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  • PHP PDO - Num Rows

    - by Ian
    PDO apparently has no means to count the number of rows returned from a select query (mysqli has the num_rows variable). Is there a way to do this, short of using count($results->fetchAll()) ?

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  • Fiscal year, quarters, student table, and faculty table... How do I relate these?!

    - by yuudachi
    I have a student and faculty table. The primary key for student is studendID (SID) and faculty's primary key is facultyID, naturally. Student has an advisor column and a requested advisor column, which are foreign key to faculty. That's simple enough, right? However, now I have to throw in dates. I want to be able to view who their advisor was for a certain quarter (such as 2009 Winter) and who they had requested. The result will be a table like this: Year | Term | SID | Current | Requested ------------------------------------------------ 2009 | Winter | 860123456 | 1 | NULL 2009 | Winter | 860445566 | 3 | NULL 2009 | Winter | 860369147 | 5 | 1 And then if I feel like it, I could also go ahead and view a different year and a different term. I am not sure how these new table(s) will look like. Will there be a year table with three columns that are Fall, Spring and Winter? And what will the Fall, Spring, Winter table have? I am new to the art of tables, so this is baffling me... Also, I feel I should clarify how the site works so far now. Admin can approve student requests, and what happens is that the student's current advisor gets overwritten with their request. However, I think I should not do that anymore, right?

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  • SQL conditional row insert

    - by Pablo
    Is it possible to insert a new row if a condition is meet? For example, i have this table with no primary key nor uniqueness +----------+--------+ | image_id | tag_id | +----------+--------+ | 39 | 8 | | 8 | 39 | | 5 | 11 | +----------+--------+ I would like to insert a row if a combination of image_id and tag_id doesn't exists for example; INSERT ..... WHERE image_id!=39 AND tag_id!=8

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  • Why is the ( ) mandatory in the SQL statement select * from gifts INNER JOIN sentgifts using (giftID

    - by Jian Lin
    Why is the ( ) mandatory in the SQL statement select * from gifts INNER JOIN sentgifts using (giftID); ? The ( ) usually is for specifying grouping of something. But in this case, are we supposed to be able to use 2 or more field names... in the example above, it can be all clear that it is 1 field, is it just that the parser is not made to bypass the ( ) when it is all clear? (such as in the language Ruby).

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  • Need an alternative to two left joins.

    - by Scarface
    Hey guys quick question, I always use left join, but when I left join twice I always get funny results, usually duplicates. I am currently working on a query that Left Joins twice to retrieve the necessary information needed but I was wondering if it were possible to build another select statement in so then I do not need two left joins or two queries or if there were a better way. For example, if I could select the topic.creator in table.topic first AS something, then I could select that variable in users and left join table.scrusersonline. Thanks in advance for any advice. SELECT * FROM scrusersonline LEFT JOIN users ON users.id = scrusersonline.id LEFT JOIN topic ON users.username = topic.creator WHERE scrusersonline.topic_id = '$topic_id' The whole point of this query is to check if the topic.creator is online by retrieving his name from table.topic and matching his id in table.users, then checking if he is in table.scrusersonline. It produces duplicate entries unfortunately and is thus inaccurate in my mind.

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  • how to specify a BIGINT in a ruby scaffold?

    - by webdestroya
    I am trying to create a model in ruby that uses a BIGINT datatype (as opposed to the INT done by :integer). I have search all over Google, but all I seem to find is "run an SQL statement to alter the table to a BIGINT" - This seems a bit hack-ish to me, so I wanted to know if there was a way to specify a bigint in the ruby system like :big_int or something Any ideas?

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  • Analyzing Web Application Speed

    - by Amy
    I'm a bit confused because the logical/programmer brain in me says that if all things are constant, the speed of a function must be constant. I am working on a PHP web application with jqGrid as a front end for showing the data. I am testing on my personal computer, so network traffic does not apply. I make an HTTP request to a PHP function, it returns the data, and then jqGrid renders it. What has me befuddled is that sometimes, Firebug reports that this is taking 300-600 milliseconds sometimes, and sometimes, it's taking 3.68 seconds. I can run the request over and over again, with very radically different response times. The query is the same. The number of users on the system is the same. No network latency. Same code. I'm not running other applications on the computer while testing. I could understand query caching improving performance on subsequent requests, but the speed is just fluctuating wildly with no rhyme or reason. So, my question is, what else can cause such variability in the response time? How can I determine what's doing it? More importantly, is there any way to get things more consistent?

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  • how to have defined connection within function for pdo communication with DB

    - by Scarface
    hey guys I just started trying to convert my query structure to PDO and I have come across a weird problem. When I call a pdo query connection within a function and the connection is included outside the function, the connection becomes undefined. Anyone know what I am doing wrong here? I was just playing with it, my example is below. include("includes/connection.php"); function query(){ $user='user'; $id='100'; $sql = 'SELECT * FROM users'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($user, $id)); // now iterate over the result as if we obtained // the $stmt in a call to PDO::query() while($r = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "$r[username] $r[id] \n"; } } query();

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  • Create Downloadable CSV File from PHP Script

    - by Aphex22
    How would I create a formatted version of the following PHP script as a downloadable CSV file from the code below (1.0) At the moment the fputcsv function is currently dumping the unparsed PHP/HTML code into a CSV file. This is incorrect. The downloaded CSV file should contain the columns and rows generated from the code at (1.0) as shown in the image link below. I've tried using the following code at the top of the PHP file: // output headers so that the file is downloaded rather than displayed header('Content-Type: text/csv; charset=utf-8'); header('Content-Disposition: attachment; filename=amazon.csv'); // create a file pointer connected to the output stream $output = fopen('php://output', 'w'); $mysql_hostname = ""; $mysql_user = ""; $mysql_password = ""; $mysql_database = ""; $bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Could not connect database"); mysql_select_db($mysql_database, $bd) or die("Could not select database"); $sql = "select * from product WHERE on_amazon = 'on' AND active = 'on'"; $result = mysql_query($sql) or die ( mysql_error() ); // loop over the rows, outputting them while ($sql_result = mysql_fetch_assoc($sql)) fputcsv($output, $sql_result); 1.0 The start of the code outputs the column headings for the CSV file: // set headers echo " item_sku, external_product_id, external_product_id_type, item_name, brand_name, manufacturer, product_description, feed_product_type, update_delete, part_number, model, standard_price, list_price, currency, quantity, product_tax_code, product_site_launch_date, merchant_release_date, restock_date ... <br>"; And then follows PHP script for the column values // load all stock while ($line = mysql_fetch_assoc($result) ) { ?> <?php $size_suffix = array ("",'_chain','_con_b','_con_c'); $arrayLength = count ($size_suffix); for($y=0;$y<$arrayLength;$y++) { //Possible size array to loop through when checking quantity $con_size = array (36,365,37,375,38,385,39,395,40,405,41,415,42,425,43,435,44,445,45,455,46,465,47,475,48,485); $arrlength=count($con_size); for($x=0;$x<$arrlength;$x++) { // check if size is available if($line['quantity_c_size_'.$con_size[$x].$size_suffix[$y]] > 0 ) { ?> <!-- item sku --> <?=$line['product_id']?>, <!-- external product id --> <?=$line['code_size_'.$con_size[$x].'']?>, <? // external product id type $barcode = $line['code_size_'.$con_size[$x]]; $trim_barcode = trim($barcode); $count = strlen($trim_barcode); if ($count == 12) { echo "UPC"; } if ($count == 13) { echo "EAN"; } elseif ($count < 12) { echo " "; } ?>, <!-- item name --> <?=$line['title']?>, <? // brand_name $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <? // manufacturer $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <!-- product description --> <?=preg_replace('/[^\da-z]/i', ' ', $line['amazon_desc']) ?>, <!-- feed product type --> Shoes, , , , <!-- standard price --> <?=$line['price']?>, , <!-- currency --> GBP, <!-- quantity --> <?=$line['quantity_size_'.$con_size[$x].$size_suffix[$y]]?>, , <!-- product site launch date --> <?=$line['added_y']?>-<?=$line['added_m']?>-<?=$line['added_d']?>, <!-- merchat release date --> <?=$line['added_y']?>-<?=$line['added_m']?>-<?=$line['added_d']?>, , , , , <!-- item package quantity --> 1, , , , , <!-- fulfillment latency --> 2, <!-- max aggregate ship quantity --> 1, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , <!-- main image url, url1, url2, url3 --> http://www.getashoe.co.uk/full/<?=$line['product_id']?>_1.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_2.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_3.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_4.jpg, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , <!-- heel height --> <?=$line['heel']?>, , , , , , , , , , , <!-- colour name --> <?=$line['colour']?>, <!-- colour map --> <? $colour = preg_replace('/[()]/i', ' ', $line['colour']); if (preg_match( '/[\/].*/i', $colour)) { echo 'Multicolour'; } if (preg_match( '/off.*/i', $colour)) { echo 'Off-White'; } elseif( preg_match( '/white.*/i', $colour)) { echo 'White'; } elseif( preg_match( '/moro.*/i', $colour)) { echo 'Brown'; } elseif( preg_match( '/morado.*/i', $colour)) { echo 'Purple'; } elseif( preg_match( '/cream.*/i', $colour)) { echo 'Off-White'; } elseif( preg_match( '/pewter.*/i', $colour)) { echo 'Silver'; } elseif( preg_match( '/yellow.*/i', $colour)) { echo 'Yellow'; } elseif( preg_match( '/camel.*/i', $colour)) { echo 'Beige'; } elseif( preg_match( '/navy.*/i', $colour)) { echo 'Blue'; } elseif( preg_match( '/tan.*/i', $colour)) { echo 'Brown'; } elseif( preg_match( '/rainbow.*/i', $colour)) { echo 'Multicolour'; } elseif( preg_match( '/orange.*/i', $colour)) { echo 'Orange'; } elseif( preg_match( '/leopard.*/i', $colour)) { echo 'Multicolour'; } elseif( preg_match( '/red.*/i', $colour)) { echo 'Red'; } elseif( preg_match( '/pink.*/i', $colour)) { echo 'Pink'; } elseif( preg_match( '/purple.*/i', $colour)) { echo 'Purple'; } elseif( preg_match( '/blue.*/i', $colour)) { echo 'Blue'; } elseif( preg_match( '/green.*/i', $colour)) { echo 'Green'; } elseif( preg_match( '/brown.*/i', $colour)) { echo 'Brown'; } elseif( preg_match( '/grey.*/i', $colour)) { echo 'Grey'; } elseif( preg_match( '/black.*/i', $colour)) { echo 'Black'; } elseif( preg_match( '/gold.*/i', $colour)) { echo 'Gold'; } elseif( preg_match( '/silver.*/i', $colour)) { echo 'Silver'; } elseif( preg_match( '/multi.*/i', $colour)) { echo 'Multicolour'; } elseif( preg_match( '/beige.*/i', $colour)) { echo 'Beige'; } elseif( preg_match( '/nude.*/i', $colour)) { echo 'Beige'; } ?>, <!-- size name --> <? echo $con_size[$x];?>, <!-- size map --> <? if ($con_size[$x] == 36) { echo "3 UK"; } elseif ($con_size[$x] == 37 ) { echo "4 UK"; } elseif ($con_size[$x] == 38) { echo "5 UK"; } elseif ($con_size[$x] == 39 ) { echo "6 UK"; } elseif ($con_size[$x] == 40 ) { echo "7 UK"; } elseif ($con_size[$x] == 41) { echo "8 UK"; } elseif ($con_size[$x] == 42) { echo "9 UK"; } elseif ($con_size[$x] == 43) { echo "10 UK"; } elseif ($con_size[$x] == 44 ) { echo "11 UK"; } elseif ($con_size[$x] == 45 ) { echo "12 UK"; } elseif ($con_size[$x] == 46 ) { echo "13 UK"; } elseif ($con_size[$x] == 47 ) { echo "14 UK"; } elseif ($con_size[$x] == 48 ) { echo "15 UK"; } elseif ($con_size[$x] == 365) { echo "3.5 UK"; } elseif ($con_size[$x] == 375 ) { echo "4.5 UK"; } elseif ($con_size[$x] == 385) { echo "5.5 UK"; } elseif ($con_size[$x] == 395 ) { echo "6.5 UK"; } elseif ($con_size[$x] == 405 ) { echo "7.5 UK"; } elseif ($con_size[$x] == 415) { echo "8.5 UK"; } elseif ($con_size[$x] == 425) { echo "9.5 UK"; } elseif ($con_size[$x] == 435) { echo "10.5 UK"; } elseif ($con_size[$x] == 445 ) { echo "11.5 UK"; } elseif ($con_size[$x] == 455 ) { echo "12.5 UK"; } elseif ($con_size[$x] == 465 ) { echo "13.5 UK"; } elseif ($con_size[$x] == 475 ) { echo "14.5 UK"; } elseif ($con_size[$x] == 485 ) { echo "15.5 UK"; } ?>, <br> <? // finish checking if size is available } } } ?> I've included an image of how the CSV file should appear. https://i.imgur.com/ZU3IFer.png Any help would be great.

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  • Javascript Confirm Delete in One PHP File (on href)

    - by gamerzfuse
    <p><span class="linky"><a href="deletephone.php?id=' . $row['id'] . '">Delete Phone</a></span></p><br /> I have the above code that I am using to link to a delete script. I want to somehow incorporate Javascript with a simple onclick confirmation. This way if they choose OK, I can run the code to delete the item from the database, but if they choose Cancel then I can cancel the operation and do nothing. I have tried a whole variety of functions with changing the window.location to the delete file, and trying to cancel the href= if they choose Cancel, but it always goes to the link regardless of what the user clicks. I would like to be able to keep the delete functions inside the same PHP file if possible, but this is not necessary at all. Thanks in advance! ASIDE: If there is a simple PHP way to check IF the alert was confirmed or denied, that could work also. Any way to check what the user chooses and then run my simple delete PHP command.

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  • error come to execute the stored procedure using with open xml in sql server

    - by Muthumari
    Hi, i execute the below stored procedure.but it shows the error. The error is 'Incorrect syntax near '.'.i.e error shows in 'xmlFields.Country' please look this stored procedure also and help me thanks, in advance create procedure sp_SuUpdateSUADUsersStatus ( @FinalEMPCode nvarchar(50), @xmlFields NTEXT ) AS DECLARE @CityIDReturn INT SET NOCOUNT ON BEGIN DECLARE @hdoc INT EXEC sp_xml_preparedocument @hdoc OUTPUT, @xmlFields BEGIN EXEC @CityIDReturn=sp_SuSaveADUsersLocation @Country=xmlFields.Country, xmlFields.State,xmlFields.City FROM OPENXML(@hDoc, 'EmpCode/User', 2) WITH (Country nvarchar(500),State nvarchar(500),City nvarchar(500)) as xmlFields where xmlFields.Country <>'' and xmlFields.State <>'' and xmlFields.City <>'') END EXEC sp_xml_removedocument @hdoc End

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  • Remove duplicate records/objects uniquely identified by multiple attributes

    - by keruilin
    I have a model called HeroStatus with the following attributes: id user_id recordable_type hero_type (can be NULL!) recordable_id created_at There are over 100 hero_statuses, and a user can have many hero_statuses, but can't have the same hero_status more than once. A user's hero_status is uniquely identified by the combination of recordable_type + hero_type + recordable_id. What I'm trying to say essentially is that there can't be a duplicate hero_status for a specific user. Unfortunately, I didn't have a validation in place to assure this, so I got some duplicate hero_statuses for users after I made some code changes. For example: user_id = 18 recordable_type = 'Evil' hero_type = 'Halitosis' recordable_id = 1 created_at = '2010-05-03 18:30:30' user_id = 18 recordable_type = 'Evil' hero_type = 'Halitosis' recordable_id = 1 created_at = '2009-03-03 15:30:00' user_id = 18 recordable_type = 'Good' hero_type = 'Hugs' recordable_id = 1 created_at = '2009-02-03 12:30:00' user_id = 18 recordable_type = 'Good' hero_type = NULL recordable_id = 2 created_at = '2009-012-03 08:30:00' (Last two are not a dups obviously. First two are.) So what I want to do is get rid of the duplicate hero_status. Which one? The one with the most-recent date. I have three questions: How do I remove the duplicates using a SQL-only approach? How do I remove the duplicates using a pure Ruby solution? Something similar to this: http://stackoverflow.com/questions/2790004/removing-duplicate-objects. How do I put a validation in place to prevent duplicate entries in the future?

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  • SQL How to join multiplue columns with same name to one column

    - by Choi Shun Chi
    There is a super class account {User, TYPE} and subclasses saving{User, ID, balance,TYPE,interest,curency_TYPE} time{User,ID,balance,TYPE,interest,curency_TYPE,start_date,due_date,period} fore{User,ID,balance,interest,curency_TYPE} User and TYPE is the primary key of account and foreign key of three subclasses ID is primary key of three subclasses how to make a list of showing all IDs in one column?Also the same as balance and TYPE meet the problem I considered a.ID as saving, b.ID as time but it showing them separately

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  • SQL Query Math Gymnastics

    - by keruilin
    I have two tables of concern here: users and race_weeks. User has many race_weeks, and race_week belongs to User. Therefore, user_id is a fk in the race_weeks table. I need to perform some challenging math on fields in the race_weeks table in order to return users with the most all-time points. Here are the fields that we need to manipulate in the race_weeks table. races_won (int) races_lost (int) races_tied (int) points_won (int, pos or neg) recordable_type(varchar, Robots can race, but we're only concerned about type 'User') Just so that you fully understand the business logic at work here, over the course of a week a user can participate in many races. The race_week record represents the summary results of the user's races for that week. A user is considered active for the week if races_won, races_lost, or races_tied is greater than 0. Otherwise the user is inactive. So here's what we need to do in our query in order to return users with the most points won (actually net_points_won): Calculate each user's net_points_won (not a field in the DB). To calculate net_points, you take (1000 * count_of_active_weeks) - sum(points__won). (Why 1000? Just imagine that every week the user is spotted a 1000 points to compete and enter races. We want to factor-out what we spot the user because the user could enter only one race for the week for 100 points, and be sitting on 900, which we would skew who actually EARNED the most points.) This one is a little convoluted, so let me know if I can clarify further.

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  • Query broke down and left me stranded in the woods

    - by user1290323
    I am trying to execute a query that deletes all files from the images table that do not exist in the filters tables. I am skipping 3,500 of the latest files in the database as to sort of "Trim" the table back to 3,500 + "X" amount of records in the filters table. The filters table holds markers for the file, as well as the file id used in the images table. The code will run on a cron job. My Code: $sql = mysql_query("SELECT * FROM `images` ORDER BY `id` DESC") or die(mysql_error()); while($row = mysql_fetch_array($sql)){ $id = $row['id']; $file = $row['url']; $getId = mysql_query("SELECT `id` FROM `filter` WHERE `img_id` = '".$id."'") or die(mysql_error()); if(mysql_num_rows($getId) == 0){ $IdQue[] = $id; $FileQue[] = $file; } } for($i=3500; $i<$x; $i++){ mysql_query("DELETE FROM `images` WHERE id='".$IdQue[$i]."' LIMIT 1") or die("line 18".mysql_error()); unlink($FileQue[$i]) or die("file Not deleted"); } echo ($i-3500)." files deleted."; Output: 0 files deleted. Database contents: images table: 10,000 rows filters table: 63 rows Amount of rows in filters table that contain an images table id: 63 Execution time of php script: 4 seconds +/- 0.5 second Relevant DB structure TABLE: images id url etc... TABLE: filter id img_id (CONTAINS ID FROM images table) etc...

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  • Complicated SQL query

    - by Yandawl
    Please bare with me this is difficult to explain xD http://img90.imageshack.us/i/croppercapture1.png/ This is based on an undergraduate degree course where a student takes many units (say 4 core units and 1 optional unit per year). tblAwardCoreUnits and tblAwardOptUnits store which units are optional and core for which award, hence the relationship to tblAward and tblStudentCoreUnits and tblStudentOptUnits store the particular instances of those units which a particular student is taking. Secondly, a unit can have multiple events (say a lecture and a unit) and each of those events has sessions in which a student can attend, hence tblEvents, tblSessions and tblAttendances. The query I am trying to produce is to get a list of all level one students, grouped by their award that lists the percentage of attendances in all the units in the current level. I've tried and tried with this and the following is the best I've managed to come up with so far... I'd REALLY appreciate any help you can give with this! SELECT tblStudents.enrolmentNo, tblStudents.forename, tblStudents.surname, tblAwards.title, (SELECT COUNT((tblAttendances.attended + tblAttendances.authorisedAbsence)) AS SumOfAttendances FROM tblAttendances INNER JOIN (tblStudents ON tblStudents.enrolmentNo = tblAttendances.enrolmentNo)) / FROM tblUnits, tblAwards INNER JOIN ((tblStudents INNER JOIN tblStudentOptUnit ON tblStudents.studentID = tblStudentOptUnit.studentID) INNER JOIN tblStudentCoreUnit ON tblStudents.studentID = tblStudentCoreUnit.studentID) ON tblAwards.awardID = tblStudents.awardID WHERE (((tblStudents.level)="1") AND ((tblStudents.status)="enrolled")) GROUP BY tblAwards.title ORDER BY tblStudents.forname;

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  • details in one Row without any redundancy in the CATID

    - by alkitbi
    $query1 = "select * from linkat_link where emailuser = '$email2' or linkname ='$domain_name2' ORDER BY date desc LIMIT $From,$PageNO"; id   catid      discription            price ------------------------------------ 1         1     domain name     100 2         1      book                  50 3        2      hosting               20 4        2      myservice           20 in this script i have one problem , if i have an ID for Each Cantegory , i have some duplicated CATID which has different content but shares the same CATID, i need to make any duplicated CATID to show in one , and all the discription will be in the same line (Cell) on the same row . So Each CatID will have all the details in one Row without any redundancy in the CATID

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  • Favouriting things in a database - most efficient method of keeping track?

    - by a2h
    I'm working on a forum-like webapp where I'd like to allow users to favourite an item so that they can keep track of it, and also so that others can see how many times an item's been favourited. The problem is, I'm unsure on the best practices for databases, which includes this situation. I have two ideas in my head on how to do this: Add an extra column to the user table and store things like so: "|2|5|73|" Add an extra table with at least two columns, one for referencing an item, the other for referencing a user. I feel uncomfortable about going for the second method as it involves an extra table, and potentially more queries would be required. Perhaps these beliefs aren't an issue, as I have little understanding of databases beyond simply working with table layouts and basic queries.

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  • Avoiding Nested Queries

    - by Midhat
    How Important is it to avoid nested queries. I have always learnt to avoid them like a plague. But they are the most natural thing to me. When I am designing a query, the first thing I write is a nested query. Then I convert it to joins, which sometimes takes a lot of time to get right. And rarely gives a big performance improvement (sometimes it does) So are they really so bad. Is there a way to use nested queries without temp tables and filesort

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  • Why is str_replace not replacing this string?

    - by Niall
    I have the following PHP code which should load the data from a CSS file into a variable, search for the old body background colour, replace it with the colour from a submitted form, resave the CSS file and finally update the colour in the database. The problem is, str_replace does not appear to be replacing anything. Here is my PHP code (stored in "processors/save_program_settings.php"): <?php require("../security.php"); $institution_name = mysql_real_escape_string($_POST['institution_name']); $staff_role_title = mysql_real_escape_string($_POST['staff_role_title']); $program_location = mysql_real_escape_string($_POST['program_location']); $background_colour = mysql_real_escape_string($_POST['background_colour']); $bar_border_colour = mysql_real_escape_string($_POST['bar_border_colour']); $title_colour = mysql_real_escape_string($_POST['title_colour']); $url = $global_variables['program_location']; $data_background = mysql_query("SELECT * FROM sents_global_variables WHERE name='background_colour'") or die(mysql_error()); $background_output = mysql_fetch_array($data_background); $css = file_get_contents($url.'/default.css'); $str = "body { background-color: #".$background_output['data']."; }"; $str2 = "body { background-color: #".$background_colour."; }"; $css2 = str_replace($str, $str2, $css); unlink('../default.css'); file_put_contents('../default.css', $css2); mysql_query("UPDATE sents_global_variables SET data='{$institution_name}' WHERE name='institution_name'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$staff_role_title}' WHERE name='role_title'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$program_location}' WHERE name='program_location'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$background_colour}' WHERE name='background_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$bar_border_colour}' WHERE name='bar_border_colour'") or die(mysql_error()); mysql_query("UPDATE sents_global_variables SET data='{$title_colour}' WHERE name='title_colour'") or die(mysql_error()); header('Location: '.$url.'/pages/start.php?message=program_settings_saved'); ?> Here is my CSS (stored in "default.css"): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } I've run some checks using the following code in the PHP file: echo $css . "<br><br>" . $str . "<br><br>" . $str2 . "<br><br>" . $css2; exit; And it outputs (as you can see it's not changing anything in the CSS): @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; } body { background-color: #CCCCFF; } body { background-color: #FF5719; } @charset "utf-8"; /* CSS Document */ body,td,th { font-family: Arial, Helvetica, sans-serif; font-size: 14px; color: #000; } body { background-color: #CCCCFF; } .main_table th { background:#003399; font-size:24px; color:#FFFFFF; } .main_table { background:#FFF; border:#003399 solid 1px; } .subtitle { font-size:20px; } input#login_username, input#login_password { height:30px; width:300px; font-size:24px; } input#login_submit { height:30px; width:150px; font-size:16px; } .timetable_cell_lesson { width:100px; font-size:10px; } .timetable_cell_tutorial_a, .timetable_cell_tutorial_b, .timetable_cell_break, .timetable_cell_lunch { width:100px; background:#999; font-size:10px; }

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  • Selecting all but one field?

    - by gsquare567
    instead of SELECT * FROM mytable, i would like to select all fields EXCEPT one (namely, the 'serialized' field, which stores a serialized object). this is because i think that losing that field will speed up my query by a lot. however, i have so many fields and am quite the lazy guy. is there a way to say... `SELECT ALL_ROWS_EXCEPT(serialized) FROM mytable` ? thanks!

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  • How to get rank based on SUM's?

    - by Kenan
    I have comments table where everything is stored, and i have to SUM everything and add BEST ANSWER*10. I need rank for whole list, and how to show rank for specified user/ID. Here is the SQL: SELECT m.member_id AS member_id, (SUM(c.vote_value) + SUM(c.best)*10) AS total FROM comments c LEFT JOIN members m ON c.author_id = m.member_id GROUP BY c.author_id ORDER BY total DESC LIMIT {$sql_start}, 20

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