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  • Custom Grails plugin dependency

    - by ankimal
    I have a custom grails plugin I m trying to develop and set this def dependsOn = [tomcat: "1.0"] in the Plugin script. Now, my custom plugin loads just fine but I dont see tomcat installed in my application. How does one install a dependency plugin (prompt the user to say yes/no)? Is this even possible?

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  • jQuery: how to know when an external JS has finished?

    - by andufo
    Hi, i need to execute specific javascript instructions AFTER an external javascript finishes its own process. (function(){ var dsq = document.createElement('script'); dsq.type = 'text/javascript'; dsq.async = true; dsq.src = 'http://xxxxxxxx.disqus.com/embed.js'; (document.getElementsByTagName('head')[0] || document.getElementsByTagName('body')[0]).appendChild(dsq); })(); How can jQuery know when that .js has finished doing what it does?

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  • Auto accept outlook VBA

    - by Russ
    Is there a VB macro or some sort of add-on out there that will allow me to auto accept invitations in outlook by sender or by folder? I was thinking about doing a VB script for this but I don't want to re-invent the wheel?

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  • Create an upload form, select a folder and get a specific file in folder

    - by aladine
    Hi, To upload a single file, it is very simple to use this HTML script: <p> <input type="file" name="input.txt" /> In this question, my task is to select a folder and then get the input.txt inside that folder. The server will response whether input.txt is available or not and to upload it to web server. Is there any way to select a folder instead selecting a file in the input form. Thanks.

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  • Jquery image preview thumbnail doesn't seem to work....

    - by Pandiya Chendur
    I just tried the tooltip like this Easy image preview... But i cant get it to work.... I used this, <style> body { margin:0; padding:40px; background:#fff; font:80% Arial, Helvetica, sans-serif; color:#555; line-height:180%; } h1{ font-size:180%; font-weight:normal; color:#555; } h2{ clear:both; font-size:160%; font-weight:normal; color:#555; margin:0; padding:.5em 0; } a{ text-decoration:none; color:#f30; } p{ clear:both; margin:0; padding:.5em 0; } pre{ display:block; font:100% "Courier New", Courier, monospace; padding:10px; border:1px solid #bae2f0; background:#e3f4f9; margin:.5em 0; overflow:auto; width:800px; } img{border:none;} ul,li{ margin:0; padding:0; } li{ list-style:none; float:left; display:inline; margin-right:10px; } /* */ #preview{ position:absolute; border:1px solid #ccc; background:#333; padding:5px; display:none; color:#fff; } /* */ </style> <script type="text/javascript" src="jquery.js"></script> <ul> <li> <a href="Images/4.jpg" class="preview" title="Lake and a mountain"> <img src="Images/4s.jpg" alt="gallery thumbnail" /> </a> </li> </ul> and included style... Nothing happens when i hover over the anchor tag....

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  • Converting numbers to their language, how?

    - by SoLoGHoST
    Ok, I'm using mathematical equations to output numbers, though, I need this to be compatible for all languages. Currently, all language strings are within a php array called $txt, and each key of the array gets called for that language. I'm outputting the following: Column 1, Column 2, Column 3, and so on, as well as Row 1, Row 2, Row 3, and so on. The calculations are done via php and javascript, so I'm wondering on the best approach for how to support all languages for the numbers only. I don't do the translations, someone else does, but I need to be able to point it to, either the php variable $txt of where the language is defined, or, since the calculations are done via javascript also, I need to somehow store this in there. I'm thinking of storing something like this: // This part goes in the php language file. $txt['0'] = '0'; $txt['1'] = '1'; $txt['2'] = '2'; $txt['2'] = '3'; $txt['4'] = '4'; $txt['5'] = '5'; $txt['6'] = '6'; $txt['7'] = '7'; $txt['8'] = '8'; $txt['9'] = '9'; // This part goes in the php file that needs to call the numbers. echo '<script> var numtxts = new Array(); numtxts[0] = \'', $txt['0'], '\'; numtxts[1] = \'', $txt['1'], '\'; numtxts[2] = \'', $txt['2'], '\'; numtxts[3] = \'', $txt['3'], '\'; numtxts[4] = \'', $txt['4'], '\'; numtxts[5] = \'', $txt['5'], '\'; numtxts[6] = \'', $txt['6'], '\'; numtxts[7] = \'', $txt['7'], '\'; numtxts[8] = \'', $txt['8'], '\'; numtxts[9] = \'', $txt['9'], '\'; </script>'; And than in the javascript function it could grab the correct string for each number like so: // Example Number String below. var numString = "10"; var transNum = ""; for(x=0;x<numString.length;x++) { var numChar = numString.charAt(x); transNum += numtxts[parseInt(numChar)]; } return transNum; The problem with this bit of code is that it groups the numbers, not sure if all languages do that, like the english language does...? Perhaps there's a better approach for this? Can anyone help please? Thanks :)

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  • How can I get a list of licenses from intalled RPMs?

    - by Peter
    We've been asked to list all the software and licenses used in our organization. Without deciding the value of this request, I'd like to get my Fedora laptop to answer the question easily. rpm -qa Gives me a list of packages, but no license data. My next step is to take that output and write a script to query each package's license. Anyone got an easier idea?

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  • pickle on jruby

    - by brad
    Does anyone know if pickle is compatible with jruby? I just installed cucumber and cucumber-rails. I then tried gem install pickle and it installs, but a script/generate pickle yields Couldn't find 'pickle' generator I did everything according to the readme no dice. Anyone have any experience with this: specs jruby-1.4.0 rails-2.3.5 cucumber 0.7.2 pickle 0.2.10

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  • Animation using AniMate with Unity3D doesn't interact with physical objects

    - by Albz
    I'm designing a maze with Unity3D. The maze has a number of bifurcations and the player will stop before each bifurcation and simply choose left or right. Then an automatic animation will move the player through the next bifurcation till the end of the maze (or till a dead end). To animate the player I'm using AniMate and C# in my Unity project. Using AniMate I'm simply creating a point-to-point animation for each bifurcation (e.g. mage below: from the start/red arrow to point 5) My problem is that my animation script (associated to the "First Person Controller") is not working properly since physics is not respected (the player passes through walls). If in the same project I enable the standard character controls in Unity, then I can navigate in the maze with the physical contrains of walls etc... (i.e. I have colliders). This is an example of the code I'm using when I press left to pass from starting point, trough point 1 to point 2: void FixedUpdate () { if (Input.GetKey(KeyCode.LeftArrow)) { //To point 1 Hashtable props = new Hashtable(); props.Add("position", new Vector3(756f,112f,1124f)); props.Add("physics", true); Ani.Mate.To(transform, 2, props); //To point 2 Hashtable props2 = new Hashtable(); props2.Add("position", new Vector3(731f,112f,1124f)); props2.Add("physics", true); Ani.Mate.To(transform, 2, props2); } } What happens practically when I press the left arrow button is that the player moves directly to point 2 using a straight line passing through the wall. I tried to pass to AniMate "Physics = true" but it doesn't seem to help. Any idea on how to solve this issue? Alternatively... any hint on how to have a more optimized code and just use a series of vector3 coordinates (one for each point) to obtain the simple animation I want without having to declare new Hashtable(); etc... every time? I chose AniMate simply because 1. I'm a beginner with Unity 2. I don't need complex animations (e.g. I don't need to use iTween), just fixed animations along straight lines and I need something really simple and quick to implement in a script. However, if someone has an equally simple solution it will be welcome. thank you in advance for your help

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  • jQuery AJAX type: 'GET', passing value problem.

    - by Trez
    I have a jQuery AJAX call with type:'GET' like this: $.ajax({type:'GET',url:'/createUser',data:"userId=12345&userName=test"}, success:function(data){ alert('successful'); } ); In my console output is: GET:http://sample.com/createUser?userId=12345&userName=test params: userId 12345 userName test In my script i should get the value using $_GET['userId'] and $_GET['userName'] but i can't get the value passed in by ajax request using GET method. Any ideas on how to do this? thanks,

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  • how can i put an image into select?

    - by Syom
    i have this script <select> <option value="1">one<img src="star.gif" height="15" width="15"></img> </option> </select> but it doesn't work. how can i put an image into select? thanks update: so it's impossible?:(

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  • Syntax highlighting in vim

    - by Rimian
    I'm having trouble reading dark blue on black when I turn on syntax colours in vim. How do I change some of the default colours or the colours of schemas like: http://www.vim.org/scripts/script.php?script_id=1571

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  • unable to copy release folder to desktop using AppleScript

    - by Miraaj
    Hi all, I tried this script to copy release folder of one of my Xcode projects to desktop: tell application "Finder" set targetFolder to folder "release" of folder "build" of folder "8_15pm" of folder "26th_March" of folder "XYZ" of startup disk set destinationFolder to folder "Desktop" of folder "miraaj" of folder "Users" of startup disk copy targetFolder to destinationFolder end tell I was expecting that I will obtain a folder named as release on my desktop but I did not get any :( Can anyone suggest me where I am wrong or some better way to do this?? Thanks, Miraaj

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  • Why always fires OnFailure when return View() to Ajax Form ?

    - by Wahid Bitar
    I'm trying to make a log-in log-off with Ajax supported. I made some logic in my controller to sign the user in and then return simple partial containing welcome message and log-Off ActionLink my Action method looks like this : public ActionResult LogOn(LogOnModel model, string returnUrl) { if (ModelState.IsValid) { if (MembershipService.ValidateUser(model.UserName, model.Password)) { FormsService.SignIn(model.UserName, model.RememberMe); if (Request.IsAjaxRequest()) { //HERE IS THE PROBLEM :( return View("LogedInForm"); } else { if (!String.IsNullOrEmpty(returnUrl)) return Redirect(returnUrl); else return RedirectToAction("Index", "Home"); } } else { ModelState.AddModelError("", "The user name or password provided is incorrect."); if (Request.IsAjaxRequest()) { return Content("There were an error !"); } } } return View(model); } and I'm trying to return this simple partial : Welcome <b><%= Html.Encode(Model.UserName)%></b>! <%= Html.ActionLink("Log Off", "LogOff", "Account") %> and of-course the two partial are strongly-typed to LogOnModel. But if i returned View("PartialName") i always get OnFailure with status code 500. While if i returned Content("My Message") everything is going right. so please tell me why i always get this "StatusCode = 500" ??. where is the big mistake ??. By the way in my Site MasterPage i rendered partial to show long-on simple form this partial looks like this : <script type="text/javascript"> function ShowErrorMessage(ajaxContext) { var response = ajaxContext.get_response(); var statusCode = response.get_statusCode(); alert("Sorry, the request failed with status code " + statusCode); } function ShowSuccessMessage() { alert("Hey everything is OK!"); } </script> <div id="logedInDiv"> </div> <% using (Ajax.BeginForm("LogOn", "Account", new AjaxOptions { UpdateTargetId = "logedInDiv", InsertionMode = InsertionMode.Replace, OnSuccess = "ShowSuccessMessage", OnFailure = "ShowErrorMessage" })) { %> <%= Html.TextBoxFor(m => m.UserName)%> <%= Html.PasswordFor(m => m.Password)%> <%= Html.CheckBoxFor(m => m.RememberMe)%> <input type="submit" value="Log On" /> < <% } %>

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  • Can't start rails server after 3.0.1 upgrade

    - by Alberto
    Followed instructions on Railscast but can't get server to start. It states the following error: $ rails s script/rails:6:in `require': no such file to load -- rails/commands (LoadError)` from script/rails:6:in `<main>' Saw the answer on this related question but my Gemfile has no reference to any rails 2.x version and in the "bundle install" results i get this in the results: "Using rails (3.0.1)" EDIT: (adding Gemfile.lock details) GEM remote: http://rubygems.org/ specs: abstract (1.0.0) actionmailer (3.0.1) actionpack (= 3.0.1) mail (~> 2.2.5) actionpack (3.0.1) activemodel (= 3.0.1) activesupport (= 3.0.1) builder (~> 2.1.2) erubis (~> 2.6.6) i18n (~> 0.4.1) rack (~> 1.2.1) rack-mount (~> 0.6.12) rack-test (~> 0.5.4) tzinfo (~> 0.3.23) activemodel (3.0.1) activesupport (= 3.0.1) builder (~> 2.1.2) i18n (~> 0.4.1) activerecord (3.0.1) activemodel (= 3.0.1) activesupport (= 3.0.1) arel (~> 1.0.0) tzinfo (~> 0.3.23) activeresource (3.0.1) activemodel (= 3.0.1) activesupport (= 3.0.1) activesupport (3.0.1) arel (1.0.1) activesupport (~> 3.0.0) builder (2.1.2) calendar_date_select (1.16.1) erubis (2.6.6) abstract (>= 1.0.0) googlecharts (1.6.0) i18n (0.4.2) mail (2.2.9) activesupport (>= 2.3.6) i18n (~> 0.4.1) mime-types (~> 1.16) treetop (~> 1.4.8) mechanize (1.0.0) nokogiri (>= 1.2.1) mime-types (1.16) nokogiri (1.4.3.1) pg (0.9.0) polyglot (0.3.1) rack (1.2.1) rack-mount (0.6.13) rack (>= 1.0.0) rack-test (0.5.6) rack (>= 1.0) rails (3.0.1) actionmailer (= 3.0.1) actionpack (= 3.0.1) activerecord (= 3.0.1) activeresource (= 3.0.1) activesupport (= 3.0.1) bundler (~> 1.0.0) railties (= 3.0.1) railties (3.0.1) actionpack (= 3.0.1) activesupport (= 3.0.1) rake (>= 0.8.4) thor (~> 0.14.0) rake (0.8.7) sparklines (0.5.2) thor (0.14.4) treetop (1.4.8) polyglot (>= 0.3.1) tzinfo (0.3.23) PLATFORMS ruby DEPENDENCIES calendar_date_select googlecharts mechanize pg rails (= 3.0.1) sparklines EDIT: (adding Boot.rb details) require 'rubygems' # Set up gems listed in the Gemfile. gemfile = File.expand_path('../../Gemfile', __FILE__) begin ENV['BUNDLE_GEMFILE'] = gemfile require 'bundler' Bundler.setup rescue Bundler::GemNotFound => e STDERR.puts e.message STDERR.puts "Try running `bundle install`." exit! end if File.exist?(gemfile)

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  • people picker control inside gridview template field with ajax update panel applied SharePoint 2010

    - by user1434450
    In my page I have drop down control, grid view. Inside the grid view in template field I have people picker control. When ever I change the drop down value from 'Select' to another I am displaying my grid view with people picker. Everything is working fine. But after applying 'update panel', whenever I change the drop down value, people picker control is not working inside the grid view. <asp:UpdatePanel ID="UpdatePanel1" runat="server" UpdateMode="Conditional"> <ContentTemplate> <asp:GridView ID="gvDirectory" runat="server" AutoGenerateColumns="false" ShowHeader="false" onrowcommand="gvDirectory_RowCommand" onrowdeleting="gvDirectory_RowDeleting" onrowdatabound="gvDirectory_RowDataBound" BorderWidth="0"> <Columns> <asp:TemplateField> <ItemTemplate> <asp:CheckBox ID="chkselect" runat="server" Width="20px" AutoPostBack="true" oncheckedchanged="chkselect_CheckedChanged"/> </ItemTemplate> </asp:TemplateField> <asp:TemplateField> <ItemTemplate> <asp:HyperLink ID="lnkcategory" runat="server" Text='<%# Eval("Title") %>' Target="_blank" NavigateUrl='<%# Eval("URL") %>' Width="200px" onclick="ShowAwesomeHelloPageInDialog(this);return false;"></asp:HyperLink> <asp:Label ID="lblvalue" runat="server" Text='<%# Eval("value") %>' Visible="false"></asp:Label> </ItemTemplate> </asp:TemplateField> <asp:TemplateField> <ItemTemplate> <SharePoint:PeopleEditor ID="Assignedusers" runat="server" AllowEmpty="false" MultiSelect="true" Width="250px" BorderColor="#559CD7" Height="20px" SelectionSet="User,SPGroup" Rows="2" PlaceButtonsUnderEntityEditor="false" EnableViewState="true" /> </ItemTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="Delete"> <ItemTemplate> <asp:ImageButton ID="btnDelete" runat="server" CommandArgument='<%# Container.DataItemIndex%>' ImageUrl="~/_layouts/images/EditTaskPage/Delete.png" CommandName="Delete" Text="Delete" Height="26px" Width="26px"/> </ItemTemplate> </asp:TemplateField> </Columns> </asp:GridView> </ContentTemplate> <%--<Triggers> <asp:PostBackTrigger ControlID="ddlCategory" /> </Triggers>--%> </asp:UpdatePanel> <script type="text/javascript"> _spOriginalFormAction = document.forms[0].action; _spSuppressFormOnSubmitWrapper = true; </script> how can I solve this problem.. thanks in advance....

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  • how to display user name in login name control

    - by user569285
    I have a master page that holds the loginview content that appears on all subsequent pages based on the master page. i have a username control also nested in the loginview to display the name of the user when they are logged in. the code for the loginview from the master page is displayed as follows: <div class="loginView"> <asp:LoginView ID="MasterLoginView" runat="server"> <LoggedInTemplate> Welcome <span class="bold"><asp:LoginName ID="HeadLoginName" runat="server" /> <asp:Label ID="userNameLabel" runat="server" Text="Label"></asp:Label></span>! [ <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Logout.aspx"/> ] <%--Welcome: <span class="bold"><asp:LoginName ID="MasterLoginName" runat="server" /> </span>!--%> </LoggedInTemplate> <AnonymousTemplate> Welcome: Guest [ <a href="~/Account/Login.aspx" ID="HeadLoginStatus" runat="server">Log In</a> ] </AnonymousTemplate> </asp:LoginView> <%--&nbsp;&nbsp; [&nbsp;<asp:LoginStatus ID="MasterLoginStatus" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" />&nbsp;]&nbsp;&nbsp;--%> </div> Since VS2010 launches with a default login page in the accounts folder, i didnt think it necessary to create a separate log in page, so i just used the same log in page. please find the code for the login control below: <asp:Login ID="LoginUser" runat="server" EnableViewState="false" RenderOuterTable="false"> <LayoutTemplate> <span class="failureNotification"> <asp:Literal ID="FailureText" runat="server"></asp:Literal> </span> <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="failureNotification" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend style="text-align:left; font-size:1.2em; color:White;">Account Information</legend> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User ID:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="failureNotification" ErrorMessage="User ID is required." ToolTip="User ID field is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="failureNotification" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="submitButton"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="LoginUserValidationGroup" onclick="LoginButton_Click"/> </p> </div> </LayoutTemplate> </asp:Login> I then wrote my own code for authentication since i had my own database. the following displays the code in the login buttons click event.: public partial class Login : System.Web.UI.Page { //create string objects string userIDStr, pwrdStr; protected void LoginButton_Click(object sender, EventArgs e) { //assign textbox items to string objects userIDStr = LoginUser.UserName.ToString(); pwrdStr = LoginUser.Password.ToString(); //SQL connection string string strConn; strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ConnectionString; SqlConnection Conn = new SqlConnection(strConn); //SqlDataSource CSMDataSource = new SqlDataSource(); // CSMDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ToString(); //SQL select statement for comparison string sqlUserData; sqlUserData = "SELECT StaffID, StaffPassword, StaffFName, StaffLName, StaffType FROM Staffs"; sqlUserData += " WHERE (StaffID ='" + userIDStr + "')"; sqlUserData += " AND (StaffPassword ='" + pwrdStr + "')"; SqlCommand com = new SqlCommand(sqlUserData, Conn); SqlDataReader rdr; string usrdesc; string lname; string fname; string staffname; try { //string CurrentData; //CurrentData = (string)com.ExecuteScalar(); Conn.Open(); rdr = com.ExecuteReader(); rdr.Read(); usrdesc = (string)rdr["StaffType"]; fname = (string)rdr["StaffFName"]; lname = (string)rdr["StaffLName"]; staffname = lname.ToString() + " " + fname.ToString(); LoginUser.UserName = staffname.ToString(); rdr.Close(); if (usrdesc.ToLower() == "administrator") { Response.Redirect("~/CaseAdmin.aspx", false); } else if (usrdesc.ToLower() == "manager") { Response.Redirect("~/CaseManager.aspx", false); } else if (usrdesc.ToLower() == "investigator") { Response.Redirect("~/Investigator.aspx", false); } else { Response.Redirect("~/Default.aspx", false); } } catch(Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } finally { Conn.Close(); } } My authentication works perfectly and the page gets redirected to the designated destination. However, the login view does not display the users name. i actually cant figure out how to pass the users name that i had picked from the database to the login name control to be displayed. taking a close look i also noticed the logout text that should be displayed after successful log in does not show. that leaves me wondering if the loggedin template control on the masterpage even fires at all or its still the anonymous template control that keeps displaying.? How do i get this to work as expected? Please help....

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  • Wordpress and Joomla Permalinks plus domain redirect to specific subdirectory on Zeus

    - by moss
    Hi, Here's what I'm trying to do: joomla in 1 subdirectory, wordpress in another. mysite.com directs to the joomla directory mysite.com/blog gives wordpress. I would also like to use seo friendly permalinks for both. I am using Zeus Linux shared hosting with Joomla 1.5 and wordpress 2.9.2, and having a great deal of trouble finding a suitable rewrite script. Any help would be very much appreciated! Thank you.

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  • Escaping Code for Different Shells

    - by Jon Purdy
    Question: What characters do I need to escape in a user-entered string to securely pass it into shells on Windows and Unix? What shell differences and version differences should be taken into account? Can I use printf "%q" somehow, and is that reliable across shells? Backstory (a.k.a. Shameless Self-Promotion): I made a little DSL, the Vision Web Template Language, which allows the user to create templates for X(HT)ML documents and fragments, then automatically fill them in with content. It's designed to separate template logic from dynamic content generation, in the same way that CSS is used to separate markup from presentation. In order to generate dynamic content, a Vision script must defer to a program written in a language that can handle the generation logic, such as Perl or Python. (Aside: using PHP is also possible, but Vision is intended to solve some of the very problems that PHP perpetuates.) In order to do this, the script makes use of the @system directive, which executes a shell command and expands to its output. (Platform-specific generation can be handled using @unix or @windows, which only expand on the proper platform.) The problem is obvious, I should think: test.htm: <!-- ... --> <form action="login.vis" method="POST"> <input type="text" name="USERNAME"/> <input type="password" name="PASSWORD"/> </form> <!-- ... --> login.vis: #!/usr/bin/vision # Think USERNAME = ";rm -f;" @system './login.pl' { USERNAME; PASSWORD } One way to safeguard against this kind of attack is to set proper permissions on scripts and directories, but Web developers may not always set things up correctly, and the naive developer should get just as much security as the experienced one. The solution, logically, is to include a @quote directive that produces a properly escaped string for the current platform. @system './login.pl' { @quote : USERNAME; @quote : PASSWORD } But what should @quote actually do? It needs to be both cross-platform and secure, and I don't want to create terrible problems with a naive implementation. Any thoughts?

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  • php curl upload speed

    - by zanatic
    hey i made a script that uploads files to different servers using php curl and the problem is that it eats all my upload bandwith and my apache does not respond as i would like. the call is made from the php-cli and can not use any apache bandwith limiting bandwith thanks in advance

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  • MySQL foreign key creation with alter table command

    - by user313338
    I created some tables using MySQL Workbench, and then did forward ‘forward engineer’ to create scripts to create these tables. BUT, the scripts lead me to a number of problems. One of which involves the foreign keys. So I tried creating separate foreign key additions using alter table and I am still getting problems. The code is below (the set statements, drop/create statements I left in … though I don’t think they should matter for this): SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_UserName` VARCHAR(35) NOT NULL , `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`), FOREIGN KEY (`User_UserName`) REFERENCES `mydb`.`User` (`UserName`) ON UPDATE CASCADE ON DELETE CASCADE) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; The error this produces is: Error Code: 1005 Can't create table 'mydb.user_space' (errno: 150) Anybody know what the heck I’m doing wrong?? And anybody else have problems with the script generation done by mysql workbench? It’s a nice tool, but annoying that it pumps out scripts that don’t work for me. [As an fyi here’s the script it auto-generates: SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0; SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0; SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='TRADITIONAL'; DROP SCHEMA IF EXISTS `mydb` ; CREATE SCHEMA IF NOT EXISTS `mydb` DEFAULT CHARACTER SET latin1 COLLATE latin1_swedish_ci ; -- ----------------------------------------------------- -- Table `mydb`.`User` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User` ; CREATE TABLE IF NOT EXISTS `mydb`.`User` ( `UserName` VARCHAR(35) NOT NULL , `Num_Accts` INT NOT NULL , `Password` VARCHAR(45) NULL , `Email` VARCHAR(45) NULL , `User_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_ID`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `mydb`.`User_Space` -- ----------------------------------------------------- DROP TABLE IF EXISTS `mydb`.`User_Space` ; CREATE TABLE IF NOT EXISTS `mydb`.`User_Space` ( `User_Space_ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY (`User_Space_ID`) , INDEX `User_ID` () , CONSTRAINT `User_ID` FOREIGN KEY () REFERENCES `mydb`.`User` () ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; SET SQL_MODE=@OLD_SQL_MODE; SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS; SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS; ** Thanks!]

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