Search Results

Search found 31657 results on 1267 pages for 'too much php'.

Page 542/1267 | < Previous Page | 538 539 540 541 542 543 544 545 546 547 548 549  | Next Page >

  • Does ini_set('session.save_path', 'custom path'); effect the session garbage cleaner?

    - by newbtophp
    Hi! Does ini_set('session.save_path', 'custom path'); effect the session garbage cleaner? As I'm setting a custom directory for the sessions, because I've read from various php security guides, that setting a custom directory on shared hosting for sessions; can improve session security. But the problem is I've read somewhere that PHP does/handles the session garbage cleaning only when the session_save_path is the default and not modified (ie. using a custom directory)? - is this true, if so is their a solution for this?. (take into consideration I'm using shared hosting). Appreciate all help!

    Read the article

  • Injecting single-use object into class

    - by moteutsch
    I have the following code: <?php class X { public function do($url) { $httpRequest = new \HttpRequest\Curl($url, $this->getOptions()); $httpRequest->fire(); // etc. } // ... } In order to be able to unit test this class, I'd like to inject a mocked HttpRequest class. One way to do this would be as follows: <?php class X { private $httpRequestClass; public function __construct($httpRequestClass = '\HttpRequest\Curl') { $this->httpRequestClass = $httpRequestClass; } public function do($url) { $httpRequest = new $this->httpRequestClass($url, $this->getOptions()); $httpRequest->fire(); // etc. } // ... } But this doesn't seem right. Any other ideas?

    Read the article

  • how to list out the submited data in same page where form submitted?

    - by OM The Eternity
    I have a form with 3 text values and one image.. I want to save these values such that i can display these records in the list below.. how can i do that... I am using osCommerce For example: <form method="post" id="fm-form" action ="" enctype="multipart/form-data"> <label>Name:</label> <input type="text" id="fm-name" name="fm-name" value="" /> <label>Email:</label> <input type="text" id="fm-email" name="fm-email" value="" /> <label>Birthdate:</label> <input type="text" id="fm-birthdate" name="fm-birthdate" value="" /> <input type="file" id="fm-image" name="fm-image"/> <input type="submit" id="fm-submit" value="Save it"> </form> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr > <td align="center" class="productListing-heading">Product(s)</td> <td align="center" class="productListing-heading">Edit</td> <td align="center" class="productListing-heading">Delete</td> </tr> <?php for($i=0;$i<$count_image;$i++){?> <tr> <td align="left" class="productListing-data1"> <?php echo tep_image(DIR_WS_IMAGES . $file_realname, $save_image[$i], '110', '110');?> </td> <td align="center" class="productListing-data1">Edit</td> <td align="center" class="productListing-data1">Delete</td> </tr> <tr><td>&nbsp;</td></tr> <?php }?> </table> In the above format as the form is submitted the image has to be stored in a count_image array variable... and the on its count, the list below the form is displayed.. but i cannot get it worked.. could u pls help in doing this...

    Read the article

  • Access a static variable by $var::$reference

    - by chuckg
    I am trying to access a static variable within a class by using a variable class name. I'm aware that in order to access a function within the class, you use call_user_func(): class foo { function bar() { echo 'hi'; } } $class = "foo"; all_user_func(array($class, 'bar')); // prints hi However, this does not work when trying to access a static variable within the class: class foo { public static $bar = 'hi'; } $class = "foo"; call_user_func(array($class, 'bar')); // nothing echo $foo::$bar; // invalid How do I get at this variable? Is it even possible? I have a bad feeling this is only available in PHP 5.3 going forward and I'm running PHP 5.2.6. Thanks.

    Read the article

  • mysql_real_escape_string & slashes (again, oh yes)

    - by Fizzadar
    Righto, firstly magic quotes & runtime are disabled correctly in php.ini, and confirmed by phpinfo(). PHP version: 5.3.4 MySQL version: 5.1.52 I'm only use mysql_real_escape_string on the data, after htmlspecialchars and a trim, that's all the data cleaning on the variable. Yet, when I submit a single quote, the slash remains in the database. When running mysql_query I'm using "' . $var . '", although in the past this hasn't changed anything (could be due to the double quotes?). Any ideas? and please don't tell me about PDO/prepared statements, I'm aware of them and I have my reasons for doing it this way. Thanks!

    Read the article

  • How to access constant defined in child class from parent class functions?

    - by kavoir.com
    I saw this example from php.net: <?php class MyClass { const MY_CONST = "yonder"; public function __construct() { $c = get_class( $this ); echo $c::MY_CONST; } } class ChildClass extends MyClass { const MY_CONST = "bar"; } $x = new ChildClass(); // prints 'bar' $y = new MyClass(); // prints 'yonder' ?> But $c::MY_CONST is only recognized in version 5.3.0 or later. The class I'm writing may be distributed a lot. Basically, I have defined a constant in ChildClass and one of the functions in MyClass (father class) needs to use the constant. Any idea?

    Read the article

  • Logging in to a website cURL!

    - by uknowho_freeman
    I am using cURL for the first time. I need to login to a site. I have problem with setting cookie file and to retrive, so that i can acces that page not just one time, but several times. I found the code on the web, for logging in to a site and Scrap a page for some detailed info, cause to get that page it takes to much time. so i just want to know if it is OK! the code belove(it is just for login in the code for Scraping its not ready) <?php curl_login('http://mywantedsite.com/login.php','user=******&pass=******','','off'); echo curl_grab_page('http://mywantedsite.com/somepage.php','','off'); function curl_login($url,$data,$proxy,$proxystatus){ $fp = fopen("cookie.txt", "w"); fclose($fp); $login = curl_init(); curl_setopt($login, CURLOPT_COOKIEJAR, "cookie.txt"); curl_setopt($login, CURLOPT_COOKIEFILE, "cookie.txt"); curl_setopt($login, CURLOPT_USERAGENT, "Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)"); curl_setopt($login, CURLOPT_TIMEOUT, 40); curl_setopt($login, CURLOPT_RETURNTRANSFER, TRUE); if ($proxystatus == 'on') { curl_setopt($login, CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($login, CURLOPT_HTTPPROXYTUNNEL, TRUE); curl_setopt($login, CURLOPT_PROXY, $proxy); } curl_setopt($login, CURLOPT_URL, $url); curl_setopt($login, CURLOPT_HEADER, TRUE); curl_setopt($login, CURLOPT_USERAGENT, $_SERVER['HTTP_USER_AGENT']); curl_setopt($login, CURLOPT_FOLLOWLOCATION, TRUE); curl_setopt($login, CURLOPT_POST, TRUE); curl_setopt($login, CURLOPT_POSTFIELDS, $data); ob_start(); // prevent any output return curl_exec ($login); // execute the curl command ob_end_clean(); // stop preventing output curl_close ($login); unset($login); } function curl_grab_page($site,$proxy,$proxystatus){ $ch = curl_init(); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); if ($proxystatus == 'on') { curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, FALSE); curl_setopt($ch, CURLOPT_HTTPPROXYTUNNEL, TRUE); curl_setopt($ch, CURLOPT_PROXY, $proxy); } curl_setopt($ch, CURLOPT_COOKIEFILE, "cookie.txt"); curl_setopt($ch, CURLOPT_URL, $site); ob_start(); // prevent any output return curl_exec ($ch); // execute the curl command ob_end_clean(); // stop preventing output curl_close ($ch); }

    Read the article

  • Are there any alternative to the header(); function ?

    - by Simon
    The thing is, I have a log-in page. And, when user enters Username & Password, they must be re-directed to success/failure page. Now, I have placed a "header('location:welcome.php');" after mysql rows are returned. But, it is giving me Header already sent errors, and I don't know much about PHP to do anything about it, let alone understand why it is happening. So, how to you transfer a user to another page after log-in data is verified? Same problem is happening with register, post, comment and search functions in my site.

    Read the article

  • How can I get class, property, and method data from files without executing their code, similar to R

    - by Chris
    I have a bunch of PHP files with classes, in them (although I can't be 100% sure that they won't have code outside of classes in them too), and I need to parse these files to get information about the classes, such as the names of the classes, the methods, the properties, whether they are private/public/static, etc. I looked at PHP's reflection classes and this is very close to what I want but the reflection doesn't seem to use external files and it appears to need to define the classes first. I need to make sure that none of the code is executed and I will be editing the files so I can't guarantee that they will even be error-free. Any suggestions? Thanks.

    Read the article

  • Why my query is not working?

    - by Poma
    my website has PHP command: mysql_query("SELECT * FROM users WHERE id=" . $_GET["id"]) or die(mysql_error()); When I enter URL http://example.com/index.php?id=1;%20UPDATE%20users%20SET%20password=123%20WHERE%20id=1 I get following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'UPDATE users SET password=abc WHERE id=1' at line 1 But in phpmyamin query executes successfully. What's wrong here? Why it doesn't execute in browser?

    Read the article

  • Secure method for linking to image files uploaded via custom CMS

    - by letseatfood
    How does one provide a direct URL for an image file (JPEG) that is secure? For example, if a PHP script writes uploaded images to directory http://www.somehost.com/images, is it okay to provide http://www.somehost.com/images/someimage.jpg as the URL, or is there a more secure way to do this? Should I look into something like the permalink feature that is a part of Wordpress? I am not sure if that is related. The main reason I ask is that I have a custom PHP/MySQL CMS for managing images. I would like for the client to be able to copy a link to the image they want and then include it in a TinyMCE text editor for inserting the image in their website. Thanks!

    Read the article

  • Error - Trying to get property of non-object

    - by Patrick Lanfranco
    I am currently getting this error on one of my files: /var/www/vhosts/httpdocs/generator/index.php on line 6 Line 6 would be resulting in: echo $results->GetBookCodesResult->BookCodes->BookInfo->ServiceCode; My code: <?php $config['soap_url'] = "http://myservice.com?WSDL"; if(isset($_REQUEST['codes'])) { $results = request_Data(explode("\n",$_REQUEST['codes'])); echo $results->GetBookCodesResult->BookCodes->BookInfo->ServiceCode; } .... What is the best method to have this fixed? Some advice would be appreciated.

    Read the article

  • file_get_contents not working

    - by DCD
    I am trying to read a file in with file_get_contents () - it's a remote HTTP file, and I've checked the URL and it's fine. Only it doesn't work. More to the point the the error message is the standard Firefox server error: The connection was reset The connection to the server was reset while the page was loading. ... rather than any form of PHP error. It also only took a couple of seconds to come back so it can't be hitting the script runtime limit - any ideas on what is going wrong here? It's PHP 5 on Apache 2, running on Windows btw.

    Read the article

  • Submit form without page reloading

    - by Camran
    I have a classifieds website, and on the page where ads are showed, I am creating a "Send a tip to a friend" form... So anybody who wants can send a tip of the ad to some friends email-adress. I am guessing the form must be submitted to a php page right? <form name='tip' method='post' action='tip.php'> Tip somebody: <input name="tip_email" type="text" size="30" onfocus="tip_div(1);" onblur="tip_div(2);"/> <input type="submit" value="Skicka Tips"/> <input type="hidden" name="ad_id" /> </form> When submitting the form, the page gets reloaded... I don't want that... Is there any way to make it not reload and still send the mail? Preferrably without ajax or jquery... Thanks

    Read the article

  • update in codeigniter works but displays an error message

    - by Charmie
    i was just wondering what could be the problem with a working code yet displays an error message such as this: A PHP Error was encountered Severity: Notice Message: Array to string conversion Filename: database/DB_active_rec.php Line Number: 1407 im trying to update fields in my database. I have this code and every tutorial are just the same for batch upload. It works anyway but the thing is it display such an error. this what i have in my model: function update2($data){ $this->db->update_batch('users',$data, "id"); } This what i have in my controller: public function updateValues(){ $this->load->model('get_db'); $newRow = array( array( 'id' => '3', 'firstname' => 'Rapphie' ), array( 'id' => '2', 'firstname' => 'Charmie' ) ); $this->get_db->update2($newRow); echo "it has been updated"; } please help.

    Read the article

  • How to allow three optional parameters in the URL by .htaccess?

    - by eij
    I have http://example.com and a PHP routing class that checks if some URL exists. I want to make a new route, which is: http://example.com/foo/bar/123 but as long as I open it, the Apache redirects me to an error page. So I'm using a .htaccess. The code is: RewriteEngine on RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*) /index.php [L] and it works, as long as I use http://example.com/foo, but once I add some other parameters, it redirects me to an error. I'm guessing that the rewrite code is wrong. Is it wrong? If yes, could you suggest me the good one? If no, where the problem could be located?

    Read the article

  • Is it possible to create a link that acts like a button and can carry out a function when clicked?

    - by Tim
    In PHP, I want to execute a function when a hyperlink is clicked. The only way I can think of doing this is by having the link attach a get parameter to the url when clicked and by doing an if statement that checks to see if that parameter exists and if so then have the function executed. But is there a way to do this like: <a href='#' onclick='<?php functionName(); ?>'> Obviously there are a million things wrong with this example but is it possible in any other way?

    Read the article

  • Timezone settings in MySQL - Using NOW()?

    - by matt74tm
    SOmewhat related to Doing calculations in MySQL vs PHP Right now, our database assumes that the system time is in UTC and uses that to calculate NOW(). PHP explicitly sets the timezone as UTC (so its impervious to server time zone shifts). An accidental shift of timezones on the server messed this relationship up at the database level and i'm now trying to figure out the ideal congiguration: configure Mysql to be in UTC, but also from the perspective that: our application may be on someone else's server where they might have a different TZ (so i cant set the timezone at the mysql/server level). How do i configure it at the specific database level?

    Read the article

  • Is checkdnsrr() function good enough to establish domain (in)availability?

    - by Stipe
    I want to create simple script to check domain availability. Can anybody tell me is this function enough to check domain availability before user can register: <?php $recordexists = checkdnsrr("www.google.com", "ANY"); if ($recordexists) echo "The domain name has been taken. Sorry!"; else echo "The domain name is available!"; ?> or should I go with some other whois script like http://www.mrscripts.co.uk/index.php?op=lite

    Read the article

  • Won't connect to the database

    - by user1657958
    I'm confused...I'm using the same code in a different document and in there it's not a problem to get a connection to the database. But in the new document it's just not working...(password, username, database name...all is checked and correct) :-/ <?php define ("DB_HOST", "db1234567.db.hello.com"); // set database host define ("DB_USER", "db1234567"); // set database user define ("DB_PASS","password123"); // set database password define ("DB_NAME","db1234567"); // set database name $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die("Couldn't make connection."); $db = mysql_select_db(DB_NAME, $link) or die("Couldn't select database"); ?> In the browser I get this: "Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'db1234567'@'123.123.12.12 (using password: YES) in /homepages/12/1234567/test/test.php on line 8 Couldn't make connection." Would be cool if someone could help me :) I'm not seeing any error... Thx!

    Read the article

  • Is there any way to rename or hide only one HTML tag?

    - by Jason
    Preface: I cannot rename the source tags or edit their IDs. Any changes to the tags must happen after they have been fetched. What I'm doing: using file_get_contents in PHP, I am requesting data from a remote site. This data is just two <p> tags. I need to hide or rename the second of the two <p> tags. Is this possible with PHP or jQuery? What I'm working with: <p>Hello my name is test</p><p>I like studying geology.</p>

    Read the article

  • What type of data should I send to view?

    - by Vizualni
    Hello, this question I've been asking myself since the day I started programming in MVC way. Should I send to view arrays filled with data or should I send it as on objects I retrieved from database? My model returns me data as objects. What would be the best way to create such a thing? $new_data = $model->find_by_id(1); echo $new_data->name; $new_data->name= "whatever"; $new_data->save(); For example. view.php echo $object->name; or echo $array['name'] Language is php :).

    Read the article

< Previous Page | 538 539 540 541 542 543 544 545 546 547 548 549  | Next Page >