Search Results

Search found 9066 results on 363 pages for 'product'.

Page 55/363 | < Previous Page | 51 52 53 54 55 56 57 58 59 60 61 62  | Next Page >

  • DotNetNuke 7.0 Only Weeks Away!

    - by sbwalker
    The software industry moves at a lightning pace, and it is only through constant focus and continuous investment that a software product can remain both stable and relevant over the long term. As we approach the 10 Year Anniversary of the DotNetNuke platform, it seems only fitting that we are on the verge of announcing yet another significant product milestone. DotNetNuke 7.0 is just around the corner and represents a bold step forward for our Content Management Platform, including substantial business productivity enhancements, investments in web platform relevance, and a significant overhaul and modernization of the user interface and user experience. It has been five months since I posted the announcement that the next major version of the platform was going to be DotNetNuke 7.0.  This announcement created tremendous excitement and anticipation in the DotNetNuke community, as major version increments have always been utilized as an opportunity  to introduce revolutionary new product features and capabilities. After months of intense product development, the finish line is finally in sight. With that, I am pleased to announce that we released a Release Candidate (RC) of DotNetNuke 7.0 yesterday. You can download the RC from our project page on Codeplex. A Release Candidate represents a software version which is very near to “release” quality. So although we will not be officially endorsing the RC for production use, or providing an official upgrade path, it does represent a significant milestone in our software development efforts ( if you are looking for a more detailed explanation of our software release terminology, I would encourage you to read the blog written by Co-Founder, Joe Brinkman titled "What's In A Name?" ). Modernizing a software platform does have its share of challenges from a backward compatibility perspective and, as usual, we are taking great care in ensuring a seamless upgrade path for our customers. In order to remain relevant and progressive, you need to be aware that DotNetNuke 7.0 has adopted a new set of baseline infrastructure requirements including ASP.NET 4.0.  As a result we are encouraging all major stakeholders in the ecosystem ( module developers, designers, partners, customers, etc... ) to take the opportunity to install the RC in their own local environments. This is the last opportunity to let us know about any final issues which may need to be addressed prior to final release. Mark your calendars now… the expected public release date (RTM) for DotNetNuke 7.0 will be Wednesday, November 28th. On a side note, we expect to release a 6.2.5 Maintenance version today. This release contains some high priority product quality improvements as well as security patches for some vulnerabilities reported through our standard ecosystem channels. As a result we will be encouraging all of our customers to upgrade to the 6.2.5 release as soon as it is available. I hope everyone is as excited as I am about the upcoming DotNetNuke 7.0 release. Please take the opportunity over the next week to put the new platform through its paces. Remember, only through our collective efforts can we ensure that this release has the greatest market impact of any DotNetNuke release to date.

    Read the article

  • Visual Studio Extensions

    - by Scott Dorman
    Originally posted on: http://geekswithblogs.net/sdorman/archive/2013/10/18/visual-studio-extensions.aspxAs a product, Visual Studio has been around for a long time. In fact, it’s been 18 years since the first Visual Studio product was launched. In that time, there have been some major changes but perhaps the most important (or at least influential) changes for the course of the product have been in the last few years. While we can argue over what was and wasn’t an important change or what has and hasn’t changed, I want to talk about what I think is the single most important change Microsoft has made to Visual Studio. Specifically, I’m referring to the Visual Studio Gallery (first introduced in Visual Studio 2010) and the ability for third-parties to easily write extensions which can add new functionality to Visual Studio or even change existing functionality. I know Visual Studio had this ability before the Gallery existed, but it was expensive (both from a financial and development resource) perspective for a company or individual to write such an extension. The Visual Studio Gallery changed all of that. As of today, there are over 4000 items in the Gallery. Microsoft itself has over 100 items in the Gallery and more are added all of the time. Why is this such an important feature? Simply put, it allows third-parties (companies such as JetBrains, Telerik, Red Gate, Devart, and DevExpress, just to name a few) to provide enhanced developer productivity experiences directly within the product by providing new functionality or changing existing functionality. However, there is an even more important function that it serves. It also allows Microsoft to do the same. By providing extensions which add new functionality or change existing functionality, Microsoft is not only able to rapidly innovate on new features and changes but to also get those changes into the hands of developers world-wide for feedback. The end result is that these extensions become very robust and often end up becoming part of a later product release. An excellent example of this is the new CodeLens feature of Visual Studio 2013. This is, perhaps, the single most important developer productivity enhancement released in the last decade and already has huge potential. As you can see, out of the box CodeLens supports showing you information about references, unit tests and TFS history.   Fortunately, CodeLens is also accessible to Visual Studio extensions, and Microsoft DevLabs has already written such an extension to show code “health.” This extension shows different code metrics to help make sure your code is maintainable. At this point, you may have already asked yourself, “With over 4000 extensions, how do I find ones that are good?” That’s a really good question. Fortunately, the Visual Studio Gallery has a ratings system in place, which definitely helps but that’s still a lot of extensions to look through. To that end, here is my personal list of favorite extensions. This is something I started back when Visual Studio 2010 was first released, but so much has changed since then that I thought it would be good to provide an updated list for Visual Studio 2013. These are extensions that I have installed and use on a regular basis as a developer that I find indispensible. This list is in no particular order. NuGet Package Manager for Visual Studio 2013 Microsoft CodeLens Code Health Indicator Visual Studio Spell Checker Indent Guides Web Essentials 2013 VSCommands for Visual Studio 2013 Productivity Power Tools (right now this is only for Visual Studio 2012, but it should be updated to support Visual Studio 2013.) Everyone has their own set of favorites, so mine is probably not going to match yours. If there is an extension that you really like, feel free to leave me a comment!

    Read the article

  • Oracle Fusion Supply Chain Management (SCM) Designs May Improve End User Productivity

    - by Applications User Experience
    By Applications User Experience on March 10, 2011 Michele Molnar, Senior Usability Engineer, Applications User Experience The Challenge: The SCM User Experience team, in close collaboration with product management and strategy, completely redesigned the user experience for Oracle Fusion applications. One of the goals of this redesign was to increase end user productivity by applying design patterns and guidelines and incorporating findings from extensive usability research. But a question remained: How do we know that the Oracle Fusion designs will actually increase end user productivity? The Test: To answer this question, the SCM Usability Engineers compared Oracle Fusion designs to their corresponding existing Oracle applications using the workflow time analysis method. The workflow time analysis method breaks tasks into a sequence of operators. By applying standard time estimates for all of the operators in the task, an estimate of the overall task time can be calculated. The workflow time analysis method has been recently adopted by the Applications User Experience group for use in predicting end user productivity. Using this method, a design can be tested and refined as needed to improve productivity even before the design is coded. For the study, we selected some of our recent designs for Oracle Fusion Product Information Management (PIM). The designs encompassed tasks performed by Product Managers to create, manage, and define products for their organization. (See Figure 1 for an example.) In applying this method, the SCM Usability Engineers collaborated with Product Management to compare the new Oracle Fusion Applications designs against Oracle’s existing applications. Together, we performed the following activities: Identified the five most frequently performed tasks Created detailed task scenarios that provided the context for each task Conducted task walkthroughs Analyzed and documented the steps and flow required to complete each task Applied standard time estimates to the operators in each task to estimate the overall task completion time Figure 1. The interactions on each Oracle Fusion Product Information Management screen were documented, as indicated by the red highlighting. The task scenario and script provided the context for each task.  The Results: The workflow time analysis method predicted that the Oracle Fusion Applications designs would result in productivity gains in each task, ranging from 8% to 62%, with an overall productivity gain of 43%. All other factors being equal, the new designs should enable these tasks to be completed in about half the time it takes with existing Oracle Applications. Further analysis revealed that these performance gains would be achieved by reducing the number of clicks and screens needed to complete the tasks. Conclusions: Using the workflow time analysis method, we can expect the Oracle Fusion Applications redesign to succeed in improving end user productivity. The workflow time analysis method appears to be an effective and efficient tool for testing, refining, and retesting designs to optimize productivity. The workflow time analysis method does not replace usability testing with end users, but it can be used as an early predictor of design productivity even before designs are coded. We are planning to conduct usability tests later in the development cycle to compare actual end user data with the workflow time analysis results. Such results can potentially be used to validate the productivity improvement predictions. Used together, the workflow time analysis method and usability testing will enable us to continue creating, evaluating, and delivering Oracle Fusion designs that exceed the expectations of our end users, both in the quality of the user experience and in productivity. (For more information about studying productivity, refer to the Measuring User Productivity blog.)

    Read the article

  • Where to store front-end data for "object calculator"

    - by Justin Grahn
    I recently have completed a language library that acts as a giant filter for food items, and flows a bit like this :Products -> Recipes -> MenuItems -> Meals and finally, upon submission, creates an Order. I have also completed a database structure that stores all the pertinent information to each class, and seems to fit my needs. The issue I'm having is linking the two. I imagined all of the information being local to each instance of the product, where there exists one backend user who edits and manipulates data, and multiple front end users who select their Meal(s) to create an Order. Ideally, all of the front end users would have all of this information stored locally within the library, and would update the library on startup from a database. How should I go about storing the data so that I can load it into the library every time the user opens the application? Do I package a database onboard and just load and populate every time? The only method I can currently conceive of doing this, even if I only have 500 possible Product objects, would require me to foreach the list for every Product that I need to match to a Recipe and so on and so forth every time I relaunch the program, which seems like a lot of wasteful loading. Here is a general flow of my architecture: Products: public class Product : IPortionable { public Product(string n, uint pNumber = 0) { name = n; productNumber = pNumber; } public string name { get; set; } public uint productNumber { get; set; } } Recipes: public Recipe(string n, decimal yieldAmt, Volume.Unit unit) { name = n; yield = new Volume(yieldAmt, unit); yield.ConvertUnit(); } /// <summary> /// Creates a new ingredient object /// </summary> /// <param name="n">Name</param> /// <param name="yieldAmt">Recipe Yield</param> /// <param name="unit">Unit of Yield</param> public Recipe(string n, decimal yieldAmt, Weight.Unit unit) { name = n; yield = new Weight(yieldAmt, unit); } public Recipe(Recipe r) { name = r.name; yield = r.yield; ingredients = r.ingredients; } public string name { get; set; } public IMeasure yield; public Dictionary<IPortionable, IMeasure> ingredients = new Dictionary<IPortionable,IMeasure>(); MenuItems: public abstract class MenuItem : IScalable { public static string title = null; public string name { get; set; } public decimal maxPortionSize { get; set; } public decimal minPortionSize { get; set; } public Dictionary<IPortionable, IMeasure> ingredients = new Dictionary<IPortionable, IMeasure>(); and Meal: public class Meal { public Meal(int guests) { guestCount = guests; } public int guestCount { get; private set; } //TODO: Make a new MainCourse class that holds pasta and Entree public Dictionary<string, int> counts = new Dictionary<string, int>(){ {MainCourse.title, 0}, {Side.title , 0}, {Appetizer.title, 0} }; public List<MenuItem> items = new List<MenuItem>(); The Database just stores and links each of these basic names and amounts together usings ID's (RecipeID, ProductID and MenuItemID)

    Read the article

  • A developer&rsquo;s WBS &ndash; 3 factors of 5

    - by johndoucette
    As a development manager, I have requested work breakdown structures (WBS) many times from the dev leads. Everyone has their own approach and why it takes sometimes days to get this simple list is often frustrating. Here is a simple way to get that elusive WBS done in 30 minutes and have 125 items in your list – well, 126. The WBS is made up of parent-child entities representing the overall outcome of the project. At the bottom of the hierarchical list should be the task item that a developer would perform in support of the branch in the list or WBS. Because I work with different dev leads on every project, I always ask the “what time value would you like to see at the lowest task in order to assign it to a developer and ensure it gets done within the timeframe”. I am particular to a task being 8 hours. Some like 8 to 24 hours. Stay away from tasks defaulting to 1 week. The task becomes way to vague and hard to manage completeness, especially on short budgets. As a developer, your focus is identifying the tasks you to accomplish in order to deliver the product. As a project manager, you will take the developer's WBS and add all the “other stuff” like quality testing, meetings, documentation, transition to maintenance, etc… Start your exercise with the name of the product you are delivering as a result of the project. You should be able to represent what you are building and deploying with one to three words. Example; XYZ Public Website Middleware BizTalk Application The reason you start with that single identifier is to always see the list as the product. It helps during each of the next three passes. Now, choose 5 tasks which in their entirety represent the product you will be delivering and add them to list under the product name you created earlier; Public Website     Security     Sites     Infrastructure     Publishing     Creative Continue this concept of seeing the list as the complete picture and decompose it one more level. You should have 25 items. Public Website     Security         Authentication         Login Control         Administration         DRM         Workflow     Sites         Masterpages         Page Layouts         Web Parts (RIA, Multimedia)         Content Types         Structures     Infrastructure         ...     Publishing         ...     Creative         ... And one more time for a total of 125 items. The top item makes the list 126. Public Website     Security         Authentication             Install (AD/ADAM/LDAP/SQL)             Configuration             Management             Web App Configuration             Implement Provider         Login Control             Login Form             Login/Logoff             pw change             pw recover/forgot             email verification         Administration             ...         DRM             ...         Workflow             ...     Sites         Masterpages         Page Layouts         Web Parts (RIA, Multimedia)         Content Types         Structures     Infrastructure         ...     Publishing         ...     Creative         ... The next step is to make sure the task at the bottom of every branch represents the “time value” you planned for the project. You can add more to the WBS and of course if you can’t find 5 items, 4 is fine. If a task can be done in a fraction of the time value you determined for the project, try to roll it up into a larger task. In the task actions (later when the iteration is being planned), decompose the details back to the simple tasks. Now, go estimate!

    Read the article

  • Reaching to the Holy Grail of Data Management

    - by Irem Radzik
    Pervasive, continuous access to trusted data. That’s the ultimate goal of data management. It enables to leverage data as an asset to create value for customers and the organization. It creates the strong foundation needed to move the business forward. How you get there is also critical. As with all IT initiatives using high performance solutions with low cost of ownership is another key requirement in today’s IT world. Oracle's  data integration product strategy focuses on helping customers achieve this ultimate goal with high performance and low TCO.  At OpenWorld, we will be showing how Oracle Data Integration products help you reach your data management goals, considering new trends in information management, such as big data and cloud computing. We will also provide an update on the latest product releases, such as Oracle GoldenGate 11gR2. If you will be at OpenWorld, please join us on Monday Oct 1st 10:45am at Moscone West – 3005 to hear our VP of Product Development, Brad Adelberg, present "Future Strategy, Direction, and Roadmap of Oracle’s Data Integration Platform". The Data Integration track at OpenWorld covers variety of topics and speakers. In addition to product management of Oracle GoldenGate, Oracle Data Integrator, and Enteprise Data Quality presenting product updates and roadmap, we have several customer panels and stand-alone sessions featuring select customers such as St. Jude Medical, Raymond James, Aderas, Turkcell, Paychex, Comcast,  Ticketmaster, Bank of America and more. You can see an overview of Data Integration sessions here. If you are not able to attend OpenWorld, please check out our latest resources for Data Integration and Oracle GoldenGate. In the coming weeks you will see more blogs about our products’ new capabilities and what to expect at OpenWorld. I hope to see you at OpenWorld and stay in touch via our future blogs. Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin;}

    Read the article

  • Why Are We Here?

    - by Jonathan Mills
    Back in the early 2000s, Toyota had a vision of building the number one best selling minivan in North America. Their current minivan, the Sienna, was small, underpowered, and badly needed help.  Yuji Yokoya was given the job of re-engineering the Sienna. There was just one problem, Yuji, lived in Japan. He did not know the people or places that he would be engineering for. Believe it or not, Japan is nothing like North America. So, what does a chief engineer do in a situation like that? He packed up his team and flew halfway around the world. He made a commitment to drive through every state in the US, every province in Canada, and Mexico. He met the people and drove the roads that the Sienna would be driving. And guess what, what he learned on that trip revolutionized the Sienna. The innovations he made, sent the Sienna to number one. Why? Because he knew who he was building his product for. He knew, why he was there.Let me ask you this, do you know why you are building what you are building? As a member of a product team, can you tell me how your product will be used in the real world? As you are writing code, building test plans, writing stories, or any of the other project tasks, can you picture the face of a person who will be using what you are building? All to often, the answer to those questions is, no. Why is it important? Because, every day, project team members make assumptions. Over a given project, it is safe to say project team members will make thousands of assumptions about what they are doing. And all to often, those assumptions are not quite right. Its not that they are not good at their job, its just that they don’t really know why they are there.So, what to do? First and foremost, stop doing what you are doing. Yes, really. Schedule some time to go visit the people who will be using your product. Don’t invite them to you, go to them. Watch them work. Interact with them. Ask them questions. Maybe even try it out yourself. This serves two purposes. One, It shows them that you care about them. They will be far more engaged in your project if they feel like you care. And nothing says you care more that spending some time. Second, if gives you the proper frame of reference for you work. It gives you something tangible to go back to as you are building your product. As you make the thousands of assumptions that you will make over the life of your project, it gives you something to see in your mind that makes it real to you.Ultimately, setting a proper frame of reference is critical to the overall success of a project. The funny thing is, it really does not even take that long. In most cases, a 2-3 hour session will give you most of what you need to get the right insight. For the project, it will be the best 2 hours you could spend.

    Read the article

  • Convert IEnumerable to EntitySet

    - by Gregorius
    Hey all, Hoping somebody can shed some light, and perhaps a possible solution to this issue I'm having... I have used LINQ to SQL to pull some data from a database into local entities. They are products from a shopping cart system. A product can contain a collection of KitGroups (which are stored in an EntitySet (System.Data.Linq.EntitySet). KitGroups contain collections of KitItems, and KitItems can contain Nested Products (which link back up to the original Product type - so its recursive). From these entities I'm building XML using LINQ to XML - all good here - my XML looks beautiful, calling a "GenerateProductElement" function, which calls itself recursively to generate the nested products. Wonderful stuff. However, here's where i'm stuck.. i'm now trying to deserialize that XML back to the original objects (all autogenerated by Linq to SQL)... and herein lies the problem. Linq tO Sql expects my collections to be EntitySet collections, however Linq to Xml (which i'm tyring to use to deserailise) is returning IEnumerable. I've experimented with a few ways of casting between the 2, but nothing seems to work... I'm starting to think that I should just deserialise manually (with some funky loops and conditionals to determine which KitGroup KitItems belong to, etc)... however its really quite tricky and that code is likely to be quite ugly, so I'd love to find a more elegant solution to this problem. Any suggestions? Here's a code snippet: private Product GenerateProductFromXML(XDocument inDoc) { var prod = from p in inDoc.Descendants("Product") select new Product { ProductID = (int)p.Attribute("ID"), ProductGUID = (Guid)p.Attribute("GUID"), Name = (string)p.Element("Name"), Summary = (string)p.Element("Summary"), Description = (string)p.Element("Description"), SEName = (string)p.Element("SEName"), SETitle = (string)p.Element("SETitle"), XmlPackage = (string)p.Element("XmlPackage"), IsAKit = (byte)(int)p.Element("IsAKit"), ExtensionData = (string)p.Element("ExtensionData"), }; //TODO: UUGGGGGGG Converting b/w IEnumerable & EntitySet var kitGroups = (from kg in inDoc.Descendants("KitGroups").Elements("KitGroup") select new KitGroup { KitGroupID = (int) kg.Attribute("ID"), KitGroupGUID = (Guid) kg.Attribute("GUID"), Name = (string) kg.Element("Name"), KitItems = // THIS IS WHERE IT FAILS - "Cannot convert source type IEnumerable to target type EntitySet..." (from ki in kg.Descendants("KitItems").Elements("KitItem") select new KitItem { KitItemID = (int) ki.Attribute("ID"), KitItemGUID = (Guid) ki.Attribute("GUID") }); }); Product ImportedProduct = prod.First(); ImportedProduct.KitGroups = new EntitySet<KitGroup>(); ImportedProduct.KitGroups.AddRange(kitGroups); return ImportedProduct; }

    Read the article

  • Cant insert row with auto-increment key via FluentNhibernate

    - by Jeff Shattock
    I'm getting started with Fluent NHibernate, and NHibernate in general. I'm trying to do something that I feel is pretty basic, but I cant quite get it to work. I'm trying to add a new entry to a simple table. Here's the Entity class. public class Product { public Product() { id = 0; } public virtual int id {get; set;} public virtual string description { get; set; } } Here's its mapping. public class ProductMap : ClassMap<Product> { public ProductMap() { Id(p => p.id).GeneratedBy.Identity().UnsavedValue(0); Map(p => p.description); } } I've tried that with and without the additional calls after Id(). And the insert code: var p = new Product() { description = "Apples" }; using (var s = _sf.CreateSession()) { s.Save(new_product); s.Flush(); } where _sf is a properly configured SessionSource. When I execute this code, I get: NHibernate.AssertionFailure : null identifier, which makes sense based on the SQL that NHibernate is executing: INSERT INTO "Product" (description) VALUES (@p0);@p0 = 'Apples' It doesnt seem to be trying to set the Id field, which seems ok (on its face) since the DB should generate that. But its not, I think. The DB schema is autogenerated by FNH: var config = Fluently.Configure().Database(MsSqlCeConfiguration.Standard.ShowSql().ConnectionString(@"Data Source=Database1.sdf")); var SessionSource = new SessionSource(config.BuildConfiguration().Properties, new ModelMappings()); var Session = SessionSource.CreateSession(); SessionSource.BuildSchema(Session); CreateInitialData(Session); Session.Flush(); Session.Clear(); I'm sure to be doing tons of things wrong, but whats the one thats causing this error?

    Read the article

  • Repository Pattern and Entity Framework.

    - by vitorcast
    Hi people, I want to make an implementation with repository pattern with ASP.NET MVC 2 and Entity Framework but I have had some issues in the process. First of all, I have 2 entities that has a relationship between them, like Order and Product. When I generate my dbml file it gaves me a class Order with a property that map a "ProductSet" and one class Product with a property that map wich Order that Product relates itself. So I create my Repository pattern like IReporitory with the basic CRUD operations and inside my controllers I implement the ProductRepository or OrderRepository. The problem occurs when I try to create Product and have to assign my Order on it, like ProductOne.Order = _orderRepository.Find(orderId); That operation gave me some strange behavior and I can't find out what is wrong with it. Thanks for the help.

    Read the article

  • LinqToSql - Parallel - DataContext and Parallel

    - by Gregoire
    In .NET 4 and multicore environment, does the linq to sql datacontext object take advantage of the new parallels if we use DataLoadOptions.LoadWith? EDIT I know linq to sql does not parallelize ordinary queries. What I want to know is when we specify DataLoadOption.LoadWith, does it use parallelization to perform the match between each entity and its sub entities? Example: using(MyDataContext context = new MyDataContext()) { DataLaodOptions options =new DataLoadOptions(); options.LoadWith<Product>(p=>p.Category); return this.DataContext.Products.Where(p=>p.SomeCondition); } generates the following sql: Select Id,Name from Categories Select Id,Name, CategoryId from Products where p.SomeCondition when all the products are created, will we have a categories.ToArray(); Parallel.Foreach(products, p => { p.Category == categories.FirstOrDefault(c => c.Id == p.CategoryId); }); or categories.ToArray(); foreach(Product product in products) { product.Category = categories.FirstOrDefault(c => c.Id == product.CategoryId); } ?

    Read the article

  • Nhibernate Criteria Query with Join

    - by John Peters
    I am looking to do the following using an NHibernate Criteria Query I have "Product"s which has 0 to Many "Media"s A product can be associated with 1 to Many ProductCategories These use a table in the middled to create the join ProductCategories Id Title ProductsProductCategories ProductCategoryId ProductId Products Id Title ProductMedias ProductId MediaId Medias Id MediaType I need to implement a criteria query to return All Products in a ProductCategory and the top 1 associated Media or no media if none exists. So although for example a "T Shirt" may have 10 Medias associated, my result should be something similar to this Product.Id Product.Title MediaId 1 T Shirt 21 2 Shoes Null 3 Hat 43 I have tried the following solutions using JoinType.LeftOuterJoin 1) productCriteria.SetResultTransformer(Transformers.DistinctRootEntity); This hasnt worked as the transform is done code side and as I have .SetFirstResult() and .SetMaxResults() for paging purposes it wont work. 2) .SetProjection( Projections.Distinct( Projections.ProjectionList() .Add(Projections.Alias(Projections.Property("Id"), "Id")) ... .SetResultTransformer(Transformers.AliasToBean()); This hasn't worked as I cannot seem to populate a value for Medias.Id in the projections. (Similar to http://stackoverflow.com/questions/1036116/nhibernate-criteria-api-projections) Any help would be greatly appreciated

    Read the article

  • Doctrine 2 Cannot find entites

    - by Flyn San
    I'm using Kohana 3 and have a /doctrine/Entites folder with my entities inside. When executing the code $product = Doctrine::em()->find('Entities\Product', 1); in my controller, I get the error class_parents(): Class Entities\Product does not exist and could not be loaded Below is the Controller (classes/controller/welcome.php): <?php class Controller_Welcome extends Controller { public function action_index() { $prod = Doctrine::em()->find('Entities\Product', 1); } } Below is the Entity (/doctrine/Entities/Product.php): <?php /** * @Entity * @Table{name="products"} */ class Product { /** @Id @Column{type="integer"} */ private $id; /** @Column(type="string", length="255") */ private $name; public function getId() { return $this->id; } public function setId($id) { $this->id = intval($id); } public function getName() { return $this->name; } public function setName($name) { $this->name = $name; } } Below is the Doctrine module bootstrap file (/modules/doctrine/init.php): class Doctrine { private static $_instance = null; private $_application_mode = 'development'; private $_em = null; public static function em() { if ( self::$_instance === null ) self::$_instance = new Doctrine(); return self::$_instance->_em; } public function __construct() { require __DIR__.'/classes/doctrine/Doctrine/Common/ClassLoader.php'; $classLoader = new \Doctrine\Common\ClassLoader('Doctrine', __DIR__.'/classes/doctrine'); $classLoader->register(); $classLoader = new \Doctrine\Common\ClassLoader('Symfony', __DIR__.'/classes/doctrine/Doctrine'); $classLoader->register(); $classLoader = new \Doctrine\Common\ClassLoader('Entities', APPPATH.'doctrine'); $classLoader->register(); //Set up caching method $cache = $this->_application_mode == 'development' ? new \Doctrine\Common\Cache\ArrayCache : new \Doctrine\Common\Cache\ApcCache; $config = new Configuration; $config->setMetadataCacheImpl( $cache ); $driver = $config->newDefaultAnnotationDriver( APPPATH.'doctrine/Entities' ); $config->setMetadataDriverImpl( $driver ); $config->setQueryCacheImpl( $cache ); $config->setProxyDir( APPPATH.'doctrine/Proxies' ); $config->setProxyNamespace('Proxies'); $config->setAutoGenerateProxyClasses( $this->_application_mode == 'development' ); $dbconf = Kohana::config('database'); $dbconf = reset($dbconf); //Use the first database specified in the config $this->_em = EntityManager::create(array( 'dbname' => $dbconf['connection']['database'], 'user' => $dbconf['connection']['username'], 'password' => $dbconf['connection']['password'], 'host' => $dbconf['connection']['hostname'], 'driver' => 'pdo_mysql', ), $config); } } Any ideas what I've done wrong?

    Read the article

  • Private constructor and public parameter constructor -C#

    - by Amutha
    I heard that private constructor prevent object creation from outside world. When i have a code public class Product { public string Name { get;set;} public double Price {get;set;} Product() { } public Product(string _name,double _price) { } } here still i can declare public constructor(parameter),won't it spoil the purpose of private constructor? When do we need both private and public constructor(parameter) in code? I need detailed explanation please.

    Read the article

  • sharp architecture mapping error

    - by fez
    this is the error when i load product entity my code is Configuration cfg = new NHibernate.Cfg.Configuration(); ISessionFactory sessions; public MedicineController() //Construtor { cfg.Configure(); sessions = cfg.BuildSessionFactory(); } using (var session = sessions.OpenSession()) { var pGet = session.Get<Product>(0); } The Error is Unable to locate persister for the entity named 'SharpArchitecture.Domain.Product'. The persister define the persistence strategy for an entity. Possible causes: - The mapping for 'SharpArchitecture.Domain.Product' was not added to the NHibernate configuration. Thanks in advance

    Read the article

  • How to group a complex list of objects using LINQ?

    - by Daoming Yang
    I want to select and group the products, and rank them by the number of times they occur. For example, I have an OrderList each of order object has a OrderProductVariantList(OrderLineList), and each of OrderProductVariant object has ProductVariant, and then the ProductVariant object will have a Product object which contains product information. A friend helped me with the following code. It could be compiled, but it did not return any value/result. I used the watch window for the query and it gave me "The name 'query' does not exist in the current context". Can anyone help me? Many thanks. var query = orderList.SelectMany( o => o.OrderLineList ) // results in IEnumerable<OrderProductVariant> .Select( opv => opv.ProductVariant ) .Select( pv => p.Product ) .GroupBy( p => p ) .Select( g => new { Product = g.Key, Count = g.Count() });

    Read the article

  • Django: Using 2 different AdminSite instances with different models registered

    - by omat
    Apart from the usual admin, I want to create a limited admin for non-staff users. This admin site will have different registered ModelAdmins. I created a folder /useradmin/ in my project directory and similar to contrib/admin/_init_.py I added an autodiscover() which will register models defined in useradmin.py modules instead of admin.py: # useradmin/__init__.py def autodiscover(): # Same as admin.autodiscover() but registers useradmin.py modules ... for app in settings.INSTALLED_APPS: mod = import_module(app) try: before_import_registry = copy.copy(site._registry) import_module('%s.useradmin' % app) except: site._registry = before_import_registry if module_has_submodule(mod, 'useradmin'): raise I also cretated sites.py under useradmin/ to override AdminSite similar to contrib/admin/sites: # useradmin/sites.py class UserAdminSite(AdminSite): def has_permission(self, request): # Don't care if the user is staff return request.user.is_active def login(self, request): # Do the login stuff but don't care if the user is staff if request.user.is_authenticated(): ... else: ... site = UserAdminSite(name='useradmin') In the project's URLs: # urls.py from django.contrib import admin import useradmin admin.autodiscover() useradmin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^useradmin/', include(useradmin.site.urls)), ) And I try to register different models in admin.py and useradmin.py modules under app directories: # products/useradmin.py import useradmin class ProductAdmin(useradmin.ModelAdmin): pass useradmin.site.register(Product, ProductAdmin) But when registering models in useradmin.py like useradmin.site.register(Product, ProductAdmin), I get 'module' object has no attribute 'ModelAdmin' exception. Though when I try this via shell; import useradmin from useradmin import ModelAdmin does not raise any exception. Any ideas what might be wrong? Edit: I tried going the @Luke way and arranged the code as follows as minimal as possible: (file paths are relative to the project root) # admin.py from django.contrib.admin import autodiscover from django.contrib.admin.sites import AdminSite user_site = AdminSite(name='useradmin') # urls.py (does not even have url patterns; just calls autodiscover()) import admin admin.autodiscover() # products/admin.py import admin from products.models import Product admin.user_site.register(Product) As a result I get an AttributeError: 'module' object has no attribute 'user_site' when admin.user_site.register(Product) in products/admin.py is called. Any ideas? Solution: I don't know if there are better ways but, renaming the admin.py in the project root to useradmin.py and updating the imports accordingly resolved the last case, which was a naming and import conflict.

    Read the article

  • Conflict between Jquery Validate and Asp.net MVC

    - by chobo2
    Hi I am using asp.net mvc 2.0 and jquery validate 1.7 (http://bassistance.de/jquery-plugins/jquery-plugin-validation/) What happens is this. A user can click on a link to edit a product. When a user clicks on which product they want to edit a jquery dialog box appears with a form of textboxes and dropdown lists. These html controls have information filled in them. Say if the user chooses to edit the Ipad product a dialog will appear and one of the form textboxes will have "Ipad" in it. Now this form gets rendered on the server side(the form is in a partial view). When loading the dialog box a ajax request is made to get that partial view and in the response part of the ajax call I do something like $('#EditDialog).html(ajaxresponse).dialog({...}); So I would have something like this rendered in my dialog box <form id="EditProduct"> Product Name: <input type="text" value="IPad" name="ProductName" /> </form> Now my jquery validate would be something like this. $("#EditProduct").validate( { errorContainer: "#Errorbox", errorLabelContainer: "#Errorbox ul", wrapper: "li", rules: { ProductName: "required" } }); So I know this works because I use the same validate for add product and if you try to leave ProductName blank it will show a validation error. Now it does not work with the edit one though and I think I know the reason why but not how to fix it. The value for the textbox is "IPad" this is how the Html.TextBoxFor() renders it. However if a user goes and changes the product name to "Iphone" or blank the value never changes. It is always "Ipad" in the html. So I think when the validate goes and looks it goes oh there is a value already in it. It is valid even though in reality it might be blank. When I post to the server through ajax it gets the right value and the server side validation stops it but my entire clientside validation is rendered useless because of this problem as it will never change the html.

    Read the article

  • Fluent | Nhibernate multiple inheritance mapping?

    - by Broken Pipe
    I'm trying to map this classes: public interface IBusinessObject { Guid Id { get; set; } } public class Product { public virtual Guid Id { get; set; } public virtual int ProductTypeId { get; set; } } public class ProductWeSell : Product, IBusinessObject { } public class ProductWeDontSell : Product { } Using this Fluent mapping code: public class IBusinessObjectMap : ClassMap<IBusinessObject> { public IBusinessObjectMap() { Id(t => t.Id).GeneratedBy.Guid(); Table("BusinessObject"); } } public class ProductMap : ClassMap<Product> { public ProductMap() { Id(t => t.Id); DiscriminateSubClassesOnColumn("ProductTypeId", "null").Nullable(); } } public class ProductWeSellMap : SubclassMap<ProductWeSell> { public ProductWeSellMap() { DiscriminatorValue(1); KeyColumn("Id"); } } public class ProductWeDontSellMap : SubclassMap<ProductWeDontSell> { public ProductWeDontSellMap() { DiscriminatorValue(2); KeyColumn("Id"); } } But I get {"Duplicate class/entity mapping ProductWeSell"} error. And if we take a look at generated HBM, indeed it's duplicated, but i have no idea how to write this mapping without duplicating it if it's possible at all. Produced hbm: <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class xmlns="urn:nhibernate-mapping-2.2" name="IBusinessObject" table="BusinessObject"> <joined-subclass name="ProductWeSell" table="ProductWeSell"/> </class> </hibernate-mapping> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class xmlns="urn:nhibernate-mapping-2.2" discriminator-value="null" name="Product" table="Product"> <discriminator type="String"> <column name="ProductTypeId" not-null="false" /> </discriminator> <subclass name="ProductWeDontSell" discriminator-value="2" /> <subclass name="ProductWeSell" discriminator-value="1" /> </class> </hibernate-mapping> So far I was unable to figure out how to map this using fluent Nhibernate (i haven't tried mapping this using hmb files). Any help appreciated Fluent or HBM files. The thing I'm trying to solve look identical to this topic: NHibernate inheritance mapping question

    Read the article

  • Ternary (and n-ary) relationships in Hibernate

    - by Bytecode Ninja
    Q 1) How can we model a ternary relationship using Hibernate? For example, how can we model the ternary relationship presented here using Hibernate (or JPA)? Ideally I prefer my model to be like this: class SaleAssistant { Long id; //... } class Customer { Long id; //... } class Product { Long id; //... } class Sale { SalesAssistant soldBy; Customer buyer; Product product; //... } Q 1.1) How can we model this variation, in which each Sale item might have many Products? class SaleAssistant { Long id; //... } class Customer { Long id; //... } class Product { Long id; //... } class Sale { SalesAssistant soldBy; Customer buyer; Set<Product> products; //... } Q 2) In general, how can we model n-ary, n = 3 relationships with Hibernate? Thanks in advance.

    Read the article

  • Query returns too few rows

    - by Tareq
    setup: mysql> create table product_stock( product_id integer, qty integer, branch_id integer); Query OK, 0 rows affected (0.17 sec) mysql> create table product( product_id integer, product_name varchar(255)); Query OK, 0 rows affected (0.11 sec) mysql> insert into product(product_id, product_name) values(1, 'Apsana White DX Pencil'); Query OK, 1 row affected (0.05 sec) mysql> insert into product(product_id, product_name) values(2, 'Diamond Glass Marking Pencil'); Query OK, 1 row affected (0.03 sec) mysql> insert into product(product_id, product_name) values(3, 'Apsana Black Pencil'); Query OK, 1 row affected (0.03 sec) mysql> insert into product_stock(product_id, qty, branch_id) values(1, 100, 1); Query OK, 1 row affected (0.03 sec) mysql> insert into product_stock(product_id, qty, branch_id) values(1, 50, 2); Query OK, 1 row affected (0.03 sec) mysql> insert into product_stock(product_id, qty, branch_id) values(2, 80, 1); Query OK, 1 row affected (0.03 sec) my query: mysql> SELECT IFNULL(SUM(s.qty),0) AS stock, product_name FROM product_stock s RIGHT JOIN product p ON s.product_id=p.product_id WHERE branch_id=1 GROUP BY product_name ORDER BY product_name; returns: +-------+-------------------------------+ | stock | product_name | +-------+-------------------------------+ | 100 | Apsana White DX Pencil | | 80 | Diamond Glass Marking Pencil | +-------+-------------------------------+ 1 row in set (0.00 sec) But I want to have the following result: +-------+------------------------------+ | stock | product_name | +-------+------------------------------+ | 0 | Apsana Black Pencil | | 100 | Apsana White DX Pencil | | 80 | Diamond Glass Marking Pencil | +-------+------------------------------+ To get this result what mysql query should I run?

    Read the article

  • How to change id value when using Html.DropDownListFor helper in asp.net mvc 2.0?

    - by chobo2
    Hi I have a partial view that has something like this <%= Html.DropDownListFor(m => m.SelectedProductName, Model.ProductList, "Select a Product") %> Now you can create a new product and edit a existing product. Both editing and creating use the same form. The create is on the main page on load up. Edit popus up in a jquery u.i model dialog and renders a new partial view. So as far as the page is concerned is that I have 2 dropdown boxes with the same "id" which is bad since they should be unique. So how do I change the id? So when the edit loads it might have a id of "editSelectedProductName"? I tried to do this in the view model public string SelectedProductName{ get; set; } ViewModelConstructor() { SelectedProductName = "EditSelectedProductName"; } But it seems to not care and keeps using "SelectedProductName" as the product name. Thanks

    Read the article

  • SO what RDF database do i use?

    - by keisimone
    Hi, i have a similar issue as espoused in http://stackoverflow.com/questions/695752/product-table-many-kinds-of-product-each-product-has-many-parameters i am convinced to use RDF now. but i already have a database in mysql and the code is in php. 1) So what RDF database should I use? 2) do i combine the approach? meaning i have a class table inheritance in the mysql database and just the weird product attributes in the RDF? I dont think i should move everything to a RDF database since it is only just products and the wide array of possible attributes and value that is giving me the problem. 3) what php resources, articles should i look at that will help me better in the creation of this? 4) thank you.

    Read the article

  • how can i convert a .tpl file to a .php file? [closed]

    - by kim
    What do I do?? I am building a site and there is a categories.tpl that I want to go where sitemap.php is. sorry i am brand new to all this. let me try to be more clear.id show you a picture but it is marking it as spam. i have a menu at the top of my site like with any retail site. [About Cart Account and Products]. when you click products it takes to you the sitemap.php file. however i need the content from the categories.tpl to appear instead. (Categories in prestashop is another way of saying products) here is the categories.tpl code: {include file=$tpl_dir./breadcrumb.tpl} {include file=$tpl_dir./errors.tpl} {if $category-id AND $category-active} {$category-name|escape:'htmlall':'UTF-8'} {$nb_products|intval} {if $nb_products1}{l s='products'}{else}{l s='product'}{/if} {if $scenes} <!-- Scenes --> {include file=$tpl_dir./scenes.tpl scenes=$scenes} {else} <!-- Category image --> {if $category->id_image} <img src="{$link->getCatImageLink($category->link_rewrite, $category->id_image, 'category')}" alt="{$category->name|escape:'htmlall':'UTF-8'}" title="{$category->name|escape:'htmlall':'UTF-8'}" id="categoryImage" /> {/if} {/if} {if $category->description} <div class="cat_desc">{$category->description}</div> {/if} {if isset($subcategories)} <!-- Subcategories --> <div id="subcategories"> <h3>{l s='Subcategories'}</h3> <ul class="inline_list"> {foreach from=$subcategories item=subcategory} <li> <a href="{$link->getCategoryLink($subcategory.id_category, $subcategory.link_rewrite)|escape:'htmlall':'UTF-8'}" title="{$subcategory.name|escape:'htmlall':'UTF-8'}"> {if $subcategory.id_image} <img src="{$link->getCatImageLink($subcategory.link_rewrite, $subcategory.id_image, 'medium')}" alt="" /> {else} <img src="{$img_cat_dir}default-medium.jpg" alt="" /> {/if} </a> <br /> <a href="{$link->getCategoryLink($subcategory.id_category, $subcategory.link_rewrite)|escape:'htmlall':'UTF-8'}">{$subcategory.name|escape:'htmlall':'UTF-8'}</a> </li> {/foreach} </ul> <br class="clear"/> </div> {/if} {if $products} {include file=$tpl_dir./product-sort.tpl} {include file=$tpl_dir./product-list.tpl products=$products} {include file=$tpl_dir./pagination.tpl} {elseif !isset($subcategories)} <p class="warning">{l s='There is no product in this category.'}</p> {/if} {elseif $category-id} {l s='This category is currently unavailable.'} {/if} and here is the sitemap.php include(dirname(FILE).'/config/config.inc.php'); include(dirname(FILE).'/header.php'); include(dirname(FILE).'/product-sort.php'); $nbProducts = intval(Product::getNewProducts(intval($cookie-id_lang), isset($p) ? intval($p) - 1 : NULL, isset($n) ? intval($n) : NULL, true)); include(dirname(FILE).'/pagination.php'); $smarty-assign(array( 'products' = Product::getNewProducts(intval($cookie-id_lang), intval($p) - 1, intval($n), false, $orderBy, $orderWay), 'nbProducts' = intval($nbProducts))); $smarty-display(_PS_THEME_DIR_.'new-products.tpl'); include(dirname(FILE).'/footer.php'); ?

    Read the article

  • testing In-app purchases iphone??

    - by hemant
    while testing my application i bought a product it had on my phone through the test account...now i deleted the application and reinstalled it but in my application it still shows that the product is already bought...when we buy through in-app purchase does the product i bought or its id gets stored on iphone filesystem?? i am just testing the application so i dont know much about what could be wrong in it??

    Read the article

< Previous Page | 51 52 53 54 55 56 57 58 59 60 61 62  | Next Page >