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  • String generator issue

    - by Andrey
    I want to write a method which returns a string. So far so good. The creation of the string however is quite complicated. I have 3 string lists - the first one has 155 entries, the second one - 9, the third one 21. I want my method if called enough times(155*9*21) to return all the possible combinations of values from the 3 lists (basically this method should keep count on how many times it was called and return only one combination each time). Any ideas how to accomplish that? I have 155*9*22 possible combinations. The first time the method is called it should take List1(0), List2(0), List3(0). After that in the next 21 iterations, the index of the third list is only changed. Once all the elements from the third list have been used increment the index of the second list and so on. Once the method has produced all the possible combinations (155*9*22) I want it to start from the beginning.

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  • ID generator with local static variable - thread-safe?

    - by Poseidon
    Will the following piece of code work as expected in a multi-threaded scenario? int getUniqueID() { static int ID=0; return ++ID; } It's not necessary that the IDs to be contiguous - even if it skips a value, it's fine. Can it be said that when this function returns, the value returned will be unique across all threads?

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  • How to implemenet Password Resets

    - by Sanju
    Hi, I have an existing application that i want to implement password resets after 30 days. But i dont want the user to use the same password as the last 5 times. How do i go about doing this or is there any links i can follow. Please help Thanks,

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  • Special simple random number generator

    - by psihodelia
    How to create a function, which on every call generates a random integer number? This number must be most random as possible (according to uniform distribution). It is only allowed to use one static variable and at most 3 elementary steps, where each step consists of only one basic arithmetic operation of arity 1 or 2. Example: int myrandom(void){ static int x; x = some_step1; x = some_step2; x = some_step3; return x; } Basic arithmetic operations are +,-,%,and, not, xor, or, left shift, right shift, multiplication and division. Of course, no rand(), random() or similar staff is allowed.

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  • how to store username password in device memory

    - by ranjanarr
    How to store username password in device memory. Even after the user closes the application and returns back , he should be able to authenticate his username and password. Right now I am testing in Eclipse... so please help me with some pointers/links which will allow me to test in Eclipse and eventually run on Mobile.

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  • Metamorphic generator

    - by user222094
    I am trying to find references about different designs of metamorphic generators can someone point me to the right direction. I have gone through some papers in ACM but couldn't find what I am looking for.

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  • SSH hangs without password prompt

    - by Wilco
    Just reinstalled OS X and for some reason I now cannot connect to a specific machine on my local network via SSH. I can SSH to other machines on the network without any problems, and other machines can SSH to the problematic one as well. I'm not sure where to start looking for problems - can anyone point me in the right direction? Here's a dump of a connection attempt: OpenSSH_5.1p1, OpenSSL 0.9.7l 28 Sep 2006 debug1: Reading configuration data /etc/ssh_config debug1: Connecting to 10.0.1.7 [10.0.1.7] port 22. debug1: Connection established. debug1: identity file /Users/nwilliams/.ssh/identity type -1 debug1: identity file /Users/nwilliams/.ssh/id_rsa type -1 debug1: identity file /Users/nwilliams/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_4.5 debug1: match: OpenSSH_4.5 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.1 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-cbc hmac-md5 none debug1: kex: client->server aes128-cbc hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host '10.0.1.7' is known and matches the RSA host key. debug1: Found key in /Users/nwilliams/.ssh/known_hosts:1 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi-with-mic,password,keyboard-interactive debug1: Next authentication method: gssapi-keyex debug1: No valid Key exchange context debug1: Next authentication method: gssapi-with-mic ... at this point it hangs for quite a while, and then resumes ... debug1: Unspecified GSS failure. Minor code may provide more information Server not found in Kerberos database debug1: Unspecified GSS failure. Minor code may provide more information Server not found in Kerberos database debug1: Unspecified GSS failure. Minor code may provide more information debug1: Next authentication method: publickey debug1: Trying private key: /Users/nwilliams/.ssh/identity debug1: Trying private key: /Users/nwilliams/.ssh/id_rsa debug1: Trying private key: /Users/nwilliams/.ssh/id_dsa debug1: Next authentication method: keyboard-interactive

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  • OSX Server 10.5 - Cannot log into Workgroup Manager - diradmin password is correct

    - by Mister IT Guru
    I've got a setup where I am trying to rescue a broken AD. We can no longer authenticate on the Workgroup manager, with passwords being rejected all the time - even though it is correct. I can connect using the workgroup manager on another server and I get the user list as expected, but when I click the padlock to make changes, I get the following screen: The problem is, I know the password is correct, I just used it to connect to the server in the first place. I can log into the server using the local admin, and services such as AFP, VPN and SMB continue to serve users. I have about 300 or so users on this server, and I would very much like to avoid having a rebuild. As there is much configuration that has been done without my knowledge (it's a client machine), I'd like to attempt to fix it, and then create another server and migration OD off this broken machine, then decommission it "gently". Ultimately this would mean no disruption of services. What I'd like it some tips as to how to fix the problem with authenticating to make changes in the work group manager, and maintenance on open directory in general. Thanks

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  • Exclamation 403 forbidden for cgi-bin/ and cannot protect site with password

    - by gasgdasdgasdg
    First problem i have is i am getting 403 forbidden error for cgi-bin/ I have created a new /var/www2/ i can access it fine. php runs fine. Second problem is I cannot password protect it. i first tried doing htpasswd, it asks for login but everytime i login it keeps asking for new one. its getting frustrating, i have tried all tricks. and doesn't seem to work. this is a virtual host config inside sites-available. httpd.conf is empty but i have apache2.conf Code: NameVirtualHost 12.12.12.12. <VirtualHost 12.12.12.12> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /var/www2/cgi-bin/ <Directory "/var/www2/cgi-bin/"> AllowOverride Options Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch AddHandler cgi-script cgi pl Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost>

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  • Subversion Edge LDAP (require CAC Certificate not Username and Password)

    - by Frank Hale
    What I've Done: I've successfully installed and configured Subversion Edge 3.1.2 with LDAP support on a Windows 2008 server. I have configured LDAP users and am able to use LDAP credentials to work on repositories just fine. No issues whatsoever. Works great! What I Want To Do: I've been searching for several hours now in hopes to find some information on how to configure Subversion Edge server to require client certificates for user authentication against an LDAP environment. I have not found anything yet that gives me an indication of how to do it. I know there are SVN clients that are capable of prompting for CAC certificates but I cannot figure out how to set my server up to require it. NOTE: CAC authentication is already setup and working in the windows environment. Desired Outcome: When running svn commands that require authentication against my Subversion Edge Server I want it to prompt me for my CAC certificate instead of my Active Directory username and password. If anyone has any information on this I'd greatly appreciate it. EDIT: I'm still digging so if I find out anything I'll update this question with what I found.

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  • ssh without password does not work for some users

    - by joshxdr
    I have a new RHEL4 Linux box that I am using to copy data to old Solaris 2.6 and RHEL3 Linux boxes with scp. I have found that with the same setup, it works for some users but not for others. For user jane, this works fine: jane@host1$ ssh -v remhost debug1: Next authentication method: publickey debug1: Trying private key: /mnt/home/osborjo/.ssh/identity debug1: Offering public key: /mnt/home/osborjo/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: read PEM private key done: type RSA debug1: Authentication succeeded (publickey). for user jack it does not: jack@host1 ssh -v remhost debug1: Next authentication method: publickey debug1: Trying private key: /mnt/home/oper1/.ssh/identity debug1: Offering public key: /mnt/home/oper1/.ssh/id_rsa debug1: Authentications that can continue: publickey,password,keyboard-interactive I have looked at the permissions for all the keys and files, they look the same. Since I am using home directories mounted by NFS, the keys for both the remote host and the local host are in the same directory. This is how things look for jane: jane@host1$ ls -l $HOME/.ssh -rw-rw-r-- 1 jane operator 394 Jan 27 16:28 authorized_keys -rw------- 1 jane operator 1675 Jan 27 16:27 id_rsa -rw-r--r-- 1 jane operator 394 Jan 27 16:27 id_rsa.pub -rw-rw-r-- 1 jane operator 1205 Jan 27 16:46 known_hosts For user jack: jack@host1$ ls -l $HOME/.ssh -rw-rw-r-- 1 jack engineer 394 Jan 27 16:28 authorized_keys -rw------- 1 jack engineer 1675 Jan 27 16:27 id_rsa -rw-r--r-- 1 jack engineer 394 Jan 27 16:27 id_rsa.pub -rw-rw-r-- 1 jack engineer 1205 Jan 27 16:46 known_hosts As a last ditch effort, I copied the authorized_keys, id_rsa, and id_rsa.pub from jill to jack, and changed the username in authorized_keys and id_rsa.pub with vi. It still did not work. It seems there is something different between the two users but I cannot figure out what it is.

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  • Correct MySQL username/password, but getting Access Denied error when run from script

    - by Nick
    I'm currently trying to run the following command from within a shell script. /usr/bin/mysql -u username -ppassword -h localhost database It works perfectly fine when executed manually, and not from within a script. When I try to execute a script that contains that command, I get the following error: ERROR 1045 (28000) at line 3: Access denied for user 'username'@'localhost' (using password: YES) I literally copied and pasted the working command into the script. Why the error? As a sidenote: the ultimate intent is to run the script with cron. EDIT: Here is a stripped down version of my script that I'm trying to run. You can ignore most of it up until the point where it connects to MySQL around line 19. #!/bin/sh #Run download script to download product data cd /home/dir/Scripts/Linux /bin/sh script1.sh #Run import script to import product data to MySQL cd /home/dir/Mysql /bin/sh script2.sh #Download inventory stats spreadsheet and rename it cd /home/dir /usr/bin/wget http://www.url.com/file1.txt mv file1.txt sheet1.csv #Remove existing export spreadsheet rm /tmp/sheet2.csv #Run MySQL queries in "here document" format /usr/bin/mysql -u username -ppassword -h localhost database << EOF --Drop old inventory stats table truncate table table_name1; --Load new inventory stats into table Load data local infile '/home/dir/sheet1.csv' into table table_name1 fields terminated by ',' optionally enclosed by '"' lines terminated by '\r\n'; --MySQL queries to combine product data and inventory stats here --Export combined data in spreadsheet format group by p.value into outfile '/tmp/sheet2.csv' fields terminated by ',' optionally enclosed by '"' lines terminated by '\r\n'; EOF EDIT 2: After some more testing, the issue is with the << EOF that is at the end of the command. This is there for the "here document". When removed, the command works fine. The problem is that I need << EOF there so that the MySQL queries will run.

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  • HP Power Manager SMTP setup doesn't have space for username & password

    - by Martha
    Is there some way to configure HP Power Manager to not assume that there's an email server running locally? We recently acquired an HP T1500 G3 UPS, which we're trying to control using HP Power Manager 4.2. The main reason we wanted to get this particular UPS is because it says it's capable of sending notifications (of the "Yo, the power's out, you may want to look into it" type) via email, as opposed to SNMP. Turns out, that's not entirely true. The server is running Windows Server 2003. It is not running an email server of any sort - we do that via two different providers. Outlook email is provided by Verizon, and our SMTP email service is provided by a small local company. When we use CDO to send auto-generated notification emails, we have to provide the SMTP server name, port, username, and password. The HP Power Manager interface only allows us to enter the server name and the username. Thus, not surprisingly, the emails never go anywhere. Help?

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  • Exclamation 403 forbidden for cgi-bin/ and cannot protect site with password

    - by gasgdasdgasdg
    First problem i have is i am getting 403 forbidden error for cgi-bin/ I have created a new /var/www2/ i can access it fine. php runs fine. Second problem is I cannot password protect it. i first tried doing htpasswd, it asks for login but everytime i login it keeps asking for new one. its getting frustrating, i have tried all tricks. and doesn't seem to work. this is a virtual host config inside sites-available. httpd.conf is empty but i have apache2.conf Code: NameVirtualHost 12.12.12.12. <VirtualHost 12.12.12.12> ServerAdmin webmaster@localhost DocumentRoot /var/www2/ <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www2/> Options Indexes FollowSymLinks MultiViews AllowOverride None Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /var/www2/cgi-bin/ <Directory "/var/www2/cgi-bin/"> AllowOverride Options Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch AddHandler cgi-script cgi pl Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined ServerSignature On Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost>

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  • 40k Event Log Errors an hour Unknown Username or bad password

    - by ErocM
    I am getting about 200k of these an hour: An account failed to log on. Subject: Security ID: SYSTEM Account Name: TGSERVER$ Account Domain: WORKGROUP Logon ID: 0x3e7 Logon Type: 4 Account For Which Logon Failed: Security ID: NULL SID Account Name: administrator Account Domain: TGSERVER Failure Information: Failure Reason: Unknown user name or bad password. Status: 0xc000006d Sub Status: 0xc0000064 Process Information: Caller Process ID: 0x334 Caller Process Name: C:\Windows\System32\svchost.exe Network Information: Workstation Name: TGSERVER Source Network Address: - Source Port: - Detailed Authentication Information: Logon Process: Advapi Authentication Package: Negotiate Transited Services: - Package Name (NTLM only): - Key Length: 0 This event is generated when a logon request fails. It is generated on the computer where access was attempted. The Subject fields indicate the account on the local system which requested the logon. This is most commonly a service such as the Server service, or a local process such as Winlogon.exe or Services.exe. The Logon Type field indicates the kind of logon that was requested. The most common types are 2 (interactive) and 3 (network). The Process Information fields indicate which account and process on the system requested the logon. The Network Information fields indicate where a remote logon request originated. Workstation name is not always available and may be left blank in some cases. The authentication information fields provide detailed information about this specific logon request. - Transited services indicate which intermediate services have participated in this logon request. - Package name indicates which sub-protocol was used among the NTLM protocols. - Key length indicates the length of the generated session key. This will be 0 if no session key was requested. On my server... I changed my adminstrative username to something else and since then I've been inidated with these messages. I found on http://technet.microsoft.com/en-us/library/cc787567(v=WS.10).aspx that the 4 means "Batch logon type is used by batch servers, where processes may be executing on behalf of a user without their direct intervention." which really doesn't shed any light on it for me. I checked the services and they are all logging in as local system or network service. Nothing for administrator. Anyone have any idea how I tell where these are coming from? I would assume this is a program that is crapping out... Thanks in advance!

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  • X509Certificate.CreateFromCertFile - the specified network password is not correct

    - by pcampbell
    I have a .NET application that I want to use as a client to call an SSL SOAP web service. I have been supplied with a valid client certificate called foo.pfx. There is a password on the certificate itself. I've located the certificate at the following location: C:\certs\foo.pfx To call the web service, I need to attach the client certificate. Here's the code: public X509Certificate GetCertificateFromDisk(){ try{ string certPath = ConfigurationManager.AppSettings["MyCertPath"].ToString(); //this evaluates to "c:\\certs\\foo.pfx". So far so good. X509Certificate myCert = X509Certificate.CreateFromCertFile(certPath); // exception is raised here! "The specified network password is not correct" return cert; } catch (Exception ex){ throw; } } It sounds like the exception is around the .NET application trying to read the disk. The method CreateFromCertFile is a static method that should create a new instance of X509Certificate. The method isn't overridden, and has only one argument: the path. When I inspect the Exception, I find this: _COMPlusExceptionCode = -532459699 Source=mscorlib Question: does anyone know what the cause of the exception "The specified network password is not correct" ?

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  • SCons does not clean all files

    - by meowsqueak
    I have a file system containing directories of "builds", each of which contains a file called "build-info.xml". However some of the builds happened before the build script generated "build-info.xml" so in that case I have a somewhat non-trivial SCons SConstruct that is used to generate a skeleton build-info.xml so that it can be used as a dependency for further rules. I.e.: for each directory: if build-info.xml already exists, do nothing. More importantly, do not remove it on a 'scons --clean'. if build-info.xml does not exist, generate a skeleton one instead - build-info.xml has no dependencies on any other files - the skeleton is essentially minimal defaults. during a --clean, remove build-info.xml if it was generated, otherwise leave it be. My SConstruct looks something like this: def generate_actions_BuildInfoXML(source, target, env, for_signature): cmd = "python '%s/bin/create-build-info-xml.py' --version $VERSION --path . --output ${TARGET.file}" % (Dir('#').abspath,) return cmd bld = Builder(generator = generate_actions_BuildInfoXML, chdir = 1) env.Append(BUILDERS = { "BuildInfoXML" : bld }) ... # VERSION = some arbitrary string, not important here # path = filesystem path, set elsewhere build_info_xml = "%s/build-info.xml" % (path,) if not os.path.exists(build_info_xml): env.BuildInfoXML(build_info_xml, None, VERSION = build) My problem is that 'scons --clean' does not remove the generated build-info.xml files. I played around with env.Clean(t, build_info_xml) within the 'if' but I was unable to get this to work - mainly because I could not work out what to assign to 't' - I want a generated build-info.xml to be cleaned unconditionally, rather than based on the cleaning of another target, and I wasn't able to get this to work. If I tried a simple env.Clean(None, "build_info_xml") after but outside the 'if' I found that SCons would clean every single build-info.xml file including those that weren't generated. Not good either. What I'd like to know is how SCons goes about determining which files should be cleaned and which should not. Is there something funny about the way I've used a generator function that prevents SCons from recording this target as a Clean candidate?

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  • Windows server 2003 default administrator password

    - by Jason Baker
    Sorry if this is an overly simplistic question, but I'm a bit stuck here. :) I need a windows machine for me to do some programming for class. Since I have my Macbook with me everywhere I go, I figured that it would be easiest to install a vm. And since I can get a copy of Windows server 2k3 for free via dreamspark, I thought I'd try to do that. Here's what happened though: I installed windows server (disk one). When the system booted up, vmware automatically installed VMWare tools and prompted me to restart. There was also a prompt to start the installation of disc 2, but I figured it would be better to restart before doing that. When the machine came back up, I was prompted to log in as the administrator. The problem is that I wasn't prompted to make an administrator account or password. Is there a default password I can use? I've tried all the obvious ones (blank, password, etc) and googling, but I didn't come up with anything.

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  • ASP.NET Membership ChangePassword control - Need to check for previous password

    - by Steve
    Hi guys, I have a new table that hold old passwords, I need to check if there is a match. If there is a match I need the ChangePassword contol to NOT change the password. I need to tell the user that this password was used and pic a new one. I can't seem to be able to interrupt the control from changing the password. Maybe I am using the wrong event. Here is a piece of my code, or how I wish it would work. I appreciate all your help. protected void ChangePassword1_ChangedPassword(object sender, EventArgs e) { MembershipUser user = Membership.GetUser(); string usrName = ""; if (user != null) { string connStr = ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString; SqlConnection mySqlConnection = new SqlConnection(connStr); SqlCommand mySqlCommand = mySqlConnection.CreateCommand(); mySqlCommand.CommandText = "Select UserName from OldPasswords where UserName = 'test'"; mySqlConnection.Open(); SqlDataReader mySqlDataReader = mySqlCommand.ExecuteReader(CommandBehavior.Default); while (mySqlDataReader.Read()) { usrName = mySqlDataReader["UserName"].ToString(); if (usrName == user.ToString()) { Label1.Text = "Match"; } else { Label1.Text = "NO Match!"; } }

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  • C# Active Directory - Check username / password

    - by Michael G
    I'm using the following code on Windows Vista Ultimate SP1 to query our active directory server to check the user name and password of a user on a domain. public Object IsAuthenticated() { String domainAndUsername = strDomain + @"\" + strUser; DirectoryEntry entry = new DirectoryEntry(_path, domainAndUsername, strPass); SearchResult result; try { //Bind to the native AdsObject to force authentication. DirectorySearcher search = new DirectorySearcher(entry) { Filter = ("(SAMAccountName=" + strUser + ")") }; search.PropertiesToLoad.Add("givenName"); // First Name search.PropertiesToLoad.Add("sn"); // Last Name search.PropertiesToLoad.Add("cn"); // Last Name result = search.FindOne(); if (null == result) { return null; } //Update the new path to the user in the directory. _path = result.Path; _filterAttribute = (String)result.Properties["cn"][0]; } catch (Exception ex) { return new Exception("Error authenticating user. " + ex.Message); } return user; } the target is using .NET 3.5, and compiled with VS 2008 standard I'm logged in under a domain account that is a domain admin where the application is running. The code works perfectly on windows XP; but i get the following exception when running it on Vista: System.DirectoryServices.DirectoryServicesCOMException (0x8007052E): Logon failure: unknown user name or bad password. at System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail) at System.DirectoryServices.DirectoryEntry.Bind() at System.DirectoryServices.DirectoryEntry.get_AdsObject() at System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne) at System.DirectoryServices.DirectorySearcher.FindOne() at Chain_Of_Custody.Classes.Authentication.LdapAuthentication.IsAuthenticated() at System.DirectoryServices.DirectoryEntry.Bind(Boolean throwIfFail) at System.DirectoryServices.DirectoryEntry.Bind() at System.DirectoryServices.DirectoryEntry.get_AdsObject() at System.DirectoryServices.DirectorySearcher.FindAll(Boolean findMoreThanOne) at System.DirectoryServices.DirectorySearcher.FindOne() at Chain_Of_Custody.Classes.Authentication.LdapAuthentication.IsAuthenticated() I've tried changing the authentication types, I'm not sure what's going on. See also: http://stackoverflow.com/questions/290548/c-validate-a-username-and-password-against-active-directory

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  • 48-bit bitwise operations in Javascript?

    - by randomhelp
    I've been given the task of porting Java's Java.util.Random() to JavaScript, and I've run across a huge performance hit/inaccuracy using bitwise operators in Javascript on sufficiently large numbers. Some cursory research states that "bitwise operators in JavaScript are inherently slow," because internally it appears that JavaScript will cast all of its double values into signed 32-bit integers to do the bitwise operations (see https://developer.mozilla.org/En/Core_JavaScript_1.5_Reference/Operators/Bitwise_Operators for more on this.) Because of this, I can't do a direct port of the Java random number generator, and I need to get the same numeric results as Java.util.Random(). Writing something like this.next = function(bits) { if (!bits) { bits = 48; } this.seed = (this.seed * 25214903917 + 11) & ((1 << 48) - 1); return this.seed >>> (48 - bits); }; (which is an almost-direct port of the Java.util.Random()) code won't work properly, since Javascript can't do bitwise operations on an integer that size.) I've figured out that I can just make a seedable random number generator in 32-bit space using the Lehmer algorithm, but the trick is that I need to get the same values as I would with Java.util.Random(). What should I do to make a faster, functional port?

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  • django: cannot import settings, cannot login to admin, cannot change admin password

    - by xpanta
    Hi, It seems that I am completely lost here. Yesterday I noticed that I cannot login to the admin panel (don't use it much, so it's been some weeks since last login). I thought that I might have changed the admin password and now I can't remember it (though I doubt it). I tried django-admin.py changepassword (using django 1.2.1) but it said that 'changepassword' is unknown command (I have all the necessary imports in my settings.py. Admin interface used to work ok). Then I gave a django-admin.py validate. Then the hell begun. django-admin.py validate gave me this error: Error: Settings cannot be imported, because environment variable DJANGO_SETTINGS_MODULE is undefined. I then gave a set DJANGO_SETTINGS_MODULE=myproject.settings and then again a django-admin.py validate This is what I get now: Error: Could not import settings 'myproject.settings' (Is it on sys.path? Does it have syntax errors?): No module named myproject.settings and now I am lost. I tried django console and sys.path.append('c:\workspace') or sys.append('c:\workspace\myproject') but still get the same errors. I use windows 7 and my project dir is c:\workspace. I don't use a PYTHONPATH variable (although I tried setting it temporarily to C:\workspace but I still get the same error). I don't use Apache, just the django development server. What am I doing wrong? My web page works fine. I think that the fact that I can't login as admin is related to the previous import error, no? PS: I also tried this: http://coderseye.com/2007/howto-reset-the-admin-password-in-django.html but still I couldn't change admin password for some reason. Although I could create another admin user (with which I couldn't login).

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  • Generate an ID via COM interop

    - by Erik van Brakel
    At the moment, we've got an unmaintanable ball of code which offers an interface to a third party application. The third party application has a COM assembly which MUST be used to create new entries. This process involves two steps: generate a new object (basically an ID), and update that object with new field values. Because COM interop is so slow, we only use that to generate the ID (and related objects) in the database. The actual update is done using a regular SQL query. What I am trying to figure out if it's possible to use NHibernate to do some of the heavy lifting for us, without bypassing the COM assembly. Here's the code for saving something to the database as I envision it: using(var s = sessionFactory.OpenSession()) using(var t = s.BeginTransaction()) { MyEntity entity = new MyEntity(); s.Save(entity); t.Commit(); } Regular NH code I'd say. Now, this is where it gets tricky. I think I have to supply my own implementation of NHibernate.Id.IIdentifierGenerator which calls the COM assembly in the Generate method. That's not a problem. What IS a problem is that the COM assembly requires initialisation, which does take a bit of time. It also doesn't like multiple instances in the same process, for some reason. What I would like to know is if there's a way to properly access an external service in the generator code. I'm free to use any technique I want, so if it involves something like an IoC container that's no problem. The thing I am looking for is where exactly to hook-up my code so I can access the things I need in my generator, without having to resort to using singletons or other nasty stuff.

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  • Recognizing terminals in a CFG production previously not defined as tokens.

    - by kmels
    I'm making a generator of LL(1) parsers, my input is a CoCo/R language specification. I've already got a Scanner generator for that input. Suppose I've got the following specification: COMPILER 1. CHARACTERS digit="0123456789". TOKENS number = digit{digit}. decnumber = digit{digit}"."digit{digit}. PRODUCTIONS Expression = Term{"+"Term|"-"Term}. Term = Factor{"*"Factor|"/"Factor}. Factor = ["-"](Number|"("Expression")"). Number = (number|decnumber). END 1. So, if the parser generated by this grammar receives a word "1+1", it'd be accepted i.e. a parse tree would be found. My question is, the character "+" was never defined in a token, but it appears in the non-terminal "Expression". How should my generated Scanner recognize it? It would not recognize it as a token. Is this a valid input then? Should I add this terminal in TOKENS and then consider an error routine for a Scanner for it to skip it? How does usual language specifications handle this?

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