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  • memory available to 64bit Fedora guest under 32bit XP host running virtualbox

    - by Chris Card
    I have successfully installed a 64 bit Fedora 11 guest os using VirtualBox on a host machine (AMD64) running 32 bit Windows XP . At the moment the host machine has 2 Gb ram installed and I've allocated 1 Gb to the guest, which all works well. The host machine can hold a maximum of 4 Gb ram, so I was wondering if it's worth buying an extra 2 Gb for it. I know that 32 bit Windows XP can't use all of the 4 Gb, but can the guest os use any of the ram that the host os can't use?

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  • Is JavaFx suitable for creating online multiplayer board/card games?

    - by Piniu
    In JavaFx i can easy create animations, moving pieces etc., but as far as i see there is better to write program logic and communication in java. Worst i see at the moment is calling javafx part as a result of data incoming from server. Is there any convenient way to do it or its better to change to other technology (flex, qt?) assuming it is not important if program will run in browser or outside as a standalone application? I just started to learn javafx but can drop it and move to other technology and consider c++ + wxWidgets or Qt which im more comforatable with.

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  • How GPS works in iPhone ?

    - by Krishnan
    Hi Friends, I am using a iPhone 3g. I am in India(I got it in India). I just tried to check my location using the Google Maps. My location was spotted when I had sim in my phone. But when I took out the SIM from iPhone, I did not get my location. I tried the same with the Locate me Sample Application . So can someone explain how GPS works in iPhone, and how to fix my problem(to get my location when there is no SIM). Thanks and Regards, krishnan

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  • create a dict of lists from a string

    - by Chris Card
    I want to convert a string such as 'a=b,a=c,a=d,b=e' into a dict of lists {'a': ['b', 'c', 'd'], 'b': ['e']} in Python 2.6. My current solution is this: def merge(d1, d2): for k, v in d2.items(): if k in d1: if type(d1[k]) != type(list()): d1[k] = list(d1[k]) d1[k].append(v) else: d1[k] = list(v) return d1 record = 'a=b,a=c,a=d,b=e' print reduce(merge, map(dict,[[x.split('=')] for x in record.split(',')])) which I'm sure is unnecessarily complicated. Any better solutions?

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  • How to load jni from sd card on android 2.1?

    - by user263423
    I want to load third-party jni library in runtime. I've tried to load directly from sdcard. It expectedly failed. I've tried to copy library from sdcard to /data/data/app/ and then System.load(/data/data/libjni.so) It works on HTC HERO, but fails on HTC Legend with Android 2.1. it fails during execution of native code and write to log uninformative stack trace Any other way to do it?

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  • C to C++ Conversion [closed]

    - by Annalyne
    Can someone convert this code to C++, pretty please? :( #include <stdio.h> #include <stdlib.h> #include <time.h> #define WEAPON_ROPE 10 #define WEAPON_REVOLVER 20 #define WEAPON_LEADPIPE 30 #define WEAPON_CANDLESTICK 40 #define WEAPON_KNIFE 50 #define WEAPON_WRENCH 60 #define PEOPLE_MRGREEN 100 #define PEOPLE_MSSCARLET 200 #define PEOPLE_CONLMUSTARD 300 #define PEOPLE_PROFPLUM 400 #define PEOPLE_MISPEACOCK 500 #define PEOPLE_MISWHITE 600 #define PLACE_KITCHEN 1 #define PLACE_HALL 2 #define PLACE_POOLROOM 3 #define PLACE_STUDY 4 #define PLACE_LOUNG 5 #define PLACE_LIBRARY 6 #define PLACE_CONSERVATORY 7 #define PLACE_DINING 8 #define PLACE_BILLIARDS 9 int main() { int die = 0; int players[6][9] = {{0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0}}; int allCards[] = {WEAPON_ROPE, WEAPON_REVOLVER, WEAPON_LEADPIPE, WEAPON_CANDLESTICK, WEAPON_CANDLESTICK, WEAPON_KNIFE, WEAPON_WRENCH, PEOPLE_MRGREEN, PEOPLE_MSSCARLET, PEOPLE_CONLMUSTARD, PEOPLE_CONLMUSTARD, PEOPLE_PROFPLUM, PEOPLE_MISPEACOCK, PEOPLE_MISWHITE, PLACE_KITCHEN, PLACE_HALL, PLACE_POOLROOM, PLACE_STUDY, PLACE_LOUNG, PLACE_LIBRARY, PLACE_CONSERVATORY, PLACE_DINING, PLACE_BILLIARDS}; int deckSize = 23; // number of cards in allCards array int count; for (count = 0; count < deckSize; ++count) { printf(", %d", allCards[count]); } // End for // These three array's are so you can put a card back, if need be... int weaponCards[] = {WEAPON_ROPE, WEAPON_REVOLVER, WEAPON_LEADPIPE, WEAPON_CANDLESTICK, WEAPON_CANDLESTICK, WEAPON_KNIFE, WEAPON_WRENCH}; int weaponDeckSize = 7; int peopleCards[] = {PEOPLE_MRGREEN, PEOPLE_MSSCARLET, PEOPLE_CONLMUSTARD, PEOPLE_CONLMUSTARD, PEOPLE_PROFPLUM, PEOPLE_MISPEACOCK, PEOPLE_MISWHITE}; int peopleDeckSize = 7; int placeCards[] = {PLACE_KITCHEN, PLACE_HALL, PLACE_POOLROOM, PLACE_STUDY, PLACE_LOUNG, PLACE_LIBRARY, PLACE_CONSERVATORY, PLACE_DINING, PLACE_BILLIARDS}; int placeDeckSize = 9; srand(clock()); // seed rand() using clock() which gives // the current tick your processor is at... int killer[3]; // no need to initialize yet. killer[0-2] will initialize int deckShuffle = rand() % weaponDeckSize; // picks one number out of the deck killer[0] = weaponCards[deckShuffle]; allCards[deckShuffle] = 0; // Card drawn. No longer exists in deck deckShuffle = rand() % peopleDeckSize; // picks another random card out of the deck killer[1] = peopleCards[deckShuffle]; allCards[deckShuffle + weaponDeckSize] = 0; // Card drawn. No longer exists in deck deckShuffle = rand() % placeDeckSize; // randomly picks the last card needed killer[2] = placeCards[deckShuffle]; allCards[deckShuffle + weaponDeckSize + peopleDeckSize] = 0; // Card drawn. No longer exists in deck int numberOfCards = 0; printf("CLUE\n"); printf("written by John Schintone\n"); printf("Origonal game delvoped by Hasbro\n"); int numberOfPlayers = 0; while ((numberOfPlayers < 3) || (numberOfPlayers > 6)) { printf("How many players are Going to play :\n"); printf("[number] > "); scanf("%d",&numberOfPlayers); // A very fast if statement which only uses integers/char's switch(numberOfPlayers) { case 6: { numberOfCards = 3; } break; case 5: { numberOfCards = 4; } break; case 4: { numberOfCards = 5; } break; case 3: { numberOfCards = 6; } break; default: { printf("You must enter a number between 3 and 6...\n"); } // End default } // End switch } // End while int index1, index2; // Note: ++index1; is faster than index1++; and will almost always // produce better code (index1++ happens after this statement line. // ++index1 increments index1 before this statement line) for (index1 = 0; index1 < numberOfPlayers; ++index1) { printf("Player %d", index1); for (index2 = 0; index2 < numberOfCards; ++index2) { // Remember that allCards[deckShuffle] == 0 because we removed that // card ages ago... works out well, just don't forget you did that : ) while (allCards[deckShuffle] == 0) { deckShuffle = rand() % deckSize; } // End while players[index1][index2] = allCards[deckShuffle]; allCards[deckShuffle] = 0; // Card removed for after loop... printf(", %d", players[index1][index2]); switch(players[index1][index2]) { case WEAPON_ROPE: { } break; // Add more... case PEOPLE_MRGREEN: { } break; // Add more... case PLACE_KITCHEN: { } break; // Add more... default: { printf("Program has caught player %d cheating...", index1); } // End default } // End switch } // End for printf("\n"); } // End for printf("The killer is %d, with the %d, and in the %d \n\n", killer[0], killer[1], killer[2]); printf("Type h for this help... \n"); printf("Type e to escape... \n"); printf("Type r to roll the die... \n"); char command = '\0'; // \0 represents zero, or the null character while (command != 'e') { printf("[one character] > "); scanf("%c", &command); if (command == 'r') { die = rand() % 6 + 1; printf("Your number is: %d \n", die); } // end while if (command == 'h') { printf("Type h for this help... \n"); printf("Type e to escape... \n"); printf("Type r to roll the die... \n"); } // End if printf("\n"); } // End while return(0); // Success. Program worked ok } // End main() Function

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  • Why doesn't splicing an object from an array in Javascript return the array?

    - by Allen Gould
    I have an array of objects (say, a deck of cards): var deck = []; deck.push(new Card(suit, rank)); The following seems to work: var card = deck.pop(); var card = deck.shift(); (pulling from the "top" or "bottom" of the deck respectively) But if I want a card from the middle (say, if this was a hand of cards) var card = deck.splice(2,1); The object doesn't seem to get properly assigned to the variable (everything is undefined). Everything I look up says that splice should return the object that I'm removing - what am I missing?

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  • List.clear() followed by List.add() not working.

    - by Vincent
    I have the following C# Class/Function: class Hand { private List<Card> myCards = new List<Card>(); public void sortBySuitValue() { IEnumerable<Card> query = from s in myCards orderby (int)s.suit, (int)s.value select s; myCards = new List<Card>(); myCards.AddRange(query); } } On a card Game. This works fine, however, I had trouble at first, instead of using myCards = new List(); to 'reset' myCards, I would use myCards.clear(), however, once I called the clear function, I would not be able to call myCards.add() or myCards.addRange(). The count would stay at zero. Is my current approach good? Is using LINQ to sort my cards good/bad?

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  • Comparing Isis, Google, and Paypal

    - by David Dorf
    Back in 2010 I was sure NFC would make great strides, but here we are two years later and NFC doesn't seem to be sticking. The obvious reason being the chicken-and-egg problem.  Retailers don't want to install the terminals until the phones support NFC, and vice-versa. So consumers continue to sit on the sidelines waiting for either side to blink and make the necessary investment.  In the meantime, EMV is looking for a way to sneak into the US with the help of the card brands. There are currently three major solutions that are battling in the marketplace.  All three know that replacing mag-stripe alone is not sufficient to move consumers.  Long-term it's the offers and loyalty programs combined with tendering that make NFC attractive. NFC solutions cross lots of barriers, so a strong partner system is required.  The solutions need to include the carriers, card brands, banks, handset manufacturers, POS terminals, and most of all lots of merchants.  Lots of coordination is necessary to make the solution seamless to the consumer. Google Wallet Google's problem has always been that only the Nexus phone has an NFC chip that supports their wallet.  There are a couple of additional phones out there now, but adoption is still slow.  They acquired Zavers a while back to incorporate digital coupons, but the the bulk of their users continue to be non-NFC.  They have taken an open approach by not specifying particular payment brands.  Google is piloting in San Francisco and New York, supporting both MasterCard PayPass and stored value. I suppose the other card brands may eventually follow.  There's no cost for consumers or merchants -- Google will make money via targeted ads. Isis Not long after Google announced its wallet, AT&T, Verizon, and T-Mobile announced a joint venture called Isis.  They are in the unique position of owning the SIM in the phones they issue.  At first it seemed Isis was a vehicle for the carriers to compete with the existing card brands, but Isis later switched to a generic wallet that supports the major card brands.  Isis reportedly charges issuers a $5 fee per customer per year.  Isis will pilot this summer in Salt Lake City and Austin. PayPal PayPal, the clear winner in the online payment space beyond traditional credit cards, is trying to move into physical stores.  After negotiations with Google to provide a wallet broke off, PayPal decided to avoid NFC altogether, at least for now, and focus on payments without any physical card or phone.  By avoiding NFC, consumers don't need an NFC-enabled phone and merchants don't need a new reader.  Consumers must enter their phone number and PIN in the merchant's existing device, or they can enter their PIN in the PayPal inStore app running on their phone, then show the merchant a unique barcode which authorizes payment. Paypal is free for consumers and charges a fee for merchants.  Its not clear, at least to me, how PayPal handles fraudulent transactions and whether the consumer is protected. The wildcard is, of course, Apple.  Their mobile technologies set the standard, so incorporating NFC chips would certainly accelerate adoption of many payment solutions.  Their announcement today of the iOS Passbook is a step in the right direction, but stops short of handling payments. For those retailers that have invested in modern terminals, it seems the best strategy is to support all the emerging solutions and let the consumers choose the winner.

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  • Best triple head display setup

    - by dgel
    I'm currently running Ubuntu 12.04 with a darn good triple head display setup. I've got a VisionTek 900530 Radeon HD 5450 512MB DDR3 PCI Express video card that has two DVI outputs and one Mini DisplayPort that I have connected to a HDMI adapter. I'm running three identical Asus 1920x1080 monitors that each have a DVI, VGA, and HDMI input. I'm using the xorg-edgers ppa, so I'm using the open source radeon driver version 6.99.99. I tried using the ATI binary fglrx driver, but I wasn't able to get the three monitors working properly- the monitor connected via HDMI / DisplayPort wouldn't run at full resolution. The setup is almost perfect: Compiz runs fine and is quite snappy. I'm not able to use that great compiz feature where you can drag a window to the side of a display and it will half maximize. I occasionally experience display corruption weirdness with Unity and need to restart it. When I use a dropdown menu in LibreOffice it often pops the menu down in another window. For example, if I'm using the center monitor and click the Insert menu, the menu pulls down on the monitor to my right, forcing me to chase it. If I chase down the menu and choose Manual Break, the dialog appears over on my left monitor. This absurdity is mildly entertaining but has lost its novelty. I've decided to build a new system and have spared no expense- latest i7 processor, SSD, etc. I really like the performance of the Nvidia binary drivers, so I put two ZOTAC ZT-40707-10L GeForce GT 440 in the system, figuring I'd have four DVI outputs and an awesome triple (or even eventually quad) head setup. Unfortunately it appears that I didn't do sufficient research before my purchase. It seems that Nvidia TwinView only supports two monitors on one card (I guess that's why they call it TwinView...). I messed around with running two X servers, but I really don't want that- being able to drag windows to any monitor is critical. It doesn't sound like Xinerama is an option because from what I understand it simply doesn't support Compiz. I've seen a BaseMosaic option that can be used with the Nvidia drivers that appears to support an almost unlimited number of heads- unfortunately me cheap little cards don't support it. I'm also not sure whether you'll still have all nice maximizing and snapping that TwinView provides, or whether Ubuntu will only see it as one massive display. I put my old trusty ATI card into my new system and installed 12.10. I'm using the opensource radeon drivers again because even in 12.10 I can't get the fglrx binary drivers to do triple head. Unfortunately, even with an unbelievably powerful system the experience is extremely sluggish (much more so than my experience in 12.04). The menu scattering problem appears to be fixed, but I get a lot of nasty Unity display corruption. So finally, my question is this: What hardware / drivers should I use? I'm willing to buy (almost) any video card(s). I have two PCI-Express 3.0 slots on my motherboard (which has an integrated Intel HD card). I'm willing to use ATI or Nvidia cards and willing to run Ubuntu 12.04.1 or 12.10. I'm not a gamer, but do want beautiful and snappy Compiz effects. Does anyone out there have the perfect triple head setup in 12.04 or 12.10? What hardware / drivers are you using? I have those two Nvidia cards but will probably be returning them unless someone knows a way to use them together for a triple head setup. Since I'm having pretty good luck with a single ATI card providing three displays, should I just buy a beefier one with the hopes that it will fix the horrible sluggishness I'm experiencing in 12.10?

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  • Scheme homework Black jack help....

    - by octavio
    So I need to do a game of blackjack simulator, butt can't seem to figure out whats wrong with the shuffle it's suppose to take a card randomly from the pack the put it on top of the pack. The delete it from the rest. so : (ace)(2)(3)(4)(5)...(k) if random card is let say 5 (5)(ace)(2)(3)(4)(5)...(k) then it deletes the 2nd 5 (5)(ace)(2)(3)(4)(6)...(k) here is the code: (define deck '((A . C) (2 . C) (3 . C) (4 . C) (5 . C) (6 . C) (7 . C) (8 . C) (9 . C) (10 . C) (V . C) (Q . C) (K . C))) ;auxilliary function for shuffle let you randomly select a card. (define shuffAux (lambda (t) (define cardR (lambda (t) (list-ref t (random 13)))) (cardR t))) ;auxilliary function used to remove the card after the car to prevent you from removing the randomly selected from the car(begining of the deck). (define (removeDupC card deck) (delete card (cdr deck)) ) (define shuffle2ndtry (lambda (deck seed) (define do-shuffle (lambda (deck seed) (if (> seed 0)( (cons (shuffAux deck) deck) (removeDupC (car deck) deck) (- 1 seed)) (write deck) ) ) ) (do-shuffle deck seed))) (define (shuffle deck seed) (define cards (cons (shuffAux deck) deck)) (write cards) (case (> seed 0) [(#t) (removeDupC (car cards) (cdr cards)) (shuffle cards (- seed 1))] [(#f) (write cards)])) (define random (let ((seed 0) (a 3141592653) (c 2718281829) (m (expt 2 35))) (lambda (limit) (cond ((and (integer? limit)) (set! seed (modulo (+ (* seed a) c) m)) (quotient (* seed limit) m)) (else (/ (* limit (random 34359738368)) 34359738368)))))) ;function in which you can delete an element from the list. (define delete (lambda (item list) (cond ((equal? item (car list)) (cdr list)) (else (cons (car list) (delete item (cdr list))))))) (

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  • C#: How to parse a hexadecimal digit

    - by Biosci3c
    Okay, I am working on a card playing program, and I am storing card values as hexadecimal digits. Here is the array: public int[] originalCards = new int[54] { 0x11, 0x12, 0x13, 0x14, 0x15, 0x16, 0x17, 0x18, 0x19, 0x1A, 0x1B, 0x1C, 0x1D, 0x21, 0x22, 0x23, 0x24, 0x25, 0x26, 0x27, 0x28, 0x29, 0x2A, 0x2B, 0x2C, 0x2D, 0x31, 0x32, 0x33, 0x34, 0x35, 0x36, 0x37, 0x38, 0x39, 0x3A, 0x3B, 0x3C, 0x3D, 0x41, 0x42, 0x43, 0x44, 0x45, 0x46, 0x47, 0x48, 0x49, 0x4A, 0x4B, 0x4C, 0x4D, 0x50, 0x51 }; The first digit refers to the suit (1 = spades; 2 = clubs; .... 5 = Jokers) The second digit is the number of the card (1 = ace, 5 = 5; 13 = K, etc). I would like to do something like the following: Pseudocode: public int ReturnCard(int num) { int card = currentDeck[num]; int suit = card.firsthexdigit; int value = card.secondhexdigit; return 0; } I don't need a new method to work on ints, I just included it for clarity's sake. Anybody know how to do this in C#?

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  • dealing cards in Clojure

    - by Ralph
    I am trying to write a Spider Solitaire player as an exercise in learning Clojure. I am trying to figure out how to deal the cards. I have created (with the help of stackoverflow), a shuffled sequence of 104 cards from two standard decks. Each card is represented as a (defstruct card :rank :suit :face-up) The tableau for Spider will be represented as follows: (defstruct tableau :stacks :complete) where :stacks is a vector of card vectors, 4 of which contain 5 cards face down and 1 card face up, and 6 of which contain 4 cards face down and 1 card face up, for a total of 54 cards, and :complete is an (initially) empty vector of completed sets of ace-king (represented as, for example, king-hearts, for printing purposes). The remainder of the undealt deck should be saved in a ref (def deck (ref seq)) During the game, a tableau may contain, for example: (struct-map tableau :stacks [[AH 2C KS ...] [6D QH JS ...] ... ] :complete [KC KS]) where "AH" is a card containing {:rank :ace :suit :hearts :face-up false}, etc. How can I write a function to deal the stacks and then save the remainder in the ref?

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  • TransactionRequiredException on OptimisticLockException

    - by João Madureira Pires
    Hi there. I have the following class that generates sequencial Card Numbers. I'm trying to recover from OptimisticLockException, by calling recursively the same method. however, i'm getting TransactionRequiredException. Dows anyone knows how to recover from OptimisticLockException in my case? Thanks a lot in advance @Name("simpleAutoIncrementGenerator") public class SimpleAutoIncrementGenerator extends CardNumberGenerator{ private static final long serialVersionUID = 2869548248468809665L; private int numberOfRetries = 0; @Override public String generateNextNumber(CardInstance cardInstance, EntityManager entityManager) { try{ EntityCard card = (EntityCard)entityManager.find(EntityCard.class, cardInstance.getId()); if(card != null){ String nextNumber = ""; String currentNumber = card.getCurrentCardNumber(); if(currentNumber != null && !currentNumber.isEmpty()){ Long numberToInc = Long.parseLong(currentNumber); numberToInc ++; nextNumber = String.valueOf(numberToInc); card.setCurrentCardNumber(nextNumber); // this is just to cause a OptimisticLock Exception try { Thread.sleep(4000); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } entityManager.persist(card); entityManager.flush(); return nextNumber; } } }catch (OptimisticLockException oLE) { System.out.println("\n\n\n\n OptimisticLockException \n\n\n\n"); if(numberOfRetries < CentralizedConfig.CARD_NUMBER_GENERATOR_MAX_TRIES){ numberOfRetries ++; return generateNextNumber(cardInstance,entityManager); } }catch (TransactionRequiredException trE) { System.out.println("\n\n\n\n TransactionRequiredException \n\n\n\n"); if(numberOfRetries < CentralizedConfig.CARD_NUMBER_GENERATOR_MAX_TRIES){ numberOfRetries ++; return generateNextNumber(cardInstance,entityManager); } }catch (StaleObjectStateException e) { System.out.println("\n\n\n\n StaleObjectStateException \n\n\n\n"); if(numberOfRetries < CentralizedConfig.CARD_NUMBER_GENERATOR_MAX_TRIES){ numberOfRetries ++; return generateNextNumber(cardInstance,entityManager); } } return null; } }

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  • Center DIV via jQuery

    - by tony noriega
    I have a footer that is fixed to the bottom of the viewport. I am using jQuery toggle to open a comment card for users to comment and submit: $('a#footer-comment').click(function() { $("#comment-card").toggle(300); return false; $('#comment-card').show({ position:); }); $('a#footer-comment-hide').click(function() { $("#comment-card").toggle(300); return false; $('#comment-card').hide(); }); naturally if i dont add any CSS selectors to #comment-card it shows up UNDER the footer, and out of sight. So i added: {position:absolute; bottom:30px; left:auto;} 30px so it shows up above the footer which is 30px high. Problem is, i can not get this to center in the viewport... if i use pixels, depending on the resolution, it is either too far left or right... how do i center this in the viewport?

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  • Sun Ray 3 Plus Appliance Announced

    - by [email protected]
    There were many of you out there wondering if Oracle was going to keep and add to the Sun Ray and Sun virtualized desktop product suite, there have been a number of affirmative statements over the last many months. However, none of them resound like this; the introduction of a new product pretty much proves the point. A couple minutes before 3:00, local time yesterday, Oracle announced the release of a new Sun Ray, appliance, the Sun Ray 3 Plus. This is the unit that will replace the SR 2 FS (which has been for sale now since the middle of last decade).  Physically it is about the same size as the 2 FS but there are some significant differences... As you can see there is no smart card reader in the front - that has moved to the top to ensure only one hand is required to insert the card.  There is also a larger surround on the card reader that lights up to show the user the card is being read (properly).  A new power on/off switch is on the front which essentially brings power consumption to ~0 watts, but there is also a new 'sleep' timer looking for 30 minutes of inactivity and then will drop the power consumption down to ~ 1watt. There are also 2 USB 2.0 ports are accessible on the front instead of one.  The standard mic in and headphone out ports are there as well.  There is even more interesting stuff on the back. From the top down there are two more USB 2.0 ports for a total of four, but then the Oracle "Peripheral Kit" keyboard includes a 3-port USB Hub, too.  There's a 10/100/1000 Ethernet port as well as a 1000 Mb SFP port.  Standard DB-9 Serial port and then two DVI ports.  Then there is the really big news.  Two DVI ports driving 2560 x 1600 resolution, each. Most PCs can't do that without adding an adapter card.Now the images I have here are ones taken on a prototype a couple months back.  They are essentially the same as the Production unit, but if you would like to see an image of the Production Sun Ray 3 Plus unit you can see one here. There is a full data sheet available here. So this is the first Oracle Sun Ray desktop appliance.  Proof that the product line lives on.  A very good start!

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  • Ubuntu Server and setting up two nic cards

    - by kmalik
    I have ubuntu server on a computer with a wireless and hardwired nic card. The wireless needs to get the internet and pass it to the ubuntu server as well as pass it along to the hardwired nic card to more computers. I am having issues getting the basic set up as I believe the route table is grabbing from the wrong nic card. The router is 192.168.1.0 and the server is set to 192.168.1.11 on the wireless card through DHCP ETH0 (wired nic card) is set up to be 10.10.10.0 and the server is 10.10.10.1) I am not a linux or networking guru but basically I am trying to have internet come from a guest network 192.168.1.0 i believe to give internet to the ubuntu server then the ubuntu server will also A) have the wired nic serve DHCP addresses to other computers via a switch or router (that acts as a switch) via 10.10.10.0 addresses. And I would love if it also passed along internet capabilities as well if possible. Bu really at this point my hope is to at least get the internet working on the server and the DHCP to pass correctly. At the moment the specific issue I am having is getting ubuntu server to connect to the internet and have both nic cards up and running correctly. Any help would be appreciated! The route table is as follows: Destination Gateway GM Flags Metric Iface 0.0.0.0 10.10.10.1 0.0.0.0 UG 100 eth0 10.10.10.0 0.0.0.0 255.255.255.0 U 0 eth0 169.254.0.0 0.0.0.0 255.255.0.0 U 0 eth0 1992.168.1.0 0.0.0.0 255.255.255.255.0 U 0 eth1 My interfaces is set up as follows: auto lo iface lo inet loopback auto eth0 iface eth0 inet static address 10.10.10.1 netmask 255.255.255.0 network 10.10.10.0 broadcast 10.10.10.255 gateway 10.10.10.1 domain-name-servers 192.168.1.0 auto eth1 iface eth1 inet dhcp netmask 255.255.255.0 gateway 192.168.1.0 wpa-driver wext wpa-ssid "ssid_name" wpa-ap-scan 1 wpa-proto wpa wpa-pairwise ccmp wpa-group ccmp wpa-key-mgmt wpa-psk wpa-psk "HASH" My DHCPD.conf (as there is a domain name server on here is as follows): ddns-update-style none default-lease-time 600 max-lease-time 7200 authoritative option domain-name "Kamron's Network" option subnet-mask 255.255.255.0 option broadcast-address 10.10.10.255 option routers 192.168.1.0 option domain-name-server 192.168.1.0 98.223.128.213 ooption subnet 10.10.10.0 netmask 255.255.255.0 { range 10.10.10.10 10.10.10.99 } log-facility local7

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  • Two interfaces with identical signatures

    - by corsiKa
    I am attempting to model a card game where cards have two important sets of features: The first is an effect. These are the changes to the game state that happen when you play the card. The interface for effect is as follows: boolean isPlayable(Player p, GameState gs); void play(Player p, GameState gs); And you could consider the card to be playable if and only if you can meet its cost and all its effects are playable. Like so: // in Card class boolean isPlayable(Player p, GameState gs) { if(p.resource < this.cost) return false; for(Effect e : this.effects) { if(!e.isPlayable(p,gs)) return false; } return true; } Okay, so far, pretty simple. The other set of features on the card are abilities. These abilities are changes to the game state that you can activate at-will. When coming up with the interface for these, I realized they needed a method for determining whether they can be activated or not, and a method for implementing the activation. It ends up being boolean isActivatable(Player p, GameState gs); void activate(Player p, GameState gs); And I realize that with the exception of calling it "activate" instead of "play", Ability and Effect have the exact same signature. Is it a bad thing to have multiple interfaces with an identical signature? Should I simply use one, and have two sets of the same interface? As so: Set<Effect> effects; Set<Effect> abilities; If so, what refactoring steps should I take down the road if they become non-identical (as more features are released), particularly if they're divergent (i.e. they both gain something the other shouldn't, as opposed to only one gaining and the other being a complete subset)? I'm particularly concerned that combining them will be non-sustainable as soon as something changes. The fine print: I recognize this question is spawned by game development, but I feel it's the sort of problem that could just as easily creep up in non-game development, particularly when trying to accommodate the business models of multiple clients in one application as happens with just about every project I've ever done with more than one business influence... Also, the snippets used are Java snippets, but this could just as easily apply to a multitude of object oriented languages.

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  • Java - Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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  • Draw Cards and Eliminate Cards Problem

    - by Jen
    I am having a problem in this question. I want a system inside a game wherein the player draws 2 cards randomly, and the enemy draws 2 cards randomly. Then, what the program does is to print out to the console the cards the player draw and the enemy's. The cards should not conflict and must not be the same. Then lastly, the program prints out the card that was not drawn by both the player and the enemy. Here's how I did it but it was lengthy and full of errors: import java.util.Random; public class Draw { public static Random random = new Random(); public static String cards[] = {"Hall", "Kitchen", "Billiard", "Study", "Pool"}; public static int playercounter; public static int enemycounter; public static String playercardA = null; public static String playercardB = null; public static String enemycardA = null; public static String enemycardB = null; public String lastcard = null; public static void playercardAdraw() { playercounter = random.nextInt(5); playercardA = cards[playercounter]; } public static void playercardBdraw() { playercounter=random.nextInt(5); playercardB= cards[playercounter]; if (playercardB==playercardA || playercardB == enemycardA || playercardB == enemycardB) { return; } } public static void enemycardAdraw () { enemycounter = random.nextInt(5); enemycardA=cards[enemycounter]; if (enemycardA == playercardA || enemycardA == playercardB) { return; } } public static void enemycardBdraw () { enemycounter = random.nextInt(5); enemycardB=cards[enemycounter]; if (enemycardB == playercardA || enemycardB == playercardB || enemycardB == enemycardA) { return; } } public static void main (String args []) { System.out.println("Starting to draw..."); System.out.println("Player's Turn: "); playercardAdraw(); System.out.println("Player's first card: " + playercardA); playercardBdraw(); System.out.println("Player's second card: " + playercardB); System.out.println("Enemy's Turn: "); enemycardAdraw(); System.out.println("Enemy's first card: " + enemycardA); enemycardBdraw(); System.out.println("Enemy's Second card: " + enemycardB); } }

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  • Using all Ten IO slots on a 7420

    - by user12620172
    So I had the opportunity recently to actually use up all ten slots in a clustered 7420 system. This actually uses 20 slots, or 22 if you count the clusteron card. I thought it was interesting enough to share here. This is at one of my clients here in southern California. You can see the picture below. We have four SAS HBAs instead of the usual two. This is becuase we wanted to split up the back-end taffic for different workloads. We have a set of disk trays coming from two SAS cards for nothing but Exadata backups. Then, we have a different set of disk trays coming off of the other two SAS cards for non-Exadata workloads, such as regular user file storage. We have 2 Infiniband cards which allow us to do a full mesh directly into the back of the nearby, production Exadata, specifically for fast backups and restores over IB. You can see a 3rd IB card here, which is going to be connected to a non-production Exadata for slower backups and restores from it.The 10Gig card is for client connectivity, allowing other, non-Exadata Oracle databases to make use of the many snapshots and clones that can now be created using the RMAN copies from the original production database coming off the Exadata. This allows for a good number of test and development Oracle databases to use these clones without effecting performance of the Exadata at all.We also have a couple FC HBAs, both for NDMP backups to an Oracle/StorageTek tape library and also for FC clients to come in and use some storage on the 7420.  Now, if you are adding more cards to your 7420, be aware of which cards you can place in which slots. See the bottom graphic just below the photo.  Note that the slots are numbered 0-4 for the first 5 cards, then the "C" slots which is the dedicated Cluster card (called the Clustron), and then another 5 slots numbered 5-9. Some rules for the slots: Slots 1 & 8 are automatically populated with the two default SAS cards. The only other slots you can add SAS cards to are 2 & 7. Slots 0 and 9 can only hold FC cards. Nothing else. So if you have four SAS cards, you are now down to only four more slots for your 10Gig and IB cards. Be sure not to waste one of these slots on a FC card, which can go into 0 or 9, instead.  If at all possible, slots should be populated in this order: 9, 0, 7, 2, 6, 3, 5, 4

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  • Windows Phone 7, taking the mobile out of mobile

    - by markritchie
    I’ll start off this blog entry with a little background which is necessary for you to understand my situation. I moved from to the UK to Germany about three years ago and while I can converse in German, English is still very much my first language and the language I want my content delivered in. I happily purchased a HTC HD7 when WP7 was released here in Germany thinking foolishly that Microsoft really would get internationalization and localization as it’s at the heart of their business and developer products. Overall I’m very happy with my WP7, the camera sucks but that’s more HTC’s fault that Microsoft, but other than that it’s a very promising platform. My problems started when I purchased my first app. Initially everything appeared to be fine and things were as smooth as things had been with my previous free applications, however about a month after I received an email from Zune informing me that the credit card that they had registered against my account had expired. No problem I foolishly thought; I’ll simply add a new one. I don’t want to bore you with the details of what I’ve been through other than to take the low-lights: trying numerous websites, posts on Microsoft Answers and a tweet to Microsoft Support all to no avail. Today somebody suggested that I call the Xbox support line in the UK as they had solved their billing problems this way. So I called up the Xbox support line since I hadn’t resolved the problem using the Zune portal to resolve my problem with my WP7 (anybody else thinks Microsoft might need some consolidation here). After being on the phone with a very friendly representative in Ireland I was informed that because my British credit card has a billing address in Germany they are unable to accept it as a credit card. Because my Live ID and Zune Tag are registered in the UK they cannot take my card. Their solution is that I have to create a new Zune Tag that has its locale in Germany and then associate it with my phone. Now, first thing I go to register for a Zune Tag with a German locale it very kindly switches into German for me, nothing quite like reading a EULA in a language you’re not fluent in. I’ve no idea how this will affect the apps that are available to me in the app store, and I’m pretty sure it means that all my Xbox live achievements will become history. And what if I was to move to say France at some point do I have to go through all this again? At the end of the day I’m trying to set something up so I can give them my money and they’re making it VERY difficult for me. Could you imagine walking into a book store when you were on holiday and being told by the clerk that they couldn’t take your credit card because you came from another country?

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  • graphics performance better on battery?

    - by Scott Beeson
    Anyone have any idea why my laptop would perform (considerably) better while on battery than while plugged in? It's a Dell Latitude E6420 with Windows 8 Pro. I tried mirroring all the settings in the selected power plan from "On battery" to "Plugged In" and that didn't help. I then just restored the defaults for all power plans (balanced and high performance). I'm still seeing the same results. The best example where it is most noticeable (don't laugh) is Sim City Social in Chrome. I'm probably seeing a performance increase of 5x on battery versus plugged in. This is easily reproducible too. I'm very confused. Could it be caused by dust? The laptop isn't that old and there is no visible dust. I'm not going to take it apart to check the insides as it's a corporate laptop. Could it be overheating? Battery Sim City Social: 68 degrees max Civ V: 77 degrees max Charger Sim City Social: 68 Civ V: did not test See answer below... I'm retarded

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  • validate uniqueness amongst multiple subclasses with Single Table Inheritance

    - by irkenInvader
    I have a Card model that has many Sets and a Set model that has many Cards through a Membership model: class Card < ActiveRecord::Base has_many :memberships has_many :sets, :through => :memberships end class Membership < ActiveRecord::Base belongs_to :card belongs_to :set validates_uniqueness_of :card_id, :scope => :set_id end class Set < ActiveRecord::Base has_many :memberships has_many :cards, :through => :memberships validates_presence_of :cards end I also have some sub-classes of the above using Single Table Inheritance: class FooCard < Card end class BarCard < Card end and class Expansion < Set end class GameSet < Set validates_size_of :cards, :is => 10 end All of the above is working as I intend. What I'm trying to figure out is how to validate that a Card can only belong to a single Expansion. I want the following to be invalid: some_cards = FooCard.all( :limit => 25 ) first_expansion = Expansion.new second_expansion = Expansion.new first_expansion.cards = some_cards second_expansion.cards = some_cards first_expansion.save # Valid second_expansion.save # **Should be invalid** However, GameSets should allow this behavior: other_cards = FooCard.all( :limit => 10 ) first_set = GameSet.new second_set = GameSet.new first_set.cards = other_cards # Valid second_set.cards = other_cards # Also valid I'm guessing that a validates_uniqueness_of call is needed somewhere, but I'm not sure where to put it. Any suggestions? UPDATE 1 I modified the Expansion class as sugested: class Expansion < Set validate :validates_uniqueness_of_cards def validates_uniqueness_of_cards membership = Membership.find( :first, :include => :set, :conditions => [ "card_id IN (?) AND sets.type = ?", self.cards.map(&:id), "Expansion" ] ) errors.add_to_base("a Card can only belong to a single Expansion") unless membership.nil? end end This works when creating initial expansions to validate that no current expansions contain the cards. However, this (falsely) invalidates future updates to the expansion with new cards. In other words: old_exp = Expansion.find(1) old_exp.card_ids # returns [1,2,3,4,5] new_exp = Expansion.new new_exp.card_ids = [6,7,8,9,10] new_exp.save # returns true new_exp.card_ids << [11,12] # no other Expansion contains these cards new_exp.valid? # returns false ... SHOULD be true

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  • Does enabling SMB2 on a NetApp filer require a cifs restart?

    - by Sim
    I would like to enable SMB2 on a FAS 2050 running Data ONTAP 7.3.2 as by default it is disabled. I have discovered that to enable SMB2 the following option must be set: options cifs.smb2.client.enable on Does this require a restart of cifs to take affect or just does it start working magically? Also will this change persist across a reboot?

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