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• zfdatagrid : how to set the relative order of columns?

  - by user522350

  To those of you who are familiar with zfdatagrid for the Zend framework: I got a recordset by a JOIN query, say from tables s and t, now I want to set the order in which the columns appear in the deployed table. For example, 5th column of table t to appear at the leftmost side, then 3rd column of table s, then 2nd column of table t, then 4th column of table s. How do I do this? Whatever I tried, it always shows first the columns of the left table of the JOIN, then the columns of the right table of the JOIN. I only know how to tell it which columns to show, but not their order. Thanks!

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• How do I list all tables in all databases in SQL Server in a single result set?

  - by msorens

  I am looking for T-SQL code to list all tables in all databases in SQL Server (at least in SS2005 and SS2008; would be nice to also apply to SS2000). The catch, however, is that I would like a single result set. This precludes the otherwise excellent answer from Pinal Dave: sp_msforeachdb 'select "?" AS db, * from [?].sys.tables' The above stored proc generates one result set per database, which is fine if you are in an IDE like SSMS that can display multiple result sets. However, I want a single result set because I want a query that is essentially a "find" tool: if I add a clause like WHERE tablename like '%accounts' then it would tell me where to find my BillAccounts, ClientAccounts, and VendorAccounts tables regardless of which database they reside in.

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• GWT synchronization

  - by hdantas

  i'm doing a function in gwt it sends an IQ stanza into a server and has to wait for the server answer in the function i make the handler that waits for the answer from the server to that IQ stanza so what i need is for the function to wait until i get the response from the server and after that do other stuff i'm a beginner in gwt so any thoughts would be great thanks public void getServices() { IQ iq = new IQ(IQ.Type.get); iq.setAttribute("to", session.getDomainName()); iq.addChild("query", "http://jabber.org/protocol/disco#items"); session.addResponseHandler(iq, new ResponseHandler() { public void onError(IQ iq, ErrorType errorType, ErrorCondition errorCondition, String text) { <do stuff> } public void onResult(IQ iq) { <do stuff> } }); session.send(iq); <after receiving answer do stuff> }

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• Poll database using jQuery/Ajax

  - by Gav

  Hi guys, I am trying to use jQuery (latest version) & ajax to poll a mysql db every x seconds, post.php does a simple search query on the table and limits to 1 row. (eg SELECT id FROM TABLE LIMIT 1) I've got some other jQuery UI (using v1.8) code that displays some modal/dialog boxes on the screen, simply put if post.php returns something from the db I need to initialise the dialog to pop up onto the screen. I've done all the popup stuff I am just having issues joining all these bits together - i've added some pseudo code of how i expect this to work. Thanks in advance var refreshId = setInterval(function(){ $.ajax({ type: "POST", url: "post.php", data: "", success: function(html){ $("#responsecontainer").html(html); } }); }, 2000 );s /* proposed pseudocode */ if (ajax is successful & returns a db row to #responsecontainer) { show jQueryUI modal (done this bit already fortunately) }

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• Fluent Nhibernate left join

  - by Ronnie

  I want to map a class that result in a left outer join and not in an innner join. My composite user entity is made by one table ("aspnet_users") and an some optional properties in a second table (like FullName in "users"). public class UserMap : ClassMap<User> { public UserMap() { Table("aspnet_Users"); Id(x => x.Id, "UserId").GeneratedBy.Guid(); Map(x => x.UserName, "UserName"); Map(x => x.LoweredUserName, "LoweredUserName"); Join("Users",mm=> { mm.Map(xx => xx.FullName); }); } } this mapping result in an inner join select so no result come out is second table as no data. I'd like to generate an left join. Is this possible only at query level?

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• How do I UPDATE a Linked Server table where "alias" is required, in SQL Server 2000?

  - by Mark Hurd

  In SQL Server 2005 tablename can be used to distinguish which table you're referring to: UPDATE LinkedServer.database.user.tablename SET val=u.val FROM localtable u WHERE tablename.ID=u.ID In SQL Server 2000 this results in Server: Msg 107, Level 16, State 2 The column prefix 'tablename' does not match with a table name or alias name used in the query. Trying UPDATE LinkedServer.database.user.tablename SET val=u.val FROM localtable u WHERE LinkedServer.database.user.tablename.ID=u.ID results in Server: Msg 117, Level 15, State 2 The number name 'LinkedServer.database.user.tablename' contains more than the maximum number of prefixes. The maximum is 3. And, of course, UPDATE LinkedServer.database.user.tablename SET val=u.val FROM localtable u WHERE ID=u.ID results in Server: Msg 209, Level 16, State 1 Ambiguous column name 'ID'. (In fact searching on "The number name contains more than the maximum number of prefixes. The maximum is 3." I found the answer, but I've typed up this question and I'm going to post it! :-) )

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• How to manually verify a user against the asp.net memberhip database

  - by Ekk

  I would like to know how I can verify a user's credential against an existing asp.net membership database. The short story is that we want provide single sign on access. So what I've done is to connect directly to the membership database and tried to run a sql query against the aspnet_Membership table: private bool CanLogin(string userName, string password) { // Check DB to see if the credential is correct try { string passwordHash = FormsAuthentication.HashPasswordForStoringInConfigFile(password, "SHA1"); string sql = string.Format("select 1 from aspnet_Users a inner join aspnet_Membership b on a.UserId = b.UserId and a.applicationid = b.applicationid where a.username = '{0}' and b.password='{1}'", userName.ToLowerInvariant(), passwordHash); using (SqlConnection sqlConn = new SqlConnection(ConfigurationManager.ConnectionStrings["LocalSqlServer"].ConnectionString)) using (SqlCommand sqlCmd = new SqlCommand(sql, sqlConn)) { sqlConn.Open(); int count = sqlCmd.ExecuteNonQuery(); sqlConn.Close(); return count == 1; } } catch (Exception ex) { return false; } } The problem is the password value, does anyone know how the password it is hashed?

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• SQLServer using too much memory

  - by Israel Pereira Valverde

  I have installed on my desktop machine (with windows 7) SQLServer 2008 R2 Express. I have only one local server running (./SQLEXPRESS) but the sqlserver process is taking ALL the RAM possible. With an machine with 3GB of RAM the things starts to get slow, so I limited the maximun amount of RAM in the server, and now, constantly the SQLServer give some error messages that the memory is not enought. It's using 1GB of RAM with only one LOCAL server with 2 databases completely empty, how 1GB of RAM isn't enought ? When the process start it's using an really acceptable amount of memory (around 80MB) but it's keep increasing until it reaches the maximun defined and start to complain about having not enought memory available. In that point I have to restart the server to use it again. I have read about an hotfix to solve one of the errors I got from sqlserver: There is insufficient system memory in resource pool 'internal' to run this query But it's already installed on my sqlserver. Why it's using so much memory?

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• Matching an IP address with an IP range?

  - by Legend

  I have a MySQL table setup as follows: +---------------+-------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+-------------+------+-----+---------+----------------+ | ipaddress_s | varchar(15) | YES | MUL | NULL | | | ipaddress_e | varchar(16) | YES | | NULL | | +---------------+-------------+------+-----+---------+----------------+ where, ipaddress_s and ipaddress_e look something like: 4.100.159.0-4.100.159.255 Now is there a way I can actually get the row that contains a given IP address? For instance, given the IP address: "4.100.159.5", I want the above row to be returned. So I am trying for a query that looks something like this (but of course this is wrong because in the following I am considering IPs as strings): SELECT * FROM ranges WHERE ipaddress_s<"4.100.159.5" AND ipaddress_e>"4.100.159.5" Any suggestions?

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• How can I selectively override a django .count() method

  - by Tom Viner

  I'm using postGresSQL and my main table has about 20,000 rows. Sometimes count() methods can take ages or even timeout. Mod.manager.filter(...).count() I need to selectively override the count() method depending on what filter has been applied. Just having a cache of results would be a great gain but I'd like to be able to say: if filter query is just {'enabled'=True} then return 20,000 without touching the db. Note: I can't prevent the call to .count() as it's inside django's pagination, which always does a count.

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• Linq to NHibernate - How to include parent object and only certain child objects

  - by vakman

  Given a simplified model like the following: public class Enquiry { public virtual DateTime Created { get; set; } public virtual Sender Sender { get; set; } } public class Sender { public virtual IList<Enquiry> Enquiries { get; set; } } How can you construct a Linq to Nhibernate query such that it gives you back a list of senders and their enquiries where the enquiries meet some criteria. I have tried something like this: return session.Linq<Enquiry>() .Where(enquiry => enquiry.Created < DateTime.Now) .Select(enquiry => enquiry.Sender) In this case I get an InvalidCastException saying you can't cast type Sender to type Enquiry. Any pointers on how I can do this without using HQL?

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• postscript to text

  - by SANJAY RAO

  I am working on a project to convert OCR'd PDf to png using ImageMagick and ghostscript and display in the browser so that i can select words in the image by letting a user query for the word . Imagemagick works fine along with ghostscript . I have a problem with the ps2text utility where it does not work reliably with pdf's . could anybody suggest a good utility to convert postscript to text in Linux so that i can store it in a db . thereafter i use a custom written search class to find out the co-ordinates of each word and highlight the text in the browser . Thanks

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• Reducing a normalized table to one value

  - by Dio

  Hello, I'm sure this has been asked but I'm not quite sure how to properly search for this question, my apologies. I have two tables, Foo and Bar. For has one row per Food, bar has many rows per food matching descriptors. Foo name id Apple 1 Orange 2 Bar id description 1 Tasty 1 Ripe 2 Sweet etc (sorry for the somewhat contrived example). I'm trying to return a query where if, for each row in Foo, Bar contains a descriptor in ('Tasty', 'Juicy') return true ex: Output Apple True Orange False I had been solving this somewhat trivially with a case when I only had one item to match select Foo.name, case bar.description when 'Tasty' then True else 'False' end from Foo left join Bar on foo.id = bar.id where bar.description = 'Tasty' But with multiple items, I keep ending up with extra rows: Output Apple True Apple False etc etc Can someone point me in the right direction on how to think about this problem or what I should be doing? Thank you.

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• Querying Active Directory in ruby app on Windows box

  - by Ben

  I have a small ruby app in which I'm trying to query some information from Active Directory. The app will be run by a Windows user who is already logged in. It looks like the ruby-net-ldap gem wants me to connect to an LDAP server using an IP address, port and then pass my username and password. Is there a way to achieve this (with a different gem, say) so that I don't have to pass this information (I don't have the current user's password for example, so that's not going to work)? I'm also hosting a Trac website on our intranet (which is written in Python if I remember correctly and that seems to know the current Windows username and domain. If it can do it, surely my little ruby app can access this information too?

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• Faster way to update 250k rows with SQL

  - by pablo

  I need to update about 250k rows on a table and each field to update will have a different value depending on the row itself (not calculated based on the row id or the key but externally). I tried with a parametrized query but it turns out to be slow (I still can try with a table-value parameter, SqlDbType.Structured, in SQL Server 2008, but I'd like to have a general way to do it on several databases including MySql, Oracle and Firebird). Making a huge concat of individual updates is also slow. What about creating a temp table and running an update joining my table and the tmp one? Will it work faster?

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• Sending variables in URLs in PHP with echo

  - by alexpelan

  Hi all, I can't really find good guidelines through google searches of the proper way to escape variables in URLs. Basically I am printing out a bunch of results from a mysql query in a table and I want one of the entries in each row to be a link to that result's page. I think this is easy, that I'm just missing a apostrophe or backslash somewhere, but I can't figure it out. Here's the line that's causing the error: echo "<a href = \"movies.php/?movie_id='$row['movie_id']'\"> Who Owns It? </a> "; and this is the error I'm getting: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING If you could elaborate in your answers about general guidelines for working with echo and variables in urls, that would be great. Thanks.

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• Java Desktop app with Ms Access.

  - by zayar

  My Db connection is error "class not found exception!". I want to show in java jTable with query result.. static Connection databaseConnection()throws ClassNotFoundException{ Connection con=null; File file=new File("PlayDb/PlayIS.mdb"); try{ Class.forName("sun.jdbc.odbc.jdbcodbcDriver"); con =DriverManager.getConnection("jdbc:odbc:Driver="+"{Microsoft Access Driver(*.mdb,*.accdb)};DBQ="+file.getAbsoluteFile()); System.out.print("Success con!!"); } catch(Exception e){ System.out.print("connection fail!!"); e.printStackTrace(); } return con; }

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• How can I pull data from a SQL Database that spans an academic year?

  - by Eric Reynolds

  Basically, I want to pull data from August to May for a given set of dates. Using the between operator works as long as I do not cross the year marker (i.e. BETWEEN 8 AND 12 works -- BETWEEN 8 AND 5 does not). Is there any way to pull this data? Here is the SQL Query I wrote: SELECT count(*), MONTH(DateTime) FROM Downloads WHERE YEAR(DateTime) BETWEEN 2009 AND 2010 AND MONTH(DateTime) BETWEEN 8 AND 5 GROUP BY MONTH(DateTime) ORDER BY MONTH(DateTime)" Any help is appreciated. Thanks, Eric R.

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• Reading data from database and binding them to custom ListView

  - by N.K.

  I try to read data from a database i have made and to show some of the data in a row at a custom ListView. I can not understand what is my mistake. This is my code: public class EsodaMainActivity extends Activity { public static final String ROW_ID = "row_id"; //Intent extra key private ListView esodaListView; // the ListActivitys ListView private SimpleCursorAdapter esodaAdapter; // adapter for ListView DatabaseConnector databaseConnector = new DatabaseConnector(EsodaMainActivity.this); // called when the activity is first created @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_esoda_main); esodaListView = (ListView)findViewById(R.id.esodaList); esodaListView.setOnItemClickListener(viewEsodaListener); databaseConnector.open(); //Cursor cursor= databaseConnector.query("esoda", new String[] // {"name", "amount"}, null,null,null); Cursor cursor=databaseConnector.getAllEsoda(); startManagingCursor(cursor); // map each esoda to a TextView in the ListView layout // The desired columns to be bound String[] from = new String[] {"name","amount"}; // built an String array named "from" //The XML defined views which the data will be bound to int[] to = new int[] { R.id.esodaTextView, R.id.amountTextView}; // built an int array named "to" // EsodaMainActivity.this = The context in which the ListView is running // R.layout.esoda_list_item = Id of the layout that is used to display each item in ListView // null = // from = String array containing the column names to display // to = Int array containing the column names to display esodaAdapter = new SimpleCursorAdapter (this, R.layout.esoda_list_item, cursor, from, to); esodaListView.setAdapter(esodaAdapter); // set esodaView's adapter } // end of onCreate method @Override protected void onResume() { super.onResume(); // call super's onResume method // create new GetEsodaTask and execute it // GetEsodaTask is an AsyncTask object new GetEsodaTask().execute((Object[]) null); } // end of onResume method // onStop method is executed when the Activity is no longer visible to the user @Override protected void onStop() { Cursor cursor= esodaAdapter.getCursor(); // gets current cursor from esodaAdapter if (cursor != null) cursor.deactivate(); // deactivate cursor esodaAdapter.changeCursor(null); // adapter now has no cursor (removes the cursor from the CursorAdapter) super.onStop(); } // end of onStop method // this class performs db query outside the GUI private class GetEsodaTask extends AsyncTask<Object, Object, Cursor> { // we create a new DatabaseConnector obj // EsodaMainActivity.this = Context DatabaseConnector databaseConnector = new DatabaseConnector(EsodaMainActivity.this); // perform the db access @Override protected Cursor doInBackground(Object... params) { databaseConnector.open(); // get a cursor containing call esoda return databaseConnector.getAllEsoda(); // the cursor returned by getAllContacts() is passed to method onPostExecute() } // end of doInBackground method // here we use the cursor returned from the doInBackground() method @Override protected void onPostExecute(Cursor result) { esodaAdapter.changeCursor(result); // set the adapter's Cursor databaseConnector.close(); } // end of onPostExecute() method } // end of GetEsodaTask class // creates the Activity's menu from a menu resource XML file @Override public boolean onCreateOptionsMenu(Menu menu) { super.onCreateOptionsMenu(menu); MenuInflater inflater = getMenuInflater(); inflater.inflate(R.menu.esoda_menu, menu); // inflates(eµf?s?) esodamainactivity_menu.xml to the Options menu return true; } // end of onCreateOptionsMenu() method //handles choice from options menu - is executed when the user touches a MenuItem @Override public boolean onOptionsItemSelected(MenuItem item) { // creates a new Intent to launch the AddEditEsoda Activity // EsodaMainActivity.this = Context from which the Activity will be launched // AddEditEsoda.class = target Activity Intent addNewEsoda = new Intent(EsodaMainActivity.this, AddEditEsoda.class); startActivity(addNewEsoda); return super.onOptionsItemSelected(item); } // end of method onPtionsItemSelected() // event listener that responds to the user touching a esoda's name in the ListView OnItemClickListener viewEsodaListener = new OnItemClickListener() { @Override public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) { // create an intent to launch the ViewEsoda Activity Intent viewEsoda = new Intent(EsodaMainActivity.this, ViewEsoda.class); // pass the selected esoda's row ID as an extra with the Intent viewEsoda.putExtra(ROW_ID, arg3); startActivity(viewEsoda); // start viewEsoda.class Activity } // end of onItemClick() method }; // end of viewEsodaListener } // end of EsodaMainActivity class The statement: Cursor cursor=databaseConnector.getAllEsoda(); queries all data (columns) From the data I want to show at my custom ListView 2 of them: "name" and "amount". But I still get a debugger error. Please help.

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• Container for database-like searches

  - by Milan Babuškov

  I'm looking for some STL, boost, or similar container to use the same way indexes are used in databases to search for record using a query like this: select * from table1 where field1 starting with 'X'; or select * from table1 where field1 like 'X%'; I thought about using std::map, but I cannot because I need to search for fields that "start with" some text, and not those that are "equal to". I could create a sorted vector or list and use binary search (breaking the set in 2 in each step by reading the element in the middle and seeing if it's more or less than 'X'), but I wonder if there is some ready-made container I could use without reinventing the wheel?

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• Searching algorithmics: Parsing and processing a request

  - by James P.

  Say you were to create a search engine that can accept a query statement under the form of a String. The statement can be used to retrieve different types of objects with a given set of characteristics and possibly linked to other objects. In plain english or pseudo-code using an OOP approach, how would you go about parsing and processing statements as follows to get the series of desired objects ? get fruit with colour green get variety of apples, pears from Andy get strawberry with colour "deep red" and origin not Spain get total of sales of melons between 2010-10-10 and 2010-12-30 get last deliverydate of bananas from "Pete" and state not sold Hope the question is clear. If not I'll be more than happy to reformulate. P.S: This isn't homework ;)

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• How to add condition on multiple-join table

  - by Jean-Philippe

  Hi, I have those two tables: client: id (int) #PK name (varchar) client_category: id (int) #PK client_id (int) category (int) Let's say I have those datas: client: {(1, "JP"), (2, "Simon")} client_category: {(1, 1, 1), (2, 1, 2), (3, 1, 3), (4,2,2)} tl;dr client #1 has category 1, 2, 3 and client #2 has only category 2 I am trying to build a query that would allow me to search multiple categories. For example, I would like to search every clients that has at least category 1 and 2 (would return client #1). How can I achieve that? Thanks!

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• Subquery Doctrine Couldn't find class

  - by yosesita

  I'm trying to create a query like this one : $q = Doctrine_Query::create() -select('p.nombre') -addSelect('(select count(*) from alojamiento a left join localidad l on a.localidad_id=l.id where p.id=l.provincia_id and a.activo=true)') -from('provincia p'); but it fails : error 500, couldn't find class a. And : $q = Doctrine_Query::create() -select('nombre') -addSelect('(select count(*) from alojamiento left join localidad on alojamiento.localidad_id=localidad.id where provincia.id=localidad.provincia_id and alojamiento.activo=true)') -from('provincia'); leads to : SQLSTATE[42S22]: Column not found: 1054 Unknown column 'a.localidad_id' in 'on clause'. Any help would be greatly appreciated !

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• Storing SQL queries in Table in sql server

  - by Rohit

  We have multiple jobs in our system.These jobs are listed in a grid. We have 3 different user types (usertypeid 1,2,3). For each user listing is different and he can filter listing by selecting view from a dropdown. ViewName in the below table is the view which needs to be displayed. To achieve this functionality, a fellow developer has created the following table structure and stored sql fragments in SQLExpression in the below table. According to me the query should not be stored in database. What are the pros and cons of this approach and what are the available alternatives? JobListingViewID ViewName SQLExpression UserTypeID 3 All Jobs 1 = 1 3 4 Error Jobs JobStatusID IN ( 2 ) 1 5 Error Jobs JobStatusID IN ( 2 ) 2 6 Error Jobs JobStatusID IN ( 2 ) 3 7 Speech JobStatusID IN ( 1, 3, 8 ) 1

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• Zip Code to City/State and vice-versa in a database?

  - by Simucal

  I'm new to SQL and relational databases and I have what I would imagine is a common problem. I'm making a website and when each user submits a post they have to provide a location in either a zip code or a City/State. What is the best practice for handling this? Do I simply create a Zip Code and City and State table and query against them or are there ready made solutions for handling this? I'm using SQL Server 2005 if it makes a difference. I need to be able to retrieve a zip code given a city/state or I need to be able to spit out the city state given a zip code.

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