Search Results

Search found 2723 results on 109 pages for 'ssrs printing'.

Page 56/109 | < Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >

  • Error while printing crystal report, with that exception message "No printers are installed".

    - by Ahmed
    I got an exception with message "No printers are installed." while printing a report for depolyed release of our website. I use _rptDocument.PrintToPrinter(1, false, 0, 0); to print a report. I got that exception, even I've more than one printer installed on my machine. Also, I don't get that exception while development, everything while development is going fine. I used "Publish Web Site" and "Web Project Deployment" options to publish/deploy website, but I got the same result. Any suggestions?

    Read the article

  • Why doesn't sed's automatic printing deliver the expected results?

    - by CodeGnome
    What Works This sed script works as intended: $ echo -e "2\n1\n4\n3" | sed -n 'h; n; G; p' 1 2 3 4 It takes pair of input lines at a time, and swaps the lines. So far, so good. What Doesn't Work What I don't understand is why I can't use sed's automatic printing. Since sed automatically prints the pattern space at the end of each execution cycle (except when it's suppressed), why is this not equivalent? $ echo -e "2\n1\n4\n3" | sed 'h; n; G' 2 1 2 4 3 4 What I think the code says is: The input line is copied to the hold space. The next line is read into the pattern space. The hold space is appended to the pattern space. The pattern space (line1 + newline + line2) is printed automatically because we've reached the end of the execution cycle. Obviously, I'm wrong...but I don't understand why. Can anyone explain why this second example breaks, and why print suppression is needed to yield the correct results?

    Read the article

  • Enabling printing feature within the Terminal Server environment that is published to the internet?

    - by Albert Widjaja
    I got the home and remote office users connect to the Terminal Server on my Windows Server 2003 that I published securely through Juniper SSL VPN client applet, they use normal internet connection to access the link which pop up the Terminal Server Remote Desktop application, so my question is, how can they print out the document from within their terminal server session ? if it is going through the internal office LAN mapping the printer through Remote Desktop connection is the solution but not for this one. Any kind of help and suggestion would be greatly appreciated. Thanks

    Read the article

  • How to create or save a PDF with printing/editing restrictions without using Adobe?

    - by suit
    I saved a Powerpoint as a pdf in Office 2007 but I don't see any options to add print restrictions or edit restrictions to it. I don't have Adobe either, so I'm wondering if there is any alternative way to add restrictions to a pdf. I know there are tools to remove document restrictions, but can they do they opposite? Is there any freeware or websites available that can add restrictions to my pdf I created? I found a website that looked promising but it didn't end up working (The upload didn't work).

    Read the article

  • SQL Server Reporting Services proxy timeout (ASP.NET)

    - by Philip
    Morning, We are using SSRS (2005) and have a ASP.NET frontend using the SSRS WebControl. I've boiled the problem down the time it takes for one particular report to be generated is greater than the timeout on the proxy server. It looks like the way the SSRS web control tries to do things is by performing an HTTP request for the report, however the problem with this is the request can timeout potentially before the report has generated. Looking at the HTTP traffic the response is a 504 (gateway timeout). Is there a way to increase the timeout or change SSRS WebControl to use more robust polling mechanism (which isn't dependant on the timeout of the HTTP request). I could be wrong but I don't think ServerReport.Timeout property would resolve the issue we are seeing? Any thoughts? Philip

    Read the article

  • SSRS How to access the current value within a list control?

    - by Dale Burrell
    In SQL Server Reporting Services I have a report which has a list control which groups on currency. Within the list control I display the detailed rows of all records filtered to those with a value = £500. i.e. the top earners. However for each row I need to calculate the percentage of its amount over the total of the entire dataset. Because I am filtering it I can't use Sum(Fields!Amount.Value) as that only sums the data after filtering, so I am trying a conditional sum over the entire dataset, but am struggling with the correct condition e.g =100.00*Fields!Amount.Value/Sum((IIf(Fields!Currency.Value = "£", Fields!Amount.Value, CDec(0))),"DataSet") So where the hardcoded currency symbol is I need to access the current value of currency for the list control, but because my sum is scoped at dataset level any field access is dataset level. Ideally I'd like something like the following, otherwise any other ideas on how to solve this problem. =100.00*Fields!Amount.Value/Sum((IIf(Fields!Currency.Value = myListControl.Value, Fields!Amount.Value, CDec(0))),"DataSet") In fact, thinking about it, it would work if I just could access the row level data at that point, but how to do that when its at dataset scope within the sum statement? Hope that makes sense, any help appreciated.

    Read the article

  • How do I group a SSRS report by month?

    - by Anthony K
    I have a set of data that includes a field with the datetime that events happen. i want to group the events by month. I haven't come across a simple and elegant expression to achieve this. So far all I can come up with is to convert the field to a date, then take the year and month as integers and then convert this back to a string with the day set to 1. In Crystal Reports I would group on the datetime field and then set the period to month, very easy. I am sure there is an easy answer to this that I haven't been able to find.

    Read the article

  • Silverlight Cream for May 18, 2010 -- #864

    - by Dave Campbell
    In this Issue: Jesse Liberty, Chris Koenig, Kyle McClellan, Kunal Chowdhury(-2-), Tim Heuer, and Jonathan van de Veen. Shoutout: René Schulte has posted a SLARToolkit Beginner's Guide Erik Mork and the Sparkling Podcast crew posted Silverlight Week – Silverlight Android? John Papa opens up a dialog: Ask the Experts on Silverlight TV ... get your questions answered! From SilverlightCream.com: Windows Phone 7 For Silverlight Programmers Jesse Liberty's starting a series on WP7, so you obviously don't want to miss this... source, commentary, external links, how-to's... what more could you ask for?? WP7 Part 3: Navigation Chris Koenig is revamping his WP7 application to use Community Megaphone instead of Nerd Dinner and in this episode 3 he's looking into Navigation ... definitely good stuff here. RIA Services Authentication Out-Of-Browser Kyle McClellan has code up demonstrating how to get around the fact that the Browser networking stack handles cookies differently than the client networking stack used OOB, and achieve forms authentication OOB. How to work with the Silverlight BusyIndicator? Kunal Chowdhury has a post up talking about the busy indicator and how to use it to show an active indicator while disabling other content. Drag and Drop Operation in Silverlight ListBox In a second entry, Kunal Chowdhury has a nice long post displaying drag-and-drop within and between ListBox controls. Silverlight 4 Tools, WCF RIA Services and Themes Released As usual, Tim Heuer has a great post up about the new releases not only for those with 'clean' machines, but also instructions for those that have been playing along. Advanced printing in Silverlight 4 Just after a post on printing yesterday, Jonathan van de Veen has a post up at SilverlightShow on printing as well, and is demonstrating fitting the text to the page and printing multiple pages. Stay in the 'Light! Twitter SilverlightNews | Twitter WynApse | WynApse.com | Tagged Posts | SilverlightCream Join me @ SilverlightCream | Phoenix Silverlight User Group Technorati Tags: Silverlight    Silverlight 3    Silverlight 4    Windows Phone MIX10

    Read the article

  • Why does fprintf start printing out of order or not at all?

    - by Steve Melvin
    This code should take an integer, create pipes, spawn two children, wait until they are dead, and start all over again. However, around the third time around the loop I lose my prompt to enter a number and it no longer prints the number I've entered. Any ideas? #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <errno.h> #define WRITE 1 #define READ 0 int main (int argc, const char * argv[]) { //Pipe file-descriptor array unsigned int isChildA = 0; int pipeA[2]; int pipeB[2]; int num = 0; while(1){ fprintf(stderr,"Enter an integer: "); scanf("%i", &num); if(num == 0){ fprintf(stderr,"You entered zero, exiting...\n"); exit(0); } //Open Pipes if(pipe(pipeA) < 0){ fprintf(stderr,"Could not create pipe A.\n"); exit(1); } if(pipe(pipeB) < 0){ fprintf(stderr,"Could not create pipe B.\n"); exit(1); } fprintf(stderr,"Value read: %i \n", num); fprintf(stderr,"Parent PID: %i\n", getpid()); pid_t procID = fork(); switch (procID) { case -1: fprintf(stderr,"Fork error, quitting...\n"); exit(1); break; case 0: isChildA = 1; break; default: procID = fork(); if (procID<0) { fprintf(stderr,"Fork error, quitting...\n"); exit(1); } else if(procID == 0){ isChildA = 0; } else { write(pipeA[WRITE], &num, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); pid_t pid; while (pid = waitpid(-1, NULL, 0)) { if (errno == ECHILD) { break; } } } break; } if (procID == 0) { //We're a child, do kid-stuff. ssize_t bytesRead = 0; int response; while (1) { while (bytesRead == 0) { bytesRead = read((isChildA?pipeA[READ]:pipeB[READ]), &response, sizeof(int)); } if (response < 2) { //Kill other child and self fprintf(stderr, "Terminating PROCID: %i\n", getpid()); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); return 0; } else if(!(response%2)){ //Even response/=2; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } else { //Odd response*=3; response++; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } } } } return 0; } This is the output I am getting... bash-3.00$ ./proj2 Enter an integer: 101 Value read: 101 Parent PID: 9379 PROCID: 9380, VALUE: 304 PROCID: 9381, VALUE: 152 PROCID: 9380, VALUE: 76 PROCID: 9381, VALUE: 38 PROCID: 9380, VALUE: 19 PROCID: 9381, VALUE: 58 PROCID: 9380, VALUE: 29 PROCID: 9381, VALUE: 88 PROCID: 9380, VALUE: 44 PROCID: 9381, VALUE: 22 PROCID: 9380, VALUE: 11 PROCID: 9381, VALUE: 34 PROCID: 9380, VALUE: 17 PROCID: 9381, VALUE: 52 PROCID: 9380, VALUE: 26 PROCID: 9381, VALUE: 13 PROCID: 9380, VALUE: 40 PROCID: 9381, VALUE: 20 PROCID: 9380, VALUE: 10 PROCID: 9381, VALUE: 5 PROCID: 9380, VALUE: 16 PROCID: 9381, VALUE: 8 PROCID: 9380, VALUE: 4 PROCID: 9381, VALUE: 2 PROCID: 9380, VALUE: 1 Terminating PROCID: 9381 Terminating PROCID: 9380 Enter an integer: 102 Value read: 102 Parent PID: 9379 PROCID: 9386, VALUE: 51 PROCID: 9387, VALUE: 154 PROCID: 9386, VALUE: 77 PROCID: 9387, VALUE: 232 PROCID: 9386, VALUE: 116 PROCID: 9387, VALUE: 58 PROCID: 9386, VALUE: 29 PROCID: 9387, VALUE: 88 PROCID: 9386, VALUE: 44 PROCID: 9387, VALUE: 22 PROCID: 9386, VALUE: 11 PROCID: 9387, VALUE: 34 PROCID: 9386, VALUE: 17 PROCID: 9387, VALUE: 52 PROCID: 9386, VALUE: 26 PROCID: 9387, VALUE: 13 PROCID: 9386, VALUE: 40 PROCID: 9387, VALUE: 20 PROCID: 9386, VALUE: 10 PROCID: 9387, VALUE: 5 PROCID: 9386, VALUE: 16 PROCID: 9387, VALUE: 8 PROCID: 9386, VALUE: 4 PROCID: 9387, VALUE: 2 PROCID: 9386, VALUE: 1 Terminating PROCID: 9387 Terminating PROCID: 9386 Enter an integer: 104 Value read: 104 Parent PID: 9379 Enter an integer: PROCID: 9388, VALUE: 52 PROCID: 9389, VALUE: 26 PROCID: 9388, VALUE: 13 PROCID: 9389, VALUE: 40 PROCID: 9388, VALUE: 20 PROCID: 9389, VALUE: 10 PROCID: 9388, VALUE: 5 PROCID: 9389, VALUE: 16 PROCID: 9388, VALUE: 8 PROCID: 9389, VALUE: 4 PROCID: 9388, VALUE: 2 PROCID: 9389, VALUE: 1 Terminating PROCID: 9388 Terminating PROCID: 9389 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9395, VALUE: 316 PROCID: 9396, VALUE: 158 PROCID: 9395, VALUE: 79 PROCID: 9396, VALUE: 238 PROCID: 9395, VALUE: 119 PROCID: 9396, VALUE: 358 PROCID: 9395, VALUE: 179 PROCID: 9396, VALUE: 538 PROCID: 9395, VALUE: 269 PROCID: 9396, VALUE: 808 PROCID: 9395, VALUE: 404 PROCID: 9396, VALUE: 202 PROCID: 9395, VALUE: 101 PROCID: 9396, VALUE: 304 PROCID: 9395, VALUE: 152 PROCID: 9396, VALUE: 76 PROCID: 9395, VALUE: 38 PROCID: 9396, VALUE: 19 PROCID: 9395, VALUE: 58 PROCID: 9396, VALUE: 29 PROCID: 9395, VALUE: 88 PROCID: 9396, VALUE: 44 PROCID: 9395, VALUE: 22 PROCID: 9396, VALUE: 11 PROCID: 9395, VALUE: 34 PROCID: 9396, VALUE: 17 PROCID: 9395, VALUE: 52 PROCID: 9396, VALUE: 26 PROCID: 9395, VALUE: 13 PROCID: 9396, VALUE: 40 PROCID: 9395, VALUE: 20 PROCID: 9396, VALUE: 10 PROCID: 9395, VALUE: 5 PROCID: 9396, VALUE: 16 PROCID: 9395, VALUE: 8 PROCID: 9396, VALUE: 4 PROCID: 9395, VALUE: 2 PROCID: 9396, VALUE: 1 Terminating PROCID: 9395 Terminating PROCID: 9396 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9397, VALUE: 316 PROCID: 9398, VALUE: 158 PROCID: 9397, VALUE: 79 PROCID: 9398, VALUE: 238 PROCID: 9397, VALUE: 119 PROCID: 9398, VALUE: 358 PROCID: 9397, VALUE: 179 PROCID: 9398, VALUE: 538 PROCID: 9397, VALUE: 269 PROCID: 9398, VALUE: 808 PROCID: 9397, VALUE: 404 PROCID: 9398, VALUE: 202 PROCID: 9397, VALUE: 101 PROCID: 9398, VALUE: 304 PROCID: 9397, VALUE: 152 PROCID: 9398, VALUE: 76 PROCID: 9397, VALUE: 38 PROCID: 9398, VALUE: 19 PROCID: 9397, VALUE: 58 PROCID: 9398, VALUE: 29 PROCID: 9397, VALUE: 88 PROCID: 9398, VALUE: 44 PROCID: 9397, VALUE: 22 PROCID: 9398, VALUE: 11 PROCID: 9397, VALUE: 34 PROCID: 9398, VALUE: 17 PROCID: 9397, VALUE: 52 PROCID: 9398, VALUE: 26 PROCID: 9397, VALUE: 13 PROCID: 9398, VALUE: 40 PROCID: 9397, VALUE: 20 PROCID: 9398, VALUE: 10 PROCID: 9397, VALUE: 5 PROCID: 9398, VALUE: 16 PROCID: 9397, VALUE: 8 PROCID: 9398, VALUE: 4 PROCID: 9397, VALUE: 2 PROCID: 9398, VALUE: 1 Terminating PROCID: 9397 Terminating PROCID: 9398 106 Value read: 106 Parent PID: 9379 Enter an integer: PROCID: 9399, VALUE: 53 PROCID: 9400, VALUE: 160 PROCID: 9399, VALUE: 80 PROCID: 9400, VALUE: 40 PROCID: 9399, VALUE: 20 PROCID: 9400, VALUE: 10 PROCID: 9399, VALUE: 5 PROCID: 9400, VALUE: 16 PROCID: 9399, VALUE: 8 PROCID: 9400, VALUE: 4 PROCID: 9399, VALUE: 2 PROCID: 9400, VALUE: 1 Terminating PROCID: 9399 Terminating PROCID: 9400 ^C Another thing that's strange, when ran from within XCode it behaves normally. However, when ran from bash on Solaris or OSX it acts up.

    Read the article

  • How do we group in BIRT without wasting lines, and still only printing the group item on the first l

    - by paxdiablo
    When grouping in BIRT, we frequently want the grouping value to show up on the first line as follows: Group User Reputation ------ --------------- ---------- Admins Bill The Weasel 51,018 Mark Grovel 118,101 Users pax_my_bags 73,554 Jon Scoot **,***,*** <- overflow clueless 92,928 The normal way of acheiving this is to lay out the group in the designer as follws: +---------+--------+--------------+ Tbl Hdr | Group | User | Reputation | +---------+--------+--------------+ Grp Hdr | [Group] | | | +---------+--------+--------------+ Grp Dtl | | [User] | [Reputation] | +---------+--------+--------------+ Grp Ftr | | | | +---------+--------+--------------+ Tbl Ftr | | | | +---------+--------+--------------+ which, unfortunately, lays out the data in exactly that way, with the grouped value on a different line: Group User Reputation ------ --------------- ---------- Admins Bill The Weasel 51,018 Mark Grovel 118,101 Users pax_my_bags 73,554 Jon Scoot **,***,*** <- overflow clueless 92,928 This is particularly painful with data where there's lots of groups with only one user since we use twice as much space as needed. If we move the [Group] data item down to the Grp Dtl line, we get it printed for every line in the group. How, in BIRT, do we merge the two lines Grp Hdr and the first Grp Dtl?

    Read the article

  • How can I change the precision of printing with the stl?

    - by mmr
    This might be a repeat, but my google-fu failed to find it. I want to print numbers to a file using the stl with the number of decimal places, rather than overall precision. So, if I do this: int precision = 16; std::vector<double> thePoint(3); thePoint[0] = 86.3671436; thePoint[0] = -334.8866574; thePoint[0] = 24.2814; ofstream file1(tempFileName, ios::trunc); file1 << std::setprecision(precision) << thePoint[0] << "\\" << thePoint[1] << "\\" << thePoint[2] << "\\"; I'll get numbers like this: 86.36714359999999\-334.8866574\24.28140258789063 What I want is this: 86.37\-334.89\24.28 In other words, truncating at two decimal points. If I set precision to be 4, then I'll get 86.37\-334.9\24.28 ie, the second number is improperly truncated. I do not want to have to manipulate each number explicitly to get the truncation, especially because I seem to be getting the occasional 9 repeating or 0000000001 or something like that that's left behind. I'm sure there's something obvious, like using the printf(%.2f) or something like that, but I'm unsure how to mix that with the stl << and ofstream.

    Read the article

  • CGI Perl script is printing the HTML (along with 'content-type: text/html') string to the browser ra

    - by Wikidkaka
    I have a perl CGI script that needs to send back some HTML print qq^Content-type: text/html\n\n <HTML> <HEAD> <TITLE>some title</TITLE> ... ... ... ... ^: Instead of seeing the rendered HTML in the browser, I see the entire HTML along with the tags and the 'content-type' line in plain text. Below is how things look in the browser - Content-type: text/html <HTML> <HEAD> <TITLE>some title</TITLE> </HEAD> <BODY BGCOLOR="#FFFFFF" TEXT="#000000" LINK="#000000" VLINK="#000000" ALINK="#000000" BACKGROUND="" onLoad=document.forms[0].elements[0].focus();>

    Read the article

  • Printing an array in a method, from a different class?

    - by O.Lodhi
    Hello All, I'm a fairly inexperienced programmer, and i'm currently working on a Console Application project. It's basically a little 'mathematics game'; the application generates two random numbers, that have either been added, subtracted, multiplied or divided against each other randomly. The answer is shown on screen and the user has to pick from the menu which is the right mathematical operator, once the correct answer is picked the application then displays on screen how long it took for the user in milliseconds to input the correct answer. Now I want to save the times of the players in an array that can be called up later with all the scores. I need to include a method in this programme and I figured a method to save the times into an array would be suitable. I seem to have stumbled across a little problem though. I'm not quite sure what's wrong: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace Mathgame { class Program { } class arrayclass { public static void saveInArray(int duration) { int[] TopTenScores = {000,1000,2000,3000,4000,5000,6000,7000,8000,9000}; if (duration < 1000) { duration = TopTenScores[000]; } else if ((duration >= 1000) && (duration <= 1999)) { duration = TopTenScores[1000]; } else if ((duration >= 2000) && (duration <= 2999)) { duration = TopTenScores[2000]; } else if ((duration >= 3000) && (duration <= 3999)) { duration = TopTenScores[3000]; } else if ((duration >= 4000) && (duration <= 4999)) { duration = TopTenScores[4000]; } else if ((duration >= 5000) && (duration <= 5999)) { duration = TopTenScores[5000]; } else if ((duration >= 6000) && (duration <= 6999)) { duration = TopTenScores[6000]; } else if ((duration >= 7000) && (duration <= 7999)) { duration = TopTenScores[7000]; } else if ((duration >= 8000) && (duration <= 8999)) { duration = TopTenScores[8000]; } else if ((duration >= 9000) && (duration <= 9999)) { duration = TopTenScores[9000]; } Console.WriteLine(TopTenScores); } static void Main(string[] args) { int intInput, num1, num2, incorrect, array1; float answer; string input; System.Random randNum = new System.Random(); Console.WriteLine("Welcome to the Maths game!"); Console.WriteLine("(Apologies for the glitchiness!)"); Console.WriteLine(); Console.WriteLine("Please choose from the following options:"); Console.WriteLine(); retry: Console.WriteLine("1 - Test your Maths against the clock!"); Console.WriteLine("2 - Exit the application."); Console.WriteLine("3 - Top scores"); Console.WriteLine(); input = Console.ReadLine(); intInput = int.Parse(input); if (intInput == 1) { goto start; } else if (intInput == 2) { goto fin; } else if (intInput == 3) { array1 = array1.saveInArray; goto retry; } Now, in the last 'else if' statement in the code, you can see my variable array1 trying to call the method, but no matter what I do I keep getting errors. This is the only error I have at the moment, but I have a feeling soon as I resolve that error, another will come up. For now i'm just determined to get past this error: 'int' does not contain a definition for 'saveInArray' and no extension method 'saveInArray' accepting a first argument of type 'int' could be found (are you missing a using directive or an assembly reference?). Any help would be kindly appreciated, apologies in advanced for my ugly written code! And thank you to any help that I receive! Regards, Omar.

    Read the article

  • Drupal 6: Printing Unadulterated Primary Links and all children...

    - by dcolumbus
    How in the WORLD is possible? I swear, I've read the equivalent of 3 encyclopedias to no avail. I've tried solutions within regions, page.tpl.php and blocks. None of them give me what I need... and I know there are so many other people that need this too! I've come to the conclusion that I want to print out the menu within my page.tpl.php ... so no block solutions, please. I want to be able to loop through the primary menu links (AND children) and rewrite the output so that there's no default Drupal class tagging. The closest I've found is this example: <?php if (is_array($primary_links)) : ?> <ul id="sliding-navigation"> <?php foreach ($primary_links as $link): ?> <li class="sliding-element"><?php $href = $link['href'] == "<front>" ? base_path() : base_path() . drupal_get_path_alias($link['href']); print "<a href='" . $href . "'>" . $link['title'] . "</a>"; ?></li> <?php endforeach; ?> </ul> <?php endif; ?> As you can see, links are being reprinted with a custom UL and LI class ... that's GREAT! However, no children are being printed. How would I extend this code so that all children are a part of the list? NOTE: I don't want the children to only appear on their parent page, they must be present all the time. Otherwise, the drop-down menu I have planned is useless. I sincerely thank you in advance to lessening my gargantuan headache!

    Read the article

  • Why is my program printing out the null termination character?

    - by Tyler Pfaff
    When I run this, it will SOMETIMES print out a null termination character. Most of the time it will, and probably 1/5 times it will print just the characters. void cryptogram::Encrypt(){ cout<<"encrypt"<tempS){ len=tempS.length(); int a=0; for(int j=0;j if(j!=len){ //if the word still has more characters j++; a=0; }else{ //if the word is done being scanned cout<<" "; } } } } } } } So that's it and this is the corresponding EXPECTED output that is printed SOMETIMES xvk bkikhxlr wggbtfkj wiylekgbdhx wjjm hko wigbtubxt xvk iwhj uedjkm glctb gvrmdiwhj iebbdielmeggtbx ctb xvtmk gbtubxvk wjjdxdthgbtubodll khvxvk imkbfdik xt xvk bkudth whj gbtfdjk hko tgxdthm whj tggtbxehdxdkm ctb mxejkhxmibdzdhtltur whj pemxdik mxejdkm mxdh cok wbk wlmt gbkgctb cteb hko zdh cgvrmdikjeiwhj qdhkmdtlturzzkjdydtivkzdmxbrw zdh zdjjlkkjeiwhj w jtixtbdh kjeiwjzdhdmxbittgkbodxv mjme whj eimj This is what normally prints though xvkÈ bkikhxlrÈ wggbtfkjÈ wiylekgbdhxÈ wjjmÈ hkoÈ wigbtubxtÈ xvkÈ iwhjÈ uedjkmÈ glctbÈ gvrmdiwhjÈ iebbdielmeggtbxÈ ctbÈ xvtmkÈ gbtubxvkÈ wjjdxdthgbtubodllÈ khvxvkÈ imkbfdikÈ xtÈ xvkÈ bkudthÈ whjÈ gbtfdjkÈ hkoÈ tgxdthmÈ whjÈ tggtbxehdxdkmÈ ctbÈ mxejkhxmibdzdhtlturÈ whjÈ pemxdikÈ mxejdkmÈ mxdhÈ cokÈ wbkÈ wlmtÈ gbkgctbÈ ctebÈ hkoÈ zdhÈ cgvrmdikjeiwhjÈ qdhkmdtlturzzkjdydtivkzdmxbrwÈ zdhÈ zdjjlkkjeiwhjÈ wÈ jtixtbdhÈ kjeiwjzdhdmxbittgkbodxvÈ mjmeÈ whjÈ eimj or some variation of an odd character at the end of each word This is what the cryptogram array is filled with by the way wyijkcuvdpqlzhtgabmxefonrs

    Read the article

  • Why is my code not printing anything to stdout?

    - by WM
    I'm trying to calculate the average of a student's marks: import java.util.Scanner; public class Average { public static void main(String[] args) { int mark; int countTotal = 0; // to count the number of entered marks int avg = 0; // to calculate the total average Scanner Scan = new Scanner(System.in); System.out.print("Enter your average: "); String Name = Scan.next(); while (Scan.hasNextInt()) { mark = Scan.nextInt(); countTotal++; avg = avg + ((mark - avg) / countTotal); } System.out.print( Name + " " + avg ); } }

    Read the article

  • How do you prevent Git from printing 'remote:' on each line of the output of a post-recieve hook?

    - by Matt Hodan
    I recently configured an EC2 instance with a Git deployment workflow that resembles Heroku, but I can't seem to figure out how Heroku prevents the Git post-receive hook from outputting 'remote:' on each line. Consider the following two examples (one from my EC2 project and one from a Heroku project): My EC2 project: git push prod master Counting objects: 9, done. Delta compression using up to 2 threads. Compressing objects: 100% (5/5), done. Writing objects: 100% (5/5), 456 bytes, done. Total 5 (delta 3), reused 0 (delta 0) remote: remote: Receiving push remote: Deploying updated files (by resetting HEAD) remote: HEAD is now at bf17da8 test commit remote: Running bundler to install gem dependencies remote: Fetching source index for http://rubygems.org/ remote: Installing rake (0.8.7) remote: Installing abstract (1.0.0) ... remote: Installing railties (3.0.0) remote: Installing rails (3.0.0) remote: Your bundle is complete! It was installed into ./.bundle/gems remote: Launching (by restarting Passenger)... done remote: To ssh://[email protected]/~/apps/app_name e8bd06f..bf17da8 master -> master Heroku: $> git push heroku master Counting objects: 179, done. Delta compression using up to 2 threads. Compressing objects: 100% (89/89), done. Writing objects: 100% (105/105), 42.70 KiB, done. Total 105 (delta 53), reused 0 (delta 0) -----> Heroku receiving push -----> Rails app detected -----> Gemfile detected, running Bundler version 1.0.3 Unresolved dependencies detected; Installing... Using --without development:test Fetching source index for http://rubygems.org/ Installing rake (0.8.7) Installing abstract (1.0.0) ... Installing railties (3.0.0) Installing rails (3.0.0) Your bundle is complete! It was installed into ./.bundle/gems Compiled slug size is 4.8MB -----> Launching... done http://your_app_name.heroku.com deployed to Heroku To [email protected]:your_app_name.git 3bf6e8d..642f01a master -> master

    Read the article

  • printing menu in terminal and choosing an option, how to?

    - by carlos
    I'm a haskell beginner. I'm trying to make a program that shows a menu through terminal and ask user to introduce an option. Here is the code: main :: IO () main = do putStrLn "0 <- quit" putStrLn "1 <- Hello" putStr "Choose an option: " c <- getChar case c of '0' -> return () '1' -> putChar '\n' >> putStrLn "Hello World" >> main When I use this module in the ghci interpreter everything works like it's suposed to do. But if i compile this with: ghc hello.hs and run it in the terminal, it doesn't display the line "Choose an option:" before ask for a char to be introduced. I think this may be caused because of haskell lazy nature and I don't know how to fix it. Any ideas?

    Read the article

  • Printf is not printing anything to output? C++ SDL

    - by Qasim
    I am trying to use "printf" in my Visual C++ project however it is not working. Using Lazy Foo's tutorial, I set up SDL in my project, but when I play it, printf doesnt do anything. #include "SDL.h" #include <stdio.h> int main( int argc, char* args[] ) { printf("Testing"); return 0; } The output looks like this: The program '[4664] SDL Testing.exe: Native' has exited with code 0 (0x0). And that's about it. What could be wrong?

    Read the article

  • Errors not printing correctly..Is this logic flow correct? c++

    - by igor
    Example user input: PA1 9 //correct PJ1 9 //wrong, error printed "Invalid row" because it is not between A and I PA11 9 //wrong, error printer "Invalid column" because it is not between 1 and 9. The problem I am having is that it should clear the remaining input and then ask for the user to enter the "move" again, and it is not. Where did I go wrong? I've been at it for a while and still got no progress.. void clearInput() { cin.clear(); } bool getCoords(int & x, int & y) { char row; while(true){ cin>>row>>y; row=toupper(row); if(/*(id=='P' || id=='p' || id=='D' || id=='d') && */row>='A' && row<='I' && isalpha(row) && y>=1 && y<=9){ x=row-'A'; y=y-1; return true; } else if(!(y>=1 && y<=9)){ cout<<"Invalid column\n"<< endl << endl; cout<<y; clearInput(); cout<<y; //return false; } else{ cout<<"Invalid row\n"<< endl << endl; clearInput(); //cout<<x<<y; //return false; } } }

    Read the article

< Previous Page | 52 53 54 55 56 57 58 59 60 61 62 63  | Next Page >