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  • How to implement jsf validator?

    - by Krishna
    HI, I want to know how to implement Validator in JSF. What is the advantages of declaring the validator-id. When it will be called in the life cycle?. I have implemented the following code. Please find out what is wrong in the code. I am not seeing it called anywhere in the life cycle. <?xml version="1.0"?> <!DOCTYPE faces-config PUBLIC "-//Sun Microsystems, Inc.//DTD JavaServer Faces Config 1.1//EN" "http://java.sun.com/dtd/web-facesconfig_1_1.dtd"> <faces-config> <lifecycle> <phase-listener>javabeat.net.jsf.JsfPhaseListener</phase-listener> </lifecycle> <validator> <validator-id>JsfValidator</validator-id> <validator-class>javabeat.net.jsf.JsfValidator</validator-class> </validator> <managed-bean> <managed-bean-name>jsfBean</managed-bean-name> <managed-bean-class>javabeat.net.beans.ManagedBean</managed-bean-class> <managed-bean-scope>request</managed-bean-scope> </managed-bean> <navigation-rule> <navigation-case> <from-outcome>success</from-outcome> <to-view-id>success.jsp</to-view-id> </navigation-case> </navigation-rule> </faces-config> public class JsfValidator implements Validator { public JsfValidator() { System.out.println("Inside JsfValidator Constructor"); } @Override public void validate(FacesContext facesContext, UIComponent uiComponent, Object object) throws ValidatorException { System.out.println("Inside Validator"); } }

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  • Parse error: syntax error, unexpected ';'

    - by sufoid
    Hallo I have this script: <? require("lib2/config.inc.php"); require("lib2/tpl.class.php"); require("lib2/db.class.php"); require("lib2/um.class.php"); $tpl = new template("templates", "tpl"); $db = new db($db['location'], $db['username'], $db['passwort'], $db['database']); $um = new usermanagment(); /** User login **/ $checklogin = $um->check_login(); $userdata = $um->getuserdata(); if(!$checklogin && !$guest) { header("LOCATION: ./index2.php"); } eval("\$header .= \" ".$tpl->get("header")."\";"); eval("\$footer .= \" ".$tpl->get("footer")."\";"); $time = time(); $db->Query("UPDATE userdaten SET lastaction = '$time' WHERE userid = '".$userdata['userid']."'"); ?> And get this error: Parse error: syntax error, unexpected ';' in /home/httpd/html/login/global.php(22) : eval()'d code on line 96 Any ideas?

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  • custom rss feed suddenly does not work anymore

    - by krike
    I just don't understand what's happening, I haven't change anything to the site for a few months but now suddenly the rss feed doesn't work anymore. I create a php file with the following code: header('Content-type: text/xml'); include("config/config.inc.php"); $result = mysqli_query($link, "SELECT * FROM tutorials ORDER BY tutorial_id DESC LIMIT 50"); ?> <rss version="2.0"> <channel> <title>CMS tutorial site</title> <description>Bringing you the best CMS tutorials from the web</description> <link>http://cmstutorials.org</link> <?php while($row = mysqli_fetch_object($result)) { $user = mysqli_fetch_object(mysqli_query($link, "SELECT * FROM user_extra WHERE userid=".$row->user_id."")); ?> <item> <title><?php echo $row->title; ?></title> <author><?php echo $user->username; ?></author> <description><?php echo $row->description; ?></description> <pubDate><?php echo $row->date; ?></pubDate> <link>http://cmstutorials.org/view_tutorial.php?tutorial_id=<?php echo $row->tutorial_id; ?></link> </item> <?php } ?> </channel> </rss> I checked the query by executing it in phpmyadmin and it works, doesn't give any error. When I delete the header content type and the rss tag it will print out each line from the query but the feed won't display anything this is the link of the feed http://cmstutorials.org/rss (or http://cmstutorials.org/rss.php)

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  • PHP: Join two separate mysql queries into the same json data object

    - by Dan
    I'm trying to mesh the below mysql query results into a single json object, but not quite sure how to do it properly. //return data $sql_result = mysql_query($sql,$connection) or die ("Fail."); $arr = array(); while($obj = mysql_fetch_object($sql_result)) { $arr[] = $obj; } echo json_encode($arr); //return json //plus the selected options $sql_result2 = mysql_query($sql2,$connection) or die ("Fail."); $arr2 = array(); while($obj2 = mysql_fetch_object($sql_result2)) { $arr2[] = $obj2; } echo json_encode($arr2); //return json Here's the current result: [{"po_number":"test","start_date":"1261116000","end_date":"1262239200","description":"test","taa_required":"0","account_overdue":"1","jobs_id":null,"job_number":null,"companies_id":"4","companies_name":"Primacore Inc."}][{"types_id":"37"},{"types_id":"4"}] Notice how the last section [{"types_id":"37"},{"types_id":"4"}] is placed into a separate chunk under root. I'm wanting it to be nested inside the first branch under a name like, "types". I think my question has more to do with Php array manipulation, but I'm not the best with that. Thank you for any guidance.

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  • php Warning: strtotime() Error

    - by Kavithanbabu
    I have changed my joomla and wordpress files from old server to new server. In the front end and admin side its working without any errors. But in the Database (phpmyadmin) Section it shows some warning messages like this.. Warning: strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'Asia/Calcutta' for 'IST/5.0/no DST' instead in /usr/share/phpmyadmin/libraries/db_info.inc.php on line 88 Warning: strftime() [function.strftime]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'Asia/Calcutta' for 'IST/5.0/no DST' instead in /usr/share/phpmyadmin/libraries/common.lib.php on line 1483 Can you please suggest, how to hide these warning messages?? Thanks in advance.

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  • ssh & script problem

    - by Nishanth
    I am having a strange problem while doing ssh. I am not sure where the term Unmatched ` is coming from. What I need to do is run script that logs information of what I am doing on the terminal to text file. After ssh - Sun Microsystems Inc. SunOS 5.8 Generic Patch October 2001 This is /etc/motd, last updated 3 Feb 2003. To learn about the UCS system and other aspects of computing at UL-Lafayette visit our home page http://helpdesk.louisiana.edu/ . For more information about system use, contact the Help Desk, Stephens Hall, Room 201, 482-5516 (x25516), during normal UL office hours; or send e-mail to [email protected]. ATTENTION: Unsecure Telnet and FTP will be turned off soon. Please make arrange to use ssh or sftp. Putty(telnet) and WinSCP(ftp) would be a good replacement. Unmatched ` d13.ucs.louisiana.edu% bash bash-2.04$ script -a myInformation.txt Script started, file is myInformation.txt Unmatched ` d13.ucs.louisiana.edu% When I tried to start the script with name myInformation.txt, you can see the message I am getting - Script started, file is myInformation.txt. But again I am getting that message Unmatched ` and is coming out of bash, as you can notice. What is the problem ? Any insights suggested would be very great. Note: file with name myInformation.txt is being created but nothing goes in to it. As I have even tried running certain commands like ls and then exited the script with ctrl+d. But when I open the file, nothing is there.

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  • Catchable fatal error: Object of class view_user could not be converted to string in C:\xampp\xampp\htdocs\textile\admin\view_class.php on line 9 [closed]

    - by user1282142
    <?php include('config.inc'); class view_user { function view($user) { $temp = mysql_query("SELECT * from register_user where user_name = '$user'"); $value = mysql_fetch_array($temp); $query = mysql_query("SELECT order_user.design_name, order_user.reaad, order_user.pick, order_user.yarn_detail FROM register_user INNER JOIN order_user ON register_user.register_id = '$value[register_id]' and order_user.register_id = $value[register_id]"); if($query) { echo "<center><table border = 1> <tr> <th>Design Name</th> <th>Read</th> <th>Pick</th> <th>Design Detail</th> </tr>"; while($row = mysql_fetch_array($query)) { echo "<tr>"; echo "<td>$row[design_name]</td>"; echo "<td>$row[reaad]</td>"; echo "<td>$row[pick]</td>"; echo "<td>$row[yarn_detail]</td>"; echo"</tr></center>"; } } else { echo"User doesn't Exist"; include('footer1.php'); } } } ?>

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  • PEAR:DB connection parameters

    - by Markus Ossi
    I just finished my first PHP site and now I have a security-related question. I used PEAR:DB for the database connection and made a separate parameter file for it. How should I hide this parameter file? I found a guide (http://www.kitebird.com/articles/peardb.html) that says: Another way to specify connection parameters is to put them in a separate file that you reference from your main script. ... It also enables you to move the parameter file outside of the web server's document tree, which prevents its contents from being displayed literally if the server becomes misconfigured and starts serving PHP scripts as plain text. I have now put my file in a directory like this /include/db_parameters.inc However, if I go to this URL, the web server shows me the contents of the file including my database username and password. From what I've understood, I should protect this file so, that even though PHP would be served as text, nobody could read this. What does outside of web server's document tree mean here? Put the PHP file out of public_html directory altogether deeper into the server file system? Some CHMOD?

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  • use Ghostscript to convert pcl to postscript

    - by Bryon
    So I want to use Ghostscript to convert files that are created in pcl format to postscript. That's the gist of my problem. I am simply trying to run it on the command line, but in the final stage it will have to be run on a lp command like lp -d < gs something something GPL Ghostscript 9.00 (2010-09-14) I will be running this on a solaris 10 server but I believe any unix system should work similar. bash-3.00# /usr/local/bin/gs -sDEVICE=pswrite -dLanguageLevel=1 -dNOPAUSE -dBATCH -dSAFER -sOutputFile=output.ps cms-form.pcl GPL Ghostscript 9.00 (2010-09-14) Copyright (C) 2010 Artifex Software, Inc. All rights reserved. This software comes with NO WARRANTY: see the file PUBLIC for details. Error: /undefined in &k2G-210z100u0l6d0e63fa0V Operand stack: Execution stack: %interp_exit .runexec2 --nostringval-- --nostringval-- --nostringval-- 2 %stopped_push --nostringval-- --nostringval-- --nostringval-- false 1 %stopped_push 1910 1 3 %oparray_pop 1909 1 3 %oparray_pop 1893 1 3 %oparray_pop 1787 1 3 %oparray_pop --nostringval-- %errorexec_pop .runexec2 --nostringval-- --nostringval-- --nostringval-- 2 %stopped_push --nostringval-- Dictionary stack: --dict:1154/1684(ro)(G)-- --dict:0/20(G)-- --dict:77/200(L)-- Current allocation mode is local Current file position is 30 GPL Ghostscript 9.00: Unrecoverable error, exit code 1

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  • How to configure and run a fastcgi application using Lighthttpd...

    - by Airy
    Hi, i've installed Lighthttpd for windows and i'd created a simple program in c++ which uses fastcgi libraries. i'll post the code here... #include "fcgi_stdio.h" #include <stdlib.h> int count; void initialize(void) { count=0; } void main(void) { initialize(); while (FCGI_Accept() >= 0) { printf("Content-type: text/html\r\n" "\r\n" "<title>FastCGI Hello! (C, fcgi_stdio library)</title>" "<h1>FastCGI Hello! (C, fcgi_stdio library)</h1>" "Request number %d running on host <i>%s</i>\n", ++count, getenv("SERVER_HOSTNAME")); } } I've spawned the fastcgi application in lighthttpd using the below configuration in lightttpd-inc.conf fastcgi.server = ( ".exe" => ( "" => ( "bin-path" => "D:\tinycgi.exe", "port" => 8080, "min-procs" => 1, "max-procs" => 1 ) ) ) while sending a request using the browser the server is responding with this message in the console 2009-02-18 16:08:34: (mod_fastcgi.c.2494) unexpected end-of-file (perhaps the fa stcgi process died): pid: 0 socket: tcp:localhost:8080 2009-02-18 16:08:34: (mod_fastcgi.c.3325) response not received, request sent: 1 024 on socket: tcp:localhost:8080 for /new/tinycgi.exe , closing connection I think the fastcgi application is not spawned correctly. Thank you, Varun

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  • #1146 - Table 'phpmyadmin.pma_recent' doesn't exist

    - by Mumin Ali
    Solution Guys... FYI i am using xampp to use phpmyadmin. and this error happens during the process of creating a database on localhost. Below is the code for config.inc file under phpmyadmin directory: <?php /* * This is needed for cookie based authentication to encrypt password in * cookie */ $cfg['blowfish_secret'] = 'xampp'; /* YOU SHOULD CHANGE THIS FOR A MORE SECURE COOKIE AUTH! */ /* * Servers configuration */ $i = 0; /* * First server */ $i++; /* Authentication type and info */ $cfg['Servers'][$i]['auth_type'] = 'HTTP'; $cfg['Servers'][$i]['user'] = 'root'; $cfg['Servers'][$i]['password'] = 'password'; $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = true; $cfg['Lang'] = ''; /* Bind to the localhost ipv4 address and tcp */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; /* User for advanced features */ $cfg['Servers'][$i]['controluser'] = 'pma'; $cfg['Servers'][$i]['controlpass'] = ''; /* Advanced phpMyAdmin features */ $cfg['Servers'][$i]['pmadb'] = 'phpmyadmin'; $cfg['Servers'][$i]['bookmarktable'] = 'pma_bookmark'; $cfg['Servers'][$i]['relation'] = 'pma_relation'; $cfg['Servers'][$i]['table_info'] = 'pma_table_info'; $cfg['Servers'][$i]['table_coords'] = 'pma_table_coords'; $cfg['Servers'][$i]['pdf_pages'] = 'pma_pdf_pages'; $cfg['Servers'][$i]['column_info'] = 'pma_column_info'; $cfg['Servers'][$i]['history'] = 'pma_history'; $cfg['Servers'][$i]['designer_coords'] = 'pma_designer_coords'; $cfg['Servers'][$i]['tracking'] = 'pma_tracking'; $cfg['Servers'][$i]['userconfig'] = 'pma_userconfig'; $cfg['Servers'][$i]['recent'] = 'pma_recent'; $cfg['Servers'][$i]['table_uiprefs'] = 'pma_table_uiprefs'; /* * End of servers configuration */ ?>

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  • WN server filter won't work

    - by Mike Fink
    WN servers have an alternative to cgi programs called filters. I have been trying to get one to work, but I have had no luck. I am writing in python. It looks like the server is not receiving any output from the program but is parsing nothing and wrapping this nothing in my standard header and footer. I have chmod 755 the program and my index.wn file reads: Default-Attributes=parse Default-Wrappers=templates/template1.inc File=includeTests.html File=index.html File=archives.html File=contact.html File=style.css File=testProgram.py #here is the stuff about the filter File=testFilter.html Content-type=text/html Filter=testProgram.py Attributes=parse, cgi here is what is in the filter called testProgram.py: #!/usr/bin/python print "Content-Type: text/html\n\n" print "hi" testProgram.py works perfectly if it is shoved into a cgi-bin folder and chmoded. I suppose my problem may lay with the fact that I have never ever seen a filter program in python. I'm not sure I have even seen a filter program at all. Does anyone out there have any experience with wn servers and filters? Any ideas?

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  • mongoose updating a field in a MongoDB not working

    - by Masiar
    I have this code var UserSchema = new Schema({ Username: {type: String, index: true}, Password: String, Email: String, Points: {type: Number, default: 0} }); [...] var User = db.model('User'); /* * Function to save the points in the user's account */ function savePoints(name, points){ if(name != "unregistered user"){ User.find({Username: name}, function(err, users){ var oldPoints = users[0].Points; var newPoints = oldPoints + points; User.update({name: name}, { $inc: {Points: newPoints}}, function(err){ if(err){ console.log("some error happened when update"); } else{ console.log("update successfull! with name = " + name); User.find({Username: name}, function(err, users) { console.log("updated : " + users[0].Points); }); } }); }); } } savePoints("Masiar", 666); I would like to update my user (by finding it with its name) by updating his/her points. I'm sure oldPoints and points contain a value, but still my user keep being at zero points. The console prints "update successful". What am I doing wrong? Sorry for the stupid / noob question. Masiar

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  • In ArrayBlockingQueue, why copy into ReentrantLock field into local final variable?

    - by mjlee
    In ArrayBlockingQueue, any method that requires lock will get set 'final' local variable before calling 'lock()'. public boolean offer(E e) { if (e == null) throw new NullPointerException(); final ReentrantLock lock = this.lock; lock.lock(); try { if (count == items.length) return false; else { insert(e); return true; } } finally { lock.unlock(); } } Is there any reason to set a local variable 'lock' from 'this.lock' when field 'this.lock' is final also. Additionally, it also set local variable of E[] before acting on. private E extract() { final E[] items = this.items; E x = items[takeIndex]; items[takeIndex] = null; takeIndex = inc(takeIndex); --count; notFull.signal(); return x; } Is there any reason for copying to local final variable?

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  • How would I combine these two codes, PHP and HTML?

    - by user1887109
    This is what I have currently: <html> <body oncontextmenu="return false;" bgcolor="5385ab"> <p align=center><a href="test.php"><img src="image.png"/></a></p> </body> </html> I need the <body> part and to combine this PHP geo-redirect code with "test.php" also including the "image.png" Here is the PHP code: <?php require_once("geoip.inc"); $gi = geoip_open("/var/lib/GeoIP/GeoIP.dat",GEOIP_STANDARD); $country_code = geoip_country_code_by_addr($gi, $_SERVER['REMOTE_ADDR']); geoip_close($gi); if($country_code == 'FR') { header('Location: http://www.test.php'); } else { header('Location: http://www.yahoo.com/'); } ?> I'm not familiar with PHP so I have no idea how to even go about testing these two together. Hope you can help! Thank you.

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  • how to add an ajax jQuery code, that return a row from php file [DB] and then change the value of input text?

    - by Nisreen KH
    //this is a code in php which is fetch a record from database <?php include("dbconn.inc"); $data=mysql_query("SELECT `subtitle`, `mian-title`, `page_num`, `note_path`, `flash_path` FROM `main-page` WHERE `page_num` =".$r." LIMIT 1"); echo $data; if (mysql_num_rows($data) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($data)) { echo $row['page_num']; } include("close.php"); ?> //and this is a code in html <form method="post" action="data.php"> <input name="Button1" type="submit" value="&lt;&lt;" /> <input name="test" style="width: 31px; height: 23px" type="text" /> // this is a value of page_num in DB. <input name="Button2" type="submit" value="&gt;&gt;" > </form> //i want to add an ajax code to retrieve the record from php code, and then change the input values depends on returned data ,and also to prevent refreshing the page always!!

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  • Jython & Mysql - what is the current practice for connection?

    - by Sector7B
    Just trying jython for the first time, because something came up at work that would fit for this perfect for it. I assume jython can make mysql jdbc connection using the mysql jdbc driver. After googling and reading, however I am having problems and it seems jython specific and probably simple. so i do jython: Jython 2.5.1 (Release_2_5_1:6813, Sep 26 2009, 13:47:54) [Java HotSpot(TM) 64-Bit Server VM (Apple Inc.)] on java1.6.0_17 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/JYTHONPATH/mysql-connector-java-5.1.10-bin.jar', '/WorkArea/Apps/jython/jython2.5.1/Lib', '__classpath__', '__pyclasspath__/', '/WorkArea/Apps/jython/jython2.5.1/Lib/site-packages'] >>> code i'm running from java.lang import * from java.sql import * driverName="com.mysql.jdbc.Driver" Class.forName(driverName) url = "jdbc:mysql://localhost/test?user=jgreenaw&password=" con = DriverManager.getConnection(url) stmt = con.createStatement() output riux:Desktop$ jython pymysql.py Traceback (most recent call last): File "pymysql.py", line 7, in <module> Class.forName(driverName) at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) java.lang.ClassNotFoundException: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver any advice? thanks

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  • how can you have the same form handle by javascript multiple times on the same page?

    - by DeChamp
    I have a thumb gallery where I am using ajax/javascript to submit a form per image to report the image as broken seamlessly along with php. The form and script is templated so the script is in the header and then the form is printed multiple times on the same page with a hidden field with a different id for the value per thumb. So basically this is what i have. javascript in header just a quick idea of the forms i have. Just a quick idea not what I actually have. image1 followed by the form image2 followed by the form So when you hit the button it basically submits all of the forms at the same time. I am sure it can be fixed with a (this) or something like that so it only submits a single form at a time. Let me know please. $(function() { $(".submit").click(function() { var imgId = $("#imgId").val(); var dataString = 'imgId='+ imgId; if(imgId==''){ $('.success').fadeOut(200).hide(); $('.error').fadeIn(200).show(); $('.error').fadeOut(200).hide(); }else{ $.ajax({ type: "POST", url: "inc/brokenImgReport.php", data: dataString, success: function(){ }); $('.error').fadeOut(200).hide(); $('.success').fadeIn(200).show(); setTimeout(function() { $('.success').fadeOut(200); }, 2000); } return false; }); });

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  • Drupal 7 configuration error with Postgresql in Mac OS 10.6.5

    - by Sam
    I am trying to configure Drupal 7 with Postgres. At the database setup step, I get the following error. Warning: PDO::_construct(): [2002] No such file or directory (trying to connect via unix:///var/mysql/mysql.sock) in DatabaseConnection-_construct() (line 300 of /Users/shamod/Sites/drupal/7/includes/database/database.inc). In order for Drupal to work, and to continue with the installation process, you must resolve all issues reported below. For more help with configuring your database server, see the installation handbook. If you are unsure what any of this means you should probably contact your hosting provider. Failed to connect to your database server. The server reports the following message: SQLSTATE[HY000] [2002] No such file or directory. Is the database server running? Does the database exist, and have you entered the correct database name? Have you entered the correct username and password? Have you entered the correct database hostname? NOTE: I am trying to connect to Postgresql but it fails on var/mysql/mysql.sock error. I have setup the database connection string in settings.php for Postgresql. It still does not work. Any idea?

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  • Has anyone ever had OpenCV work with Python 2.7 on MacOS 10.6?

    - by ?????
    I've been trying on and off for the past 6 months to get OpenCV to work with Python on MacOS. Every time there's a new release, I try again and fail. I've tried both 64-bit and 32-bit, and both the xcode gcc and gcc installed via macports. I just spend the past two days on it, hopeful that the latest OpenCV release, that appears to include Python support directly would work. It doesn't. I've also tried and failed to use this: http://code.google.com/p/pyopencv/ I've been using OpenCV with C++ or Microsoft C++/CLI for the past few years, but I'd love to use it with Python on a Mac because that is my primary development environment. I'd love to hear from anyone who's actually been able to get the opencv python examples to run under Mac OS 10.6, either 32 or 64-bit. My last attempt was to follow the instructions on this page http://recursive-design.com/blog/2010/12/14/face-detection-with-osx-and-python/ with a clean, fresh install of 10.6 on a 64-bit capable Mac. My PYTHONPATH is set, and I can see the cv library in it. But an "import cv" from python fails. Previously, the closest I've ever gotten (again, staring on a clean, fresh 10.6 install) was this: Python 2.7.1 (r271:86882M, Nov 30 2010, 10:35:34) [GCC 4.2.1 (Apple Inc. build 5664)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> import cv Fatal Python error: Interpreter not initialized (version mismatch?) Abort trap thrilllap-2:~ swirsky$ I've seen a lot of folks answering similar questions here, but have never seen an definitive answer for it.

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  • Write to the second line of a PHP file

    - by Woz
    I have a php file that I want to add an include path to on the second line. I need to open the file and inset a line of code on line 2. I have tried a few techniques none of which are working but I think it has something to do with the text I am trying to write and possibly not escaping character correctly as I am not too familiar with file writing. So here is the file I want to write to: $file = $_SERVER['DOCUMENT_ROOT'].'/'.$domaindir.'/test.php'; Here is the piece of text I want to insert into the file: $dbfile = "include('".$_SERVER['DOCUMENT_ROOT']."/".$domaindir."/web_".$dbname.".inc.php');"; Then what I was doing was a string replace but all it did was bump the "session_start();" bit to a newline! Can anyone point me in the direction of a tutorial that might tell me how to insert this into the second line of my php file or indeed if anyone has any ideas? I can say for sure that the path to the PHP file is fully tested so i know its not that the file is not being open or written to. Any ideas would be much appreciated. Thanks in advance.

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  • extract out text in each line and put it in seperate variables with javascript

    - by user357034
    I have the following address which is in a paragraph with no great way to select the individual text areas within. I do not have access to this code. I want to extract out each line and put the text values in a variable for each type. Not sure what would be the best way to do it. Use .split('<br>') ? then use .split('&nbsp;') to separate the state from the zip same with city and state I am a little lost here. Here are the variables I would like. company name, person's name, address1, city, state, country, zip code, phone, Here is the paragraph that i have. I do not need the '(Residential Address)' <p> XYZ Inc<br> John&nbsp;Smith<br> 555 Anywhere Street<br> New York, NY&nbsp;11150<br> United States<br> 212-555-1212<br> (Residential Address) </p>

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  • C++ ulong to class method pointer and back

    - by Simone Margaritelli
    Hi guys, I'm using a hash table (source code by Google Inc) to store some method pointers defined as: typedef Object *(Executor::*expression_delegate_t)( vframe_t *, Node * ); Where obviously "Executor" is the class. The function prototype to insert some value to the hash table is: hash_item_t *ht_insert( hash_table_t *ht, ulong key, ulong data ); So basically i'm doing the insert double casting the method pointer: ht_insert( table, ASSIGN, reinterpret_cast<ulong>( (void *)&Executor::onAssign ) ); Where table is defined as a 'hash_table_t *' inside the declaration of the Executor class, ASSIGN is an unsigned long value, and 'onAssign' is the method I have to map. Now, Executor::onAssign is stored as an unsigned long value, its address in memory I think, and I need to cast back the ulong to a method pointer. But this code: hash_item_t* item = ht_find( table, ASSIGN ); expression_delegate_t delegate = reinterpret_cast < expression_delegate_t > (item->data); Gives me the following compilation error : src/executor.cpp:45: error: invalid cast from type ‘ulong’ to type ‘Object* (Executor::*)(vframe_t*, Node*)’ I'm using GCC v4.4.3 on a x86 GNU/Linux machine. Any hints?

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  • Does operator precedence in C++ differ for pointers and iterators?

    - by oraz
    The code below demonstrates this difference: #include <iostream> #include <string> int main() { char s[] = "ABCD"; std::string str(s); char *p = s; while(*p) { *p++ = tolower(*p); // <-- incr after assignment } std::cout << s << std::endl; std::string::iterator it = str.begin(), end = str.end(); while(it != end) { *it++ = tolower(*it); // <-- incr before assignment ? } std::cout << str << std::endl; return 0; } the code above outputs: abcd bcd if we separate assignment operation and increment operator: while(it != end) { *it = tolower(*it); // <-- incr before assignment ? it++; } the output will be as expected. What's wrong with the original code? $ g++ --version g++ (GCC) 3.4.4 (cygming special, gdc 0.12, using dmd 0.125) Copyright (C) 2004 Free Software Foundation, Inc.

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  • Nginx - Treats PHP as binary

    - by Think Floyd
    We are running Nginx+FastCgi as the backend for our Drupal site. Everything seems to work like fine, except for this one url. http:///sites/all/modules/tinymce/tinymce/jscripts/tiny_mce/plugins/smimage/index.php (We use TinyMCE module in Drupal, and the url above is invoked when user tries to upload an image) When we were using Apache, everything was working fine. However, nginx treats that above url Binary and tries to Download it. (We've verified that the file pointed out by the url is a valid PHP file) Any idea what could be wrong here? I think it's something to do with the NGINX configuration, but not entirely sure what that is. Any help is greatly appreciated. Config: Here's the snippet from the nginx configuration file: root /var/www/; index index.php; if (!-e $request_filename) { rewrite ^/(.*)$ /index.php?q=$1 last; } error_page 404 index.php; location ~* \.(engine|inc|info|install|module|profile|po|sh|.*sql|theme|tpl(\.php)?|xtmpl)$|^(code-style\.pl|Entries.*|Repository|Root|Tag|Template)$ { deny all; } location ~* ^.+\.(jpg|jpeg|gif|png|ico)$ { access_log off; expires 7d; } location ~* ^.+\.(css|js)$ { access_log off; expires 7d; } location ~ .php$ { include /etc/nginx/fcgi.conf; fastcgi_pass 127.0.0.1:8888; fastcgi_index index.php; fastcgi_param SCRIPT_FILENAME $document_root$fastcgi_script_name; fastcgi_param QUERY_STRING $query_string; fastcgi_param REQUEST_METHOD $request_method; fastcgi_param CONTENT_TYPE $content_type; fastcgi_param CONTENT_LENGTH $content_length; } location ~ /\.ht { deny all; }

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