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  • How To Collapse Just One Field in Django Admin?

    - by Apreche
    The django admin allows you to specify fieldsets. You properly structure a tuple that groups different fields together. You can also specify classes for certain groups of fields. One of those classes is collapse, which will hide the field under a collapsable area. This is good for hiding rarely used or advanced fields to keep the UI clean. However, I have a situation where I want to hide just one lonesome field on many different apps. This will be a lot of typing to create a full fieldset specification in every admin.py file just to put one field into the collapsed area. It also creates a difficult maintenance situation because I will have to edit the fieldset every time I edit the associated model. I can easily exclude the field entirely using the exclude option. I want something similar for collapse. Is this possible?

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  • django-haystack urlpatterns include('haystack.urls') where does it lead to?

    - by Eugene
    I've recently begun to learn/install django/haystack/solr. Following the tutorial given in haystack site, I have urlpatterns = pattern('', r'^search/', include('haystack.urls')) I found haystack installed in /usr/local/lib/python2.6/dist-packages/haystack and located urls.py there. It has urlpatterns=patterns('haystack.views', url(r'^$', SearchView(), name='haystack_search'),) I thought the second argument of url() should be callable object. I looked at the views.py and SearchView is a class. What is going on here? What's get called eventually?

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  • How do I check for Existence of a Record in GAE

    - by VDev
    I am trying to create a simple view in Django & GAE, which will check if the user has a profile entity and prints a different message for each case. I have the program below, but somehow GAE always seem to return a object. My program is below import datetime from django.http import HttpResponse, HttpResponseRedirect from google.appengine.api import users from google.appengine.ext import db from models import Profile import logging #from accounts.views import profile # Create your views here. def login_view(request): user = users.get_current_user() profile = db.GqlQuery("SELECT * FROM Profile WHERE account = :1", users.get_current_user()) logging.info(profile) logging.info(user) if profile: return HttpResponse("Congratulations Your profile is already created.") else: return HttpResponse("Sorry Your profile is NOT created.") My model object is Profile defined as follows: class Profile(db.Model): first_name = db.StringProperty() last_name = db.StringProperty() gender = db.StringProperty(choices=set(["Male", "Female"])) account = db.UserProperty(required = True) friends = db.ListProperty(item_type=users.User) last_login = db.DateTimeProperty(required=True) Thanks for the help.

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  • How make this special many2many fields validation using Django ORM?

    - by e-satis
    I have the folowing model: class Step(models.Model): order = models.IntegerField() latitude = models.FloatField() longitude = models.FloatField() date = DateField(blank=True, null=True) class Journey(models.Model): boat = models.ForeignKey(Boat) route = models.ManyToManyField(Step) departure = models.ForeignKey(Step, related_name="departure_of", null=True) arrival = models.ForeignKey(Step, related_name="arrival_of", null=True) I would like to implement the following check: # If a there is less than one step, raises ValidationError. routes = tuple(self.route.order_by("date")) if len(routes) <= 1: raise ValidationError("There must be at least two setps in the route") # save the first and the last step as departure and arrival self.departure = routes[0] self.arrival = routes[-1] # departure and arrival must at least have a date if not (self.departure.date or self.arrival.date): raise ValidationError("There must be an departure and an arrival date. " "Please set the date field for the first and last Step of the Journey") # departure must occurs before arrival if not (self.departure.date > self.arrival.date): raise ValidationError("Departure must take place the same day or any date before arrival. " "Please set accordingly the date field for the first and last Step of the Journey") I tried to do that by overloading save(). Unfortunately, Journey.route is empty in save(). What's more, Journey.id doesn't exists yet. I didn't try django.db.models.signals.post_save but suppose it will fail because Journey.route is empty as well (when does this get filled anyway?). I see a solution in django.db.models.signals.m2m_changed but there are a lot of steps (thousands), and I want to avoid to perform an operation for every single of them.

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  • How do I subtract two dates in Django/Python?

    - by Ryan
    Hi! I'm working on a little fitness tracker in order to teach myself Django. I want to graph my weight over time, so I've decided to use the Python Google Charts Wrapper. Google charts require that you convert your date into a x coordinate. To do this I want to take the number of days in my dataset by subtracting the first weigh-in from the last weigh-in and then using that to figure out the x coords (for example, I could 100 by the result and increment the x coord by the resulting number for each y coord.) Anyway, I need to figure out how to subtract Django datetime objects from one another and so far, I am striking out on both google and here at the stack. I know PHP, but have never gotten a handle on OO programming, so please excuse my ignorance. Here is what my models look like: class Goal(models.Model): goal_weight = models.DecimalField("Goal Weight",max_digits=4, decimal_places=1) target_date = models.DateTimeField("Target Date to Reach Goal") set_date = models.DateTimeField("When did you set your goal?") comments = models.TextField(blank=True) def __unicode__(self): return unicode(self.goal_weight) class Weight(models.Model): """Weight at a given date and time """ goal = models.ForeignKey(Goal) weight = models.DecimalField("Current Weight",max_digits=4, decimal_places=1) weigh_date = models.DateTimeField("Date of Weigh-In") comments = models.TextField(blank=True) def __unicode__(self): return unicode(self.weight) def recorded_today(self): return self.date.date() == datetime.date.today() Any ideas on how to proceed in the view? Thanks so much!

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  • How to limit fields in django-admin depending on user?

    - by minder
    I suppose similar problem would have been discussed here, but I couldn't find it. Let's suppose I have an Editor and a Supervisor. I want the Editor to be able to add new content (eg. a news post) but before publication it has to be acknowledged by Supervisor. When Editor lists all items, I want to set some fields on the models (like an 'ack' field) as read-only (so he could know what had been ack'ed and what's still waiting approval) but the Supervisor should be able to change everything (list_editable would be perfect) What are the possible solutions to this problem?

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  • why isn't my id showing up in django admin list?

    - by FurtiveFelon
    Hi all, I have a class Task(models.Model), and i didn't define id field explicitly (since it defines automatically for you). I checked in the database, it exists for the Task. Now i would like to display it in the list via list_display property in admin.ModelAdmin. I have a bunch of things in there, only id is not showing up for any of the rows i have. Everything else works fine. Anyone know anything special i have to do to get id to display? Thanks a lot! Jason

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  • gunicorn + django + nginx unix://socket failed (11: Resource temporarily unavailable)

    - by user1068118
    Running very high volume traffic on these servers configured with django, gunicorn, supervisor and nginx. But a lot of times I tend to see 502 errors. So I checked the nginx logs to see what error and this is what is recorded: [error] 2388#0: *208027 connect() to unix:/tmp/gunicorn-ourapp.socket failed (11: Resource temporarily unavailable) while connecting to upstream Can anyone help debug what might be causing this to happen? This is our nginx configuration: sendfile on; tcp_nopush on; tcp_nodelay off; listen 80 default_server; server_name imp.ourapp.com; access_log /mnt/ebs/nginx-log/ourapp-access.log; error_log /mnt/ebs/nginx-log/ourapp-error.log; charset utf-8; keepalive_timeout 60; client_max_body_size 8m; gzip_types text/plain text/xml text/css application/javascript application/x-javascript application/json; location / { proxy_pass http://unix:/tmp/gunicorn-ourapp.socket; proxy_pass_request_headers on; proxy_read_timeout 600s; proxy_connect_timeout 600s; proxy_redirect http://localhost/ http://imp.ourapp.com/; #proxy_set_header Host $host; #proxy_set_header X-Real-IP $remote_addr; #proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; #proxy_set_header X-Forwarded-Proto $my_scheme; #proxy_set_header X-Forwarded-Ssl $my_ssl; } We have configure Django to run in Gunicorn as a generic WSGI application. Supervisord is used to launch the gunicorn workers: home/user/virtenv/bin/python2.7 /home/user/virtenv/bin/gunicorn --config /home/user/shared/etc/gunicorn.conf.py daggr.wsgi:application This is what the gunicorn.conf.py looks like: import multiprocessing bind = 'unix:/tmp/gunicorn-ourapp.socket' workers = multiprocessing.cpu_count() * 3 + 1 timeout = 600 graceful_timeout = 40 Does anyone know where I can start digging to see what might be causing the problem? This is what my ulimit -a output looks like on the server: core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 59481 max locked memory (kbytes, -l) 64 max memory size (kbytes, -m) unlimited open files (-n) 50000 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 8192 cpu time (seconds, -t) unlimited max user processes (-u) 1024 virtual memory (kbytes, -v) unlimited file locks (-x) unlimited

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  • nginx+django serving static files

    - by avalore
    I have followed instruction for setting up django with nginx from the django wiki (https://code.djangoproject.com/wiki/DjangoAndNginx) and have nginx setup as follows (a few name changes to fit my setup). user nginx nginx; worker_processes 2; error_log /var/log/nginx/error_log info; events { worker_connections 1024; use epoll; } http { include /etc/nginx/mime.types; default_type application/octet-stream; log_format main '$remote_addr - $remote_user [$time_local] ' '"$request" $status $bytes_sent ' '"$http_referer" "$http_user_agent" ' '"$gzip_ratio"'; client_header_timeout 10m; client_body_timeout 10m; send_timeout 10m; connection_pool_size 256; client_header_buffer_size 1k; large_client_header_buffers 4 2k; request_pool_size 4k; gzip on; gzip_min_length 1100; gzip_buffers 4 8k; gzip_types text/plain; output_buffers 1 32k; postpone_output 1460; sendfile on; tcp_nopush on; tcp_nodelay on; keepalive_timeout 75 20; ignore_invalid_headers on; index index.html; server { listen 80; server_name localhost; location /static/ { root /srv/static/; } location ~* ^.+\.(jpg|jpeg|gif|png|ico|css|zip|tgz|gz|rar|bz2|doc|xls|exe|pdf|ppt|txt|tar|mid|midi|wav|bmp|rtf|js|mov) { access_log off; expires 30d; } location / { # host and port to fastcgi server fastcgi_pass 127.0.0.1:8080; fastcgi_param PATH_INFO $fastcgi_script_name; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param QUERY_STRING $query_string; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; fastcgi_pass_header Authorization; fastcgi_intercept_errors off; fastcgi_param REMOTE_ADDR $remote_addr; } access_log /var/log/nginx/localhost.access_log main; error_log /var/log/nginx/localhost.error_log; } } Static files aren't being served (nginx 404). If I look in the access log it seems nginx is looking in /etc/nginx/html/static... rather than /srv/static/ as specified in the config. I've no clue why it's doing this, any help would be hugely appreciated.

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  • Request data from database using Django

    - by user21901
    I have somehow two variables for example x and y. I have also made a model with 3 fields (longitude,latitude,name) and have it activated in mysql database. I need to send these two variables(x,y) to the django server so as to search if there is an object with longitude=x and latitude=y.If there is one i want to get back it's name. How can i do this?

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • Django app that can provide user friendly, multiple / mass file upload functionality to other apps

    - by hopla
    Hi, I'm going to be honest: this is a question I asked on the Django-Users mailinglist last week. Since I didn't get any replies there yet, I'm reposting it on Stack Overflow in the hope that it gets more attention here. I want to create an app that makes it easy to do user friendly, multiple / mass file upload in your own apps. With user friendly I mean upload like Gmail, Flickr, ... where the user can select multiple files at once in the browse file dialog. The files are then uploaded sequentially or in parallel and a nice overview of the selected files is shown on the page with a progress bar next to them. A 'Cancel' upload button is also a possible option. All that niceness is usually solved by using a Flash object. Complete solutions are out there for the client side, like: SWFUpload http://swfupload.org/ , FancyUpload http://digitarald.de/project/fancyupload/ , YUI 2 Uploader http://developer.yahoo.com/yui/uploader/ and probably many more. Ofcourse the trick is getting those solutions integrated in your project. Especially in a framework like Django, double so if you want it to be reusable. So, I have a few ideas, but I'm neither an expert on Django nor on Flash based upload solutions. I'll share my ideas here in the hope of getting some feedback from more knowledgeable and experienced people. (Or even just some 'I want this too!' replies :) ) You will notice that I make a few assumptions: this is to keep the (initial) scope of the application under control. These assumptions are of course debatable: All right, my idea's so far: If you want to mass upload multiple files, you are going to have a model to contain each file in. I.e. the model will contain one FileField or one ImageField. Models with multiple (but ofcourse finite) amount of FileFields/ ImageFields are not in need of easy mass uploading imho: if you have a model with 100 FileFields you are doing something wrong :) Examples where you would want my envisioned kind of mass upload: An app that has just one model 'Brochure' with a file field, a title field (dynamically created from the filename) and a date_added field. A photo gallery app with models 'Gallery' and 'Photo'. You pick a Gallery to add pictures to, upload the pictures and new Photo objects are created and foreign keys set to the chosen Gallery. It would be nice to be able to configure or extend the app for your favorite Flash upload solution. We can pick one of the three above as a default, but implement the app so that people can easily add additional implementations (kinda like Django can use multiple databases). Let it be agnostic to any particular client side solution. If we need to pick one to start with, maybe pick the one with the smallest footprint? (smallest download of client side stuff) The Flash based solutions asynchronously (and either sequentially or in parallel) POST the files to a url. I suggest that url to be local to our generic app (so it's the same for every app where you use our app in). That url will go to a view provided by our generic app. The view will do the following: create a new model instance, add the file, OPTIONALLY DO EXTRA STUFF and save the instance. DO EXTRA STUFF is code that the app that uses our app wants to run. It doesn't have to provide any extra code, if the model has just a FileField/ImageField the standard view code will do the job. But most app will want to do extra stuff I think, like filling in the other fields: title, date_added, foreignkeys, manytomany, ... I have not yet thought about a mechanism for DO EXTRA STUFF. Just wrapping the generic app view came to mind, but that is not developer friendly, since you would have to write your own url pattern and your own view. Then you have to tell the Flash solutions to use a new url etc... I think something like signals could be used here? Forms/Admin: I'm still very sketchy on how all this could best be integrated in the Admin or generic Django forms/widgets/... (and this is were my lack of Django experience shows): In the case of the Gallery/Photo app: You could provide a mass Photo upload widget on the Gallery detail form. But what if the Gallery instance is not saved yet? The file upload view won't be able to set the foreignkeys on the Photo instances. I see that the auth app, when you create a user, first asks for username and password and only then provides you with a bigger form to fill in emailadres, pick roles etc. We could do something like that. In the case of an app with just one model: How do you provide a form in the Django admin to do your mass upload? You can't do it with the detail form of your model, that's just for one model instance. There's probably dozens more questions that need to be answered before I can even start on this app. So please tell me what you think! Give me input! What do you like? What not? What would you do different? Is this idea solid? Where is it not? Thank you!

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  • Django query if field value is one of multiple choices

    - by Nathan
    Say I want to model a system where a piece of data can have multiple tags (e.g. a question on a StackOverflow is the data, it's set of tags are the tags). I can model this in Django with the following: class Tag(models.Model): name = models.CharField(10) class Data(models.Model): tags = models.ManyToManyField(Tag) Given a set of strings, what's the best way to go about finding all Data objects that have one of these strings as the name of a tag in their tag list. I've come up with the following, but can't help thinking there is a more "Djangonic" way. Any ideas? tags = [ "foo", "bar", "baz" ] q_objects = Q( tags__name = tags[0] ) for t in tags[1:]: q_objects = q_objects | Q( tags__name = t ) data = Data.objects.filter( q_objects ).distinct()

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  • Django queries: Count number of objects with FK to model instance

    - by Chris Lawlor
    This should be easy but for some reason I'm having trouble finding it. I have the following: App(models.Model): ... Release(models.Model): date = models.DateTimeField() App = models.ForeignKey(App) ... How can I query for all App objects that have at least one Release? I started typing: App.objects.all().annotate(release_count=Count('??????')).filter(release_count__gt=0) Which won't work because Count doesn't span relationships, at least as far as I can tell. BONUS: Ultimately, I'd also like to be able to sort Apps by latest release date. I'm thinking of caching the latest release date in the app to make this a little easier (and cheaper), and updating it in the Release model's save method, unless of course there is a better way. Edit: I'm using Django 1.1 - not averse to migrating to dev in anticipation of 1.2 if there is a compelling reason though.

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  • Django IN query as a string result - invalid literal for int() with base 10

    - by bmelton
    Trying to query a 'Favorites' model to get a list of items a user has favorited, and then querying against a different model to get the objects back from that query to present to the template, but I'm getting an error: "invalid literal for int() with base 10" Looking over all of the other instances of that error, I couldn't find any in which the asker actually wanted to work with a comma separated list of integers, so I'm kind of at a loss. Model class Favorite(models.Model): # key should be the model name, id is the model.id, and user is the User object. key = models.CharField(max_length=255, unique=True) val = models.IntegerField(default=0) user = models.ForeignKey(User) class Admin: list_display = ('key', 'id', 'user') View def index(request): favorites = Favorite.objects.filter(key='blog', user=request.user.pk) values = "" for favorite in favorites: values += "%s," % favorite.val #values = "[%s]" % values blogs = Blog.objects.filter(pk__in=values) return render_to_response('favorite/index.html', { "favorites" : favorites, "blogs" : blogs, "values" : values, }, context_instance=RequestContext(request) ) enter code here

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  • django app organization

    - by iHeartDucks
    I have been reading some django tutorial and it seems like all the view functions have to go in a file called "views.py" and all the models go in "models.py". I fear that I might end up with a lot of view functions in my view.py file and the same is the case with models.py. Is my understanding of django apps correct? Django apps lets us separate common functionality into different apps and keep the file size of views and models to a minimum? For example: My project can contain an app for recipes (create, update, view, and search) and a friend app, the comments app, and so on. Can I still move some of my view functions to a different file? So I only have the CRUD in one single file?

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  • How do I prevent a ManyToManyField('self') from linked an object to itself?

    - by dyve
    Consider this model (simplified for this question): class SecretAgentName(models.Model): name = models.CharField(max_length=100) aliases = ManyToManyField('self') I have three names, "James Bond", "007" and "Jason Bourne". "James Bond" and "007" are aliases of each other. This works exactly like I want it to, except for the fact that every instance can also be an alias of itself. This I want to prevent. So, there can be many SecretAgentNames, all can be aliases of each other as long as "James Bond" does not show up as an alias for "James Bond". Can I prevent this in the model definition? If not, can I prevent it anywhere else, preferably so that the Django Admin understands it?

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  • Multi-thread conversation in django (like Reddit)

    - by dotty
    Hay, i have an app which essentially a conversation system (much like reddits) Where a post can have multiple replies, and a reply and have multiplies, and a reply to a reply can have multiple replies (etc) I've made the model like this class Discussion(models.Model): message = models.TextField() replies = models.ManyToManyField('self') and the view discussions = Discussions.objects.all() and the template looks like this {% for discussion in discussions %} {{ discussion.message }} {% endfor %} How would i go about making a system where i can output all replies like this discussion reply reply reply reply reply reply Which would go down as far as it needs to to ensure all replies are listed. Thanks

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  • Difficulty adding widgets to django form.

    - by codingJoe
    I have a django app that tracks activities that can benefit a classroom. Using the django examples, I was able to build a form to enter this data. But when I try to add widgets to that form, things get tricky. What I want is a calendar widget that lets the user enter the 'activity_date' field using a widget. If I use Admin interface. The AdminDateWidget works fine. however. This particular user isn't allowed access to the admin interface so I need a different way to present this widget. Also I couldn't figure out how to make the bring the admin widget over into non-admin pages. So I tried a custom widget. This is the first custom widget I've built, so I'm not quite sure what is supposed to be going on here. Any Expert Advice? How do I get my date widget to work? # The Model class Activity(models.Model): activity_date = models.DateField() activity_type = models.CharField(max_length=50, choices=ACTIVITY_TYPES) activity_description = models.CharField(max_length=200) activity_duration= models.DecimalField(decimal_places=2, max_digits=4) est_attendance = models.IntegerField("Estimated attendance") # The Form class ActivityForm(forms.ModelForm): # The following line causes lockup if enabled. # With the DateTimeWidget removed, the form functions correctly except that there is no widget. #activity_date = forms.DateField(label=_('Date'), widget=DateTimeWidget) ##!!! Point of Error !!! class Meta: model = Activity fields = ('activity_date', 'activity_type', 'activity_description', 'activity_duration', 'est_attendance') def __init__(self, *args, **kwargs): super(ActivityForm, self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) edit_aid = kwargs.get('edit_aid', False) # On a different approach, the following also didn't work. #self.fields['activity_date'].widget = widgets.AdminDateWidget() # The Widget # Example referenced: http://djangosnippets.org/snippets/391/ calbtn = u""" <button id="calendar-trigger">...</button> <img src="%s/site_media/images/icon_calendar.gif" alt="calendar" id="%s_btn" style="cursor: pointer; border: 1px solid #8888aa;" title="Select date and time" onmouseover="this.style.background='#444444';" onmouseout="this.style.background=''" /> <script type="text/javascript"> Calendar.setup({ trigger : "calendar-trigger", inputField : "%s" }); </script>""" class DateTimeWidget(forms.widgets.TextInput): dformat = '%Y-%m-%d %H:%M' def render(self, name, value, attrs=None): print "DTWgt render name=%s, value=%s" % name, value if value is None: value = '' final_attrs = self.build_attrs(attrs, type=self.input_type, name=name) if value != '': try: final_attrs['value'] = \ force_unicode(value.strftime(self.dformat)) except: final_attrs['value'] = \ force_unicode(value) if not final_attrs.has_key('id'): final_attrs['id'] = u'%s_id' % (name) id = final_attrs['id'] jsdformat = self.dformat #.replace('%', '%%') cal = calbtn % (settings.MEDIA_URL, id, id, jsdformat, id) a = u'<input%s />%s' % (forms.util.flatatt(final_attrs), cal) print "render return %s " % a return mark_safe(a) def value_from_datadict(self, data, files, name): print "DTWgt value_from_datadict" dtf = forms.fields.DEFAULT_DATETIME_INPUT_FORMATS empty_values = forms.fields.EMPTY_VALUES value = data.get(name, None) if value in empty_values: return None if isinstance(value, datetime.datetime): return value if isinstance(value, datetime.date): return datetime.datetime(value.year, value.month, value.day) for format in dtf: try: return datetime.datetime(*time.strptime(value, format)[:6]) except ValueError: continue return None

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  • Django: order by count of a ForeignKey field?

    - by AP257
    This is almost certainly a duplicate question, in which case apologies, but I've been searching for around half an hour on SO and can't find the answer here. I'm probably using the wrong search terms, sorry. I have a User model and a Submission model. Each Submission has a ForeignKey field called user_submitted for the User who uploaded it. class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) My question is pretty simple: how can I get a list of the three users with the most Submissions? I trued creating a num_submissions method on the User model: def num_submissions(self): num_submissions = Submission.objects.filter(uploaded_by=self).count() return num_submissions and then doing: top_users = User.objects.filter(problem_user=False).order_by('num_submissions')[:3] but this fails, as do all the other things I've tried. Can I actually do it using a smart database query? Or should I just do something more hacky in the views file?

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  • Single database with multiple instances of Django

    - by jwesonga
    I have a Django project where the company will have a main site like www.ourcompany.org and a bunch of sub-domains like project.ourcompany.org. Content appearing in the sub-domains like case studies should also appear in the main site. I've decided to use multiple instances of Django BUT one database for each sub-domain so that I can have some flexibility and take advantage of the Sites framework. What I'm not sure of is how to access the models across the multiple instances. If I have a model: class CaseStudy(models.Model): title=models.CharField(max_length=100) site=models.ManyToMany(Site) Do I need to create this model in every instance so that I can have access to the object?

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  • Django: How to handle imports in a reusable app

    - by facha
    everyone I'm just starting with django. It is not quite clear to me, how should I write an app I could reuse later. In every tutorial I read I see the same piece of code: view.py from project.app.models import MyModel So, if I move my apps to another project, I'll have to modify the "project.app.models" so that it looks like "project2.app.models" for every app I move. Is there a way to avoid that? Thanks in advance.

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