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  • A pointer member variable having different values

    - by Rohan Prabhu
    Ok, to begin with, this is my code: HyperSprite::HyperSprite() { _view = 0; } void HyperSprite::publish(QGraphicsView* view) { _view = view; } void HyperSprite::getKFrame() { if(_view != 0) { qDebug()<<(void*)_view; } } Now, if I call HyperSprite::getKFrame() from within main(), I get the output: 0xbf8ffb84 I have a TCP server, which requires this QGraphicsView* variable. So whenever a new connection is made, HyperSprite::getKFrame() is called. However, whenever I make a connection to my server, this is the output: 0x1e425ff I honestly don't understand this. Shouldn't the value of a member remain same throughout? Why is the pointer value changing? As is obvious, whenever I try to use the _view pointer to access any of its members, a Segmentation Fault occurs. I tried using QSharedPointer, but it also results in the same problem. The data of the QSharedPointer automatically changes. Why is this happening?

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  • inserts 'Array' into mysql table

    - by Noah Smith
    i want to insert an array into a mysql table. The array is produced by script scanning all the links, converting into absolute links and then displaying them in an array. i decided to mysql_query the array into the table but now i am stuck. it only posts 'Array', instead of every row from the array into a different row. Any ideas??! <?php require_once('simplehtmldom_1_5/simple_html_dom.php'); require_once('url_to_absolute/url_to_absolute.php'); $connect = mysql_connect("xxxx", "xxxx", "xxx") or die('Couldn\'t connect to MySQL Server: ' . mysql_error()); mysql_select_db("xxxx", $connect ) or die('Couldn\'t Select the database: ' . mysql_error( $connect )); $links = Array(); $URL = 'http://www.theqlick.com'; // change it for urls to grab // grabs the urls from URL $file = file_get_html($URL); foreach ($file->find('a') as $theelement) { $links[] = url_to_absolute($URL, $theelement->href); } print_r($links); mysql_query("INSERT INTO pages (url) VALUES ('$links[]')"); mysql_close($connect);

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  • problem when uploading file

    - by Syom
    i have the form, and i want to upload two files. here is the script <form action="form.php" method="post" enctype="multipart/form-data" /> <input type="file" name="video" /> <input type="file" name="picture" > <input type="submit" class="input" value="?????" /> <input type="hidden" name="MAX_FILE_SIZE" value="100000000" /> </form> form.php: <? print_r($_FILES); $video_name = $_FILES["video"]["name"]; $image_name = $_FILES["picture"]["name"]; echo "video",$video_name; echo "image",$image_name; //returns Array ( ) videoimage ?> when i try to upload the file greater than 10MB, it doesn't happen. i try in many browsers. maybe i must change some field in php.ini? but i haven't permission to change them on the server. so what can i do? thanks

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  • how to fetch data using jquery

    - by user3566029
    I have tried to connect my index.php file in 000webhost.com using jQuery. From the site menu I have connected with 000webhost using FTP details available in 000webhost.com. When I tried to read data from jQuery it doesn’t working. Anyone please tell me what should I need to change? Should I need to connect my Dreamweaver database to webhost? If yes please explain? This is what I have done. index.php $mysql_host = "mysql0.000webhost.com"; $mysql_database = "a000000_mydb"; $mysql_user = "a000000_root"; $mysql_password = "******"; $conn=@mysql_connect ( $mysql_host,$mysql_user,$mysql_password )or die('aa'); mysql_select_db($mysql_database,$conn) or die('eoor on db'); $quer=mysql_query("SELECT * FROM sam"); $res=array(); while($row=mysql_fetch_row($quer)) { $res[]=$row; } print(json_encode($res)); return json_encode($res); mysql_close(); index.html $.get('public_html/index.php', function( data ) { alert( 'Successful' +data); });

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  • Apache mod_rewrite : How to REWRITE (or whatever) child directories to parent?

    - by ????
    Actually i am trying to make a PHP MVC like application. A basic one. The current milestone i am reaching already includes: Basic RESTful Routing Means, if i type: www.example.com/items/book/8888 .. it properly just stays there as it is and i can already slice out the URL by slashes / and loads the responsible Controllers .... etc from the top single index.php file. I mean, so it is OK for the backend PHP. But the only problem is, it still CAN NOT process the REWRITES properly. For example, the CSS & JS are BROKEN as if i VIEW PAGE SOURCE of the page www.example.com/items/book/8888, the asset files are being called as: www.example.com/items/book/8888/css/main.css www.example.com/items/book/8888/js/jquery.js .. which really are PROBLEMS because in the code is like: <link type="text/css" rel="stylesheet" media="all" href="css/main.css"> <script type="text/javascript" src="js/jquery.js"></script> So the question is: How can i use Apache REWRITE (or whatever approach) to make sure every ASSET FILES to be correctly being called from the DOCROOT. For example, if i am in the URL: www.example.com/items/book/8888 My ASSET FILES should still be called as: www.example.com/css/main.css www.example.com/js/jquery.js Or is there any other methods i need to follow? Please kindly help suggest. Thank you.

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  • Page does update with details from the database after i hit a button

    - by swathi
    I have a code and the way it should work is,when they click on NEW CUSTOMER,it takes them to test1.php where in they enter the details and they hit submit.it saves all the details in properly in the database and when i go back and hit REFRESH ,it should come up with the customer details which they had entered in previously. But what happens is, when i click on the REFRESH,it refreshes the same old page which is empty.I wanted to find out where am i missing the logic.Thanks in advance. The sample code would be <tr> <td class="tdvisitbig" colspan="5">THIS IS A TEST</td> </tr> <tr> <td class='tdvisitbig' colspan="5"><input type="button" onClick="openVisit('test1.php?id=<?=$key?>&name=<?=$name?>');return false;" value="NEW CUSTOMER" class="submit">&nbsp;<input type="button" value="REFRESH" name="add_xyz" class="submit" onClick="document.add.target='_self';document.add.action='test3.php?redirect=visit&section=test page';document.add.submit();"></td> </tr> <? $q = "SELECT address,customernum,status FROM customer WHERE name='$name' ORDER BY customernum"; $r = mysql_query( $q , $Link ); while( $rw = mysql_fetch_assoc( $r ) ) { extract( $rw ); ?> <tr> <? } ?>

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  • Adding an integer at the end of an input's name to get a specific url

    - by Gadgetster
    I am trying to get a url where I can retrieve the selected values from. For example, if I put a check mark on a and b then sumbit, I will get: index.php?category=1&&category=2 I want to get this instead: index.php?category0=1&&category1=2 So that I can later get this specific value with $_GET['category0'] Is there a way to add a counter for the selected checkboxes and add 0,1,2,3.. at the end of the name of its input? <form action="" method="get"> <!-- this will be a php loop instead of hardcored which will retrieve data from the db --> <label><input type="checkbox" name="category" value="1">a</label> <label><input type="checkbox" name="category" value="2">b</label> <label><input type="checkbox" name="category" value="3">c</label> <label><input type="checkbox" name="category" value="4">d</label> <label><input type="checkbox" name="category" value="5">e</label> <input type="submit"> </form>

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  • QFileDialog used as widget

    - by lvp
    Hi! My goal is: user can choose file (only *mp3) and after clicking twice on it it should play (so the QString to file should be send to play() funtion) Firstly I started to work with QTreeView, but it has signal when the file is selected. So I decided to create QFileDialog and used it as widget built-in into MainWindow. The only problem that I have, that after double-click it dissapers. It is possible to avoid it? Should I work with some QDialog::finished() signal or, QDialog::done()?

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  • Scan HTML for values with a special character before them.

    - by DogPooOnYourShoe
    Say I have values on my page, like #100 #246, What I want to do is scan the page for values with a # before them and then alter them to put a hyperlink on it $MooringNumbers = '#!' . $MooringNumbers . ' | ' . '#!' . $row1["Number"]; } $viewedResult = '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; preg_replace('/#!(\d\d\d)/', '<a href="update.php?id=${1}">${1}</a>', $viewedResult); echo $viewedResult; This is the broken code which doesnt work.

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  • preg_match to find the current directory in a URL

    - by Ian
    I'm trying to detect the current section of a site that a user is viewing by checking for the final directory in the URL. I'm using a PHP and regex to do it and I think I'm close but unfortunately not quite there yet. Here's what I currently have: <?php $url = $_SERVER['REQUEST_URI_PATH'] = preg_replace('/\\?.*/', '', $_SERVER['REQUEST_URI']); $one = '/one/'; $two = '/three/'; $three = '/three/'; $four = '/four/'; $five = '/five/'; echo $url; if (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($one)) == $one) { // URI path starts with "/one/" echo "The section is one."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($two)) == $two) { // URI path starts with "/two/" echo "The section is two."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($three)) == $three) { // URI path starts with "/three/" echo "The section is three."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($four)) == $four) { // URI path starts with "/four/" echo "The section is four."; } elseif (substr($_SERVER['REQUEST_URI_PATH'], 0, strlen($five)) == $five) { // URI path starts with "/five/" echo "The section is five."; } ?> I've placed in the echo before the if statements just to get confirmation of the value of $url. This outputs /currentdirectory/file.php However the conditions themselves don't match anything and my individual echo for each section never displays. Also if there's a simpler way of doing it then I'm open to suggestions. Thanks

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  • Translate sequence in macro parameters to separate macros

    - by Alex Tiger
    How to acces each element in macro if the definition is like MACRO(name, seq) and the code is like: MACRO("TheName", (Elem1) (Elem2) (Elem3) ) I want to generate the next code: MACRO("TheName", ELEMMACRO(Elem1) ELEMMACRO(Elem2) ELEMMACRO(Elem3) ) Or something like that. In other words, I want to process every parameter separately (I don't care of definition, even if it will be something like MACRO("TheName", Elem1, Elem2, Elem3 ) There could be more elements, there could be less. I have tried V_ARGS (I need it only for gcc), but I can only copy all the elements by that, not to process them separately. What can I do? P.S. Because of some reasons, I can't use Boost.

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  • Cannot Display Data from MySQL table

    - by MxmastaMills
    I've got a pretty standard call to a MySQL database and for some reason I can't get the code to work. Here's what I have: $mysqli = mysqli_connect("localhost","username","password"); if (!$mysqli) { die('Could not connect: ' . mysqli_error($mysqli)); } session_start(); $sql = "SELECT * FROM jobs ORDER BY id DESC"; $result = $mysqli->query($sql); $num_rows = mysqli_num_rows($result); Now, first, I know that it is connecting properly because I'm not getting the die method plus I added an else conditional in there previously and it checked out. Then the page displays but I get the errors: Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 11 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, boolean given in blablabla/index.php on line 12 I've double-checked my database and there is a table called jobs with a row of "id" (it's the primary row). The thing that confuses me is this is code that I literally copied and pasted from another site I built and for some reason the code doesn't work on this one (I obviously copy and pasted it and then just changed the table name and rows accordingly). I saw the error and tried: $num_rows = $mysqli_result->num_rows; $row_array = $mysqli_result->fetch_array; and that fixed the errors but resulted in no data being passed (because obviously $mysqli_result has no value). I don't know why the error is calling for that (is it a difference in version of MySQL or PHP from the other site)? Can someone help me track down the problem? Thanks so much. Sorry if it's something super simple that I'm overlooking, I've been at it for a while.

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  • Overload the behavior of count() when called on certain objects

    - by Tom
    In PHP 5, you can use magic methods, overload some classes, etc. In C++, you can implement functions that exist is STL as long as the argument types are different. Is there a way to do this in PHP? An example of what I'd like to do is this: class a { function a() { $this->list = array("1", "2"); } } $blah = new a(); count($blah); I would like blah to return 2. IE count the values of a specific array in the class. So in C++, the way I would do this might look like this: int count(a varName) { return count(varName->list); } Basically, I am trying to simplify data calls for a large application so I can call do this: count($object); rather than count($object->list); The list is going to be potentially a list of objects so depending on how it's used, it could be really nasty statement if someone has to do it the current way: count($object->list[0]->list[0]->list); So, can I make something similar to this: function count(a $object) { count($object->list); } I know PHP's count accepts a mixed var, so I don't know if I can override an individual type.

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  • ajax form handling an array

    - by moata_u
    am trying to handle an array comes from php file after submitting the form data , the value of data after submitting the form is = ARRAY but i cant use this array in any way , any idea how can i handle this array !!!! Javascript : $('#file').live('change',function(){ $('#preview').html(''); $('#preview').html('<img src="loader.gif" />'); $('#data').ajaxForm(function(data){ $(data['toshow']).insertBefore('.pic_content').hide().fadeIn(1000); }).submit(); }); PHP : .... ....etc echo json_encode(array('toshow'=>somedata,'data'=>somedata)); data come from php file {"toshow":"\r\n\t\t\t\t\r\n\t\t<table class=\"out\">\r\n\t\t\t<tr ><td class=\"img\"><a title=\"2012-06-02 01-22-09\" rel=\"prettyPhoto\" href=\"img\/2012-06-02 01-22-09.284.jpg\"><img src=\"img\/thumb\/2012-06-02 01-22-09.284.jpg\"\/><\/a><\/td><\/tr>\r\n\t\t\t\r\n\t\t\t<td>\r\n\t\t\t\t<table cellSpacing=\"1\" cellPadding=\"0\">\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">2012-06-02 01-22-09<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">Download<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><a href=\"img\/2012-06-02 01-22-09.284.jpg\"><span class=\"click\">View<\/span><\/a><\/td><\/tr>\r\n\t\t\t\t<\/table>\r\n\t\t\t<\/td>\r\n\t\t\t<\/tr>\r\n\t\t<\/table>","span":"<span class='text'><img src='greencheck.png'\/>2012-06-02 01-22-09 Uploaded ,File Size =152Kb <\/span>"}

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  • Infrastructure for high transactional system (language & hosting suggestion help)

    - by RPS
    Some of our friends (University students) are trying to develop a twitter type application, I want to plan for at least 1000 transactions per second (I know it's wishful thinking) for initial launch. This involves several people connecting and getting updates and posting (text + images) to site. In the back end db will server the data and also calculates rankings of what to push to user based on complex algorithm on the fly real-time. Our group is familiar with Java and Tomcat/MySQL. We can also easily learn/code in PHP/MySQL. What is the best suited platform for our purpose ? Though Java seem to be easy to implement for us I am afraid that hosting will be a bit difficult. I could find cloud based php hosting services (like rackspace cloudsites) at reasonable cost. Amazon EC2 is a bit over our heads to manage on day-to-day. Also any recommendation on hosting ? (PHP or Java) We don't have millions in seed money but about $20K to start with. Any advice on above or any thing in general approach is much appreciated.

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  • How can I call these urls in jquery to display content on one page?

    - by Thorbis Website Design
    ok I figured out the jquery part but not the parameters of them all can anyone help figure out the parameters for each url string? this is the jquery I figured out! also would this work better then what the below answer? $.get('adminajax.php', {'action':'getUsers'}, function(data){ $('#users .users').html(data); }); He sent me this in an email: You can specify a page by adding: p=[page #] You can specify a file and it will add a checkbox next to the user which will be checked if the user has permission to download: file=[file location] adminajax.php?action=createDirectory&directory=[new directory location] adminajax.php?action=setAvailability&user=[username]&file=[filelocation]&available=[true or false] I'm trying to get it to display in these html tags: <div id="files"> <b>Files:</b> <ul class="files"></ul> </div> <div id="file_options"> <b>Options:</b> </div> <div id="users"> <b>Users:</b> <ul class="users"></ul> </div>

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  • Storing data from database [mysql_num_rows]

    - by user1717305
    So I have this code to pass items from database to my order table. When I'm echoing the session. The session variable contains something so there's no problem with that. But when I echo those variables under numrows, it only shows nothing. Is there something wrong? <?php error_reporting(E_ALL ^ E_NOTICE); session_start(); require("connect.php"); $UserID = $_SESSION['CustNum']; $UserN = $_SESSION['UserName']; $ProdGTotal = $_SESSION['ProdGTotal']; $queryord = mysql_query("SELECT * FROM customer WHERE UserName = '$UserN'"); $numrows = mysql_num_rows($queryord); if(numrows == 1){ $row = mysql_fetch_assoc($queryord)or die ('Unable to run query:'.mysql_error()); // fetch associated: get function from a query for a database $dbstreet = $row['Street']; $dhousenum = $row['HouseNum']; $dbcnum = $row['CelNum']; $dbarea = $row['Area']; $dbbuilding = $row['Building']; $dbcity = $row['City']; $dbpnum = $row['PhoneNum']; $dbfname = $row['FName']; $dblname = $row['LName']; } else die(mysql_error()); $query4=mysql_query("INSERT INTO orderdetails VALUES ('', '$UserID', Now(), '$dbhousenum', '$dbstreet', '$dbarea', '$dbbuilding', '$dbcity', '$dbfname', '$dblname', '$dbcnum', '$dbpnum', '$ProdGTotal')",$connect); if ($query4){ header("location:index.php"); } else die(mysql_error()); ?>

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  • Connection Reset on MySQL query

    - by sunwukung
    OK, I'm flummoxed.(i've asked this question over on Stack too - but I need to get it fixed so I'm asking here too - any help is GREATLY appreciated) I'm trying to execute a query on a database (locally) and I keep getting a connection reset error. I've been using the method below in a generic DAO class to build a query string and pass to Zend_Db API. public function insert($params) { $loop = false; $keys = $values = ''; foreach($params as $k => $v){ if($loop == true){ $keys .= ','; $values .= ','; } $keys .= $this->db->quoteIdentifier($k); $values .= $this->db->quote($v); $loop = true; } $sql = "INSERT INTO " . $this->table_name . " ($keys) VALUES ($values)"; //formatResult returns an array of info regarding the status and any result sets of the query //I've commented that method call out anyway, so I don't think it's that try { $this->db->query($sql); return $this->formatResult(array( true, 'New record inserted into: '.$this->table_name )); }catch(PDOException $e) { return $this->formatResult($e); } } So far, this has worked fine - the errors have been occurring since we generated new tables to record user input. The insert string looks like this: INSERT INTO tablename(`id`,`title`,`summary`,`description`,`keywords`,`type_id`,`categories`) VALUES ('5539','Sample Title','Sample content',' \'Lorem ipsum dolor sit amet, consectetur adipiscing elit. In et pellentesque mauris. Curabitur hendrerit, leo id ultrices pellentesque, est purus mattis ligula, vitae imperdiet neque ligula bibendum sapien. Curabitur aliquet nisi et odio pharetra tincidunt. Phasellus sed iaculis nisl. Fusce commodo mauris et purus vehicula dictum. Nulla feugiat molestie accumsan. Donec fermentum libero in risus tempus elementum aliquam et magna. Fusce vitae sem metus. Aenean commodo pharetra risus, nec pellentesque augue ullamcorper nec. Class aptent taciti sociosqu ad litora torquent per conubia nostra, per inceptos himenaeos. Nullam vel elit libero. Vestibulum in turpis nunc.\'','this,is,a,sample,array',1,'category title') Here are the parameters it's getting before assembling the query (var_dump): array 'id' => string '1' (length=4) 'title' => string 'Sample Title' (length=12) 'summary' => string 'Sample content' (length=14) 'description' => string '<p>'Lorem ipsum dolor sit amet, consectetur adipiscing elit. In et pellentesque mauris. Curabitur hendrerit, leo id ultrices pellentesque, est purus mattis ligula, vitae imperdiet neque ligula bibendum sapien. Curabitur aliquet nisi et odio pharetra tincidunt. Phasellus sed iaculis nisl. Fusce commodo mauris et purus vehicula dictum. Nulla feugiat molestie accumsan. Donec fermentum libero in risus tempus elementum aliquam et magna. Fusce vitae sem metus. Aenean commodo pharetra risus, nec pellentesque augue'... (length=677) 'keywords' => string 'this,is,a,sample,array' (length=22) 'type_id' => int 1 'categories' => string 'category title' (length=43) The next port of call was checking the limits on the table, since it seems to insert if the length of "description" is around the 300 mark (it varies between 310 - 330). The field limit is set to VARCHAR(1500) and the validation on this field won't allow anything past bigger than 1200 with HTML, 800 without. The real kicker is that if I take this sql string and execute it via the command line, it works fine - so I can't for the life of me figure out what's wrong. I've tried extending the server parameters i.e. http://stackoverflow.com/questions/1964554/unexpected-connection-reset-a-php-or-an-apache-issue So, in a nutshell, I'm stumped. Any ideas?

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  • Varnish + Nginx + multiple IP addresses

    - by adnan
    This is my first shot at making Varnish work on my dedicated server which hosts 2 domains with 2 separate IP-addresses. My simplified setup is as follows: Nginx conf server { listen ip-address-1:8080; } server { listen ip-address-2:8080; } Varnish vcl backend default { .host = "127.0.0.1"; .port = "80"; } And in the varnish conf I have defined VARNISH_LISTEN_PORT=80 Varnish and Nginx (and php-fpm) are running properly but when I try to go to my website it shows the welcome to nginx page. The headers don't have the x-varnish in it. It seems that for some reason varnish is not listening to port 80. I'm suspecting this has to do with the vcl file where it is listening to the 127.0.0.1 host. I'm running two wordpress sites. Where should I look for to get Varnish working properly? Cheers, Adnan EDIT: Nginx seems to be in 8080 correctly but Varnish is not listening to the right ip address. Using Jens multiple varnish ip addresses netstat -lnp yields: Proto Recv-Q Send-Q Local Address Foreign Address State PID/Program name tcp 0 0 46.105.40.241:8080 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 5.135.166.39:8080 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 0.0.0.0:80 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 127.0.0.1:53 0.0.0.0:* LISTEN 2544/named tcp 0 0 0.0.0.0:21 0.0.0.0:* LISTEN 1195/vsftpd tcp 0 0 0.0.0.0:22 0.0.0.0:* LISTEN 1184/sshd tcp 0 0 127.0.0.1:953 0.0.0.0:* LISTEN 2544/named tcp 0 0 46.105.40.241:443 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 5.135.166.39:443 0.0.0.0:* LISTEN 21610/nginx tcp 0 0 127.0.0.1:6082 0.0.0.0:* LISTEN 21350/varnishd tcp 0 0 :::80 :::* LISTEN 21351/varnishd tcp 0 0 ::1:53 :::* LISTEN 2544/named tcp 0 0 :::22 :::* LISTEN 1184/sshd tcp 0 0 ::1:953 :::* LISTEN 2544/named udp 0 0 127.0.0.1:53 0.0.0.0:* 2544/named udp 0 0 ::1:53 :::* 2544/named default.vcl backend ikhebeenbril { .host = "5.135.166.39"; .port = "8080"; } backend sunculture { .host = "46.105.40.241"; .port = "8080"; } sub vcl_recv { if (server.ip == "5.135.166.39") { set req.backend = ikhebeenbril; } else { set req.backend = sunculture; } ... } sub vcl_hash { hash_data(server.ip); if (req.http.host) { hash_data(req.http.host); } hash_data(req.url); if (req.http.Accept-Encoding) { hash_data(req.http.Accept-Encoding); } return (hash); } nginx server blocks server { listen 5.135.166.39:80; listen 5.135.166.39:443 default ssl spdy; server_name www.ikhebeenbril.nl; } server { listen 46.105.40.241:80; listen 46.105.40.241:443 default ssl spdy; server_name www.thesunculture.com; }

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  • Apache config that uses two document roots based on whether the requested resource exists in the first

    - by mattalexx
    Background I have a client site that consists of a CakePHP installation and a Magento installation: /web/example.com/ /web/example.com/app/ <== CakePHP /web/example.com/app/webroot/ <== DocumentRoot /web/example.com/app/webroot/store/ <== Magento /web/example.com/config/ <== Site-wide config /web/example.com/vendors/ <== Site-wide libraries The server runs Apache 2.2.3. The problem The whole company has FTP access and got used to clogging up the /web/example.com/, /web/example.com/app/webroot/, and /web/example.com/app/webroot/store/ directories with their own files. Sometimes these files need HTTP access and sometimes they don't. In any case, this mess makes my job harder when it comes to maintaining the site. Code merges, tarring the live code, etc, is very complicated and usually requires a bunch of filters. Abandoned solution At first, I thought I would set up a new subdomain on the same server, move all of their files there, and change their FTP chroot. But that wouldn't work for these reasons: Firstly, I have no idea (and neither do they remember) what marketing materials they've sent out that contain URLs to certain resources they've uploaded to the server, using the main domain, and also using abstract subdomains that use the main virtual host because it has ServerAlias *.example.com. So suddenly having them only use static.example.com isn't feasible. Secondly, The PHP scripts in their projects are potentially very non-portable. I want their files to stay in as similar an environment as they were built as I can. Also, I do not want to debug their code to make it portable. Half-baked solution After some thought, I decided to find a way to section off the actual website files into another directory that they would not touch. The company's uploaded files would stay where they were. This would ensure that I didn't break any of their projects that needed HTTP access. It would look something like this: /web/example.com/ <== A bunch of their files are in here /web/example.com/app/webroot/ <== 1st DocumentRoot; A bunch of their files are in here /web/example.com/app/webroot/store/ <== Some more are in here /web/example.com/site/ <== New dir; Contains only site files /web/example.com/site/app/ <== CakePHP /web/example.com/site/app/webroot/ <== 2nd DocumentRoot /web/example.com/site/app/webroot/store/ <== Magento /web/example.com/site/config/ <== Site-wide config /web/example.com/site/vendors/ <== Site-wide libraries After I made this change, I would not need to pay attention to anything except for the stuff within /web/example.com/site/ and my job would be a lot easier. I would be the only one changing stuff in there. So here's where the Apache magic would happen: I need an HTTP request to http://www.example.com/ to first use /web/example.com/app/webroot/ as the document root. If nothing is found (no miscellaneous uploaded company projects are found), try finding something within /web/example.com/site/app/webroot/. Another thing to keep in mind is, the site might have some problems if the $_SERVER['DOCUMENT_ROOT'] variable reads /web/example.com/app/webroot/ but the actual files are within /web/example.com/site/app/webroot/. It would be better if the DOCUMENT_ROOT environment variable could be /web/example.com/site/app/webroot/ for anything within the /web/example.com/site/app/webroot/ directory. Conclusion Is my half-baked solution possible with Apache 2.2.3? Is there a better way to solve this problem?

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