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  • Project Showcase: SaaS Web Apps Hits a Home Run with New SCMS Database

    - by Webgui
    We love seeing projects from start to finish, and we’re happy to share the latest example with you. Who: SaaS Web Apps – they use Software as a Service to create web applications that look and feel like desktop applications. What: SaaS Web Apps needed to build a Sports Contract Management System (SCMS) for one of its customers, Premier Stinson Sports. Why: The SCMS database is used for collecting, analyzing and recording college coach and athletic directors’ employment and contract data. The Challenge: Premier Stinson Sports works with a number of partners, each with its own needs and unique requirements. For example, USA Today uses the system to provide cutting edge news analysis while The National Sports Law Institute of Marquette University Law School uses it to for the latest sports contract data and student analysis. In addition, the system needed to be secure due to the sensitivity of the data; it was essential that the user security and permissions be easily configurable. As always, performance was a key factor, especially with the intense reporting and analytical capabilities for this project. Because of this, most of the processing had to be done on a dedicated server but the project called for the richness and responsiveness of a desktop application. The Solution: To execute the project, SaaS Web Apps used APS.Net-based Visual WebGui from Gizmox, combined with SQL Server 2008 and SQL Reporting Services. This combination resulted in a quick deployment for SaaS Web Apps’ customers. The Result: The completed project gave each partner the scalability and availability of a web application with the performance and security of a desktop application. As an example, USA Today pulls data from this database to give readers the latest sports stats – Salary analysis of 2010 Football Bowl Subdivision Coaches. And here’s a screenshot of the database itself. Great work, SaaS Web Apps!

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  • Shoring up deficiencies in a "home grown" programmer?

    - by JohnP
    I started out by teaching myself BASIC on a Vic 20, and in college (mid 80's) I had Fortran, Pascal, limited C, machine and assembler (With a smattering of COBOL). I didn't touch programming from approx 1989 to 1999. At that point, I was lucky enough to get hired as a Clipper programmer. Took me about 6 months to learn most of it, and by now (13 yrs) I'm pretty expert in it. I have also picked up Cold Fusion, some C#, some ASP, SQL, etc. I know programming structures, but in most languages I'm missing the esoterics, and I know my code could be much tighter. The problem is that I've learned what I needed to, to get the job done. This results in a lot of gaps in practical knowledge. I am also missing out on a TON of theory. Things like SRP, Refactoring, etc are alien terms. (Although I grok the intent after a short read). In addition, I am in the position now of teaching junior programmers the company and our software, and I don't want to pass on the knowledge gaps. I know this is somewhat of a subjective question and may be closed, but how do you go back and pick up what you've missed?

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  • BlackBerry 10 en images (4/9) : la Home, des vignettes dynamiques mais pas personnalisables

    BlackBerry 10 en images (1/9) : BlackBerry Flow RIM dévoile les nouveautés au compte-goutte et promet de très grosses surprises Deux jours après les annonces officielles du PDG de RIM, la filiale Française nous a conviés à une démonstration pour nous dévoiler « en vrai » quelques nouveautés supplémentaires de son prochain BlackBerry 10. « Son plus gros lancement de tous les temps », selon David Derrida, le responsable produit. Les voici en images au moment où le code est officiellement gelé. BlackBerry Flow C'est la nouvelle manière d'interagir avec l'OS. ...

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  • Can I make a business in teaching home users Ubuntu [on hold]

    - by Dorgaldir
    I was thinking about a way to bring Ubuntu to the bigger public, since it has great advantages for people in the lower income class that only use a PC for basic usage. They pay for a windows licence without actually needing windows because 95% of what they do is in a browser and the other 5% is typing a word document or making a simpel Excel sheet. So for these people something like Ubuntu is ideal, they can prolong the life of their old PC or laptop with Ubuntu and thus saving extra money. And as we all know, saving money is not only interesting for the lowest of income but for most of us. But when I talk to people they don't want to use Ubuntu because they know Windows and they don't know this, they'll complain about having to adapt to windows 8 but adapting to Ubuntu seems a bridge too far. But what if someone in the neighborhood gave simple Ubuntu courses. Teaching people about Ubuntu, stuff like: What is an OS What is Ubuntu How do I obtain Ubuntu How do I install Ubuntu How do I set up my email in Ubuntu How do I make a text document in Ubuntu How do I update my facebook wall in Ubuntu ... Simple basic PC usage, but within Ubuntu. But as much as I would like to work for free all day, I can't do this for free for people outside of my social circle. So I was wondering if it is possible to make a business and make money with giving Ubuntu courses, or are their steps to be taken before this is possible. However... Do I need an Ubuntu or Canonical license? Do I need to get a certificate? Do I have to make some kind of deal or contract with Canonical? Just to be clear this is all just an idea in my head at this point, I'm just gathering information. I'm not a teacher at a school, just a programmer that is thinking about options in life. Thanks in advance!

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  • Can't load Wordpress static files on home network

    - by Tosho
    I've just installed Wordpress 3.5 on my laptop (LAMP on Ubuntu 12.10) and when I'm trying to access the site from my phone but it doesn't load static files (css and images). I tried with Opera Mobile Emulator on my laptop and it works perfectly. I also have another Drupal site on my localhost which I can load from my phone without any issues. Both directories have chmod 777 permissions. What can cause that? Just tried to open the site from my sister's laptop but it except static file I can't access any post or page.

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  • Recursive Perl detail need help

    - by Catarrunas
    Hi everybody, i think this is a simple problem, but i'm stuck with it for some time now! I need a fresh pair of eyes on this. The thing is i have this code in perl: #!c:/Perl/bin/perl use CGI qw/param/; use URI::Escape; print "Content-type: text/html\n\n"; my $directory = param ('directory'); $directory = uri_unescape ($directory); my @contents; readDir($directory); foreach (@contents) { print "$_\n"; } #------------------------------------------------------------------------ sub readDir(){ my $dir = shift; opendir(DIR, $dir) or die $!; while (my $file = readdir(DIR)) { next if ($file =~ m/^\./); if(-d $dir.$file) { #print $dir.$file. " ----- DIR\n"; readDir($dir.$file); } push @contents, ($dir . $file); } closedir(DIR); } I've tried to make it recursive. I need to have all the files of all of the directories and subdirectories, with the full path, so that i can open the files in the future. But my output only returns the files in the current directory and the files in the first directory that it finds. If i have 3 folders inside the directory it only shows the first one. Ex. of cmd call: "perl readDir.pl directory=C:/PerlTest/" Thanks

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  • Active Directory Membership Provider - how to expand on this?

    - by Jaxidian
    I'm working on getting an MVC app up and running via AD Membership Provider and I'm having some issues figuring this out. I have a base configuration setup and working when I login as [email protected] + password. <connectionStrings> <add name="MyConnString" connectionString="LDAP://domaincontroller/OU=Product Users,DC=my,DC=domain,DC=com" /> </connectionStrings> <membership defaultProvider="MyProvider"> <providers> <clear /> <add name="MyProvider" connectionStringName="MyConnString" connectionUsername="my.domain.com\service_account" connectionPassword="biguglypassword" type="System.Web.Security.ActiveDirectoryMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" /> </providers> </membership> However, I'd LIKE to do some other things and I'm not sure how to go about them. Login without typing the domain (i.e. the "@my.domain.com"). I realize that this could only work if I limit myself to just one domain - that's fine. Organize users in up to N different OUs within a single OU. As you can tell from my current connection string, I'm authenticating users in my Product Users OU. I would LIKE to create OUs for various companies within this OU and put the users into those OUs. How can I authenticate across all of these different OUs? I'm trying to figure out how the Active Directory Membership Provider ties in with the Profile and Role providers. Are there AD versions of those too or am I stuck with SQL, home-grown, or finding something somebody else has coded up? Many thanks!!

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  • How can I remove all users in an Active Directory group?

    - by Beavis
    I'm trying to remove all users from an AD group with the following code: private void RemoveStudents() { foreach (DirectoryEntry childDir in rootRefreshDir.Children) { DirectoryEntry groupDE = new DirectoryEntry(childDir.Path); for (int counter = 0; counter < groupDE.Properties["member"].Count; counter++) { groupDE.Properties["member"].Remove(groupDE.Properties["member"][counter]); groupDE.CommitChanges(); groupDE.Close(); } } } The rootRefreshDir is the directory that contains all the AD groups (childDir). What I'm finding here is that this code does not behave correctly. It removes users, but it doesn't do it after the first run. It does "some". Then I run it again, and again, and again - depending on how many users need to be deleted in a group. I'm not sure why it's functioning this way. Can someone help fix this code or provide an alternative method to delete all users in a group? Thanks!

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  • Hiding elements based on last closed element jquery script

    - by Jared
    Hi my question is, how can I make this jquery script close all previously opened children when entering a new parent? At the moment it traverses thru all the tree structure fine, but switching from one parent to another does not close the previous children, but rather only the each individual parents elements as a user browses. Here is the jquery I'm using: <script type="text/javascript"> $(document).ready($(function(){ $('#nav>li>ul').hide(); $('.children').hide(); $('#nav>li').mousedown(function(){ // check that the menu is not currently animated if ($('#nav ul:animated').size() == 0) { // create a reference to the active element (this) // so we don't have to keep creating a jQuery object $heading = $(this); // create a reference to visible sibling elements // so we don't have to keep creating a jQuery object $expandedSiblings = $heading.siblings().find('ul:visible'); if ($expandedSiblings.size() > 0) { $expandedSiblings.slideUp(0, function(){ $heading.find('ul').slideDown(0); }); } else { $heading.find('ul').slideDown(0); } } }); $('#nav>li>ul>li').mousedown(function(){ // check that the menu is not currently animated if ($('#nav ul:animated').size() == 0) { // create a reference to the active element (this) // so we don't have to keep creating a jQuery object $heading2 = $(this); // create a reference to visible sibling elements // so we don't have to keep creating a jQuery object $expandedSiblings2 = $heading2.siblings().find('.children:visible'); if ($expandedSiblings2.size() > 0) { $expandedSiblings2.slideUp(0, function(){ $heading2.find('.children').slideDown(0); }); } else { $heading2.find('.children').slideDown(0); } } }); })); </script> and here is my html output <ul id="nav"> <li><a href="#">folder 4</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder 4/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder 4/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder 4/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder 4/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder 4/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder 4/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder 4/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder 4/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder 4/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder 4/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> <li><a href="#">folder1</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder1/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder1/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder1/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder1/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder1/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder1/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder1/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder1/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder1/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder1/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> <li><a href="#">folder2</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder2/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder2/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder2/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder2/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder2/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder2/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder2/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder2/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder2/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder2/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> <li><a href="#">folder3</a> <ul><li><a href="#">2001</a> <ul><li class="children"><a href="./directory//folder3/2001/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2001/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder3/2001/doc3.txt">doc3.txt</a></li> </ul> </li> <li><a href="#">2002</a> <ul><li class="children"><a href="./directory//folder3/2002/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2002/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder3/2002/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder3/2002/doc4.txt">doc4.txt</a></li> </ul> </li> <li><a href="#">2003</a> <ul><li class="children"><a href="./directory//folder3/2003/Copy of doc1.txt">Copy of doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2003/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2003/doc2.txt">doc2.txt</a></li> </ul> </li> <li><a href="#">2004</a> <ul><li class="children"><a href="./directory//folder3/2004/doc1.txt">doc1.txt</a></li> <li class="children"><a href="./directory//folder3/2004/doc2.txt">doc2.txt</a></li> <li class="children"><a href="./directory//folder3/2004/doc3.txt">doc3.txt</a></li> <li class="children"><a href="./directory//folder3/2004/doc4.txt">doc4.txt</a></li> </ul> </li> </ul> </li> </ul> I assume my problem is, jquery isn't closing the children between each new parent so I need to make a call, but I'm a bit lost on how to do that. I know the code is pretty messy, this project was done in a huge rush and a very tight timeframe. Appreciate your answers and any other constructive comments, cheers :)

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  • Enabling Session Directory under Terminal Server Configuration Tool and Server Settings

    - by LPE
    Yello, I'm trying to add up a Terminal Server Session Directory client to an already fully functional Session Directory cluster which today runs two clients as well as the server. I've been reading up on both Google, Microsoft KB's as well as old documentation from an earlier employee but to no avail. The step I'm stuck at is when I open up Terminal Server Configuration Tool (tscc.msc), chooses ServerSettings. I know there should be an option saying "Session Directory" on the right hand side along with Active Desktop, Licensing and whatnot, but it's not there. I've logged on to both the other already functional clients and checked the same list and there the Session Directory option sure is both visible as well as working good with the specified information. This picture is the same view that I'm looking at at the moment, but mine is missing the bottom option that says "Session Directory" http://www.inetnj.com/doc/images/TerminalServerConfiguration.jpg Any help would be greatly appriciated. Regards LPE

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  • Directory Not Found Error

    - by noobguy
    I am trying to verify tails and when I get to the command prompt portion of the verification some difficulties seem to have arose. Below is the script: noob@noob-System-Product-Name:~$ cd [/media/noob/UUI] bash: cd: [/media/noob/UUI]: No such file or directory noob@noob-System-Product-Name:~$ gpg --keyid-format long --import tails-signing.key gpg: can't open `tails-signing.key': No such file or directory gpg: Total number processed: 0 Same thing happens when I try from download directory; noob@noob-System-Product-Name:~$ cd [/home/noob/Downloads] bash: cd: [/home/noob/Downloads]: No such file or directory noob@noob-System-Product-Name:~$ gpg --keyid-format long --import tails-signing.key gpg: can't open `tails-signing.key': No such file or directory gpg: Total number processed: 0 Any suggestions would be greatly appreciated.

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  • Jail Linux user to directory for FTP login

    - by Greg
    I'm planning on using vsftpd to act as a secure ftp server, but I am having difficulty controlling the linux users that will be used as ftp logins. The users are required to be "jailed" into a specific directory (and subdirectories) and have full read/write access. Requirements: - User account "admin_ftp" should be jailed to /var/www directory. - Other accounts will be added as needed, for each site... e.g: - User account "picturegallery_ftp" should be jailed to /var/www/picturegallery.com directory. I have tried the following, but to no avail: # Group to store all ftp accounts in. groupadd ftp_accounts # Group for single user, with the same name as the username. groupadd admin_ftp useradd -g admin_ftp -G ftp_accounts admin_ftp chgrp -R ftp_accounts /var/www chmod -R g+w /var/www When I log into FTP using account admin_ftp, I am given the error message: 500 OOPS: cannot change directory:/home/admin_ftp But didn't I specify the home directory? Extra internets for a guide how to do this specifically for vsftpd :)

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  • How to enable directory browsiing in IIS7?

    - by frankadelic
    How I enable directory browsing in IIS7? MS technet says this can be done in the IIS console: Open IIS Manager and navigate to the level you want to manage. In Features View, double-click Directory Browsing. In the Actions pane, click Enable if the Directory Browsing feature is disabled and you want to enable it. Or, click Disable if the Directory Browsing feature is enabled and you want to disable it. http://technet.microsoft.com/en-us/library/cc731109%28WS.10%29.aspx However, my IIS console doesn't have the Directory Browsing option mentioned in Step 2. How can this option be made available. Note, this is for a static HTML site, so I don't have any web.config or ASPX files.

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  • wget recursively with -np option still ascends to parent directory

    - by vectra
    tl;dr: will `wget --no-parrent -r ' download from a directory above the given url's directory? when using wget to download, say images, recursively from example.com/a/b with the -r and -np options, will a picture that is under example.com/a/c/ be downloaded when example.com/a/b/ delivers a html-file containing a link to the picture? if so, how do i get all pictures, that are in a folder and it's subfolders and only those? the description of the option --no-parent says "Do not ever ascend to the parent directory when retrieving recursively". anyway directory browsing delivers a link to the parent directory, which wget will follow, despite mentioned option. now what did i miss? edit: using GNU Wget 1.12

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  • Can't read directory owned by my group

    - by Jonathan
    I moved the postgres data directory to a separate partition and it works great. The directory is owned by postgres user and postgres group. d-wx------ 11 postgres postgres 4.0K 2010-06-11 08:28 data/ I added myself to the group > sudo addgroup me postgres > groups me me : me adm dialout cdrom plugdev lpadmin admin sambashare postgres And gave the group read and execute permissions to everything in the directory. sudo chmod -R g+rx ./data d-wxr-x--- 11 postgres postgres 4.0K 2010-06-11 08:28 data/ But I still can not CD or LS the directory. > ls data ls: cannot open directory data: Permission denied What beginner mistake am I making?

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  • Can't get sync with SVN to work to put a directory under version control

    - by Chamster
    I've created a directory on our SVN server and added a local directory with my project to it. It got uploaded and seems to be OK. However, I didn't get those cute green (or any others) icons on the file. So I clicked on the project's directory and used "checkout". That wasn't good because I've downloaded ALL of the repository. How can I synchronize my uploaded directory with it's corresponding directory on the server? (It's probably something easy that I've forgot to check in or so...)

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