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  • How to do left joins with least-n-per-group query?

    - by Nate
    I'm trying to get a somewhat complicated query working and am not having any luck whatsoever. Suppose I have the following tables: cart_items: +--------------------------------------------+ | item_id | cart_id | movie_name | quantity | +--------------------------------------------+ | 0 | 0 | braveheart | 4 | | 1 | 0 | braveheart | 9 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +--------------------------------------------+ movies: +------------------------------+ | movie_id | movie_name | ... | +------------------------------+ | 0 | braveheart | . | | . | . | . | | . | . | . | | . | . | . | | . | . | . | +------------------------------+ pricing: +-----------------------------------------+ | id | movie_name | quantity | price_per | +-----------------------------------------+ | 0 | braveheart | 1 | 1.99 | | 1 | braveheart | 2 | 1.50 | | 2 | braveheart | 4 | 1.25 | | 3 | braveheart | 8 | 1.00 | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | | . | . | . | . | +-----------------------------------------+ I need to join the data from the tables, but with the added complexity that I need to get appropriate price_per from the pricing table. Only one price should be returned for each cart_item, and that should be the lowest price from the pricing table where the quantity for the cart item is at least the quantity in the pricing table. So, the query should return for each item in cart_items the following: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ Example 1: Variable passed to the query: cart_id = 0. Return: +---------------------------------------------+ | item_id | movie_name | quantity | price_per | +---------------------------------------------+ | 0 | braveheart | 4 | 1.25 | | 1 | braveheart | 9 | 1.00 | +---------------------------------------------+ Note that this is a minimalist example and that additional data will be pulled from the tables mentioned (particularly the movies table). How could this query be composed? I have tried using left joins and subqueries, but the difficult part is getting the price and nothing I have tried has worked. Thanks for your help. EDIT: I think this is similar to what I have working with my "real" tables: SELECT t1.item_id, t2.movie_name, t1.quantity FROM cart_items t1 LEFT JOIN movies t2 ON t2.movie_name = t1.movie_name WHERE t1.cart_id = 0 Assuming I wrote that correctly (I quickly tried to "port over" my real query), then the output would currently be: +---------------------------------+ | item_id | movie_name | quantity | +---------------------------------+ | 0 | braveheart | 4 | | 1 | braveheart | 9 | +---------------------------------+ The trouble I'm having is joining the price at a certain quantity for a movie. I simply cannot figure out how to do it.

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  • Possible to sort via two time stamps and display same row twice.

    - by jamiethompson90
    I'm looking at creating a time table solution. I have a task sheet that looks like Area 1 item 1 startTime endTime Area 1 item1 startTime endTime I wish to create a display where I can view what even is happening next, either endTime or startTime i.e. Newcastle reel 16:45 18:45 Newcastle reel2 17:45 19:45 would output Newcastle reel 16:45 Newcastle reel 17:45 Newcastle reel 18:45 Newcastle reel 19:45 More so, I would like to detect if the time is a startTime or an endTime would I have to enter two rows for each activity (time,area,item, start|end). I can make the interface to the creation of two rows. I just wondered if there was a better solution. Any input is appreciated, Thanks, Jamie

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  • Zend Framework multiple databases

    - by Uffo
    I'm currently using only one database with Zend Framework, but now I have to add ONE MORE. I'm using this code right now: public static function setupDatabase() { $config = self::$registry->configuration; $db = Zend_Db::factory($config->db->adapter, $config->db->toArray()); $db->query("SET NAMES 'utf8'"); self::$registry->database = $db; Zend_Db_Table::setDefaultAdapter($db); } What code do I need to write in order to use ONE MORE database; and how I will reference it, when I need to make some queries or so.. Best Regards!

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  • having trouble with a mysql query

    - by chuck akers
    this keeps saying Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in directory here the error is near the login_query variable, can someone help me fix it. <?php if (isset($_POST['login_username'], $_POST['login_password'])) { $login_username = trim(mysql_real_escape_string(htmlentities($_POST['login_username']))); $login_password = md5(trim(mysql_real_escape_string(htmlentities($_POST['login_password'])))); if (!empty($login_username) && !empty($login_password)) { $login_query = mysql_query("SELECT user_id FROM username WHERE username='".$login_username."' AND password='".$login_password."'"); if (mysql_num_rows($login_query)==1) { $user_id = mysql_result($login_query, 0, 'user_id'); $_SESSION['user_id'] = $user_id; header('Location: index.php'); die(); } }} ?

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  • SQL - How to display the students with the same age?

    - by Cristian
    the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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  • COUNT issue across multiple tables

    - by Kim
    I am trying to count across 2 tables and I dont see whats wrong with my query yet I get a wrong result. User 2 does not exist in table_two, so the zero is correct. SELECT t1.creator_user_id, COUNT(t1.creator_user_id), COUNT(t2.user_id) FROM table_one AS t1 LEFT JOIN table_two AS t2 ON t2.user_id = t1.creator_user_id GROUP BY t1.creator_user_id, t2.user_id Actual result 1 192 192 2 9 0 Expected result 1 16 12 2 9 0 The result indicate a missing group by condition, but I already got both fields used. Where am I wrong ? Also, can I sum up all users that doesnt exist in table_two for t1 ? Like user 3 exists 21 times in t1, then the results would be: 1 16 12 (users with > 0 in t2 will need their own row) 2 30 0 (user 2=9 + user 3=21 => 30) Its okay for the user Id to be wrong for sum of t1 for all users with 0 in t2. If not possible, then I'll just do two queries.

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  • mysqli_query SELECT FROM WHERE [ partial match ] ?

    - by user296516
    Hi guys, I have a database that a time filed that is stored in this format "2010.06.04. | 18:53 01". What I need is to select rows that have a specific date, for example "2010.06.04." Right now I am doing it my first selecting all rows and then looping through them and adding ones with the specified date to a new array. Maybe there is an easier way to do it and I somehow can select it using mysqli_query? Thanks!

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  • Perl daemon script for message queue hanging for 20 seconds after each process. Why?

    - by Mike Diena
    I have daemon script written in Perl that checks a database tables for rows, pulls them in one by one, sends the contents via HTTP post to another service, then logs the result and repeats (only a single child). When there are rows present, the first one is posted and logged immediately, but every subsequent one is delayed for around 20 seconds. There are no sleep()'s running, and I can't find any other obvious delays. Any ideas?

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  • How can I figure out a users postal code if I have their latitude / longitude location? Need help w

    - by mike
    I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

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  • getting sql records

    - by droidus
    when i run this code, it returns the topic fine... $query = mysql_query("SELECT topic FROM question WHERE id = '$id'"); if(mysql_num_rows($query) > 0) { $row = mysql_fetch_array($query) or die(mysql_error()); $topic = $row['topic']; } but when I change it to this, it doesn't run at all. why is this happening? $query = mysql_query("SELECT topic, lock FROM question WHERE id = '$id'"); if(mysql_num_rows($query) > 0) { $row = mysql_fetch_array($query) or die(mysql_error()); $topic = $row['topic']; $lockedThread = $row['lock']; echo "here: " . $lockedThread; }

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  • VS 2008 linking error

    - by AvatarBlue
    I'm using Visual Studio 2008 C++ and working on a dll project. Debug compiled and linked perfectly but when I compile the release version, it shows this: VImgPtr.obj : error LNK2001: unresolved external symbol @__security_check_cookie@4 VLibraryPtr.obj : error LNK2001: unresolved external symbol "void __cdecl operator delete[](void *)" (??_V@YAXPAX@Z) D:\Source Code\VImgLib\Release-vc9u\VImgLib-vc9u.dll : fatal error LNK1120: 2 unresolved externals If I selected Multi-threaded (/MT) in "C/C++-Code Generation tab), it linked ok. The problem is only when I choose Multi-threaded DLL (/MD). I'm releasing a dll, so should be /MD right?

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  • Getting a table's values into a tree

    - by Jason
    So, I have a table like such: id|root|kw1|kw2|kw3|kw4|kw5|name 1| A| B| C| D| E| F|fileA 2| A| B| | | | |fileB 3| B| C| D| E| | |fileC 4| A| B| | | | |fileD (several hundred rows...) And I need to get it into a tree like the following: *A *B -fileB -fileD *C *D *E *F -fileA *B *C *D *E -fileC I'm pretty sure the table is laid out poorly but it's what I have to live with. I've read a little about Adjacency List Model & Modified Preorder Tree Traversal but I don't think my data is laid out correctly. I think this requires a recursive function, but I'm not at all sure how to go about that. I'm open to any ideas of how to get this done even if it means extracting the data into a new table just to process this. Are there any good options available to me or any good ways to do this? (Examples are a bonus of course)

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  • Optimize innodb table

    - by ming yeow
    When i run optimize table on a innodb table, i get this message instead. does it mean that the table has already been optimized, but in a different manner? "table | optimize | note | Table does not support optimize, doing recreate + analyze instead |"

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  • diffing two databases

    - by flybywire
    Is there a tool to find the difference between two databases. Both the schema and the actual data are pretty much the same, but not 100%. Do you know a tool that can help to succinctly describe the changes.

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  • Deleting rows from different tables

    - by Ross
    Here is what i'm trying to do: Delete the project from projects table and all the images associated with that project in the images table Lets say $del_id = 10 DELETE FROM projects, images WHERE projects.p_id = '$del_id' AND images.p_id = '$del_id' What is wrong with this query

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  • self join to select consecutive numbers

    - by shantanuo
    CREATE TABLE `mybug` ( `SEAT_NO` decimal(2,0) NOT NULL, `ROW_NO` decimal(2,0) NOT NULL, `COL_NO` decimal(2,0) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `mybug` VALUES ('1','1','1'),('26','7','2'),('31','8','2'),('32','8','1'),('33','9','1'),('34','9','2'),('35','9','5'),('36','9','6'),('37','10','6'),('38','10','5'),('39','10','2'),('40','10','1'),('41','11','1'),('42','11','2'),('43','11','4'),('44','11','5'); +---------+--------+--------+ | SEAT_NO | ROW_NO | COL_NO | +---------+--------+--------+ | 1 | 1 | 1 | | 26 | 7 | 2 | | 31 | 8 | 2 | | 32 | 8 | 1 | | 33 | 9 | 1 | | 34 | 9 | 2 | | 35 | 9 | 5 | | 36 | 9 | 6 | | 37 | 10 | 6 | | 38 | 10 | 5 | | 39 | 10 | 2 | | 40 | 10 | 1 | | 41 | 11 | 1 | | 42 | 11 | 2 | | 43 | 11 | 4 | | 44 | 11 | 5 | +---------+--------+--------+ 16 rows in set (0.00 sec) In the above chart, I need to select 2 seats those are in the same row AND column numbers are next to each other. For e.g. Seat Numbers 38 & 39 can not be issued even if both the seats are from the same row because the column numbers 2 & 5 are not adjacent. The expected results are as follows: 31 33 35 37 39 41 43 These are the starting numbers and the next seat will be automatically booked as well. for e.g. 31 & 32

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  • How do I create a user history?

    - by ggfan
    I want to create a user history function that allows shows users what they done. ex: commented on an ad, posted an ad, voted on an ad, etc. How exactly do I do this? I was thinking about... in my site, when they log in it stores their user_id ($_SESSION['user_id']) so I guess whenever an user posts an ad(postad.php), comments(comment.php), I would just store in a database table "userhistory" what they did based on whenever or not their user_id was activate. When they comment, I store the user_id in the comment dbc table, so I'll also store it in the "userhistory" table. And then I would just queries all the rows in the dbc for the user to show it Any steps/improvements I can make? :)

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  • The remote server returned an error: (407) Proxy Authentication Required

    - by chris
    I'm getting this error when I call a web service: "The remote server returned an error: (407) Proxy Authentication Required". I get the general idea and I can get the code to work by adding myProxy.Credentials= NetworkCredential("user", "password", "domain"); or by using DefaultCredentials in code. My problem is that the call to the web service works in production without this. It seems like there is a non code solution involving Machine.config, but what is it? At the moment I can't get to the production boxes machine.config file to see what that looks like. I tried updating my machine.config as follows, but I still get the 407 error.

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  • Sql Query to get total rows and total rows matching specific condition

    - by mrNepal
    OK, Here is what my table looks like ------------------------------------------------ id type ----------------------------------------------- 1 a 2 b 3 a 4 c 5 c 7 a 8 a ------------------------------------------------ Now, I need a query that can give me this output... ----------------------------------------------------------------- count(*) | count(type=a) | count(type=b) | count(type=c) ----------------------------------------------------------------- 8 4 1 3 ------------------------------------------------------------------ I only know to get the total set using count(*), but how to do the remaining

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  • get data from to tables !

    - by mehdi
    i want to sort my users based on most viewed profile in my user list . i have these two tables but i don't know how to right correct query to make this happen . i used grouping like this : $sql ="select userid , count(*) form profile_visit group by userid " ; but it's not make sense to me , i don't think this query will help me at all . +-----------+---------------+------+-----+-------------------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+---------------+------+-----+-------------------+----------------+ | userid | int(11) | NO | PRI | NULL | auto_increment | | username | varchar(128) | NO | | NULL | | | password | char(40) | NO | | NULL | | | email | varchar(128) | NO | | NULL | | | name | varchar(256) | NO | | NULL | | | lastname | varchar(256) | NO | | NULL | | | job | varchar(256) | NO | | NULL | | | birthdate | varchar(100) | NO | | NULL | | | address | varchar(1024) | NO | | NULL | | | website | varchar(100) | NO | | NULL | | | tel | varchar(100) | NO | | NULL | | | role | tinyint(1) | NO | | 0 | | | reg_date | timestamp | NO | | CURRENT_TIMESTAMP | | +-----------+---------------+------+-----+-------------------+----------------+ and profile_visit table like this +------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------+-------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | ip_address | varchar(70) | NO | | NULL | | | userid | int(11) | NO | | NULL | | +------------+-------------+------+-----+---------+----------------+

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