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• ignoring elements order in xml validation against xsd

  - by segolas

  Hi, Ia processing an email and saving some header inside a xml document. I also need to validate the document against a xml schema. As the subject suggest, I need to validate ignoring the elements order but, as far as I read this seems to be impossible. Am I correct? If I put the headers in a<xsd:sequence>, the order obviously matter. If I us the order is ignored but for some strange reason this imply that the elements must occur at least once. My xml is something like this: <headers> <subject>bla bla bla</subject> <recipient>[email protected]</recipient> <recipient>rcp02domain.com</recipient> <recipient>[email protected]</recipient> </headers> but I think the final document is valid even if subject and recipient elements are swapped. There is really nothing to do?

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• Linq to xml, retreaving generic interface-based list

  - by Rita

  I have an xml document that looks like this <Elements> <Element> <DisplayName /> <Type /> </Element> </Elements> I have an interface, interface IElement { string DisplayName {get;} } and a couple of derived classes: public class AElement: IElement public class BElement: IElement What I want to do, is to write the most efficient query to iterate through the xml and create a list of IElement, containing AElement or BElement, based on the 'Type' property in the xml. So far I have this: IEnumerable<AElement> elements = from xmlElement in XElement.Load(path).Elements("Element") where xmlElement.Element("type").Value == "AElement" select new AElement(xmlElement.Element("DisplayName").Value); return elements.Cast<IElement>().ToList(); But this is only for AElement, is there a way to add BElement in the same query, and also make it generic IEnumerable? Or would I have to run this query once for each derived type?

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• How to get values of xml elements?

  - by user187580

  Hi, I have some xml data and I am trying to access some elements. The structure of data is as below (using print_r($data)). I can get $data->{'parent'}->title, it works but if I try to get value of href using $data->{'parent'}->link[0]->{'@attributes'}->href .. it doesnt work .. any ideas? Thanks SimpleXMLElement Object ( [@attributes] => Array ( [children] => 29 [modules] => 0 ) [title] => Test title [link] => Array ( [0] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => data.php?id=2322 [rel] => self [type] => application/xml ) ) [1] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => data.php?id=2342 [rel] => alternate [type] => text/html ) ) ) [parent] => SimpleXMLElement Object ( [@attributes] => Array ( [children] => 6 [modules] => 0 ) [title] => Top [link] => Array ( [0] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => /data.php?id=5763 [rel] => self [type] => application/xml ) ) [1] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => /data.php?id=2342 [rel] => alternate [type] => text/html ) ) ) ) )

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• Default entries on a first time creation for a serialized class

  - by MGSoto

  I have a class I am using for serializing various configuration options for an application I am working on. I'm adding a new property to the class that is a List, and I'd like it to fill this list if it does not exist already in a XML file. My first thought was to check if the list contained zero items, however this is not acceptable because there are times I want to have zero items in the list. In essence I want a file that has been serialized with an older version of the same class to be "upgraded" and have defaults automatically inserted for new properties. How can I do this? For a more visual example of what I'm trying to do, see below: When I deserialize an XML file that contains: <Item1>wtfe</Item1> <Item2>wtfe</Item2> and after I've added a list property it will serialze as: <Item1>wtfe</Item1> <Item2>wtfe</Item2> <Item3/> I want it to serialize as: <Item1>wtfe</Item1> <Item2>wtfe</Item2> <Item3> <DefaultSubItem/ Field="wtfe"> <DefaultSubItem/ Field="wtfe"> </Item3> But allow me to change it to: <Item1>wtfe</Item1> <Item2>wtfe</Item2> <Item3></Item3>

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• Android XML Preference issue. Can't make it persistent

  - by Budius

  I have a very simple activity just to show the preference fragment: public class PreferencesActivity extends Activity { Fragment frag = null; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); FragmentTransaction ft = getFragmentManager().beginTransaction(); if (frag == null) { // If not, instantiate and add it to the activity frag = new PrefsFragment(); ft.add(android.R.id.content, frag, frag.getClass().getName()); } else { // If it exists, simply attach it in order to show it ft.attach(frag); } ft.commit(); } private static class PrefsFragment extends PreferenceFragment { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); addPreferencesFromResource(R.xml.preferences); } } } and preferences.xml with persistent to true: <?xml version="1.0" encoding="utf-8"?> <PreferenceScreen xmlns:android="http://schemas.android.com/apk/res/android" android:enabled="true" android:persistent="true" android:title="@string/settings" > <EditTextPreference android:dialogTitle="@string/dialog_ip" android:negativeButtonText="@android:string/cancel" android:persistent="true" android:positiveButtonText="@android:string/ok" android:title="@string/ip" /> </PreferenceScreen> if I open the EditTextPreference, write something, close the dialog and open it again. The value is still there. But that's it... if I click the Back button, and enter the again on the preferences screen, I already lost what was written. If you exit the application also doesn't save. Am I missing something here? Running on: Android 4.0.3 Asus TF300

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• Nested Data XML design

  - by esryl

  Looking to nest (to unlimited levels) elements in XML. Like so: <items> <item> <name>Item One</name> <item> <name>Item Two</name> </item> <item> <name>Item Three</name> <item> <name>Item Four</name> </item> <!-- etc... --> </item> </item> </items> However. While browsing for a solution I noticed in the comments of: http://stackoverflow.com/questions/988139/weird-nesting-in-xml while the above is well formed it would not validate against any sinsible DTD. Two things, what is a better way of nesting similar elements, and secondly what would be the design of the DTD. UPDATE: Would prefer to validate against an XML Schema rather than DTD.

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• LINQ to XML query attributes

  - by kb

  Hi using LINQ to XML, this is a sample of my XML <shows> <Show Code="456" Name="My Event Name"> <Event Code="2453" VenueCode="39" Date="2010-04-13 10:30:00" /> <Event Code="2454" VenueCode="39" Date="2010-04-13 13:30:00" /> <Event Code="2455" VenueCode="39" Date="2010-04-14 10:30:00" /> <Event Code="2456" VenueCode="39" Date="2010-04-14 13:30:00" /> <Event Code="2457" VenueCode="39" Date="2010-04-15 10:30:00" /> </Show> <Show... /> <Show... /> </shows> How do I return a list of the Dates for a specfic show? I am passing the show code ("456") in the querystring and want all the dates/times returned as a list. This is the code i have so far: XDocument xDoc = XDocument.Load("path to xml"); var feeds = from feed in xDoc.Descendants("Show") where feed.Attribute("Code").Equals("456") select new { EventDate = feed.Attribute("Date").Value }; foreach(var feed in feeds) { Response.Write(feed.EventDate + "<br />"); } But i get no results returned

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• Appending an existing XML file with c#

  - by Farstucker

  I have an existing XML file that I would like to append without changing the format. Existing File looks like this: <Clients> <User username="farstucker"> <UserID>1</UserID> <DOB /> <FirstName>Steve</FirstName> <LastName>Lawrence</LastName> <Location>NYC</Location> </User> </Clients> How can I add another user using this format? My existing code is: string fileLocation = "clients.xml"; XmlTextWriter writer; if (!File.Exists(fileLocation)) { writer = new XmlTextWriter(fileLocation, null); writer.WriteStartDocument(); // Write the Root Element writer.WriteStartElement("Clients"); // End Element and Close writer.WriteEndElement(); writer.Close(); } // Append new data here Ive thought about using XmlDocument Fragment to append the data but Im not certain if I can maintain the existing format ( and empty tags ) without messing up the file. Any advice you could give is much appreciated. EDIT Ive changed the code to read the original XML but the file keeps getting overwritten.

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• Linq-to-XML explicit casting in a generic method

  - by vlad

  I've looked for a similar question, but the only one that was close didn't help me in the end. I have an XML file that looks like this: <Fields> <Field name="abc" value="2011-01-01" /> <Field name="xyz" value="" /> <Field name="tuv" value="123.456" /> </Fields> I'm trying to use Linq-to-XML to get the values from these fields. The values can be of type Decimal, DateTime, String and Int32. I was able to get the fields one by one using a relatively simple query. For example, I'm getting the 'value' from the field with the name 'abc' using the following: private DateTime GetValueFromAttribute(IEnumerable<XElement> fields, String attName) { return (from field in fields where field.Attribute("name").Value == "abc" select (DateTime)field.Attribute("value")).FirstOrDefault() } this is placed in a separate function that simply returns this value, and everything works fine (since I know that there is only one element with the name attribute set to 'abc'). however, since I have to do this for decimals and integers and dates, I was wondering if I can make a generic function that works in all cases. this is where I got stuck. here's what I have so far: private T GetValueFromAttribute<T>(IEnumerable<XElement> fields, String attName) { return (from field in fields where field.Attribute("name").Value == attName select (T)field.Attribute("value").Value).FirstOrDefault(); } this doesn't compile because it doesn't know how to convert from String to T. I tried boxing and unboxing (i.e. select (T) (Object) field.Attribute("value").Value but that throws a runtime Specified cast is not valid exception as it's trying to convert the String to a DateTime, for instance. Is this possible in a generic function? can I put a constraint on the generic function to make it work? or do I have to have separate functions to take advantage of Linq-to-XML's explicit cast operators?

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• Structure map and generics (in XML config)

  - by James D

  Hi I'm using the latest StructureMap (2.5.4.264), and I need to define some instances in the xml configuration for StructureMap using generics. However I get the following 103 error: Unhandled Exception: StructureMap.Exceptions.StructureMapConfigurationException: StructureMap configuration failures: Error: 103 Source: Requested PluginType MyTest.ITest`1[[MyTest.Test,MyTest]] configured in Xml cannot be found Could not create a Type for 'MyTest.ITest`1[[MyTest.Test,MyTest]]' System.ApplicationException: Could not create a Type for 'MyTest.ITest`1[[MyTest.Test,MyTest]]' ---> System.TypeLoadException: Could not loa d type 'MyTest.ITest`1' from assembly 'StructureMap, Version=2.5.4.264, Culture=neutral, PublicKeyToken=e60ad81abae3c223'. at System.RuntimeTypeHandle._GetTypeByName(String name, Boolean throwOnError, Boolean ignoreCase, Boolean reflectionOnly, StackCrawlMark& stackMark, Boolean loadTypeFromPartialName) at System.RuntimeTypeHandle.GetTypeByName(String name, Boolean throwOnError, Boolean ignoreCase, Boolean reflectionOnly, StackCrawlMark& stackMark) at System.RuntimeType.PrivateGetType(String typeName, Boolean throwOnError, Boolean ignoreCase, Boolean reflectionOnly, StackCrawlMark& s tackMark) at System.Type.GetType(String typeName, Boolean throwOnError) at StructureMap.Graph.TypePath.FindType() --- End of inner exception stack trace --- at StructureMap.Graph.TypePath.FindType() at StructureMap.Configuration.GraphBuilder.ConfigureFamily(TypePath pluginTypePath, Action`1 action) A simply replication of the code is as follows: public interface ITest<T> { } public class Test { } public class Concrete : ITest<Test> { } Which I then wish to define in the XML configuration something as follows: <DefaultInstance PluginType="MyTest.ITest`1[[MyTest.Test,MyTest]],MyTest" PluggedType="MyTest.Concrete,MyTest" Scope="Singleton" /> I've been racking my brain, however I can't see what I'm doing wrong - I've used Type.GetType to verify the type actually is valid which it is. Anyone have any ideas? Thanks !

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• generating XML in rails

  - by PeterWong

  I created a controller having an action: def gen_books_xml @books = Book.find(:all, :conditions => {:owner_id => 1}) respond_to do |format| format.xml { render :xml => @books.to_xml(:root => "Books", :skip_types=>true) } end end How could I implement the to_xml method in the Book model sa that it can generate the following format? <?xml version="1.0" encoding="UTF-8"?> <Books> <Owner>1</Owner> <Book><title>some title</title></Book> <Book><title>some title</title></Book> <Book><title>some title</title></Book> ... </Books> where there is only 1 Owner element and many Book elements I can only output the Book elements but cannot output the one Owner in the same level of Books. Please HELP!!!

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• Java/Android get array from xml

  - by Ashley

  I have a list of longitude and longitude points in an xml file that is used throughout my application. I find my self repeating this code to get points often and think there must be a better way? String[] mTempArray = getResources().getStringArray(R.array.stations); int len = mTempArray.length; mStationArray = new ArrayList<Station>(); for(int i = 0; i < len; i++){ Station s = new Station(); String[] fields = mTempArray[i].split("[\t ]"); s.setValuesFromArray(fields); Log.i("ADD STATION", ""+s); mStationArray.add(s); } XML is in the format of: <?xml version="1.0" encoding="utf-8"?> <resources> <array name="stations"> <item> <name>Station name</name> <longitude>1111111</longitude> <latitude>11111</latitude> <code>1</code> </item> And another (possible) problem is that to get just one station I have to get all of them and pull the one I want from the array. Is this going to be considerably slower? Can I make this array consistent throughout the app? (But keeping the separate Intent methodology)

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• Reading XML or objects from a Web service

  - by Shawn

  This is my first time working with webservices and I am a bit lost. I successfully called the functions, but I only can get one value from the service. I read that the easiest way is to read xml or create objects and then call their values. Currently I use functions that return the desired value but I need to call them 3 times to get all the data witch is a waste of time and resources. I tried to call the service with the URL and use it as a website or getting the service to work the same way without importing into the program. The thing is that i cant find a way to pass the values into the url, because of that i get only blank pages. What is the fastest way to get my data from the services? I need city name, temperature and a flag if the city is valid. I need to pass the zip code to the service. Thank you. My current code wetther.Weather wether = new wetther.Weather(); string farenhait = wether.GetCityWeatherByZIP(zip).Temperature; string city = wether.GetCityWeatherByZIP(zip).City; bool correct = wether.GetCityWeatherByZIP(zip).Success; I tried it that way // Retrieve XML document XmlTextReader reader = new XmlTextReader("http://xml.weather.yahoo.com/forecastrss?p=94704"); // Skip non-significant whitespace reader.WhitespaceHandling = WhitespaceHandling.Significant; // Read nodes one at a time while (reader.Read()) { // Print out info on node Console.WriteLine("{0}: {1}", reader.NodeType.ToString(), reader.Name); } This one works for the yahoo page but not for mine. I need to use this webservice - http://wsf.cdyne.com/WeatherWS/Weather.asmx

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• How do I differentiate between different descendents with the same name?

  - by zotty

  I've got some XML I'm trying to import with c#, which looks something like this: <run> <name = "bob"/> <date = "1958"/> </run> <run> <name = "alice"/> <date = "1969"/> </run> I load my xml using XElement xDoc=XElement.Load(filename); What I want to do is have a class for "run", under which I can store names and dates: public class RunDetails { public RunDetails(XElement xDoc, XNamespace xmlns) { var query = from c in xDoc.Descendants(xmlns + "run").Descendants(xmlns + "name") select c; int i=0; foreach (XElement a in query) { this.name= new NameStr(a, xmlns); // a class for names Name.Add(this.name); //Name is a List<NameStr> i++; } // Here, i=2, but what I want is a new instance of the RunDetails class for each <run> } } How can I set up my code to create a new instance of the RunDetails class for every < run, and to only select the < name and < date inside a given < run?

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• flush XML tags having certain value

  - by azathoth

  Hello all I have a webservice that returns an XML like this: <?xml version="1.0" encoding="UTF-8"?> <contractInformation> <contract> <idContract type="int">87191827</idContract> <region type="varchar">null</region> <dueDate type="varchar">null</dueDate> <contactName type="varchar">John Smith</contactName> </contract> </contractInformation> I want to empty every tag that contains the string null, so it would look like this: <?xml version="1.0" encoding="UTF-8"?> <contractInformation> <contract> <idContract type="int">87191827</idContract> <region type="varchar"/> <dueDate type="varchar"/> <contactName type="varchar">John Smith</contactName> </contract> </contractInformation> How do I accomplish that by using XSLT?

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• Android Organizing Strings.xml

  - by Neb

  I'm making an android app and since I've just started I want to try get the most organised code/resources. In my strings.xml file so far I have this: <?xml version="1.0" encoding="utf-8"?> <resources> <string name="app_name">GameController</string> <string name="stop">Stop</string> <string name="start">Start</string> <string name="preferences">Preferences</string> <string name="back">Back</string> </resources> All of the strings except app_name are used in an options menu. But since I will be adding much more strings I was thinking that it might be better to do something like this: <?xml version="1.0" encoding="utf-8"?> <resources> <string name="app_name">GameController</string> <string name="menu_stop">Stop</string> <string name="menu_start">Start</string> <string name="menu_preferences">Preferences</string> <string name="menu_back">Back</string> </resources> Is it the best way or should I use another system?

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• How do you rename the child XML elements used in an XML Serialized List<string>?

  - by GrZeCh

  Hello, I'm serializing to XML my class where one of properties has type List<string>. public class MyClass { ... public List<string> Properties { get; set; } ... } XML created by serializing this class looks like this: <MyClass> ... <Properties> <string>somethinghere</string> <string>somethinghere</string> </Properties> ... </MyClass> and now my question. How can I change my class to achieve XML like this: <MyClass> ... <Properties> <Property>somethinghere</Property> <Property>somethinghere</Property> </Properties> ... </MyClass> after serializing. Thanks for any help!

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• linq to xml selection/update

  - by gleasonomicon

  If I have the following xml, how would I use linq to xml blank out the date fields in each video node? I wanted to do it for the purpose of a comparison in a unit test. <?xml version="1.0" encoding="utf-8" standalone="yes" ?> <main> <videos> <video> <id>00000000-0000-0000-0000-000000000000</id> <title>Video Title</title> <videourl>http://sample.com</videourl> <thumbnail>http://sample.com</thumbnail> <dateCreated>2011-01-12T18:54:56.7318386-05:00</dateCreated> <dateModified>2011-02-12T18:54:56.7318386-05:00</dateModified> <Numbers> <Number>28</Number> <Number>78</Number> </Numbers> </video> <video> <id>00000000-0000-0000-0000-000000000000</id> <title>Video Title</title> <videourl>http://sample.com</videourl> <thumbnail>http://sample.com</thumbnail> <dateCreated>2011-01-12T18:54:56.7318386-05:00</dateCreated> <dateModified>2011-02-12T18:54:56.7318386-05:00</dateModified> <Numbers> <Number>28</Number> <Number>78</Number> </Numbers> </video> </videos>

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• Restructure an xml document

  - by krishna

  here is my structure of xml document, <worldpatentdata> <patent-family> <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> <familymember>.....</familymember> <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> <familymember>.....</familymember> <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> <familymember>.....</familymember> </patent-family> </worldpatentdata> In the above xml structure,all the element is found to be child node of element. I want these elements as childnode of element,so that the xml have the following structure, <worldpatentdata> <patent-family> <familymember>..... <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> </familymember> <familymember>..... <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> </familymember> <familymember>..... <exchange-documents>......</exchange-documents> <exchange-documents>......</exchange-documents> </familymember> </patent-family> </worldpatentdata> can anybody help me on this? thanks

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• XML to JSON - losing root node

  - by Mike

  I'm using net.sf.json with a Java project and it works great. The conversion of this XML: <?xml version="1.0" encoding="UTF-8"?> <important-data certified="true" processed="true"> <timestamp>232423423423</timestamp> <authors> <author> <firstName>Tim</firstName> <lastName>Leary</lastName> </author> </authors> <title>Flashbacks</title> <shippingWeight>1.4 pounds</shippingWeight> <isbn>978-0874778700</isbn> </important-data> converts to this in JSON: { "@certified": "true", "@processed": "true", "timestamp": "232423423423", "authors": [ { "firstName": "Tim", "lastName": "Leary" }], "title": "Flashbacks", "shippingWeight": "1.4 pounds", "isbn": "978-0874778700" } However, the root tag <important-data> is lost in the conversion. Being new to XML and JSON, I am not sure if this is suppose to be the correct behaviour. If not, is there any way to tell net.sf.json to convert it while keeping the root node property? Thanks.

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• Javascript function with PHP throwing a "Illegally Formed XML Syntax" error

  - by Joe

  I'm trying to learn some javascript and i'm having trouble figuring out why my code is incorrect (i'm sure i'm doing something wrong lol), but anyways I am trying to create a login page so that when the form is submitted javascript will call a function that checks if the login is in a mysql database and then checks the validity of the password for the user if they exist. however I am getting an error (Illegally Formed XML Syntax) i cannot resolve. I'm really confused, mostly because netbeans is saying it is a xml syntax error and i'm not using xml. here is the code in question: function validateLogin(login){ login.addEventListener("input", function() { $value = login.value; if (<?php //connect to mysql mysql_connect(host, user, pass) or die(mysql_error()); echo("<script type='text/javascript'>"); echo("alert('MYSQL Connected.');"); echo("</script>"); //select db mysql_select_db() or die(mysql_error()); echo("<script type='text/javascript'>"); echo("alert('MYSQL Database Selected.');"); echo("</script>"); //query $result = mysql_query("SELECT * FROM logins") or die(mysql_error()); //check results against given login while($row = mysql_fetch_array($result)){ if($row[login] == $value){ echo("true"); exit(0); } } echo("false"); exit(0); ?>) { login.setCustomValidity("Invalid Login. Please Click 'Register' Below.") } else { login.setCustomValidity("") } }); } the code is in an external js file and the error throws on the last line. Also from reading i understand best practices is to not mix js and php so how would i got about separating them but maintaining the functionality i need? thanks!

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• How do I use XPath with a default namespace with no prefix?

  - by Scott Stafford

  What is the XPath (in C# API to XDocument.XPathSelectElements(xpath, nsman) if it matters) to query all MyNodes from this document? <?xml version="1.0" encoding="utf-8"?> <configuration> <MyNode xmlns="lcmp" attr="true"> <subnode /> </MyNode> </configuration I tried /configuration/MyNode which is wrong because it ignores the namespace. I tried /configuration/lcmp:MyNode which is wrong because lcmp is the URI, not the prefix. I tried /configuration/{lcmp}MyNode which failed because Additional information: '/configuration/{lcmp}MyNode' has an invalid token. EDIT: I can't use mgr.AddNamespace("df", "lcmp"); as some of the answerers have suggested. That requires that the XML parsing program know all the namespaces I plan to use ahead of time. Since this is meant to be applicable to any source file, I don't know which namespaces to manually add prefixes for. It seems like {my uri} is the XPath syntax, but Microsoft didn't bother implementing that... true?

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• Should xml represent a set or a list?

  - by sixtyfootersdude

  I always think of xml like a set data structure. Ie: <class> <person>john</person> <person>sarah</person> </class> Is equivalent to: <class> <person>sarah</person> <person>john</person> </class> Question One: Are these two things logicly equivalant? Are you allowed to make things like this in xml? <methodCall> <param>happy</param> <param>sad</param> </methodCall> Or do you need to do it like this: <methodCall> <param arg="1">happy</param> <param arg="2">sad</param> </methodCall> Question Two: Are these two things logically equivalent? Question Three: Is xml usually treated like a set or a list?

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• Creating a 'flexible' XML schema

  - by Fiona Holder

  I need to create a schema for an XML file that is pretty flexible. It has to meet the following requirements: Validate some elements that we require to be present, and know the exact structure of Validate some elements that are optional, and we know the exact structure of Allow any other elements Allow them in any order Quick example: XML <person> <age></age> <lastname></lastname> <height></height> </person> My attempt at an XSD: <xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xs:element name="person"> <xs:complexType> <xs:sequence> <xs:element name="firstname" minOccurs="0" type="xs:string"/> <xs:element name="lastname" type="xs:string"/> <xs:any processContents="lax" minOccurs="0" maxOccurs="unbounded" /> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Now my XSD satisfies requirements 1 and 3. It is not a valid schema however, if both firstname and lastname were optional, so it doesn't satisfy requirement 2, and the order is fixed, which fails requirement 4. Now all I need is something to validate my XML. I'm open to suggestions on any way of doing this, either programmatically in .NET 3.5, another type of schema etc. Can anyone think of a solution to satisfy all 4 requirements?

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• Trying to parse xml file for javascript quiz

  - by App_beginner

  Hi I am trying to create a javascript quiz, that gets the questions from a xml file. At the moment I am only starting out trying to parse my xml file without any success. Can anyone point me to what I am doing wrong? <html> <head> <title>Test</title> </head> <body> <div class="items"> </div> <script type="text/javascript"> var quizXML = '<quiz><Sporsmal tekst="bla bla bla"/><alternativer><tekst>bla</tekst><tekst>bli</tekst><tekst correct="yes">ble</tekst></alternativer><Sporsmal tekst="More blah"/><alternativer><tekst>bla bla</tekst><tekst correct="yes">bli bli</tekst><tekst>ble ble</tekst></alternativer></quiz>' var quizDOM = $.xmlDOM( quizXML ); quizDOM.find('quiz > Sporsmal').each(function() { var sporsmalTekst = $(this).attr('tekst'); var qDiv = $("<div />") .addClass("item") .addClass("sporsmal") .appendTo($(".spmArr")); var sTekst = $("<h2/>") .html(sporsmalTekst) .appendTo(qDiv); } </script> </body> </html> When I try this in my browser the classes and div are not being created. And the page is just blank. Am i doing something wrong when I intialize the xml?

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