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• How to properly add newlines to an XML string in PHP?

  - by stormist

  I have some xml that I manually construct in a function that is something like: $xml = "<myxml>"; $xml .= "<items>"; $xml .= "<item1>blah</item1>"; $xml .= "</items>"; $xml .= "</myxml>"; When I output the string though I'd like the newlines to be present. How can I add this to the string without affecting a web service accepting the xml? Do newlines in XML even matter?

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• How to change or remove all traces of original author name in Excel 2010 document

  - by Adam Ryczkowski

  At our company we need to deploy one Excel Workbook in that way that nobody would see it is made by us by looking at the Office metadata. What fields do we need to look for? I know, that the document has track of original writer and the last save author. But is it all? I guess there might be some hidden properties, that might give our company name. Where to look for such fields? Is there any good editor available, or will explorer's property page give enough power? I use Excel 2010

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• XML-RPC over SSL with Ruby: end of file reached (EOFError)

  - by Michael Conigliaro

  Hello, I have some very simple Ruby code that is attempting to do XML-RPC over SSL: require 'xmlrpc/client' require 'pp' server = XMLRPC::Client.new2("https://%s:%d/" % [ 'api.ultradns.net', 8755 ]) pp server.call2('UDNS_OpenConnection', 'sponsor', 'username', 'password') The problem is that it always results in the following EOFError exception: /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/net/protocol.rb:135:in `sysread': end of file reached (EOFError) So it appears that after doing the POST, I don't get anything back. Interestingly, this is the behavior I would expect if I tried to make an HTTP connection on the HTTPS port (or visa versa), and I actually do get the same exact exception if I change the protocol. Everything I've looked at indicates that using "https://" in the URL is enough to enable SSL, but I'm starting wonder if I've missed something. Note that Even though the credentials I'm using in the RPC are made up, I'm expecting to at least get back an XML error page (similar to if you access https://api.ultradns.net:8755/ with a web browser). I've tried running this code on OSX and Linux with the exact same result, so I have to conclude that I'm just doing something wrong here. Does anyone have any examples of doing XML-RPC over SSL with Ruby?

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• Parsing XML in C# from stream

  - by Phillip

  I've tried several methods, from Linq to loading the data to an XML document, but i can't seem to be able to return the result that i need. here's the example XML: <serv:message xmlns:serv="http://www.webex.com/schemas/2002/06/service" xmlns:com="http://www.webex.com/schemas/2002/06/common" xmlns:event="http://www.webex.com/schemas/2002/06/service/event"><serv:header><serv:response><serv:result>SUCCESS</serv:result><serv:gsbStatus>PRIMARY</serv:gsbStatus></serv:response></serv:header><serv:body><serv:bodyContent xsi:type="event:createEventResponse" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"><event:sessionKey>11111111</event:sessionKey><event:guestToken>111111111111111111111</event:guestToken></serv:bodyContent></serv:body></serv:message> And, here's what i've tried to do: StreamReader reader = new StreamReader(dataStream); XmlDocument doc = new XmlDocument(); doc.LoadXml(reader.ReadToEnd()); XmlNamespaceManager ns = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns2 = new XmlNamespaceManager(doc.NameTable); XmlNamespaceManager ns3 = new XmlNamespaceManager(doc.NameTable); ns.AddNamespace("serv", "http://www.webex.com/schemas/2002/06/service"); ns2.AddNamespace("com", "http://www.webex.com/schemas/2002/06/common"); ns3.AddNamespace("event", "http://www.webex.com/schemas/2002/06/service/event"); XmlNode node = doc.SelectSingleNode("result",ns); Yet, for some reason i cannot ever seem to return the actual result, which should be either 'SUCCESS' or 'FAILURE' based on the actual xml above. How can i do this?

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• Duplicate elements when adding XElement to XDocument

  - by Andy

  I'm writing a program in C# that will go through a bunch of config.xml files and update certain elements, or add them if they don't exist. I have the portion down that updates an element if it exists with this code: XDocument xdoc = XDocument.Parse(ReadFile(_file)); XElement element = xdoc.Elements("project").Elements("logRotator") .Elements("daysToKeep").Single(); element.Value = _DoRevert; But I'm running into issues when I want to add an element that doesn't exist. Most of the time part of the tree is in place and when I use my code it adds another identical tree, and that causes the program reading the xml to blow up. here is how I am attempting to do it xdoc.Element("project").Add(new XElement("logRotator", new XElement("daysToKeep", _day))); and that results in a structure like this(The numToKeep tag was already there): <project> <logRotator> <daysToKeep>10</daysToKeep> </logRotator> <logRotator> <numToKeep>13</numToKeep> </logRotator> </project> but this is what I want <project> <logRotator> <daysToKeep>10</daysToKeep> <numToKeep>13</numToKeep> </logRotator> </project>

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• Android - Loop Through strings.xml file

  - by Alexis Cartier

  I was wondering if there is anyway to loop through the strings.xml file. Let's say that I have the following format: <!-- FIRST SECTION --> <string name="change_password">Change Password</string> <string name="change_server">Change URL</string> <string name="default_password">password</string> <string name="default_server">http://xxx:8080</string> <string name="default_username">testPhoneAccount</string> <!-- SECOND SECTION --> <string name="debug_settings_category">Debug Settings</string> <string name="reload_data_every_startup_pref">reload_data_every_startup</string> <string name="reload_data_on_first_startup_pref">reload_data_on_first_startup</string> Now let's say I have this: private HashMap<String,Integer> hashmapStringValues = new HashMap<String, Integer>(); Is there a way to iterate only in the second section of my xml file? Maybe wrap the section with a tag like <section2> and then iterate through it? public void initHashMap(){ for (int i=0;i< ???? ;i++) //Here I need to loop only in the second section of my xml file { String nameOfTag = ? // Here I get the name of the tag int value = R.string.nameOfTag // Here I get the associated value of the tag this.hashmapStringValues.put(nameOfTag,value); } }

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• Choose a XML node in SQL Server based on max value of a child element

  - by Jay

  I am trying to select from SQL Server 2005 XML datatype some values based on the max data that is located in a child node. I have multiple rows with XML similar to the following stored in a field in SQL Server: <user> <name>Joe</name> <token> <id>ABC123</id> <endDate>2013-06-16 18:48:50.111</endDate> </token> <token> <id>XYX456</id> <endDate>2014-01-01 18:48:50.111</endDate> </token> </user> I want to perform a select from this XML column where it determines the max date within the token element and would return the datarows similar to the result below for each record: Joe XYZ456 2014-01-01 18:48:50.111 I have tried to find a max function for xpath that would all me to select the correct token element but I couldn't find one that would work. I also tried to use the SQL MAX function but I wasn't able to get it working with that method either. If I only have a single token it of course works fine but when I have more than one I get a NULL, most likely because the query doesn't know which date to pull. I was hoping there would be a way to specify a where clause [max(endDate)] on the token element but haven't found a way to do that. Here is an example of the one that works when I only have a single token: SELECT XMLCOL.query('user/name').value('.','NVARCHAR(20)') as name XMLCOL.query('user/token/id').value('.','NVARCHAR(20)') as id XMLCOL.query('user/token/endDate').value(,'xs:datetime(.)','DATETIME') as endDate FROM MYTABLE

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• parsing xml using dom4j

  - by D3GAN

  My XML structure is like this: <rss> <channel> <yweather:location city="Paris" region="" country="France"/> <yweather:units temperature="C" distance="km" pressure="mb" speed="km/h"/> <yweather:wind chill="-1" direction="40" speed="11.27"/> <yweather:atmosphere humidity="87" visibility="9.99" pressure="1015.92" rising="0"/> <yweather:astronomy sunrise="8:30 am" sunset="4:54 pm"/> </channel> </rss> when I tried to parse it using dom4j SAXReader xmlReader = createXmlReader(); Document doc = null; doc = xmlReader.read( inputStream );//inputStream is input of function log.info(doc.valueOf("/rss/channel/yweather:location/@city")); private SAXReader createXmlReader() { Map<String,String> uris = new HashMap<String,String>(); uris.put( "yweather", "http://xml.weather.yahoo.com/ns/rss/1.0" ); uris.put( "geo", "http://www.w3.org/2003/01/geo/wgs84_pos#" ); DocumentFactory factory = new DocumentFactory(); factory.setXPathNamespaceURIs( uris ); SAXReader xmlReader = new SAXReader(); xmlReader.setDocumentFactory( factory ); return xmlReader; } But I got nothing in cmd but when I print doc.asXML(), my XML structure print correctly!

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• mysql to xml (DOM question)

  - by Jerry

  Hello guys I am new to php dom and trying to get the mysql data transfer into xml. My current xml output is like this <markers> <city> <name>Seattle</name> <size>medium</size> <name>New York</name> <size>big</size> <city> <markers> but I want to change it to <markers> <city> <name>Seattle</name> <size>medium</size> <city> <city> <name>New York</name> <size>big</size> </city> <city> <markers> my php $dom=new DOMDocument("1.0"); $node=$dom->createElement("markers"); $parnode=$dom->appendChild($node); $firstElement=$dom->createElement("city"); $parnode->appendChild($firstElement); $getLocationQuery=mysql_query("SELECT * FROM location",$connection); header("Content-type:text/xml"); while($row=mysql_fetch_assoc($getLocationQuery)){ foreach ($row as $fieldName=>$value){ $child=$dom->createElement($fieldName); $value=$dom->createTextNode($value); $child->appendChild($value); $firstElement->appendChild($child); } } I can't figure out how to change my php code. Please help me about it. Thanks a lot.

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• POST XML to server, receive PDF

  - by Shaggy Frog

  Similar to this question, we are developing a Web app where the client clicks a button to receive a PDF from the server. Right now we're using the .ajax() method with jQuery to POST the data the backend needs to generate the PDF (we're sending XML) when the button is pressed, and then the backend is generating the PDF entirely in-memory and sending it back as application/pdf in the HTTP response. One answer to that question requires the server-side save the PDF to disk so it can give back a URL for the client to GET. But I don't want the backend caching content at all. The other answer suggests the use of a jQuery plugin, but when you look at its code, it's actually generating a form element and then submitting the form. That method will not work for us since we are sending XML data in the body of the HTTP request. Is there a way to have the browser open up the PDF without caching the PDF server-side, and without requiring us to throw out our send-data-to-the-server-using-XML solution? (I'd like the browser to behave like it does when a form element is submitted -- a POST is made and then the browser looks at the Content-type header to determine what to do next, like load the PDF in the browser window, a la Safari)

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• php XML DOM translates special chars to &#xYY;

  - by ZiTAL

  I send this with AJAX POST: <li><ul class "zone zCentral ui-sortable"><li><ul class="region rCol3 ui-sortable"><li class="" style=""><div><span class="tc tc_video">574081</span> <span>video: 'Mundo.Hoy': ¿Dónde habré olvidado... mi memoria?</span></div></li></ul></li></ul></li> I do this to create XML: header('Content-type: text/html; charset=utf-8'); if(isset($_POST) && isset($_POST['data'])) { $data = '<ul id="zone_container" class="ui-sortable">'; $data .= $_POST['data']; $data .= '</ul>'; $dom = new DOMDocument('1.0', 'utf-8'); $dom->loadXML($data); echo $dom->saveXML(); exit(); } and i get this: <?xml version="1.0"?> <ul id="zone_container" class="ui-sortable"> <li><ul class="zone zCentral ui-sortable"><li><ul class="region rCol3 ui-sortable"><li class="" style=""><div><span class="tc tc_video">574081</span> <span>video: 'Mundo.Hoy': &#xBF;D&#xF3;nde habr&#xE9; olvidado... mi memoria?</span></div> </li></ul></li></ul></li></ul> ¿Dónde habré olvidado... mi memoria? translates to: &#xBF;D&#xF3;nde habr&#xE9 ; olvidado... mi memoria? Y need original chars in the XML, these are utf-8 valid i don't know the reason for this encode :(

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• Remove the Parent tag in xml using php

  - by Wasim

  I am facing a problem in editing a xml file. <?xml version="1.0" encoding="UTF-8"?> <urlset> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> </urlset> I want to add one more set of records starting with <url> with its other tags, (i.e) "loc,lastmod,changefreq,priority" and than save the xml file.For adding the new record i need to remove the parent closing tag that is </urlset> and than add the rest of the records and close the main tag. Can anyone please help me solving my problem.Thanks

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• Problem creating XML using c#

  - by Pankaj

  I am searching a batter solution for creating xml through xml serialization. What i need, i have a given format like this <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <note>!--note 1---</note> <note>!--note 2--</note> ...... </notes> </product> what i am doing here, i created a 2 classes like this public class product { [XmlElement("name")] public string Name { get; set; } [XmlArray("notes")] public List<notes> ListNotes { get; set; } } public class notes { [XmlIgnore] public string Note { get; set; } } when i am serializing this then i am getting xml in this formate <product Id="1"> <name>2 1/2 X 6 PVC NIPPLE TOE SCH 80</name> <notes> <notes> <note>!--note 1---</note> <note>!--note 2--</note> </notes> </notes> </product> i don't want extra <notes>. Any batter solution to solve this problem? Thanks

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• How to parse the second child node from xml page in iphone

  - by Warrior

  I am new to iphone development.I want parse an you-tube XML page and retrieve its contents and display in a RSS feed. my xml page is <entry> <id>xxxxx</id> <title>xxx xxxx xxxx</title> <content>xxxxxxxxxxx</content> <media:group> <media:thumbnail url="http://tiger.jpg"/> </media:group> </entry> To retrieve the content i am using xml parsing. - (void)parser:(NSXMLParser *)parser didStartElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName attributes:(NSDictionary *)attributeDict{ currentElement = [elementName copy]; if ([elementName isEqualToString:@"entry"]) { entry = [[NSMutableDictionary alloc] init]; currentTitle = [[NSMutableString alloc] init]; currentcontent = [[NSMutableString alloc] init]; } } - (void)parser:(NSXMLParser *)parser didEndElement:(NSString *)elementName namespaceURI:(NSString *)namespaceURI qualifiedName:(NSString *)qName{ if ([elementName isEqualToString:@"entry"]) { [entry setObject:currentTitle forKey:@"title"]; [entry setObject:currentDate forKey:@"content"]; [stories addObject:[entry copy]]; }} - (void)parser:(NSXMLParser *)parser foundCharacters:(NSString *)string{ if ([currentElement isEqualToString:@"title"]) { [currentTitle appendString:string]; } else if ([currentElement isEqualToString:@"content"]) { [currentLink appendString:string]; } } I am able to retrieve id , title and content value and display it in a table-view.How can i retrieve tiger image URL and display it in table-view.Please help me out.Thanks.

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• Using a string inside the DocumentBuilder parse method (need it for parsing XML using XPath)

  - by dierre

  Hi guys! I'm trying to create a RESTful webservice using a Java Servlet. The problem is I have to pass via POST method to a webserver a request. The content of this request is not a parameter but the body itself. So I basically send from ruby something like this: url = URI.parse(@host) req = Net::HTTP::Post.new('/WebService/WebServiceServlet') req['Content-Type'] = "text/xml" # req.basic_auth 'account', 'password' req.body = data response = Net::HTTP.start(url.host, url.port){ |http| puts http.request(req).body } Then I have to retrieve the body of this request in my servlet. I use the classic readline, so I have a string. The problem is when I have to parse it as XML: private void useXML( final String soft, final PrintWriter out) throws ParserConfigurationException, SAXException, IOException, XPathExpressionException, FileNotFoundException { DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance(); domFactory.setNamespaceAware(true); // never forget this! DocumentBuilder builder = domFactory.newDocumentBuilder(); Document doc = builder.parse(soft); XPathFactory factory = XPathFactory.newInstance(); XPath xpath = factory.newXPath(); XPathExpression expr = xpath.compile("//software/text()"); Object result = expr.evaluate(doc, XPathConstants.NODESET); NodeList nodes = (NodeList) result; for (int i = 0; i < nodes.getLength(); i++) { out.println(nodes.item(i).getNodeValue()); } } The problem is that builder.parse() accepts: parse(File f), parse(InputSource is), parse(InputStream is). Is there any way I can transform my xml string in an InputSource or something like that? I know it could be a dummy question but Java is not my thing, I'm forced to use it and I'm not very skilled.

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• Iterate through every node in a XML

  - by Rachel

  Hi I am trying to iterate through every node in a xml, be it the element node, text node or comment. With the below XSL in the very first statement prints the complete xml. How do i copy the very first node in $nodes and call the template process-nodes again removing teh first node in my next iteration? <?xml version='1.0'?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <xsl:call-template name="process-nodes"> <xsl:with-param name="nodes" select="//node()" as="node()*"/> </xsl:call-template> </xsl:template> <xsl:template name="process-nodes"> <xsl:param name="nodes" as="node()*" /> <xsl:copy-of select="$nodes[1]"/> <xsl:if test="$nodes"> <xsl:call-template name="process-nodes"> <xsl:with-param name="nodes" select="remove($nodes, 1)" /> </xsl:call-template> </xsl:if> </xsl:template> </xsl:stylesheet> Note: I am looking for fixing the issue in this kind of implementation rather than changing the template match to <xsl:template match="@* | node()"> as I need to have some processing which requires this approach. Thanks.

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• Stop CDATA tags from being output-escaped when writing to XML in C#

  - by Smallgods

  We're creating a system outputting some data to an XML schema. Some of the fields in this schema need their formatting preserved, as it will be parsed by the end system into potentially a Word doc layout. To do this we're using <![CDATA[Some formatted text]]> tags inside of the App.Config file, then putting that into an appropriate property field in a xsd.exe generated class from our schema. Ideally the formatting wouldn't be out problem, but unfortunately thats just how the system is going. The App.Config section looks as follows: <header> <![CDATA[Some sample formatted data]]> </header> The data assignment looks as follows: HeaderSection header = ConfigurationManager.GetSection("header") as HeaderSection; report.header = "<[CDATA[" + header.Header + "]]>"; Finally, the Xml output is handled as follows: xs = new XmlSerializer(typeof(report)); fs = new FileStream (reportLocation, FileMode.Create); xs.Serialize(fs, report); fs.Flush(); fs.Close(); This should in theory produce in the final Xml a section that has information with CDATA tags around it. However, the angled brackets are being converted into &lt; and &gt; I've looked at ways of disabling Outout Escaping, but so far can only find references to XSLT sheets. I've also tried @"<[CDATA[" with the strings, but again no luck. Any help would be appreciated!

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• Load images into separate movie clips from a XML, Flash, Actionscript 3.0

  - by James Dunay

  I have an xml image bank, pretty standard, and I have a loader, along with movie clips that I want the images loaded into, the problem that I am running into is I want the images to load into separate movie clips, so I’m using a case statement to specify where they go. However, I can only get them to load into a single movie clip, I assume they are loading ontop of each other and I don’t know how to get them to separate out. I’ll post my code. It doesn’t make any sense to me but if you have any suggestions that would be real great. I can make separate loaders and then just do 1 image per loader, but that just doesn’t sound right to me. var counterNumber:Number = 0; function callThumbs():void{ for (var i:Number = 0; i <3; i++){ thumbLoaded(); counterNumber++; } } function thumbLoaded(){ var photoLoader = new Loader(); switch (counterNumber){ case 1: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageOne.image.@url[0])); whole.boxOne.pictureLoader.addChild(photoLoader); trace("1Done"); break; case 2: photoLoader.load(new URLRequest(MovieClip(this.parent).xml.photos.imageTwo.image.@url[0])); whole.boxTwo.pictureLoader.addChild(photoLoader); trace("2Done"); break; } }

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• can't read XML via PHP

  - by jasmine

  I can't find the reason, only see the following error message. Input is not proper UTF-8, indicate encoding ! Bytes: 0x00 0x5D 0x5D 0x3E the followings are my php code $reader2 = new XMLReader(); $reader2->XML($xmlstring); $user_data=""; while ($reader2->read()) { if ($reader2->name == "user_id" && $reader2->nodeType == XMLReader::ELEMENT) { $reader2->read(); $user_data .=$reader2->value; } } $reader2->close(); The followings are XML data <?xml version="1.0" encoding="UTF-8" ?> <SOAP:Envelope xmlns:SOAP="http://www.w3.org/2003/05/soap-envelope" > <SOAP:Body > <user_id>1234567890</user_id> <greeting_name><![CDATA[ABCDEF ..yl/?]]></greeting_name> </SOAP:Body> </SOAP:Envelope> I try a lot of ways,but still can't find the solution. the greeting tag value may be chinese or English words.

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• Fastest XML parser for small, simple documents in Java

  - by Varkhan

  I have to objectify very simple and small XML documents (less than 1k, and it's almost SGML: no namespaces, plain UTF-8, you name it...), read from a stream, in Java. I am using JAXP to process the data from my stream into a Document object. I have tried Xerces, it's way too big and slow... I am using Dom4j, but I am still spending way too much time in org.dom4j.io.SAXReader. Does anybody out there have any suggestion on a faster, more efficient implementation, keeping in mind I have very tough CPU and memory constraints? [Edit 1] Keep in mind that my documents are very small, so the overhead of staring the parser can be important. For instance I am spending as much time in org.xml.sax.helpers.XMLReaderFactory.createXMLReader as in org.dom4j.io.SAXReader.read [Edit 2] The result has to be in Dom format, as I pass the document to decision tools that do arbitrary processing on it, like switching code based on the value of arbitrary XPaths, but also extracting lists of values packed as children of a predefined node. [Edit 3] In any case I eventually need to load/parse the complete document, since all the information it contains is going to be used at some point. (This question is related to, but different from, http://stackoverflow.com/questions/373833/best-xml-parser-for-java )

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• JQuery can't return xml value

  - by Mistergreen

  I have this simple xml <?xml version="1.0"?> <library> <item name="box_shelf"> <imageback src="images/box_shelf_color.png"/> <outline src="images/box_shelf_outline.png"/> <sku> <wh sku="4696424171" /> <ch sku="4696424179" /> <choc sku="4696425863" /> <ma sku="4696424175" /> </sku> </item> </library> Loading the xml is fine. I then have a function to parse certain nodes. function parseImageXml(mainNode,targetNode) { $(libraryXML).find('item').each(function() { if($(this).attr('name') == mainNode) { var $temp = $(this).find(targetNode).attr('src'); console.log("******"+$temp); return $temp; } }); } The console log is fine with ******images/box_shelf_outline.png ******images/box_shelf_color.png But when I try to return the value into variables, I get undefined. var image_outline = ''+parseImageXml("box_shelf","outline"); var image_back = parseImageXml("box_shelf","imageback"); console.log(image_outline+":"+image_back); undefined:undefined Any insight would be great, thanks

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• How to get values of xml elements?

  - by user187580

  Hi, I have some xml data and I am trying to access some elements. The structure of data is as below (using print_r($data)). I can get $data->{'parent'}->title, it works but if I try to get value of href using $data->{'parent'}->link[0]->{'@attributes'}->href .. it doesnt work .. any ideas? Thanks SimpleXMLElement Object ( [@attributes] => Array ( [children] => 29 [modules] => 0 ) [title] => Test title [link] => Array ( [0] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => data.php?id=2322 [rel] => self [type] => application/xml ) ) [1] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => data.php?id=2342 [rel] => alternate [type] => text/html ) ) ) [parent] => SimpleXMLElement Object ( [@attributes] => Array ( [children] => 6 [modules] => 0 ) [title] => Top [link] => Array ( [0] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => /data.php?id=5763 [rel] => self [type] => application/xml ) ) [1] => SimpleXMLElement Object ( [@attributes] => Array ( [href] => /data.php?id=2342 [rel] => alternate [type] => text/html ) ) ) ) )

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• How to send XML and other post parameters via cURL in PHP

  - by tomaszs

  Hello. I've used code below to send XML to my REST API. $xml_string_data contains proper XML, and it is passed well to mypi.php: //set POST variables $url = 'http://www.server.cu/mypi.php'; $fields = array( 'data'=>urlencode($xml_string_data) ); //url-ify the data for the POST $fields_string = ""; foreach($fields as $key=>$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); echo $fields_string; //open connection $ch = curl_init(); curl_setopt($ch,CURLOPT_URL,$url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, true); curl_setopt($ch,CURLOPT_POST,count($fields)); curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); curl_setopt($ch,CURLOPT_HTTPHEADER,array ( "Expect: " )); //execute post $result = @curl_exec($ch); But when I've added other field: $fields = array( 'method' => "methodGoPay", 'data'=>urlencode($xml_string_data) ); It stopped to work. On the mypi.php I don't recieve any more POST parameters at all! Could you you please tell me what to do to send XML and other post parameters in one cURL request? Please don't suggest using any libraries, I wan't to acomplish it in plain PHP.

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• Android: How to put ListView in XML?

  - by FloIancu

  I want to make a simple app that shows a list of contacts (name, surname). My code: package lista.android; import java.util.*; import android.app.ListActivity; import android.os.Bundle; import android.widget.*; class Contact{ String nume; String prenume; Contact(String nume, String prenume){ this.nume=nume; this.prenume=prenume; } public String toString(){ return prenume +" "+ nume; } } public class Lista1Activity extends ListActivity { /** Called when the activity is first created. */ ArrayList <Contact> lista; ArrayAdapter <Contact> adaptor; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); setListAdapter(adaptor); lista=new ArrayList<Contact>(); adaptor=new ArrayAdapter<Contact>(this, R.id.element, lista); adaugaContact("Florian", "Iancu"); adaugaContact("Ioana", "Constantina"); } public void adaugaContact(String nume, String prenume){ lista.add(new Contact(nume, prenume)); adaptor.notifyDataSetChanged(); } } In the XML I have the LinearLayout and a TextView that is the list element. When I run it, the simulator says "Sorry, the application [...] has stopped unexpectedly. Please try again." The LogCat tells me I have to have a ListView whose id is android.R.id.lista. If I create a random ListView field in the XML file and give it the "lista" id, it still doesn't work. How to I call that ListView from XML to match something in my Java code? In other words, I know I'm wrong, but where and how do I fix it?

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• ignoring elements order in xml validation against xsd

  - by segolas

  Hi, Ia processing an email and saving some header inside a xml document. I also need to validate the document against a xml schema. As the subject suggest, I need to validate ignoring the elements order but, as far as I read this seems to be impossible. Am I correct? If I put the headers in a<xsd:sequence>, the order obviously matter. If I us the order is ignored but for some strange reason this imply that the elements must occur at least once. My xml is something like this: <headers> <subject>bla bla bla</subject> <recipient>[email protected]</recipient> <recipient>rcp02domain.com</recipient> <recipient>[email protected]</recipient> </headers> but I think the final document is valid even if subject and recipient elements are swapped. There is really nothing to do?

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