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  • how to display user name in login name control

    - by user569285
    I have a master page that holds the loginview content that appears on all subsequent pages based on the master page. i have a username control also nested in the loginview to display the name of the user when they are logged in. the code for the loginview from the master page is displayed as follows: <div class="loginView"> <asp:LoginView ID="MasterLoginView" runat="server"> <LoggedInTemplate> Welcome <span class="bold"><asp:LoginName ID="HeadLoginName" runat="server" /> <asp:Label ID="userNameLabel" runat="server" Text="Label"></asp:Label></span>! [ <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Logout.aspx"/> ] <%--Welcome: <span class="bold"><asp:LoginName ID="MasterLoginName" runat="server" /> </span>!--%> </LoggedInTemplate> <AnonymousTemplate> Welcome: Guest [ <a href="~/Account/Login.aspx" ID="HeadLoginStatus" runat="server">Log In</a> ] </AnonymousTemplate> </asp:LoginView> <%--&nbsp;&nbsp; [&nbsp;<asp:LoginStatus ID="MasterLoginStatus" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" />&nbsp;]&nbsp;&nbsp;--%> </div> Since VS2010 launches with a default login page in the accounts folder, i didnt think it necessary to create a separate log in page, so i just used the same log in page. please find the code for the login control below: <asp:Login ID="LoginUser" runat="server" EnableViewState="false" RenderOuterTable="false"> <LayoutTemplate> <span class="failureNotification"> <asp:Literal ID="FailureText" runat="server"></asp:Literal> </span> <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="failureNotification" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend style="text-align:left; font-size:1.2em; color:White;">Account Information</legend> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User ID:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="failureNotification" ErrorMessage="User ID is required." ToolTip="User ID field is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="failureNotification" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="submitButton"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="LoginUserValidationGroup" onclick="LoginButton_Click"/> </p> </div> </LayoutTemplate> </asp:Login> I then wrote my own code for authentication since i had my own database. the following displays the code in the login buttons click event.: public partial class Login : System.Web.UI.Page { //create string objects string userIDStr, pwrdStr; protected void LoginButton_Click(object sender, EventArgs e) { //assign textbox items to string objects userIDStr = LoginUser.UserName.ToString(); pwrdStr = LoginUser.Password.ToString(); //SQL connection string string strConn; strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ConnectionString; SqlConnection Conn = new SqlConnection(strConn); //SqlDataSource CSMDataSource = new SqlDataSource(); // CSMDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ToString(); //SQL select statement for comparison string sqlUserData; sqlUserData = "SELECT StaffID, StaffPassword, StaffFName, StaffLName, StaffType FROM Staffs"; sqlUserData += " WHERE (StaffID ='" + userIDStr + "')"; sqlUserData += " AND (StaffPassword ='" + pwrdStr + "')"; SqlCommand com = new SqlCommand(sqlUserData, Conn); SqlDataReader rdr; string usrdesc; string lname; string fname; string staffname; try { //string CurrentData; //CurrentData = (string)com.ExecuteScalar(); Conn.Open(); rdr = com.ExecuteReader(); rdr.Read(); usrdesc = (string)rdr["StaffType"]; fname = (string)rdr["StaffFName"]; lname = (string)rdr["StaffLName"]; staffname = lname.ToString() + " " + fname.ToString(); LoginUser.UserName = staffname.ToString(); rdr.Close(); if (usrdesc.ToLower() == "administrator") { Response.Redirect("~/CaseAdmin.aspx", false); } else if (usrdesc.ToLower() == "manager") { Response.Redirect("~/CaseManager.aspx", false); } else if (usrdesc.ToLower() == "investigator") { Response.Redirect("~/Investigator.aspx", false); } else { Response.Redirect("~/Default.aspx", false); } } catch(Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } finally { Conn.Close(); } } My authentication works perfectly and the page gets redirected to the designated destination. However, the login view does not display the users name. i actually cant figure out how to pass the users name that i had picked from the database to the login name control to be displayed. taking a close look i also noticed the logout text that should be displayed after successful log in does not show. that leaves me wondering if the loggedin template control on the masterpage even fires at all or its still the anonymous template control that keeps displaying.? How do i get this to work as expected? Please help....

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  • Can't start rails server after 3.0.1 upgrade

    - by Alberto
    Followed instructions on Railscast but can't get server to start. It states the following error: $ rails s script/rails:6:in `require': no such file to load -- rails/commands (LoadError)` from script/rails:6:in `<main>' Saw the answer on this related question but my Gemfile has no reference to any rails 2.x version and in the "bundle install" results i get this in the results: "Using rails (3.0.1)" EDIT: (adding Gemfile.lock details) GEM remote: http://rubygems.org/ specs: abstract (1.0.0) actionmailer (3.0.1) actionpack (= 3.0.1) mail (~> 2.2.5) actionpack (3.0.1) activemodel (= 3.0.1) activesupport (= 3.0.1) builder (~> 2.1.2) erubis (~> 2.6.6) i18n (~> 0.4.1) rack (~> 1.2.1) rack-mount (~> 0.6.12) rack-test (~> 0.5.4) tzinfo (~> 0.3.23) activemodel (3.0.1) activesupport (= 3.0.1) builder (~> 2.1.2) i18n (~> 0.4.1) activerecord (3.0.1) activemodel (= 3.0.1) activesupport (= 3.0.1) arel (~> 1.0.0) tzinfo (~> 0.3.23) activeresource (3.0.1) activemodel (= 3.0.1) activesupport (= 3.0.1) activesupport (3.0.1) arel (1.0.1) activesupport (~> 3.0.0) builder (2.1.2) calendar_date_select (1.16.1) erubis (2.6.6) abstract (>= 1.0.0) googlecharts (1.6.0) i18n (0.4.2) mail (2.2.9) activesupport (>= 2.3.6) i18n (~> 0.4.1) mime-types (~> 1.16) treetop (~> 1.4.8) mechanize (1.0.0) nokogiri (>= 1.2.1) mime-types (1.16) nokogiri (1.4.3.1) pg (0.9.0) polyglot (0.3.1) rack (1.2.1) rack-mount (0.6.13) rack (>= 1.0.0) rack-test (0.5.6) rack (>= 1.0) rails (3.0.1) actionmailer (= 3.0.1) actionpack (= 3.0.1) activerecord (= 3.0.1) activeresource (= 3.0.1) activesupport (= 3.0.1) bundler (~> 1.0.0) railties (= 3.0.1) railties (3.0.1) actionpack (= 3.0.1) activesupport (= 3.0.1) rake (>= 0.8.4) thor (~> 0.14.0) rake (0.8.7) sparklines (0.5.2) thor (0.14.4) treetop (1.4.8) polyglot (>= 0.3.1) tzinfo (0.3.23) PLATFORMS ruby DEPENDENCIES calendar_date_select googlecharts mechanize pg rails (= 3.0.1) sparklines EDIT: (adding Boot.rb details) require 'rubygems' # Set up gems listed in the Gemfile. gemfile = File.expand_path('../../Gemfile', __FILE__) begin ENV['BUNDLE_GEMFILE'] = gemfile require 'bundler' Bundler.setup rescue Bundler::GemNotFound => e STDERR.puts e.message STDERR.puts "Try running `bundle install`." exit! end if File.exist?(gemfile)

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  • people picker control inside gridview template field with ajax update panel applied SharePoint 2010

    - by user1434450
    In my page I have drop down control, grid view. Inside the grid view in template field I have people picker control. When ever I change the drop down value from 'Select' to another I am displaying my grid view with people picker. Everything is working fine. But after applying 'update panel', whenever I change the drop down value, people picker control is not working inside the grid view. <asp:UpdatePanel ID="UpdatePanel1" runat="server" UpdateMode="Conditional"> <ContentTemplate> <asp:GridView ID="gvDirectory" runat="server" AutoGenerateColumns="false" ShowHeader="false" onrowcommand="gvDirectory_RowCommand" onrowdeleting="gvDirectory_RowDeleting" onrowdatabound="gvDirectory_RowDataBound" BorderWidth="0"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:CheckBox ID="chkselect" runat="server" Width="20px" AutoPostBack="true" oncheckedchanged="chkselect_CheckedChanged"/> </ItemTemplate> </asp:TemplateField> <asp:TemplateField> <ItemTemplate> <asp:HyperLink ID="lnkcategory" runat="server" Text='<%# Eval("Title") %>' Target="_blank" NavigateUrl='<%# Eval("URL") %>' Width="200px" onclick="ShowAwesomeHelloPageInDialog(this);return false;"></asp:HyperLink> <asp:Label ID="lblvalue" runat="server" Text='<%# Eval("value") %>' Visible="false"></asp:Label> </ItemTemplate> </asp:TemplateField> <asp:TemplateField> <ItemTemplate> <SharePoint:PeopleEditor ID="Assignedusers" runat="server" AllowEmpty="false" MultiSelect="true" Width="250px" BorderColor="#559CD7" Height="20px" SelectionSet="User,SPGroup" Rows="2" PlaceButtonsUnderEntityEditor="false" EnableViewState="true" /> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="Delete"> <ItemTemplate> <asp:ImageButton ID="btnDelete" runat="server" CommandArgument='<%# Container.DataItemIndex%>' ImageUrl="~/_layouts/images/EditTaskPage/Delete.png" CommandName="Delete" Text="Delete" Height="26px" Width="26px"/> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> </ContentTemplate> <%--<Triggers> <asp:PostBackTrigger ControlID="ddlCategory" /> </Triggers>--%> </asp:UpdatePanel> <script type="text/javascript"> _spOriginalFormAction = document.forms[0].action; _spSuppressFormOnSubmitWrapper = true; </script> how can I solve this problem.. thanks in advance....

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  • PHP Increasing write to page speed.

    - by Frederico
    I'm currently writing out xml and have done the following: header ("content-type: text/xml"); header ("content-length: ".strlen($xml)); $xml being the xml to be written out. I'm near about 1.8 megs of text (which I found via firebug), it seems as the writing is taking more time than the script to run.. is there a way to increase this write speed? Thank you in advance.

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  • php curl upload speed

    - by zanatic
    hey i made a script that uploads files to different servers using php curl and the problem is that it eats all my upload bandwith and my apache does not respond as i would like. the call is made from the php-cli and can not use any apache bandwith limiting bandwith thanks in advance

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  • Wordpress and Joomla Permalinks plus domain redirect to specific subdirectory on Zeus

    - by moss
    Hi, Here's what I'm trying to do: joomla in 1 subdirectory, wordpress in another. mysite.com directs to the joomla directory mysite.com/blog gives wordpress. I would also like to use seo friendly permalinks for both. I am using Zeus Linux shared hosting with Joomla 1.5 and wordpress 2.9.2, and having a great deal of trouble finding a suitable rewrite script. Any help would be very much appreciated! Thank you.

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  • ajax/JS timed countdown?

    - by kieran
    Let me explain what I'm trying to do. I want to make a simple box which counts down numbers at intervals I specify. For example, I'd like to set it to start at 150, and then I want to set it to drop by 15 every 30 seconds. Is this possible with AJAX/Javascript? If so, could someone point me in the right direction? Would really appreciate any help on this script, been Googling for hours now! :( Cheers Kieran

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  • scripting fruityloops or propellerheads reason from VB or Python?

    - by interstar
    I have both Fruityloops and Propellerheads Reason software synths on my Windows PC. Any way I can get at and script these from either Visual Basic or Python? Or at least send Midi messages to the synths from code? Update : attempts to use something like a "midi-mapper" (thanks for link MusiGenesis) don't seem to work. I don't think Reason or FL Studio act like standard GM Midi synths. Update 2 : If you're interested in this question, check out this too.

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  • MySQL foreign key creation with alter table command

    - by user313338
    I created some tables using MySQL Workbench, and then did forward ‘forward engineer’ to create scripts to create these tables. BUT, the scripts lead me to a number of problems. One of which involves the foreign keys. So I tried creating separate foreign key additions using alter table and I am still getting problems. The code is below (the set statements, drop/create statements I left in … though I don’t think they should matter for this): SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_UserName` VARCHAR(35) NOT NULL , `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`), FOREIGN KEY (`User_UserName`) REFERENCES `mydb`.`User` (`UserName`) ON UPDATE CASCADE ON DELETE CASCADE) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; The error this produces is: Error Code: 1005 Can't create table 'mydb.user_space' (errno: 150) Anybody know what the heck I’m doing wrong?? And anybody else have problems with the script generation done by mysql workbench? It’s a nice tool, but annoying that it pumps out scripts that don’t work for me. [As an fyi here’s the script it auto-generates: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`) , INDEX `User_ID` () , CONSTRAINT `User_ID` FOREIGN KEY () REFERENCES `mydb`.`User` () ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; ** Thanks!]

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  • Escaping Code for Different Shells

    - by Jon Purdy
    Question: What characters do I need to escape in a user-entered string to securely pass it into shells on Windows and Unix? What shell differences and version differences should be taken into account? Can I use printf "%q" somehow, and is that reliable across shells? Backstory (a.k.a. Shameless Self-Promotion): I made a little DSL, the Vision Web Template Language, which allows the user to create templates for X(HT)ML documents and fragments, then automatically fill them in with content. It's designed to separate template logic from dynamic content generation, in the same way that CSS is used to separate markup from presentation. In order to generate dynamic content, a Vision script must defer to a program written in a language that can handle the generation logic, such as Perl or Python. (Aside: using PHP is also possible, but Vision is intended to solve some of the very problems that PHP perpetuates.) In order to do this, the script makes use of the @system directive, which executes a shell command and expands to its output. (Platform-specific generation can be handled using @unix or @windows, which only expand on the proper platform.) The problem is obvious, I should think: test.htm: <!-- ... --> <form action="login.vis" method="POST"> <input type="text" name="USERNAME"/> <input type="password" name="PASSWORD"/> </form> <!-- ... --> login.vis: #!/usr/bin/vision # Think USERNAME = ";rm -f;" @system './login.pl' { USERNAME; PASSWORD } One way to safeguard against this kind of attack is to set proper permissions on scripts and directories, but Web developers may not always set things up correctly, and the naive developer should get just as much security as the experienced one. The solution, logically, is to include a @quote directive that produces a properly escaped string for the current platform. @system './login.pl' { @quote : USERNAME; @quote : PASSWORD } But what should @quote actually do? It needs to be both cross-platform and secure, and I don't want to create terrible problems with a naive implementation. Any thoughts?

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  • Exclude a file in a filematch

    - by lund.mikkel
    Hey folks I'm trying to prepend a gzip script at the beginning of every file using php_value auto_prepend_file gzip_start.php in my .htaccess. The problem is that I've already got a document called combine.php that gzips it contents. What I need to know is, how I can exclude combine.php from the files who get the gzip prepended. I thought about using filesmatch, but can only figure out how to do it on just that one file, and not the exact opposite. Any ideas?

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  • Why doesn't my form post when I disable the submit button to prevent double clicking?

    - by John MacIntyre
    Like every other web developer on the planet, I have an issue with users double clicking the submit button on my forms. My understanding is that the conventional way to handle this issue, is to disable the button immediately after the first click, however when I do this, it doesn't post. I did do some research on this, god knows there's enough information, but other questions like Disable button on form submission, disabling the button appears to work. The original poster of Disable button after submit appears to have had the same problem as me, but there is no mention on how/if he resolved it. Here's some code on how to repeat it (tested in IE8 Beta2, but had same problem in IE7) My aspx code <%@ Page Language="C#" CodeFile="Default.aspx.cs" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <script language="javascript" type="text/javascript"> function btn_onClick() { var chk = document.getElementById("chk"); if(chk.checked) { var btn = document.getElementById("btn"); btn.disabled = true; } } </script> <body> <form id="form1" runat="server"> <asp:Literal ID="lit" Text="--:--:--" runat="server" /> <br /> <asp:Button ID="btn" Text="Submit" runat="server" /> <br /> <input type="checkbox" id="chk" />Disable button on first click </form> </body> </html> My cs code using System; public partial class _Default : System.Web.UI.Page { protected override void OnInit(EventArgs e) { base.OnInit(e); btn.Click += new EventHandler(btn_Click); btn.OnClientClick = "btn_onClick();"; } void btn_Click(object sender, EventArgs e) { lit.Text = DateTime.Now.ToString("HH:mm:ss"); } } Notice that when you click the button, a postback occurs, and the time is updated. But when you check the check box, the next time you click the button, the button is disabled (as expected), but never does the postback. WHAT THE HECK AM I MISSING HERE??? Thanks in advance.

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  • Creating membership tables online

    - by JPJedi
    I want to create the membership tables online that are used for ASP.Net 3.5 login controls. I thought their was a script I could use or executable on my computer to install those tables. Is that the case? or what would be the best method to create the tables online.

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  • Adding a mini admin to a webpage.

    - by DADU
    Hello Picture this: you are creating a little module that people can incorporate into their website easily, for example, a little contact form. It would consist of a PHP file that outputs some HTML, a Javascript file (ajax etc.), a CSS file and a CSS skin. Now the person who doesn't know much about coding wants to integrate it on a webpage (website/index.php). We could do this with three rules of code: <link rel="stylesheet" href="module/css/module.css" /> <script src="module/js/module.js"></script> <?php require_once 'module/module.php'; ?> There's no doubt this part is questionable, right? Now when we want to add an admin for this little module, there are two options: Accessing the admin via an extra URL like website/module/admin.php and after authentication, displaying a page where the person can do all the settings. The person then goes back to index.php to see the results. Enabling the admin via an extra URL like website/module/admin.php and after authentication, redirecting back to index.php. The person can now edit the module directly (HTML5 contenteditable) and see changes live, on the webpage where everybody else will see it when the person saves the changes. Option 2 has a couple of advantages: The person doesn't have to toggle between admin and index.php. The person can see directly how it's looking at the webpage it's integrated in. The person probably feels like the module is more part of the webpage/website. Of course option 2 has some disadvantages too: Not everything works well editing it inline. The person would need to have an HTML5 compliant browser. Probably some more I can't think of right now. Now I have a few concerns that's I can't seem to see a clear answer to. How would we let the person integrate the admin on their webpage? The admin files only need to be included in index.php if the person has choosen to edit the module via the url (website/module/admin.php). But how can we do this if we have a admin.css file that belongs in the head section, an admin.php file that goes into the body, and another admin.js file that's included at the end of the body? How would we know the file that admin.php needs to redirect back to, after authentication? index.php could be any webpage with any name. Any real life website/web apps examples using this principle are welcome too. If there's something unclear, I am glad to add additional info.

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  • Need Help on OAuthException Code 2500

    - by Deepak
    I am trying to develop an Facebook application (apps.facebook.com/some_app) using PHP where I need to present some information based on user's music interests. I found that its under "user_likes games". My problems are as follows: To gain access, I have implemented the oauth dialog method as suggested in API in my index page. $auth_url = "http://www.facebook.com/dialog/oauth?client_id=" . $app_id . "&redirect_uri=" . urlencode($canvas_page) ."&scope=user_likes"; After successful authorization I come back to index page with "code" as parameters. http://MY_CANVAS_PAGE/?code=some base64 encoded letters Firstly I don't know if I need access_token just to read user's music interests but I have tried all the methods suggested. I couldn't move forward from this point I have a code like this (in my index page), which redirects for authorization if code parameters is not set. if(empty($code) && !isset($_REQUEST['error'])) { $_SESSION['state'] = md5(uniqid(rand(), TRUE)); //CSRF protection echo("<script> top.location.href='" . $auth_url . "'</script>"); } Currently I am just trying to get user's public information here but with no success. I have tried the signed_request method as suggested but no success $signed_request = $_REQUEST["signed_request"]; list($encoded_sig, $payload) = explode('.', $signed_request, 2); $data = json_decode(base64_decode(strtr($payload, '-_', '+/')), true); echo ("Welcome User: " . $data["user_id"]); Also tried the code found in http://developers.facebook.com/blog/post/500/ but I am getting error when trying to get the debug info using print_r($decoded_response); stdClass Object ( [error] => stdClass Object ( [message] => An active access token must be used to query information about the current user. [type] => OAuthException [code] => 2500 ) ) To get user's public info, I have tried also the suggested example in PHP SDK $facebook = new Facebook(array( 'appId' => MY_APP_ID, //registered facebook APP ID 'secret' => MY_SECRET, //secret key for APP )); $fb_user = $facebook->getUser(); if($fb_user){ try { $user_profile = $facebook->api('/me'); echo $user_profile['email']; } catch(FacebookApiException $e) { $fb_user = null; } } But no success. Can somebody explain me why I am getting this error and how to access the user's music interest properly. Probably I misunderstood the API. Thanks Deepak

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  • Python (Django). Store telnet connection

    - by Shamanu4
    Hello. I am programming web interface which communicates with cisco switches via telnet. I want to make such system which will be storing one telnet connection per switch and every script (web interface, cron jobs, etc.) will have access to it. This is needed to make a single query queue for each device and prevent huge cisco processor load caused by several concurent telnet connections. How do I can do this?

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  • Callback function in jquery doesn't seem to work......

    - by Pandiya Chendur
    I use the following jquery pagination plugin and i got the error a.parentNode is undefined when i executed it... <script type="text/javascript"> $(document).ready(function() { getRecordspage(1, 5); $(".pager").pagination(17, { callback: pagechange, current_page: '0', items_per_page: '5', num_display_entries : '5', next_text: 'Next', prev_text: 'Prev', num_edge_entries: '1' }); }); function pagechange() { $("#ResultsDiv").empty(); $("#ResultsDiv").css('display', 'none'); getRecordspage($(this).text(), 5); } function getRecordspage(curPage, pagSize) { $.ajax({ type: "POST", url: "Default.aspx/GetRecords", data: "{'currentPage':" + curPage + ",'pagesize':" + pagSize + "}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(jsonObj) { var strarr = jsonObj.d.split('##'); var jsob = jQuery.parseJSON(strarr[0]); var divs = ''; $.each(jsob.Table, function(i, employee) { divs += '<div class="resultsdiv"><br /><span class="resultName">' + employee.Emp_Name + '</span><span class="resultfields" style="padding-left:100px;">Category&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Desig_Name + '</span><br /><br /><span id="SalaryBasis" class="resultfields">Salary Basis&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.SalaryBasis + '</span><span class="resultfields" style="padding-left:25px;">Salary&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.FixedSalary + '</span><span style="font-size:110%;font-weight:bolder;padding-left:25px;">Address&nbsp;:</span>&nbsp;<span class="resultfieldvalues">' + employee.Address + '</span></div>'; }); $("#ResultsDiv").append(divs).show('slow'); $(".resultsdiv:even").addClass("resultseven"); $(".resultsdiv").hover(function() { $(this).addClass("resultshover"); }, function() { $(this).removeClass("resultshover"); }); } }); } </script> and in my page, <div id="ResultsDiv" style="display:none;"> </div> <div id="pager" class="pager"> </div> Any suggestion....

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  • jQuery and iterating on JSON objects.

    - by The Devil
    Hey everybody, I'm currently trying to figure out how can I iterate over all of the objects in an JSON response. My object may have endless sub objects and they may also have endless sub objects. { "obj1" : { "obj1.1" : "test", "obj1.2" : { "obj1.1.1" : true, "obj1.1.2" : "test2", "obj1.1.3" : { ... // etc } } } } I was just wondering if there is a out of the box script that can handle such kind of objects? Thanks in advance, The Devil

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