 1 argument (2 given)" error

    - by Oleksandr Bolotov
    I'm trying to store the user's ID in the session using django.contrib.auth.login . But it is not working not as expected. I'm getting error login() takes exactly 1 argument (2 given) With login(user) I'm getting AttributeError at /login/ User' object has no attribute 'method' I'm using slightly modifyed example form http://docs.djangoproject.com/en/dev/topics/auth/ : from django.shortcuts import render_to_response from django.contrib.auth import authenticate, login def login(request): msg = [] if request.method == 'POST': username = request.POST['u'] password = request.POST['p'] user = authenticate(username=username, password=password) if user is not None: if user.is_active: login(request, user) msg.append("login successful") else: msg.append("disabled account") else: msg.append("invalid login") return render_to_response('login.html', {'errors': msg}) there's nothing special about login.html: <html> <head> <title></title> </head> <body> <form action="/login/" method="post"> Login:&nbsp; <input type="text" name="u"> <br/> Password:&nbsp; <input type="password" name="p"> <input type="submit" value="Login"> </form> {% if errors %} <ul> {% for error in errors %} <li>{{ error }}</li> {% endfor %} </ul> {% endif %} </body> </html> Does anybody have idea how to make login() work.

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  • manage.py runserver throws an ImportError with my appname, MacPorts issue on OSX?

    - by christmasgorilla
    I've been developing a Django app for weeks locally on OSX 10.6.3. Recently, I rebooted my machine and went to start my development environment up. Here's the error: cm:myApp cm$ python manage.py runserver Traceback (most recent call last): File "manage.py", line 11, in execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/init.py", line 360, in execute_manager setup_environ(settings_mod) File "/Library/Python/2.6/site-packages/django/core/management/init.py", line 343, in setup_environ project_module = import_module(project_name) File "/Library/Python/2.6/site-packages/django/utils/importlib.py", line 35, in import_module import(name) ImportError: No module named myapp I'm pretty new to Django / Python. Digging around, it's possible that this might be due to MacPorts. Initially, I had a rough time getting Django up and running and I no longer remember if I'm using the Django from a MacPorts install or from easy_install. How do I tell? (I'd prefer not to reinstall everything). Also, why is the camel casing in my app name gone in the ImportError message? When I search for "myapp" in my django project, I don't find it without camelcase anywhere. And what causes MacPorts to work for a while but then break? As a few other details, from settings.py: INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.admin', 'south', 'registration', 'pypaypal', 'notifier', 'myApp.batches', )

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  • JSON Serialization of a Django inherited model

    - by Simon Morris
    Hello, I have the following Django models class ConfigurationItem(models.Model): path = models.CharField('Path', max_length=1024) name = models.CharField('Name', max_length=1024, blank=True) description = models.CharField('Description', max_length=1024, blank=True) active = models.BooleanField('Active', default=True) is_leaf = models.BooleanField('Is a Leaf item', default=True) class Location(ConfigurationItem): address = models.CharField(max_length=1024, blank=True) phoneNumber = models.CharField(max_length=255, blank=True) url = models.URLField(blank=True) read_acl = models.ManyToManyField(Group, default=None) write_acl = models.ManyToManyField(Group, default=None) alert_group= models.EmailField(blank=True) The full model file is here if it helps. You can see that Company is a child class of ConfigurationItem. I'm trying to use JSON serialization using either the django.core.serializers.serializer or the WadofStuff serializer. Both serializers give me the same problem... >>> from cmdb.models import * >>> from django.core import serializers >>> serializers.serialize('json', [ ConfigurationItem.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.configurationitem", "fields": {"is_leaf": true, "extension_attribute_10": "", "name": "", "date_modified": "2010-05-19 14:42:53", "extension_attribute_11": false, "extension_attribute_5": "", "extension_attribute_2": "", "extension_attribute_3": "", "extension_attribute_1": "", "extension_attribute_6": "", "extension_attribute_7": "", "extension_attribute_4": "", "date_created": "2010-05-19 14:42:53", "active": true, "path": "/Locations/London", "extension_attribute_8": "", "extension_attribute_9": "", "description": ""}}]' >>> serializers.serialize('json', [ Location.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.location", "fields": {"write_acl": [], "url": "", "phoneNumber": "", "address": "", "read_acl": [], "alert_group": ""}}]' >>> The problem is that serializing the Company model only gives me the fields directly associated with that model, not the fields from it's parent object. Is there a way of altering this behaviour or should I be looking at building a dictionary of objects and using simplejson to format the output? Thanks in advance ~sm

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  • Javascript with Django?

    - by Rosarch
    I know this has been asked before, but I'm having a hard time setting up JS on my Django web app, even though I'm reading the documentation. I'm running the Django dev server. My file structure looks like this: mysite/ __init__.py MySiteDB manage.py settings.py urls.py myapp/ __init__.py admin.py models.py test.py views.py templates/ index.html Where do I want to put the Javascript and CSS? I've tried it in a bunch of places, including myapp/, templates/ and mysite/, but none seem to work. From index.html: <head> <title>Degree Planner</title> <script type="text/javascript" src="/scripts/JQuery.js"></script> <script type="text/javascript" src="/media/scripts/sprintf.js"></script> <script type="text/javascript" src="/media/scripts/clientside.js"></script> </head> From urls.py: (r'^admin/', include(admin.site.urls)), (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'media'}) (r'^.*', 'mysite.myapp.views.index'), I suspect that the serve() line is the cause of errors like: TypeError at /admin/auth/ 'tuple' object is not callable Just to round off the rampant flailing, I changed these settings in settings.py: MEDIA_ROOT = '/media/' MEDIA_URL = 'http://127.0.0.1:8000/media'

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  • Django: Serving Media Behind Custom URL

    - by TheLizardKing
    So I of course know that serving static files through Django will send you straight to hell but I am confused on how to use a custom url to mask the true location of the file using Django. http://stackoverflow.com/questions/2681338/django-serving-a-download-in-a-generic-view but the answer I accepted seems to be the "wrong" way of doing things. urls.py: url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), views.py: def song_download(request, song_id): song = Song.objects.get(id=song_id) fsock = open(os.path.join(song.path, song.filename)) response = HttpResponse(fsock, mimetype='audio/mpeg') response['Content-Disposition'] = "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response This solution works perfectly but not perfectly enough it turns out. How can I avoid having a direct link to the mp3 while still serving through nginx/apache? EDIT 1 - ADDITIONAL INFO Currently I can get my files by using an address such as: http://www.example.com/music/song/1692/download/ But the above mentioned method is the devil's work. How can I accomplished what I get above while still making nginx/apache serve the media? Is this something that should be done at the webserver level? Some crazy mod_rewrite? http://static.example.com/music/Aphex%20Twin%20-%20Richard%20D.%20James%20(V0)/10%20Logon-Rock%20Witch.mp3

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  • Using Pylint with Django

    - by rcreswick
    I would very much like to integrate pylint into the build process for my python projects, but I have run into one show-stopper: One of the error types that I find extremely useful--:E1101: *%s %r has no %r member*--constantly reports errors when using common django fields, for example: E1101:125:get_user_tags: Class 'Tag' has no 'objects' member which is caused by this code: def get_user_tags(username): """ Gets all the tags that username has used. Returns a query set. """ return Tag.objects.filter( ## This line triggers the error. tagownership__users__username__exact=username).distinct() # Here is the Tag class, models.Model is provided by Django: class Tag(models.Model): """ Model for user-defined strings that help categorize Events on on a per-user basis. """ name = models.CharField(max_length=500, null=False, unique=True) def __unicode__(self): return self.name How can I tune Pylint to properly take fields such as objects into account? (I've also looked into the Django source, and I have been unable to find the implementation of objects, so I suspect it is not "just" a class field. On the other hand, I'm fairly new to python, so I may very well have overlooked something.) Edit: The only way I've found to tell pylint to not warn about these warnings is by blocking all errors of the type (E1101) which is not an acceptable solution, since that is (in my opinion) an extremely useful error. If there is another way, without augmenting the pylint source, please point me to specifics :) See here for a summary of the problems I've had with pychecker and pyflakes -- they've proven to be far to unstable for general use. (In pychecker's case, the crashes originated in the pychecker code -- not source it was loading/invoking.)

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  • Django apache-wsgi configuration problem

    - by omat
    Hi, I am trying to get my Django project running on the production server. I setup the environment using pip, so it is identical to the development environment where everything is running fine. The only difference is that I don't use virtualenv on production, because this project is the only one that is going to run on production. Also on production, there is an Nginx reverse proxy to serve static content, and passes dynamic requests to Apache2. The Apache wsgi file is as follows: import sys, os sys.path.append('/home/project/src') os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() When I access the server, I get an import error: ImproperlyConfigured: Error importing middleware middleware: "cannot import name UserProfile" Which refers to the middleware.py under src/ folder which is referred by the settings. But I can import both the middleware and the UserProfile class from within ./manage.py shell prompt. It seems like a problem with paths in wsgi file but I cannot see what. The directory structure is: /home/project /home/project/src (which contains the settings.py, middleware.py and app folders) /home/apache/apache.wsgi Any help is greatly appreciated. Thanks, oMat

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  • problems doing the Django tutorial on Dreamhost using Passengers

    - by Pietro Speroni
    I have looked and I could not find this question before, and it surprises me. I am reasonably proficient in Python, and I used Dreamhost for a number of years. Now I would like to learn Django. They are finally supporting it using Passenger. Which I do not know what is. Following the instructions on Dreamhost I installed Django. Then I started following the tutorial 01. This went well, except that I could not start the server (this in the tutorial) since the code was live on dreamhost. At the time this did not seem to make any difference. Then when I went on the second part of the tutorial I had to access the admin site. And it worked well going to myurl/admin/ , as it should. But here the problems started. According to the tutorial (here) I have to add a file in the poll application and then restart the server. But I never started the server in the first place, my code is running live on the web... but when I add a file the website the admin acts as if it does not see it. Probably dreamhost has started its own server, and I don't know how to restart it. But I assume this is going to be a common problem when you run django on dreamhost. Every time you add a file you will have to tell the server to consider it. So what should I do to let the server know about it? Thanks, Pietro

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  • Django sitemap intermittent www

    - by Jen Z
    The automatic sitemap for my Django site fluctuates between including the www on urls and leaving it out (I'm aiming to have it in all the time). This has ramifications in google not indexing my pages properly so I'm trying to narrow down what would be causing this issue. I have set PREPEND_WWW = True and my site record in the sites framework is set to include the www e.g. it's set to www.example.com as opposed to example.com. I'm using memcached but pages should expire from the cache after 48 hours so I wouldn't have thought that would be causing the issue? You can see the problem in effect at http://www.livingspaceltd.co.uk/sitemap.xml (refresh the page a few times). My sitemaps setup is fairly prosaic so I'm doubtful that that is the issue, but in case it's something obvious I'm missing here's the code: ***urls.py*** sitemaps = { 'subpages': Subpages_Sitemap, 'standalone_pages': Standalone_Sitemap, 'categories': Categories_Sitemap, } urlpatterns = patterns('', (r'^sitemap\.xml$', 'django.contrib.sitemaps.views.sitemap', {'sitemaps': sitemaps}), ... ***sitemaps.py*** # -*- coding: utf-8 -*- from django_ls.livingspace.models import Page, Category, Standalone_Page, Subpage from django.contrib.sitemaps import Sitemap class Subpages_Sitemap(Sitemap): changefreq = "monthly" priority = 0.4 def items(self): return Subpage.objects.filter(restricted_to__isnull=True) class Standalone_Sitemap(Sitemap): changefreq = "weekly" priority = 1 def items(self): return Standalone_Page.objects.all() class Categories_Sitemap(Sitemap): changefreq = "weekly" priority = 0.7 def items(self): return Category.objects.all()

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  • Django does not load internal .css files

    - by Rubén Jiménez
    I have created a Django project in local which runs without any kind of problem. But, after an annoying and difficult Cherokee + uWSGI installation on Amazon AWS, my project does not show Django .css internal files. http://f.cl.ly/items/2Q2W3I3R0X1n2X3v0q2P/django_error.jpg <-- /Admin/ looks like The image is a screen of my /admin/, which should have a different style, but .css files are not loaded. [pid: 23206|app: 0|req: 19/19] 83.49.10.217 () {56 vars in 1121 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/base.css = generated 2896 bytes in 6 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) [pid: 23206|app: 0|req: 20/20] 83.49.10.217 () {56 vars in 1125 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/login.css = generated 2899 bytes in 5 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) This is a log from Cherokee. I don't understand why it is looking for the .css files in that path. Cherokee should be searching the files in Django original directory so i didn't change .css files in my project. Any advice? Thanks a lot.

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  • inserting a form to session raises picklingerror - django

    - by shanyu
    I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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  • On-Demand thumbnail creation with django and nginx

    - by sharjeel
    I want to generate thumbnails of images on the fly. My site is built with django and deployed using nginx which serves all the static content and communicates with django/apache using reverse proxy. Right now, for every image in my site, I generate all required sizes of thumbnails on-hand and deliver them when required. The problem is that whenever I change the size of a thumbnail, I have to regenerate all of them (and they are tons). However now I'd like to generate the thumbnail the first time it is accessed and later on nginx would deliver the same file over n over. If I delete that thumbnail file because of lesser accesses, it should get generated automatically the next time. Thumbnails in my case also have watermarks which require some computation logic of my application so a webserver thumbnail module might not work very well. The size of the thumbnail can be embedded in the URL. So http://www.example.com/thumbnail/abc_320x240.jpg gets the 320x240 size of the thumbnail. The approach I'm looking right now is to let nginx lookup the file and if it doesn't exist, forward the query to my django application which would create the thumbnail and send either the response or a redirect string. However I'm not sure about the concurrency issues and any other issues which might pop up later. What is the appropriate way to achieve this?

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  • Django website on Apache with wsgi failing

    - by notagain
    I have a website I've built in django that I'm trying to get working on our corporate Apache server (on debian) for our intranet at my workplace. Unfortunately, Apache keeps returning server errors whenever I try to navigate to my site. Although I can navigate to the statics folder. My Apache config and wsgi script look like the following... lbirdf.wsgi import os import sys sys.path.append('/home/lbi/rdfweb/web') sys.path.append('/home/lbi/rdfweb/lbirdf') os.environ['DJANGO_SETTINGS_MODULE'] = 'lbirdf.settings_production' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Apache config Listen 8080 <VirtualHost *:8080> ServerName server1 WSGIScriptAlias /rdfweb /home/lbi/rdfweb/web/lbirdf/apache/lbirdf.wsgi Alias /statics /home/lbi/rdfweb/web/lbirdf/statics Alias /admin_media /home/lbi/rdfweb/web/lbirdf/admin_media <Directory /home/lbi/rdfweb/web/lbirdf/apache> Order allow,deny Allow from all </Directory> <Directory /home/lbi/rdfweb/web/lbirdf/admin_media> Order allow,deny Allow from all </Directory> </VirtualHost> Any ideas on where I might be going wrong?

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  • Django Development Environment Setup Questions

    - by Ross Peoples
    Hello, I'm trying to set up a good development environment for a Django project that I will be working on from two different physical locations. I have two Mac machines, one at home and one at work that I do most of my development on. I currently host a Ubuntu virtual machine on one of the machines to host the Django environemnt, install DropBox on it, and edit source code from my Mac. When I save the code file, the changes get synced over DropBox to the Ubuntu VM and the Django development server automatically restarts because of the change. This method has worked well in the past, but I am starting to use DropBox for a lot of other things now and don't want all of that to be downloaded on every virtual machine I use. Plus, I want to start using Eclipse + PyDev to be able to debug code and have code completion. Currently, I use TextEdit which is great, but doesn't support debugging or completion. So what are my options? I thought about setting up a Parallels VM on a thumb drive that has my entire environment on it (Eclipse included), but that has its own problems. Any other thoughts?

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  • JavaScript cookie value can't be retrieved in Django

    - by Boris Rusev
    I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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  • Ajax request not receiving xml from Django

    - by amougeot
    I have a Django server which handles requests to a URL which will return some HTML for use in an image gallery. I can navigate to the URL and the browser will display the HTML that is returned, but I can't get that same HTML by doing an AJAX call (using jQuery) to the same URL. This is the view that generates the response: def gallery_images(request, gallery_name): return render_to_response('galleryimages.html', {'images': get_images_of_gallery(gallery_name)}, mimetype='text/xml') This is the 'galleryimages.html' template: {% for image in images %} <div id="{{image.name}}big"> <div class="actualImage" style="background-image:url({{image.image.name}});"> <h1>{{image.caption|safe}}</h1> </div> </div> {% endfor %} This is the jQuery call I am making: $("#allImages").load("http://localhost:8000/galleryimages/Web"); However, this loads nothing into my #allImages div. I've used firebug and ran jQuery's Ajax method .get("http://localhost:8000/galleryimages/Web") and firebug says that the response text is completely empty. When I check my Django server log, this is the entry I see for when I navigate to the URL manually, through my browser: [16/Jan/2010 17:34:10] "GET /galleryimages/Web HTTP/1.1" 200 215 This is the entry in the server log for when I make the AJAX call: [16/Jan/2010 17:36:19] "OPTIONS /galleryimages/Web HTTP/1.1" 200 215 Why does the AJAX request not get the xml that my Django page is serving?

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  • Django | passing form values

    - by MMRUser
    I want to create a user sign up process that requires two different forms with the same data one (1st form) is for filling out the data and other one (2nd form) is for displaying the filled data as a summery (before actually saving the data) so then user can view what he/she has filled up... my problem is that how do I pass 1st form's data in to the 2nd one .. I have used the basic Django form manipulation mechanism and passed the form field values to the next form using Django template tags.. if request.method == 'POST': form = Users(request.POST) if form.is_valid(): cd = form.cleaned_data try: name = cd['fullName'] email = cd['emailAdd'] password1 = cd['password'] password2 = cd['password2'] phoneNumber = cd['phoneNumber'] return render_to_response('signup2.html', {'name': name, 'email': email, 'password1': password1, 'password2': password2, 'phone': phone, 'pt': phoneType}) except Exception, ex: return HttpResponse("Error %s" % str(ex)) and from the second from I just displayed those field values using tags and also used hidden fields in order to submit the form with values, like this: <label for="">Email:</label> {{ email }} <input type="hidden" id="" name="email" class="width250" value="{{ email }}" readonly /> It works nicely from the out look, but the real problem is that if someone view the source of the html he can simply get the password even hackers can get through this easily. So how do I avoid this issue.. and I don't want to use Django session since this is just a simple sign up process and no other interactions involved. Thanks.

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