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  • tiled images in swing

    - by sasquatch90
    I have task to prepare two windows with swing. One contains grid of squares, with random numbers in them. In second I need to load pieces of tiled image and then show them in the correct order, forming tiled image. Windows should look like this : http://img535.imageshack.us/img535/3129/lab8a.jpg Okay so how to bite this ? I've used swing only few times to draw some 2d polylines, so basically I just theoretically now what to do. Ok, so window number 1: I start with creating Jframe for the window. Then I do for loop and in it create 16 JLabels with random numbers in them ? How to set margins between each tile and the whole window ? Window number 2 : So I start the same, but instead of loading numbers I add images ? Now, how can I load image from file and then set it as background ?

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  • Counting number of times an item occurs in a linked list

    - by HanaCHaN92
    Here is the assignment: Here's the assignment: Implement a method countValue() that counts the number of times an item occurs in a linked list. Remember to use the STL list. int countValue(list front, const int item); Generate 20 random numbers in the range of 0 to 4, and insert each number in the linked list. Output the list by using a method which you would call writeLinkedList which you would add to the ListP.cpp. In a loop, call the method countValue() , and display the number of occurrences of each value from 0 to 4 in the list. Remember that all the above is to be included in the file ListP.ccp Run: 2 3 4 0 1 0 2 4 2 3 3 4 3 3 3 0 0 2 0 2 0 : 5, 1 : 1, 2 : 5, 3 : 6, 4 : 3 and here is what I have so far: #include<iostream> #include<list> #include<tchar.h> int countValue(list<int> front, const int item); using namespace std; int _tmain(int argc, _TCHAR* argv[]){ list<int> front; int listCount; cout << "Enter the size of the list: "; cin >> listCount; for (int i = 1; i <= listCount; i++) front.insert(rand()%5); cout << "Original List of Values: " << endl; //writeLinkedList(front, " "); cout << endl; for(int j=0;j<5;++j) cout << countValue (front,j) << endl; cout << endl; return 0; } int countValue(list<int> front, const int item) { int count0; int count1; int count2; int count3; int count4; list<int> *List; for(list<int>::iterator i = front.begin(); i != front.end(); i++) { if(List->item == 0) { count0++; } if(List->item == 1) { count1++; } if(List->item == 2) { count2++; } if(List->item == 3) { count2++; }if(List->item == 4) { count4++; } } } And here are the errors: error C2065: 'list' : undeclared identifier line 5 error C2062: type 'int' unexpected line 5 error C2661: 'std::list<_Ty>::insert' : no overloaded function takes 1 arguments line 16 error C3861: 'countValue': identifier not found line 21 IntelliSense: no instance of overloaded function "std::list<_Ty, _Ax>::insert [with _Ty=int, _Ax=std::allocator<int>]" matches the argument list line 16 IntelliSense: too few arguments in function call line 16 error C2039: 'item': is not a member of 'std::list<_Ty>' lines 34, 38, 42, 46, 49 IntelliSense: declaration is incompatible with "int countValue" (declared at line 5) line 25 IntelliSense: class "std::list<int, std:: allocator<int>>" has no member "item" lines 34, 38, 42, 46, 49 I just want to know what I've done wrong and how to fix it and also if someone could help me figure out if I'm doing the countValue function wrong or not based on the instructions I would really appreciate it. I've read the chapter in our textbook several times, looked up tutorials on youtube and on Dream in Code, and still I can not figure this out. All helpful information is appreciated!

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  • Understanding prolog [lists]

    - by wwrob
    I am to write a program that does this: ?- pLeap(2,5,X,Y). X = 2, Y = 3 ; X = 3, Y = 4 ; X = 4, Y = 5 ; X = 5, Y = 5 ; false. (gives all pairs X,X+1 between 2 and 5, plus the special case at the end). This is supposedly the solution. I don't really understand how it works, could anyone guide me through it? pLeap(X,X,X,X). pLeap(L,H,X,Y) :- L<H, X is L, Y is X+1. pLeap(L,H,X,Y) :- L=<H, L1 is L+1, pLeap(L1,H,X,Y). I'd do it simply like this: pLeap(L,H,X,Y) :- X >= L, X =< H, Y is X+1. Why doesn't it work (ignoring the special case at the end)?

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  • dynimically using pointer

    - by gcc
    Input: 3 1 2 n 4 5 d 1 21 30 x Output: 2: 4 5 21 30 Input: 3 j 3 34 6 22 10 51 n 1 2 j 1 3 4 5 n 6 7 x Output: 1: 1 2 3 4 5 2: 6 7 3: 34 6 22 10 51 'j': (Jump to array# command) 'd': (Delete array# command) 'n': (Next array command) 'x': (Exit command) #: (Integer number) int num_arrays; /* maximum number of arrays */ int **arrays; /* array of array pointers */ int *l_arrays; /* actual lengths of arrays */ int *c_arrays; /* actual capacities of arrays */ how can we write that code

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  • Javascript question

    - by Craig
    I am supposed to make this simple program. It produces a multiplication problem, and when the user types the correct answer, it is supposed to produce another question. Instead it goes into an infinite loop and never stops, the answer field and the button go away. Also, I am supposed to make the comment about the users answer, one of 4 different sayings. Without using Arrays how would I do that? My professor is no help, really getting aggravated as I have no where else to turn. <html> <title>HW 9.27 and 9.28</title> <head> <script type="text/javascript"> var number1; var number2; var answer3; var answer2; function problem() { number1 = Math.floor(1 + Math.random() * 9); number2 = Math.floor(1 + Math.random() * 9); document.writeln("How much is " + number1 + " times " + number2 + " ?"); answer2 = (number1 * number2); } function answer1() { var statusDiv = document.getElementById("status"); answer3 = document.getElementById("answer").value; if (answer3 != answer2) statusDiv.innerHTML = "No. Please try again"; else if (answer3 == answer2) { statusDiv.innerHTML = "Very good!"; problem(); } } problem(); </script> </head> <body> <form> <input id="answer" type="text" /> <input type="button" value="Solve!" onclick="answer1()" /> <div id ="status">Click the Solve button to Solve the problem</div> </form> </body> </html>

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  • C# Freq. Table with Random Values

    - by Sef
    Hello, I am trying to write a frequency program that will represent a bar diagram (in console code). The problem is i have no idea how exactly to caculate this frequency or how do i exactly then give the bars different heights according to there frequency (trough calculation). The frequency height is capped at 21. (meaning the bars go from 1 to 21, so the max bar height would be for example 21 stars(* as display sign for the bar itself). A calculation i have so far (although not sure if correct) for frequency: This array takes the random values generated: for (int j = 0; j < T.Length; j++) { T[j] = (MaxHeight* T[j]) / Ber.GreatestElement(T); Console.Write("{0,7}", T[j]); } This results in values between 0 and 21 -- Based on the values my bars should give a certain height compared to all the other frequency values. (for example 8000 could have 21 in height where 39 could have 1). To represent this diagram i used 2 for loops to display height and width (keep in mind i only wish to use Using System; to keep it to the "basics"). for (int height= 1; height<= 21; height++) { for (int width= 0; width<= 10; width++) { if(...??) { Console.Write("{0,7}", bar); // string bar= ("*"); } else { Console.Write("{0,7}", empty); } } Console.WriteLine(); } So so far i have a entire field filled with * and the random values generated along with their frequency value (although i have no idea if the freq value is properly calculated). I assume i need a if (.....) in the second for but i cannot seem to get further then this. Thanks in advance!

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  • JAX-B annotations for elements that inherit from a parent

    - by AlexM
    When adding JAX-B Java annotations for Java classes - if I have a parent Class Entry, with two children, Book and JournalArticle, Would I add these annotations for all three classes: @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement ie: @XmlSeeAlso({au.com.library.Book.class, au.com.library.JournalArticle.class}) @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement public abstract class Entry implements Serializable{ private static final long serialVersionUID = -1895155325179947581L; @XmlElement(name="title") protected String title; @XmlElement(name="author") protected String author; @XmlElement(name="year") protected int year; and @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement public class Book extends Entry { @XmlElement(name="edition") private String edition; @XmlElement(name="publisher") private String publisher; @XmlElement(name="placeOfPublication") private String placeOfPub; and @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement public class JournalArticle extends Entry { @XmlElement(name="journalTitle") private String journalTitle; @XmlElement(name="volume") private String volume; @XmlElement(name="issue") private String issue; @XmlElement(name="pageNumbers") private String pgNumbers;

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  • Sorting a list of numbers with modified cost

    - by David
    First, this was one of the four problems we had to solve in a project last year and I couldn’t find a suitable algorithm so we handle in a brute force solution. Problem: The numbers are in a list that is not sorted and supports only one type of operation. The operation is defined as follows: Given a position i and a position j the operation moves the number at position i to position j without altering the relative order of the other numbers. If i j, the positions of the numbers between positions j and i - 1 increment by 1, otherwise if i < j the positions of the numbers between positions i+1 and j decreases by 1. This operation requires i steps to find a number to move and j steps to locate the position to which you want to move it. Then the number of steps required to move a number of position i to position j is i+j. We need to design an algorithm that given a list of numbers, determine the optimal (in terms of cost) sequence of moves to rearrange the sequence. Attempts: Part of our investigation was around NP-Completeness, we make it a decision problem and try to find a suitable transformation to any of the problems listed in Garey and Johnson’s book: Computers and Intractability with no results. There is also no direct reference (from our point of view) to this kind of variation in Donald E. Knuth’s book: The art of Computer Programing Vol. 3 Sorting and Searching. We also analyzed algorithms to sort linked lists but none of them gives a good idea to find de optimal sequence of movements. Note that the idea is not to find an algorithm that orders the sequence, but one to tell me the optimal sequence of movements in terms of cost that organizes the sequence, you can make a copy and sort it to analyze the final position of the elements if you want, in fact we may assume that the list contains the numbers from 1 to n, so we know where we want to put each number, we are just concerned with minimizing the total cost of the steps. We tested several greedy approaches but all of them failed, divide and conquer sorting algorithms can’t be used because they swap with no cost portions of the list and our dynamic programing approaches had to consider many cases. The brute force recursive algorithm takes all the possible combinations of movements from i to j and then again all the possible moments of the rest of the element’s, at the end it returns the sequence with less total cost that sorted the list, as you can imagine the cost of this algorithm is brutal and makes it impracticable for more than 8 elements. Our observations: n movements is not necessarily cheaper than n+1 movements (unlike swaps in arrays that are O(1)). There are basically two ways of moving one element from position i to j: one is to move it directly and the other is to move other elements around i in a way that it reaches the position j. At most you make n-1 movements (the untouched element reaches its position alone). If it is the optimal sequence of movements then you didn’t move the same element twice.

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  • Mathmatic errors in basic C++ program

    - by Heather
    I am working with a basic C++ program to determine the area and perimeter of a rectangle. My program works fine for whole numbers but falls apart when I use any number with a decimal. I get the impression that I am leaving something out, but since I'm a complete beginner, I have no idea what. Below is the source: #include <iostream> using namespace std; int main() { // Declared variables int length; // declares variable for length int width; // declares variable for width int area; // declares variable for area int perimeter; // declares variable for perimeter // Statements cout << "Enter the length and the width of the rectangle: "; // states what information to enter cin >> length >> width; // user input of length and width cout << endl; // closes the input area = length * width; // calculates area of rectangle perimeter = 2 * (length + width); //calculates perimeter of rectangle cout << "The area of the rectangle = " << area << " square units." <<endl; // displays the calculation of the area cout << "The perimeter of the rectangle = " << perimeter << " units." << endl; // displays the calculation of the perimeter system ("pause"); // REMOVE BEFORE RELEASE - testing purposes only return 0; }

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  • overflow technique in stack

    - by metashockwave
    int main(void) { problem2(); } void doit2(void) { int overflowme[16]; //overflowme[37] =0; } void problem2(void) { int x = 42; doit2(); printf("x is %d\n", x); printf("the address of x is 0x%x\n", &x); } Would someone help me understand why overflowme[37] =0; from the doit2 function will overwrite the value of x? (please include Program Counter and Frame Pointer of the function doit2 in your explanation) Thank you! It works every time with Project properties-Configuration properties-C/C++ -Code Generation-Basic Runtime Checks set to "Default". so it's not an undefined behavior.

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  • How do I add an object to a binary tree based on the value of a member variable?

    - by Max
    How can I get a specific value from an object? I'm trying to get a value of an instance for eg. ListOfPpl newListOfPpl = new ListOfPpl(id, name, age); Object item = newListOfPpl; How can I get a value of name from an Object item?? Even if it is easy or does not interest you can anyone help me?? Edited: I was trying to build a binary tree contains the node of ListOfPpl, and need to sort it in the lexicographic. Here's my code for insertion on the node. Any clue?? public void insert(Object item){ Node current = root; Node follow = null; if(!isEmpty()){ root = new Node(item, null, null); return; }boolean left = false, right = false; while(current != null){ follow = current; left = false; right = false; //I need to compare and sort it if(item.compareTo(current.getFighter()) < 0){ current = current.getLeft(); left = true; }else { current = current.getRight(); right = true; } }if(left) follow.setLeft(new Node(item, null, null)); else follow.setRight(new Node(item, null, null)); }

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  • Errors not printing correctly..Is this logic flow correct? c++

    - by igor
    Example user input: PA1 9 //correct PJ1 9 //wrong, error printed "Invalid row" because it is not between A and I PA11 9 //wrong, error printer "Invalid column" because it is not between 1 and 9. The problem I am having is that it should clear the remaining input and then ask for the user to enter the "move" again, and it is not. Where did I go wrong? I've been at it for a while and still got no progress.. void clearInput() { cin.clear(); } bool getCoords(int & x, int & y) { char row; while(true){ cin>>row>>y; row=toupper(row); if(/*(id=='P' || id=='p' || id=='D' || id=='d') && */row>='A' && row<='I' && isalpha(row) && y>=1 && y<=9){ x=row-'A'; y=y-1; return true; } else if(!(y>=1 && y<=9)){ cout<<"Invalid column\n"<< endl << endl; cout<<y; clearInput(); cout<<y; //return false; } else{ cout<<"Invalid row\n"<< endl << endl; clearInput(); //cout<<x<<y; //return false; } } }

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  • Java - Counting how many characters show up in another string

    - by Vu Châu
    I am comparing two strings, in Java, to see how many characters from the first string show up in the second string. The following is some expectations: matchingChars("AC", "BA") ? 1 matchingChars("ABBA", "B") ? 2 matchingChars("B", "ABBA") ? 1 My approach is as follows: public int matchingChars(String str1, String str2) { int count = 0; for (int a = 0; a < str1.length(); a++) { for (int b = 0; b < str2.length(); b++) { char str1Char = str1.charAt(a); char str2Char = str2.charAt(b); if (str1Char == str2Char) { count++; str1 = str1.replace(str1Char, '0'); } } } return count; } I know my approach is not the best, but I think it should do it. However, for matchingChars("ABBA", "B") ? 2 My code yields "1" instead of "2". Does anyone have any suggestion or advice? Thank you very much.

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  • Delete last 3 lines within while ((line = r.ReadLine()) != null) but not open a new text file to delete the lines?

    - by user1473672
    This is the code I've seen so far to delete last 3 lines in a text file, but it's required to determine string[] lines = File.ReadAllLines(); which is nt necessary for me to do so. string[] lines = File.ReadAllLines(@"C:\\Users.txt"); StringBuilder sb = new StringBuilder(); int count = lines.Length - 3; // except last 3 lines for (int s = 0; s < count; s++) { sb.AppendLine(lines[s]); } The code works well, but I don't wanna re-read the file as I've mentioned the streamreader above : using (StreamReader r = new StreamReader(@"C:\\Users.txt")) Im new to C#, as far as I know, after using streamreader, and if I wanna modify the lines, I have to use this : while ((line = r.ReadLine()) != null) { #sample codes inside the bracket line = line.Replace("|", ""); line = line.Replace("MY30", ""); line = line.Replace("E", ""); } So, is there any way to delete the last 3 lines in the file within the "while ((line = r.ReadLine()) != null)" ?? I have to delete lines, replace lines and a few more modications in one shot, so I can't keep opening/reading the same text file again and again to modify the lines. I hope the way I ask is understable for you guys .< Plz help me, I know the question sounds simple but I've searched so many ways to solve it but failed =( So far, my code is : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.IO; namespace ConsoleApplication11 { public class Read { static void Main(string[] args) { string tempFile = Path.GetTempFileName(); using (StreamReader r = new StreamReader(@"C:\\Users\SAP Report.txt")) { using (StreamWriter sw = new StreamWrite (@"C:\\Users\output2.txt")) { string line; while ((line = r.ReadLine()) != null) { line = line.Replace("|", ""); line = line.Replace("MY30", ""); line = line.Replace("E", ""); line = System.Text.RegularExpressions.Regex.Replace(line, @"\s{2,}", " "); sw.WriteLine(line); } } } } } } Now my next task is to delete the last 3 lines in the file after these codes, and I need help on this one. Thank you.

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  • Return the Largest Span in a given Array -Core Java and Arrays Question

    - by Deepak
    Hi Stack People, Merry Christmas and hope you are in great Spirits,I have a Question in Java-Arrays as shown below.Im stuck up with this struggling to get it rite. Consider the leftmost and righmost appearances of some value in an array. We'll say that the "span" is the number of elements between the two inclusive. A single value has a span of 1. Write a **Java Function** that returns the largest span found in the given array. **Example: maxSpan({1, 2, 1, 1, 3}) ? 4,answer is 4 coz MaxSpan between 1 to 1 is 4 maxSpan({1, 4, 2, 1, 4, 1, 4}) ? 6,answer is 6 coz MaxSpan between 4 to 4 is 6 maxSpan({1, 4, 2, 1, 4, 4, 4}) ? 6,answer is 6 coz Maxspan between 4 to 4 is 6 which is greater than MaxSpan between 1 and 1 which is 4,Hence 64 answer is 6. I have the code which is not working,it includes all the Spans for a given element,im unable to find the MaxSpan for a given element. Please help me out. Results of the above Program are as shown below Expected This Run maxSpan({1, 2, 1, 1, 3}) ? 4 5 X maxSpan({1, 4, 2, 1, 4, 1, 4}) ? 6 8 X maxSpan({1, 4, 2, 1, 4, 4, 4}) ? 6 9 X maxSpan({3, 3, 3}) ? 3 5 X maxSpan({3, 9, 3}) ? 3 3 OK maxSpan({3, 9, 9}) ? 2 3 X maxSpan({3, 9}) ? 1 1 OK maxSpan({3, 3}) ? 2 3 X maxSpan({}) ? 0 1 X maxSpan({1}) ? 1 1 OK ::Code:: public int maxSpan(int[] nums) { int count=1;//keep an intial count of maxspan=1 int maxspan=0;//initialize maxspan=0 for(int i=0;i<nums.length;i++){ for(int j=i+1;j<nums.length;j++){ if(nums[i] == nums[j]){ //check to see if "i" index contents == "j" index contents count++; //increment count maxspan=count; //make maxspan as your final count int number = nums[i]; //number=actual number for maxspan } } } return maxspan+1; //return maxspan }

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  • Help me understand why page sizes are a power of 2?

    - by eric
    Answer I need help with is: Recall that paging is implemented by breaking up an address into a page and offset number. It is most efficient to break the address into X page bits and Y offset bits, rather than perform arithmetic on the address to calculate the page number and offset. Because each bit position represents a power of 2, splitting an address between bits results in a page size that is a power of 2. i don't quite understand this answer, can anyone give a simpler explanation?

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  • Java Sql Udate error, data type missmatch

    - by codo
    I have created a table in ms access. I have set the data type of ID to Auto Number in MS-access. In java when I try to update a record. the netBeans IDE gives me the error of " data type missmatch in criteria expression". But when I changed the ID number that was not in the table already it works well. The code is below. String sql = "Update table1 set price ='" + txtPrice.getText() + "', quantity='" + txtQuantity.getText() + "', description='" + txtDescription.getText() + "' where id= " + txtid.getText() + ""; try { pst = conn.prepareStatement(sql); pst.executeUpdate(); JOptionPane.showMessageDialog(null, "Updated"); UpdateJTable(); } catch (Exception e) { JOptionPane.showMessageDialog(null, e); }

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  • Big O Complexity of a method

    - by timeNomad
    I have this method: public static int what(String str, char start, char end) { int count=0; for(int i=0;i<str.length(); i++) { if(str.charAt(i) == start) { for(int j=i+1;j<str.length(); j++) { if(str.charAt(j) == end) count++; } } } return count; } What I need to find is: 1) What is it doing? Answer: counting the total number of end occurrences after EACH (or is it? Not specified in the assignment, point 3 depends on this) start. 2) What is its complexity? Answer: the first loops iterates over the string completely, so it's at least O(n), the second loop executes only if start char is found and even then partially (index at which start was found + 1). Although, big O is all about worst case no? So in the worst case, start is the 1st char & the inner iteration iterates over the string n-1 times, the -1 is a constant so it's n. But, the inner loop won't be executed every outer iteration pass, statistically, but since big O is about worst case, is it correct to say the complexity of it is O(n^2)? Ignoring any constants and the fact that in 99.99% of times the inner loop won't execute every outer loop pass. 3) Rewrite it so that complexity is lower. What I'm not sure of is whether start occurs at most once or more, if once at most, then method can be rewritten using one loop (having a flag indicating whether start has been encountered and from there on incrementing count at each end occurrence), yielding a complexity of O(n). In case though, that start can appear multiple times, which most likely it is, because assignment is of a Java course and I don't think they would make such ambiguity. Solving, in this case, is not possible using one loop... WAIT! Yes it is..! Just have a variable, say, inc to be incremented each time start is encountered & used to increment count each time end is encountered after the 1st start was found: inc = 0, count = 0 if (current char == start) inc++ if (inc > 0 && current char == end) count += inc This would also yield a complexity of O(n)? Because there is only 1 loop. Yes I realize I wrote a lot hehe, but what I also realized is that I understand a lot better by forming my thoughts into words...

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  • How to return a copy of the data in C++

    - by Josh Curren
    I am trying to return a new copy of the data in a C++ Template class. The following code is getting this error: invalid conversion from ‘int*’ to ‘int’. If I remove the new T then I am not returning a copy of the data but a pointer to it. template<class T> T OrderedList<T>::get( int k ) { Node<T>* n = list; for( int i = 0; i < k; i++ ) { n=n->get_link(); } return new T( n->get_data() ); // This line is getting the error ********** }

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