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  • Free SVN repo server without requiring a project

    - by Nathan Campos
    I want to know if there are any free Subversion repository hosting servers where you don't need to have a 'project' to host your C++ files in. I don't have a actual project, but I want to store my C++ in an SVN repository. I am looking for something like OpenSVN where you can upload your C++ files, but it requires you to have a project. Can you recommend a Subversion hosting service where you can upload your files to an account, rather than a project. Something like: http://www.test-svn.com/~nathanpc/

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  • deploying project to tomcat ROOT

    - by stsd
    I have deployed my project to tomcat root, and it works fine without any problem. To acheive this I created a ROOT file TOMCAT_HOME/conf/Catalina/localhost/ROOT.xml with content below: <Context docBase="/home/user/project.war" path="" reloadable="true" /> So right now I can see my project under localhost:8080/ without any problem.. but I don't know where my project has been extracted, there is even no ROOT directory under TOMCAT_HOME/webapps, any idea?

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  • Problem to build Flex project.

    - by nemade-vipin
    hello friends, I have created one application when I have clean the project.And use the Build project option it is not building SWF file again.I want to reflect changes in my project.Please tell me how to build project in Flex builder.

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  • importing project in Eclipse

    - by Zachary
    Hello I am new to Eclipse (and I am a novice in Java): I am creating a project which should make use of some classes from another project. Do I have to export necessarily this last project as JAR file and add in my project? Are there other alternatives?

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  • PHP remote project and subversion

    - by jax
    I am working on a live remote php project in eclipse. ie, I just connect the the project using RSE edit the files and save. I have recently setup subeclipse and am wondering if there is an way to add my php files to a subversion project while still working on the live project? Or maybe there is a better way to do this and get the same result.

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  • How to open an existing project in .net c# in Visual studio 2008

    - by LS
    I already have a project folder, with relevant files inside. I need to change the working directory in Visual studio to this project folder, I just can't find how to do it in Visual studio. It seems I can only create a new project or open a solution file, but not set the working directory to the folder I want and start work on existing project. There is no solution file in the folder too.

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  • Size doesn't matter

    - by ssoolsma
    Whenever I start a new project I *always* break up my code in different projects. Also known as n-tier solution. The scale of  the project doesn't matter, but make sure that each project is responsible for himself (or herself if you prefer). I make sure that i ....At least thought about how the project should work on the toilet or in a project team meeting.Have a solution directory and create my projects within. I like to name my project (and it's folders by the namespaces). For instance: When i'm creating a piece of (web)software called: ChuckNorris, i always include the software name in my projects. Start off with designing the DataAccess project. I name it: ChuckNorris.DataAccess which lets me easily identify the project incase the project scales alot.Build the classes which represent the database structure. Don't stop working on a class untill it's finished for now. Also, don't over-do the methods. Build stuff only when it's needed, and not think: "Hm, that would be cool to have". Cause most of the time you end up with unused code, and we don't want that.Build a unittest project and make sure you create the folder inside the project that it's testing. So, create the ChuckNorris.DataAccess.UnitTest project inside the folder of the dataaccess project. I would suggest using the nUnit testframework.Incase you though, hm i skip unittest: Don't! Just build it - it will safe you alot of time later onNow, read 5 again. Build that bloody unittest. Don't skip. (i cant emphasize this enough)Now, every class in the dataaccess project is responsible for itself. They don't rely on each other. This is where we use the BusinessLogic project for. Start creating the ChuckNorris.BusinessLogic project. (not inside the data-access project ofcourse, but withing the ChuckNorris folder.Combine stuff from data-access. This usual involves alot of copying the data-access classes and feels silly at first. (we'll get to that later on)Now you come up to a point of creating a service project. You might not always see why to use it, but see it as a way to expose your businesslogic to any application (including your own). Sometimes i use it as a so-called "Factory". Every call goes through this factory, so that's the only thing i'm exposing to any program, and make sure that those methods are the only ones that I allow you to invoke.Build any UI (website, phoneapp, forms application, silverlight, wpf or whatever) and reference it to you service project. Fall in love (cough) with this approach.It's possible that it doesn't seem to make much sense, and very incomplete. Well, that last part is correct. Next post will go in to detail of setting up your Data-Access project and use the entity framework.

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  • Survey of project-administration experience [on hold]

    - by Salvador Beltrán
    My name is Salvador, I'm a Computer System Eng. Student and I'm searching for people to contribute with my research and I need real opinions - Experience (is an investigation for problems in the Project Management Area), just to be clear it can be any kind of project. If you help me with these 3 questions I would appreciate you so much! :) 1 - Any kind of problem that ocurred during the process of the project administration(Just the description). 2 - What was the impact? 3 - And what was the solution to avoid this problem in some future. 4 - What do you do(Software Engineering,Networking,etc). Thank you very much!

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  • Bigger ProjectServer farm is performing worse

    - by MSPS DBA
    I am using Project Server 2007 sp3 with SharePoint 2007 sp3 and SQL Server 2008 r2. I have recently moved my farm from 2 servers (1 DB and 1 App/Web) to a very big farm having Many Servers, Clustered Database, Load Balancer, Powerful processors and Large RAM. This Farm has more than one Web Servers, Project App Servers, SharePoint App Servers and a separate Index Server. But the performance of Project Server in the new Farm has been downgraded. Views are taking even more time to load data and Project publishing time has also been increased. I am also facing deadlock problems which are causing the project server queue jobs to fail. Could anyone inform me that what would be the reason of this problem and what should be the starting point to look into the issue? Is it mainly because now the application server needs to communicate with other application servers which were not needed in the previous farm? Thanks!

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  • Changing the name of a folder in php

    - by SpikETidE
    Hi everyone... All are aware of the rename function in php .... But is there a way to just change the name of a folder using php...? Or copying the whole folder to a new place with the intended name is the only way..? Thanks for your answers...

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  • Using Python to get a CSV output for the following example.

    - by Az
    Hi there, I'm back again with my ongoing saga of Student-Project Allocation questions. Thanks to Moron (who does not match his namesake) I've got a bit of direction for an evaluation portion of my project. Going with the idea of the Assignment Problem and Hungarian Algorithm I would like to express my data in the form of a .csv file which would end up looking like this in spreadsheet form. This is based on the structure I saw here. | | Project 1 | Project 2 | Project 3 | |----------|-----------|-----------|-----------| |Student1 | | 2 | 1 | |----------|-----------|-----------|-----------| |Student2 | 1 | 2 | 3 | |----------|-----------|-----------|-----------| |Student3 | 1 | 3 | 2 | |----------|-----------|-----------|-----------| To make it less cryptic: the rows are the Students/Agents and the columns represent Projects/Task. Obviously ONE project can be assigned to ONE student. That, in short, is what my project is about. The fields represent the preference weights the students have placed upon the projects (ranging from 1 to 10). If blank, that student does not want that project and there's no chance of him/her being assigned such. Anyway, my data is stored within dictionaries. Specifically the students and projects dictionaries such that: students[student_id] = Student(student_id, student_name, alloc_proj, alloc_proj_rank, preferences) where preferences is in the form of a dictionary such that preferences[rank] = {project_id} and projects[project_id] = Project(project_id, project_name) I'm aware that sorted(students.keys()) will give me a sorted list of all the student IDs which will populate the row labels and sorted(projects.keys()) will give me the list I need to populate the column labels. Thus for each student, I'd go into their preferences dictionary and match the applicable projects to ranks. I can do that much. Where I'm failing is understanding how to create a .csv file. Any help, pointers or good tutorials will be highly appreciated.

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  • Change -- to . for all files in a directory

    - by Larry
    Hello, I need to rename all the files in a directory. Some examples of the source filenames are: alpha--sometext.381928 comp--moretext.7294058 The resultant files would be renamed as: alpha.sometext.381928 comp.moretext.7294058 The number of characters before and after the -- is not consistant. The script needs to work on current installations of Ubuntu and FreeBSD. These are lean LAMP servers so only the necessary packages have been installed. Thanks

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  • Basic Application Organization + Publishing (.NET 4.0)

    - by keynesiancross
    Hi all, I'm trying to figure out the best way to keep my program organized. Currently I have many class files in one project file, but some of these classes do things that are very different, and some I would like to expose to other applications in the future. One thought I had to organizing my application was to create multiple project files, with one "Main" project, which would interact with all the other projects and their relevant classes as needed. Does this make sense? I was wondering if anyone had any suggestions in regards to using multiple project files in one solution (and how do you create something like this?), and if it makes sense to have multiple namespaces in one solution... Cheers ----Edit Below---- Sorry, my fault. Currently my program is all in one console project. Within this project I have several classes, some of which basically launch a BackgroundWorker and run an endless loop pulling data. The BackgroundWorker then passes this data back to the main business logic as needed. I'm hoping to seperate this data pull material (including the background worker material) into one project file, and the rest of the business logic into another project file. The projects will have to pass objects between eachother though (the data to the main business logic, and the business logic will pass startup parameteres to the dataPull project)... Hopefully this adds a bit more detail.

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  • apache+mod_wsgi configuration for django project(s) on a quad core

    - by Stefano
    I've been experiment quite some time with a "typical" django setting upon nginx+apache2+mod_wsgi+memcached(+postgresql) (reading the doc and some questions on SO and SF, see comments) Since I'm still unsatisfied with the behavior (definitely because of some bad misconfiguration on my part) I would like to know what a good configuration would look like with these hypotesis: Quad-Core Xeon 2.8GHz 8 gigs memory several django projects (anything special related to this?) These are excerpts form my current confs: apache2 SetEnv VHOST null #WSGIPythonOptimize 2 <VirtualHost *:8082> ServerName subdomain.domain.com ServerAlias www.domain.com SetEnv VHOST subdomain.domain AddDefaultCharset UTF-8 ServerSignature Off LogFormat "%{X-Real-IP}i %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-agent}i\"" custom ErrorLog /home/project1/var/logs/apache_error.log CustomLog /home/project1/var/logs/apache_access.log custom AllowEncodedSlashes On WSGIDaemonProcess subdomain.domain user=www-data group=www-data threads=25 WSGIScriptAlias / /home/project1/project/wsgi.py WSGIProcessGroup %{ENV:VHOST} </VirtualHost> wsgi.py import os import sys # setting all the right paths.... _realpath = os.path.realpath(os.path.dirname(__file__)) _public_html = os.path.normpath(os.path.join(_realpath, '../')) sys.path.append(_realpath) sys.path.append(os.path.normpath(os.path.join(_realpath, 'apps'))) sys.path.append(os.path.normpath(_public_html)) sys.path.append(os.path.normpath(os.path.join(_public_html, 'libs'))) sys.path.append(os.path.normpath(os.path.join(_public_html, 'django'))) os.environ['DJANGO_SETTINGS_MODULE'] = 'settings' import django.core.handlers.wsgi _application = django.core.handlers.wsgi.WSGIHandler() def application(environ, start_response): """ Launches django passing over some environment (domain name) settings """ application_group = environ['mod_wsgi.application_group'] """ wsgi application group is required. It's also used to generate the HOST.DOMAIN.TLD:PORT parameters to pass over """ assert application_group fields = application_group.replace('|', '').split(':') server_name = fields[0] os.environ['WSGI_APPLICATION_GROUP'] = application_group os.environ['WSGI_SERVER_NAME'] = server_name if len(fields) > 1 : os.environ['WSGI_PORT'] = fields[1] splitted = server_name.rsplit('.', 2) assert splitted >= 2 splited.reverse() if len(splitted) > 0 : os.environ['WSGI_TLD'] = splitted[0] if len(splitted) > 1 : os.environ['WSGI_DOMAIN'] = splitted[1] if len(splitted) > 2 : os.environ['WSGI_HOST'] = splitted[2] return _application(environ, start_response)` folder structure in case it matters (slightly shortened actually) /home/www-data/projectN/var/logs /project (contains manage.py, wsgi.py, settings.py) /project/apps (all the project ups are here) /django /libs Please forgive me in advance if I overlooked something obvious. My main question is about the apache2 wsgi settings. Are those fine? Is 25 threads an /ok/ number with a quad core for one only django project? Is it still ok with several django projects on different virtual hosts? Should I specify 'process'? Any other directive which I should add? Is there anything really bad in the wsgi.py file? I've been reading about potential issues with the standard wsgi.py file, should I switch to that? Or.. should this conf just be running fine, and I should look for issues somewhere else? So, what do I mean by "unsatisfied": well, I often get quite high CPU WAIT; but what is worse, is that relatively often apache2 gets stuck. It just does not answer anymore, and has to be restarted. I have setup a monit to take care of that, but it ain't a real solution. I have been wondering if it's an issue with the database access (postgresql) under heavy load, but even if it was, why would the apache2 processes get stuck? Beside these two issues, performance is overall great. I even tried New Relic and got very good average results.

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  • Extracting metadata from flac header in linux

    - by Tommy Fisk
    Hello. I recently (and accidentally) wiped a hard-drive which should NOT have been formatted. Thankfully, PhotoRec was able to recover some of the most important files from the disk. Part of those files include a large music collection of flac files. I've placed these in a folder named 'FLAC' that looks like this: [Start of FLAC Folder] f11655088.flac f11698672.flac ... (around 2,000 files total) f291142600.flac [End of FLAC Folder] I'm running a livecd to rescue this data. I have access to a standard terminal in Ubuntu 10.10. I've noticed that the music player in linux will display the song title when I open any of these songs. My goal is to automatically extract the song title from these files and update their names from f12313512.flac to 'Libera - Rebirth.flac' - or whatever the song title happens to be. Thanks in advance for suggestions on how I might accomplish this!

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  • renaming hard drives (sdc to sdb) on the fly

    - by w00t
    ata2: link is slow to respond, please be patient (ready=0) kernel: [2761026.198796] ata2: soft resetting link kernel: [2761031.226669] ata2.00: disabled kernel: [2761031.226720] ata2: EH complete kernel: [2761031.226753] sd 1:0:0:0: [sdb] Result: hostbyte=DID_BAD_TARGET driverbyte=DRIVER_OK,SUGGEST_OK After receiving the error above, I couldn't access /dev/sdb anymore. Not wanting to restart the server, I rescanned for the device using echo "- - -" > /sys/class/scsi_host/host1/scan and it readded the drive as /dev/sdc. From what I have found, I need to use echo "scsi add-single-device 0 0 3 0" > /proc/scsi/scsi, "3" being the SCSI ID which corresponds to sdb. Everything nice up to the point I execute the command and get -bash: echo: write error: Invalid argument. All the solutions point to using this method, but I am unable to. Any other method available? Debian 5.0.8 - 2.6.26-1-686

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  • Cannot log into Windows XP Embedded after changing computer name

    - by bignis
    Hi everyone, I purchased a tablet pc running Windows XP Embedded. The tablet was used in a medical clinic on a domain. For illustrative purposes, say the computer name was "COMPLEXCOMPUTERNAME". There was an administrator account, so I changed the password on account "COMPLEXCOMPUTERNAME\Administrator" to a blank password. I logged out and logged in successfully with the blank administrator password when the log-in dialog said "Log in to COMPLEXCOMPUTERNAME (this computer)". Next I renamed the computer from COMPLEXCOMPUTERNAME to SIMPLECOMPUTERNAME, which required a reboot. I did so, and I can't log in anymore. The log in screen still just says "Log in to COMPLEXCOMPUTERNAME (this computer)", but the account "COMPLEXCOMPUTERNAME\Administrator" no longer works. I suspect that this is because the computer has been renamed to SIMPLECOMPUTERNAME and it can no longer find the account. The "Log in to" dropdown can't be typed in, so I can't change the computer name Windows is trying to log into. I fear that I'm stuck. Is there a way I can get Windows to log into the computer name that I chose? Thanks! -Mike

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  • Run Bash Script Another Server

    - by psce
    I want to run command one by one, for change the names of the directories on the server. When I run script, directories renamed in server 1. But, directories are not found in server 2. What the error could be in the script? Script; #!/bin/bash mach_directory=/home/user/example erase_dir1=cache erase_dir2=tmp for i in {0..10} do user=user server=$(ssh $user@server$i hostname) ssh $user@$server find $mach_directory -type d -name $erase_dir1 ! -path "*Admin/$erase_dir1*" -print0 | while IFS= read -r -d '' file ; do mv "$file" "${file}_$(date +%d%m%Y)"; done ssh $user@$server find $mach_directory -type d -name $erase_dir2 ! -path "*Admin/$erase_dir2*" -print0 | while IFS= read -r -d '' file ; do mv "$file" "${file}_$(date +%d%m%Y)"; done done

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  • Batch renaming 32000 files - splitting into multiple subdirectories

    - by Gareth
    I've got a web server which has files uploaded to it. There is a script which assigns them numeric IDs and stores them in a corresponding subdirectory. I've now got 32000 of these uploads and that's too many for the server to handle in one directory. The script I'm using does have a way to "namespace" uploads so that ID 12345 - instead of sitting in /files/12345 - would sit in /files/namespaced/000/012/345. The code can deal with this just fine, but I now have 32000 subdirectories in the wrong naming style. What's the easiest way to go through my existing files and put them in the right place?

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  • Renaming Nginx 1.3.5 Server: response header

    - by Ryan
    In nginx 1.2 & 1.3 you can modify the source to change the name: src/http/ngx_http_header_filter_module.c (lines 48 and 49): static char ngx_http_server_string[] = "Server: Not Nginx" CRLF; static char ngx_http_server_full_string[] = "Server: Not Nginx/1.0" CRLF; Renaming those and recompiling the source changes the server response name in nginx 1.2. However doing this in 1.3 does not seem to change the name. It still says nginx/1.3.5 and with server_tokens off; it just says nginx. How can I change the server name in 1.3 without installing the 3rd party addon headers more? I want to compile from source.

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