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  • How to use git to download a particular tag?

    - by Jack BeNimble
    I'm trying to figure out how do download a particular tag of a git repository - it's one version behind the current version. I saw there was a tag for the previous version on the git web page, with object name of something long hex number. But the version name is "Tagged release 1.1.5" according the site. I tried a command like this (with names changed): git clone http://git.abc.net/git/abc.git my_abc And I did get something - a directory, a bunch of subdirectories, etc. If it's the whole repository, how do I get at the version I'm seeking? If not, how do I download that particular version?

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  • Is putting the javascript before the closing body tag okay on an asp.net website?

    - by Jason Weber
    I pretty much stated what I have to ask. But is taking all of your external .js files and putting them before the closing body tag on your master pages okay on an asp.net website? I'm just going off of what yslow and google speed have been showing. I can't combine these javascripts, so I'm trying to load them "after page load", but doing so makes them useless; some of my jquery things don't work. I moved my .js files above the opening body tag, and they work. What am I doing wrong? And what could I do to load my .js files after page load? Thanks for any advice anybody can offer!

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  • javascript/html/php: Is it possible to insert a value into a form with Ajax?

    - by user1260310
    I have a form where users enter some text manually. Then I'd like to let the users choose a tag from a database through AJAX, not unlike how tag suggestions appear in the SO question form. While the div where the ajax call places the tag is inside the form, it does not seem to register and the tag is not picked up by the form. Am I missing something in my code, is this impossible or, if impossible there a better way to do this? Thanks for any suggestions. Here is code: html <form method="post" action="enterdata.php"> <input type="text" name="text">Enter text here. <div id="inserttags"></div><a href="javascript:void(0);" onclick="getTags()";>Get tags</a> <form type="button" name="submit" value="Enter Text and Tag"> </form> javascript getTags() { various Ajax goes here, then //following line inserts value into div of html document.getElementById("inserttags").innerHTML=xmlhttp.responseText; // a bit more ajax, then following pulls tag from db xmlhttp.open("GET","findtags.php",true); xmlhttp.send(); } //end function php //gettags.php //first pull tag from db. Then: echo 'input type="text" name="tag" value= "html">Enter tag'; //above output gets inserted in div and is visible on page. Though the above output is visible on page, the form does not seem to pick it up when you click "Enter Text and Tag" to submit the form.

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  • UIView viewWithTag 0 problem

    - by leon
    Hi, On view in IB I have numerous items (including view itself). ONLY one item has tag 0, yet following line works for ANY UITextBox other then the one with tag 0. Note that only ONE UITextBox has tag 0, why: (UITextField *) [self.view viewWithTag:0]).text = @"foo"; Interesting that when triggered event received for the element with tag 0, I can get value of Tag 0 with no problem. Is there a limitation to look for tag 0 elements?

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  • Can I insert a style tag and contents from a view with CakePHP?

    - by Richard
    From what I can see, CakePHP makes it easy to link to a CSS file in a view with the following: echo $html->css('my-css-filename',null,array(),FALSE); But what if I don't want to exclusively use hardcoded files? How can I get it to create a style tag with some dynamically generated rules in e.g. <style type="text/css" media="all">p {font-size:1.5em}</style> I am trying to do this in a view file, I'd like the CSS to be placed in the head tag, and I'm using CakePHP 1.2.7

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  • How to encode video to use HTML 5 video tag? [closed]

    - by exquisitor
    I'm trying to use <video> tag feature. I've encoded my file with ffmpeg: ffmpeg -i 1.vob -f ogg -vcodec libtheora -b 800k -g 300 -acodec libvorbis -ab 128k out.ogv I've placed this text in index.html: <video src="out.ogv" controls></video> I've loaded this files to nginx document root and opened index.html in Firefox 3.5. I see the first frame, see controls, but can't play video. This video plays good even from my server. How should I encode video to view it in browser? UPD: If I start playing video from the middle, everything works fine.

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  • django: how to use many-to-many relationships in values()?

    - by john
    i need to group results by a field that requires a few joins from the original model: // response_filter_args is created dynamically responses = Response.objects.filter(**response_filter_args) \ .values('customer__tags__tag') \ # django doesn't like this .annotate(average_score=Avg('rating__score')) Response - customer - tags (many-to-many field pointing to Tag) - tag (the tag as a string) Models are: class Response(models.Model): customer = models.ForeignKey(Customer) ... class Customer(models.Model): tags = models.ManyToManyField(Tag) ... class Tag(models.Model): tag = models.CharField(max_length=255) ... i'm trying to calculate average ratings. to make it work i need to tell django to group by 'tag', but it refuses to. it gives an error: Invalid field name: 'customer__tags__tag' anyone know how i can get it to group by tag? i've tried all the combinations of underscores in customer_tags_tag that i can think of, but nothing works.

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  • How to obtain a random sub-datatable from another data table

    - by developerit
    Introduction In this article, I’ll show how to get a random subset of data from a DataTable. This is useful when you already have queries that are filtered correctly but returns all the rows. Analysis I came across this situation when I wanted to display a random tag cloud. I already had the query to get the keywords ordered by number of clicks and I wanted to created a tag cloud. Tags that are the most popular should have more chance to get picked and should be displayed larger than less popular ones. Implementation In this code snippet, there is everything you need. ' Min size, in pixel for the tag Private Const MIN_FONT_SIZE As Integer = 9 ' Max size, in pixel for the tag Private Const MAX_FONT_SIZE As Integer = 14 ' Basic function that retreives Tags from a DataBase Public Shared Function GetTags() As MediasTagsDataTable ' Simple call to the TableAdapter, to get the Tags ordered by number of clicks Dim dt As MediasTagsDataTable = taMediasTags.GetDataValide ' If the query returned no result, return an empty DataTable If dt Is Nothing OrElse dt.Rows.Count < 1 Then Return New MediasTagsDataTable End If ' Set the font-size of the group of data ' We are dividing our results into sub set, according to their number of clicks ' Example: 10 results -> [0,2] will get font size 9, [3,5] will get font size 10, [6,8] wil get 11, ... ' This is the number of elements in one group Dim groupLenth As Integer = CType(Math.Floor(dt.Rows.Count / (MAX_FONT_SIZE - MIN_FONT_SIZE)), Integer) ' Counter of elements in the same group Dim counter As Integer = 0 ' Counter of groups Dim groupCounter As Integer = 0 ' Loop througt the list For Each row As MediasTagsRow In dt ' Set the font-size in a custom column row.c_FontSize = MIN_FONT_SIZE + groupCounter ' Increment the counter counter += 1 ' If the group counter is less than the counter If groupLenth <= counter Then ' Start a new group counter = 0 groupCounter += 1 End If Next ' Return the new DataTable with font-size Return dt End Function ' Function that generate the random sub set Public Shared Function GetRandomSampleTags(ByVal KeyCount As Integer) As MediasTagsDataTable ' Get the data Dim dt As MediasTagsDataTable = GetTags() ' Create a new DataTable that will contains the random set Dim rep As MediasTagsDataTable = New MediasTagsDataTable ' Count the number of row in the new DataTable Dim count As Integer = 0 ' Random number generator Dim rand As New Random() While count < KeyCount Randomize() ' Pick a random row Dim r As Integer = rand.Next(0, dt.Rows.Count - 1) Dim tmpRow As MediasTagsRow = dt(r) ' Import it into the new DataTable rep.ImportRow(tmpRow) ' Remove it from the old one, to be sure not to pick it again dt.Rows.RemoveAt(r) ' Increment the counter count += 1 End While ' Return the new sub set Return rep End Function Pro’s This method is good because it doesn’t require much work to get it work fast. It is a good concept when you are working with small tables, let says less than 100 records. Con’s If you have more than 100 records, out of memory exception may occur since we are coping and duplicating rows. I would consider using a stored procedure instead.

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  • Maintaining shared service in ASP.NET MVC Application

    - by kazimanzurrashid
    Depending on the application sometimes we have to maintain some shared service throughout our application. Let’s say you are developing a multi-blog supported blog engine where both the controller and view must know the currently visiting blog, it’s setting , user information and url generation service. In this post, I will show you how you can handle this kind of case in most convenient way. First, let see the most basic way, we can create our PostController in the following way: public class PostController : Controller { public PostController(dependencies...) { } public ActionResult Index(string blogName, int? page) { BlogInfo blog = blogSerivce.FindByName(blogName); if (blog == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindPublished(blog.Id, PagingCalculator.StartIndex(page, blog.PostPerPage), blog.PostPerPage); int count = postService.GetPublishedCount(blog.Id); UserInfo user = null; if (HttpContext.User.Identity.IsAuthenticated) { user = userService.FindByName(HttpContext.User.Identity.Name); } return View(new IndexViewModel(urlResolver, user, blog, posts, count, page)); } public ActionResult Archive(string blogName, int? page, ArchiveDate archiveDate) { BlogInfo blog = blogSerivce.FindByName(blogName); if (blog == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindArchived(blog.Id, archiveDate, PagingCalculator.StartIndex(page, blog.PostPerPage), blog.PostPerPage); int count = postService.GetArchivedCount(blog.Id, archiveDate); UserInfo user = null; if (HttpContext.User.Identity.IsAuthenticated) { user = userService.FindByName(HttpContext.User.Identity.Name); } return View(new ArchiveViewModel(urlResolver, user, blog, posts, count, page, achiveDate)); } public ActionResult Tag(string blogName, string tagSlug, int? page) { BlogInfo blog = blogSerivce.FindByName(blogName); if (blog == null) { return new NotFoundResult(); } TagInfo tag = tagService.FindBySlug(blog.Id, tagSlug); if (tag == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindPublishedByTag(blog.Id, tag.Id, PagingCalculator.StartIndex(page, blog.PostPerPage), blog.PostPerPage); int count = postService.GetPublishedCountByTag(tag.Id); UserInfo user = null; if (HttpContext.User.Identity.IsAuthenticated) { user = userService.FindByName(HttpContext.User.Identity.Name); } return View(new TagViewModel(urlResolver, user, blog, posts, count, page, tag)); } } As you can see the above code heavily depends upon the current blog and the blog retrieval code is duplicated in all of the action methods, once the blog is retrieved the same blog is passed in the view model. Other than the blog the view also needs the current user and url resolver to render it properly. One way to remove the duplicate blog retrieval code is to create a custom model binder which converts the blog from a blog name and use the blog a parameter in the action methods instead of the string blog name, but it only helps the first half in the above scenario, the action methods still have to pass the blog, user and url resolver etc in the view model. Now lets try to improve the the above code, first lets create a new class which would contain the shared services, lets name it as BlogContext: public class BlogContext { public BlogInfo Blog { get; set; } public UserInfo User { get; set; } public IUrlResolver UrlResolver { get; set; } } Next, we will create an interface, IContextAwareService: public interface IContextAwareService { BlogContext Context { get; set; } } The idea is, whoever needs these shared services needs to implement this interface, in our case both the controller and the view model, now we will create an action filter which will be responsible for populating the context: public class PopulateBlogContextAttribute : FilterAttribute, IActionFilter { private static string blogNameRouteParameter = "blogName"; private readonly IBlogService blogService; private readonly IUserService userService; private readonly BlogContext context; public PopulateBlogContextAttribute(IBlogService blogService, IUserService userService, IUrlResolver urlResolver) { Invariant.IsNotNull(blogService, "blogService"); Invariant.IsNotNull(userService, "userService"); Invariant.IsNotNull(urlResolver, "urlResolver"); this.blogService = blogService; this.userService = userService; context = new BlogContext { UrlResolver = urlResolver }; } public static string BlogNameRouteParameter { [DebuggerStepThrough] get { return blogNameRouteParameter; } [DebuggerStepThrough] set { blogNameRouteParameter = value; } } public void OnActionExecuting(ActionExecutingContext filterContext) { string blogName = (string) filterContext.Controller.ValueProvider.GetValue(BlogNameRouteParameter).ConvertTo(typeof(string), Culture.Current); if (!string.IsNullOrWhiteSpace(blogName)) { context.Blog = blogService.FindByName(blogName); } if (context.Blog == null) { filterContext.Result = new NotFoundResult(); return; } if (filterContext.HttpContext.User.Identity.IsAuthenticated) { context.User = userService.FindByName(filterContext.HttpContext.User.Identity.Name); } IContextAwareService controller = filterContext.Controller as IContextAwareService; if (controller != null) { controller.Context = context; } } public void OnActionExecuted(ActionExecutedContext filterContext) { Invariant.IsNotNull(filterContext, "filterContext"); if ((filterContext.Exception == null) || filterContext.ExceptionHandled) { IContextAwareService model = filterContext.Controller.ViewData.Model as IContextAwareService; if (model != null) { model.Context = context; } } } } As you can see we are populating the context in the OnActionExecuting, which executes just before the controllers action methods executes, so by the time our action methods executes the context is already populated, next we are are assigning the same context in the view model in OnActionExecuted method which executes just after we set the  model and return the view in our action methods. Now, lets change the view models so that it implements this interface: public class IndexViewModel : IContextAwareService { // More Codes } public class ArchiveViewModel : IContextAwareService { // More Codes } public class TagViewModel : IContextAwareService { // More Codes } and the controller: public class PostController : Controller, IContextAwareService { public PostController(dependencies...) { } public BlogContext Context { get; set; } public ActionResult Index(int? page) { IEnumerable<PostInfo> posts = postService.FindPublished(Context.Blog.Id, PagingCalculator.StartIndex(page, Context.Blog.PostPerPage), Context.Blog.PostPerPage); int count = postService.GetPublishedCount(Context.Blog.Id); return View(new IndexViewModel(posts, count, page)); } public ActionResult Archive(int? page, ArchiveDate archiveDate) { IEnumerable<PostInfo> posts = postService.FindArchived(Context.Blog.Id, archiveDate, PagingCalculator.StartIndex(page, Context.Blog.PostPerPage), Context.Blog.PostPerPage); int count = postService.GetArchivedCount(Context.Blog.Id, archiveDate); return View(new ArchiveViewModel(posts, count, page, achiveDate)); } public ActionResult Tag(string blogName, string tagSlug, int? page) { TagInfo tag = tagService.FindBySlug(Context.Blog.Id, tagSlug); if (tag == null) { return new NotFoundResult(); } IEnumerable<PostInfo> posts = postService.FindPublishedByTag(Context.Blog.Id, tag.Id, PagingCalculator.StartIndex(page, Context.Blog.PostPerPage), Context.Blog.PostPerPage); int count = postService.GetPublishedCountByTag(tag.Id); return View(new TagViewModel(posts, count, page, tag)); } } Now, the last thing where we have to glue everything, I will be using the AspNetMvcExtensibility to register the action filter (as there is no better way to inject the dependencies in action filters). public class RegisterFilters : RegisterFiltersBase { private static readonly Type controllerType = typeof(Controller); private static readonly Type contextAwareType = typeof(IContextAwareService); protected override void Register(IFilterRegistry registry) { TypeCatalog controllers = new TypeCatalogBuilder() .Add(GetType().Assembly) .Include(type => controllerType.IsAssignableFrom(type) && contextAwareType.IsAssignableFrom(type)); registry.Register<PopulateBlogContextAttribute>(controllers); } } Thoughts and Comments?

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  • Using the HTML5 &lt;input type=&quot;file&quot; multiple=&quot;multiple&quot;&gt; Tag in ASP.NET

    - by Rick Strahl
    Per HTML5 spec the <input type="file" /> tag allows for multiple files to be picked from a single File upload button. This is actually a very subtle change that's very useful as it makes it much easier to send multiple files to the server without using complex uploader controls. Please understand though, that even though you can send multiple files using the <input type="file" /> tag, the process of how those files are sent hasn't really changed - there's still no progress information or other hooks that allow you to automatically make for a nicer upload experience without additional libraries or code. For that you will still need some sort of library (I'll post an example in my next blog post using plUpload). All the new features allow for is to make it easier to select multiple images from disk in one operation. Where you might have required many file upload controls before to upload several files, one File control can potentially do the job. How it works To create a file input box that allows with multiple file support you can simply do:<form method="post" enctype="multipart/form-data"> <label>Upload Images:</label> <input type="file" multiple="multiple" name="File1" id="File1" accept="image/*" /> <hr /> <input type="submit" id="btnUpload" value="Upload Images" /> </form> Now when the file open dialog pops up - depending on the browser and whether the browser supports it - you can pick multiple files. Here I'm using Firefox using the thumbnail preview I can easily pick images to upload on a form: Note that I can select multiple images in the dialog all of which get stored in the file textbox. The UI for this can be different in some browsers. For example Chrome displays 3 files selected as text next to the Browse… button when I choose three rather than showing any files in the textbox. Most other browsers display the standard file input box and display the multiple filenames as a comma delimited list in the textbox. Note that you can also specify the accept attribute in the <input> tag, which specifies a mime-type to specify what type of content to allow.Here I'm only allowing images (image/*) and the browser complies by just showing me image files to display. Likewise I could use text/* for all text formats registered on the machine or text/xml to only show XML files (which would include xml,xst,xsd etc.). Capturing Files on the Server with ASP.NET When you upload files to an ASP.NET server there are a couple of things to be aware of. When multiple files are uploaded from a single file control, they are assigned the same name. In other words if I select 3 files to upload on the File1 control shown above I get three file form variables named File1. This means I can't easily retrieve files by their name:HttpPostedFileBase file = Request.Files["File1"]; because there will be multiple files for a given name. The above only selects the first file. Instead you can only reliably retrieve files by their index. Below is an example I use in app to capture a number of images uploaded and store them into a database using a business object and EF 4.2.for (int i = 0; i < Request.Files.Count; i++) { HttpPostedFileBase file = Request.Files[i]; if (file.ContentLength == 0) continue; if (file.ContentLength > App.Configuration.MaxImageUploadSize) { ErrorDisplay.ShowError("File " + file.FileName + " is too large. Max upload size is: " + App.Configuration.MaxImageUploadSize); return View("UploadClassic",model); } var image = new ClassifiedsBusiness.Image(); var ms = new MemoryStream(16498); file.InputStream.CopyTo(ms); image.Entered = DateTime.Now; image.EntryId = model.Entry.Id; image.ContentType = "image/jpeg"; image.ImageData = ms.ToArray(); ms.Seek(0, SeekOrigin.Begin); // resize image if necessary and turn into jpeg Bitmap bmp = Imaging.ResizeImage(ms.ToArray(), App.Configuration.MaxImageWidth, App.Configuration.MaxImageHeight); ms.Close(); ms = new MemoryStream(); bmp.Save(ms,ImageFormat.Jpeg); image.ImageData = ms.ToArray(); bmp.Dispose(); ms.Close(); model.Entry.Images.Add(image); } This works great and also allows you to capture input from multiple input controls if you are dealing with browsers that don't support multiple file selections in the file upload control. The important thing here is that I iterate over the files by index, rather than using a foreach loop over the Request.Files collection. The files collection returns key name strings, rather than the actual files (who thought that was good idea at Microsoft?), and so that isn't going to work since you end up getting multiple keys with the same name. Instead a plain for loop has to be used to loop over all files. Another Option in ASP.NET MVC If you're using ASP.NET MVC you can use the code above as well, but you have yet another option to capture multiple uploaded files by using a parameter for your post action method.public ActionResult Save(HttpPostedFileBase[] file1) { foreach (var file in file1) { if (file.ContentLength < 0) continue; // do something with the file }} Note that in order for this to work you have to specify each posted file variable individually in the parameter list. This works great if you have a single file upload to deal with. You can also pass this in addition to your main model to separate out a ViewModel and a set of uploaded files:public ActionResult Edit(EntryViewModel model,HttpPostedFileBase[] uploadedFile) You can also make the uploaded files part of the ViewModel itself - just make sure you use the appropriate naming for the variable name in the HTML document (since there's Html.FileFor() extension). Browser Support You knew this was coming, right? The feature is really nice, but unfortunately not supported universally yet. Once again Internet Explorer is the problem: No shipping version of Internet Explorer supports multiple file uploads. IE10 supposedly will, but even IE9 does not. All other major browsers - Chrome, Firefox, Safari and Opera - support multi-file uploads in their latest versions. So how can you handle this? If you need to provide multiple file uploads you can simply add multiple file selection boxes and let people either select multiple files with a single upload file box or use multiples. Alternately you can do some browser detection and if IE is used simply show the extra file upload boxes. It's not ideal, but either one of these approaches makes life easier for folks that use a decent browser and leaves you with a functional interface for those that don't. Here's a UI I recently built as an alternate uploader with multiple file upload buttons: I say this is my 'alternate' uploader - for my primary uploader I continue to use an add-in solution. Specifically I use plUpload and I'll discuss how that's implemented in my next post. Although I think that plUpload (and many of the other packaged JavaScript upload solutions) are a better choice especially for large uploads, for simple one file uploads input boxes work well enough. The advantage of this solution is that it's very easy to handle on the server side. Any of the JavaScript controls require special handling for uploads which I'll also discuss in my next post.© Rick Strahl, West Wind Technologies, 2005-2012Posted in HTML5  ASP.NET  MVC   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • Load an html table from a mysql database when an onChange event is triggered from a select tag

    - by Crew Peace
    So, here's the deal. I have an html table that I want to populate. Specificaly the first row is the one that is filled with elements from a mysql database. To be exact, the table is a questionnaire about mobile phones. The first row is the header where the cellphone names are loaded from the database. There is also a select tag that has company names as options in it. I need to trigger an onChange event on the select tag to reload the page and refill the first row with the new names of mobiles from the company that is currently selected in the dropdown list. This is what my select almost looks like: <select name="select" class="companies" onChange="reloadPageWithNewElements()"> <?php $sql = "SELECT cname FROM companies;"; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<option value=\"".$row['cname']."\">".$row['cname']."</option>\n "; } ?> </select> So... is there a way to refresh this page with onChange and pass the selected value to the same page again and assign it in a new php variable so i can do the query i need to fill my table? <?php //$mobileCompanies = $_GET["selectedValue"]; $sql = "SELECT mname FROM ".$mobileCompanies.";"; $rs = mysql_query($sql); while ($row = mysql_fetch_array($rs)) { echo "<td><div class=\"q1\">".$row['mname']."</div></td>"; } ?> something like this. (The reloadPageWithNewElements() and selectedValue are just an idea for now)

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  • Chrome: Dynamically created <style> tag does not have content?

    - by Shizhidi
    Hello. I encountered a weird problem when trying to write a cross-browser script. Basically my header looks like this <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> </head> Then in the body tag: <p id="hey">Hey</p> <input type="button" value="attachStyle" name="attachStyle" onclick="attachStyle();"></input> <script> function attachStyle() { var strVar=""; strVar += "<style type='text\/css'>#hey {border:5px solid red;}<\/script>"; $("head").append(strVar); } </script> The button works in Firefox, but not in Chrome. When I looked at the html DOM elements in the developer tool, the style tag was inserted but without content, like this: <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script> <style type='text/css'></script> </head> I'm curious as to what causes this? And how to create CSS style in a way that is cross-browser? Thanks!

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  • jQuery enclose text before and after anchor tag in separate spans.

    - by Devashish Bahri
    hey dere, first of all, thnx a ton for taking out time to see my post. i have a big problem with jQuery. i have this code: <p>Hi. I am your friend. you are my friend.<br> we <a href="both.html">both</a> are friends.</p> My aim is to enclose the text before the anchor tag as well as after the anchor tag into separate spans. Thus, i want something like this in the DOM: <p><span>Hi. I am your friend. you are my friend.<br> we </span><a href="both.html">both</a><span> are friends.</span></p> Can anybody please help me and tell me how to do it in jQuery. PLease... its very important..!! Thnx in advance...

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  • jQuery: How to innerHTML an HTML tag without id?

    - by marknt15
    Hi, For example I have this HTML code: <div id="canvas"> <div id="root"> <div id="content"> <span> <title>My SVG Example Title</title> <ellipse id="svg_1" /> </span> </div> </div> </div> How can I innerHTML the <span> tag without changing the <title> tag using jQuery? So my expected output would be something like this: <div id="canvas"> <div id="root"> <div id="content"> <span> <title>My SVG Example Title</title> <input type="text" value="this is the innerHTML I must insert but how?" /> </span> </div> </div> </div>

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  • Should a "script" tag be allowed to remove itself?

    - by Nischal
    We've been having a discussion at our workplace on this with some for and some against the behavior. Wanted to hear views from you guys : <html> <body> <div> Test! <script> document.body.removeChild(document.getElementsByTagName('div')[0]); </script> </div> </body> </html> Should the above script work and do what it's supposed to do? First, let's see what's happening here : I have a javascript that's inside the <div> element. This javascript will delete the child node within body which happens to hold the div inside which the script itself exists. Now, the above script works fine in Firefox, Opera and IE8. But IE6 and IE7 give an alert saying they cannot open the page. Let's not debate on how IE should have handled this (they've accepted it as a bug and hence fixed it in IE8). The point here is since the 'SCRIPT' tag itself is a part of DOM, should it be allowed to do something like this? Should it even exist after such an operation? Edit: Firefox, Opera, IE9 etc. do not remove the 'script' tag if I run the above code. But, document.getElementsByTagName('script').length returns 0! To understand what I mean, add alert(document.getElementsByTagName('script').length); before and after document.body.removeChild(document.getElementsByTagName('div')[0]); in the code above.

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  • Parse M3U file locations to fully qualified paths

    - by Guy
    I would like to parse the file location information in an M3U playlist into fully qualified paths. The possible formats in M3U files seem to be: c:\mydir\songs\tune.mp3 \songs\tune.mp3 ..\songs\tune.mp3 For the first example, just leave it alone. For the second add the directory that the playlist resides in so it would become c:\playlists\songs\tune.mp3 and the same for the third case so it would also become: c:\playlists\songs\tune.mp3. I'm using vb under VS2008 and I can't find a way to recognise each of the potential location formats in the M3U file. System.IO.Path offers no solution that I can find. I've searched extensively for terms like "convert relative path to absolute" but no luck. Any advice appreciated. Thanks.

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  • Synchronizing Java Visualizer Audio and Visual

    - by Matt
    I've run into a problem creating a visualizer for .mp3 files in Java. My goal is to create a visualization that runs in time with the .mp3 file being played. I can currently visualize an .mp3 OR play it, but not both at the same time. I am using libraries which may make this trickier than necessary. I currently: Read in the .mp3 as a FileInputStream. a) Convert the FileInputStream into a Bitstream and run the Visualizer OR b) Pass the FileInputStream to a library Play method where it converts it into a Bitstream, decodes it, and plays it. I am using the JLayer library to play and decode the .mp3. My question is: how do I synchronize the two actions so that I can run both at the same time AND they line up (so my visualizations correspond to the changing frequencies). This implies that they finish at the same time as well.

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  • In terminal, merging multiple folders into one.

    - by Josh Pinter
    I have a backup directory created by WDBackup (western digital external HD backup util) that contains a directory for each day that it backed up and the incremental contents of just what was backed up. So the hierarchy looks like this: 20100101 My Documents Letter1.doc My Music Best Songs Every First Songs.mp3 My song.mp3 # modified 20100101 20100102 My Documents Important Docs Taxes.doc My Music My Song.mp3 # modified 20100102 ...etc... Only what has changed is backed up and the first backup that was ever made contains all the files selected for backup. What I'm trying to do now is incrementally copy, while keeping the folder structure, from oldest to newest, each of these dated folders into a 'merged' folder so that it overrides the older content and keeps the new stuff. As an example, if just using these two example folders, the final merged folder would look like this: Merged My Documents Important Docs Taxes.doc Letter1.doc My Music Best Songs Every First Songs.mp3 My Song.mp3 # modified 20100102 Hope that makes sense. Thanks, Josh

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  • Finding files with bash and copy to another location and reducing depth of folders

    - by Kevin F
    I'm trying to recover a mates hard drive, there is no structure what so ever so music and images are everywhere but in named folders sometimes 5 folders deep, I've managed to write a one-liner that finds the files and copies them to a mounted drive but it preserves the file structure completely. What I'm after is a bit of code that searches the drive and copies to another location and copies just the parent folder with the mp3/jpg files within and not the complete path. The other issue I have is the music is /folder/folder/folder/Artist/1.mp3..2.mp3..10.mp3 etc etc so I have to preserve the folder 'Artist' to give him any hope of finding his tracks again. What I have working currently: find /media/HP/ -name *.mp3 -fprintf /media/HP/MUSIC/Script.sh 'mkdir -p "/media/HP/MUSIC/%h" \n cp "%h/%f" "/media/HP/MUSIC/%h/"\n' I then run the script.sh and it does all the copying. Many Thanks

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  • Paperclip generating wrong URLs in Heroku

    - by Tony
    Paperclip is generating wrong URLs in Heroku. I have an Audio model which has a mp3 field as follows: class Audio < ActiveRecord::Base has_attached_file :mp3, :storage => :s3, :s3_credentials => S3_CREDENTIALS, :bucket => S3_CREDENTIALS[:bucket], :path => ":rails_root/public/system/:attachment/:id/:style/:filename", :url => "/system/:attachment/:id/:style/:filename" I am calling audio.mp3.url from a controller, and it returns http://s3.amazonaws.com/MyApp/audios/mp3s//original/96a9ae89302fdf8462ee05eb829f2e17578b144e20120908-2-11f61zr.mp3?1347135050 instead of http://s3.amazonaws.com/MyApp/audios/mp3s/000/000/004/original/96a9ae89302fdf8462ee05eb829f2e17578b144e20120908-2-11f61zr.mp3?1347135050 (which works) Why is it missing the '000/000/004' part of the route? The same model is generating the right URL when used in a view. Any help? I am using paperclip 3.2.0 and Rails 3.1.8. Any help?

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  • Android launches system settings instead of my app

    - by jsundin
    Hi, For some reason whenever I (try to) start my app the phone decides to launch system settings instead of my "main activity". And yes, I am referring to the "Android system settings", and not something from my app. This only happens on my phone, and I suppose it probably could be related to the fact that my app had just opened system settings when I decided to re-launch with a new version from Eclipse. It is possible to start the app from within Eclipse, but when I navigate back from the app it returns to the system settings rather than the home screen, as if the settings activity was started first and then my activity. If I then start the app from the phone all I get is system settings yet again. The app is listening to the VIEW-action for a specific URL substring, and when I start the app using a matching URL I get the same result as when I start it from Eclipse, app starts, but when I return I return to settings. I have tried googling for this problem, and all I could find was something about Android saving state when an app gets killed, but without any information on how to reset this state. I have tried uninstalling the app, killing system settings, rebooting the phone, reinstalling, clearing application data.. no luck.. For what it's worth, here's the definition of my main activity from the manifest, <activity android:name=".HomeActivity" android:label="@string/app_name" android:screenOrientation="portrait" android:clearTaskOnLaunch="true" android:launchMode="singleTop"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> <intent-filter> <action android:name="android.intent.action.VIEW"></action> <category android:name="android.intent.category.DEFAULT"></category> <category android:name="android.intent.category.BROWSABLE"></category> <data android:pathPrefix="/isak-web-mobile/smart/" android:scheme="http" android:host="*"></data> </intent-filter> </activity> And here is the logcat-line from when I try to start my app, nothing about any settings anywhere. I/ActivityManager( 1301): Starting activity: Intent { act=android.intent.action.MAIN cat=[android.intent.category.LAUNCHER] flg=0x10200000 cmp=se.opencare.isak/.HomeActivity } When I launch from Eclipse I also get this line (as one would expect), I/ActivityManager( 1301): Start proc se.opencare.isak for activity se.opencare.isak/.HomeActivity: pid=23068 uid=10163 gids={3003, 1007, 1015} If it matters the phone is a HTC Desire Z running 2.2.1. Currently, this is my HomeActivity, public class HomeActivity extends Activity { public static final String TAG = "HomeActivity"; @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { Log.d(TAG, "onActivityResult(" + requestCode + ", " + resultCode + ", " + data + ")"); super.onActivityResult(requestCode, resultCode, data); } @Override protected void onCreate(Bundle savedInstanceState) { Log.d(TAG, "onCreate(" + savedInstanceState + ")"); super.onCreate(savedInstanceState); } @Override protected void onDestroy() { Log.d(TAG, "onDestroy()"); super.onDestroy(); } @Override protected void onPause() { Log.d(TAG, "onPause()"); super.onPause(); } @Override protected void onPostCreate(Bundle savedInstanceState) { Log.d(TAG, "onPostCreate(" + savedInstanceState + ")"); super.onPostCreate(savedInstanceState); } @Override protected void onPostResume() { Log.d(TAG, "onPostResume()"); super.onPostResume(); } @Override protected void onRestart() { Log.d(TAG, "onRestart()"); super.onRestart(); } @Override protected void onRestoreInstanceState(Bundle savedInstanceState) { Log.d(TAG, "onRestoreInstanceState(" + savedInstanceState + ")"); super.onRestoreInstanceState(savedInstanceState); } @Override protected void onResume() { Log.d(TAG, "onResume()"); super.onResume(); } @Override protected void onStart() { Log.d(TAG, "onStart()"); super.onStart(); } @Override protected void onStop() { Log.d(TAG, "onStop()"); super.onStop(); } @Override protected void onUserLeaveHint() { Log.d(TAG, "onUserLeaveHint()"); super.onUserLeaveHint(); } } Nothing (of the above) is written to the log.

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  • Inheriting XML files and modifying values

    - by Veehmot
    This is a question about concept. I have an XML file, let's call it base: <base id="default"> <tags> <tag>tag_one</tag> <tag>tag_two</tag> <tag>tag_three</tag> </tags> <data> <data_a>blue</data_a> <data_b>3</data_b> </data> </base> What I want to do is to be able to extend this XML in another file, modifying individual properties. For example, I want to inherit that file and make a new one with a different data/data_a node: <base id="green" import="default"> <data> <data_a>green</data_a> </data> </base> So far it's pretty simple, it replaces the old data/data_a with the new one. I even can add a new node: <base id="ext" import="default"> <moredata> <data>extended version</data> </moredata> </base> And still it's pretty simple. The problem comes when I want to delete a node or deal with XML Lists (like the tags node). How should I reference a particular index on a list? I was thinking doing something like: <base id="diffList" import="default"> <tags> <tag index="1">this is not anymore tag_two</tag> </tags> </base> And for deleting a node / array index: <base id="deleting" import="default"> <tags> <tag index="2"/> </tags> <data/> </base> <!-- This will result in an XML containing these values: --> <base> <tag>tag_one</tag> <tag>tag_two</tag> </base> But I'm not happy with my solutions. I don't know anything about XSLT or other XML transformation tools, but I think someone must have done this before. The key goal I'm looking for is ease to write the XML by hand (both the base and the "extended"). I'm open to new solutions besides XML, if they are easy to write manually. Thanks for reading.

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  • How can we write the html tidy coding to insert the closing tag ?

    - by Harikrishna
    How can we write html tidy coding only for inserting closing tag in the html file where closing tags are missing ? I am parsing html tabular information using Html Agilitiy Pack. But where the ending tags are missing extracting information with html agility pack are not performed well. And if we write the ending tags manually and then we can extract the information perfectly with html agility pack.So I want to insert the closing tags where they are missing so html agility pack extracts the information perfectly.

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