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  • CUPS basic auth error through web interface

    - by Inaimathi
    I'm trying to configure CUPS to allow remote administration through the web interface. There's enough documentation out there that I can figure out what to change in my cupsd.conf (changing Listen localhost:631 to Port 631, and adding Allow @LOCAL to the /, /admin and /admin/conf sections). I'm now at the point where I can see the CUPS interface from another machine on the same network. The trouble is, when I try to Add Printer, I'm asked for a username and password, but my response is rejected even when I know I've gotten it right (I assume it's asking for the username and password of someone in the lpadmin group on the server machine; I've sshed in with credentials its rejecting, and the user I'm using has been added to the lpadmin group). If I disable auth outright, by changing DefaultAuthType Basic to DefaultAuthType None, I get an "Unauthorized" error instead of a password request when I try to Add Printer. What am I doing wrong? Is there a way of letting users from the local network to administer the print server through the CUPS web interface? EDIT: By request, my complete cupsd.conf (spoiler: minimally edited default config file that comes with the edition of CUPS from the Debian wheezy repos): LogLevel warn MaxLogSize 0 SystemGroup lpadmin Port 631 # Listen localhost:631 Listen /var/run/cups/cups.sock Browsing On BrowseOrder allow,deny BrowseAllow all BrowseLocalProtocols CUPS dnssd # DefaultAuthType Basic DefaultAuthType None WebInterface Yes <Location /> Order allow,deny Allow @LOCAL </Location> <Location /admin> Order allow,deny Allow @LOCAL </Location> <Location /admin/conf> AuthType Default Require user @SYSTEM Order allow,deny Allow @LOCAL </Location> # Set the default printer/job policies... <Policy default> # Job/subscription privacy... JobPrivateAccess default JobPrivateValues default SubscriptionPrivateAccess default SubscriptionPrivateValues default # Job-related operations must be done by the owner or an administrator... <Limit Create-Job Print-Job Print-URI Validate-Job> Order deny,allow </Limit> <Limit Send-Document Send-URI Hold-Job Release-Job Restart-Job Purge-Jobs Set-Job-Attributes Create-Job-Subscription Renew-Subscription Cancel-Subscription Get-Notifications Reprocess-Job Cancel-Current-Job Suspend-Current-Job Resume-Job Cancel-My-Jobs Close-Job CUPS-Move-Job CUPS-Get-Document> Require user @OWNER @SYSTEM Order deny,allow </Limit> # All administration operations require an administrator to authenticate... <Limit CUPS-Add-Modify-Printer CUPS-Delete-Printer CUPS-Add-Modify-Class CUPS-Delete-Class CUPS-Set-Default CUPS-Get-Devices> AuthType Default Require user @SYSTEM Order deny,allow </Limit> # All printer operations require a printer operator to authenticate... <Limit Pause-Printer Resume-Printer Enable-Printer Disable-Printer Pause-Printer-After-Current-Job Hold-New-Jobs Release-Held-New-Jobs Deactivate-Printer Activate-Printer Restart-Printer Shutdown-Printer Startup-Printer Promote-Job Schedule-Job-After Cancel-Jobs CUPS-Accept-Jobs CUPS-Reject-Jobs> AuthType Default Require user @SYSTEM Order deny,allow </Limit> # Only the owner or an administrator can cancel or authenticate a job... <Limit Cancel-Job CUPS-Authenticate-Job> Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit All> Order deny,allow </Limit> </Policy> # Set the authenticated printer/job policies... <Policy authenticated> # Job/subscription privacy... JobPrivateAccess default JobPrivateValues default SubscriptionPrivateAccess default SubscriptionPrivateValues default # Job-related operations must be done by the owner or an administrator... <Limit Create-Job Print-Job Print-URI Validate-Job> AuthType Default Order deny,allow </Limit> <Limit Send-Document Send-URI Hold-Job Release-Job Restart-Job Purge-Jobs Set-Job-Attributes Create-Job-Subscription Renew-Subscription Cancel-Subscription Get-Notifications Reprocess-Job Cancel-Current-Job Suspend-Current-Job Resume-Job Cancel-My-Jobs Close-Job CUPS-Move-Job CUPS-Get-Document> AuthType Default Require user @OWNER @SYSTEM Order deny,allow </Limit> # All administration operations require an administrator to authenticate... <Limit CUPS-Add-Modify-Printer CUPS-Delete-Printer CUPS-Add-Modify-Class CUPS-Delete-Class CUPS-Set-Default> AuthType Default Require user @SYSTEM Order deny,allow </Limit> # All printer operations require a printer operator to authenticate... <Limit Pause-Printer Resume-Printer Enable-Printer Disable-Printer Pause-Printer-After-Current-Job Hold-New-Jobs Release-Held-New-Jobs Deactivate-Printer Activate-Printer Restart-Printer Shutdown-Printer Startup-Printer Promote-Job Schedule-Job-After Cancel-Jobs CUPS-Accept-Jobs CUPS-Reject-Jobs> AuthType Default Require user @SYSTEM Order deny,allow </Limit> # Only the owner or an administrator can cancel or authenticate a job... <Limit Cancel-Job CUPS-Authenticate-Job> AuthType Default Require user @OWNER @SYSTEM Order deny,allow </Limit> <Limit All> Order deny,allow </Limit> </Policy>

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  • SQL SERVER – SmallDateTime and Precision – A Continuous Confusion

    - by pinaldave
    Some kinds of confusion never go away. Here is one of the ancient confusing things in SQL. The precision of the SmallDateTime is one concept that confuses a lot of people, proven by the many messages I receive everyday relating to this subject. Let me start with the question: What is the precision of the SMALLDATETIME datatypes? What is your answer? Write it down on your notepad. Now if you do not want to continue reading the blog post, head to my previous blog post over here: SQL SERVER – Precision of SMALLDATETIME. A Social Media Question Since the increase of social media conversations, I noticed that the amount of the comments I receive on this blog is a bit staggering. I receive lots of questions on facebook, twitter or Google+. One of the very interesting questions yesterday was asked on Facebook by Raghavendra. I am re-organizing his script and asking all of the questions he has asked me. Let us see if we could help him with his question: CREATE TABLE #temp (name VARCHAR(100),registered smalldatetime) GO DECLARE @test smalldatetime SET @test=GETDATE() INSERT INTO #temp VALUES ('Value1',@test) INSERT INTO #temp VALUES ('Value2',@test) GO SELECT * FROM #temp ORDER BY registered DESC GO DROP TABLE #temp GO Now when the above script is ran, we will get the following result: Well, the expectation of the query was to have the following result. The row which was inserted last was expected to return as first row in result set as the ORDER BY descending. Side note: Because the requirement is to get the latest data, we can’t use any  column other than smalldatetime column in order by. If we use name column in the order by, we will get an incorrect result as it can be any name. My Initial Reaction My initial reaction was as follows: 1) DataType DateTime2: If file precision of the column is expected from the column which store date and time, it should not be smalldatetime. The precision of the column smalldatetime is One Minute (Read Here) for finer precision use DateTime or DateTime2 data type. Here is the code which includes above suggestion: CREATE TABLE #temp (name VARCHAR(100), registered datetime2) GO DECLARE @test datetime2 SET @test=GETDATE() INSERT INTO #temp VALUES ('Value1',@test) INSERT INTO #temp VALUES ('Value2',@test) GO SELECT * FROM #temp ORDER BY registered DESC GO DROP TABLE #temp GO 2) Tie Breaker Identity: There are always possibilities that two rows were inserted at the same time. In that case, you may need a tie breaker. If you have an increasing identity column, you can use that as a tie breaker as well. CREATE TABLE #temp (ID INT IDENTITY(1,1), name VARCHAR(100),registered datetime2) GO DECLARE @test datetime2 SET @test=GETDATE() INSERT INTO #temp VALUES ('Value1',@test) INSERT INTO #temp VALUES ('Value2',@test) GO SELECT * FROM #temp ORDER BY ID DESC GO DROP TABLE #temp GO Those two were the quick suggestions I provided. It is not necessary that you should use both advices. It is possible that one can use only DATETIME datatype or Identity column can have datatype of BIGINT or have another tie breaker. An Alternate NO Solution In the facebook thread this was also discussed as one of the solutions: CREATE TABLE #temp (name VARCHAR(100),registered smalldatetime) GO DECLARE @test smalldatetime SET @test=GETDATE() INSERT INTO #temp VALUES ('Value1',@test) INSERT INTO #temp VALUES ('Value2',@test) GO SELECT name, registered, ROW_NUMBER() OVER(ORDER BY registered DESC) AS "Row Number" FROM #temp ORDER BY 3 DESC GO DROP TABLE #temp GO However, I believe it is not the solution and can be further misleading if used in a production server. Here is the example of why it is not a good solution: CREATE TABLE #temp (name VARCHAR(100) NOT NULL,registered smalldatetime) GO DECLARE @test smalldatetime SET @test=GETDATE() INSERT INTO #temp VALUES ('Value1',@test) INSERT INTO #temp VALUES ('Value2',@test) GO -- Before Index SELECT name, registered, ROW_NUMBER() OVER(ORDER BY registered DESC) AS "Row Number" FROM #temp ORDER BY 3 DESC GO -- Create Index ALTER TABLE #temp ADD CONSTRAINT [PK_#temp] PRIMARY KEY CLUSTERED (name DESC) GO -- After Index SELECT name, registered, ROW_NUMBER() OVER(ORDER BY registered DESC) AS "Row Number" FROM #temp ORDER BY 3 DESC GO DROP TABLE #temp GO Now let us examine the resultset. You will notice that an index which is created on the base table which is (indeed) schema change the table but can affect the resultset. As you can see, an index can change the resultset, so this method is not yet perfect to get the latest inserted resultset. No Schema Change Requirement After giving these two suggestions, I was waiting for the feedback of the asker. However, the requirement of the asker was there can’t be any schema change because the application was used by many other applications. I validated again, and of course, the requirement is no schema change at all. No addition of the column of change of datatypes of any other columns. There is no further help as well. This is indeed an interesting question. I personally can’t think of any solution which I could provide him given the requirement of no schema change. Can you think of any other solution to this? Need of Database Designer This question once again brings up another ancient question:  “Do we need a database designer?” I often come across databases which are facing major performance problems or have redundant data. Normalization is often ignored when a database is built fast under a very tight deadline. Often I come across a database which has table with unnecessary columns and performance problems. While working as Developer Lead in my earlier jobs, I have seen developers adding columns to tables without anybody’s consent and retrieving them as SELECT *.  There is a lot to discuss on this subject in detail, but for now, let’s discuss the question first. Do you have any suggestions for the above question? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: CodeProject, Developer Training, PostADay, SQL, SQL Authority, SQL DateTime, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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  • Is it legal to ask photo ID and credit card copy in the U.S

    - by selim
    I regularly order from online shops around the world and I have not see any case where the company asks for photo ID or credit card copy. Yesterday I make an order from linode.com and my order is on hold because of their "fraud check system". Is it common to ask those info in U.S. where I have never asked such info in here (Istanbul, Turkey). And I already asked what is their motive and legal stand and the reason my order is hold by their fraud system. And I also added whether is because I live in Istanbul, Turkey. Their answer was as following: "We would not be able to disclose specific information related to our fraud system." And I'm asked repeatedly whether I want to cancel my order or not. I dont questioning reputation of linode.com if I think so, I did not make an order. I think asking for photo ID is neither legal nor provide any security.

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  • PHP: How do I loop through every XML file in a directory?

    - by celebritarian
    Hi! I'm building a simple application. It's a user interface to an online order system. Basically, the system is going to work like this: Other companies upload their purchase orders to our FTP server. These orders are simple XML files (containing things like customer data, address information, ordered products and the quantities…) I've built a simple user interface in HTML5, jQuery and CSS — all powered by PHP. PHP reads the content of an order (using the built-in features of SimpleXML) and displays it on the web page. So, it's a web app, supposed to always be running in a browser at the office. The PHP app will display the content of all orders. Every fifteen minutes or so, the app will check for new orders. How do I loop through all XML files in a directory? Right now, my app is able to read the content of a single XML file, and display it in a nice way on the page. My current code looks like this: // pick a random order that I know exists in the Order directory: $xml_file = file_get_contents("Order/6366246.xml",FILE_TEXT); $xml = new SimpleXMLElement($xml_file); // start echo basic order information, like order number: echo $xml->OrderHead->ShopPO; // more information about the order and the customer goes here… echo "<ul>"; // loop through each order line, and echo all quantities and products: foreach ($xml->OrderLines->OrderLine as $orderline) { echo "<tr>\n". "<li>".$orderline->Quantity." st.</li>\n". "<li>".$orderline->SKU."</li>\n"; } echo "</ul>"; // more information about delivery options, address information etc. goes here… So, that's my code. Pretty simple. It only needs to do one thing — print out the content of all order files on the screen — so me and my colleagues can see the order, confirm it and deliver it. That's it. But right now — as you can see — I'm selecting one single order at a time, located in the Order directory. But how do I loop through the entire Order directory, and read aand display the content of each order (like above)? I'm stuck. I don't really know how you get all (xml) files in a directory and then do something with the files (like reading them and echo out the data, like I want to). -- I'd really appreciate some help. I'm not very experienced with PHP/server-side programming, so if you could help me out here I'd be very grateful. Thanks a lot in advance! // Björn (celebritarian at me dot com)

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  • Do I need to compile my solution with VS2010 in order to benefit from .NET 4.0 new Code Access Secur

    - by leo
    Hello, I currently develop an application in C# with framework .NET 3.5 SP1. In my app, I have satellite assemblies which are not in the same folder as the exe, and that causes me some trouble with FullTrust, as explained here. In order to solve that problem, I wish to use .NET 4.0 whose Code Access Security Policy should allow my satellite assemblies to be FullyTrusted. So my question is: is just installing the framework enough, or do I need to rebuild the solution with VS2010? Thanks

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  • What is the best way to add and order to Doctrine Nested Set Trees?

    - by murze
    What is the best way to add a sense of order in Doctrine Nested Sets? The documention contains several examples of how to get al the childeren of a specific node $category->getNode()->getSiblings() But how can I for example: change the position of the fourth sibling to the second position get only the second sibling add a sibling between the second and third child etc... Do I have to manually add and ordercolumn to the model to do these operations?

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  • jquery multiple ajax check for all done? (order not important)

    - by second
    Is there a neat way to make sure a bunch of ajax callbacks have all finished? They don't need to be executed in order, i just need all the data to be there. one idea is to have them all increment a counter on completion and check if counter == countMax, but that seems ugly. Also, are there sync issues? (from simultaneous read/write to the counter)

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  • Does the order of columns matter in a group by clause?

    - by Jeff Meatball Yang
    If I have two columns, one with very high cardinality and one with very low cardinality (unique # of values), does it matter in which order I group by? Here's an example: select dimensionName, dimensionCategory, sum(someFact) from SomeFact f join SomeDim d on f.dimensionKey = d.dimensionKey group by d.dimensionName, -- large number of unique values d.dimensionCategory -- small number of unique values Are there situations where it matters?

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  • Does a HashMap retain the order of its elements on the next read if it is constructed as a LinkedHas

    - by javanix
    Suppose I have a Java method that returns a HashMap object. Because a LinkedHashMap is a subclass of HashMap, I can return a LinkedHashMap from this method just fine. On the next "read" action (no adding/removing/modifying of K/V pairs), would iterating over the keys of the resulting method (which returns a HashMap) go in the same order as the originating LinkedHashMap, even though the HashMap lacks the key links?

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