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  • Why do I have two different DNS suffix lists?

    - by Rob Kennedy
    My Windows XP laptop has two different DNS suffix lists. The first is the one I see by selecting the Properties dialog of any of my network connections, selecting Internet Protocol Properties Advanced DNS tab, and looking at the list under the "Append these DNS suffixes (in order)" option. The second list is the one shown under "DNS Suffix Search List" when I run ipconfig /all. As far as I can tell, only the second list ever gets used to resolve unqualified host names. Why are there two different lists? How do I configure the second list? Or how can I make my computer use the first list?

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  • How do you write multiple lists from Matlab to the same excel file?

    - by Ben Fossen
    I have several lists in Matlab that I want to write to the same excel file. I have one list xordered and another list aspl. I do not know the length of the lists till after I run the Matlab program. I used data = xlswrite('edgar.xls',fliplr(sortedx'),'A2:A3000') for the first list but when I tried to write another list to the same file like this I ended up with two different excel files named edgar.xls asp_data = xlswrite('edagr.xls', fliplr(aspl'), 'B2:B3000') Is there a way I can write both of these lists into the same excel file? xordered in the A column and aspl in the B column?

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  • Algorithm to find a measurement of similarity between lists.

    - by Cubed
    Given that I have two lists that each contain a separate subset of a common superset, is there an algorithm to give me a similarity measurement? Example: A = { John, Mary, Kate, Peter } and B = { Peter, James, Mary, Kate } How similar are these two lists? Note that I do not know all elements of the common superset. Update: I was unclear and I have probably used the word 'set' in a sloppy fashion. My apologies. Clarification: Order is of importance. If identical elements occupy the same position in the list, we have the highest similarity for that element. The similarity decreased the farther apart the identical elements are. The similarity is even lower if the element only exists in one of the lists. I could even add the extra dimension that lower indices are of greater value, so a a[1] == b[1] is worth more than a[9] == b[9], but that is mainly cause I am curious.

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  • How can I merge two lists and sort them working in 'linear' time?

    - by Sergio Tapia
    I have this, and it works: # E. Given two lists sorted in increasing order, create and return a merged # list of all the elements in sorted order. You may modify the passed in lists. # Ideally, the solution should work in "linear" time, making a single # pass of both lists. def linear_merge(list1, list2): finalList = [] for item in list1: finalList.append(item) for item in list2: finalList.append(item) finalList.sort() return finalList # +++your code here+++ return But, I'd really like to learn this stuff well. :) What does 'linear' time mean?

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  • Why are web developers so keen to use lists ?

    - by Bob
    I've been developing for a while and often develop sites using menu tabs. And I can't figure out why so many web developers like using lists < ul < li etc rather than just using plain old divs. I can make menus in divs which are simple and work perfectly in every browser. With lists, I'm usually trying to hack it one way or another to get it work properly. So my question is simple : why should I use lists to create my menus instead of divs ?

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  • JUnit Theories: Why can't I use Lists (instead of arrays) as DataPoints?

    - by MatrixFrog
    I've started using the new(ish) JUnit Theories feature for parameterizing tests. If your Theory is set up to take, for example, an Integer argument, the Theories test runner picks up any Integers marked with @DataPoint: @DataPoint public static Integer number = 0; as well as any Integers in arrays: @DataPoints public static Integer[] numbers = {1, 2, 3}; or even methods that return arrays like: @DataPoints public static Integer[] moreNumbers() { return new Integer[] {4, 5, 6};}; but not in Lists. The following does not work: @DataPoints public static List<Integer> numberList = Arrays.asList(7, 8, 9); Am I doing something wrong, or do Lists really not work? Was it a conscious design choice not to allow the use Lists as data points, or is that just a feature that hasn't been implemented yet? Are there plans to implement it in a future version of JUnit?

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  • Ubuntu Software Center will not load and cannot be removed

    - by Drew Z.
    My Ubuntu Software Center has stopped working and I have been trying to uninstall/re-install it. This is the error that I repeatedly keep receiving: drew@drew-Aspire-5750:~$ sudo apt-get remove software-center [sudo] password for drew: Reading package lists... Error! E: Encountered a section with no Package: header E: Problem with MergeList /var/lib/apt/lists/dl.google.com_linux_chrome_deb_dists_stable_main_binary-i386_Packages E: The package lists or status file could not be parsed or opened. drew@drew-Aspire-5750:~$ sudo apt-get autoremove software-center Reading package lists... Error! E: Encountered a section with no Package: header E: Problem with MergeList /var/lib/apt/lists/dl.google.com_linux_chrome_deb_dists_stable_main_binary-i386_Packages E: The package lists or status file could not be parsed or opened. drew@drew-Aspire-5750:~$ Any help would be gratefully appreciated.

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  • how to speed up the code??

    - by kaushik
    i have very huge code about 600 lines plus. cant post the whole thing here. but a particular code snippet is taking so much time,leading to problems. here i post that part of code please tell me what to do speed up the processing.. please suggest the part which may be the reason and measure to improve them if this small part of code is understandable. using_data={} def join_cost(a , b): global using_data #print a #print b save_a=[] save_b=[] print 1 #for i in range(len(m)): #if str(m[i][0])==str(a): save_a=database_index[a] #for i in range(len(m)): # if str(m[i][0])==str(b): #print 'save_a',save_a #print 'save_b',save_b print 2 save_b=database_index[b] using_data[save_a[0]]=save_a s=str(save_a[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') print 3 for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) end_time=save_a[4] #print end_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(end_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 q=[] print 4 l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') q=k3.split(' ') #print q print 5 s=str(save_b[1]).replace('phone','text') s=str(s)+'.pm' p=os.path.join("c:/begpython/wavnk/",s) x=open(p , 'r') for i in range(6): x.readline() k2='a' j=0 o=[] while k2 is not '': k2=x.readline() k2=k2.rstrip('\n') oj=k2.split(' ') o=o+[oj] #print o[j] j=j+1 #print j #print o[2][0] temp=long(1232332) strt_time=save_b[3] #print strt_time k=(j-1) for i in range(k): diff=float(o[i][0])-float(strt_time) if diff<0: diff=diff*(-1) if temp>diff: temp=diff pm_row=i #print pm_row #print temp #print o[pm_row] #pm_row=3 w=[] l=str(p).replace('.pm','.mcep') z=open(l ,'r') for i in range(pm_row): z.readline() k3=z.readline() k3=k3.rstrip('\n') w=k3.split(' ') #print w cost=0 for i in range(12): #print q[i] #print w[i] h=float(q[i])-float(w[i]) cost=cost+math.pow(h,2) j_cost=math.sqrt(cost) #print cost return j_cost def target_cost(a , b): a=(b+1)*3 b=(a+1)*2 t_cost=(a+b)*5/2 return t_cost r1='shht:ra_77' r2='grx_18' g=[] nodes=[] nodes=nodes+[[r1]] for i in range(len(y_in_db_format)): g=y_in_db_format[i] #print g #print g[0] g.remove(str(g[0])) nodes=nodes+[g] nodes=nodes+[[r2]] print nodes print "lenght of nodes",len(nodes) lists=[] #lists=lists+[r1] for i in range(len(nodes)): for j in range(len(nodes[i])): lists=lists+[nodes[i][j]] #lists=lists+[r2] print lists distance={} for i in range(len(lists)): if i==0: distance[str(lists[i])]=0 else: distance[str(lists[i])]=long(123231223) #print distance group_dist=[] infinity=long(123232323) for i in range(len(nodes)): distances=[] for j in range(len(nodes[i])): #distances=[] if i==0: distances=distances+[[nodes[i][j], 0]] else: distances=distances+[[nodes[i][j],infinity]] group_dist=group_dist+[distances] #print distances print "group_distances",group_dist #print "check",group_dist[0][0][1] #costs={} #for i in range(len(lists)): #if i==0: # costs[str(lists[i])]=1 #else: # costs[str(lists[i])]=get_selfcost(lists[i]) path=[] for i in range(len(nodes)): mini=[] if i!=(len(nodes)-1): #temp=long(123234324) #Now calculate the cost between the current node and each of its neighbour for k in range(len(nodes[(i+1)])): for j in range(len(nodes[i])): current=nodes[i][j] #print "current_node",current j_distance=join_cost( current , nodes[i+1][k]) #t_distance=target_cost( current , nodes[i+1][k]) t_distance=34 #print distance #print "distance between current and neighbours",distance total_distance=(.5*(float(group_dist[i][j][1])+float(j_distance))+.5*(float(t_distance))) #print "total distance between the intial_nodes and current neighbour",total_distance if int(group_dist[i+1][k][1]) > int(total_distance): group_dist[i+1][k][1]=total_distance #print "updated distance",group_dist[i+1][k][1] a=current #print "the neighbour",nodes[i+1][k],"updated the value",a mini=mini+[[str(nodes[i+1][k]),a]] print mini

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  • How can I collapse a nested list using jQuery?

    - by Bradley Herman
    I have a nested list: <ul> <li><a href='#'>stuff</a></li> <li><a href='#'>stuff2</a></li> <ul> <li><a href='#'>stuff3</a></li> </ul> <li><a href='#'>stuff4</a></li> </ul> ...and want to collapse the nested ul when the li is clicked. Before I was using $('UL LI').click(function(){ $(this).next().slideToggle(); }); ...but this obviously causes a problem when a li doesn't have a ul nested after it. Is there a better way to do this, or is there a way for me to determine if the object returned by $(this).next() is a UL?

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  • Ho do I extract a Outlook message nested into another using Apache POI - HSMF?

    - by Jan
    I am using Apache POI - HSMF to extract attachments from Outlooks msg-files. It works fine except for nested messages. If an msg is attached to another msg I am able to get the files. If a message is nested I get the information but I need the file. MAPIMessage msg = new MAPIMessage(fileName) for(AttachmentChunks attachment : msg.getAttachmentFiles()) { if(attachment.attachmentDirectory!=null){ MAPIMessage nestedMsg attachment.attachmentDirectory.getAsEmbededMessage(); // now save nestedMsg as a msg-file } } Is it possible to save the nested message file as a regular msg-file?

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  • What's the standard algorithm for syncing two lists of objects?

    - by Oliver Giesen
    I'm pretty sure this must be in some kind of text book (or more likely in all of them) but I seem to be using the wrong keywords to search for it... :( A common task I'm facing while programming is that I am dealing with lists of objects from different sources which I need to keep in sync somehow. Typically there's some sort of "master list" e.g. returned by some external API and then a list of objects I create myself each of which corresponds to an object in the master list. Sometimes the nature of the external API will not allow me to do a live sync: For instance the external list might not implement notifications about items being added or removed or it might notify me but not give me a reference to the actual item that was added or removed. Furthermore, refreshing the external list might return a completely new set of instances even though they still represent the same information so simply storing references to the external objects might also not always be feasible. Another characteristic of the problem is that both lists cannot be sorted in any meaningful way. You should also assume that initializing new objects in the "slave list" is expensive, i.e. simply clearing and rebuilding it from scratch is not an option. So how would I typically tackle this? What's the name of the algorithm I should google for? In the past I have implemented this in various ways (see below for an example) but it always felt like there should be a cleaner and more efficient way. Here's an example approach: Iterate over the master list Look up each item in the "slave list" Add items that do not yet exist Somehow keep track of items that already exist in both lists (e.g. by tagging them or keeping yet another list) When done iterate once more over the slave list Remove all objects that have not been tagged (see 4.) Update Thanks for all your responses so far! I will need some time to look at the links. Maybe one more thing worthy of note: In many of the situations where I needed this the implementation of the "master list" is completely hidden from me. In the most extreme cases the only access I might have to the master list might be a COM-interface that exposes nothing but GetFirst-, GetNext-style methods. I'm mentioning this because of the suggestions to either sort the list or to subclass it both of which is unfortunately not practical in these cases unless I copy the elements into a list of my own and I don't think that would be very efficient. I also might not have made it clear enough that the elements in the two lists are of different types, i.e. not assignment-compatible: Especially, the elements in the master list might be available as interface references only.

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  • Of these 3 methods for reading linked lists from shared memory, why is the 3rd fastest?

    - by Joseph Garvin
    I have a 'server' program that updates many linked lists in shared memory in response to external events. I want client programs to notice an update on any of the lists as quickly as possible (lowest latency). The server marks a linked list's node's state_ as FILLED once its data is filled in and its next pointer has been set to a valid location. Until then, its state_ is NOT_FILLED_YET. I am using memory barriers to make sure that clients don't see the state_ as FILLED before the data within is actually ready (and it seems to work, I never see corrupt data). Also, state_ is volatile to be sure the compiler doesn't lift the client's checking of it out of loops. Keeping the server code exactly the same, I've come up with 3 different methods for the client to scan the linked lists for changes. The question is: Why is the 3rd method fastest? Method 1: Round robin over all the linked lists (called 'channels') continuously, looking to see if any nodes have changed to 'FILLED': void method_one() { std::vector<Data*> channel_cursors; for(ChannelList::iterator i = channel_list.begin(); i != channel_list.end(); ++i) { Data* current_item = static_cast<Data*>(i->get(segment)->tail_.get(segment)); channel_cursors.push_back(current_item); } while(true) { for(std::size_t i = 0; i < channel_list.size(); ++i) { Data* current_item = channel_cursors[i]; ACQUIRE_MEMORY_BARRIER; if(current_item->state_ == NOT_FILLED_YET) { continue; } log_latency(current_item->tv_sec_, current_item->tv_usec_); channel_cursors[i] = static_cast<Data*>(current_item->next_.get(segment)); } } } Method 1 gave very low latency when then number of channels was small. But when the number of channels grew (250K+) it became very slow because of looping over all the channels. So I tried... Method 2: Give each linked list an ID. Keep a separate 'update list' to the side. Every time one of the linked lists is updated, push its ID on to the update list. Now we just need to monitor the single update list, and check the IDs we get from it. void method_two() { std::vector<Data*> channel_cursors; for(ChannelList::iterator i = channel_list.begin(); i != channel_list.end(); ++i) { Data* current_item = static_cast<Data*>(i->get(segment)->tail_.get(segment)); channel_cursors.push_back(current_item); } UpdateID* update_cursor = static_cast<UpdateID*>(update_channel.tail_.get(segment)); while(true) { if(update_cursor->state_ == NOT_FILLED_YET) { continue; } ::uint32_t update_id = update_cursor->list_id_; Data* current_item = channel_cursors[update_id]; if(current_item->state_ == NOT_FILLED_YET) { std::cerr << "This should never print." << std::endl; // it doesn't continue; } log_latency(current_item->tv_sec_, current_item->tv_usec_); channel_cursors[update_id] = static_cast<Data*>(current_item->next_.get(segment)); update_cursor = static_cast<UpdateID*>(update_cursor->next_.get(segment)); } } Method 2 gave TERRIBLE latency. Whereas Method 1 might give under 10us latency, Method 2 would inexplicably often given 8ms latency! Using gettimeofday it appears that the change in update_cursor-state_ was very slow to propogate from the server's view to the client's (I'm on a multicore box, so I assume the delay is due to cache). So I tried a hybrid approach... Method 3: Keep the update list. But loop over all the channels continuously, and within each iteration check if the update list has updated. If it has, go with the number pushed onto it. If it hasn't, check the channel we've currently iterated to. void method_three() { std::vector<Data*> channel_cursors; for(ChannelList::iterator i = channel_list.begin(); i != channel_list.end(); ++i) { Data* current_item = static_cast<Data*>(i->get(segment)->tail_.get(segment)); channel_cursors.push_back(current_item); } UpdateID* update_cursor = static_cast<UpdateID*>(update_channel.tail_.get(segment)); while(true) { for(std::size_t i = 0; i < channel_list.size(); ++i) { std::size_t idx = i; ACQUIRE_MEMORY_BARRIER; if(update_cursor->state_ != NOT_FILLED_YET) { //std::cerr << "Found via update" << std::endl; i--; idx = update_cursor->list_id_; update_cursor = static_cast<UpdateID*>(update_cursor->next_.get(segment)); } Data* current_item = channel_cursors[idx]; ACQUIRE_MEMORY_BARRIER; if(current_item->state_ == NOT_FILLED_YET) { continue; } found_an_update = true; log_latency(current_item->tv_sec_, current_item->tv_usec_); channel_cursors[idx] = static_cast<Data*>(current_item->next_.get(segment)); } } } The latency of this method was as good as Method 1, but scaled to large numbers of channels. The problem is, I have no clue why. Just to throw a wrench in things: if I uncomment the 'found via update' part, it prints between EVERY LATENCY LOG MESSAGE. Which means things are only ever found on the update list! So I don't understand how this method can be faster than method 2. The full, compilable code (requires GCC and boost-1.41) that generates random strings as test data is at: http://pastebin.com/e3HuL0nr

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  • Why doesn't Python have a "flatten" function for lists?

    - by Hubro
    Erlang and Ruby both come with functions for flattening arrays. It seems like such a simple and useful tool to add to a language. One could do this: >>> mess = [[1, [2]], 3, [[[4, 5]], 6]] >>> mess.flatten() [1, 2, 3, 4, 5, 6] Or even: >>> import itertools >>> mess = [[1, [2]], 3, [[[4, 5]], 6]] >>> list(itertools.flatten(mess)) [1, 2, 3, 4, 5, 6] Instead, in Python, one has to go through the trouble of writing a function for flattening arrays from scratch. This seems silly to me, flattening arrays is such a common thing to do. It's like having to write a custom function for concatenating two arrays. I have Googled this fruitlessly, so I'm asking here; is there a particular reason why a mature language like Python 3, which comes with a hundred thousand various batteries included, doesn't provide a simple method of flattening arrays? Has the idea of including such a function been discussed and rejected at some point?

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  • Process arbitrarily large lists without explicit recursion or abstract list functions?

    - by Erica Xu
    This is one of the bonus questions in my assignment. The specific questions is to see the input list as a set and output all subsets of it in a list. We can only use cons, first, rest, empty?, empty, lambda, and cond. And we can only define exactly once. But after a night's thinking I don't see it possible to go through the arbitrarily long list without map or foldr. Is there a way to perform recursion or alternative of recursion with only these functions?

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  • From the Tips Box: Quick File Renaming in Windows 7, Fast Access to Web Sites on Android, and GPS-based Todo Lists

    - by Jason Fitzpatrick
    Once a week we round up some reader tips and share them with the greater How-To Geek audience. This week we’re looking at speedy file renaming in Windows 7, fast access to bookmarks in Android, and a neat GPS-based todo list. How to Stress Test the Hard Drives in Your PC or Server How To Customize Your Android Lock Screen with WidgetLocker The Best Free Portable Apps for Your Flash Drive Toolkit

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  • How to see the lists of my videos in Shotwell?

    - by Joe Cabezas
    I made an import from my camera (photos and videos), and after imported them, the "last sync" item, shows me the photos and videos i've recently imported. But if I click any Event in the "Events" tree (left side), only shows my photos... How to see my videos imported that day also? using shotwell 0.12.3 (default in ubuntu 12.10) pics: Last import preview: http://i.stack.imgur.com/uVnQR.png Event preview: http://i.stack.imgur.com/WTuSg.png PD: sorry I have no rights yet to post pictures

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  • How often do you use data structures (ie Binary Trees, Linked Lists) in your jobs/side projects?

    - by Chris2021
    It seems to me that, for everyday use, more primitive data structures like arrays get the job done just as well as a binary tree would. My question is how common is to use these structures when writing code for projects at work or projects that you pursue in your free time? I understand the better insertion time/deletion time/sorting time for certain structures but would that really matter that much if you were working with a relatively small amount of data?

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  • Is it conceivable to have millions of lists of data in memory in Python?

    - by Codemonkey
    I have over the last 30 days been developing a Python application that utilizes a MySQL database of information (specifically about Norwegian addresses) to perform address validation and correction. The database contains approximately 2.1 million rows (43 columns) of data and occupies 640MB of disk space. I'm thinking about speed optimizations, and I've got to assume that when validating 10,000+ addresses, each validation running up to 20 queries to the database, networking is a speed bottleneck. I haven't done any measuring or timing yet, and I'm sure there are simpler ways of speed optimizing the application at the moment, but I just want to get the experts' opinions on how realistic it is to load this amount of data into a row-of-rows structure in Python. Also, would it even be any faster? Surely MySQL is optimized for looking up records among vast amounts of data, so how much help would it even be to remove the networking step? Can you imagine any other viable methods of removing the networking step? The location of the MySQL server will vary, as the application might well be run from a laptop at home or at the office, where the server would be local.

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  • Why would you use data structures (ie Binary Trees, Linked Lists) in your jobs/side projects? [closed]

    - by Chris2021
    It seems to me that, for everyday use, more primitive data structures like arrays get the job done just as well as a binary tree would. My question is how common is to use these structures when writing code for projects at work or projects that you pursue in your free time? I understand the better insertion time/deletion time/sorting time for certain structures but would that really matter that much if you were working with a relatively small amount of data?

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  • Why is Swing Parser's handleText not handling nested tags?

    - by Jim P
    I need to transform some HTML text that has nested tags to decorate 'matches' with a css attribute to highlight it (like firefox search). I can't just do a simple replace (think if user searched for "img" for example), so I'm trying to just do the replace within the body text (not on tag attributes). I have a pretty straightforward HTML parser that I think should do this: final Pattern pat = Pattern.compile(srch, Pattern.CASE_INSENSITIVE); Matcher m = pat.matcher(output); if (m.find()) { final StringBuffer ret = new StringBuffer(output.length()+100); lastPos=0; try { new ParserDelegator().parse(new StringReader(output.toString()), new HTMLEditorKit.ParserCallback () { public void handleText(char[] data, int pos) { ret.append(output.subSequence(lastPos, pos)); Matcher m = pat.matcher(new String(data)); ret.append(m.replaceAll("<span class=\"search\">$0</span>")); lastPos=pos+data.length; } }, false); ret.append(output.subSequence(lastPos, output.length())); return ret; } catch (Exception e) { return output; } } return output; My problem is, when I debug this, the handleText is getting called with text that includes tags! It's like it's only going one level deep. Anyone know why? Is there some simple thing I need to do to HTMLParser (haven't used it much) to enable 'proper' behavior of nested tags? PS - I figured it out myself - see answer below. Short answer is, it works fine if you pass it HTML, not pre-escaped HTML. Doh! Hope this helps someone else. <span>example with <a href="#">nested</a> <p>more nesting</p> </span> <!-- all this gets thrown together -->

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  • Same query has nested loops when used with INSERT, but Hash Match without.

    - by AaronLS
    I have two tables, one has about 1500 records and the other has about 300000 child records. About a 1:200 ratio. I stage the parent table to a staging table, SomeParentTable_Staging, and then I stage all of it's child records, but I only want the ones that are related to the records I staged in the parent table. So I use the below query to perform this staging by joining with the parent tables staged data. --Stage child records INSERT INTO [dbo].[SomeChildTable_Staging] ([SomeChildTableId] ,[SomeParentTableId] ,SomeData1 ,SomeData2 ,SomeData3 ,SomeData4 ) SELECT [SomeChildTableId] ,D.[SomeParentTableId] ,SomeData1 ,SomeData2 ,SomeData3 ,SomeData4 FROM [dbo].[SomeChildTable] D INNER JOIN dbo.SomeParentTable_Staging I ON D.SomeParentTableID = I.SomeParentTableID; The execution plan indicates that the tables are being joined with a Nested Loop. When I run just the select portion of the query without the insert, the join is performed with Hash Match. So the select statement is the same, but in the context of an insert it uses the slower nested loop. I have added non-clustered index on the D.SomeParentTableID so that there is an index on both sides of the join. I.SomeParentTableID is a primary key with clustered index. Why does it use a nested loop for inserts that use a join? Is there a way to improve the performance of the join for the insert?

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