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• GnoMenu integration in docky.

  - by Lyon Apostol

  Posting the error: Running docky --debug < ...some other stuff... > [Info 10:27:52.535] [Helper] Starting GnoMenu.py [Info 10:27:52.560] [HelperService] Helper added: /usr/share/dockmanager/scripts/GnoMenu.py [Info 10:27:52.757] [Helper] GnoMenu.py :: No module named dockmanager.dockmanager [Info 10:27:52.758] [Helper] GnoMenu.py :: gconf backend [Info 10:27:52.758] [Helper] GnoMenu.py :: 239 [Error 10:27:52.759] [Helper] GnoMenu.py :: Traceback (most recent call last): [Error 10:27:52.759] [Helper] GnoMenu.py :: File "/usr/share/dockmanager/scripts/GnoMenu.py", line 120, in < module > [Error 10:27:52.759] [Helper] GnoMenu.py :: class DockyGnoMenuItem(DockManagerItem): [Error 10:27:52.759] [Helper] GnoMenu.py :: NameError: name 'DockManagerItem' is not defined [Info 10:27:52.874] [Helper] GnoMenu.py has exited (Code 1). After installing dockmanager Now this is what happens: [Info 11:34:36.166] [Helper] GnoMenu.py :: gconf backend [Info 11:34:36.166] [Helper] GnoMenu.py :: 136 [Info 11:34:36.166] [Helper] GnoMenu.py :: DockManagerSink(): System.NotSupportedException: Cannot send null variant [Info 11:34:36.210] [Helper] GnoMenu.py has exited (Code 0). I tried to click the icon at the dock: gconf backend 380 DockManagerSink(): System.NotSupportedException: Cannot send null variant gconf backend 380 DockManagerSink(): System.NotSupportedException: Cannot send null variant How can I fix this? Thanks for your prompt answer!

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• pymatplotlib without xserver

  - by vigilant

  Is it possible to use networkx or pymatplotlib without an xserver running? I keep getting the following error with their first example (of networkx): Traceback (most recent call last): File "test.py", line 17, in <module> nx.draw(G,pos,node_color='#A0CBE2',edge_color=colors,width=4,edge_cmap=plt.cm.Blues,with_labels=False) File "/usr/local/lib/python2.6/dist-packages/networkx-1.3-py2.6.egg/networkx/drawing/nx_pylab.py", line 124, in draw cf=pylab.gcf() File "/usr/lib/pymodules/python2.6/matplotlib/pyplot.py", line 276, in gcf return figure() File "/usr/lib/pymodules/python2.6/matplotlib/pyplot.py", line 254, in figure **kwargs) File "/usr/lib/pymodules/python2.6/matplotlib/backends/backend_tkagg.py", line 90, in new_figure_manager window = Tk.Tk() File "/usr/lib/python2.6/lib-tk/Tkinter.py", line 1646, in __init__ self.tk = _tkinter.create(screenName, baseName, className, interactive, wantobjects, useTk, sync, use) _tkinter.TclError: couldn't connect to display ""

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• Passenger_wsgi.py given precedence over DirectoryIndex?

  - by Walkerneo

  I was having an issue with my site today, where apache wasn't serving index.php by default. I had moved passenger_wsgi.py to the directory above document root so that I could serve python files without having to use PassengerAppRoot in the .htaccess file. I wanted to do this because I set up a development sub-domain on the site, and I wanted to use a different passenger_wsgi for the two domains, but that meant having different .htaccess files for the different PassengerAppRoots. Is there a way to have passenger_wsgi.py where it was and still let apache serve the index.phps? edit: I'm sorry, I'm tired. I just realized that the way this probably works is that passenger_wsgi.py is handling the routing instead of apache.

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• Dropbox.py on RHEL 6

  - by Timothy R. Butler

  I'm trying to run a headless install of Dropbox on RHEL 6. The daemon seems to be running, but when I try to use Dropbox's associated dropbox.py tool to control the daemon, it fails to run with the following error: Traceback (most recent call last): File "./dropbox.py", line 26, in <module> import locale File "/usr/lib64/python2.6/locale.py", line 202, in <module> import re, operator ImportError: /home/dropbox/.dropbox-dist/operator.so: undefined symbol: _PyUnicodeUCS2_AsDefaultEncodedString I'm running the current RHEL build of Python 2.6: root@cedar [/home/dropbox/.dropbox-dist]# rpm -qv python python-2.6.6-29.el6_3.3.x86_64 (I'm not sure if this would be better suited to Stack Overflow since it is on the verge of being a programming issue, but since I'm trying to use a program straight from Dropbox, I placed it here.)

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• Django - How to do CSFR on public pages? Or, better yet, how should it be used period?

  - by orokusaki

  After reading this: http://docs.djangoproject.com/en/dev/ref/contrib/csrf/#how-to-use-it I came to the conclusion that it is not valid to use this except for when you trust the person who is using the page which enlists it. Is this correct? I guess I don't really understand when it's safe to use this because of this statement: This should not be done for POST forms that target external URLs, since that would cause the CSRF token to be leaked, leading to a vulnerability. The reason it's confusing is that to me an "external URL" would be on that isn't part of my domain (ie, I own www.example.com and put a form that posts to www.spamfoo.com. This obviously can't be the case since people wouldn't use Django for generating forms that post to other people's websites, but how could it be true that you can't use CSRF protection on public forms (like a login form)?

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• Django: A Result Specific Numeration for Pagination.

  - by TheLizardKing

  Simply put I want what http://www.reddit.com/ and http://news.ycombinator.com/ have to the left of every link. A numerated link starting with 1 and continuing to the next page by means of pagination. I really enjoy using generic views and their built-in pagination for Django and it seems to allow me access to these values if I was on page 3 with 2 items per page. {'MEDIA_URL': ''} {'LANGUAGES': '<<languages>>', 'LANGUAGE_BIDI': False, 'LANGUAGE_CODE': 'en-us'} {'debug': True, 'sql_queries': '<<sql_queries>>'} {'messages': [], 'perms': <django.core.context_processors.PermWrapper object at 0xadedeec>, 'user': <User: thelizardking>} {'first_on_page': 5, 'has_next': True, 'has_previous': True, 'hits': 7, 'is_paginated': True, 'last_on_page': 6, 'links_list': [<Link: Funky Town>, <Link: Apple Jax>], 'next': 4, 'page': 3, 'page_obj': <Page 3 of 4>, 'page_range': [1, 2, 3, 4], 'pages': 4, 'paginator': <django.core.paginator.Paginator object at 0xadf914c>, 'previous': 2, 'results_per_page': 2} I know there is an add filter for templates but that's as close as I think I can get and that really doesn't do what I want. Am I going to have to use a custom template filter here or is there something I am not seeing?

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• django customizing form labels

  - by Henri

  I have a problem in customizing labels in a Django form This is the form code in file contact_form.py: from django import forms class ContactForm(forms.Form): def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) The view I am using this in looks like: def contact(request, product_id=None): . . . if request.method == 'POST': form = contact_form.ContactForm(request.POST) if form.is_valid(): . . else: form = contact_form.ContactForm( subject_label = "Subject", message_label = "Your Message", email_label = "Your email", cc_myself_label = "Cc myself") The strings used for initializing the labels will eventually be strings dependent on the language, i.e. English, Dutch, French etc. When I test the form the email is not sent and instead of the redirect-page the form returns with: <QueryDict: {u'cc_myself': [u'on'], u'message': [u'message body'], u'email':[u'[email protected]'], u'subject': [u'test message']}>: where the subject label was before. This is obviously a dictionary representing the form fields and their contents. When I change the file contact_form.py into: from django import forms class ContactForm(forms.Form): """ def __init__(self, subject_label="Subject", message_label="Message", email_label="Your email", cc_myself_label="Cc myself", *args, **kwargs): super(ContactForm, self).__init__(*args, **kwargs) self.fields['subject'].label = subject_label self.fields['message'].label = message_label self.fields['email'].label = email_label self.fields['cc_myself'].label = cc_myself_label """ subject = forms.CharField(widget=forms.TextInput(attrs={'size':'60'})) message = forms.CharField(widget=forms.Textarea(attrs={'rows':15, 'cols':80})) email = forms.EmailField(widget=forms.TextInput(attrs={'size':'60'})) cc_myself = forms.BooleanField(required=False) i.e. disabling the initialization then everything works. The form data is sent by email and the redirect page shows up. So obviously something the the init code isn't right. But what? I would really appreciate some help.

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• Django "login() takes exactly 1 argument (2 given)" error

  - by Oleksandr Bolotov

  I'm trying to store the user's ID in the session using django.contrib.auth.login . But it is not working not as expected. I'm getting error login() takes exactly 1 argument (2 given) With login(user) I'm getting AttributeError at /login/ User' object has no attribute 'method' I'm using slightly modifyed example form http://docs.djangoproject.com/en/dev/topics/auth/ : from django.shortcuts import render_to_response from django.contrib.auth import authenticate, login def login(request): msg = [] if request.method == 'POST': username = request.POST['u'] password = request.POST['p'] user = authenticate(username=username, password=password) if user is not None: if user.is_active: login(request, user) msg.append("login successful") else: msg.append("disabled account") else: msg.append("invalid login") return render_to_response('login.html', {'errors': msg}) there's nothing special about login.html: <html> <head> <title></title> </head> <body> <form action="/login/" method="post"> Login:&nbsp; <input type="text" name="u"> <br/> Password:&nbsp; <input type="password" name="p"> <input type="submit" value="Login"> </form> {% if errors %} <ul> {% for error in errors %} <li>{{ error }}</li> {% endfor %} </ul> {% endif %} </body> </html> Does anybody have idea how to make login() work.

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• JSON Serialization of a Django inherited model

  - by Simon Morris

  Hello, I have the following Django models class ConfigurationItem(models.Model): path = models.CharField('Path', max_length=1024) name = models.CharField('Name', max_length=1024, blank=True) description = models.CharField('Description', max_length=1024, blank=True) active = models.BooleanField('Active', default=True) is_leaf = models.BooleanField('Is a Leaf item', default=True) class Location(ConfigurationItem): address = models.CharField(max_length=1024, blank=True) phoneNumber = models.CharField(max_length=255, blank=True) url = models.URLField(blank=True) read_acl = models.ManyToManyField(Group, default=None) write_acl = models.ManyToManyField(Group, default=None) alert_group= models.EmailField(blank=True) The full model file is here if it helps. You can see that Company is a child class of ConfigurationItem. I'm trying to use JSON serialization using either the django.core.serializers.serializer or the WadofStuff serializer. Both serializers give me the same problem... >>> from cmdb.models import * >>> from django.core import serializers >>> serializers.serialize('json', [ ConfigurationItem.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.configurationitem", "fields": {"is_leaf": true, "extension_attribute_10": "", "name": "", "date_modified": "2010-05-19 14:42:53", "extension_attribute_11": false, "extension_attribute_5": "", "extension_attribute_2": "", "extension_attribute_3": "", "extension_attribute_1": "", "extension_attribute_6": "", "extension_attribute_7": "", "extension_attribute_4": "", "date_created": "2010-05-19 14:42:53", "active": true, "path": "/Locations/London", "extension_attribute_8": "", "extension_attribute_9": "", "description": ""}}]' >>> serializers.serialize('json', [ Location.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.location", "fields": {"write_acl": [], "url": "", "phoneNumber": "", "address": "", "read_acl": [], "alert_group": ""}}]' >>> The problem is that serializing the Company model only gives me the fields directly associated with that model, not the fields from it's parent object. Is there a way of altering this behaviour or should I be looking at building a dictionary of objects and using simplejson to format the output? Thanks in advance ~sm

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• Django m2m form appearing fields

  - by dana

  I have a classroom application,and a follow relation. Users can follow each other and can create classrooms.When a user creates a classroom, he can invite only the people that are following him. The Classroom model is a m2m to User table. i have in models. py: class Classroom(models.Model): creator = models.ForeignKey(User) classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members") and in models.py of the follow application: class Relations(models.Model): initiated_by = models.ForeignKey(User, editable=False) date_initiated = models.DateTimeField(auto_now=True, editable = False) follow = models.ForeignKey(User, editable = False, related_name = "follow") date_follow = models.DateTimeField(auto_now=True, editable = False) and in views.py of the classroom app: def save_classroom(request, username): if request.method == 'POST': u = User.objects.get(username=username) form = ClassroomForm(request.POST, request.FILES) if form.is_valid(): new_obj = form.save(commit=False) new_obj.creator = request.user r = Relations.objects.filter(initiated_by = request.user) # new_obj.members = new_obj.save() return HttpResponseRedirect('.') else: form = ClassroomForm() return render_to_response('classroom/classroom_form.html', { 'form': form, }, context_instance=RequestContext(request)) i'm using a ModelForm for the classroom form, and the default view, taking in consideration my many to many relation with User table, in the field Members, is a list of all Users in my database. But i only want in that list the users that are in a follow relationship with the logged in user - the one who creates the classroom. How can i do that? Thanks!

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• Django: Serving Media Behind Custom URL

  - by TheLizardKing

  So I of course know that serving static files through Django will send you straight to hell but I am confused on how to use a custom url to mask the true location of the file using Django. http://stackoverflow.com/questions/2681338/django-serving-a-download-in-a-generic-view but the answer I accepted seems to be the "wrong" way of doing things. urls.py: url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), views.py: def song_download(request, song_id): song = Song.objects.get(id=song_id) fsock = open(os.path.join(song.path, song.filename)) response = HttpResponse(fsock, mimetype='audio/mpeg') response['Content-Disposition'] = "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response This solution works perfectly but not perfectly enough it turns out. How can I avoid having a direct link to the mp3 while still serving through nginx/apache? EDIT 1 - ADDITIONAL INFO Currently I can get my files by using an address such as: http://www.example.com/music/song/1692/download/ But the above mentioned method is the devil's work. How can I accomplished what I get above while still making nginx/apache serve the media? Is this something that should be done at the webserver level? Some crazy mod_rewrite? http://static.example.com/music/Aphex%20Twin%20-%20Richard%20D.%20James%20(V0)/10%20Logon-Rock%20Witch.mp3

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• Using Pylint with Django

  - by rcreswick

  I would very much like to integrate pylint into the build process for my python projects, but I have run into one show-stopper: One of the error types that I find extremely useful--:E1101: *%s %r has no %r member*--constantly reports errors when using common django fields, for example: E1101:125:get_user_tags: Class 'Tag' has no 'objects' member which is caused by this code: def get_user_tags(username): """ Gets all the tags that username has used. Returns a query set. """ return Tag.objects.filter( ## This line triggers the error. tagownership__users__username__exact=username).distinct() # Here is the Tag class, models.Model is provided by Django: class Tag(models.Model): """ Model for user-defined strings that help categorize Events on on a per-user basis. """ name = models.CharField(max_length=500, null=False, unique=True) def __unicode__(self): return self.name How can I tune Pylint to properly take fields such as objects into account? (I've also looked into the Django source, and I have been unable to find the implementation of objects, so I suspect it is not "just" a class field. On the other hand, I'm fairly new to python, so I may very well have overlooked something.) Edit: The only way I've found to tell pylint to not warn about these warnings is by blocking all errors of the type (E1101) which is not an acceptable solution, since that is (in my opinion) an extremely useful error. If there is another way, without augmenting the pylint source, please point me to specifics :) See here for a summary of the problems I've had with pychecker and pyflakes -- they've proven to be far to unstable for general use. (In pychecker's case, the crashes originated in the pychecker code -- not source it was loading/invoking.)

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• django hidden field error

  - by dana

  hi, there, i'm building a message system for a virtual community, but i can't take the userprofile id i have in views.py def save_message(request): if request.method == 'POST': form = MessageForm(request.POST) if form.is_valid(): new_obj = form.save(commit=False) new_obj.sender = request.user u = UserProfile.objects.get(request.POST['userprofile_id']) new_obj.owner = u new_obj.save() return HttpResponseRedirect('.') else: form = MessageForm() return render_to_response('messages/messages.html', { 'form': form, }, context_instance=RequestContext(request)) and the template: {% block primary %} <form action="." method="post"> {{ form.as_p }} <p><input type="hidden" value="{{ userprofile.id }}" name = "owner" /></p> <p><input type="submit" value="Send Message!" /></p> </form> {% endblock %} forms.py: class MessageForm(ModelForm): class Meta: model = Messages fields = ['message'] models.py: class Messages(models.Model): message = models.CharField(max_length = 300) read = models.BooleanField(default=False) owner = models.ForeignKey(UserProfile) sender = models.ForeignKey(User) I don't figure out why i get this error,since i'm just trying to get the profileId of a user, using a hiddeen field. the error is: Key 'UserProfile_id' not found in <QueryDict: {u'owner': [u''], u'message': [u'fdghjkl']}> and i'm getting it after i fill out the message text field. Thanks!

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• problems doing the Django tutorial on Dreamhost using Passengers

  - by Pietro Speroni

  I have looked and I could not find this question before, and it surprises me. I am reasonably proficient in Python, and I used Dreamhost for a number of years. Now I would like to learn Django. They are finally supporting it using Passenger. Which I do not know what is. Following the instructions on Dreamhost I installed Django. Then I started following the tutorial 01. This went well, except that I could not start the server (this in the tutorial) since the code was live on dreamhost. At the time this did not seem to make any difference. Then when I went on the second part of the tutorial I had to access the admin site. And it worked well going to myurl/admin/ , as it should. But here the problems started. According to the tutorial (here) I have to add a file in the poll application and then restart the server. But I never started the server in the first place, my code is running live on the web... but when I add a file the website the admin acts as if it does not see it. Probably dreamhost has started its own server, and I don't know how to restart it. But I assume this is going to be a common problem when you run django on dreamhost. Every time you add a file you will have to tell the server to consider it. So what should I do to let the server know about it? Thanks, Pietro

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• Django sitemap intermittent www

  - by Jen Z

  The automatic sitemap for my Django site fluctuates between including the www on urls and leaving it out (I'm aiming to have it in all the time). This has ramifications in google not indexing my pages properly so I'm trying to narrow down what would be causing this issue. I have set PREPEND_WWW = True and my site record in the sites framework is set to include the www e.g. it's set to www.example.com as opposed to example.com. I'm using memcached but pages should expire from the cache after 48 hours so I wouldn't have thought that would be causing the issue? You can see the problem in effect at http://www.livingspaceltd.co.uk/sitemap.xml (refresh the page a few times). My sitemaps setup is fairly prosaic so I'm doubtful that that is the issue, but in case it's something obvious I'm missing here's the code: ***urls.py*** sitemaps = { 'subpages': Subpages_Sitemap, 'standalone_pages': Standalone_Sitemap, 'categories': Categories_Sitemap, } urlpatterns = patterns('', (r'^sitemap\.xml$', 'django.contrib.sitemaps.views.sitemap', {'sitemaps': sitemaps}), ... ***sitemaps.py*** # -*- coding: utf-8 -*- from django_ls.livingspace.models import Page, Category, Standalone_Page, Subpage from django.contrib.sitemaps import Sitemap class Subpages_Sitemap(Sitemap): changefreq = "monthly" priority = 0.4 def items(self): return Subpage.objects.filter(restricted_to__isnull=True) class Standalone_Sitemap(Sitemap): changefreq = "weekly" priority = 1 def items(self): return Standalone_Page.objects.all() class Categories_Sitemap(Sitemap): changefreq = "weekly" priority = 0.7 def items(self): return Category.objects.all()

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• Django does not load internal .css files

  - by Rubén Jiménez

  I have created a Django project in local which runs without any kind of problem. But, after an annoying and difficult Cherokee + uWSGI installation on Amazon AWS, my project does not show Django .css internal files. http://f.cl.ly/items/2Q2W3I3R0X1n2X3v0q2P/django_error.jpg <-- /Admin/ looks like The image is a screen of my /admin/, which should have a different style, but .css files are not loaded. [pid: 23206|app: 0|req: 19/19] 83.49.10.217 () {56 vars in 1121 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/base.css = generated 2896 bytes in 6 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) [pid: 23206|app: 0|req: 20/20] 83.49.10.217 () {56 vars in 1125 bytes} [Sun Apr 15 05:50:24 2012] GET /static/admin/css/login.css = generated 2899 bytes in 5 msecs (HTTP/1.1 404) 1 headers in 51 bytes (1 switches on core 0) This is a log from Cherokee. I don't understand why it is looking for the .css files in that path. Cherokee should be searching the files in Django original directory so i didn't change .css files in my project. Any advice? Thanks a lot.

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• On-Demand thumbnail creation with django and nginx

  - by sharjeel

  I want to generate thumbnails of images on the fly. My site is built with django and deployed using nginx which serves all the static content and communicates with django/apache using reverse proxy. Right now, for every image in my site, I generate all required sizes of thumbnails on-hand and deliver them when required. The problem is that whenever I change the size of a thumbnail, I have to regenerate all of them (and they are tons). However now I'd like to generate the thumbnail the first time it is accessed and later on nginx would deliver the same file over n over. If I delete that thumbnail file because of lesser accesses, it should get generated automatically the next time. Thumbnails in my case also have watermarks which require some computation logic of my application so a webserver thumbnail module might not work very well. The size of the thumbnail can be embedded in the URL. So http://www.example.com/thumbnail/abc_320x240.jpg gets the 320x240 size of the thumbnail. The approach I'm looking right now is to let nginx lookup the file and if it doesn't exist, forward the query to my django application which would create the thumbnail and send either the response or a redirect string. However I'm not sure about the concurrency issues and any other issues which might pop up later. What is the appropriate way to achieve this?

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• inserting a form to session raises picklingerror - django

  - by shanyu

  I receive an exception when I add a form to the session: PicklingError: Can't pickle <class 'django.utils.functional.__proxy__'>: attribute lookup django.utils.functional.__proxy__ failed The form includes a few simple fields and has some javascript attached to a widget. It might be that Django forms cannot be pickled at all, but the exception seems to point to unicode lazy translation. To test further, I have also tried to insert only the form errors (an errordict) to the session and received the same error. I appreciate some help here, thanks in advance. EDIT: Here's why I insert a form into the session: I have an app that has a form. This form is rendered by a template tag in another app. When posted, if the form is valid, no problem, I do stuff and redirect to "next". However if it is not valid, I want to go back to the posting page to show errors. Recall that the comments app in this case redirects to an intermediate "hey, please fix the errors" page. I am trying to avoid this, and hence redirect back to the posting page with the form and its errors in the session that the template tag will render.

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• Django: How to dynamically add tag field to third party apps without touching app's source code

  - by Chris Lawlor

  Scenario: large project with many third party apps. Want to add tagging to those apps without having to modify the apps' source. My first thought was to first specify a list of models in settings.py (like ['appname.modelname',], and call django-tagging's register function on each of them. The register function adds a TagField and a custom manager to the specified model. The problem with that approach is that the function needs to run BEFORE the DB schema is generated. I tried running the register function directly in settings.py, but I need django.db.models.get_model to get the actual model reference from only a string, and I can't seem to import that from settings.py - no matter what I try I get an ImportError. The tagging.register function imports OK however. So I changed tactics and wrote a custom management command in an otherwise empty app. The problem there is that the only signal which hooks into syncdb is post_syncdb which is useless to me since it fires after the DB schema has been generated. The only other approach I can think of at the moment is to generate and run a 'south' like database schema migration. This seems more like a hack than a solution. This seems like it should be a pretty common need, but I haven't been able to find a clean solution. So my question is: Is it possible to dynamically add fields to a model BEFORE the schema is generated, but more specifically, is it possible to add tagging to a third party model without editing it's source. To clarify, I know it is possible to create and store Tags without having a TagField on the model, but there is a major flaw in that approach in that it is difficult to simultaneously create and tag a new model.

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• Django website on Apache with wsgi failing

  - by notagain

  I have a website I've built in django that I'm trying to get working on our corporate Apache server (on debian) for our intranet at my workplace. Unfortunately, Apache keeps returning server errors whenever I try to navigate to my site. Although I can navigate to the statics folder. My Apache config and wsgi script look like the following... lbirdf.wsgi import os import sys sys.path.append('/home/lbi/rdfweb/web') sys.path.append('/home/lbi/rdfweb/lbirdf') os.environ['DJANGO_SETTINGS_MODULE'] = 'lbirdf.settings_production' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() Apache config Listen 8080 <VirtualHost *:8080> ServerName server1 WSGIScriptAlias /rdfweb /home/lbi/rdfweb/web/lbirdf/apache/lbirdf.wsgi Alias /statics /home/lbi/rdfweb/web/lbirdf/statics Alias /admin_media /home/lbi/rdfweb/web/lbirdf/admin_media <Directory /home/lbi/rdfweb/web/lbirdf/apache> Order allow,deny Allow from all </Directory> <Directory /home/lbi/rdfweb/web/lbirdf/admin_media> Order allow,deny Allow from all </Directory> </VirtualHost> Any ideas on where I might be going wrong?

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• Django Development Environment Setup Questions

  - by Ross Peoples

  Hello, I'm trying to set up a good development environment for a Django project that I will be working on from two different physical locations. I have two Mac machines, one at home and one at work that I do most of my development on. I currently host a Ubuntu virtual machine on one of the machines to host the Django environemnt, install DropBox on it, and edit source code from my Mac. When I save the code file, the changes get synced over DropBox to the Ubuntu VM and the Django development server automatically restarts because of the change. This method has worked well in the past, but I am starting to use DropBox for a lot of other things now and don't want all of that to be downloaded on every virtual machine I use. Plus, I want to start using Eclipse + PyDev to be able to debug code and have code completion. Currently, I use TextEdit which is great, but doesn't support debugging or completion. So what are my options? I thought about setting up a Parallels VM on a thumb drive that has my entire environment on it (Eclipse included), but that has its own problems. Any other thoughts?

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• JavaScript cookie value can't be retrieved in Django

  - by Boris Rusev

  I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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• Django: Serving a Download in a Generic View

  - by TheLizardKing

  So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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• Ajax request not receiving xml from Django

  - by amougeot

  I have a Django server which handles requests to a URL which will return some HTML for use in an image gallery. I can navigate to the URL and the browser will display the HTML that is returned, but I can't get that same HTML by doing an AJAX call (using jQuery) to the same URL. This is the view that generates the response: def gallery_images(request, gallery_name): return render_to_response('galleryimages.html', {'images': get_images_of_gallery(gallery_name)}, mimetype='text/xml') This is the 'galleryimages.html' template: {% for image in images %} <div id="{{image.name}}big"> <div class="actualImage" style="background-image:url({{image.image.name}});"> <h1>{{image.caption|safe}}</h1> </div> </div> {% endfor %} This is the jQuery call I am making: $("#allImages").load("http://localhost:8000/galleryimages/Web"); However, this loads nothing into my #allImages div. I've used firebug and ran jQuery's Ajax method .get("http://localhost:8000/galleryimages/Web") and firebug says that the response text is completely empty. When I check my Django server log, this is the entry I see for when I navigate to the URL manually, through my browser: [16/Jan/2010 17:34:10] "GET /galleryimages/Web HTTP/1.1" 200 215 This is the entry in the server log for when I make the AJAX call: [16/Jan/2010 17:36:19] "OPTIONS /galleryimages/Web HTTP/1.1" 200 215 Why does the AJAX request not get the xml that my Django page is serving?

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• Django | passing form values

  - by MMRUser

  I want to create a user sign up process that requires two different forms with the same data one (1st form) is for filling out the data and other one (2nd form) is for displaying the filled data as a summery (before actually saving the data) so then user can view what he/she has filled up... my problem is that how do I pass 1st form's data in to the 2nd one .. I have used the basic Django form manipulation mechanism and passed the form field values to the next form using Django template tags.. if request.method == 'POST': form = Users(request.POST) if form.is_valid(): cd = form.cleaned_data try: name = cd['fullName'] email = cd['emailAdd'] password1 = cd['password'] password2 = cd['password2'] phoneNumber = cd['phoneNumber'] return render_to_response('signup2.html', {'name': name, 'email': email, 'password1': password1, 'password2': password2, 'phone': phone, 'pt': phoneType}) except Exception, ex: return HttpResponse("Error %s" % str(ex)) and from the second from I just displayed those field values using tags and also used hidden fields in order to submit the form with values, like this: <label for="">Email:</label> {{ email }} <input type="hidden" id="" name="email" class="width250" value="{{ email }}" readonly /> It works nicely from the out look, but the real problem is that if someone view the source of the html he can simply get the password even hackers can get through this easily. So how do I avoid this issue.. and I don't want to use Django session since this is just a simple sign up process and no other interactions involved. Thanks.

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