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• I cant able to remove a row from a table while running through a loop

  - by Vibin Jith

  I am iterating through the table rows . if the row row is null I just want to remove the row. it shows an error Public Sub RemoveBlankRow(ByVal MyDataTable As DataTable) Try Dim MyRowStr As String = String.Empty For Each MyRow As DataRow In MyDataTable.Rows MyRowStr = "" For Each MyCellText As Object In MyRow.ItemArray MyRowStr = MyRowStr + MyCellText.ToString Next MyRowStr = Replace(MyRowStr, "0", " ") MyRowStr = Replace(MyRowStr, ".", " ") If MyRowStr.Trim = String.Empty Then MyDataTable.Rows.Remove(MyRow) End If Next Catch ex As Exception End Try End Sub How to overcome this issue?

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• UIWebView comparing current and defined URL's with a loop depending on result

  - by Syleron

  I am trying to compare the current url in webView with a defined url say google.com so in theory.. NSURLRequest *currentRequest = [webView request]; NSURL *currentURL = [currentRequest URL]; would give us our current url... NSString *newurl = @"http://www.google.com"; this would give us the compared to defined url while (!currentURL == newurl) { //do whatever here because currentURL does not equal the newurl } This does not seem to work though.. solutions?

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• Java Function Analysis

  - by khan

  Okay..I am a total Python guy and have very rarely worked with Java and its methods. The condition is that I have a got a Java function that I have to explain to my instructor and I have got no clue about how to do so..so if one of you can read this properly, kindly help me out in breaking it down and explaining it. Also, i need to find out any flaw in its operation (i.e. usage of loops, etc.) if there is any. Finally, what is the difference between 'string' and 'string[]' types? public static void search(String findfrom, String[] thething){ if(thething.length > 5){ System.err.println("The thing is quite long"); } else{ int[] rescount = new int[thething.length]; for(int i = 0; i < thething.length; i++){ String[] characs = findfrom.split("[ \"\'\t\n\b\f\r]", 0); for(int j = 0; j < characs.length; j++){ if(characs[j].compareTo(thething[i]) == 0){ rescount[i]++; } } } for (int j = 0; j < thething.length; j++) { System.out.println(thething[j] + ": " + rescount[j]); } } }

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• help, stuck with logic variable comparison loop, javascript

  - by Jamex

  I have an input text box for search of input, the id of the text box is: id="search". if a user enters 'cat' at first and hit search. In the function, I get the value 'cat' by using the syntax: var input = document.getElementById("search").value; After that, the user enter 'dog' in the search box and hit search using the same function. The function would assign 'dog' to the input variable. How would I compare the current value (dog) to the previously entered value (cat)? I have tried to assign the original input with a statement, something like var orig = input; but that would only overwrite the original input with the new input. What is the logical approach to this problem.

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• Python Loop for mysql statement

  - by user552974

  Hi, I have a project that i need to compile number of cities in each state and make an insert statement for mysql database. I think the easiest way to do it is via python but since i m a complete noob i would like to reach out all the python gurus here. Here is what the input looks like. Example below is for Florida. cities = ['Boca Raton', 'Boynton Beach', 'Bradenton', 'Cape Coral', 'Deltona'] and this what the output should be. INSERT INTO `oc_locations` (`idLocation`, `name`, `idLocationParent`, `friendlyName`) VALUES (1, 'Florida', 0, 'Florida'), (2, 'Boca Raton', 1, 'Boca Raton'), (3, 'Boynton Beach', 1, 'Boynton Beach'), (4, 'Bradenton', 1, 'Bradenton'), (5, 'Cape Coral', 1, 'Cape Coral'), (6, 'Deltona', 1, 'Deltona'), If you look at carefully the "idLocationParent" for "Florida" value is "0" so which means it is a top level value. This will be done for 50 states so ability to plug the state name into the mysql statement would be icing on the cake if there is a easy way to do it. Also alphabetical order and auto increment for the idLocation would be great. Here is an example of what i m trying to achieve concatenation is the part i need to figure out. for city in cities: print (1, 'city', 0, 'city'), city

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• comparing indexPaths in a loop iphone

  - by Brodie4598

  I am trying to compare an index path in my didSelectRowAtIndexPath delegate method with an array of index paths. for (n=0; n < [tempMutArrray count]; n= n+1){ NSComparisonResult *result = [indexPath compare:[tempMutArray objectAtIndex:n]; //What I want to do is is write an if statement that executes a certain block of code //if the two index paths are equal, but I cant figure out how to work with an //NSComparisonResult. }

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• calculate next line numbers

  - by osomanden

  Weird question I guess.. But I am not very math wiz - soo here goes.. I am trying to create a patterne (or variable patterns based on selection) based on x and y numbers (2 rows and 4 columns) and the direction of the counting of x numbers like: 1-2-3-4 5-6-7-8 That one is easy, when number of x-columns is reached, next line and continue x count. But with eg. this one (still 2 rows and 4 columns): 1-2-3-4 8-7-6-5 upsie.. what if it is eg. 3++ rows and still 4 columns? 1-2-3-4 8-7-6-5 9-10-11-12 what would be the formula for this - or other possible variations (teaser for variations): 9-10-11-12 8-7-6-5 1-2-3-4 or reversed

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• in R, the arguments of "for loop"

  - by alex

  Could anyone please tell me what is wrong with the R code below: i = 1.001 #make SAV and STO become vector SAV = c() STO = c() #set the initial values for the vector SAV[1] = 0 STO[1] = 100 for (t in 2:1000) { if ((price[t]>9.9)&(price[t]<10.1)&(SAV[t-1]!=0)) SAV[t]=SAV[t-1]*i STO[t]=0 } for (t in 2:1000) { if ((price[t]>9.9)&(price[t]<10.1)&(SAV[t-1]=0)) STO[t] = STO [t-1] SAV[t] = 0 } SAV STO What I am trying to do is to find vector for both SAV and STO.

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• While loop not reading in the last item

  - by Gandalf StormCrow

  I'm trying to read in a multi line string then split it then print it .. here is the string : 1T1b5T!1T2b1T1b2T!1T1b1T2b2T!1T3b1T1b1T!3T3b1T!1T3b1T1b1T!5T1*1T 11X21b1X 4X1b1X When I split the string with ! I get this without the last line string : 1T1b5T 1T1b5T1T2b1T1b2T 1T2b1T1b2T1T1b1T2b2T 1T1b1T2b2T1T3b1T1b1T 1T3b1T1b1T3T3b1T 3T3b1T1T3b1T1b1T 1T3b1T1b1T5T1*1T 5T1*1T11X21b1X 11X21b1X Here is my code : import java.io.BufferedInputStream; import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner stdin = new Scanner(new BufferedInputStream(System.in)); while (stdin.hasNext()) { for (String line : stdin.next().split("!")) { System.out.println(line); for (int i = 0; i < line.length(); i++) { System.out.print(line.charAt(i)); } } } } } Where did I make the mistake, why is not reading in the last line? After I read in all lines properly I should go trough each line if I encounter number I should print the next char the n times the number I just read, but that is long way ahead first I need help with this. Thank you UPDATE : Here is how the output should look like : 1T1b5T 1T2b1T1b2T 1T1b1T2b2T 1T3b1T1b1T 3T3b1T 1T3b1T1b1T 5T1*1T 11X21b1X 4X1b1X Here is a solution in C(my friend solved it not me), but I'd stil wanted to do it in JAVA : #include <stdio.h> int main (void) { char row[134]; for (;fgets (row,134,stdin)!=NULL;) { int i,j=0; for (i=0;row[i]!='\0';i++) { if (row[i]<='9'&&row[i]>='1') j+=(row[i]-'0'); else if ((row[i]<='Z'&&row[i]>='A')||row[i]=='*') for (;j;j--) printf ("%c",row[i]); else if (row[i]=='b') for (;j;j--) printf (" "); else if (row[i]=='!'||row[i]=='\n') printf ("\n"); } } return 0; }

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• string auto splitting in each loop - jquery

  - by sluggerdog

  I have the following jquery code that is looping through the returned json data, for some reason is it splitting the suburb by a space when being assigned as the value but not as the text, I cannot work out why this is happening. MY CODE $.each(data , function( index, obj ) { $.each(obj, function( key, value ) { var suburb = $.trim(value['mcdl01']); var number = $.trim(value['mcmcu']); $("#FeedbackBranchName").append("<option value=" + suburb + ">" + suburb + " (" + number + ")</option>"); }); }); SAMPLE RETURNED RESULTS <option **value="AIRLIE" beach=""**>AIRLIE BEACH (4440)</option> <option value="ASHMORE">ASHMORE (4431)</option> <option **value="BANYO" commercial=""**>BANYO COMMERCIAL (4432)</option> <option value="BEENLEIGH">BEENLEIGH (4413)</option> <option value="BERRIMAH">BERRIMAH (4453)</option> <option **value="BOWEN" hills=""**>BOWEN HILLS (4433)</option> Notice how for AIRLEE BEACH, BANYO COMMERICAL AND BOWN HILLS the second word has been separated out from the value attribute but it's fine at the text level. Anyone have any idea why this might happen? Thanks

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• Java do while, while

  - by Pindatjuh

  Hello, what behaviour can I expect when I run this code: do while(testA) { // do stuff } while(testB); Will it behave like: do { while(testA) { // do stuff } } while(testB); Or: if(testA) { do { // do stuff } while(testA && testB); } Or something totally unexpected? I ask this question because I think this is quite ambiguous, and for other people searching on this topic, not because I am lazy to test it out.

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• Scala println in a for loop

  - by random459

  The following Scala code does just what I expect it to - it prints each line of some_file.txt. import scala.io.Source val lines = Source.fromPath("some_file.txt").mkString for (line <- lines) print(line) If I use println instead of print, I expect to see some_file.txt printed out with double-spacing. Instead, the program prints a newline after every character of some_file.txt. Could someone explain this to me? I'm using Scala 2.8.0 Beta 1.

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• vba Loop over a non-contiguous range

  - by Jeffrey

  I have a non-contiguous range on rows (example address of myRange: $2:$2,$4:$205,$214:$214) and I would like to access a specific row and column within the range. I have tried the following: 'Get the value of the 2nd row, 1st column within the range myRange.rows(2).Cells(, 1).Value However, this is giving me the value of the 2nd row in the WorkSheet, and NOT in the range - meaning it is giving me address $3$1 - and not $4$1 Can someone please explain how I can access the values within in my range? (It may have to do with different areas) Thank You

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• Anova test in the loop and outputing the p-value in separate column

  - by Juanhijuan

  Once again I'm trying to get an answer. I am already stuck for like 5h with that so that's why I keep trying to get an answer. That's my data: id Sequence variable value 75 AAAAGAAAVANQGKK BiotinControl1_2 3893050.50 192 AAAAGAAAVANQGKK BiotinControl1_2 900604.61 3770 AAFTKLDQVWGSE BiotinControl1_2 90008.14 The code which I am trying to use to calculate the p-value: My Code: tbl_anv <- tbl_all_onlyK[,c("id", "BiotinControl1_2", "BiotinControl2", "BiotinControl3", "BiotinTreatment1_2", "BiotinTreatment2", "BiotinTreatment3", "Sequence")] tbl_reo <- melt(tbl_anv, measure.vars=2:7) set.seed(1) vars <- c("id", "BiotinControl1_2", "BiotinControl2", "BiotinControl3", "BiotinTreatment1_2", "BiotinTreatment2", "BiotinTreatment3", "Sequence") tbl_reo <- as.data.frame(tbl_reo) by(tbl_reo,tbl_reo$Sequence,function(x){ anova(lm(value ~ variable, data = x))$"Pr(>F)"[1] }) An error ocurs: There were 50 or more warnings (use warnings() to see the first 50) Anyway, how can I do that and export the p-value in the separate column. That's what I tried to do on my own: aov_test <- by(tbl_reo,tbl_reo$Sequence,function(x){ anova(lm(value ~ variable, data = x))$"Pr(>F)"[1] }) tbl_reo[,5] <- aov.test[[1]]$'Pr(>F)'[1]

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• from loop to Nested loops ?

  - by WM

  I have this program that returns a factorial of N. For example, when entering 4,,, it will give 1! , 2! , 3! How could I convert this to use nested loops? public class OneForLoop { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("Enter a number : "); int N = input.nextInt(); int factorial = 1; for(int i = 1; i < N; i++) { factorial *= i; System.out.println(i + "! = " + factorial); } } }

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• Question about variable definitions in functions.

  - by Kaan Tekelioglu

  Hi. #include <stdio.h> main() { int a; for(a=1; a<=4 && printf("%d ",a); a++) { int a; static int b=a; printf("%d ",(a++)-b); } getchar(); getchar(); } In this code, the printout is 1 0 2 1 3 2 4 3. I understand why the int a; part works differently then the int a which was defined outside the for function, and why static int b; is only defined once with the primary value of a ; but why does the (a++) part in printf affect proceeding values of a? Don't we redefine int a; each time the for function runs? Thanks in advance.

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• Parsing XML file using a for loop

  - by Johnny Spintel

  I have been working on this program which inserts an XML file into a MYSQL database. I'm new to the whole .jar idea by inserting packages. Im having an issue with parse(), select(), and children(). Can someone inform me how I could fix this issue? Here is my stack trace and my program below: Exception in thread "main" java.lang.Error: Unresolved compilation problems: The method select(String) is undefined for the type Document The method children() is undefined for the type Element The method children() is undefined for the type Element The method children() is undefined for the type Element The method children() is undefined for the type Element at jdbc.parseXML.main(parseXML.java:28) import java.io.*; import java.sql.*; import org.jsoup.Jsoup; import org.w3c.dom.*; import javax.xml.parsers.*; public class parseXML{ public static void main(String xml) { try{ BufferedReader br = new BufferedReader(new FileReader(new File("C:\\staff.xml"))); String line; StringBuilder sb = new StringBuilder(); while((line=br.readLine())!= null){ sb.append(line.trim()); } Document doc = Jsoup.parse(line); StringBuilder queryBuilder; StringBuilder columnNames; StringBuilder values; for (Element row : doc.select("row")) { // Start the query queryBuilder = new StringBuilder("insert into customer("); columnNames = new StringBuilder(); values = new StringBuilder(); for (int x = 0; x < row.children().size(); x++) { // Append the column name and it's value columnNames.append(row.children().get(x).tagName()); values.append(row.children().get(x).text()); if (x != row.children().size() - 1) { // If this is not the last item, append a comma columnNames.append(","); values.append(","); } else { // Otherwise, add the closing paranthesis columnNames.append(")"); values.append(")"); } } // Add the column names and values to the query queryBuilder.append(columnNames); queryBuilder.append(" values("); queryBuilder.append(values); // Print the query System.out.println(queryBuilder); } }catch (Exception err) { System.out.println(" " + err.getMessage ()); } } }

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• How to loop 3 dimension array using foreach PHP

  - by vzhen

  Below is foreach and the 3 dimension arrays, no problem with the looping but i cannot sepcify which array to echo, they must me the whole arrays like echo $subvalue, any better solutions with looping 3 dimension array? i actually feel weird with this looping. Thanks in adv foreach ($stories as $key => $story){ //echo "<br />"; foreach($story as $subkey => $subvalue){ echo $subvalue."<br />"; foreach($subvalue as $key => $subsubvalue){ echo $subsubvalue."<br />"; } } } Array ( [270] => Array ( [uid] => 36 [user_email] => [email protected] [sid] => 270 [story_name] => Story C [photo_url] => Array ( [0] => story_photos/2012/0322/361332381418153311.jpg [1] => story_photos/2012/0322/361332393792911587.jpg ) [photo_added_date] => Array ( [0] => 1332381418 [1] => 1332393792 ) ) [269] => Array ( [uid] => 36 [user_email] => [email protected] [sid] => 269 [story_name] => Story B [photo_url] => Array ( [0] => story_photos/2012/0322/361332381406580761.jpg ) [photo_added_date] => Array ( [0] => 1332381406 ) ) [268] => Array ( [uid] => 36 [user_email] => [email protected] [sid] => 268 [story_name] => Story A [photo_url] => Array ( [0] => story_photos/2012/0322/361332381393552719.jpg ) [photo_added_date] => Array ( [0] => 1332381393 ) ) )

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• Initialize and assign values to list of ints without a loop

  - by Shawn Mclean

  is there a shorter way to do this: List<int> mins = new List<int>(); for(int i = 0; i<60; i++) { mins.Add(i+1); } Functional version also appreciated if available in c#, also f# version appreciated.

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• PHP modifying and combining array

  - by Industrial

  Hi everyone, I have a bit of an array headache going on. The function does what I want, but since I am not yet to well acquainted with PHP:s array/looping functions, so thereby my question is if there's any part of this function that could be improved from a performance-wise perspective? I tried to be as complete as possible in my descriptions in each stage of the functions which shortly described prefixes all keys in an array, fill up eventual empty/non-valid keys with '' and removes the prefixes before returning the array: $var = myFunction ( array('key1', 'key2', 'key3', '111') ); function myFunction ($keys) { $prefix = 'prefix_'; $keyCount = count($keys); // Prefix each key and remove old keys for($i=0;$i<$keyCount; $i++){ $keys[] = $prefix.$keys[$i]; unset($keys[$i]); } // output: array('prefix_key1', 'prefix_key2', 'prefix_key3', '111) // Get all keys from memcached. Only returns valid keys $items = $this->memcache->get($keys); // output: array('prefix_key1' => 'value1', 'prefix_key2' => 'value2', 'prefix_key3'=>'value3) // note: key 111 was not found in memcache. // Fill upp eventual keys that are not valid/empty from memcache $return = $items + array_fill_keys($keys, ''); // output: array('prefix_key1' => 'value1', 'prefix_key2' => 'value2', 'prefix_key3'=>'value3, 'prefix_111' => '') // Remove the prefixes for each result before returning array to application foreach ($return as $k => $v) { $expl = explode($prefix, $k); $return[$expl[1]] = $v; unset($return[$k]); } // output: array('key1' => 'value1', 'key2' => 'value2', 'key3'=>'value3, '111' => '') return $return; } Thanks a lot!

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• Qt/C++ event loop exception handling

  - by Georg

  I am having an application heavily based on QT and on a lot of third party libs. THese happen to throw some exceptions in several cases. In a native Qt App this causes the application to abort or terminate. Often the main data model is still intact as I am keeping it in pure Qt with no external data. So I am thinking that I could also just recover by telling the user that there has occured an error in this an that process and he should save now or even decide to continue working on the main model. Currently the program jsut silently exits without even telling a story. Please help.

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• Python - List and Loop in one def

  - by Dunwitch

  I'm trying to get the def wfsc_pod1 and wfsc_ip into the same def. I'm not quite sure how to approach the problem. I want wfsc_pod1 to display all the information for name, subnet and gateway. Then wfsc_ip shows the ip addresses below it. I also get a None value when I run it as it. Not sure why. Anything more pythonic is more appreciated. class OutageAddress: subnet = ["255.255.255.0", "255.255.255.1"] # Gateway order is matched with names gateway = ["192.168.1.1", "192.168.1.2", "192.168.1.3", "192.168.1.4", "192.168.1.5", "192.168.1.6", "192.168.1.7", "192.168.1.8", "192.168.1.9"] name = ["LOC1", "LOC2", "LOC3", "LOC4", "LOC5", "LOC6", "LOC7", "LOC8", "LOC9"] def wfsc_pod1(self): wfsc_1 = "%s\t %s\t %s\t" % (network.name[0],network.subnet[0],network.gateway[0]) return wfsc_1 def wfsc_ip(self): for ip in range(100,110): ip = "192.168.1."+str(ip) print ip network = OutageAddress() print network.wfsc_pod1() print network.wfsc_ip()

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• Using array of asp inside javascript is not working in the loop

  - by Poomjai

  I have a problem that when i bring the array of asp and use it in the javascript, When i use the counter (i++) and print for each index of array just like "<%=app[i] %" and it is not return the value back to me. Please help me i solve this problem for a day !!!-Thanks ^_^ edit <% String[] asp = {"a","b","c"}; %> <script language="javascript"> for(var i=0;i<"<%=asp %>".length;i++){ document.write("<%=asp[i] %>") } </script> the error is = Compiler Error Message: CS0103: The name 'i' does not exist in the current context

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• Loop over fields in eclipse code template

  - by fastcodejava

  Can you do loops in code templates, e.g I want to print all the fields in a class. Is there a template for that?

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• [Ruby] Modifying object inside a loop doesn't change object outside of the loop?

  - by Jergason

  I am having problems with modifying objects inside blocks and not getting the expected values outside the blocks. This chunk of code is supposed to transform a bunch of points in 3d space, calculate a score (the rmsd or root mean squared deviation), and store both the score and the set of points that produced that score if it is lower than the current lowest score. At the end, I want to print out the best bunch of points. first = get_transformed_points(ARGV[0]) second = get_transformed_points(ARGV[1]) best_rmsd = first.rmsd(second) best_points = second #transform the points around x, y, and z and get the rmsd. If the new points # have a smaller rmsd, store them. ROTATION = 30 #rotate by ROTATION degrees num_rotations = 360/ROTATION radians = ROTATION * (Math::PI/180) num_rotations.times do |i| second = second * x_rotate num_rotations.times do |j| second = second * y_rotate num_rotations.times do |k| second = second * z_rotate rmsd = first.rmsd(second) if rmsd < best_rmsd then best_points = second best_rmsd = rmsd end end end end File.open("#{ARGV[1]}.out", "w") {|f| f.write(best_points.to_s)} I can print out the points that are getting stored inside the block, and they are getting transformed and stored correctly. However, when I write out the points to a file at the end, they are the same as the initial set of points. Somehow the best_points = second chunk doesn't seem to be doing anything outside of the block. It seems like there are some scoping rules that I don't understand here. I had thought that since I declared and defined best_points above, outside of the blocks, that it would be updated inside the blocks. However, it seems that when the blocks end, it somehow reverts back to the original value. Any ideas how to fix this? Is this a problem with blocks specifically?

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