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  • select & print multiple value from dropdown list

    - by sandy
    hi , in this code how can selected multiple value from dropdown list <?php include ("connect.php"); $member_id = intval($_POST['sector_list']); if($member_id == 0) { // Default choice was selected } else { $res = mysql_query("SELECT * FROM members WHERE MemberID = $member_id LIMIT 1"); if(mysql_num_rows($res) == 0) { // Not a valid member } else { // The member is in the database } } ?> <form method="post" action=""> <input type="hidden" name="sector" value="sector_list"> <select name="sector_list" class="inputstandard" multiple="multiple"> <option value="0">send to</option> <?php $result = mysql_query('SELECT * from members') or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo '<option value="' . $row['MemberID'] . '">' . $row['MemberName']. '</option>'; } ?> </select> </form> assume the drop down list contain on (a,s,d,f,g,h,j,) users selects multiple value ( a,s,j) output = a,s,j not only j ???

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  • Upgrade PHP to 5.3 in Ubuntu Server 8.04 with Plesk 9.5

    - by alcuadrado
    I have a dedicated server with Ubuntu 8.04, and really need to upgrade php to 5.3 version in order to deploy a new version of the system. This version of php is the default one in ubuntu 10.04, so I considered upgrading the OS, but after trying that, I lost my plesk installation, which annoyed my client. I tried adding the dotdeb.org repositories, but don't know why, after running an apt-get upgrade, I get this error: # apt-get upgrade Reading package lists... Done Building dependency tree Reading state information... Done The following packages have been kept back: libapache2-mod-php5 php5 php5-cgi php5-cli php5-common php5-curl php5-gd php5-imap php5-mysql php5-sqlite php5-xsl 0 upgraded, 0 newly installed, 0 to remove and 11 not upgraded. Any idea why is this happenning? Or do you know any alternative method (except compiling my own binaries) to upgrade php or update ubuntu without loosing plesk? Thanks!

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  • how to return multiple array items using json/jquery

    - by Scarface
    Hey guys, quick question, I have a query that will usually return multiple results from a database, while I know how to return one result, I am not sure how to return multiple in jquery. I just want to take each of the returned results and run them through my prepare function. I have been trying to use 'for' to handle the array of data but I don't think it can work since I am returning different array values. If anyone has any suggestions, I would really appreciate it. JQUERY RETRIEVAL for(i=0; i < json.rows; i++) { $('#users_online').append(online_users(json[i])); $('#online_list-' + count2).fadeIn(1500); } PHP PROCESSING $qryuserscount1="SELECT active_users.username,COUNT(scrusersonline.id) AS rows FROM scrusersonline LEFT JOIN active_users ON scrusersonline.id=active_users.id WHERE topic_id='$topic_id'"; $userscount1=mysql_query($qryuserscount1); while ($row = mysql_fetch_array($userscount1)) { $onlineuser= $row['username']; $rows=$row['rows']; if ($username==$onlineuser){ $str2= "<a href=\"statistics.php?user=$onlineuser\"><div class=\"me\">$onlineuser</div></a>"; } else { $str2= "<b><a href=\"statistics.php?user=$onlineuser\"><div class=\"others\">$onlineuser</div></a></b>"; } $data['rows']=$rows; $data['entry']=$str1.$str2; }

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  • SHA function issues

    - by Damian James
    I have this php code from my login.php if (isset($_POST['logIn'])) { $errmsg = ""; $logname = mysqli_real_escape_string($dbc, trim($_POST['usernameIn'])); $logpassword = mysqli_real_escape_string($dbc, trim($_POST['passwordIn'])); $query = "SELECT user_id, username FROM members WHERE username = '$logname' AND password = SHA('$logpassword')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); setcookie('user_id', $row['user_id'], time() + (60 * 60 * 24 * 30)); //expires after 30 days setcookie('username', $row['username'], time() + (60 * 60 * 24 * 30)); $home = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index.php'; header('Location: ' . $home); } else { $errmsg = '<p class="errormsg">Username or password is incorrect.</p>'; } } And for some reason, it always ends up setting $errmsg in the else statement. I am sure that I'm entering information (username,password) that is correct and exists in the database. I insert my values (from a signup script) using this query: $query = "INSERT INTO members (username, password, email) VALUES ('$username', SHA('$password'), '$email')"; Anyone see the problem with this script? Thanks!

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  • How do I check if output stream of a socket is closed?

    - by Roman
    I have this code: public void post(String message) { output.close(); final String mess = message; (new Thread() { public void run() { while (true) { try { output.println(mess); System.out.println("The following message was successfully sent:"); System.out.println(mess); break; } catch (NullPointerException e) { try {Thread.sleep(1000);} catch (InterruptedException ie) {} } } } }).start(); } As you can see I close the socket in the very beginning of the code and then try to use it to send some information to another computer. The program writes me "The following message was successfully sent". It means that the NullPointerException was not thrown. So, does Java throw no exception if it tries to use a closed output stream of a socket? Is there a way to check if a socket is closed or opened? ADDED I initialize the socket in the following way: clientSideSocket = new Socket(hostname,port); PrintWriter out = new PrintWriter(clientSideSocket.getOutputStream(), true); browser.output = out;

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  • Submit information to url, but also open PDF

    - by Mad Ducky Digital Branding
    I have a client whose desire is to have her Wordpress blog show a MailChimp form on her home page as a gateway to a .pdf. I need the following behavior to occur when the user clicks "Submit": execute the included MailChimp's javascript file; this ensures the form was properly filled, and then performs the sign-up to the newsletter list (don't need help with this part) then show the user an informational PDF for download or viewing EDIT: The logical order was flipped from when I originally posted this. The script should execute, and only if the script gets executed properly should the PDF show to the user Note: My experience level with HTML and PHP is 3/4, and with JS I am 2/4 EDIT: (seems more like 1/4 at this point lol). If my research is correct, PHP (server-side language) would be used to do that which the client wants. Additional validation is not necessary beyond what MailChimp's script provides (it ensures that user has submitted a completed form) is not necessary in this case (the client says it's ok if the e-mail isn't valid at all). EDIT: Reworded this sentence from original post to be more clear The .pdf URL and content is static, and simply needs to be shown, not generated. ----RESEARCH---- I know that the Mailchimp form uses the following line to actually submit the information, but I want to do the action mentioned below, as well as open the aforementioned .pdf: <form action="http://*BLAH*.us2.list-manage.com/subscribe/post?u=*BLAHBLAH*&amp;id=*BLAHBLAHBLAH*" method="post" id="mc-embedded-subscribe-form" name="mc-embedded-subscribe-form" class="validate" target="_blank"> I am reading on other sites that I can conceivably point "action" to a .php file, but if there is a way to do this with javascript - since its using the .js file that I created for that already anyways, then I would be most happy. Barring that, I'll take what I can get.. ----SOLUTION?---- ...

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  • Comments not Getting Inserted into MySQL Table

    - by John
    Hello, I'm trying to use the code below for a comment system. It doesn't work. The info I'm trying to insert into the MySQL table "comment" isn't getting put there. Any idea(s) why it is not working? Thanks in advance, John On comments.php: echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <label class="addacomment" for="title">Add a comment:</label> <input class="commentsubfield" name="comment" type="title" id="comment" maxlength="1000"> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; On comments2.php: $comment = $_POST['comment']; $uid = $_POST['uid']; $subid = $_POST['submissionid']; mysql_query("INSERT INTO comment VALUES (NULL, '$uid', '$subid', '$comment', NULL, NULL)");

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  • Getting XAMPP to work with multiple version of PHP

    - by Pennf0lio
    How can I install XAMPP to work with different versions of PHP? I use XAMPP because some of the scripts are buggy when run in WAMP. I use WAMP because it supports different versions of PHP. But now I would like to streamline it down to just XAMPP so that my web development would be easier to manage. Is it possible to configure XAMPP to work with more than one version of PHP? Or is it something that I have to look for in an alternative solution? Note: I'm running on Windows 7.

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  • ajax-based login fails: IE6 and IE7 ajax calls delete session data (session_id however is kept)

    - by mateipavel
    This question comes after two days of testing and debugging, right after the shock I had seeing that none of the websites i build using ajax-based login work in IE<8 The most simplified scenario si this: 1. mypage.php : session_start(); $_SESSION['mytest'] = 'x'; <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"> </script> <script type="text/javascript"> function loadit() { $.post('http://www.mysite.com/myajax.php', {action: 'test'}, function(result){alert(result);}, 'html'); } </script> <a href="javascript:void(0);" onclick="loadit(); return false;">test link</a> 2. myajax.php session_start(); print_r($_SESSION); print session_id(); When I click the "test link", the ajax call is made and the result is alert()-ed: IE6: weird bullet-character (&bull;) IE7: Array( ) <session_id> IE8/FF (Expected behaviour): Array( [mytest] => 'x' ) <session_id> I would really appreciate some pointers regarding: 1. why this happens 2. how to fix it Thank you.

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  • jquery ui autocomplete with database

    - by user301766
    I fairly new to JQuery and perhaps trying to achieve something that might be abit harder for a beginner. However I am trying to create an autocomplete that sends the current value to a PHP script and then returns the necessary values. Here is my Javascript code $("#login_name").autocomplete({ source: function(request, response) { $.ajax({ url: "http://www.myhost.com/myscript.php", dataType: "jsonp", success: function(data) { alert(data); response($.map(data, function(item) { return { label: item.user_login_name, value: item.user_id } })) } }) }, minLength: 2 }); And here is the the last half of "myscript.php" while($row = $Database->fetch(MYSQLI_ASSOC)) { foreach($row as $column=>$val) { $results[$i][$column] = $val; } $i++; } print json_encode($results); Which produces the following output [{"user_id":"2","user_login_name":"Name1"},{"user_id":"3","user_login_name":"Name2"},{"user_id":"4","user_login_name":"Name3"},{"user_id":"5","user_login_name":"Name4"},{"user_id":"6","user_login_name":"Name5"},{"user_id":"7","user_login_name":"Name6"}] Can anyone tell me where I am going wrong please? Starting to get quite frustrated. The input box just turns "white" and no options are shown. The code does work if I specify an array of values.

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  • Cakephp Function in mode not executing

    - by Rixius
    I have a function in my Comic Model as such: <?php class Comic extends AppModel { var $name = "Comic"; // Methods for retriving information. function testFunc(){ $mr = $this->find('all'); return $mr; } } ?> And I am calling it in my controller as such: <?php class ComicController extends AppController { var $name = "Comic"; var $uses = array('Comic'); function index() { } function view($q) { $this->set('array',$this->Comic->testFunc()); } } ?> When I try to load up the page; I get the following error: Warning (512): SQL Error: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'testFunc' at line 1 [CORE/cake/libs/model/datasources/dbo_source.php, line 525] Query: testFunc And the SQL dump looks like this: (default) 2 queries took 1 ms Nr Query Error Affected Num. rows Took (ms) 1 DESCRIBE comics 10 10 1 2 testFunc 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'testFunc' at line 1 0 So it looks like, instead of running the testFunc() function, it is trying to run a query of "testFunc" and failing...

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  • jquery GET and POST confusion

    - by JPro
    Hi, I am not quiet sure how jquery works. I want to know few things about the GET and POST in terms of jQuery. I use the following code in my app : <script> function example_ajax_request() { $('#example-placeholder').html('<p>Loading results ... <img src="ajax-loader.gif" /></p>'); $('#example-placeholder').load("ind.php?show=" + $('#box option:selected').val()); } </script> I am not using either GET or POST in this method. I am using a button to call the example_ajax_request to process the request and get the results. Sometimes I see code like this: $.ajax({ url: 'loader.php', data: 'somedata', method: 'GET', success: function(data){ $('#er').text(data); } }); My doubt is, is it required or not that we use a method to post the data? (either GET or POST) while send and getting the data in PHP webapps? The code that I use first works fine even though I do not use any POST or GET methods. Any inputs? Thanks.

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  • Get data from database without refresh whole page

    - by stefanz
    Hello everybody. My project is about a school admin I have a page called : createClass.php, where user inserts grade, profile etc. When he press "submit" page called createdClass.php is loading. Inside this page I have all code which insert data into database and also an "if" structure which says : "Class already exists" if in database is another class with same specifications. Also in second page (createdClass.php) i have a small table which shows the place of each student. First time all cells are green (this means that place is free) and if i click one of them appear a popup window which let me to add info about student from that place. If a place is busy the cell will be red (take a look here : http://screencast.com/t/NzM2YzYxNjct). The big problem is that the cell will be red only after refresh the page (the place ask for data from database). If I press refresh appears "class already exists". To test the code i added in a comment all lines which verify and add respectively classroom . I think my problem can be solved with ajax. I'm waiting for an answer. Regards Stefan

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  • HTML Element doesn't display when served with php5, restart server with php4 and Element displays.

    - by togglemedia
    Get this...I start the server in php5 and a specific HTML element ('a' element with a background image) is nowhere to be seen, I reboot the server in php4 and the HTML element is displaying properly. I boot back and forth between php5 and php4 with absolute consistent results, not displaying in php5 and displaying in php4. The thing that blows my mind is that: the HTML is consistent between boots of php5/4, so both scenarios have the necessary HTML elements the CSS is consistent between boots of php5/4, so both scenarios have the necessary CSS definitions there is an identically styled sibling element, with different class name that displays properly the problem is reproducible between browsers, between platforms. I've tested it on every possible config, Mac/Windows, IE6,7,8, FireFox, Safari etc... When the server is booted in php5 there is one HTML element that just doesn't display/render. A stab in the dark, I turned on PHP error reporting in php5 (to see if there would be any clues there) and low and behold the HTML element is now rendering in php5. I turn off PHP error reporting, and restart php5 and the HTML element is still rendering in php5, and the problem has been fixed...and I can't get the problem to reproduce. This is why my curiosity has brought me here. I just spent about four hours scratching my head trying to figure out how this could be. And now, I ask any php web dev gurus out there...what the heck was this all about?

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  • Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem

    - by SonOfOmer
    I am building custom implementation of php MVC routing engine, and I have custom routes like one in $routes array below. Each time when I send asynchronous GET request like xmlhttp.open("GET","someurl"); I get following message Warning: preg_match() [function.preg-match]: Unknown modifier '/' problem but with synchronous (normal) request it all works fine <?php $routes = array( array('url' => '/^someurl$/', 'controller' => 'somecontroller', 'view' => 'someview') ); $url = $_SERVER['REQUEST_URI']; $url = substr( $url, 1 ); $params = array(); $route_match = false; foreach($routes as $urls => $route) { if(preg_match($route['url'], $url, $matches)) { $params = array_merge($params, $matches); $route_match = true; break; } } require_once(CONTROLLER_PATH.$route['controller'].'.php'); ?> string(11) "/^someurl$/" is the result of var_dump($route['url']); Thanks.

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  • Trouble with jquery email form submitHandler

    - by Robert
    Here is the code I'm using for the submitHandler: submitHandler: function() { $('.holder').fadeOut('slow'); $('#loading').fadeIn('slow'); $.post('email.php',{name:$('#em_name').val(), email:$('#em_email').val(), message:$('#em_message').val()}, function(data){ $('#loading').css({display:'none'}); if( data == 'success') { $('#callback').show().append('Message delivered successfully'); $('#emailform').slideUp('slow'); } else { $('#callback').show().append('Sorry but your message could not be sent, try again later'); } }); } This isn't working when used in conjunction with this php: <?php $name = stripcslashes($_POST['name']); $emailAddr = stripcslashes($_POST['email']); $message = stripcslashes($_POST['message']); $email = "Message: $message \r \n From: $name \r \n Reply to: $emailAddr"; $to = '[email protected]'; $subject = 'Message from example'; //validate the email address on the server side if(eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$", $emailAddr) ) { //if successful lets send the message mail($to, $subject, $email); echo('success'); //return success callback } else { echo('An invalid email address was entered'); //email was not valid } ?> Does anyone have any suggestions as to why this isn't working like it should. It seems to just lock up when I submit. Any help would be appreciated. Thanks!

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  • Not getting response using SOAP and PHP.

    - by Nitish
    I'm using PHP5 and NuSOAP - SOAP Toolkit for PHP. I created the server using the code below: <?php function getStockQuote($symbol) { mysql_connect('localhost','user','pass'); mysql_select_db('test'); $query = "SELECT stock_price FROM stockprices WHERE stock_symbol = '$symbol'"; $result = mysql_query($query); $row = mysql_fetch_assoc($result); echo $row['stock_price']; } $a=require('lib/nusoap.php'); $server = new soap_server(); $server->configureWSDL('stockserver', 'urn:stockquote'); $server->register("getStockQuote", array('symbol' => 'xsd:string'), array('return' => 'xsd:decimal'), 'urn:stockquote', 'urn:stockquote#getStockQuote'); $HTTP_RAW_POST_DATA = isset($HTTP_RAW_POST_DATA) ? $HTTP_RAW_POST_DATA : ''; $server->service($HTTP_RAW_POST_DATA); ?> The client has the following code: <?php require_once('lib/nusoap.php'); $c = new soapclientNusoap('http://localhost/stockserver.php?wsdl'); $stockprice = $c->call('getStockQuote', array('symbol' => 'ABC')); echo "The stock price for 'ABC' is $stockprice."; ?> The database was created using the code below: CREATE TABLE `stockprices` ( `stock_id` INT UNSIGNED NOT NULL AUTO_INCREMENT , `stock_symbol` CHAR( 3 ) NOT NULL , `stock_price` DECIMAL(8,2) NOT NULL , PRIMARY KEY ( `stock_id` ) ); INSERT INTO `stockprices` VALUES (1, 'ABC', '75.00'); INSERT INTO `stockprices` VALUES (2, 'DEF', '45.00'); INSERT INTO `stockprices` VALUES (3, 'GHI', '12.00'); INSERT INTO `stockprices` VALUES (4, 'JKL', '34.00'); When I run the client the result I get is this: The stock price for 'ABC' is . 75.00 is not being printed as the price.

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  • wamp cannot load mysqli extension

    - by localhost
    WAMP installed fine, no problems, BUT... When going to phpMyAdmin, I get the error from phpMyAdmin as follows: "Cannot load mysqli extension. Please check your PHP configuration". Also, phpMyAdmin documentation explains this error message as follows: "To connect to a MySQL server, PHP needs a set of MySQL functions called "MySQL extension". This extension may be part of the PHP distribution (compiled-in), otherwise it needs to be loaded dynamically. Its name is probably mysql.so or php_mysql.dll. phpMyAdmin tried to load the extension but failed. Usually, the problem is solved by installing a software package called "PHP-MySQL" or something similar." Finally, the apache_error.log file has the following PHP warnings (see the mySQL warning): PHP Warning: Zend Optimizer does not support this version of PHP - please upgrade to the latest version of Zend Optimizer in Unknown on line 0 PHP Warning: Zend Platform does not support this version of PHP - please upgrade to the latest version of Zend Platform in Unknown on line 0 PHP Warning: Zend Debug Server does not support this version of PHP - please upgrade to the latest version of Zend Debug Server in Unknown on line 0 PHP Warning: gd wrapper does not support this version of PHP - please upgrade to the latest version of gd wrapper in Unknown on line 0 PHP Warning: java wrapper does not support this version of PHP - please upgrade to the latest version of java wrapper in Unknown on line 0 PHP Warning: mysql wrapper does not support this version of PHP - please upgrade to the latest version of mysql wrapper in Unknown on line 0 So, for some reason PHP is not recognizing the mysql extension. Anyone know why? Any solution or workaround?

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  • Top 10 collection completion - a monster in-query formula in MySQL?

    - by Andrew Heath
    I've got the following tables: User Basic Data (unique) [userid] [name] [etc] User Collection (one to one) [userid] [game] User Recorded Plays (many to many) [userid] [game] [scenario] [etc] Game Basic Data (unique) [game] [total_scenarios] I would like to output a table that shows the collection play completion percentage for the Top 10 users in descending order of %: Output Table [userid] [collection_completion] 3 95% 1 81% 24 68% etc etc In my mind, the calculation sequence for ONE USER is: grab user's total owned scenarios from User Collection joined with Game Basic Data and COUNT(gbd.total_scenarios) grab all recorded plays by COUNT(DISTINCT scenario) for that user Divide all recorded plays by total owned scenarios So that's 2 queries and a little PHP massage at the end. For a list of users sorted by completion percentage things get a little more complicated. I figure I could grab all users' collection totals in one query, and all users recorded plays in another, and then do the calcs and sort the final array in PHP, but it seems like overkill to potentially be doing all that for 1000+ users when I only ever want the Top 10. Is there a wicked monster query in MySQL that could do all that and LIMIT 10? Or is sticking with PHP handling the bulk of the work the way to go in this case?

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  • mySQL removes first digit

    - by kielie
    Hi guys, I am inputting data into a mySQL database via a PHP script, but for some reason when I check the database, all of the phone numbers have their first digit removed, like so, 0123456789 shows up as 123456789 in the database, but if I change the data type from INT to TEXT, it shows correctly, I am very hesitant to keep it as TEXT though, as I am sure this will cause complications further down the road as the database app starts to become more complicated, here is the PHP code. <?php $gender = $_POST['gender']; $first_name = $_POST['first_name']; $second_name = $_POST['second_name']; $id_number = $_POST['id_number']; $home_number = $_POST['home_number']; $cell_work = $_POST['cell_work']; $email_address = $_POST['email_address']; $curDate = date("Y-m-d"); mysql_connect ("server", "user", "pass") or die ('Error: ' . mysql_error()); mysql_select_db ("database"); $query = "INSERT INTO table (id,gender,first_name,second_name,id_number,home_number,cell_work,email_address,date) VALUES('NULL','".$gender."','".$first_name."','".$second_name."','".$id_number."','".$home_number."','".$cell_work."','".$email_address."','".$curDate."' )"; mysql_query($query) or die (mysql_error()); ?> Thanx in advance!

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  • encodeURIComponent is really useful?

    - by Marco Demaio
    Something I still don't understand when perfoming an http-get request to the server is what the advantage is in using JS fucntion encodeURIcomponent to encode each component of the http-get. Doing some tests I saw the server (using PHP) gets the values of the http-get request properly also if I don't use encodeURIcomponent!!! Obviuosly I still need to encode at client level the special character & ? = / : otherwise an http-get value like this "peace&love=virtue" would be considered as new key value pair of the http-get request instead of a one single value. But why does encodeURIcompenent encodes also many other charcaters like 'è' for example wich is translated into %C3%A8 that must be decoded on a PHP server using the utf8_decode function. By using encodeURIcomponent all values of the http-get request are utf8 encoded, therefor when getting them in PHP I have to call each time the utf8_decode function on each $_GET value which is quite annoying. Why can't we just encode only the & ? = / : charcaters??? see also: http://stackoverflow.com/questions/2607946/js-encodeuricomponent-result-different-from-the-one-created-by-form It shows that encodeURIComponent does not even encode properly because a simple browser FORM GET encodes charactrs like '€', in different way. So I still wonder what does this encodeURIComponent is for?

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  • Checking if an array contains all elements of another array

    - by mozcelikors
    I'm designing an electrical engineering application. However, i'm stuck on this: I have the following array <?php // Static Array $GroupOfEight = array ( array(0,1,3,2,4,5,7,6), array(4,5,6,7,16,12,13,14), array(12,13,15,14,8,9,11,10), array(2,6,14,10,3,7,15,11), array(1,3,5,7,13,15,9,11), array(0,4,12,8,1,5,13,9), array(0,1,3,2,8,9,11,10) ); ?> And I have another array, but this one is one dimensional. <?php $myStack = array(0,1,3,2,4,5,7,6); //Dynamic, gets value by POST method. ?> What I want to do is to check if $myStack is equal to any sub array of $GroupOfEight array. ( Number ordering is not important. The script should just check if every elements contained. It's not important if their order is same or not. ) Here is what I've done to solve the issue so far: <?php //Check if stackArray contains 8group for($i=0; $i<count($GroupOfEight);$i++) for($j=0; $j<count($GroupOfEight[$i]); $j++){ //$containsSearch = count(array_intersect($search_this,$all)) == count($search_this); $containsSearch = count(array_intersect($stackArray,$GroupOfEight[$j])) == count($stackArray); echo $containsSearch; } ?> Please help me correct my code or introduce me the solution of this issue, Thanks.

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  • jQuery: Using autocomplete to add values to two fields instead of one

    - by rayne
    I want to use the autocomplete plugin for jQuery to populate not one, but two fields when selecting one of the autocomplete values - the name of a band is entered in the #band input field, but the band url (if exists) should also automatically be added to the #url input field when selecting the band name. Right now I simply have an un-pretty list in an external php file from which the autocompleter takes it's values: $bands_sql = "SELECT bands.name, bands.url FROM bands ORDER BY name"; $bands_result = mysql_query($bands_sql) or print (mysql_error()); while ($bands_row = mysql_fetch_array($bands_result)) { $band_name = $bands_row['name']; $band_url = $bands_row['url']; echo $band_name."\n"; #needs to be replaced with an array that holds name and url } My autocomplete function looks very basic atm, but as I'm an absolute beginner when it comes to jQuery (and also clueless when it comes to PHP arrays), I have no idea how to tell it to populate two fields and not one. $(document).ready(function() { $("#band").autocomplete('/autocomplete-bands.php'); }); Is that even possible?!

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  • Are short tags *that* bad?

    - by Col. Shrapnel
    Everyone here on SO says it's bad, for 3 main reasons: XML is used everywhere You can't control where your script is going to be run short tags are going to be removed in PHP6 But let's see closer at them: Last one is easy - it's just not true. XML is not really a problem. If you want to use short tags, it won't be a problem for you to write a single tag using PHP echo, <?="<?XML...?>"?>. Anyway, why not to leave such a trifle thing for one's own judgment? PHP configuration access. Oh yes, the only thing that can be really considered as a reason. Of course in case you plan to spread your code wide. But if you don't? I think most of scripts being written not for the wide spread, but just for one place. If you can use short tags in that place - why to abandon them? Anyway, it's the only template we are talking about. If you don't like short tags, PHP native template is probably not for you, why not to try Smarty then? Well, the question is: is there any other real reasons to abandon short tags and make it strict recommendation? Or, as it was said, better to leave short tags alone?

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  • Need variable width negative lookbehind replacement

    - by Technoh
    I have looked at many questions here (and many more websites) and some provided hints but none gave me a definitive answer. I know regular expressions but I am far from being a guru. This particular question deals with regex in PHP. I need to locate words in a text that are not surrounded by a hyperlink of a given class. For example, I might have This <a href="blabblah" class="no_check">elephant</a> is green and this elephant is blue while this <a href="blahblah">elephant</a> is red. I would need to match against the second and third elephants but not the first (identified by test class "no_check"). Note that there could more attributes than just href and class within hyperlinks. I came up with ((?<!<a .*class="no_check".*>)\belephant\b) which works beautifully in regex test software but not in PHP. Any help is greatly appreciated. If you cannot provide a regular expression but can find some sort of PHP code logic that would circumvent the need for it, I would be equally grateful.

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