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  • how to display list of partition under 'Go' menu

    - by Roy
    I'm installing ubuntu 12.04 on my asus A43S notebook, but couldn't see any other partition under the 'Go' menu. I tried 'sudo fdisk -l' seems fine, it displays all partition. I also installed ubuntu 12.04 on my PC but there were no problems, all partition are listed under the 'Go' menu, and automaticly mounted when I clicked on them. question is, how to display all partition just like on my PC does, I don't want to mount via terminal each time I need to access them. thanks.

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  • List item stuck in "Pending"

    - by Norgean
    Problem simplified: On approval, you have an event receiver that changes a field according to some weird and wonderful business logic. But the item remains in "Pending" state. Why?   First, you obviously need to turn off the event handling when you change things in the event receiver. If not, the event receiver will be called because the item changed. Infinite recursion is a bad thing. But you guessed that.   But that's not what was wrong. The culprit in my case was that items are set to require a new approval whenever the item is changed. This is good, but not what we want in this particular case. So force it back to approved after the other column has been changed.

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  • prints line number in both txtfile and list????

    - by jad
    i have this code which prints the line number in infile but also the linenumber in words what do i do to only print the line number of the txt file next to the words??? d = {} counter = 0 wrongwords = [] for line in infile: infile = line.split() wrongwords.extend(infile) counter += 1 for word in infile: if word not in d: d[word] = [counter] if word in d: d[word].append(counter) for stuff in wrongwords: print(stuff, d[stuff]) the output is : hello [1, 2, 7, 9] # this is printing the linenumber of the txt file hello [1] # this is printing the linenumber of the list words hello [1] what i want is: hello [1, 2, 7, 9]

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  • How to access Sharepoint List Items using an ID

    - by GEShafer
    I am currently working on a nice table that displays the items in a list of "Tasks" on a dispForm page. Each Task is created and initially given a ProjectID depending on which project the task is for. The ProjectID is the actual ID given to the "project" when it is added to the list, therefore it is not actually a parameter in the list of projects while it is a parameter in the list of tasks. I would like to know how to use the ProjectID parameter in the task list to link to the Project list and grab the ProjectName parameter so that I can display the Project Name in the table. Currently I can not get it to work. All help is appreciated, Gale

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  • List and Read Text Files

    This sample takes files from a folder (in this situation, text files), and lists them in a listbox. Then, the user can click on a particular file, and display the text from the selected text file, in the textbox to the right of the listbox.

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  • DataTable to Generic List Conversion

    using System;using System.Collections.Generic;using System.Linq;using System.Data;namespace ConsoleApplication1{ class Program { static void Main(string[] args) { DataTable table = new DataTable { Columns = { {"Number", typeof(int)}, {"Name", typeof(string)} } }; //Just adding few test rows to datatable. for (int i = 1; i <= 5; i++) { table.Rows.Add(i, "Name" + i); } var returnList = from row in table.AsEnumerable() select new MyObject { Number = row.Field<int>("Number"), Name = row.Field<String>("Name") }; //Displaying converted collection foreach (MyObject item in returnList) { Console.WriteLine("{0}\t{1}", item.Number, item.Name); } } } class MyObject { public int Number { get; set; } public String Name { get; set; } }} span.fullpost {display:none;}

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  • Silverlight debugging, no list element view

    - by Snake
    When I'm debugging my Silverlight Appliction and I'm using a list internally I cannot hover over the list and see the items inside the list. I just see the RAW view of the list. If I want to see the items I have to write my own code which is tedious. Is this something normal to Silverlight? I DO have the correct list view when debugging in normal Console/WPF/... applications. Example: Silverlight: (link: click) See how there is no 'list view in the first example? And there in this one: And for non Silverlight: (link: click)

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  • how to get sapi to say 1 word from a list of words

    - by mvaughn
    I am writing a program for a spelling test in vb 2010. I have 20 input textboxes for the user to spell the words as sapi says them. My question is ! How do I get sapi to say a word from a multiline textbox then pause and give the focus to the 1st textbox so the user can type it and give them 30 sec then sapi will say the next word then give focus to the 2nd textbox so user can type and give them 30 secs to type the word. Then sapi will say 3rd word the user will get 30 secs to type the word all the way to 20 words then the test will be done. I have 1 multiline textbox that holds 20 words

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  • How to populate a form list with buttons using javascript

    - by StealingMana
    I made a script that, when you press one button(accessories) the selection(mylist) populates with one array(accessoryData), and when you hit the other button(weapons) the other array(weaponData) populates the selection. However, in the current state of the code the second button press is not re-populating the selection. What is wrong here? Also if there is a more efficient way to do this, that might be helpful. Full code function runList(form, test) { var html = ""; var x; dataType(test); while (x < dataType.length) { html += "<option>" + dataType[x]; x++; } document.getElementById("mylist").innerHTML = html; }

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  • C#, Generic Lists and Inheritance

    - by Andy
    I have a class called Foo that defines a list of objects of type A: class Foo { List<A> Items = new List<A>(); } I have a class called Bar that can save and load lists of objects of type B: class Bar { void Save(List<B> ComplexItems); List<B> Load(); } B is a child of A. Foo, Bar, A and B are in a library and the user can create children of any of the classes. What I would like to do is something like the following: Foo MyFoo = new Foo(); Bar MyBar = new Bar(); MyFoo.Items = MyBar.Load(); MyBar.Save(MyFoo.Items); Obviously this won't work. Is there a clever way to do this that avoids creating intermediate lists? thanks, Andy

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  • How to manually list set of urls for search engines to index

    - by MarutiB
    So I have created a video website which has thousands of videos and thousands of videos get added to it on a daily basis. Here is my problem :- I have created a website which basically loads the skeleton in html and puts all the content through javascript and Ajax. The problem is search engines aren't going anywhere except for the home page. Is there a way say in robots.txt where i give a link to a single html which has links to all these videos ? I agree my site is not accessible for a non-javascript user but stats show that this ratio is very low ( 0.2 % ). Is there a way I can still keep the complete AJAX website and still get each individual videos listed on google ?

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  • Removing items from a nested list Python

    - by johntfoster
    I'm trying to remove items from a nested list in Python. I have a nested list as follows: families = [[0, 1, 2],[0, 1, 2, 3],[0, 1, 2, 3, 4],[1, 2, 3, 4, 5],[2, 3, 4, 5, 6]] I want to remove the entries in each sublist that coorespond to the indexed position of the sublist in the master list. So, for example, I need to remove 0 from the first sublist, 1 from second sublist, etc. I am trying to use a list comrehension do do this. This is what I have tried: familiesNew = [ [ families[i][j] for j in families[i] if i !=j ] for i in range(len(families)) ] This works for range(len(families)) up to 3, however beyond that I get IndexError: list index out of range. I'm not sure why. Can somebody give me an idea of how to do this. Preferably a one-liner (list comprehension). Thanks.

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  • List of Asus U46 laptop troubles with Ubuntu 12.04

    - by Cybertib
    I've bought my ASUS U46 last february. I would like to make it work better with Ubuntu 12.04. Note taht I was forced to install Ubuntu 12.04 (before its publication) by ethernet. After a successfull install, several problem remain unfixed such as : USB 3 just does not work correctly. Can be fixed, but I didn't succeed yet. Nvidia Optimus (means that you can use Intel Chipset or the Nvidia GeForce) is possible to use thanks to BumbleBee project. It seems to work, though. But Nvidia tools still say they don't see any Nvidia driver installed. Battery duration can be optimised by using Laptop-tools. Any standby state lead to a X server crash. A good CTRL+ALT+F1 login and "shutdown -r" avoids a brutal power off. And since few weeks, I have some bug reports right after boot about "unattended-upgrade", and dpkg troubles after any apt-get install or update (Linux kernel doesn't compile anymore), ... Are there any ways to fix those troubles ? I would need a bit of assistance, in fact. Thank you for you help, Sincerly yours, Thibault

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  • Extract elements from list based on object property type

    - by Dustin Digmann
    Often, I have a list of objects. Each object has properties. I want to extract a subset of the list where a specific property has a predefined value. Example: I have a list of User objects. A User has a homeTown. I want to extract all users from my list with "Springfield" as their homeTown. I normally see this accomplished as follows: List users = getTheUsers(); List returnList = new ArrayList(); for (User user: users) { if ("springfield".equalsIgnoreCase(user.getHomeTown()) returnList.add(user); } I am not particularly satisfied with this solution. Yes, it works, but it seems so slow. There must be a non-linear solution. Suggestions?

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  • Perl, get all hash values

    - by Mike
    Let's say in Perl I have a list of hash references, and each is required to contain a certain field, let's say foo. I want to create a list that contains all the mappings of foo. If there is a hash that does not contain foo the process should fail. @hash_list = ( {foo=>1}, {foo=>2} ); my @list = (); foreach my $item (@hash_list) { push(@list,$item->{foo}); } #list should be (1,2); Is there a more concise way of doing this in Perl?

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  • A generic list of generics

    - by SnOrfus
    I'm trying to store a list of generic objects in a generic list, but I'm having difficulty declaring it. My object looks like: public class Field<T> { public string Name { get; set; } public string Description { get; set; } public T Value { get; set; } /* ... */ } I'd like to create a list of these. My problem is that each object in the list can have a separate type, so that the populated list could contain something like this: { Field<DateTime>, Field<int>, Field<double>, Field<DateTime> } So how do I declare that? List<Field<?>> (I'd like to stay as typesafe as possible, so I don't want to use an ArrayList).

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  • Removing duplicate solutions

    - by Enoon
    My code merges two lists of lists, item by item, in the following way: mergeL([[a,b],[c,d]], [[1,2],[3,4]], Result). Result = [[a,b,1,2],[c,d,3,4]] And this is the code i use: mergeL([],[],[]). mergeL(List, [], List). mergeL([], List, List). mergeL([X|Rest],[Y|Rest2], [XY|Res2]) :- mergeL(Rest, Rest2, Res2), append(X,Y,XY). This seems to work but if i call it with two lists of the same size i get three repeated results. Example (both list contain only one element): ?- mergeL([[a,b]],[[1,2,3]],Q). Q = [[a, b, 1, 2, 3]] ; Q = [[a, b, 1, 2, 3]] ; Q = [[a, b, 1, 2, 3]]. Is there a clean way to make this output only one solution?

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  • How to Get on Google's Top 10 List

    A question I often asked by new clients is why some websites rank higher on Google than others? This question can be difficult to answer because of the number of variables involved and the fact that Google's search algorithms are closely guarded secret. However, there are a number of standards which affect every website regardless of its topic, purpose, or age.

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  • Samba login before requesting list of shares?

    - by user69359
    I'm relatively inexperienced at this and am starting to get a little frustrated: I have a Ubuntu Server with several user accounts. The Samba file server hosts a number of public shares + the home directories of each user as a private share. When connecting to the server using my OSX machine, I am prompted to enter my login data, and get a overview of all the public shares + my accounts home directory share. Exactly the way I want it. How ever, when I connect to the server from a Ubuntu machine, I am never prompted to enter any login data, and can only see the public folders. If a user wants to connect to their home directory on the server, they have to go through "connect to server" and mount their specific private share. Is there anyway to configure Samba or the Ubuntu client in a way that will make the user experience more similar to how it is on my OSX box? Thank you for your time!

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