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• Use from value from backing bean in javascript

  - by AlfonsSocken

  What I want is to use a boolean value from applicationContext.xml (Jboss configuration file) in my javascript. Currently I use Spring to inject a value configured in applicationContext.xml into my backingbean. Then I put an output text in my jsp like this <h:outputText id="idValue" styleClass="foo" value="" rendered="#{bean.isRendered}"/> In my JavaScript I try following jQuery(function(){ bRedirect = jQuery("#foo").value != undefined; ... All this looks so terrible to me, even though it works fine. There must be a smarter way than doing what I do. Note that I am running JSF1.2 and therefore must use jQuery instead of $ and also select by unique class (foo) and not by id, which may be bad practice as well. Thank you in advance. alfons

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• Formal name of Magento’s Class Override Design Pattern?

  - by Alan Storm

  Magento is a newish (past 5 years) PHP based Ecommerce system with an architecture that's similar to the Java Spring framework (or so I've been told) One of the features of the Framework is certain classes are not directly instantiated. Rather than do something like $model = new Mage_Foo_Model_Name(); you pass an identifier into a static method on a global application object $model = Mage::getModel('foo/name'); and this instantiates the class for you. One of the wins with this approach is getModel checks a global configuration system for the foo/name identifier, and instantiates the class name it finds in the configuration system. This allows you to change the behavior of a Model system wide with a single configuration change. Is there a formal, Gang of Four or otherwise, name that describes this system/design pattern? The instantiation itself looks like a classic Factory pattern, but I'm specifically interested in the whole "override a class in the system via configuration" aspect. Is there a name/concept that covers this, or is it contained within the worldview of a Factory?

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• How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way?

  - by EugeneP

  How to deal with the Hibernate hql multi-join query result in an Object-Oriented Way? As I see it returns a list of Objects. yes, it is tricky and only you who write the query know what should the query return (what objects). But are there ways to simplify things, so that it returned specific objects with no need in casting Object to a specific class according to its position in the query ? Maybe Spring can simplify things here? It has the similar functionality for JDBC, but I don't see if it can help in a similar way with Hibernate.

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• Restrict confirm message on page reload with f5

  - by Max

  In my JSP page I am using post method while submitting the page. So once I go from Page 1 to page 2. In Page 2, If I press F5 I am getting alert as "To display this page, Firefox must send information that will repeat any action (such as a search or order confirmation) that was performed earlier." I knew this question is a bit sarcastic but please give me an Idea. I can't change my method from POST to GET because I need to send large amount of data. Thanks in advance... Edited: In my Page1.JSP I call onClick function in that function I call action as "/page2servlet.do". Now, In Java side I use Spring Framework. With MVC Object I return to page2.jsp. So where do the response.sendRedirect Fit.

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• Creating a page selector with JSP/JSTL

  - by zakSyed

  I am working on a project where I am required to build a page somewhat similar to the one you see when you visit a website like blockbuster. When you click on browse more you are taken to a page with a bar on top with different page numbers and a drop down to select the number of pages you want to view on that page. I want to include a feature like that on my page but I am not sure where to start. In my page I have list of 200 items which I want to display page by page. I was suggested to use custom tags, but is there a more simpler or efficient way to create that functionality. My web application uses Spring MVC framework and is coded entirely in Java. Any suggestions will be appreciated.

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• Unable to pass attribute from controller to view

  - by MDS

  I'm using Spring MVC 3 for a web app. In the app a URI template is supposed to be handled by a controller method, which then passes an attribute to a view. Currently, the controller does handle the request, and it even forwards to the correct view. However, it does NOT pass the attribute to the view. Below are the URI template, controller method and relevent jsp tags. Anyone see what is wrong? URI: /home/{status} Controller: @RequestMapping("/home") @Controller public class HomeController { ... ... @RequestMapping(value="/{status}") public String homeStatusView(@PathVariable("status") String status, ModelMap model) { model.addAttribute("status", status); return "home"; } } JSP: ... <c:if test="${not empty status}"> <span class="status">Your status is available...</span> </c:if> ...

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• A typical lifecycle of a Hibernate object in a web app - ?

  - by EugeneP

  Describe please a typical lifecycle of a Hibernate object (that maps to a db table) in a web app. Suppose, you create a new instance of an object and persist in the db. But during the app lifetime you'll be working on a detached object and finally you need to update it in the database, for example on exit. How does it look like with hibernate and spring? p.s. Can transactions and sessions live between servlet transitions? So that we opened 1 session and use it in all servlets without a need to reopen it?

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• org.hibernate.MappingException: Unknown entity:

  - by tsegay

  I tried to see all the questions on this topic but none of them helped me. And I really want to understand what is going on with my code. I have a standalone application which uses spring and Hibernate as JPA and I am trying to run the test using a single main Class My main class package edu.acct.tsegay.common; import edu.acct.tsegay.model.User; import edu.acct.tsegay.business.IUserBusinessObject; import org.springframework.context.ApplicationContext; import org.springframework.context.support.ClassPathXmlApplicationContext; public class App { public static void main(String[] args) { try { ApplicationContext context = new ClassPathXmlApplicationContext( "Spring3AndHibernate-servlet.xml"); IUserBusinessObject userBusinessObject = (IUserBusinessObject) context .getBean("userBusiness"); User user = (User) context.getBean("user1"); user.setPassword("pass"); user.setUsername("tsegay"); System.out.println(user.getPassword()); userBusinessObject.delete(user); User user2 = new User(); user2.setUsername("habest"); user2.setPassword("pass1"); System.out.println(user2.getPassword()); /* * userBusinessObject.save(user2); * * User user3 = userBusinessObject.searchUserbyId("tsegay"); * System.out.println("Search Result: " + user3.getUsername()); */ System.out.println("Success"); } catch (Exception e) { e.printStackTrace(); } } } my application context is: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd"> <!-- data source --> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://localhost:3306/test" /> <property name="username" value="test" /> <property name="password" value="password" /> </bean> <!-- session factory --> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="dataSource" /> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.MySQLDialect</prop> <prop key="hibernate.show_sql">true</prop> </props> </property> </bean> <!-- exposed person business object --> <bean id="userBusiness" class="edu.acct.tsegay.business.UserBusinessObject"> <property name="userDao" ref="userDao" /> </bean> <bean id="user1" class="edu.acct.tsegay.model.User"> <property name="username" value="tse" /> <property name="password" value="pass" /> </bean> <!-- Data Access Object --> <bean id="userDao" class="edu.acct.tsegay.dao.UserDao"> <property name="sessionFactory" ref="sessionFactory" /> </bean> </beans> My User Model is: package edu.acct.tsegay.model; import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; import javax.persistence.Version; import org.hibernate.annotations.NaturalId; @Entity public class User implements Serializable { /** * */ private static final long serialVersionUID = 1L; private String username; private String password; private Integer VERSION; @Version public Integer getVERSION() { return VERSION; } public void setVERSION(Integer vERSION) { VERSION = vERSION; } @NaturalId public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } } My DAO is: package edu.acct.tsegay.dao; import edu.acct.tsegay.model.User; import org.hibernate.SessionFactory; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.orm.hibernate3.HibernateTemplate; import org.springframework.stereotype.Repository; @Repository public class UserDao implements IUserDao { private SessionFactory sessionFactory; private HibernateTemplate hibernateTemplate; public SessionFactory getSessionFactory() { return sessionFactory; } @Autowired public void setSessionFactory(SessionFactory sessionFactory) { this.sessionFactory = sessionFactory; this.hibernateTemplate = new HibernateTemplate(sessionFactory); } public void save(User user) { // TODO Auto-generated method stub // getHibernateTemplate().save(user); this.hibernateTemplate.save(user); } public void delete(User user) { // TODO Auto-generated method stub this.hibernateTemplate.delete(user); } public User searchUserbyId(String username) { // TODO Auto-generated method stub return this.hibernateTemplate.get(User.class, username); } } And this my stacktrace error when i run the program: pass org.springframework.orm.hibernate3.HibernateSystemException: Unknown entity: edu.acct.tsegay.model.User; nested exception is org.hibernate.MappingException: Unknown entity: edu.acct.tsegay.model.User at org.springframework.orm.hibernate3.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:679) at org.springframework.orm.hibernate3.HibernateAccessor.convertHibernateAccessException(HibernateAccessor.java:412) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:411) at org.springframework.orm.hibernate3.HibernateTemplate.executeWithNativeSession(HibernateTemplate.java:374) at org.springframework.orm.hibernate3.HibernateTemplate.delete(HibernateTemplate.java:837) at org.springframework.orm.hibernate3.HibernateTemplate.delete(HibernateTemplate.java:833) at edu.acct.tsegay.dao.UserDao.delete(UserDao.java:34) at edu.acct.tsegay.business.UserBusinessObject.delete(UserBusinessObject.java:30) at edu.acct.tsegay.common.App.main(App.java:23) Caused by: org.hibernate.MappingException: Unknown entity: edu.acct.tsegay.model.User at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:580) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1365) at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:100) at org.hibernate.event.def.DefaultDeleteEventListener.onDelete(DefaultDeleteEventListener.java:74) at org.hibernate.impl.SessionImpl.fireDelete(SessionImpl.java:793) at org.hibernate.impl.SessionImpl.delete(SessionImpl.java:771) at org.springframework.orm.hibernate3.HibernateTemplate$25.doInHibernate(HibernateTemplate.java:843) at org.springframework.orm.hibernate3.HibernateTemplate.doExecute(HibernateTemplate.java:406) ... 6 more Please let me know if you need any more of my configuration. Any help is much appreciated..

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• java.lang.IllegalStateException: Neither BindingResult nor plain target object for bean name 'editFo

  - by mansoor

  i am working with spring frame work. Problem is that on forgot password jsp page when i enter the right name or email address the funtion send a mail to the user. But i want when user not enter username or password the calling funtion at controoler return a exception called bind exception and return not in getSuccessView() but redirct at same page and print the Invalid user name or email id. the controller code is following public class EditForgotPasswordFormController extends AbstractBaseFormController{ UserManager userManager; @Override protected ModelAndView executeOnSubmit(ExtendedHttpServletRequest request, ExtendedHttpServletResponse response, Object command, BindException errors) throws Exception { EditForgotPassword e=(EditForgotPassword)command; String s = e.getUsernameOrEmail(); try{ userManager.getNewPassword(s); }catch(RuntimeException exp) { errors.reject("Invailid Username Or EmailId",s); return new ModelAndView("normal/profile/forgot_password"); } return new ModelAndView(getSuccessView()) .addObject("heading", "Please Check You Email") .addObject("message", "Your New Account Information Is sent To At Your Email Id. "); } public UserManager getUserManager() { return userManager; } public void setUserManager(UserManager userManager) { this.userManager = userManager; } } when i am not enter the name or email id the i want redirct at following as indicate above and print message on same jsp where from request is recived........

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• Redirect on Ajax Jquery Call

  - by Mark Estrada

  Hi, I am newbie to ajax here and I know somebody would have encountered this problem already. I have a legacy app built on Spring MVC, it has a interceptor(filter) that redirects the user to the login page whenever there is no session. public class SessionCheckerInterceptor extends HandlerInterceptorAdapter { public boolean preHandle(HttpServletRequest request, HttpServletResponse response, Object handler) throws Exception { HttpSession session = request.getSession(); // check if userInfo exist in session User user = (User) session.getAttribute("user"); if (user == null) { response.sendRedirect("login.htm"); return false; } return true; } } For non-xmlhttp request, this works fine.. but when I try to use ajax in my application, everything gets weird, it is not able to redirect to the login page correctly. As check the value of the xhr.status = 200 textStatus = parseError errorThrown = "Invalid JSON -Markup of my HTML Login Page- $(document).ready(function(){ jQuery.ajax({ type: "GET", url: "populateData.htm", dataType:"json", data:"userId=SampleUser", success:function(response){ //code here }, error: function(xhr, textStatus, errorThrown) { alert('Error! Status = ' + xhr.status); } }); }); I checked on my firebug that there is a 302 HTTP response but I am not sure how to catch the response and redirect the user to the login page. Any idea here? Thanks.

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• SimpleJdbcCall ignoring JdbcTemplate fetch size

  - by user289429

  We are calling the pl/sql stored procedure through Spring SimpleJdbcCall, the fetchsize set on the JdbcTemplate is being ignored by SimpleJdbcCall. The rowmapper resultset fetch size is set to 10 even though we have set the jdbctemplate fetchsize to 200. Any idea why this happens and how to fix it? Have printed the fetchsize of resultset in the rowmapper in the below code snippet - Once it is 200 and other time it is 10 even though I use the same JdbcTemplate on both occassion. This direct execution through jdbctemplate returns fetchsize of 200 in the row mapper jdbcTemplate = new JdbcTemplate(ds); jdbcTemplate.setResultsMapCaseInsensitive(true); jdbcTemplate.setFetchSize(200); List temp = jdbcTemplate.query("select 1 from dual", new ParameterizedRowMapper() { public Object mapRow(ResultSet resultSet, int i) throws SQLException { System.out.println("Direct template : " + resultSet.getFetchSize()); return new String(resultSet.getString(1)); } }); This execution through SimpleJdbcCall is always returning fetchsize of 10 in the rowmapper jdbcCall = new SimpleJdbcCall(jdbcTemplate).withSchemaName(schemaName) .withCatalogName(catalogName).withProcedureName(functionName); jdbcCall.returningResultSet((String) outItValues.next(), new ParameterizedRowMapper<Map<String, Object>>() { public Map<String, Object> mapRow(ResultSet rs, int row) throws SQLException { System.out.println("Through simplejdbccall " + rs.getFetchSize()); return extractRS(rs, row); } }); outputList = (List<Map<String, Object>>) jdbcCall.executeObject(List.class, inParam);

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• Map enum in JPA with fixed values ?

  - by Kartoch

  I'm looking for the different ways to map an enum using JPA. I especially want to set the integer value of each enum entry and to save only the integer value. @Entity @Table(name = "AUTHORITY_") public class Authority implements Serializable { public enum Right { READ(100), WRITE(200), EDITOR (300); private int value; Right(int value) { this.value = value; } public int getValue() { return value; } }; @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "AUTHORITY_ID") private Long id; // the enum to map : private Right right; } A simple solution is to use the Enumerated annotation with EnumType.ORDINAL: @Column(name = "RIGHT") @Enumerated(EnumType.ORDINAL) private Right right; But in this case JPA maps the enum index (0,1,2) and not the value I want (100,200,300). Th two solutions I found do not seem simple... First Solution A solution, proposed here, uses @PrePersist and @PostLoad to convert the enum to an other field and mark the enum field as transient: @Basic private int intValueForAnEnum; @PrePersist void populateDBFields() { intValueForAnEnum = right.getValue(); } @PostLoad void populateTransientFields() { right = Right.valueOf(intValueForAnEnum); } Second Solution The second solution proposed here proposed a generic conversion object, but still seems heavy and hibernate-oriented (@Type doesn't seem to exist in JEE): @Type( type = "org.appfuse.tutorial.commons.hibernate.GenericEnumUserType", parameters = { @Parameter( name = "enumClass", value = "Authority$Right"), @Parameter( name = "identifierMethod", value = "toInt"), @Parameter( name = "valueOfMethod", value = "fromInt") } ) Is there any other solutions ? I've several ideas in mind but I don't know if they exist in JPA: use the setter and getter methods of right member of Authority Class when loading and saving the Authority object an equivalent idea would be to tell JPA what are the methods of Right enum to convert enum to int and int to enum Because I'm using Spring, is there any way to tell JPA to use a specific converter (RightEditor) ?

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• Custom JSTL tags with body

  - by Mickel

  Hi, We are going to use JSTL and custom JSTL-tags for some sort of template-engine in our JSP/spring-project. Is there a way to create a tag that looks similar like this: <div id="site"> <div id="header">Some title</div> <div id="navigation"> SOME DYNAMIC CONTENT HERE </div> <div id="content"> ${content} </div> <div id="footer"></div> </div> and use it like this: <mytags:template> <h1>Title</h1> <p>My content!</p> </mytags:template> i.e. use body-content inside a custom JSTL-tag... This works: <mytags:template content="some content... not HTML" /> but is not very useful in our case.

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• database design to speed up hibernate querying of large dataset

  - by paddydub

  I currently have the below tables representing a bus network mapped in hibernate, accessed from a Spring MVC based bus route planner I'm trying to make my route planner application perform faster, I load all the above tables into Lists to perform the route planner logic. I would appreciate if anyone has any ideas of how to speed my performace Or any suggestions of another method to approach this problem of handling a large set of data Coordinate Connections Table (INT,INT,INT)( Containing 50,000 Coordinate Connections) ID, FROMCOORDID, TOCOORDID 1 1 2 2 1 17 3 1 63 4 1 64 5 1 65 6 1 95 Coordinate Table (INT,DECIMAL, DECIMAL) (Containing 4700 Coordinates) ID , LAT, LNG 0 59.352669 -7.264341 1 59.352669 -7.264341 2 59.350012 -7.260653 3 59.337585 -7.189798 4 59.339221 -7.193582 5 59.341408 -7.205888 Bus Stop Table (INT, INT, INT)(Containing 15000 Stops) StopID RouteID COORDINATEID 1000100001 100 17 1000100002 100 18 1000100003 100 19 1000100004 100 20 1000100005 100 21 1000100006 100 22 1000100007 100 23 This is how long it takes to load all the data from each table: stop.findAll = 148ms, stops.size: 15670 Hibernate: select coordinate0_.COORDINATEID as COORDINA1_2_, coordinate0_.LAT as LAT2_, coordinate0_.LNG as LNG2_ from COORDINATES coordinate0_ coord.findAll = 51ms , coordinates.size: 4704 Hibernate: select coordconne0_.COORDCONNECTIONID as COORDCON1_3_, coordconne0_.DISTANCE as DISTANCE3_, coordconne0_.FROMCOORDID as FROMCOOR3_3_, coordconne0_.TOCOORDID as TOCOORDID3_ from COORDCONNECTIONS coordconne0_ coordinateConnectionDao.findAll = 238ms ; coordConnectioninates.size:48132 Hibernate Annotations @Entity @Table(name = "STOPS") public class Stop implements Serializable { @Id @GeneratedValue @Column(name = "COORDINATEID") private Integer CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Table(name = "COORDINATES") public class Coordinate { @Id @GeneratedValue @Column(name = "COORDINATEID") private Integer CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Entity @Table(name = "COORDCONNECTIONS") public class CoordConnection { @Id @GeneratedValue @Column(name = "COORDCONNECTIONID") private Integer CoordinateID; /** * From Coordinate_id value */ @Column(name = "FROMCOORDID", nullable = false) private int fromCoordID; /** * To Coordinate_id value */ @Column(name = "TOCOORDID", nullable = false) private int toCoordID; //private Coordinate toCoordID; }

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• ETL , Esper or Drools?

  - by geoaxis

  Hello, The question environment relates to JavaEE, Spring I am developing a system which can start and stop arbitrary TCP (or other) listeners for incoming messages. There could be a need to authenticate these messages. These messages need to be parsed and stored in some other entities. These entities model which fields they store. So for example if I have property1 that can have two text fields FillLevel1 and FillLevel2, I could receive messages on TCP which have both fill levels specified in text as F1=100;F2=90 Later I could add another filed say FillLevel3 when I start receiving messages F1=xx;F2=xx;F3=xx. But this is a conscious decision on the part of system modeler. My question is what do you think is better to use for parsing and storing the message. ETL (using Pantaho, which is used in other system) where you store the raw message and use task executor to consume them one by one and store the transformed messages as per your rules. One could use Espr or Drools to do the same thing , storing rules and executing them with timer, but I am not sure how dynamic you could get with making rules (they have to be made by end user in a running system and preferably in most user friendly way, ie no scripts or code, only GUI) The end user should be capable of changing the parse rules. It is also possible that end user might want to change the archived data as well (for example in the above example if a new value of FillLevel is added, one would like to put a FillLevel=-99 in the previous values to make the data consistent). Please ask for explanations, I have the feeling that I need to revise this question a bit. Thanks

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• Define DataSource bean on code

  - by Ruben Trancoso

  I would like to make a "First Access Database Setup Process" in my spring application and the only thing I can imagine as a solution would be to initialize the DataSource bean programatically. My current bean is defined as: <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close"> <property name="driverClassName" value="com.mysql.jdbc.Driver" /> <property name="url" value="jdbc:mysql://localhost:3306/catalog" /> <property name="username" value="condominium" /> <property name="password" value="password" /> <property name="validationQuery" value="SELECT 1" /> <property name="testOnBorrow" value="true" /> <property name="defaultAutoCommit" value="false" /> <property name="maxWait" value="5000" /> </bean> but the ideal thing was to load it by myself in whenever I need it and with the parameter I define. The scenario is that the user (administrator) comes to the application at the first time and I ask him the server, port and catalog to connect. I store it in a embeeded db and next time application start, a bean can check if the parameter are set on the embedded db and load it again. Is it possible?

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• Change default polymorphism in Hibernate

  - by Sujee

  Hi, I'd like to set polymorphism="explicit" property to several hibernate mapping classes. is it possible to override the default implicit value, so that I do not need to set explicit in multiple classes? <class name="xxxxx" table="XXXXX" polymorphism="explicit"> I am using hibernate mapping xml files (No annotations or JPA) and it was loaded by Spring as follows, <bean id="xxxsessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource"> <ref bean="xxxDataSource"/> </property> <property name="mappingResources"> <list> <value>xxx.hbm.xml</value> -------- -------- </list> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">org.hibernate.dialect.OracleDialect</prop> ---- ---- </props> </property> </bean> Thank you.

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• Commercial Website architecture question

  - by Maxime ARNSTAMM

  Hello everyone, I have to write an architecture case study but there are some things that i don't know, so i'd like some pointers on the following : The website must handle 5k simultaneous users. The backend is composed by a commercial software, some webservices, some message queues, and a database. I want to recommend to use Spring for the backend, to deal with the different elements, and to expose some Rest services. I also want to recommend wicket for the front (not the point here). What i don't know is : must i install the front and the back on the same tomcat server or two different ? and i am tempted to put two servers for the front, with a load balancer (no need for session replication in this case). But if i have two front servers, must i have two back servers ? i don't want to create some kind of bottleneck. Based on what i read on this blog a really huge charge is handle by one tomcat only for the first website mentionned. But i cannot find any info on this, so i can't tell if it seems plausible. If you can enlight me, so i can go on in my case study, that would be really helpful. Thanks :)

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• Preferred way of application initialization

  - by lisak

  Do you guys have your own little framework for project startups ? I mean, every time one needs to do the same things at the beginning: Context initialization - ideally after arguments are processed. Sometimes without interactive user input, sometimes with input reader. Sometimes we need to load properties, sometimes not. Then we need to get a class out of context and run its method. Programming....programming until writing shell script to place everything on classpath. It's true that it differs according to the actual needs. But it seems to me, that I'm doing always almost the same, again and again from the scratch. Sometimes I realize that I'm postponing my work just because I don't want to do these annoying startups. It would be great if there was some kind of universal Main class doing reflection to specified bean, context initialization, argument parsing, interactive user input reading and have the programmer do the important things...All setup might be done via spring configuration. I think I'll have to do it by myself. I'd appreciate your ideas

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• How to specify a parameter as part of every web service call?

  - by LES2

  Currently, each web service for our application has a user parameter that is added for every method. For example: @WebService public interface FooWebService { @WebMethod public Foo getFoo(@WebParam(name="alwaysHere",header=true,partName="alwaysHere") String user, @WebParam(name="fooId") Long fooId); @WebMethod public Result deletetFoo(@WebParam(name="alwaysHere",header=true,partName="alwaysHere") String user, @WebParam(name="fooId") Long fooId); // ... } There could be twenty methods in a service, each with the first parameter as user. And there could be twenty web services. We don't actually use the 'user' argument in the implementations - in fact, I don't know why it's there - but I wasn't involved in the design, and the person that put it there had a reason (I hope). Anyway, I'm trying to straighten out this Big Ball of Mud. I have already come a long way by wrapping the web services by a Spring proxy, which allows me to do some before-and-after processing in an interceptor (before there were at least 20 lines of copy-pasted boiler plate per method). I'm wondering if there's some kind of "message header" I can apply to the method or package and that can be accessed by some type of handler or something outside of each web service method. Thanks in advance for the advice, LES

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• Foreign/accented characters in sql query

  - by FromCanada

  I'm using Java and Spring's JdbcTemplate class to build an SQL query in Java that queries a Postgres database. However, I'm having trouble executing queries that contain foreign/accented characters. For example the (trimmed) code: JdbcTemplate select = new JdbcTemplate( postgresDatabase ); String query = "SELECT id FROM province WHERE name = 'Ontario';"; Integer id = select.queryForObject( query, Integer.class ); will retrieve the province id, but if instead I did name = 'Québec' then the query fails to return any results (this value is in the database so the problem isn't that it's missing). I believe the source of the problem is that the database I am required to use has the default client encoding set to SQL_ASCII, which according to this prevents automatic character set conversions. (The Java environments encoding is set to 'UTF-8' while I'm told the database uses 'LATIN1' / 'ISO-8859-1') I was able to manually indicate the encoding when the resultSets contained values with foreign characters as a solution to a previous problem with a similar nature. Ex: String provinceName = new String ( resultSet.getBytes( "name" ), "ISO-8859-1" ); But now that the foreign characters are part of the query itself this approach hasn't been successful. (I suppose since the query has to be saved in a String before being executed anyway, breaking it down into bytes and then changing the encoding only muddles the characters further.) Is there a way around this without having to change the properties of the database or reconstruct it? PostScript: I found this function on StackOverflow when making up a title, it didn't seem to work (I might not have used it correctly, but even if it did work it doesn't seem like it could be the best solution.):

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• Saving owned/child objects in Hibernate

  - by maxdj

  I'm having a hard time wrapping my head around the way hibernate objects work. Here's a little chunk of what my model looks like: JobOpening: @ManyToMany(fetch=FetchType.EAGER,cascade=CascadeType.ALL) @JoinTable( name="jobOpening_questionSet", joinColumns=@JoinColumn(name="jobOpenings_id"), inverseJoinColumns=@JoinColumn(name="questionSets_id") ) @IndexColumn(name="question_sets_idx",base=0,nullable=false) public List<QuestionSet> getQuestionSets() { return questionSets; } QuestionSet: @ManyToMany(mappedBy="questionSets",fetch=FetchType.EAGER) public Set<JobOpening> getJobOpenings() { return jobOpenings; } @OneToMany(cascade=CascadeType.ALL,fetch=FetchType.EAGER) @IndexColumn(name="questions_idx",base=0) @JoinColumn(name="questionset_id",nullable=false) public List<FormQuestion> getQuestions() { return questions; } FormQuestion: @ManyToOne @JoinColumn(name="questionset_id", insertable=false, updatable=false, nullable=false) @OnDelete(action=OnDeleteAction.CASCADE) public QuestionSet getQuestionSet() { return questionSet; } Now how would I go about, say, modifying a question in the question set, or changing which jobs a questionset is associated with? For example, to edit a question in a questionset, I imagine I should be able to just get the question via its id, change some values, and merge() it back in, but this doesn't work. I'm using Hibernate from Spring (appfuse), usually as detached objects.

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• ContentNegotiatingViewResolver Issue

  - by Jay

  How to map a url of this kind "/myapp/sample" to map to the default MarshallingView instead of a JSTLView. @RequestMapping("/vets") public ModelMap vetsHandler() { Vets vets = new Vets(); vets.getVetList().addAll(this.clinic.getVets()); return new ModelMap(vets); } The above code works fine. When i tried to use http://.../vets.xml, I was able to download the xml. But, @RequestMapping("/myapp/vets") public ModelMap vetsHandler() { Vets vets = new Vets(); vets.getVetList().addAll(this.clinic.getVets()); return new ModelMap(vets); } doesn't resolve to the XML MarshalView, instead it resolves to JSTLView. Any thoughts? below is the spring v 3 configuration from the petclinic example, that i'm using. <bean id="vets" class="org.springframework.web.servlet.view.xml.MarshallingView"> <property name="contentType" value="application/vnd.springsource.samples.petclinic+xml"/> <property name="marshaller" ref="marshaller"/> </bean> <bean id="test" class="org.springframework.web.servlet.view.xml.MarshallingView"> <property name="contentType" value="application/vnd.springsource.samples.petclinic+xml"/> <property name="marshaller" ref="marshaller"/> </bean> <oxm:jaxb2-marshaller id="marshaller"> <oxm:class-to-be-bound name="org.springframework.samples.petclinic.Vets"/> <oxm:class-to-be-bound name="org.springframework.samples.petclinic.Test1"/> </oxm:jaxb2-marshaller>

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• Hibernate design to speed up querying of large dataset

  - by paddydub

  I currently have the below tables representing a bus network mapped in hibernate, accessed from a Spring MVC based bus route planner I'm trying to make my route planner application perform faster, I load all the above tables into Lists to perform the route planner logic. I would appreciate if anyone has any ideas of how to speed my performace Or any suggestions of another method to approach this problem of handling a large set of data Coordinate Connections Table (INT,INT,INT, DOUBLE)( Containing 50,000 Coordinate Connections) ID, FROMCOORDID, TOCOORDID, DISTANCE 1 1 2 0.383657 2 1 17 0.173201 3 1 63 0.258781 4 1 64 0.013726 5 1 65 0.459829 6 1 95 0.458769 Coordinate Table (INT,DECIMAL, DECIMAL) (Containing 4700 Coordinates) ID , LAT, LNG 0 59.352669 -7.264341 1 59.352669 -7.264341 2 59.350012 -7.260653 3 59.337585 -7.189798 4 59.339221 -7.193582 5 59.341408 -7.205888 Bus Stop Table (INT, INT, INT)(Containing 15000 Stops) StopID RouteID COORDINATEID 1000100001 100 17 1000100002 100 18 1000100003 100 19 1000100004 100 20 1000100005 100 21 1000100006 100 22 1000100007 100 23 This is how long it takes to load all the data from each table: stop.findAll = 148ms, stops.size: 15670 Hibernate: select coordinate0_.COORDINATEID as COORDINA1_2_, coordinate0_.LAT as LAT2_, coordinate0_.LNG as LNG2_ from COORDINATES coordinate0_ coord.findAll = 51ms , coordinates.size: 4704 Hibernate: select coordconne0_.COORDCONNECTIONID as COORDCON1_3_, coordconne0_.DISTANCE as DISTANCE3_, coordconne0_.FROMCOORDID as FROMCOOR3_3_, coordconne0_.TOCOORDID as TOCOORDID3_ from COORDCONNECTIONS coordconne0_ coordinateConnectionDao.findAll = 238ms ; coordConnectioninates.size:48132 Hibernate Annotations @Entity @Table(name = "STOPS") public class Stop implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "STOPID") private int stopID; @Column(name = "ROUTEID", nullable = false) private int routeID; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "COORDINATEID", nullable = false) private Coordinate coordinate; } @Table(name = "COORDINATES") public class Coordinate { @Id @GeneratedValue @Column(name = "COORDINATEID") private int CoordinateID; @Column(name = "LAT") private double latitude; @Column(name = "LNG") private double longitude; } @Entity @Table(name = "COORDCONNECTIONS") public class CoordConnection { @Id @GeneratedValue @Column(name = "COORDCONNECTIONID") private int CoordinateID; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "FROMCOORDID", nullable = false) private Coordinate fromCoordID; @ManyToOne(fetch = FetchType.LAZY) @JoinColumn(name = "TOCOORDID", nullable = false) private Coordinate toCoordID; @Column(name = "DISTANCE", nullable = false) private double distance; }

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• Servlet Mapping Help - Possible to Avoid Referencing Context Name?

  - by AJ

  Hi all, I am working on a Spring application and trying to get my URL mapping correct. What I would like to have work is the following: http://localhost:8080/idptest -> doesn't work But instead, I have to reference the context name in my URL in order to resolve the mapping: http://localhost:8080/<context_name>/idptest -> works How can I avoid the requirement of referencing the context name in my URL without using a rewrite/proxy engine e.g. Apache? Here is the servlet definition and mapping from my web.xml: <servlet> <servlet-name>idptest</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/conf/idptest.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>idptest</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> Here's the outline of my controller (showing annotations for request mappings): @Controller @RequestMapping("/idptest") public class MyController { @RequestMapping(method=RequestMethod.GET) public String setupForm(Model model){ MyObject someObject = new MyObject(); model.addAttribute("someObject", someObject); return "myform"; } @RequestMapping(method = RequestMethod.POST) public String processSubmit(@ModelAttribute("someObject") MyObject someObject) throws Exception { // POST logic... } } Thanks!

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