Search Results

Search found 17655 results on 707 pages for 'jquery animate'.

Page 569/707 | < Previous Page | 565 566 567 568 569 570 571 572 573 574 575 576  | Next Page >

  • JQM Nested Popups

    - by mcottingham
    I am having a hard time with the new Alpha release of JQM not showing nested popups. For example, I am displaying a popup form that the user is supposed to fill out, if the server side validation fails, I want to display an error popup. I am finding that the error popup is not being shown. I suspect that it is being shown below the original popup. function bindSongWriterInvite() { // Bind the click event of the invite button $("#invite-songwriter").click(function () { $("#songwriter-invite-popup").popup("open"); }); // Bind the invitation click event of the invite modal $("#songwriter-invite-invite").click(function () { if ($('#songwriter-invite').valid()) { $('#songwriter-invite-popup').popup('close'); $.ajax({ type: 'POST', async: true, url: '/songwriter/jsoncreate', data: $('#songwriter-invite').serialize() + "&songName=" + $("#Song_Title").val(), success: function (response) { if (response.state != "success") { alert("Should be showing error dialog"); mobileBindErrorDialog(response.message); } else { mobileBindErrorDialog("Success!"); } }, failure: function () { mobileBindErrorDialog("Failure!"); }, dataType: 'json' }); } }); // Bind the cancel click event of the invite modal $("#songwriter-invite-cancel").click(function () { $("#songwriter-invite-popup").popup("close"); }); } function mobileBindErrorDialog(errorMessage) { // Close all open popups. This is a work around as the JQM Alpha does not // open new popups in front of all other popups. var error = $("<div></div>").append("<p>" + errorMessage + "</p>") .popup(); $(error).popup("open"); } So, you can see that I attempt to show the error dialog regardless of whether the ajax post succeeds or fails. It just never shows up. Anyone have any thoughts? Mike

    Read the article

  • Feature panel hover changer effect

    - by user1519157
    Haven't seen this before so hopefully someone has a easy solve, I have a 3 feature panel divs side by side, what I want happen is the 1st panel has a "hover" class added so I can change the background etc and then on a timed interval the hover class jumps to the next panel then the next panel then back to the start on a loop. Also on a side note can you keep the code in mind to be able to add more then 3 feature divs so you could have for example 6 or more or less etc.

    Read the article

  • Alert user when they hit the browser back button - with good reson

    - by Dirty Bird Design
    I know this borders on the taboo here, and please don't reply with "you should never do this etc" I have a very long form in a wizard, some users are too used to using the browsers back and forward buttons that they use those instead of the "Back" and "Next" buttons on the form wizard. If they hit the browsers back button they lose all of their form data which is a pain in the ass, since form is so long. Is it possible to display an alert that when will have a "take me out of here" and a "cancel" button so if they hit cancel it will cancel the function of the back button? Thanks!

    Read the article

  • on page load clone first image from collection of photos

    - by user313378
    On my page I'm getting collection of photos, and I store them as thumbs below showImage div which needs to be refreshed with cloned image onclick. Basically everything is ok except I need to populate this showImage div onpage load with first image, and then to use this onclick clone which already works. <a href="/Property/GetImage/someIntId"> <img id="someIntId" class="details" width="100" height="100" src="/Property/GetImage/7" alt=""> </a> function onPopUp() { $(".details").click(function (event) { //clone the clicked image var clone = $(this).clone(); clone.height("250px").width("280px"); //place it in the placeholder $('div#showImage').html(clone); }); }

    Read the article

  • swapping <div> ?

    - by kiran
    this is my sample code <div id="id-1"><div>sampledata</div><span>sampledata</span></div> <div id"id-2"><div>sampledata</div><div> smpledata</div></div> <div id"id-3"><div>sampledata</div><div> smpledata</div></div> <div id"id-3"><div>sampledata</div><div> smpledata</div></div> i'm having the id of only one div(for example id-3) . i want to swap that <div> with next <div>, since there is more than one <div> inside a <div> i cant use a next() . thanks in advance

    Read the article

  • Pulling Data out of an object in Javascript

    - by PerryCS
    I am having a problem retreiving data out of an object passed back from PHP. I've tried many different ways to access this data and none work. In Firebug I see the following... (it looks nicer in Firebug) - I tried to make this look as close to Firebug as possible results Object { data="{"formName":"form3","formData":"data goes here"}", phpLiveDebug="<...s: 198.91.215.227"} data "{"formName":"form3","formData":"data goes here"}" phpLiveDebug "<...s: 198.91.215.227" I can access phpLiveDebug no problem, but the data portion is an object. I have tried the following... success: function(results) { //$("#formName").val(results.data.formName); //$("#formName").val(results.data[0].formName); //$("#formName").val(results.data[0]); //$("#formName").val(results.data[1]); //$("#formName").val(results.data[0]["formName"]); var tmp = results.data[formName]; alert("!" + tmp + "!"); $("#formName").val(tmp); $("#jqueryPHPDebug").val(results.phpLiveDebug); } This line works in the example above... $("#jqueryPHPDebug").val(results.phpLiveDebug); but... I can't figure out how to get at the data inside the results.data portion... as you can see above, I have been trying different things and more not even listed there. I was really hoping this line would work :) var tmp = results.data[formName]; But it doesn't. So, after many days of reading, tinkering, my solution was to re-write it to return data similar to the phpLiveDebug but then I thought... it's gotta be something simple I'm overlooking... Thank you for your time. Please try and explain why my logic (my horrible attempts at trying to figure out the proper method) above is wrong if you can?

    Read the article

  • Keyup attribute 'name' change not working

    - by dclowd9901
    Hey guys, I've got what I imagine is a simple question, but for some reason, I can't get it working right. Expected Behavior: I type characters into a field, and, through a function, those characters are translated into the value of the name HTML attribute. Actual Behavior: Reflected in Firebug, the value doesn't change or update. The Code: $('input').live('keyup', function() { var name_value = $(this).val().toLowerCase(); $(this).attr('name', name_value); }); Just a side note: I'm using .live() because the element can be cloned, and those clones need to also be able to take on the properties of this .keyup event. Any ideas?

    Read the article

  • Unable to capture the id of div clicked

    - by user3674364
    This is my jsfiddle http://jsfiddle.net/6TUtw/4/ How can i register for the event div click , so that i can get the name i have tried with different things , but none of them worked . $('#tabs div').click(function() { var elem = $(this); alert(elem); }); $('#tabs').on('click', 'div.click', function () { var elem = $(this); alert(elem); }); $("#tabs").click(function(){ var elem = $(this); alert(elem); });

    Read the article

  • HTML5 drag upload in new window

    - by user463604
    I have setup an HTML5 drag and drop upload into my site. The problem that I have is when a user is uploading a large file, they must wait for the upload to finish before navigating and using the rest of the site. So, what I'd like to do is allow the user to drag files to the main site and then have it automatically open a new window and start the upload there so they can still use the rest of the site while the upload is happening. Anyone have and advice on how to accomplish this or if it can even be done?

    Read the article

  • How to determine which enemy is hit and destroy it alone

    - by Jon Ferriter
    http://jsfiddle.net/5DB6K/ I have this game being made where you shoot enemies from the sides of the screen. I've got the bullets moving and being removed when they reach the end of the screen (if they didn't hit any enemy) and removing the enemy when they collide with it. //------------collision----------------// if(shot === true){ bulletY = $('.bullet').position().top + 2; bulletX = $('.bullet').position().left + 2; $('.enemy').each(function(){ if($('.enemy').hasClass('smallEnemy')){ enemyY = $(this).position().top + 7; enemyX = $(this).position().left + 7; if(Math.abs(bulletY - enemyY) <= 9 && Math.abs(bulletX - enemyX) <=9){ $(this).remove(); score = score + 40; bulletDestroy(); } } }); } However, the bullet destroys every enemy if the collision check is right which isn't what I want. I want to check if the enemy has the class of either smallEnemy, medEnemy, or lrgEnemy and then do the collision check which is what I thought I had but it doesn't seem to work. Also, the game starts to lag the more and more time goes on. Would anyone know the reason for that?

    Read the article

  • What is the proper way to wait a script loaded completely before another

    - by FatDogMark
    I am making a website that is divided by several sections <div id='section-1' class='section'>web content</div> <div id='section-2' class='section'>web content</div> I have like ten sections on my webpage ,each sections height is set to the user window height when document is ready by javascript $('.section').height($(window).height()); Some effects like slideshows on my webpage require the calculated height of the section in order to work properly. Therefore I always use something like this at document ready as a solution. setTimeout(startslideshow,1000); setTimeout(startanimations,1000); ...etc To make sure the section height is the user window height before the slideshow's code start because the sections cannot change to user window height instantly once the webpage loaded will generate serious problems in my slideshow code,like wrong calculated positions. Therefore there will be a situation that's after the page loaded, there will be about a second everything is messed up,before everything can works properly, how could I avoid that being seen by the user? I tried to $(document).hide(),or $('html,body').hide(), then fade in after a second,but I get other weird problems, especially on ipad,my fixed position top navigation bar will always become 'not fixed' while user is scrolling. As I am a self-learner, I afraid my method is not typical. I want to know what is the common ways of real web programmers usually do when they have to divide his webpage into different sections and set its height to window height , then make sure the other effects that's depends on the section height works properly and avoid to wait the height change for a second?

    Read the article

  • 2 ajax forms on the same page posting same textbox

    - by rod
    Hi All, Is it possible to post, say like a value in a textbox, to 2 different ajax forms that are on the same page? It doesn't have to be at the same time? What I'm trying to do is this: I have a search page that searches for customers and displays them on a paged grid. Users can specify up to 5 parameters (5 textboxes) to narrow the search. On the same page I have an export option. Well since I want all the customers for the search and not just the paged data I need a way to post back to the server for this option passing the same parameters used in the grid. I'm using a ViewModel which would be nice if I can pass that back to the server rather than the individual search fields that are backed by the view model. Thanks, rodchar

    Read the article

  • Is this correct about ajax POST?

    - by Tommy
    Could you confirm I understand this correctly. Using POST, the file specified in xmlhttp.open("GET","ajax_test.asp",true); will not be cached (sent to \Temporary Internet Files) ? It will stay on the server only? If this is true, is the updated html file after calling ajax POST, being updated in the \Temporary Internet Files ? Am I missing any other important information of this mechanism? Thank You.

    Read the article

  • How to get Auto-completion in ASP.NET MVC?

    - by Richard77
    Hello, In ASP.NET MVC, we don't have controls which can do stuffs such as autocompletion (we don't have controls at all from Visual Studio like in web forms). But, Is it possible to still get 'Auto-completion' with a text box in ASP.NET MVC (like with the textbox found on the Google's Home page)? If this is the case, what's the best way to do so? JQueryUI? or there's someother way of getting that functionality? Thanks for helping.

    Read the article

  • make selectable area using javascript

    - by Mher
    lets say I have a html page. <html> <body> ... This is my HTML Page, full of html objects and mouse events on them ... <div id='blocker' style="height: 100%; position: absolute; width: 100%; top: 0px; left: 0px; right: 0px; bottom: 0px; z-index: 1001; background: none repeat scroll 0% 0% black; opacity: 0.5;"></div> <div id='window_to_my_html_page' style="display: block; left: 50px; top: 50px; width: 200px; height: 200px; z-index: 1002; position: absolute;"></div> </body> </html> In this example div which id is 'blocker' will block all mouse events from my page. All my HTML page elements behind of my second div(which id is 'window_to_my_html_page') must be active, all mouse events must work on them, this div must be like a window to my HTML page I want to make all elements from my HTML page active(to work as normal) inside this area (left: 50px; top: 50px; width: 200px; height: 200px).... and other content, outside of this area make inactive The question: how can I do it?

    Read the article

  • Having an issue wit mouseup event

    - by user3680715
    Hello everyone I have this code working fine but I want the script to stop on the mouse up event. Here is an example of what I have now. How can I stop the script on mouse up event so that it looks like it only shows the coordinates when dragging over the image. Thank you! http://jsfiddle.net/Hc7x4/20/ $(document).ready(function () { $("#map-catcher").mousedown(function (e) { $("#map-catcher").mousemove(function (e) { $("#coord").text("x:"+e.offsetX+", y:"+e.offsetY); return; }); $("#map-catcher").mouseup(function (e) { return; }); }); });

    Read the article

  • Modifying html of dom element that was created after page loaded

    - by Ben321
    I have two separate AJAX calls. One that gets a list of items from a txt file and creates an HTML table out of them and one that talks to a database to find how much each item costs and then lists this in the corresponding table cell for each item (I know this may sound like a strange approach, but it's a good option in our case...). The issue is that the price is not getting written to the table since the table is created (or to be precise, the rows of the table are created) after the page loads. I'm not sure how to fix this. $(document).ready(function() { makeItemTable(); listPrices(); ... }); function makeItemTable() { $.ajax({ url: 'products.php', type: 'GET' }) .done(function(response) { $('.price-table > tbody').html(response); }) } function listPrices() { .ajax({ url: 'prices.php', type: 'GET' }) .done(function(response) { priceData = $.parseJSON(response); $('.price-table tr').each(function() { var item = $(this).find('td:nth-child(1)').text(); if (priceData[item]) { var price = priceData[item]; $(this).find('td:nth-child(2)').text(price); } }) }

    Read the article

  • call data without refresh

    - by faisal
    Hi all,,, I am trying to do a small thing, any 1 help me, I really appricciate... I have a drop down menu,I want when I select the value, it will call the related data, which I am access with php+mysql, I dont want to jump to other page and show

    Read the article

  • Submit event from few forms

    - by Coyod
    I have a two or more forms on my page in a row. I'm trying to hook submit event like: $('form',someObj).submit(function(e){ /* Do some stuff with ajax */ return false; }); But always receive events only from a first (by code) form. Also used each() function to bind event for each object, same thing.. What's wrong? Thanks!

    Read the article

  • performance issue with a website.

    - by pradeep
    Hi, I have a website .. [SPAM LINK REMOVED]. When you see pages like [SPAM LINK REMOVED] and [SPAM LINK REMOVED]. These pages load a bit slowly in FF. Please see if the speed is reasonable or speed needs to improve and in IE 6 it takes ages to load the website. Please let me know what all should i do to increase the performance of website. I tried all the options given by firebug. But nothing much helped. If any1 can let me know where all i should take care to increase the performance it will be very helpful.

    Read the article

  • Bind event to AJAX populated list items

    - by AnPel
    I have an unordered list with no list items. I get some information from the user, I run it through my database using AJAX and the servers sends back a JSON object response. Then I append each list item I want to display to the list using something like $('blabla').append('<li>information</li>') My question is, since the li elements were not there at the time the DOM was ready, how can I bind a click event to them? Here is my full code: $(function(){ var timer; $('#f').keyup(function(){ clearTimeout(timer); timer = setTimeout(getSuggestions, 400); }); }) function getSuggestions(){ var a = $('#f')[0].value.length; if( a < 3){ if(a == 0){ $('#ajaxerror').hide(300,function(){ $('#loading').hide(300,function(){ $('#suggest').hide(300) }) }) } return; } $('#loading').slideDown(200,function(){ $.ajax({ url: '/models/AJAX/suggest.php', dataType: 'json', data: {'data' : $('#f')[0].value }, success: function(response){ $('#ajaxerror').hide(0,function(){ $('#loading').hide(100,function(){ $('#suggest ul li').remove(); for(var b = 0; b < ( response.rows * 3); b = b + 3){ $('#suggest ul').append('<li>'+response[b]+' '+response[b+1]+' '+response[b+2]+'</li>') // MISSING SOME CODE HERE TO BIND CLICK EVENT TO NEWLY CREATED LI } $('#suggest').show(300) }) }) }, error: function(){ $('#suggest').hide(0,function(){ $('#loading').slideUp(100,function(){ $('#ajaxerror').show(300) }) }) } }) }) }

    Read the article

< Previous Page | 565 566 567 568 569 570 571 572 573 574 575 576  | Next Page >