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  • JavaScript cookie value can't be retrieved in Django

    - by Boris Rusev
    I am trying to build a web site in both English and Bulgarian using the Django framework. My idea is the user should click on a button, the page will reload and the language will be changed. This is how I am trying to do it: In my html I hava a the button tag <button id='btn' onclick="changeLanguage();" type="button"> ... </button> An excerpt from cookies.js: function changeLanguage() { if (getCookie('language') == 'EN') { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'BG'); } else { document.getElementById('btn').innerHTML = getCookie('language'); setCookie("language", 'EN'); } } function setCookie(sName, sValue, oExpires, sPath, sDomain, bSecure) { var sCookie = sName + "=" + encodeURIComponent(sValue); if (oExpires) { sCookie += "; expires=" + oExpires.toGMTString(); } if (sPath) { sCookie += "; path=" + sPath; } if (sDomain) { sCookie += "; domain=" + sDomain; } if (bSecure) { sCookie += "; secure"; } document.cookie = sCookie; } And in my views.py file this is the situation @base def index(request): if request.session['language'] == 'EN': return """<b>%s</b>""" % "Home" else request.session['language'] == 'BG': return """<b>%s</b>""" % "??????" So I know that my JS changes the value of the language cookie but I think Django doesn't get that. On the other hand when I set and get the cookie in my Python code again the cookie is set. My question is whether there is a way to make JS and Django work together - JavaScript sets the cookie value and Python only reads it when asked and takes adequate actions? Thank you.

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  • Django: Serving a Download in a Generic View

    - by TheLizardKing
    So I want to serve a couple of mp3s from a folder in /home/username/music. I didn't think this would be such a big deal but I am a bit confused on how to do it using generic views and my own url. urls.py url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), The example I am following is found in the generic view section of the Django documentations: http://docs.djangoproject.com/en/dev/topics/generic-views/ (It's all the way at the bottom) I am not 100% sure on how to tailor this to my needs. Here is my views.py def song_download(request, song_id): song = Song.objects.get(id=song_id) response = object_detail( request, object_id = song_id, mimetype = "audio/mpeg", ) response['Content-Disposition'= "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response I am actually at a loss of how to convey that I want it to spit out my mp3 instead of what it does now which is to output a .mp3 with all of the current pages html contained. Should my template be my mp3? Do I need to setup apache to serve the files or is Django able to retrieve the mp3 from the filesystem(proper permissions of course) and serve that? If it do need to configure Apache how do I tell Django that? Thanks in advanced. These files are all on the HD so I don't need to "generate" anything on the spot and I'd like to prevent revealing the location of these files if at all possible. A simple /song/1234/download would be fantastic.

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  • Ajax request not receiving xml from Django

    - by amougeot
    I have a Django server which handles requests to a URL which will return some HTML for use in an image gallery. I can navigate to the URL and the browser will display the HTML that is returned, but I can't get that same HTML by doing an AJAX call (using jQuery) to the same URL. This is the view that generates the response: def gallery_images(request, gallery_name): return render_to_response('galleryimages.html', {'images': get_images_of_gallery(gallery_name)}, mimetype='text/xml') This is the 'galleryimages.html' template: {% for image in images %} <div id="{{image.name}}big"> <div class="actualImage" style="background-image:url({{image.image.name}});"> <h1>{{image.caption|safe}}</h1> </div> </div> {% endfor %} This is the jQuery call I am making: $("#allImages").load("http://localhost:8000/galleryimages/Web"); However, this loads nothing into my #allImages div. I've used firebug and ran jQuery's Ajax method .get("http://localhost:8000/galleryimages/Web") and firebug says that the response text is completely empty. When I check my Django server log, this is the entry I see for when I navigate to the URL manually, through my browser: [16/Jan/2010 17:34:10] "GET /galleryimages/Web HTTP/1.1" 200 215 This is the entry in the server log for when I make the AJAX call: [16/Jan/2010 17:36:19] "OPTIONS /galleryimages/Web HTTP/1.1" 200 215 Why does the AJAX request not get the xml that my Django page is serving?

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  • Django | passing form values

    - by MMRUser
    I want to create a user sign up process that requires two different forms with the same data one (1st form) is for filling out the data and other one (2nd form) is for displaying the filled data as a summery (before actually saving the data) so then user can view what he/she has filled up... my problem is that how do I pass 1st form's data in to the 2nd one .. I have used the basic Django form manipulation mechanism and passed the form field values to the next form using Django template tags.. if request.method == 'POST': form = Users(request.POST) if form.is_valid(): cd = form.cleaned_data try: name = cd['fullName'] email = cd['emailAdd'] password1 = cd['password'] password2 = cd['password2'] phoneNumber = cd['phoneNumber'] return render_to_response('signup2.html', {'name': name, 'email': email, 'password1': password1, 'password2': password2, 'phone': phone, 'pt': phoneType}) except Exception, ex: return HttpResponse("Error %s" % str(ex)) and from the second from I just displayed those field values using tags and also used hidden fields in order to submit the form with values, like this: <label for="">Email:</label> {{ email }} <input type="hidden" id="" name="email" class="width250" value="{{ email }}" readonly /> It works nicely from the out look, but the real problem is that if someone view the source of the html he can simply get the password even hackers can get through this easily. So how do I avoid this issue.. and I don't want to use Django session since this is just a simple sign up process and no other interactions involved. Thanks.

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  • How to get selected category id after 1st page in pagination?

    - by Surjay
    //$id=$_REQUEST['category']; //$catid=mysql_escape_string($id); $catid = isset($_GET['category']) ? (int)$_GET['category'] : 0; $recordsPerPage =4; 0 // //default startup page $pageNum = 1; if(isset($_GET['p'])) { $pageNum = $_GET['p']; settype($pageNum, 'integer'); } $offset = ($pageNum - 1) * $recordsPerPage; //set the number of columns $columns = 1; //set the number of columns $columns = 1; $query = "SELECT temp_id, temp_img, temp_header, temp_resize, temp_small, temp_name, temp_type, cat_id, col_id, artist_id FROM templates where cat_id = '{$catid}' ORDER BY temp_id DESC LIMIT $offset, $recordsPerPage"; $result = mysql_query($query); //we add this line because we need to know the number of rows $num_rows = mysql_num_rows($result); echo ""; //changed this to a for loop so we can use the number of rows for($i = 0; $i < $num_rows; $i++) { while($row = mysql_fetch_array($result)){ if($i % $columns == 0) { //if there is no remainder, we want to start a new row echo ""; } echo ...........my data(s). if(($i % $columns) == ($columns - 1) || ($i + 1) == $num_rows) { echo ""; } } } echo ""; //} ? <div class="pagination"> <? $query = "SELECT COUNT( temp_id ) AS `temp_date` FROM `templates` where cat_id ='{$catid}'"; $result = mysql_query($query) or die('Mysql Err. 2'); $row = mysql_fetch_assoc($result); $numrows = $row['temp_date']; //$numrows = mysql_num_rows($result); $self = $_SERVER['PHP_SELF']; $maxPage = ceil($numrows/$recordsPerPage); $nav = ''; for($page = 1; $page <= $maxPage; $page++) { if ($page == $pageNum) { $nav .= "$page"; } else { $nav .= "$page"; } } if ($pageNum 1) { $page = $pageNum - 1; $prev = ""; $first = ""; } else { $prev = ' '; $first = ' '; } if ($pageNum < $maxPage) { $page = $pageNum + 1; $next = " "; $last = " "; } else { $next = ' '; $last = ' '; } echo " $first $prev $nav $next $last "; ? Here my ajax code: function GetXmlHttpObject(handler) { var objXMLHttp=null if (window.XMLHttpRequest) { objXMLHttp=new XMLHttpRequest() } else if (window.ActiveXObject) { objXMLHttp=new ActiveXObject("Microsoft.XMLHTTP") } return objXMLHttp } function stateChanged() { if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") { document.getElementById("txtResult").innerHTML=xmlHttp.responseText } else { //alert(xmlHttp.status); } } function htmlData(url, qStr) { if (url.length==0) { document.getElementById("txtResult").innerHTML=""; return; } xmlHttp=GetXmlHttpObject() if (xmlHttp==null) { alert ("Browser does not support HTTP Request"); return; } url=url+"?"+qStr; url=url+"&sid="+Math.random(); xmlHttp.onreadystatechange=stateChanged; xmlHttp.open("GET",url,true) ; xmlHttp.send(null); }

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  • Sort queryset by a generic foreign key (django)?

    - by thornomad
    I am using Django's comment framework which utilizes generic foreign keys. Question: How do I sort a given model's queryset by their comment count using the generic foreign key lookup? Reading the django docs on the subject it says one needs to calculate them not using the aggregation API: Django's database aggregation API doesn't work with a GenericRelation. [...] For now, if you need aggregates on generic relations, you'll need to calculate them without using the aggregation API. The only way I can think of, though, would be to iterate through my queryset, generate a list with content_type and object_id's for each item, then run a second queryset on the Comment model filtering by this list of content_type and object_id ... sort the objects by the count, then re-create a new queryset in this order by pulling the content_object for each comment ... This just seems wrong and I'm not even sure how to pull it off. Ideas? Someone must have done this before. I found this post online but it requires me handwriting SQL -- is that really necessary ?

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  • Django template tag basic question

    - by ninja123
    It looks like this template tag works like a charm for most people: http://blog.localkinegrinds.com/2007/09/06/digg-style-pagination-in-django/ For some reason I get this error: Caught an exception while rendering: 'is_paginated' I use this template tag in my template like so: {% load digg_paginator %} {% digg_paginator %} Where digg_paginator.py is in my app/templatetags folder and the included template context digg_paginator.html is in my app/templates folder. The queryset that needs pagination is called 'destinations'. If i just specify {% digg_paginator %}, how does it know what variable to paginate?? I feel I am missing something important here or just plain stupid :P Someone please help, or explain to me how this should be done. Thanks

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  • Django rewrites URL as IP address in browser - why?

    - by Mitch
    I am using django, nginx and apache. When I access my site with a URL (e.g., http://www.foo.com/) what appears in my browser address is the IP address with admin appended (e.g., http://123.45.67.890/admin/). When I access the site by IP, it is redirected as expected by django's urls.py (e.g., http://123.45.67.890/ - http://123.45.67.890/accounts/login/?next=/) I would like to have the name URL act the same way as the IP. That is, if the URL goes to a new view, the host in the browser address should remain the same and not change to the IP address. Where should I be looking to fix this? My files: ; cpa.com (apache) NameVirtualHost *:8080 <VirtualHost *:8080> AddOutputFilterByType DEFLATE text/html text/plain text/xml text/css text/javascript application/javascript application/x-javascript BrowserMatch ^Mozilla/4 gzip-only-text/html BrowserMatch ^Mozilla/4\.0[678] no-gzip BrowserMatch \bMSIE !no-gzip !gzip-only-text/htm DocumentRoot /path/to/root ServerName www.foo.com <IfModule mod_rpaf.c> RPAFenable On RPAFsethostname On RPAFproxy_ips 127.0.0.1 </IfModule> <Directory /public/static> AllowOverride None AddHandler mod_python .py PythonHandler mod_python.publisher </Directory> Alias / /dj <Location /> SetHandler python-program PythonPath "['/usr/lib/python2.5/site-packages/django', '/usr/lib/python2.5/site-packages/django/forms'] + sys.path" PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE dj.settings PythonDebug On </Location> </VirtualHost> ; ; ports.conf (apache) Listen 127.0.0.1:8080 ; ; cpa.conf (nginx) server { listen 80; server_name www.foo.com; location /static { root /var/public; index index.html; } location /cpa/js { root /var/public/js; } location /cpa/css { root /var/public/css; } location /djmedia { alias "/usr/lib/python2.5/site-packages/django/contrib/admin/media/"; } location / { include /etc/nginx/proxy.conf; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_pass http://127.0.0.1:8080; } } ; ; proxy.conf (nginx) proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 500; proxy_buffers 32 4k;

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  • File uploads and client_max_body_size in nginx + gunicorn + django

    - by carlosescri
    I need to configure nginx + gunicorn to be able to upload files greater than the default max size in both servers. My nginx .conf file looks like this: server { # ... location / { proxy_pass_header Server; proxy_set_header Host $http_host; proxy_redirect off; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Scheme $scheme; proxy_connect_timeout 60; proxy_pass http://localhost:8000/; } } The idea is to allow requests of 20M for two locations: /admin/path/to/upload?param=value /installer/other/path/to/upload?param=value I've tried to add location directives at the same level than the one I've pasted here (getting 404 errors) and also tried to add them inside the location / directive (getting 413 Entity Too Large errors). My location directives look like these in their simplest form: location /admin/path/to/upload/ { client_max_body_size 20M; } location /installer/other/path/to/upload/ { client_max_body_size 20M; } But they don't work (actually I tested lots of combinations and I'm desperate thinking about this. Please, help If you can: What settings do I need to set to make this work? Thank you so much!

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  • permission errors with python/django

    - by tipu
    Error can be seen here: http://djaffry.selfip.com:8080/ If i go to the folder /srv/twingle/search and do ls -l I get -rwxrwxrwx 1 root root 65142784 May 26 20:28 words.db I gave it 777 access (absolutely unsafe, I know, but I thought it would atleast work) any idea what can be the permissions problem? Edit: A very strange problem is that the code doesn't crash once every few refreshes.. then goes back to crashing

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  • Is windows a "second class citizen" in the django community?

    - by Daniel Upton
    I'm currently doing R&D for a web application which we plan to host ourselves initially and then allow customers to self host. My task has been evaluating web frameworks to see which would give us the biggest productivity initially and ease of maintence while also allowing us to easily support deployment to customer controlled environments. Our team has experience with ASP.NET (MVC and Webforms) and Ruby on Rails. Our experience with rails is that windows deployment is a very taboo subject and any questions on IRC or SO are met with knee jerk "why not linux" responses.. However in this case our target market may be running windows or linux servers. Is this also the case in django land? Is it possible with rubbish performance? Is it possible with lost of pain? Is it seen as reasonable and not treated as a completely stupid idea for not wanting to run linux?

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  • Django templates crashes with no sense

    - by user233323
    Hello I'm trying to use google visualization API along with django templates system. I got an error that don't know how to fix. The error is the following: invalid_block_tag raise self.error(token, "Invalid block tag: '%s'" % command) django.template.TemplateSyntaxError: Invalid block tag: 'endfor' The code is: function drawChart() { var data = new google.visualization.DataTable(); data.addColumn('date', 'time'); data.addColumn('number', 'x'); data.addColumn('number', 'y'); data.addColumn('number', 'z'); data.addRows([ {% for d in datos &} [new Date({{d.instante|date:"Y, m, d, H, i, s"}}), {{d.x}}, {{d.y}}, {{d.z}}] {% if not forloop.last %},{% endif %} ]); {% endfor %} var chart = new google.visualization.AnnotatedTimeLine(document.getElementById('chart_div')); chart.draw(data, {displayAnnotations: true}); } Thanks you all!

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  • Django ORM: Ordering w/ aggregate functions — None special treatment

    - by deno
    Hi, I'm doing query like that: SomeObject.objects.annotate(something=Avg('something')).order_by(something).all() Now, I normally have an aggregate field in my model that I use with Django signals to keep in sync, however in this case perfomance isn't an issue so I thought I'd keep it simple and just use subqueries. This approach, however, presented an unexpected issue: It all works grate if aggregate function results are like this: [5.0, 4.0, 6.0 … (etc, just numbers)] However if you mix in some Nones than it's being ordered like this: [None, 5.0, 4.0 …] The issue is that None has higher value than any number, while it should have value at most of 0. I'm using PostgreSQL and haven't tested w/ other DBs. I haven't actually checked what query is generated etc. I worked it around by just sorting in memory: sorted(…, key=lambda _:_.avg_rating if _.avg_rating is not None else 0) So I'm just curious if you know a way to do it w/ just Django ORM. Perhaps .where? or something… Kind regards

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  • Best practice for Python & Django constants

    - by Dylan Klomparens
    I have a Django model that relies on a tuple. I'm wondering what the best practice is for refering to constants within that tuple for my Django program. Here, for example, I'd like to specify "default=0" as something that is more readable and does not require commenting. Any suggestions? Status = ( (-1, 'Cancelled'), (0, 'Requires attention'), (1, 'Work in progress'), (2, 'Complete'), ) class Task(models.Model): status = models.IntegerField(choices=Status, default=0) # Status is 'Requires attention' (0) by default. EDIT: If possible I'd like to avoid using a number altogether. Somehow using the string 'Requires attention' instead would be more readable.

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  • Django deployment: PIL and virtualenv problem

    - by AndriJan
    Hey guys, I'm deploying a Django site on my Vserver (Debian Lenny) and I'm having problem with PIL. I'm using virtualenv as well. When I'm in the virtualenv and type pip install -U PIL everything installs fine and I get this: *** TKINTER support not available --- JPEG support available --- ZLIB (PNG/ZIP) support available *** FREETYPE2 support not available *** LITTLECMS support not available And when I go in to the shell (python manage.py shell) and type from PIL import Image I get no error. But when I use it in the Django project (uploading an image in the admin for example) I just get No module named PIL I don't think it's a problem with the model because it works fine on the development machine but here is part of the class: class Category(models.Model): name = models.CharField(max_length=255, verbose_name="Name") logo = models.ImageField(upload_to='images/category/', blank=True, null=True, verbose_name="Logo") I'm going out of my mind about this. I feel like this is a very common issue but I've been trying to google this all day with no luck. Thanks in advance, AndriJan

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  • django select max field from mysql when column is varchar

    - by doza
    Hi, Using Django 1.1, I am trying to select the maximum value from a varchar column (in MySQL.) The data stored in the column looks like: 9001 9002 9017 9624 10104 11823 (In reality, the numbers are much bigger than this.) This worked until the numbers incremented above 10000: Feedback.objects.filter(est__pk=est_id).aggregate(sid=Max('sid')) Now, that same line would return 9624 instead of 11823. I'm able to run a query directly in the DB that gives me what I need, but I can't figure out the best way to do this in Django. The query would be: select max(sid+0) from Feedback; Any help would be much appreciated. Thanks!

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  • Django auth without "auth_*" tables

    - by Travis Jensen
    We would like to use our own tables for user management instead of the Django "auth" tables. We already have database tables that include all of the relevant information our application needs but it isn't in the Django format. We would prefer not to have the information duplicated in two tables. We would like to utilize the auth package, though, as there is some very nice functionality that we don't want to replicate. I realize we could build our own auth backend, but that doesn't, as far as I can tell, remove the need for two sets of tables in this case. Am I correct in assuming that we cannot do this? I have found no docs that discuss how to modify the underlying model that the auth package is using. The backend simply pre-populates the user object that would eventually be saved in the auth tables. Thanks!

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  • async handler deleted by the wrong thread in django

    - by user3480706
    I'm run this algorithm in my django application.when i run several time from my GUI django local server will stopped and i got this error Exception RuntimeError: RuntimeError('main thread is not in main loop',) in ignored Tcl_AsyncDelete: async handler deleted by the wrong thread Aborted (core dumped) code print "Learning the sin function" network =MLP.MLP(2,10,1) samples = np.zeros(2000, dtype=[('x', float, 1), ('y', float, 1)]) samples['x'] = np.linspace(-5,5,2000) samples['y'] = np.sin(samples['x']) #samples['y'] = np.linspace(-4,4,2500) for i in range(100000): n = np.random.randint(samples.size) network.propagate_forward(samples['x'][n]) network.propagate_backward(samples['y'][n]) plt.figure(figsize=(10,5)) # Draw real function x = samples['x'] y = samples['y'] #x=np.linspace(-6.0,7.0,50) plt.plot(x,y,color='b',lw=1) samples1 = np.zeros(2000, dtype=[('x1', float, 1), ('y1', float, 1)]) samples1['x1'] = np.linspace(-4,4,2000) samples1['y1'] = np.sin(samples1['x1']) # Draw network approximated function for i in range(samples1.size): samples1['y1'][i] = network.propagate_forward(samples1['x1'][i]) plt.plot(samples1['x1'],samples1['y1'],color='r',lw=3) plt.axis([-2,2,-2,2]) plt.show() plt.close() return HttpResponseRedirect('/charts/charts') how can i fix this error ?need a quick help

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  • Apache/Django subdomains problem

    - by Thomas
    Now I have apache configuration which works only with localhost domain (http://localhost/). Alias /media/ "/sciezka/do/instalacji/django/contrib/admin/media/" Alias /site_media/ "/sciezka/do/plikow/site_media/" <Location "/"> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE settings PythonPath "['/thomas/django_projects/project'] + sys.path" PythonDebug On </Location> <Location "/site_media"> SetHandler none </Location> How can I make it working for some subdomains like pl.localhost or uk.localhost? This subdomains should display the same page what domain (localhost). Second question: It is possible change default localhost address (http://localhost/) to (http://localhost.com/) or (http://www.localhost.com/) or something else?

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  • Apache/Django subdomains problem

    - by Thomas
    Now I have apache configuration which works only with localhost domain (http://localhost/). Alias /media/ "/sciezka/do/instalacji/django/contrib/admin/media/" Alias /site_media/ "/sciezka/do/plikow/site_media/" <Location "/"> SetHandler python-program PythonHandler django.core.handlers.modpython SetEnv DJANGO_SETTINGS_MODULE settings PythonPath "['/thomas/django_projects/project'] + sys.path" PythonDebug On </Location> <Location "/site_media"> SetHandler none </Location> How can I make it working for some subdomains like pl.localhost or uk.localhost? This subdomains should display the same page what domain (localhost). Second question: It is possible change default localhost address (http://localhost/) to (http://localhost.com/) or (http://www.localhost.com/) or something else?

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  • Django Auth Model Issue - AUTH_USER_MODEL Not Installed

    - by Ian Warner
    Trying to debug this error with getting a Django project running ImproperlyConfigured: AUTH_USER_MODEL refers to model 'accounts.User' that has not been installed Running python manage.py migrate Must iterate i am in no way a python or django expert - I have simply inherited someone elses project that I am trying to get running for the team here. I have followed steps to install postgres required modules including south creating database for postgres Any help appreciated on how to debug this. settings/base.py contains INSTALLED_APPS = DJANGO_APPS + THIRD_PARTY_APPS + LOCAL_APPS LOCAL_APPS = ( 'apps.core', 'apps.accounts', 'apps.project_tool', 'apps.internal', 'apps.external', ) so apps.accounts exits - but it asks for AUTH_USER_MODEL = 'accounts.User' - should it be AUTH_USER_MODEL = 'apps.accounts.User'?

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  • Problems with Snow Leopard, Django & PIL

    - by Cato Johnston
    Hi I am having some trouble getting Django & PIL work properly since upgrading to Snow Leopard. I have installed freetype, libjpeg and then PIL, which tells me: --- TKINTER support ok --- JPEG support ok --- ZLIB (PNG/ZIP) support ok --- FREETYPE2 support ok but when I try to upload a jpeg through the django admin interface I get: Upload a valid image. The file you uploaded was either not an image or a corrupted image. It works fine with PNG files. Any Ideas?

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  • Rate limiting Django admin login with Nginx to prevent dictionary attack

    - by shreddies
    I'm looking into the various methods of rate limiting the Django admin login to prevent dictionary attacks. One solution is explained here: simonwillison.net/2009/Jan/7/ratelimitcache/ However, I would prefer to do the rate limiting at the web server side, using Nginx. Nginx's limit_req module does just that - allowing you to specify the maximum number of requests per minute, and sending a 503 if the user goes over: http://wiki.nginx.org/NginxHttpLimitReqModule Perfect! I thought I'd cracked it until I realised that Django admin's login page is not in a consistent place, eg /admin/blah/ gives you a login page at that URL, rather than bouncing to a standard login page. So I can't match on the URL. Can anyone think of another way to know that the admin page was being displayed (regexp the response HTML?)

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