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  • mysql PDO how to bind LIKE

    - by dmontain
    In this query select wrd from tablename WHERE wrd LIKE '$partial%' I'm trying to bind the variable '$partial%' with PDO. Not sure how this works with the % at the end. Would it be select wrd from tablename WHERE wrd LIKE ':partial%' where :partial is bound to $partial="somet" or would it be select wrd from tablename WHERE wrd LIKE ':partial' where :partial is bound to $partial="somet%" or would it be something entirely different?

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  • MySQL : AVG of AVG impossible ?

    - by Tristan
    Hi, I want to do an average : the problem is for 1 item i'm calculating the AVG of each elements (working) but as soon as i want the GLOBAL average the average of the elements (something and foo) it doesn't work. I need to do that because i want to sort the result by the global average SELECT AVG(AVG(something)+AVG(foo)) /2 as moy ..... ORDER BY moy DESC Thanks,

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  • displaying a group once in php mysql

    - by JPro
    I have some data like this : 1 TC1 PASS 2 TC2 FAIL 3 TC3 INCONC 4 TC1 FAIL 5 TC21 FAIL 6 TC4 PASS 7 TC3 PASS 8 TC2 FAIL 9 TC1 TIMEOUT 10 TC21 FAIL If I try the below code : <?php mysql_connect("localhost", "root", "pop") or die(mysql_error()); mysql_select_db("jpd") or die(mysql_error()); $oustanding_fails = mysql_query("select * from SELECT_PASS ") or die(mysql_error()); $resultSetArray = array(); $platform; while($row1 = mysql_fetch_array( $oustanding_fails )) { if(trim($row1['TESTCASE']) <> trim($platform)) { echo $row1['TESTCASE']."-"; $platform = $row1['TESTCASE']; } echo $row1['RESULT'] ."<br>"; } ?> to get a result like this : TC1 PASS FAIL TIMEOUT TC2 FAIL FAIL TC3 INCONC PASS TC4 PASS AND SO ON. I am unable to get the result I want. Any ideas where exactly I am making mistake? Thanks.

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  • zimbra server server not sync with ldap server

    - by shreedhar.bh
    Please help me out I am intermediate on linux, 1) I do have zimbra mail server on ubuntu with ladap server and external openldap server in internal location 2) last weak we got renewed the SSL certificate on Zimbra server 3) after renewed the SSL certificate with 10 years in Zimber server its not able to sync the ladap details with internal OpenLdap server Please help me to fix this issue In advance thanks Regards Shreedhar.BH

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  • MySQL Need help constructing query: join multiple tables into single row

    - by Jed Daniels
    Hello stackoverflowers, Forgive me if this question has been asked and answered, I've searched and found a few that look similar but I'm too much of a novice with SQL to adapt them to my needs. Also forgive me if I don't use the correct terminology, I know it can be annoying when someone asks a question and they don't even know enough to be able to ask for what they need. I'm helping a friend gather some data, and need to perform a query that results in a single row per record, but instead I get multiple rows. Here is an example of what I'm querying right now (simplified, hopefully not too much): SELECT * FROM `table_one` AS t1 INNER JOIN `table_two` AS t2 ON t1.id = t2.id INNER JOIN `table_three` AS t3 ON t1.id = t3.id WHERE 1 The result is: id text number 5 Subtotal 17 5 Tax 3 5 Total 20 What I need is to create a query that results in something more like this: id text number text number text number 5 subtotal 17 Tax 3 Total 20 Any assistance/guidance would be much appreciated. Thanks! --jed

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  • MySQL function: Rotate old entries to archive table

    - by confiq
    Hi, I'm looking for the function that will take rows older then X days and put it in archive table... Was thinking to make function so it will be easer to execute... something like CREATE TABLE archive_NUMBER_OF_WEEK (...); INSERT INTO archive_NUMBER_OF_WEEK SELECT * FROM content WHERE DATE < X days; DELETE * FROM content WHERE DATE < X days RENAME TABLE content TO content_backup, content_temp TO content; Will post when I finish it :)

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  • Mysql - Help me alter this search query to get desired results

    - by sandeepan-nath
    Following is a dump of the tables and data needed to answer understand the system:- The system consists of tutors and classes. The data in the table All_Tag_Relations stores tag relations for each tutor registered and each class created by a tutor. The tag relations are used for searching classes. CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`), KEY `tag_4` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (1, 'Sandeepan'), (2, 'Nath'), (3, 'first'), (4, 'class'), (5, 'new'), (6, 'Bob'), (7, 'Cratchit'); CREATE TABLE IF NOT EXISTS `All_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) default NULL, `id_wc` int(10) unsigned default NULL, KEY `All_Tag_Relations_FKIndex1` (`id_tag`), KEY `id_wc` (`id_wc`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `All_Tag_Relations` (`id_tag`, `id_tutor`, `id_wc`) VALUES (1, 1, NULL), (2, 1, NULL), (3, 1, 1), (4, 1, 1), (6, 2, NULL), (7, 2, NULL), (5, 2, 2), (4, 2, 2); Following is my query:- This query searches for "first class" (tag for first = 3 and for class = 4, in Tags table) and returns all those classes such that both the terms first and class are present in the class name. SELECT wtagrels.id_wc,SUM(DISTINCT( wtagrels.id_tag =3)) AS key_1_total_matches, SUM(DISTINCT( wtagrels.id_tag =4)) AS key_2_total_matches FROM all_tag_relations AS wtagrels WHERE ( wtagrels.id_tag =3 OR wtagrels.id_tag =4 ) GROUP BY wtagrels.id_wc HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 LIMIT 0, 20 And it returns the class with id_wc = 1. But, I want the search to show all those classes such that all the search terms are present in the class name or its tutor name So that searching "Sandeepan class" (wtagrels.id_tag = 1,4) or "Sandeepan Nath" also returns the class with id_wc=1. And Searching. Searching "Bob First" should not return any classes. Please modify the above query or suggest a new query, if possible using MyIsam - fulltext search, but somehow help me get the result.

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  • Enforcing a query in MySql to use a specific index

    - by Hossein
    Hi, I have large table. consisting of only 3 columns (id(INT),bookmarkID(INT),tagID(INT)).I have two BTREE indexes one for each bookmarkID and tagID columns.This table has about 21 Million records. I am trying to run this query: SELECT bookmarkID,COUNT(bookmarkID) AS count FROM bookmark_tag_map GROUP BY tagID,bookmarkID HAVING tagID IN (-----"tagIDList"-----) AND count >= N which takes ages to return the results.I read somewhere that if make an index in which it has tagID,bookmarkID together, i will get a much faster result. I created the index after some time. Tried the query again, but it seems that this query is not using the new index that I have made.I ran EXPLAIN and saw that it is actually true. My question now is that how I can enforce a query to use a specific index? also comments on other ways to make the query faster are welcome. Thanks

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  • MYSQL update query php

    - by bell
    I am trying to use an update query to change values held in a database, the new values I am trying to store are held in php variables. I'm not sure what it is I'm doing wrong. mysql_query("UPDATE user SET status='full' WHERE user_id = '$user_id'")or die(mysql_error()); thanks in advance

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  • MySql SELECT AS - Append all field names

    - by jeerose
    I'd like to do something like this: SELECT table.id AS prefix_id, table.name AS prefix_name ... and have the prefix added dynamically to all field names rather than selecting them all manually (ie SELECT table.* AS prefix_* or something) Hopefully I've described that accurately. Any thoughts? Edit To be clear, the reason I'm asking is to make sure that my query result contains every column from each table I call even if there are duplicate field names. For example, I might have a table with lots of fields which means I don't want to alias all the fields manually. Further if 3 tables have a field called name my result won't contain three name results; it will have one. I want to avoid ambiguity with my column names.

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  • Get Auto Increment value with MySQL query

    - by James Simpson
    I currently have a database with over 6 million rows and growing. I currently do SELECT COUNT(id) FROM table; in order to display the number to my users, but the database is getting large and I have no need to store all of those rows except to be able to show the number. Is there a way to select the auto_increment value to display so that I can clear out most of the rows in the database? Using LAST_INSERT_ID() doesn't seem to work.

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  • SQL Server 2008 - Performance impact of transactional replication?

    - by cxfx
    I'm planning to set up transactional replication for a 100Gb SQL Server 2008 database. I have the distributor and publisher on the same server, and am using push subscription. Should there be a performance impact on my publisher server when it creates the initial snapshot, and synchronises it with a subscriber? From what I've tried so far on a staging server, it seems to slow right down. Is there a better way to create the initial snapshot without impacting my production publisher server?

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  • MySQL Query Help

    - by Andy
    I need to find the category id in the products table below. However the cms_ecom_categories.id is wrapped with the & character like &12&. Is there some kind of wild card i could use to wrap around? like %cms_ecom_categories.id% ? $sql = "SELECT * FROM cms_ecom_products, cms_ecom_categories WHERE cms_ecom_products.pCategories = cms_ecom_categories.id AND cms_ecom_categories.slug = ".$page.""; Thanks to all in advance who can help.

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  • A better way to build this MySQL statement with subselects

    - by Corey Maass
    I have five tables in my database. Members, items, comments, votes and countries. I want to get 10 items. I want to get the count of comments and votes for each item. I also want the member that submitted each item, and the country they are from. After posting here and elsewhere, I started using subselects to get the counts, but this query is taking 10 seconds or more! SELECT `items_2`.*, (SELECT COUNT(*) FROM `comments` WHERE (comments.Script = items_2.Id) AND (comments.Active = 1)) AS `Comments`, (SELECT COUNT(votes.Member) FROM `votes` WHERE (votes.Script = items_2.Id) AND (votes.Active = 1)) AS `votes`, `countrys`.`Name` AS `Country` FROM `items` AS `items_2` INNER JOIN `members` ON items_2.Member=members.Id AND members.Active = 1 INNER JOIN `members` AS `members_2` ON items_2.Member=members.Id LEFT JOIN `countrys` ON countrys.Id = members.Country GROUP BY `items_2`.`Id` ORDER BY `Created` DESC LIMIT 10 My question is whether this is the right way to do this, if there's better way to write this statement OR if there's a whole different approach that will be better. Should I run the subselects separately and aggregate the information?

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  • Getting MySQL record count with C#

    - by she hates me
    Hello, I would like to know how can I get record count of a query with C#. Here is the code that I use.. MySqlDataReader recordset = null; query = new MySqlCommand("SELECT * FROM test ORDER BY type_ID ASC", this.conn); recordset = query.ExecuteReader(); while (recordset.Read()) { result.Add(recordset["type_ID"].ToString()); } return result;

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  • Listing mysql row entries from tags into one single row

    - by Derrick
    Hi guys, Ive got two tables, one a listings and another representing a list of tags for the listing table. In the listings table the tag ids are stored in a field called tags as 1-2-3- this has worked out very well for me regular expressions and joins to seperate and display the data, BUT... I now need to pull the titles of those tags into a single row. See below. listings table id tags 1 1-2-3- 2 4-5-6- tags table id title 1 pig 2 dog 3 cat 4 mouse 5 elephant 6 duck And what I need to produce out of the listings table is: id tags 2 mouse, elephant, duck any suggestions?

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  • mysql query optimisation

    - by Bharanikumar
    i have around (1,049,906 total, Query took 0.0005 sec) in my x table , If i simply retrieve trying to retrive the particular field records , Its tooks hardly 6 mins , This is my query SELECT CUSTOMER_CODE FROM X_TBL ; CUSTOMER_CODE = UNIQUE THE ABOVE QUERY TOOK 6MIN , Tel me optimization tips for this , Also in some situation to search customer , i used the CUSTOMER_CODE in like , select CUSTOMER_CODE from X_TBL WHERE CUSTOMER_CODE LIKE "$KEY_WORD%" Regards Bharanikumar

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  • Scientific Linux - mysql and apache fail to start on reboot

    - by Derek Deed
    Both mysqld and httpd fail to restart following a reboot of the server, although chkconfig --list shows both daemons set to on for run levels 2,3,4 & 5 All control is being exectuted via Webmin Reboot serverMySQl and Apache not running MySQL Database Server MySQL version 5.1.69 MySQL is not running on your system - database list could not be retrieved. ________________________________________ Click this button to start the MySQL database server on your system with the command /etc/rc.d/init.d/mysqld start. This Webmin module cannot administer the database until it is started. Apache Webserver Apache version 2.2.15 Start Apache Search Docs.. Global configuration Existing virtual hosts Create virtual host Select all. | Invert selection. Default Server Defines the default settings for all other virtual servers, and processes any unhandled requests. Address Any Port Any Server Name Automatic Document Root /var/www/drupal Virtual Server Processes all requests on port 443 not handled by other virtual servers. Address Any Port 443 Server Name Automatic Document Root /var/www/drupal Select all. | Invert selection. chkconfig --list mysqld mysqld 0:off 1:off 2:on 3:on 4:on 5:on 6:off chkconfig --list httpd httpd 0:off 1:off 2:on 3:on 4:on 5:on 6:off Manually Restart Apache chkconfig --list httpd httpd 0:off 1:off 2:on 3:on 4:on 5:on 6:off Manually Restart MySQL chkconfig --list mysqld mysqld 0:off 1:off 2:on 3:on 4:on 5:on 6:off Everything now running okay; but no difference in the chkconfig outputs above. I tried: chkconfig --levels 235 httpd on /etc/init.d/httpd start and the same for mysqld but no change in operation. Log files show that the shutdown has been completed successfully; but there is no indication of the service restarting until it is executed manually: 131112 13:59:15 InnoDB: Starting shutdown... 131112 13:59:16 InnoDB: Shutdown completed; log sequence number 0 881747021 131112 13:59:16 [Note] /usr/libexec/mysqld: Shutdown complete 131112 13:59:16 mysqld_safe mysqld from pid file /var/run/mysqld/mysqld.pid ended 131112 14:09:52 mysqld_safe Starting mysqld daemon with databases from /var/lib/mysql 131112 14:09:52 InnoDB: Initializing buffer pool, size = 8.0M 131112 14:09:52 InnoDB: Completed initialization of buffer pool And the Apache logs: [Tue Nov 12 13:59:13 2013] [notice] suEXEC mechanism enabled (wrapper: /usr/sbin/suexec) [Tue Nov 12 13:59:13 2013] [notice] Digest: generating secret for digest authentication ... [Tue Nov 12 13:59:13 2013] [notice] Digest: done [Tue Nov 12 13:59:14 2013] [notice] Apache/2.2.15 (Unix) DAV/2 PHP/5.3.3 mod_ssl/2.2.15 OpenSSL/1.0.0-fips configured -- resuming normal operations [Tue Nov 12 13:59:14 2013] [notice] caught SIGTERM, shutting down [Tue Nov 12 14:27:13 2013] [notice] suEXEC mechanism enabled (wrapper: /usr/sbin/suexec) [Tue Nov 12 14:27:13 2013] [notice] Digest: generating secret for digest authentication ... [Tue Nov 12 14:27:13 2013] [notice] Digest: done [Tue Nov 12 14:27:13 2013] [notice] Apache/2.2.15 (Unix) DAV/2 PHP/5.3.3 mod_ssl/2.2.15 OpenSSL/1.0.0-fips configured -- resuming normal operations Is anyone able to shed any light on this problem?

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  • php MySQL snytax error

    - by Jacksta
    my scrip is supposed to look up contacts in a table and present thm on the screen to then be edited. however this is not this case. I am getting the error Parse error: syntax error, unexpected $end in /home/admin/domains/domain.com.au/public_html/pick_modcontact.php on line 50 NOTE: this is the last line in this script. <? session_start(); if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$l_name, $f_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html>

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  • Merging MySQL row entries into a single row

    - by Derrick
    I've got two tables, one for listings and another representing a list of tags for the listings table. In the listings table the tag ids are stored in a field called tags as 1-2-3-. This has worked out very well for me (regular expressions and joins to separate and display the data), but I now need to pull the titles of those tags into a single row. See below. listings table id tags 1 1-2-3- 2 4-5-6- tags table id title 1 pig 2 dog 3 cat 4 mouse 5 elephant 6 duck And what I need to produce out of the listings table is: id tags 2 mouse, elephant, duck

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