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  • Retain a list of objects and pass it to the create/edit view when validation fails in ASP.NET MVC 2

    - by brainnovative
    I am binding a Foreign key property in my model. I am passing a list of possible values for that property in my model. The model looks something like this: public class UserModel { public bool Email { get; set; } public bool Name { get; set; } public RoleModel Role { get; set; } public IList<RoleModel> Roles { get; set; } } public class RoleModel { public string RoleName { get; set; } } This is what I have in the controller: public ActionResult Create() { IList<RoleModel> roles = RoleModel.FromArray(_userService.GetAllRoles()); UserModel model = new UserModel() { Roles = roles }; return View(model); } In the view I have: <div class="editor-label"> <%= Html.LabelFor(model => model.Role) %> </div> <div class="editor-field"> <%= Html.DropDownListFor(model => model.Role, new SelectList(Model.Roles, "RoleName", "RoleName", Model.Role))%> <%= Html.ValidationMessageFor(model => model.Role)%> </div> What do I need to do to get the list of roles back to my controller to pass it again to the view when validation fails. This is what I need: [HttpPost] public ActionResult Create(UserModel model) { if (ModelState.IsValid) { // insert logic here } //the validation fails so I pass the model again to the view for user to update data but model.Roles is null :( return View(model); } As written in the comments above I need to pass the model with the list of roles again to my view but model.Roles is null. Currently I ask the service again for the roles (model.Roles = RoleModel.FromArray(_userService.GetAllRoles());) but I don't want to add an extra overhead of getting the list from DB when I have already done that.. Anyone knows how to do it?

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  • Django: Set foreign key using integer?

    - by User
    Is there a way to set foreign key relationship using the integer id of a model? This would be for optimization purposes. For example, suppose I have an Employee model: class Employee(models.Model): first_name = models.CharField(max_length=100) last_name = models.CharField(max_length=100) type = models.ForeignKey('EmployeeType') and EmployeeType(models.Model): type = models.CharField(max_length=100) I want the flexibility of having unlimited employee types, but in the deployed application there will likely be only a single type so I'm wondering if there is a way to hardcode the id and set the relationship this way. This way I can avoid a db call to get the EmployeeType object first.

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  • How do I use on delete cascade in mysql?

    - by Marius
    I have a database of components. Each component is of a specific type. That means there is a many-to-one relationship between a component and a type. When I delete a type, I would like to delete all the components which has a foreign key of that type. But if I'm not mistaken, cascade delete will delete the type when the component is deleted. Is there any way to do what I described?

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  • Symfony 1.4: Deleting a sfGuardUser

    - by Tom
    Hi, I'm having some trouble with the following... I have a sfGuardUser table set up normally, and it has a one-to-one relationship with a Profile table, which contains some additional user info. When a user wants to delete themselves from the site, I'd like to retain their info in the Profile table for various purposes BUT delete the sfGuardUser in order to keep that table cleaner/shorter (not just set it to inactive). I was under the impression that I could set the FK in the Profile table to NULL and then delete the sfGuardUser, but it seems the FK-constraint fails. Indeed, it seems I can't delete either and the queries fail: If I try to delete the sfGuardUser, the Profile table will have an invalid FK If I try to delete a Profile, the sfGuardUser will have an invalid FK Other than leaving outdated sfGuardUsers and Profiles in these tables, or having to use a cascaded delete to get rid of both, can anyone tell me if there's any other way around this? Thank you.

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  • MySQL/PHP: How to insert logged in user id into another table that is gathering data from a form tha

    - by Lisa
    For the first time I am needing to join information from two tables and am quite nervous about doing it without any advice first. Basically, I am building a secure site that is accessed by authorised users. I have my login table with user_id, username, password Once the user is on the site, they have the option of inputting data into another table called input. At the moment this table only captures the information that is entered, not the user_id or username of the inputter. I would like the form to be able to input the user_id and/or username from the login table into the input table. Please could somebody talk me through this process? I am sure that once this is amended, I will then be able to use the table to only allow the logged in user to access the information that he or she have inputted, is that correct? Many thanks

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  • Fluent NHibernate - Set reference key columns to null

    - by Matt
    Hi, I have a table of Appointments and a table of AppointmentOutcomes. On my Appointments table I have an OutcomeID field which has a foreign key to AppointmentOutcomes. My Fluent NHibernate mappings look as follows; Table("Appointments"); Not.LazyLoad(); Id(c => c.ID).GeneratedBy.Assigned(); Map(c => c.Subject); Map(c => c.StartTime); References(c => c.Outcome, "OutcomeID"); Table("AppointmentOutcomes"); Not.LazyLoad(); Id(c => c.ID).GeneratedBy.Assigned(); Map(c => c.Description); Using NHibernate, if I delete an AppointmentOutcome an exception is thrown because the foreign key is invalid. What I would like to happen is that deleting an AppointmentOutcome would automatically set the OutcomeID of any Appointments that reference the AppointmentOutcome to NULL. Is this possible using Fluent NHibernate?

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  • Cannot add or update a child row: a foreign key constraint fails

    - by myaccount
    // Getting the id of the restaurant to which we are uploading the pictures $restaurant_id = intval($_GET['restaurant-id']); if(isset($_POST['submit'])) { $tmp_files = $_FILES['rest_pics']['tmp_name']; $target_files = $_FILES['rest_pics']['name']; $tmp_target = array_combine($tmp_files, $target_files); $upload_dir = $rest_pics_path; foreach($tmp_target as $tmp_file => $target_file) { if(move_uploaded_file($tmp_file, $upload_dir."/".$target_file)) { $sql = sprintf(" INSERT INTO rest_pics (branch_id, pic_name) VALUES ('%s', '%s')" , mysql_real_escape_string($restaurant_id) , mysql_real_escape_string(basename($target_file))); $result = mysql_query($sql) or die(mysql_error()); } I get the next error: Cannot add or update a child row: a foreign key constraint fails (rest_v2.rest_pics, CONSTRAINT rest_pics_ibfk_1 FOREIGN KEY (branch_id) REFERENCES rest_branches (branch_id) ON DELETE CASCADE ON UPDATE CASCADE However, this error totally disappears and everything goes well when I put directly the restaurant id (14 for example) instead of $restaurant_id variable in the sql query. The URL am getting the id from is: http://localhost/rest_v2/public_html/admin/add-delete-pics.php?restaurant-id=2 Any help please?

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  • Save or update for FK relationship Sqlalchemy

    - by Alex
    I've googled, but haven't been able to find the answer to this seemingly simple question. I have two relations, a customer and an order. Each order is associated to a single cusomter, and therefore has a FK relationship to the customer table. The customer relation only stores customer names, and I have set a unique constraint on the customer table barring duplicate names. Let's say I create a new order instance and set a customer for the order. Something like: order_instance.customer = Customer("customer name") When I save the order instance, SqlAlchemy will complain if a customer with this name already exists in the customer table. How do I specify to SqlAlchemy to insert into the customer table if a customer with this name doesn't already exist, or just ignore (or even update) to the customer relation? I don't really want to have to check each time if a customer with some name already exists...

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  • When to use a foreign key in MySQL

    - by Mel
    Is there official guidance or a threshold to indicate when it is best practice to use a foreign key in a MySQL database? Suppose you created a table for movies. One way to do it is to integrate the producer and director data into the same table. (movieID, movieName, directorName, producerName). However, suppose most directors and producers have worked on many movies. Would it be best to create two other tables for producers and directors, and use a foreign key in the movie table? When does it become best practice to do this? When many of the directors and producers are appearing several times in the column? Or is it best practice to employ a foreign key approach at the start? While it seems more efficient to use a foreign key, it also raises the complexity of the database. So when does the trade off between complexity and normalization become worth it? I'm not sure if there is a threshold or a certain number of cell repetitions that makes it more sensible to use a foreign key. I'm thinking about a database that will be used by hundreds of users, many concurrently. Many thanks!

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  • how to save related models with non-null foreign key

    - by Fortress
    I have a model called user which has_one email. I put the foreign key (NOT NULL) inside users table. Now I'm trying to save it in the following way: @email = Email.new(params[:email]) @email.user = User.new(params[:user]) @email.save This raises a db exception, because the foreign key constraint is not met (NULL is inserted into email_id). How can I elegantly solve this or is my data modeling wrong?

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  • List all foreign key constraints that refer to a particular column in a specific table

    - by Sid
    I would like to see a list of all the tables and columns that refer (either directly or indirectly) a specific column in the 'main' table via a foreign key constraint that has the ON DELETE=CASCADE setting missing. The tricky part is that there would be an indirect relationships buried across up to 5 levels deep. (example: ... great-grandchild- FK3 = grandchild = FK2 = child = FK1 = main table). We need to dig up the leaf tables-columns, not just the very 1st level. The 'good' part about this is that execution speed isn't of concern, it'll be run on a backup copy of the production db to fix any relational issues for the future. I did SELECT * FROM sys.foreign_keys but that gives me the name of the constraint - not the names of the child-parent tables and the columns in the relationship (the juicy bits). Plus the previous designer used short, non-descriptive/random names for the FK constraints, unlike our practice below The way we're adding constraints into SQL Server: ALTER TABLE [dbo].[UserEmailPrefs] WITH CHECK ADD CONSTRAINT [FK_UserEmailPrefs_UserMasterTable_UserId] FOREIGN KEY([UserId]) REFERENCES [dbo].[UserMasterTable] ([UserId]) ON DELETE CASCADE GO ALTER TABLE [dbo].[UserEmailPrefs] CHECK CONSTRAINT [FK_UserEmailPrefs_UserMasterTable_UserId] GO The comments in this SO question inpire this question.

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  • Way to check for foreign key references before deleting in MySQL?

    - by Chad Johnson
    I'm working with a content management system, and users are prompted with a confirmation screen before deleting records. Some records are foreign key referenced in other tables, and therefore they cannot be deleted. I would like to display a message beside a given record if it has foreign key references. To know whether I should display the message for a record, I could just query the referencing table and see if there are references. But the problem is, there are about a dozen tables with records potentially referencing this record, and a lookup could take a "long" time. Is there an easy way to tell whether the record is delete-ready (ie. has no foreign key references)?

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  • MYSQL inserting records form table A into tables B and C (linked by foreign key) depending on column values in table A

    - by Chez
    Hi All, Have been searching high and low for a simple solution to a mysql insert problem. The problem is as follows: I am putting together an organisational database consisting of departments and desks. A department may or may not have n number of desks. Both departments and desks have their own table linked by a foreign key in desks to the relevant record in departments (i.e. the pk). I have a temporary table which I use to place all new department data (n records long)...In this table n number of desk records for a department follow the department record directly below. In the TEMP table, if a column department_name has a value,it is a department, if it doesn't it will have a value for the column desk and therefore will be a desk which is related to the above department. As I said there maybe several desk records until you get to the next department record. Ok, so what I want to do is the following: Insert the departments into the departments table and its desks into the desks table , generating a foreign key in the desk record to the relevant departments id. In pseudo-ish code: for each record in TEMP table if Department INSERT the record into Departments get the id of the newly created Department record and store it somewhere else if Desk INSERT the desk into the desks table with the relevant departments id as the foreignkey note once again that all departments desks directly follow the department in the TEMP Table Many Thanks

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  • Jump-To-Code-Line Eclipse Shortcuts

    - by scrr
    Hello, is it possible, in Eclipse, to mark certain lines with Shortcuts and be able to quickly jump to those lines? Example: Let's say I have maintenanceHeavyMethod() at line 120 in my class, gameLoop() at line 800 and some listener at line 1460. I'd like to f.ex. press CTRL-SHIFT-1, 2, 3 etc. to mark those positions, and then use f.ex. CTRL-1, 2, 3 to immediately jump to them. I don't like split-screens etc, but I need to jump around when writing. Is there such a feature? I'm using latest Eclipse to write Java-programs.

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  • Django: getting the list of related records for a list of objects

    - by Silver Light
    Hello! I have two models related one-to many: class Person(models.Model): name = models.CharField(max_length=255); surname = models.CharField(max_length=255); age = models.IntegerField(); class Dog(models.Model): name = models.CharField(max_length=255); owner = models.ForeignKey('Person'); I want to output a list of persons below each person a list of dogs he has. Here's how I can do it: in view: persons = Person.objects.all()[0:100]; in template: {% for p in persons %} {{ p.name }} has dogs:<br /> {% for d in persons.dog_set.all %} - {{ d.name }}<br /> {% endfor %} {% endfor %} But if I do it like that, Django will execute 101 SQL queries which is very inefficient. I tried to make a custom manager, which will get all the persons, then all the dogs and links them in python, but then I can't use paginator (my another question: http://stackoverflow.com/questions/2532475/django-paginator-raw-sql-query ) and it looks quite ugly. Is there a more graceful way doing this?

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  • How can I ask Hibernate to create an index on a foreign key (JoinColumn)?

    - by Kent Chen
    Hi, This is my model. class User{ @CollectionOfElements @JoinTable(name = "user_type", joinColumns = @JoinColumn(name = "user_id")) @Column(name = "type", nullable = false) private List<String> types = new ArrayList<String>(); } You can imagin there would be a table called "user_type", which has two columns, one is "user_id", the other is "type". And when I use hbm2ddl to generate the ddls, I can have this table, along with the foreign key constraint on "user_id". However, there is no index of this for this column. And I need this index. How can I let hibernate to generate this index for me? Thank you!

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  • Why can't I SELECT a parent field that doesn't have a child?

    - by myaccount
    (rest_branches) is the table of restaurants. (phone_numbers) is another table which contains the restaurants phone_numbers, and it has a field called (branch_id) which references the restaurant id. When I try: SELECT * FROM rest_branches NATURAL JOIN phone_numbers I only get the restaurants which have a phone_number. What should I do to get all restaurants even if they don't have a phone number?

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  • Generate Delete Statement From Foreign Key Relationships in SQL 2008 ?

    - by Element
    Is it possible via script/tool to generate a delete statement based on the tables fk relations. i.e. I have the table: DelMe(ID) and there are 30 tables with fk references to its ID that I need to delete first, is there some tool/script that I can run that will generate the 30 delete statements based on the FK relations for me ? (btw I know about cascade delete on the relations, I can't use it in this existing db) I'm using Microsoft SQL Server 2008

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  • wxpython - Nested Notebooks

    - by madtowneast
    I have been trying to make my nested notebooks a little bit more appealing code wise. At the moment, I got this #!/usr/bin/env python import os import sys import datetime import numpy as np from readmonifile import MonitorFile from sortmonifile import sort import wx class NestedPanelOne(wx.Panel): #---------------------------------------------------------------------- # First notebook that creates the tab to select the component number #---------------------------------------------------------------------- def __init__(self, parent, label, data): wx.Panel.__init__(self, parent=parent, id=wx.ID_ANY) sizer = wx.BoxSizer(wx.VERTICAL) #Loop creating the tabs according to the component name nestedNotebook = wx.Notebook(self, wx.ID_ANY) for slabel in sorted(data[label].keys()): tab = NestedPanelTwo(nestedNotebook, label, slabel, data) nestedNotebook.AddPage(tab,slabel) sizer = wx.BoxSizer(wx.VERTICAL) sizer.Add(nestedNotebook, 1, wx.ALL|wx.EXPAND, 5) self.SetSizer(sizer) class NestedPanelTwo(wx.Panel): #------------------------------------------------------------------------------ # Second notebook that creates the tab to select the main monitoring variables #------------------------------------------------------------------------------ def __init__(self, parent, label, slabel, data): wx.Panel.__init__(self, parent=parent, id=wx.ID_ANY) sizer = wx.BoxSizer(wx.VERTICAL) nestedNotebook = wx.Notebook(self, wx.ID_ANY) for sslabel in sorted(data[label][slabel][data[label][slabel].keys()[0]].keys()): tab = NestedPanelThree(nestedNotebook, label, slabel, sslabel, data) nestedNotebook.AddPage(tab, sslabel) sizer.Add(nestedNotebook, 1, wx.ALL|wx.EXPAND, 5) self.SetSizer(sizer) class NestedPanelThree(wx.Panel): #------------------------------------------------------------------------------- # Third notebook that creates checkboxes to select the monitoring sub-variables #------------------------------------------------------------------------------- def __init__(self, parent, label, slabel, sslabel, data): wx.Panel.__init__(self, parent=parent, id=wx.ID_ANY) labels=[] chbox =[] chboxdict={} for ssslabel in sorted(data[label][slabel][data[label][slabel].keys()[0]][sslabel].keys()): labels.append(ssslabel) for item in list(set(labels)): cb = wx.CheckBox(self, -1, item) chbox.append(cb) chboxdict[item]=cb gridSizer = wx.GridSizer(np.shape(list(set(labels)))[0],3, 5, 5) gridSizer.AddMany(chbox) self.SetSizer(gridSizer) ######################################################################## class NestedNotebookDemo(wx.Notebook): #--------------------------------------------------------------------------------- # Main notebook creating tabs for the monitored components #--------------------------------------------------------------------------------- def __init__(self, parent, data): wx.Notebook.__init__(self, parent, id=wx.ID_ANY, style= wx.BK_DEFAULT ) for label in sorted(data.keys()): print label tab = NestedPanelOne(self,label, data) self.AddPage(tab, label) ######################################################################## class DemoFrame(wx.Frame): #---------------------------------------------------------------------- # Putting it all together #---------------------------------------------------------------------- def __init__(self,data): wx.Frame.__init__(self, None, wx.ID_ANY, "pDAQ monitoring plotting tool", size=(800,400) ) panel = wx.Panel(self) notebook = NestedNotebookDemo(panel, data) sizer = wx.BoxSizer(wx.VERTICAL) sizer.Add(notebook, 1, wx.ALL|wx.EXPAND, 5) panel.SetSizer(sizer) self.Layout() #Menu Bar to be added later ''' menubar = wx.MenuBar() file = wx.Menu() file.Append(1, '&Quit', 'Exit Tool') menubar.Append(file, '&File') self.SetMenuBar(menubar) self.Bind(wx.EVT_MENU, self.OnClose, id=1) ''' self.Show() #---------------------------------------------------------------------- if __name__ == "__main__": if len(sys.argv) == 1: raise SystemExit("Please specify a file to process") for f in sys.argv[1:]: data=sort.sorting(f) print data['stringHub'].keys() print data.keys() print data[data.keys()[0]].keys() print 'test' app = wx.PySimpleApp() frame = DemoFrame(data) app.MainLoop() print 'testend' and I would like to reduce this whole mess into something that only has three nested for loops, so something like for label in sorted(data.keys()): self.SubNoteBooks[label] = wx.Notebook(self.Notebook, wx.ID_ANY) self.Notebook.AddPage(self.SubNoteBooks[label], label) for slabel in sorted(data[label].keys()): self.SubNoteBooks[label][slabel] = wx.Notebook(self, wx.ID_ANY) self.SubNoteBooks[label].AddPage(self.SubNoteBooks[label][slabel], slabel) for sslabel in sorted(data[label][slabel][data[label][slabel].keys()[0]].keys()): self.SubNoteBooks[label][slabel][sslabel] = wx.Notebook(self.Notebook, wx.ID_ANY) self.Notebook.AddPage(self.SubNoteBooks[label][slabel][sslabel], sslabel) I have been trying to fiddle this around but the problem seems to be the line self.SubNoteBooks[label][slabel] = wx.Notebook(self, wx.ID_ANY) I get the error: Traceback (most recent call last): File "./reducelinenumbers.py", line 162, in <module> frame = DemoFrame(data) File "./reducelinenumbers.py", line 126, in __init__ self.SubNoteBooks[label][slabel] = wx.Notebook(self, wx.ID_ANY) TypeError: 'Notebook' object does not support item assignment I understand why notebook is being type raises a TypeError here. Is there a way around this? Thanks a bunch in advance.

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  • How do I make Home / End keys behave Windows/Linux like in Terminal.app on Mac OS on Mac Pro laptop?

    - by Nick Gorbikoff
    Hello. I was wondering if somebody knows how to use home/end keys behave in a Windows/ Linux fashion. What I mean is that when I press Apple + Left (Home combo on a mac book pro laptop) it should go to the beginning of the line, and Apple + Right to the end of the line. Right now they change focus to the top of the scroll history. Drives me crazy. Home / End keys behave as expected in TextMate and such but not in terminal, which makes me think it's that app specific. I found some page saying that I need to remap key bindings but I can't do that on every mac i touch. So is there another shorcut in Mac I can use or how do I make Home/End keys behave as expected? Thank you

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  • Stop ssh client from offering all the public keys it can find?

    - by Rory McCann
    Like most sysadmins I use openssh all the time. I have about a dozen ssh keys, I like to have a different ssh key for each host. However this causes a problem when I am connecting to a host for the first time, and all I have is a password. I want to just connect to the host using a password, no ssh key in this case. However the ssh client will offer all the public keys in my ~/.ssh/ (I know this from looking at the output of ssh -v). Since I have so many, I will get disconnected for too many authentication failures. Is there some way to tell my ssh client to not offer all the ssh keys?

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  • Can I upgrade my ubuntu version and change to be primary OS after originally installing with Wibu?

    - by Garrick Wann
    I have recently installed Ubuntu 12.04 using Wubi 12.04 and I now wish to upgrade to a full installation of Ubuntu 14.04, Before attempting to upgrade through the update center I did some research on upgrading from a Wubi installation (alongside windows) to a full installation making Ubuntu primary and only OS and found that it is in fact doable through the update center however it is just highly recommended to perform a full backup before doing so. I have now finished backing up all the data I need to worry about and began the upgrade process through the update center and received the following error: Your graphics hardware may not be fully supported in Ubuntu 14.04. Running the 'unity' desktop environment is not fully supported by your graphics hardware. You will maybe end up in a very slow environment after the upgrade. Our advice is to keep the LTS version for now. For more information see https://wiki.ubuntu.com/X/Bugs/UpdateManagerWarningForUnity3D Do you still want to continue with the upgrade? My questions are as follows: A. Isnt 14.04 a LTS version??? B, What are your recomendations in order to ensure my graphics driver is installed correctly and im not stuck with bad configs/install?

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