Search Results

Search found 15859 results on 635 pages for 'xml authoring'.

Page 54/635 | < Previous Page | 50 51 52 53 54 55 56 57 58 59 60 61  | Next Page >

• xml vs java LinearLayout fills

  - by user293443

  the xml version below properly handles height and width and the java doesn't what is the java missing? xml <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_height="fill_parent" android:layout_width="fill_parent" android:orientation="horizontal"> <include android:id="@+id/cell1" layout="@layout/grid_text_view" /> <include android:id="@+id/cell2" layout="@layout/grid_text_view" /> </LinearLayout> java LinearLayout ll = new LinearLayout(this); ll.setOrientation(LinearLayout.HORIZONTAL); ll.setLayoutParams(new LayoutParams(LayoutParams.FILL_PARENT, LayoutParams.FILL_PARENT)); ll.addView((TextView)this.getLayoutInflater().inflate(R.layout.grid_text_view, null)); ll.addView((TextView)this.getLayoutInflater().inflate(R.layout.grid_text_view, null)); setContentView(ll); grid_text_view <TextView xmlns:android="http://schemas.android.com/apk/res/android" android:layout_height="fill_parent" android:layout_width="0dip" android:text="1" android:textSize="20sp" android:gravity="center" android:layout_weight="1" /> I've tried a ll.invalidate() and it didn't work either? :( screenshots at http://www.flickr.com/photos/48409507@N06/sets/72157623618407586/

  Read the article

• Serializing a DataType="time" field using XmlSerializer

  - by CraftyFella

  Hi, I'm getting an odd result when serializing a DateTime field using XmlSerializer. I have the following class: public class RecordExample { [XmlElement("TheTime", DataType = "time")] public DateTime TheTime { get; set; } [XmlElement("TheDate", DataType = "date")] public DateTime TheDate { get; set; } public static bool Serialize(Stream stream, object obj, Type objType, Encoding encoding) { try { using (var writer = XmlWriter.Create(stream, new XmlWriterSettings { Encoding = encoding })) { var xmlSerializer = new XmlSerializer(objType); if (writer != null) xmlSerializer.Serialize(writer, obj); } return true; } catch (Exception) { return false; } } } When i call the use the XmlSerializer with the following testing code: var obj = new RecordExample {TheDate = DateTime.Now.Date, TheTime = new DateTime(0001, 1, 1, 12, 00, 00)}; var ms = new MemoryStream(); RecordExample.Serialize(ms, obj, typeof (RecordExample), Encoding.UTF8); txtSource2.Text = Encoding.UTF8.GetString(ms.ToArray()); I get some strange results, here's the xml that is produced: <?xml version="1.0" encoding="utf-8"?> <RecordExample xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <TheTime>12:00:00.0000000+00:00</TheTime> <TheDate>2010-03-08</TheDate> </RecordExample> Any idea's how i can get the "TheTime" element to contain a time which looks more like this: <TheTime>12:00:00.0Z</TheTime> ...as that's what i was expecting? Thanks Dave

  Read the article

• PHP: Need help with simple XML

  - by Jack

  I am beginner in PHP. I am trying to parse this xml file. <relationship> <target> <following type="boolean">true</following> <followed_by type="boolean">true</followed_by> <screen_name>xxxx</screen_name> <id type="integer">xxxx</id> </target> <source> <notifications_enabled nil="true"/> <following type="boolean">true</following> <blocking nil="true"/> <followed_by type="boolean">true</followed_by> <screen_name>xxxx</screen_name> <id type="integer">xxxxx</id> </source> </relationship> I need to get the value of the field 'following type="boolean" ' for the target and here's my code - $xml = simplexml_load_string($response); foreach($xml->children() as $child) { if ($child->getName() == 'target') { foreach($child->children() as $child_1) if ( $child_1->getName() == 'following') { $is_my_friend = (bool)$child_1; break; } break; } } but I am not getting the correct output. I think the ' type="boolean" ' part of the field is creating problems. Please help.

  Read the article

• How do I write unescaped XML outside of a CDATA

  - by kazanaki

  Hello I am trying to write XML data using Stax where the content itself is HTML If I try xtw.writeStartElement("contents"); xtw.writeCharacters("<b>here</b>"); xtw.writeEndElement(); I get this <contents>&lt;b&gt;here&lt;/b&gt;</contents> Then I notice the CDATA method and change my code to: xtw.writeStartElement("contents"); xtw.writeCData("<b>here</b>"); xtw.writeEndElement(); and this time the result is <contents><![CDATA[<b>here</b>]]></contents> which is still not good. What I really want is <contents><b>here</b></contents> So is there an XML API/Library that allows me to write raw text without being in a CDATA section? So far I have looked at Stax and JDom and they do not seem to offer this. In the end I might resort to good old StringBuilder but this would not be elegant. Update I agree mostly with the answers so far. However instead of <b>here</b> I could have a 1MB HTML document that I want to embed in a bigger XML document. What you suggest means that I have to parse this HTML document in order to understand its structure. I would like to avoid this if possible.

  Read the article

• XmlAttribute/XmlText cannot be used to encode complex type

  - by Conrad C

  I want to serialize a class Ticket into xml. I get the error :"XmlAttribute/XmlText cannot be used to encode complex type" because of my customfield class. This is how the xml for customfields should look like ( the attribute array is nesseray but I don't understand how to create it): <custom_fields type="array"> <custom_field name="Standby Reason" id="6"> <value/> </custom_field> <custom_field name="Close Date" id="84"> Class Ticket public class Ticket { [XmlElement("custom_fields")] public CustomFields Custom_fields { get; set; } Class CustomFields [Serializable] public class CustomFields { [XmlAttribute("array")] public List<CustomField> custom_field { get; set; } Class CustomField [Serializable] public class CustomField { [XmlIgnore] public string Name { get; set; } [XmlElement] public int Id { get; set; } [XmlElement] public string Value { get; set; }

  Read the article

• Creating XML problem using c#

  - by Pankaj

  I am searching a batter solution for creating xml through xml serialization. What i need, i have a given format like this <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <note>!--note 1---</note> <note>!--note 2--</note> ...... </notes> </product> what i am doing here, i created a 2 classes like this public class product { [XmlElement("name")] public string Name { get; set; } [XmlArray("notes")] public List<notes> ListNotes { get; set; } } public class notes { [XmlIgnore] public string Note { get; set; } } when i am serializing this then i am getting xml in this formate <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <notes> <note>!--note 1---</note> <note>!--note 2--</note> </notes> </notes> </product> i don't want extra . Any batter solution to solve this problem? Thanks

  Read the article

• How to configure Eclipse XML formatting?

  - by tputkonen

  I would like to change the way Eclipse formats XML files. For example, if I have in pom.xml file a section as follows: <dependency> <groupId>junit</groupId> <artifactId>junit</artifactId> <version>3.8.1</version> <scope>test</scope> </dependency> After ctrl+shift+f it will look like: <dependency> <groupId> junit </groupId> <artifactId> junit </artifactId> <version> 3.8.1 </version> <scope> test </scope> </dependency> I prefer the first version, so how to configure Eclipse to format XML files to look like that?

  Read the article

• How to properly add newlines to an XML string in PHP?

  - by stormist

  I have some xml that I manually construct in a function that is something like: $xml = "<myxml>"; $xml .= "<items>"; $xml .= "<item1>blah</item1>"; $xml .= "</items>"; $xml .= "</myxml>"; When I output the string though I'd like the newlines to be present. How can I add this to the string without affecting a web service accepting the xml? Do newlines in XML even matter?

  Read the article

• SQL 2008 Querying Soap XML

  - by Vince

  I have been trying to process this SOAP XML return using SQL but all I get is NULL or nothing at all. I have tried different ways and pasted them all below. Declare @xmlMsg xml; Set @xmlMsg = '<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <SendWarrantyEmailResponse xmlns="http://Web.Services.Warranty/"> <SendWarrantyEmailResult xmlns="http://Web.Services.SendWarrantyResult"> <WarrantyNumber>120405000000015</WarrantyNumber> <Result>Cannot Send Email to anonymous account!</Result> <HasError>true</HasError> <MsgUtcTime>2012-06-07T01:11:36.8665126Z</MsgUtcTime> </SendWarrantyEmailResult> </SendWarrantyEmailResponse> </soap:Body> </soap:Envelope>'; declare @table table (data xml); insert into @table values (@xmlMsg); select data from @table; WITH xmlnamespaces ('http://schemas.xmlsoap.org/soap/envelope/' as [soap], 'http://Web.Services.Warranty' as SendWarrantyEmailResponse, 'http://Web.Services.SendWarrantyResult' as SendWarrantyEmailResult) SELECT Data.value('(/soap:Envelope[1]/soap:Body[1]/SendWarrantyEmailResponse[1]/SendWarrantyEmailResult[1]/WarrantyNumber[1])[1]','VARCHAR(500)') AS WarrantyNumber FROM @Table ; ;with xmlnamespaces('http://schemas.xmlsoap.org/soap/envelope/' as [soap],'http://Web.Services.Warranty' as SendWarrantyEmailResponse,'http://Web.Services.SendWarrantyResult' as SendWarrantyEmailResult) --select @xmlMsg.value('(/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult/WarrantyNumber)[0]', 'nvarchar(max)') --select T.N.value('.', 'nvarchar(max)') from @xmlMsg.nodes('/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult') as T(N) select @xmlMsg.value('(/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult/HasError)[1]','bit') as test ;with xmlnamespaces('http://schemas.xmlsoap.org/soap/envelope/' as [soap],'http://Web.Services.Warranty' as [SendWarrantyEmailResponse],'http://Web.Services.SendWarrantyResult' as [SendWarrantyEmailResult]) SELECT SendWarrantyEmailResult.value('WarrantyNumber[1]','varchar(max)') AS WarrantyNumber, SendWarrantyEmailResult.value('Result[1]','varchar(max)') AS Result, SendWarrantyEmailResult.value('HasError[1]','bit') AS HasError, SendWarrantyEmailResult.value('MsgUtcTime[1]','datetime') AS MsgUtcTime FROM @xmlMsg.nodes('/soap:Envelope/soap:Body/SendWarrantyEmailResponse/SendWarrantyEmailResult') SendWarrantyEmailResults(SendWarrantyEmailResult)

  Read the article

• XML-RPC over SSL with Ruby: end of file reached (EOFError)

  - by Michael Conigliaro

  Hello, I have some very simple Ruby code that is attempting to do XML-RPC over SSL: require 'xmlrpc/client' require 'pp' server = XMLRPC::Client.new2("https://%s:%d/" % [ 'api.ultradns.net', 8755 ]) pp server.call2('UDNS_OpenConnection', 'sponsor', 'username', 'password') The problem is that it always results in the following EOFError exception: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/net/protocol.rb:135:in `sysread': end of file reached (EOFError) So it appears that after doing the POST, I don't get anything back. Interestingly, this is the behavior I would expect if I tried to make an HTTP connection on the HTTPS port (or visa versa), and I actually do get the same exact exception if I change the protocol. Everything I've looked at indicates that using "https://" in the URL is enough to enable SSL, but I'm starting wonder if I've missed something. Note that Even though the credentials I'm using in the RPC are made up, I'm expecting to at least get back an XML error page (similar to if you access https://api.ultradns.net:8755/ with a web browser). I've tried running this code on OSX and Linux with the exact same result, so I have to conclude that I'm just doing something wrong here. Does anyone have any examples of doing XML-RPC over SSL with Ruby?

  Read the article

• Choose a XML node in SQL Server based on max value of a child element

  - by Jay

  I am trying to select from SQL Server 2005 XML datatype some values based on the max data that is located in a child node. I have multiple rows with XML similar to the following stored in a field in SQL Server: <user> <name>Joe</name> <token> <id>ABC123</id> <endDate>2013-06-16 18:48:50.111</endDate> </token> <token> <id>XYX456</id> <endDate>2014-01-01 18:48:50.111</endDate> </token> </user> I want to perform a select from this XML column where it determines the max date within the token element and would return the datarows similar to the result below for each record: Joe XYZ456 2014-01-01 18:48:50.111 I have tried to find a max function for xpath that would all me to select the correct token element but I couldn't find one that would work. I also tried to use the SQL MAX function but I wasn't able to get it working with that method either. If I only have a single token it of course works fine but when I have more than one I get a NULL, most likely because the query doesn't know which date to pull. I was hoping there would be a way to specify a where clause [max(endDate)] on the token element but haven't found a way to do that. Here is an example of the one that works when I only have a single token: SELECT XMLCOL.query('user/name').value('.','NVARCHAR(20)') as name XMLCOL.query('user/token/id').value('.','NVARCHAR(20)') as id XMLCOL.query('user/token/endDate').value(,'xs:datetime(.)','DATETIME') as endDate FROM MYTABLE

  Read the article

• Duplicate elements when adding XElement to XDocument

  - by Andy

  I'm writing a program in C# that will go through a bunch of config.xml files and update certain elements, or add them if they don't exist. I have the portion down that updates an element if it exists with this code: XDocument xdoc = XDocument.Parse(ReadFile(_file)); XElement element = xdoc.Elements("project").Elements("logRotator") .Elements("daysToKeep").Single(); element.Value = _DoRevert; But I'm running into issues when I want to add an element that doesn't exist. Most of the time part of the tree is in place and when I use my code it adds another identical tree, and that causes the program reading the xml to blow up. here is how I am attempting to do it xdoc.Element("project").Add(new XElement("logRotator", new XElement("daysToKeep", _day))); and that results in a structure like this(The numToKeep tag was already there): <project> <logRotator> <daysToKeep>10</daysToKeep> </logRotator> <logRotator> <numToKeep>13</numToKeep> </logRotator> </project> but this is what I want <project> <logRotator> <daysToKeep>10</daysToKeep> <numToKeep>13</numToKeep> </logRotator> </project>

  Read the article

• Android - Loop Through strings.xml file

  - by Alexis Cartier

  I was wondering if there is anyway to loop through the strings.xml file. Let's say that I have the following format: <!-- FIRST SECTION --> <string name="change_password">Change Password</string> <string name="change_server">Change URL</string> <string name="default_password">password</string> <string name="default_server">http://xxx:8080</string> <string name="default_username">testPhoneAccount</string> <!-- SECOND SECTION --> <string name="debug_settings_category">Debug Settings</string> <string name="reload_data_every_startup_pref">reload_data_every_startup</string> <string name="reload_data_on_first_startup_pref">reload_data_on_first_startup</string> Now let's say I have this: private HashMap<String,Integer> hashmapStringValues = new HashMap<String, Integer>(); Is there a way to iterate only in the second section of my xml file? Maybe wrap the section with a tag like <section2> and then iterate through it? public void initHashMap(){ for (int i=0;i< ???? ;i++) //Here I need to loop only in the second section of my xml file { String nameOfTag = ? // Here I get the name of the tag int value = R.string.nameOfTag // Here I get the associated value of the tag this.hashmapStringValues.put(nameOfTag,value); } }

  Read the article

• Parsing XML in C# from stream

  - by Phillip

  I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need. here's the example XML: <serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message> And, here's what i've tried to do: StreamReader reader = new StreamReader(dataStream); XmlDocument doc = new XmlDocument(); doc.LoadXml(reader.ReadToEnd()); XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable); ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service"); ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common"); ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event"); XmlNode node = doc.SelectSingleNode("result",ns); Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above. How can i do this?

  Read the article

• mysql to xml (DOM question)

  - by Jerry

  Hello guys I am new to php dom and trying to get the mysql data transfer into xml. My current xml output is like this <markers> <city> <name>Seattle</name> <size>medium</size> <name>New York</name> <size>big</size> <city> <markers> but I want to change it to <markers> <city> <name>Seattle</name> <size>medium</size> <city> <city> <name>New York</name> <size>big</size> </city> <city> <markers> my php $dom=new DOMDocument("1.0"); $node=$dom->createElement("markers"); $parnode=$dom->appendChild($node); $firstElement=$dom->createElement("city"); $parnode->appendChild($firstElement); $getLocationQuery=mysql_query("SELECT * FROM location",$connection); header("Content-type:text/xml"); while($row=mysql_fetch_assoc($getLocationQuery)){ foreach ($row as $fieldName=>$value){ $child=$dom->createElement($fieldName); $value=$dom->createTextNode($value); $child->appendChild($value); $firstElement->appendChild($child); } } I can't figure out how to change my php code. Please help me about it. Thanks a lot.

  Read the article

• Using a string inside the DocumentBuilder parse method (need it for parsing XML using XPath)

  - by dierre

  Hi guys! I'm trying to create a RESTful webservice using a Java Servlet. The problem is I have to pass via POST method to a webserver a request. The content of this request is not a parameter but the body itself. So I basically send from ruby something like this: url = URI.parse(@host) req = Net::HTTP::Post.new('/WebService/WebServiceServlet') req['Content-Type'] = "text/xml" # req.basic_auth 'account', 'password' req.body = data response = Net::HTTP.start(url.host, url.port){ |http| puts http.request(req).body } Then I have to retrieve the body of this request in my servlet. I use the classic readline, so I have a string. The problem is when I have to parse it as XML: private void useXML( final String soft, final PrintWriter out) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException, FileNotFoundException { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); // never forget this! DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse(soft); XPathFactory factory = XPathFactory.newInstance(); XPath xpath = factory.newXPath(); XPathExpression expr = xpath.compile("//software/text()"); Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; for (int i = 0; i < nodes.getLength(); i++) { out.println(nodes.item(i).getNodeValue()); } } The problem is that builder.parse() accepts: parse(File f), parse(InputSource is), parse(InputStream is). Is there any way I can transform my xml string in an InputSource or something like that? I know it could be a dummy question but Java is not my thing, I'm forced to use it and I'm not very skilled.

  Read the article

• POST XML to server, receive PDF

  - by Shaggy Frog

  Similar to this question, we are developing a Web app where the client clicks a button to receive a PDF from the server. Right now we're using the .ajax() method with jQuery to POST the data the backend needs to generate the PDF (we're sending XML) when the button is pressed, and then the backend is generating the PDF entirely in-memory and sending it back as application/pdf in the HTTP response. One answer to that question requires the server-side save the PDF to disk so it can give back a URL for the client to GET. But I don't want the backend caching content at all. The other answer suggests the use of a jQuery plugin, but when you look at its code, it's actually generating a form element and then submitting the form. That method will not work for us since we are sending XML data in the body of the HTTP request. Is there a way to have the browser open up the PDF without caching the PDF server-side, and without requiring us to throw out our send-data-to-the-server-using-XML solution? (I'd like the browser to behave like it does when a form element is submitted -- a POST is made and then the browser looks at the Content-type header to determine what to do next, like load the PDF in the browser window, a la Safari)

  Read the article

• parsing xml using dom4j

  - by D3GAN

  My XML structure is like this: <rss> <channel> <yweather:location city="Paris" region="" country="France"/> <yweather:units temperature="C" distance="km" pressure="mb" speed="km/h"/> <yweather:wind chill="-1" direction="40" speed="11.27"/> <yweather:atmosphere humidity="87" visibility="9.99" pressure="1015.92" rising="0"/> <yweather:astronomy sunrise="8:30 am" sunset="4:54 pm"/> </channel> </rss> when I tried to parse it using dom4j SAXReader xmlReader = createXmlReader(); Document doc = null; doc = xmlReader.read( inputStream );//inputStream is input of function log.info(doc.valueOf("/rss/channel/yweather:location/@city")); private SAXReader createXmlReader() { Map<String,String> uris = new HashMap<String,String>(); uris.put( "yweather", "http://xml.weather.yahoo.com/ns/rss/1.0" ); uris.put( "geo", "http://www.w3.org/2003/01/geo/wgs84_pos#" ); DocumentFactory factory = new DocumentFactory(); factory.setXPathNamespaceURIs( uris ); SAXReader xmlReader = new SAXReader(); xmlReader.setDocumentFactory( factory ); return xmlReader; } But I got nothing in cmd but when I print doc.asXML(), my XML structure print correctly!

  Read the article

• php XML DOM translates special chars to &#xYY;

  - by ZiTAL

  I send this with AJAX POST: <li><ul class "zone zCentral ui-sortable"><li><ul class="region rCol3 ui-sortable"><li class="" style=""><div><span class="tc tc_video">574081</span> <span>video: 'Mundo.Hoy': ¿Dónde habré olvidado... mi memoria?</span></div></li></ul></li></ul></li> I do this to create XML: header('Content-type: text/html; charset=utf-8'); if(isset($_POST) && isset($_POST['data'])) { $data = '<ul id="zone_container" class="ui-sortable">'; $data .= $_POST['data']; $data .= '</ul>'; $dom = new DOMDocument('1.0', 'utf-8'); $dom->loadXML($data); echo $dom->saveXML(); exit(); } and i get this: <?xml version="1.0"?> <ul id="zone_container" class="ui-sortable"> <li><ul class="zone zCentral ui-sortable"><li><ul class="region rCol3 ui-sortable"><li class="" style=""><div><span class="tc tc_video">574081</span> <span>video: 'Mundo.Hoy': &#xBF;D&#xF3;nde habr&#xE9; olvidado... mi memoria?</span></div> </li></ul></li></ul></li></ul> ¿Dónde habré olvidado... mi memoria? translates to: &#xBF;D&#xF3;nde habr&#xE9 ; olvidado... mi memoria? Y need original chars in the XML, these are utf-8 valid i don't know the reason for this encode :(

  Read the article

• How to parse the second child node from xml page in iphone

  - by Warrior

  I am new to iphone development.I want parse an you-tube XML page and retrieve its contents and display in a RSS feed. my xml page is <entry> <id>xxxxx</id> <title>xxx xxxx xxxx</title> <content>xxxxxxxxxxx</content> <media:group> <media:thumbnail url="http://tiger.jpg"/> </media:group> </entry> To retrieve the content i am using xml parsing. - (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict{ currentElement = [elementName copy]; if ([elementName isEqualToString:@"entry"]) { entry = [[NSMutableDictionary alloc] init]; currentTitle = [[NSMutableString alloc] init]; currentcontent = [[NSMutableString alloc] init]; } } - (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName{ if ([elementName isEqualToString:@"entry"]) { [entry setObject:currentTitle forKey:@"title"]; [entry setObject:currentDate forKey:@"content"]; [stories addObject:[entry copy]]; }} - (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string{ if ([currentElement isEqualToString:@"title"]) { [currentTitle appendString:string]; } else if ([currentElement isEqualToString:@"content"]) { [currentLink appendString:string]; } } I am able to retrieve id , title and content value and display it in a table-view.How can i retrieve tiger image URL and display it in table-view.Please help me out.Thanks.

  Read the article

• Remove the Parent tag in xml using php

  - by Wasim

  I am facing a problem in editing a xml file. <?xml version="1.0" encoding="UTF-8"?> <urlset> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> </urlset> I want to add one more set of records starting with <url> with its other tags, (i.e) "loc,lastmod,changefreq,priority" and than save the xml file.For adding the new record i need to remove the parent closing tag that is </urlset> and than add the rest of the records and close the main tag. Can anyone please help me solving my problem.Thanks

  Read the article

• Problem creating XML using c#

  - by Pankaj

  I am searching a batter solution for creating xml through xml serialization. What i need, i have a given format like this <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <note>!--note 1---</note> <note>!--note 2--</note> ...... </notes> </product> what i am doing here, i created a 2 classes like this public class product { [XmlElement("name")] public string Name { get; set; } [XmlArray("notes")] public List<notes> ListNotes { get; set; } } public class notes { [XmlIgnore] public string Note { get; set; } } when i am serializing this then i am getting xml in this formate <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <notes> <note>!--note 1---</note> <note>!--note 2--</note> </notes> </notes> </product> i don't want extra <notes>. Any batter solution to solve this problem? Thanks

  Read the article

• Creating subtree from tree which is represented in xml - python

  - by Jay

  Hi I have an XML (in the form of tree), I require to create sub-tree out of it. For ex: <a> <b> <c>Hello</c> <d> <e>Hi</e> </a> Subtree would be <root> <a> <b> <c>Hello</c> </b> </a> <a> <d> <e>Hi</e> </d> </a> </root> What is the best XML library in python to do it? Any algorithm that already does this would also be helpful. Note: the XML doc won't be that big, it will easily fit in memory.

  Read the article

• Fastest XML parser for small, simple documents in Java

  - by Varkhan

  I have to objectify very simple and small XML documents (less than 1k, and it's almost SGML: no namespaces, plain UTF-8, you name it...), read from a stream, in Java. I am using JAXP to process the data from my stream into a Document object. I have tried Xerces, it's way too big and slow... I am using Dom4j, but I am still spending way too much time in org.dom4j.io.SAXReader. Does anybody out there have any suggestion on a faster, more efficient implementation, keeping in mind I have very tough CPU and memory constraints? [Edit 1] Keep in mind that my documents are very small, so the overhead of staring the parser can be important. For instance I am spending as much time in org.xml.sax.helpers.XMLReaderFactory.createXMLReader as in org.dom4j.io.SAXReader.read [Edit 2] The result has to be in Dom format, as I pass the document to decision tools that do arbitrary processing on it, like switching code based on the value of arbitrary XPaths, but also extracting lists of values packed as children of a predefined node. [Edit 3] In any case I eventually need to load/parse the complete document, since all the information it contains is going to be used at some point. (This question is related to, but different from, http://stackoverflow.com/questions/373833/best-xml-parser-for-java )

  Read the article

• Stop CDATA tags from being output-escaped when writing to XML in C#

  - by Smallgods

  We're creating a system outputting some data to an XML schema. Some of the fields in this schema need their formatting preserved, as it will be parsed by the end system into potentially a Word doc layout. To do this we're using <![CDATA[Some formatted text]]> tags inside of the App.Config file, then putting that into an appropriate property field in a xsd.exe generated class from our schema. Ideally the formatting wouldn't be out problem, but unfortunately thats just how the system is going. The App.Config section looks as follows: <header> <![CDATA[Some sample formatted data]]> </header> The data assignment looks as follows: HeaderSection header = ConfigurationManager.GetSection("header") as HeaderSection; report.header = "<[CDATA[" + header.Header + "]]>"; Finally, the Xml output is handled as follows: xs = new XmlSerializer(typeof(report)); fs = new FileStream (reportLocation, FileMode.Create); xs.Serialize(fs, report); fs.Flush(); fs.Close(); This should in theory produce in the final Xml a section that has information with CDATA tags around it. However, the angled brackets are being converted into &lt; and &gt; I've looked at ways of disabling Outout Escaping, but so far can only find references to XSLT sheets. I've also tried @"<[CDATA[" with the strings, but again no luck. Any help would be appreciated!

  Read the article

< Previous Page | 50 51 52 53 54 55 56 57 58 59 60 61  | Next Page >