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  • How can I replace the contents of a scrollable div without jumping to the top?

    - by RenderIn
    I have a div with the overflow: auto style. It is populated via AJAX with a result table. The rows in this div are editable, and with each edit I refresh the contents. The problem is, if the user edits something at the bottom of the div, the refresh brings them back to the top. I had some luck using anchors with Firefox, but not all versions of IE jumped to the anchors within the div. Is there any way to replace the contents of a div like this without having the scrollbar jump to the top? Any other suggestions? I like to refresh the entire set of results rather than just the updated row if possible, but if there are no workarounds I guess I will pursue that instead.

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  • how can we change the value by using radio buttons

    - by magna
    I am making a website in Adobe Dreamweaver with php. In the site there’s a 3 buttons for selecting payment method that will act as the continue button. What I want is when the user checks a radio buttons (I agree button), it will be add with that amount and display with previous amount.. there is three buttons which has the corresponding values(amount in pounds).. plz check my website http://www.spsmobile.co.uk in this linkgo to mobile phone unlocking and after add the cart click make payment it will go to next page there is a delivery mail details.. for that delivery mail details only am asking.. here i mentioned code: <input id="radio-1" type="radio" name="rmr" value="1"> <label for="radio-1">£3</label> <input id="radio-2" type="radio" name="rmr" value="2"> <label for="radio-2">£5.5</label> <input id="radio-3" type="radio" name="rmr" value="4"> <label for="radio-3">£10</label> <div class="total-text" style="font-size:36px">£10</div> var total = parseInt($("div.total-text").text().substring(1), 10); $("input[name='rmr']").bind('change', function() { var amount = 0; switch (this.value) { case "1": amount = 3; break; case "2": amount = 5.5; break; case "4": amount = 10; break; } $("div.total-text").text("£" + (total + amount)); }); but there is no change , my previous amount did not add with that. while am clicking previous amount only displayed on browser.. i need when i cliks radio button the value should change correspondingly.. where i did that mistake...plz give me some idea and what should i do..is there any need for storing db.. thanks in adv

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  • uncheck all checkboxes except the one with a class?

    - by Dejan.S
    hi i try to check/uncheck all checkboxes that don't got a class to them. This is the code I got but it check the class boxes to. $(document).ready(function() { $('#ctl00_ContentPlaceHolder1_repReceivers_ctl00_chxAll').click( function() { if (!$("input[type='checkbox']").hasClass("testclass")) { $("input[type='checkbox']").attr('checked', $('#ctl00_ContentPlaceHolder1_repReceivers_ctl00_chxAll').is(':checked')); }}); }); any ideas where I go wrong?

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  • Random Movement in a Fixed Container

    - by James Barracca
    I'm looking to create something that can move randomly inside of a fixed div container. I love the way the object moves in this example that I found searching this website... http://jsfiddle.net/Xw29r/15/ The code on the jsfiddle contains the following: $(document).ready(function(){ animateDiv(); }); function makeNewPosition(){ // Get viewport dimensions (remove the dimension of the div) var h = $(window).height() - 50; var w = $(window).width() - 50; var nh = Math.floor(Math.random() * h); var nw = Math.floor(Math.random() * w); return [nh,nw]; } function animateDiv(){ var newq = makeNewPosition(); var oldq = $('.a').offset(); var speed = calcSpeed([oldq.top, oldq.left], newq); $('.a').animate({ top: newq[0], left: newq[1] }, speed, function(){ animateDiv(); }); }; function calcSpeed(prev, next) { var x = Math.abs(prev[1] - next[1]); var y = Math.abs(prev[0] - next[0]); var greatest = x > y ? x : y; var speedModifier = 0.1; var speed = Math.ceil(greatest/speedModifier); return speed; }? CSS: div.a { width: 50px; height:50px; background-color:red; position:fixed; }? However, I don't believe the code above constricts that object at all. I need my object to move randomly inside of a container that is let's say for now... 1200px in width and 500px in height. Can someone steer me in the right direction? I'm super new to coding so I'm having a hard time finding an answer on my own. Thanks so much! James

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  • JSON is not being recognised

    - by richzilla
    Hi All, Im having a bit of trouble getting my JSON to be recognised by my web page. I have validated JSON that im getting returned from server, so i know that is correct, however my javascript function is not doing anything with it. My succes function is as follows: success: function(data) { $('input[name=customer_name]').val(data.name); $('textarea[name=customer_address]').text(data.address); $('input[name=customer_email]').val(data.email); $('input[name=customer_tel]').val(data.tel); $('input[name=user_id]').val(item.id); } Yet the fields are not being repopulated with the data that is returned, if it helps, a sample of my JSON data: { "name": "Terry O'Toole", "address": "Terrys House\nTerry Street\nTerrysville\nTerrytown\nTT1 6TT", "email": "[email protected]", "tel": "05110000000" } Any help would be appreciated. [EDIT] Expanded ajax call: $.ajax({ url: "<?php echo site_url('user/users/ajax'); ?>", type: 'POST', data: {"userid": item.id}, success: function(data) { $('input[name=customer_name]').val(data.name); $('textarea[name=customer_address]').text(data.address); $('input[name=customer_email]').val(data.email); $('input[name=customer_tel]').val(data.tel); $('input[name=user_id]').val(item.id); } }) });

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  • alter prettyphoto to pull from div or span, not title

    - by Jason
    Here's the section of code from prettyphoto.js that I need to alter. What I am trying to achieve is have each photo have a following hidden div or span that holds the description for the photo. This way I can include html in the description. Possible? Thanks! var images = new Array(), titles = new Array(), descriptions = new Array(); if(theGallery){ $('a[rel*='+theGallery+']').each(function(i){ if($(this)[0] === $(_self)[0]) setPosition = i; // Get the position in the set images.push($(this).attr('href')); titles.push($(this).find('img').attr('alt')); descriptions.push($(this).attr('title')); }); }else{ images = $(this).attr('href'); titles = ($(this).find('img').attr('alt')) ? $(this).find('img').attr('alt') : ''; descriptions = ($(this).attr('title')) ? $(this).attr('title') : ''; } $.prettyPhoto.open(images,titles,descriptions); return false; });

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  • how to get a value which points to a function

    - by darkandcold
    hi, i have a value like that var myvalue=myfunction(1,2); what I need is that GETTING myfunction(a,b) as a string.. I mean not "myfunction's value" hmmm, let me explain, myfunction(1,2) returns 1+2=3 if I type alert(myvalue) it returns 3 but I need myfunction(a,b) AS IT'S TYPED when I use alert. NOT IT'S VALUE think it like var myvalue='myfunction(a,b)' now, if i use Alert, it gives me myfunction(a,b) how can I do that?

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  • onchange on dropdownlist

    - by Abu Hamzah
    my qeustion is continuation of what i have asked see the link. http://stackoverflow.com/questions/2640001/load-country-state-city i have expand to load my drop downs list from db and i just need a way to wire onchange method in my first dropdownlist and second, please see the code. appreciate any help. $(document).ready(function() { var options = { type: "POST", url: "SearchPage.aspx/LoadCountry", data: "{}", contentType: "application/json; charset=utf-8", dataType: "json", success: function(msg) { var returnedArray = msg.d; list = $("#country"); for (var i = 0; i { list.append("" + returnedArray[i].Name + ""); } error : function(msg) { debugger } } }; $.ajax(options); }); how would i do for STATE dropdownlist ?

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  • ie not firing ajax complete call on certain page

    - by lordlinier
    even with a piece of code like this $.get('getforums.php', function(data) { alert(data); }); works well in chrome, firefox, safari, opera but not this baby. tried everything, cleared cache, recreate this file in different editor, even make this file just echoed a 's', but no, it just don't like this file, works perfect on other file thanks for the help!

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  • Events not registering after replaceWith

    - by strager
    When I replaceWith an element to bring one out of the DOM, then replaceWith it back in, events registered to it do not fire. I need to events to remain intact. Here's my Javascript: var replacement = $(document.createElement('span')); var original = $(this).replaceWith(replacement); replacement .css('background-color', 'green') .text('replacement for ' + $(this).text()) .click(function() { replacement.replaceWith(original); }); Live demo In the demo, when you click an element, it is replaced with another element using replaceWith. When you click the new element, that is replaced with the original element using replaceWith. However, the click handler does not work any more (where I would think it should).

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  • javascript array/object issue

    - by FlyingCat
    I am trying to push elements to an array. for (a=0; a < test.length; a++){ if(this.testnumber != test[a].number){ //it will only loop 8 times under conditional statement group = { title: test.Title , ID: test.ID, contents: [] }; this.company.push(group); this.testnumber = test.number[a]; } //outside of if conditional statement.. it will loop 15 times //i want every test[a].conetents get pushed to group.contents array. //this.company is the final variable I need for this function... group.contents.push(test[a].contents); } However, when I do console.log(this.company); I see 8 elmements with only 1 element in each group.contents array The ideal situation is to have 8 elements with 2 to 3 elements in the group.contents array I hope I explain my situation well. Any idea how to solve my issue? Thanks a lot!

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  • Why does this php/ajax query fail?

    - by Ashley Brown
    I'm ajaxing over to this php file. $a = 'old'; $b = 'new'; if ($_POST['info-type'] == $a || $b) { $info = $_POST['info-type']; $query = "SELECT * FROM `tld` WHERE type = '".$var."'"; } $query = "SELECT * FROM `tld` "; $result = mysqli_query($link,$query); while($row = mysqli_fetch_assoc($result)) { echo '<div>'.$row['something'].'</div>'; } The data posted is either 'all' 'new' or 'old'. If i send the data as either new or old, the script works and outputs as expected. If the posted data is neither new or old but all instead, it fails and don't show any errors or respond anything back. (I've monitored via dev tools aswell) So, I tried this if ($_POST['info-type'] == $a || $b) { $info = $_POST['info-type']; $var = "SELECT * FROM `tld` WHERE type = '".$var."'"; } elseif ($_POST['info-type'] == 'all'){ $query = "SELECT * FROM `tld` "; } But the script still fails. If i fully remove the IF statements and use the query without the WHERE clause like it is after the elseif, it works?

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  • addthis sharing buttons adblocker workaround

    - by Manuel
    I just integrated the addthis sharing buttons into my website. I'd like to use the addthis buttons in reason of their tracking and reporting functionality. However they are blocked by adblock plus and other adblockers. Considering that nowaday 30% of internet users use an adblocker I thought of making a work around for those. I integrated manual sharing buttons into my website. So far so good. Do you have any idea on how to hide my manual sharing buttons if the addthis buttons are shown. Or better said, don't hide them if the addthis buttons are removed by a addblocker? Is it possible to detect an adblocker through js? thx, I really appreciate your help!

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  • Display latest date from a HTML attribute

    - by Tron
    I currently have several classes which contain a date inside an attribute. <div id="container"> <div class="date" date="19/11/2013"></div> <div class="date" date="06/11/2013"></div> </div> <div id="result"></div> What I would like to do, is find the latest date and display it on the page. So far, I've found the information in the attribute, checked that it doesn't exist in the array then and pushed it into an array. I'm not entirely sure of the best approach from here, but ideally i would like to find the latest date and then append it to the results container. $('.date').each(function () { var dateArray = []; var date = $(this).attr('date'); if ($.inArray(date, dateArray) == -1) { dateArray.push(date); } $('#result').append(dateArray); }); Any assistance on the above would be greatly appreciated. Thanks :)

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  • How not to lose focus on a login page

    - by Misha Moroshko
    I have a simple login form with 2 input fields: "username" and "password". "username" field is focused by default. The problem is that when user clicks outside "username" or "password" fields, the focus is gone (it is neither on "username" nor on "password" fields"). How can I force the focus to be on these 2 fields only ? In my case, this is a really annoying behavior, so I really want to do this :) Can I do something like: $("*").focus(function() { if (!$(this).hasClass("my_inputs_class")) { // How to stop the focusing process here ? } }); ?

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  • How to decide if a parameter is the click event

    - by sameold
    I have a function which can be called by either a click event or directly. When I call it directly, I need pass it a data parameter, so I've defined the function to accept a parameter to account for the direct call with the parameter. function myFunc(param){ } Within the function, I need to differentiate whether the function was called directly or from the click event, so what I thought I could simply check if param is set. If it's set, then the function is called directly. If it's not set, then it's called from the click event. The problem is that a click event by default passes an event object. So even when the function is called by the click event, param won't be null. So is there a way to check whether the param passed is the click event?

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  • How to make technical training session useful and successful for trainee?

    - by metal-gear-solid
    Are these suggestions good to give for a successful training session? Practice time should be always given immediate after technical training? usually after receiving any technical session about any new thing we do routine work. If we don't do practice just after training, later when we do any work related to that training then we feel we need training again. So if we are getting training today and will not use it for some period of time (15 -30 -60 days) then the training is of no use, as it is at the wrong time. I.e. We will forget many things Any other suggestions which i should give? I'm trainee not trainer. What suggestion should i give to trainer/organizer?

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  • Got a static var which is working, now need to get dynamic var which isnt working

    - by Ritz
    got this variable var zvmlist = { 'Huishoudelijke hulp': 'Huishoudelijke hulp', 'Verpleging thuis': 'Verpleging thuis', 'Verzorging thuis': 'Verzorging thuis', '24 uurs zorg': '24 uurs zorg', 'Ondersteunende begeleiding': 'Ondersteunende begeleiding', }; this var is used in a function to create a dropdownlist. $.each(zvmlist, function(key, value) { var selected=''; if(key==eventdata.title){var selected='selected' } $('<option value="'+key+'" '+selected+'>'+value+'</option>').appendTo($('#calendar_edit_entry_form_title')); }); which works lika a charm. Now i created a function to fetch the list from a mysql table. $.get('get_zorgvormen.php', function(data) { var zvmlist = '{'+data+'}'; //alert(zvmlist); }); when i enable the alert function it shows me the var(array). But i it wont act as a variable. How can i pass this data to my .each function? see it in action here: http://www.zorgzuster-zeeland.nl/site/static/calendar_test.php

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  • adding code to jsfiddle

    - by loriensleafs
    I want to add a very simple bit of code to a jsfiddle, but when ever I do it breaks everything else. This is the code I'd like to add: $("#launcher").click(function(){ $("#profile_850_HEADER").animate({ margin-top: "10px" }, 1500 ); }); and this is the jsfiddle http://jsfiddle.net/loriensleafs/F3wjg/3/ , I'm sure this is beyond simple but I can't figure it out, any help would be greatly appreciated.

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