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  • Open txt files from a directory, compare the values, and output the top 15 in PHP

    - by Anon
    Hello, I recently designed a referral game website for the fun of it. There's a simple MySQL user system with a email verification. It's using the UserCake user management system. On top of this i added a php page that the user could give to "victims" that when they visit it they get "infected" and can infect other users or "victims". This page uses GET to get the username from the url. I have a folder that when a user registers it creates a file with 4 digits and then the username. (ex; 0000Username.txt) All the numbers are the same, it's just so that if a user discovers the folder they won't be able to find the files. There is also a txt file in the same format with IPS in the name. (ex; 0000IPSUsername.txt) The file when visited gets the username from the url, then checks if the text file for that username exists. If the username is present in the url, and a valid user it opens the IPS file and adds the IP of the visitor, then opens the user text file, takes the value and adds one to it, and saves. At the end it makes the difference between saying "You are infected, Username has infected (amount) people." or just you have been infected. Now to what i need! I need to add a hi-scores to the website so people can compete to be the one with the most "infections". I thought i could use readdir to get a list of the files and open them with the value in an array, but i need it to also strip the username from the file name. It would be best if it just saves to a text file like "Username | value" because then i can add echo's of the html tags and have it include the file in the page i want it to be one. Many thanks in advance.

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  • Weird character at start of json content type

    - by Nek
    Hi, I'm trying to return json content read from MySQL server. This is supposed to be easy but, there is a 'weird' character that keeps appearing at start of the content. I have two pages for returning content: kcb433.sytes.net/as/test.php?json=true&limit=6&input=d this test.php is from a script written by Timothy Groves, which converts an array to json output http://kcb433.sytes.net/k.php?k=4 this one is supposed to do the same I tried to validate it here jsonformatter.curiousconcept.com but just page 1 gets validated, page 2 says that it does not contain JSON data. If accessed directly both pages has no problems. Then what is the difference, why both don't get validated? Then I found this page jsonformat.com and tried the same thing. Page 1 was ok and page 2 wasn't but, surprisingly the data could be read. At a glance, {"a":"b"} may look good but there is a character in front. According to a hex editor online, this is the value of the string above (instead of 9 values, there are 10): -- 7B 22 61 22 3A 22 62 22 7D The code to echo json in page 2 is: header("Content-Type: application/json"); echo "{\"a\":\"b\"}";

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  • PHP code displayed in browser

    - by Drake
    so, I'm working on a databases project, and i'm trying to code incrementally. the problem is, when i go to test the php in browser, it displays the php code after my use of "-". the html printing is displayed properly, which is AFTER the point where the - is. here is the php: <?php function getGraphicNovel(){ include_once("./connect.php"); $db_connection = new mysqli($SERVER, $USERNAME, $PASSWORD, $DATABASE); if (mysqli_connect_errno()) { echo("Can't connect to MySQL Server. Error code: " . mysqli_connect_error()); return null; } $stmt = $db_connection->stmt_init(); $returnValue = "invalid"; if($stmt.prepare("select series from graphic_novel_main natural join graphic_novel_misc")) { $stmt->execute(); $stmt->bind_result($series); while ($stmt->fetch()) { echo "<tr><td>" . $series . "</td></tr>"; } $stmt->close(); } $db_connection->close(); } getGraphicNovel(); ?> here is a link to the page. hopefully it works for people outside the school's network. http://plato.cs.virginia.edu/~paw5k/cainedb/viewall.html if anyone knows why this is happening, your input would be great!

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  • How to organize and manage multiple database credentials in application?

    - by Polaris878
    Okay, so I'm designing a stand-alone web service (using RestLET as my framework). My application is divided in to 3 layers: Data Layer (just above the database, provides APIs for connecting to/querying database, and a database object) Object layer (responsible for serialization from the data layer... provides objects which the client layer can use without worrying about database) Client layer (This layer is the RestLET web service... basically just creates objects from the object layer and fulfills webservice request) Now, for each object I create in the object layer, I want to use different credentials (so I can sandbox each object...). The object layer should not know the exact credentials (IE the login/pw/DB URL etc). What would be the best way to manage this? I'm thinking that I should have a super class Database object in my data layer... and each subclass will contain the required log-in information... this way my object layer can just go Database db = new SubDatabase(); and then continue using that database. On the client level, they would just be able to go ItemCollection items = new ItemCollection(); and have no idea/control over the database that gets connected. I'm asking this because I am trying to make my platform extensible, so that others can easily create services off of my platform. If anyone has any experience with these architectural problems or how to manage this sort of thing I'd appreciate any insight or advice... Feel free to ask questions if this is confusing. Thanks! My platform is Java, the REST framework I'm using is RestLET, my database is MySQL.

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  • PHP arrays - How to 1-dimensional array into nested multidimensional array?

    - by sombe
    When retrieving a hierarchical structure from MySQL (table with one ID column and one PARENT column signifying the hierarchical relationships), I map the result into an enumerated array as follows (for this example the numbers are arbitrary): Array ( [3] => Array ( [7] => Array () ), [7] => Array ( [8] => Array () ) ) Notice 3 is the parent of 7, and 7 is the parent of 8 (this could go on and on; and any parent could have multiple children). I wanted to shrink this array into a nested multidimensional array as follows: Array ( [3] => Array ( [7] => Array ( [8] => Array () ) ) ) That is, each NEW id is automatically assigned an empty array. Regardless, any ID's children will be pushed into their parent's array. Take a look at the following illustration for further clarification: This will probably result in a complicated recursive operation, since I always have to check whether a parent with any certain ID already exists (and if so, push the value into its array). Is there a built-in php function that can assist me with this? Do you have any idea as to how to go about constructing this? For what it's worth I'm using this to built a navigation bar in wordpress (which can contain categories, subcategories, posts... essentially anything).

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  • Advice needed: cold backup for SQL Server 2008 Express?

    - by Mikey Cee
    What are my options for achieving a cold backup server for SQL Server Express instance running a single database? I have an SQL Server 2008 Express instance in production that currently represents a single point of failure for my application. I have a second physical box sitting at the installation that is currently doing nothing. I want to somehow replicate my database in near real time (a little bit of data loss is acceptable) to the second box. The database is very small and resources are utilized very lightly. In the case that the production server dies, I would manually reconfigure my application to point to the backup server instead. Although Express doesn't support log shipping, I am thinking that I could manually script a poor man's version of it, where I use batch files to take the logs and copy them across the network and apply them to the second server at 5 minute intervals. Does anyone have any advice on whether this is technically achievable, or if there is a better way to do what I am trying to do? Note that I want to avoid having to pay for the full version of SQL Server and configure mirroring as I think it is an overkill for this application. I understand that other DB platforms may present suitable options (eg. a MySQL Cluster), but for the purposes of this discussion, let's assume we have to stick to SQL Server.

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  • Software Company Library

    - by dbemerlin
    Hi. A few days ago i had the idea to create a company library since my company has no training and many developers still develop as they did when they learned it 5 years ago. My hope is that they can lend books, read them and hopefully learn something from them (for example: object oriented programming or unit testing, which noone here knows how to use). After asking around most agreed that it was a good idea, so i brought my books, made a simple printed sheet with "Book A belongs to B" and "Developer A took the Book on dd.mm.yyyy" to get it started. Now i want to get some ideas for Books that i could add to the shelf (sadly from my own money since 100€/month for training is too much money for this multi-million euro company). We develop mostly PHP & MySQL so books specific to this topic would be preferred but i think if people learn other languages they might get ideas on how to develop better with the current language so other books are ok, too. Which books would you recommend? PS: Personally i'd like to add some Project Management books, too, as it's a topic i'm interested in, eventhough i'm just a junior developer (We've got Peopleware already, great book btw).

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  • POSTmethod and PHP- login verification

    - by Neethusha
    I wrote a code for login verification..I got output with GET. But i need output with POST since it is more secure.pls let me know if there is any error in my code. javascript code: var xml; function verifyusernamepasswd(pass) { //pass is password that will be passed as parameter xml=new XMLHttpRequest(); var url="http://localhost/loginvalidate.php"; var para="q="+username+"&p="+pass;//username is global xml.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xml.setRequestHeader("Content-length", para.length); xml.setRequestHeader("Connection", "close"); xml.open("POST",url,true); xml.onreadystatechange=statechanged1; xml.send(para); } function statechanged1() { if(xml.readyState==4) alert(xml.responseText); } php code: <?php $username=$_POST["q"]; $password=$_POST["p"]; $con=mysql_connect("localhost","root","blaze"); if(!$con) { die('Could not connect: '.mysql.error()); } mysql_select_db("BLAZE",$con) or die("No such Db"); $result=mysql_query("SELECT Passwword FROM USERTABLE WHERE Userhandle='$username'"); if($result==null) echo "false"; else if($result!=null) { $row=mysql_fetch_array($result); if((strcmp($row['Passwword'],$password)==0)) echo "true"; else echo "false"; } ?> the verification does not return anything, cos my alert is not displayed at all...pls tell me whats wrong....

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  • Hibernate collection mapping Problem

    - by Geln Yang
    Hi, There is a table Item like, code,name 01,parent1 02,parent2 0101,child11 0102,child12 0201,child21 0202,child22 Create a java object and hbm xml to map the table.The Item.parent is a Item whose code is equal to the first two characters of its code : class Item{ String code; String name; Item parent; List<Item> children; .... setter/getter.... } <hibernate-mapping> <class name="Item" table="Item"> <id name="code" length="4" type="string"> <generator class="assigned" /> </id> <property name="name" column="name" length="50" not-null="true" /> <many-to-one name="parent" class="Item" not-found="ignore"> <formula> <![CDATA[ (select i.code,r.name from Item i where (case length(code) when 4 then i.code=SUBSTRING(code,1,2) else false end)) ]]> </formula> </many-to-one> <bag name="children"></bag> </class> </hibernate-mapping> I try to use formula to define the many-to-one relationship,but it doesn't work!Is there something wrong?Or is there other method? Thanks! ps,I use mysql database.

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  • php syntax confusion accessing database result

    - by Babak
    I am trying to do the following: <?php foreach($sqlResult as $row): ?> <tr> <?php foreach($formdata['columns'] as $column): ?> <td><?php echo $row->$column['name']; ?></td> <?php endforeach; ?> </tr> <?php endforeach; ?> This does not work. $row is returned by my mysql query, it has the following : row-id, row-author, row-name and these work as they echo fine. $columns is the following array: 'columns' => array ( 1 => array ( 'name' => 'id' ), 2 => array ( 'name' => 'author' ), 3 => array ( 'name' => 'date' ), 4 => array ( 'name' => 'title' ) it also works fine as $column['name'] echoes id, author, date, title my question is how would it be possible for me to access the $row-method (is it a method?) by passing it a name from the array??

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  • PHP/Javascript limiting amount of checkboxes

    - by Carl294
    Hi everyone Im trying to limit the amount of checkboxes that can be checked, in this case only 3 can be checked. When using plain HTML this works fine. The code can be seen below. HTML example <td ><input type=checkbox name=ckb value=2 onclick='chkcontrol()';></td><td>Perl</td> Javascript Function <script type="text/javascript"> function chkcontrol(j) { var total=0; for(var i=0; i < document.form1.ckb.length; i++){ if(document.form1.ckb[i].checked){ total =total +1;} if(total > 3){ alert("Please Select only three") document.form1.ckb[j].checked = false; return false; } } } </script> The problem appears when replacing the fixed HTML values with values from a MYSQL database. All the information appears correctly, and can be posted to another page via a submit button. However, it seems like the 'value' assigned to each record from the database is not making its way too the javascript function. <td><input name="checkbox[]" type="checkbox" value="<?php echo $rows['TCA_QID'];?>" onclick="chkcontrol();"></td> I have tried changed the name in the javascript function to match the 'checkbox' name.Any advice would be greatly appreciated Thanks

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  • What's the next steps for moving from appengine to full django?

    - by tomcritchlow
    Hey guys, I'm super new to programming and I've been using appengine to help me learn python and general coding. I'm getting better quickly and I'm loving it all the way :) Appengine was awesome for allowing me to just dive into writing my app and getting something live that works (see http://www.7bks.com/). But I'm realising that the longer I continue to learn on appengine the more I'm constraining myself and locking myself into a single system. I'd like to move to developing on full django (since django looks super cool!). What are my next steps? To give you a feel for my level of knowledge: I'm not a unix user I'm not familiar with command line controls (I still use appengine/python completely via the appengine SDK) I've never programmed in anything other than python, anywhere other than appengine I know the word SQL, but don't know what MySQL is really or how to use it. So, specifically: What are the skills I need to learn to get up and running with full django/python? If I'm going to host somewhere else I suppose I'll need to learn some sysadmin type skills (maybe even unix?). Is there anywhere that offers easy hosting (like appengine) but that supports django? I hear such great things about heroku I'm considering switching to RoR and going there I appreciate that I'm likely not quite ready to move away from appengine just yet but I'm a fiercely passionate learner (http://www.7bks.com/blog/179001) and would love it if I knew all the steps I needed to learn so I could set about learning them. At the moment, I don't even know what the steps are I need to learn! Thank you very much. Sorry this isn't a specific programming question but I've looked around and haven't found a good how-to for someone of my level of experience and I think others would appreciate a good roadmap for the things we need to learn to get up and running. Thanks, Tom PS - if anyone is in London and fancies showing me the ropes in person that would be super awesome :)

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  • Projects integration question

    - by qkrsppopcmpt
    Other team has one legacy system, which is data aggregators. It is implemented as web service using JAVA, SOAP,MTOM,Tomcat and Axis2. They have wsdl files defining functionalities such as search, retrieve data, upload, download. Our team has a new developed website which is developed using RoR with mySQL. It is sort of social networking. Users can register, add friends, upload images, videos. Also, they can search data. We are required to connect the two systems. One possible solution I think is - Adding components into our website. The component invoke services on the aggregators. - Synchronize website database to the aggregators. My doubts are: 1. How to add components in our websites? The components should use Java or Ruby or adapter from java to ruby. It is possible using ruby invoke web service. I think it should work since it is the point of web service. If so, can ruby call those services in wsdl directly? But how to deal with those different data structure? How to synchroinze our database to the aggregators. I think the best way is also through web service invocation such as upload. That means, we have to export the db records into xml files and then write some tools to upload. The web service project support MTOM. So, it is fine to upload huge data. Am I on the right record? Can anybody give me some hint. Thanks.

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  • PHP -- automatic SQL injection protection?

    - by ashgromnies
    I took over maintenance of a PHP app recently and I'm not super familiar with PHP but some of the things I've been seeing on the site are making me nervous that it could be vulnerable to a SQL injection attack. For example, see how this code for logging into the administrative section works: $password = md5(HASH_SALT . $_POST['loginPass']); $query = "SELECT * FROM `administrators` WHERE `active`='1' AND `email`='{$_POST['loginEmail']}' AND `password`='{$password}'"; $userInfo = db_fetch_array(db_query($query)); if($userInfo['id']) { $_SESSION['adminLoggedIn'] = true; // user is logged in, other junk happens here, not important The creators of the site made a special db_query method and db_fetch_array method, shown here: function db_query($qstring,$print=0) { return @mysql(DB_NAME,$qstring); } function db_fetch_array($qhandle) { return @mysql_fetch_array($qhandle); } Now, this makes me think I should be able to do some sort of SQL injection attack with an email address like: ' OR 'x'='x' LIMIT 1; and some random password. When I use that on the command line, I get an administrative user back, but when I try it in the application, I get an invalid username/password error, like I should. Could there be some sort of global PHP configuration they have enabled to block these attacks? Where would that be configured? Here is the PHP --version information: # php --version PHP 5.2.12 (cli) (built: Feb 28 2010 15:59:21) Copyright (c) 1997-2009 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2009 Zend Technologies with the ionCube PHP Loader v3.3.14, Copyright (c) 2002-2010, by ionCube Ltd., and with Zend Optimizer v3.3.9, Copyright (c) 1998-2009, by Zend Technologies

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  • Multidimensional array (parent and childs)

    - by Juan
    I have a category system in a MySQL database with parents and childs. The database only stores the id of it''s immediate parent (or 0 if on root). Since the system allows multiple subcategories there are cases of multiple childs. For example [98] Storage [1] External [3] Pendrives [4] Portable hhdds [2] Internal [5] Sata hhdd [6] IDE hhdd [...] [99] Clothing The database would be id parent_id name 1 98 External 2 98 Internal 3 1 Pendrives 4 1 Portable 5 2 Sata 6 2 IDE 98 0 Storage 99 0 Clothing I also have a products table with a category id and I need to get a list of all the products in the first level of categories. For example: Product Category A 3 B 4 C 5 D 6 E 74 Should return 98: A, B, C, D 99: X, Y, Z... I'm stuck and I can't think of the logic to retrieve it in that way. I started by getting the IDs of all the categories that aren't in the first level by: while ($row = mysql_fetch_assoc($result)) { if ($row['parent_id'] != 0) { $level1[$i]['name'] = utf8_encode($row['categories_name']); $level1[$i]['id'] = $row['categories_id']; } $i++; } but I'm having a burnout and can't think of a way that would nest them. I thought some kind of while but it's infinite :P Any ideas please?

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  • SELECT * FROM <table> BETWEEN <value typed in a JTextField> AND <idem>

    - by Rodrigo Sieja Bertin
    In this part of the program, the JInternalFrame file FrmMovimento, I made a button called Visualizar ("View"). Based on what we type on the text fields, it must show the interval the user defined. There are these JTextFields: Code from: _ To: _ Asset: _ And these JFormattedTextFields: Date from: _ To: _ There are registers appearing already in the JDesktopPane from JInternalFrame FrmListarMov, if I use another SELECT statement selecting all registers, for example. But not if I type as I did in the title: public List<MovimentoVO> Lista() throws ErroException, InformacaoException{ List<MovimentoVO> listaMovimento = new ArrayList<> (); try { MySQLDAO.getInstancia().setAutoCommit(false); try (PreparedStatement stmt = MySQLDAO.getInstancia().prepareStatement( "SELECT * FROM Cadastro2 WHERE Codigo BETWEEN "+ txtCodDeMov +" AND "+ txtCodAteMov +";") { ResultSet registro = stmt.executeQuery(); while(registro.next()){ MovimentoVO Movimento = new MovimentoVO(); Movimento.setCodDeMov(registro.getInt(1)); Movimento.setCodAteMov(registro.getInt(2)); Movimento.setAtivoMov(registro.getString(3)); Movimento.setDataDeMov(registro.getString(4)); Movimento.setDataAteMov(registro.getString(5)); listaMovimento.add(Movimento); } } } catch (SQLException ex) { throw new ErroException(ex.getMessage()); } catch (InformacaoException ex) { throw ex; } return listaMovimento; } In the SELECT line, txtCodDeMov is how I named the JTextField of "Code from" and txtCodAtemov is how I named the JTextField of the first "To". Oh, I'm using NetBeans 7.1.2 (Build 201204101705) and MySQL Ver 14.14 Distrib 5.1.63 in a Linux Mint 12 64-bits.

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  • Spring Security ACL: NotFoundException from JDBCMutableAclService.createAcl

    - by user340202
    Hello, I've been working on this task for too long to abandon the idea of using Spring Security to achieve it, but I wish that the community will provide with some support that will help reduce the regret that I have for choosing Spring Security. Enough ranting and now let's get to the point. I'm trying to create an ACL by using JDBCMutableAclService.createAcl as follows: [code] public void addPermission(IWFArtifact securedObject, Sid recipient, Permission permission, Class clazz) { ObjectIdentity oid = new ObjectIdentityImpl(clazz.getCanonicalName(), securedObject.getId()); this.addPermission(oid, recipient, permission); } @Override @Transactional(propagation = Propagation.REQUIRED, isolation = Isolation.READ_UNCOMMITTED, readOnly = false) public void addPermission(ObjectIdentity oid, Sid recipient, Permission permission) { SpringSecurityUtils.assureThreadLocalAuthSet(); MutableAcl acl; try { acl = this.mutableAclService.createAcl(oid); } catch (AlreadyExistsException e) { acl = (MutableAcl) this.mutableAclService.readAclById(oid); } // try { // acl = (MutableAcl) this.mutableAclService.readAclById(oid); // } catch (NotFoundException nfe) { // acl = this.mutableAclService.createAcl(oid); // } acl.insertAce(acl.getEntries().length, permission, recipient, true); this.mutableAclService.updateAcl(acl); } [/code] The call throws a NotFoundException from the line: [code] // Retrieve the ACL via superclass (ensures cache registration, proper retrieval etc) Acl acl = readAclById(objectIdentity); [/code] I believe this is caused by something related to Transactional, and that's why I have tested with many TransactionDefinition attributes. I have also doubted the annotation and tried with declarative transaction definition, but still with no luck. One important point is that I have used the statement used to insert the oid in the database earlier in the method directly on the database and it worked, and also threw a unique constraint exception at me when it tried to insert it in the method. I'm using Spring Security 2.0.8 and IceFaces 1.8 (which doesn't support spring 3.0 but definetely supprorts 2.0.x, specially when I keep caling SpringSecurityUtils.assureThreadLocalAuthSet()). My AppServer is Tomcat 6.0, and my DB Server is MySQL 6.0 I wish to get back a reply soon because I need to get this task off my way

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  • Why does multiple sessions started on the same page gets the same session id?

    - by Calmarius
    I tryed the following: <?php session_name('user'); session_start(); // sets an 'user' cookie with session id. // This session stores the user's login data. // Its an ordinary session. $USERSESSION=$_SESSION; // saving this session $userSessId=session_id(); session_write_close(); //closing this session session_name('chatroom'); session_start(); // set a 'chatroom' cookie but contains the same session id and points to the same data :( . // This session would be used to store the chat text. This session would be // shared between all users joined in this chat room by setting the same session id for all members. // by calling session_regenerate_id would make a diffent session id for every user and it won't be a chat room anymore. ?> So I want to do a chat like thing with sessions. On the client side it would be done with ajax that polls this php page in every 5-10 seconds. Sessions may be cached in the server's memory so it can be accessible fast. I can store the chat in the database but my service runs on a free webhost which is limited, only 4 mysql connections allowed at a time which is almost nothing. I try to touch my database as least times as possible.

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  • Hibernate mapping Problem

    - by Geln Yang
    Hi, There is a table Item like, code,name 01,parent1 02,parent2 0101,child11 0102,child12 0201,child21 0202,child22 Create a java object and hbm xml to map the table.The Item.parent is a Item whose code is equal to the first two characters of its code : class Item{ String code; String name; Item parent; List<Item> children; .... setter/getter.... } <hibernate-mapping> <class name="Item" table="Item"> <id name="code" length="4" type="string"> <generator class="assigned" /> </id> <property name="name" column="name" length="50" not-null="true" /> <many-to-one name="parent" class="Item" not-found="ignore"> <formula> <![CDATA[ (select i.code,r.name from Item i where (case length(code) when 4 then i.code=SUBSTRING(code,1,2) else false end)) ]]> </formula> </many-to-one> <bag name="children"></bag> </class> </hibernate-mapping> I try to use formula to define the many-to-one relationship,but it doesn't work!Is there something wrong?Or is there other method? Thanks! ps,I use mysql database.

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  • If we make a number every millisecond, how much data would we have in a day?

    - by Roger Travis
    I'm a bit confused here... I'm being offered to get into a project, where would be an array of certain sensors, that would give off reading every millisecond ( yes, 1000 reading in a second ). Reading would be a 3 or 4 digit number, for example like 818 or 1529. This reading need to be stored in a database on a server and accessed remotely. I never worked with such big amounts of data, what do you think, how much in terms of MBs reading from one sensor for a day would be?... 4(digits)x1000x60x60x24 ... = 345600000 bits ... right ? about 42 MB per day... doesn't seem too bad, right? therefor a DB of, say, 1 GB, would hold 23 days of info from 1 sensor, correct? I understand that MySQL & PHP probably would not be able to handle it... what would you suggest, maybe some aps? azure? oracle? ... Thansk!

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  • rails not recognizing project

    - by tipu
    I can create a new project using rails and I can use stuff like rails migration ... and i (correctly) get a error because the sqlite gem is missing. but when i try using rails migration ... with a project i checked out from github, it doesn't recognize that it is a rails project i get: Usage: rails new APP_PATH [options] Options: -d, [--database=DATABASE] # Preconfigure for selected database (options: mysql/oracle/postgresql/sqlite3/frontbase/ibm_db) # Default: sqlite3 -O, [--skip-active-record] # Skip Active Record files [--dev] # Setup the application with Gemfile pointing to your Rails checkout -J, [--skip-prototype] # Skip Prototype files -T, [--skip-test-unit] # Skip Test::Unit files -G, [--skip-git] # Skip Git ignores and keeps -b, [--builder=BUILDER] # Path to an application builder (can be a filesystem path or URL) [--edge] # Setup the application with Gemfile pointing to Rails repository -m, [--template=TEMPLATE] # Path to an application template (can be a filesystem path or URL) -r, [--ruby=PATH] # Path to the Ruby binary of your choice # Default: /usr/bin/ruby1.8 [--skip-gemfile] # Don't create a Gemfile and it goes on. any ideas? edit: it's probably an important detail that earlier my rails wasn't working at all. i had to cp /usr/bin/ruby to /usr/bin/local/ruby

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  • Why NOT use POST method here?

    - by Camran
    I have a classifieds website. In the main page (index) I have several form fields which the user may or may not fill in, in order to specify a detailed search of classifieds. Ex: Category: Cars Price from: 3000 Price to: 10000 Color: Red Area: California The forms' action is set to a php page: <form action='query_sql.php' method='post'> In query_sql.php I fetch the variables like this: category=$_POST['category']; etc etc... Then query MySql: $query="SELECT........WHERE category='$category' etc etc.... $results = mysql_query($query); Then I simply display the results of the query to the user by creating a table which is filled in dynamically depending on the results set. However, according to an answer by Col. Shrapnel in my previous Q I shouldn't use POST here: http://stackoverflow.com/questions/3004754/how-to-hide-url-from-users-when-submitting-this-form The reason I use post is simply to hide the "one-page-word-document" long URL in the browsers adress bar. I am very confused, is it okay to use POST or not? It is working fine both when I use GET or POST now... And it is already on a production server... Btw, in the linked question, I wasn't referring to make URL invisible (or hide it) I just wanted it too look better (which I have accomplished with mod_rewrite). UPDATE: If I use GET, then how should I make the url better looking (beautiful)? Check this previous Q out: http://stackoverflow.com/questions/3000524/how-to-make-this-very-long-url-appear-short

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  • Any suggestions to improve my PDO connection class?

    - by Scarface
    Hey guys I am pretty new to pdo so I basically just put together a simple connection class using information out of the introductory book I was reading but is this connection efficient? If anyone has any informative suggestions, I would really appreciate it. class PDOConnectionFactory{ public $con = null; // swich database? public $dbType = "mysql"; // connection parameters public $host = "localhost"; public $user = "user"; public $senha = "password"; public $db = "database"; public $persistent = false; // new PDOConnectionFactory( true ) <--- persistent connection // new PDOConnectionFactory() <--- no persistent connection public function PDOConnectionFactory( $persistent=false ){ // it verifies the persistence of the connection if( $persistent != false){ $this->persistent = true; } } public function getConnection(){ try{ $this->con = new PDO($this->dbType.":host=".$this->host.";dbname=".$this->db, $this->user, $this->senha, array( PDO::ATTR_PERSISTENT => $this->persistent ) ); // carried through successfully, it returns connected return $this->con; // in case that an error occurs, it returns the error; }catch ( PDOException $ex ){ echo "We are currently experiencing technical difficulties. We have a bunch of monkies working really hard to fix the problem. Check back soon: ".$ex->getMessage(); } } // close connection public function Close(){ if( $this->con != null ) $this->con = null; } }

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  • help on developing enterprise level software solutions

    - by wefwgeweg
    there is a specific niche which I would like to target by providing a complete enterprise level software solution.... the problem is, where do i begin ? meaning, i come from writing just desktop software on VB/ASP .net/PHP/mysql and suddenly unfamiliar terms popup like Oracle, SAP Business Information Warehouse, J2EE.... obviously, something is pointing towards Java, is it common for software suites, or solutions to be developed 100% on Java technology and standards? Are there any other platform to build enterprise level software on ? i am still lacking understanding what exactly is "Enterprise level" ? what is sufficient condition to call a software that sells for $199 and then suddenly it's $19,999 for "enterprise" package. I dont understand why there is such a huge discrepancy between "standard" and "enterprise" versions of software. Is it just attempting to bag large corporations on a spending spree ? so why does one choose to develop so called "enterprise" softwares ? is it because of the large inflated price tag you can justify with ? i would also like some more enterpreneural resources on starting your own enterprise software company in a niche.... Thank you for reading, i am still trying to find the right questions.

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  • entity framework insert bug

    - by tmfkmoney
    I found a previous question which seemed related but there's no resolution and it's 5 months old so I've opened my own version. http://stackoverflow.com/questions/1545583/entity-framework-inserting-new-entity-via-objectcontext-does-not-use-existing-e When I insert records into my database with the following it works fine for a while and then eventually it starts inserting null values in the referenced field. This typically happens after I do an update on my model from the database although not always after I do an update. I'm using a MySQL database for this. I have debugged the code and the values are being set properly before the save event. They're just not getting inserted properly. I can always fix this issue by re-creating the model without touching any of my code. I have to recreate the entire model, though. I can't just dump the relevant tables and re-add them. This makes me think it doesn't have anything to do with my code but something with the entity framework. Does anyone else have this problem and/or solved it? using (var db = new MyModel()) { var stocks = from record in query let ticker = record.Ticker select new { company = db.Companies.FirstOrDefault(c => c.ticker == ticker), price = Convert.ToDecimal(record.Price), date_stamp = Convert.ToDateTime(record.DateTime) }; foreach (var stock in stocks) { if (stock.company != null) { var price = new StockPrice { Company = stock.company, price = stock.price, date_stamp = stock.date_stamp }; db.AddToStockPrices(price); } } db.SaveChanges(); }

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