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  • Beginner MYSQL Error - Access Denied

    - by WANNABE
    ERROR 1045 (28000): Access denied for user 'root'@'localhost' (using password: N O) I've tried EVERYTHING, I've read through pages of answers and no-one seems to know the right one. When i try to log into my DB i just get the above error, I havent set a password or anything. Can't log into MySQL at all now, don't understand. Thanks for your help in advance

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  • Scripts fail when jQuery.js isn't cached. When cached, scripts run fine.

    - by Bob
    I have jQuery UI Tabs which load their content via AJAX. About once every 15 times when the entire page is loaded (not just XHR), things fail and I don't see the proper content in the tab. Fiddler showed me that when things fail I also see that jQuery.js and jQuery-ui.js are both sent to the browser in full (~100kB). Normally, a page load results in HTTP status code 304 for both of those files, they're not re-downloaded, and the page displays properly. When the status code is 200 and fresh copies of jQuery/UI are sent, things fail. I notice this most often in IE8, but that's because I use it for web development. I have seen it in Firefox, but for some reason I can't reproduce it now. Fiddler shows that the HTTP request asks for: GET /Scripts/jquery-1.3.2.min.js?_=1255309685187 HTTP/1.1 I can't figure out what the ?_=1255309685187 is for, but I'm guessing it's a token to indicate for how long the file should be cached. Since I can't reproduce the problem in Firefox right now, I don't know what Firebug says. Any insight would be appreciated. EDIT: This is with Visual Studio's development webserver.

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  • Symfony2 Forms: is it possible to bind a form in an "unconventional way"?

    - by DonCallisto
    Imagine this scenario: in our company there is an employee that "play" around graphic,css,html and so on. Our new project will born under symfony2 so we're trying some silly - but "real" - stuff (like authentication from db, submit data from a form and persist it to db and so on..) The problem As far i know, learnt from symfony2 "book" that i found on the site (you can find it here), there is an "automated" way for creating and rendering forms: 1) Build the form up into a controller in this way $form = $this->createFormBuilder($task) ->add('task','text'), ->add('dueDate','date'), ->getForm(); return $this->render('pathToBundle:Controller:templateTwig', array('form'=>$form->createview()); 2) Into templateTwig render the template {{ form_widget(form) }} // or single rows method 3) Into a controller (the same that have a route where you can submit data), take back submitted information if($rquest->getMethod()=='POST'){ $form->bindRequest($request); /* and so on */ } Return to scenario Our graphic employee don't want to access controllers, write php and other stuff like those. So he'll write a twig template with a "unconventional" (from symfony2 point of view, but conventional from HTML point of view) method: /* into twig template */ <form action="{{ path('SestanteUserBundle_homepage') }}" method="post" name="userForm"> <div> USERNAME: <input type="text" name="user_name" value="{{ user.username}}"/> </div> <div> EMAIL: <input type="text" name="user_mail" value="{{ user.email }}"/> </div> <input type="hidden" name="user_id" value="{{ id }}" /> <input type="submit" value="modifica i dati"> </form> Now, if into the controller that handle the submission of data we do something like that public function indexAction(Request $request) { if($request->getMethod() == 'POST'){ // sono arrivato per via di un submit, quindi devo modificare i dati prima di farli vedere a video $defaultData = array('message'=>'ho visto questa cosa in esempio, ma non capisco se posso farne a meno'); $form = $this->createFormBuilder($defaultData) ->add('user_name','text') ->add('user_mail','email') ->add('user_id','integer') ->getForm(); $form->bindRequest($request); //bindo la form ad una request $data = $form->getData(); //mi aspetto un'array chiave=>valore /* .... */ We expected that $data will contain an array with key,value from the submitted form. We found that it isn't true. After googling for a while and try with other "bad" ideas, we're frozen into that. So, if you have a "graphic office" that can't handle directly php code, how can we interface from form(s) to controller(s) ? UPDATE It seems that Symfony2 use a different convention for form's field name and lookup once you've submitted that. In particular, if my form's name is addUser and a field is named userName, the field's name will be AddUser[username] so maybe it have a "dynamic" lookup method that will extract form's name, field's name, concat them and lookup for values. Is it possible?

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  • Custom Android control with children

    - by Gromix
    Hi, I'm trying to create a custom Android control that contains a LinearLayout. You can think of it as an extended LinearLayout with fancy borders, a background, an image on the left... I could do it all in XML (works great) but since I have dozens of occurences in my app it's getting hard to maintain. I thought it would be nicer to have something like this: /* Main.xml */ <MyFancyLayout> <TextView /> /* what goes inside my control's linear layout */ </MyfancyLayout> How would you approach this? I'd like to avoid re-writing the whole linear layout onMeasure / onLayout methods. This is what I have for the moment: /* MyFancyLayout.xml */ <TableLayout> <ImageView /> <LinearLayout id="container" /> /* where I want the real content to go */ </TableLayout> and /* MyFancyLayout.java */ public class MyFancyLayout extends LinearLayout { public MyFancyLayout(Context context) { super(context); View.inflate(context, R.layout.my_fancy_layout, this); } } How would you go about inserting the user-specified content (the TextView in main.xml) in the right place (id=container)? Cheers! Romain ----- edit ------- Still no luck on this, so I changed my design to use a simpler layout and decided to live with a bit of repeated XML. Still very interested in anyone knows how to do this though!

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  • Implementation problem. Htaccess in php

    - by Irwan
    I have a problem to fix the URL on my website at http://www.abelputra.com I need a solution: I want to change www.abelputra.com/software.php into www.abelputra.com/software I have read a tutorial like this: For .htaccess: RewriteEngine On RewriteRule ^ ([a-zA-Z0-9_-] +) $ index.php? Key = $ 1 RewriteRule ^ ([a-zA-Z0-9_-]+)/$ index.php? Key = $ 1 Then in php: index.php --- $Key=$ _GET ['key']; if ($key == 'home') { include ('index.php'); // Home page } else if ($ key == 'software') { include ('software.php'); // } else if ($ key == 'webdesign') { include ('webdesign.php'); // } The problem is: When I implemented the menu software.php index.php to call the page: www.abelputra.com/index.php?key=software what happens is the page that is shown is two pages later software.php index.php page underneath. Is it because calling functions "include ()"? index.php structures: Header Content - contains the opening words Footer software.php structure: Header Content - contains an explanation of my software Footer Sorry my english bad. im from Indonesia. Please solution .. thanks

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  • How do I add mouseClicked event to a swing table?

    - by Ayelet
    Hi, I am a new, terribly green user of Swing. I managed to create a table class using examples from java.sun tutorials, and I managed to load data dynamically into it. I want to be able to react to a click on a row by displaying a dialog box. How do I add the event Handler that will identify the selected row number? The main function code: public static void main(String[] args) { javax.swing.SwingUtilities.invokeLater(new Runnable() { public void run() { try { MainWindow window = new MainWindow(); window.frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); //Create and set up the content pane. createAndShowGUI(); //... and: private static void createAndShowGUI() { //Create and set up the window. JFrame frame = new JFrame("Data Table"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); //Create and set up data of the content pane. TableClass mainTable = new TableClass(fh.getColNames(), fh.getTableContent()); mainTable.setOpaque(true); frame.setContentPane(mainTable); //Display the window. frame.pack(); frame.setVisible(true); } Thank you

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  • Good Database with C library?

    - by Mohit Deshpande
    What is a good database with support for C? I want a database that can persist changes when the program is closing and retrieve them when the user starts up the program. I was thinking maybe like SQLite or Berkeley DB. Some documentation would be great too.

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  • Codeigniter not returning me to upload form after image upload.

    - by Drew
    I'm still very new to codeigniter. The issue i'm having is that the file uploads fine and it writes to the database without issue but it just doesn't return me to the upload form. Instead it stays in the do_upload and doesn't display anything. Even more bizarrely there is some source code behind the scenes. Can someone tell my what it is i'm doing wrong because I want to be returning to my upload form after submission. Thanks in advance. Below is my code: Controller: function do_upload() { if($this->Upload_model->do_upload()) { $this->load->view('home/upload_form'); }else{ $this->load->view('home/upload_success', $error); } } Model: function do_upload() { $config['upload_path'] = './uploads/'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '2000'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $data = $this->upload->data(); $full_path = 'uploads/' . $data['file_name']; $spam = array( 'image_url' => $full_path, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } View (called upload_form): <html> <head> <title>Upload Form</title> </head> <body> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->image_url; ?></h2> <p><?php echo $row->url; ?></p> <p><?php echo $row->name; ?></p> <p><?php echo anchor("upload/update_nav/$row->id", 'edit'); ?></p> <?php endforeach; ?> <?php endif; ?> </body> </html>

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  • SugarmCRM REST API always returns "null"

    - by TuomasR
    I'm trying to test out the SugarCRM REST API, running latest version of CE (6.0.1). It seems that whenever I do a query, the API returns "null", nothing else. If I omit the parameters, then the API returns the API description (which the documentation says it should). I'm trying to perform a login, passing as parameter the method (login), input_type and response_type (json) and rest_data (JSON encoded parameters). The following code does the query: $api_target = "http://example.com/sugarcrm/service/v2/rest.php"; $parameters = json_encode(array( "user_auth" => array( "user_name" => "admin", "password" => md5("adminpassword"), ), "application_name" => "Test", "name_value_list" => array(), )); $postData = http_build_query(array( "method" => "login", "input_type" => "json", "response_type" => "json", "rest_data" => $parameters )); echo $parameters . "\n"; echo $postData . "\n"; echo file_get_contents($api_target, false, stream_context_create(array( "http" => array( "method" => "POST", "header" => "Content-Type: application/x-www-form-urlencoded\r\n", "content" => $postData ) ))) . "\n"; I've tried different variations of parameters and using username instead of user_name, and all provide the same result, just a response "null" and that's it.

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  • Move database from sql server 2008 to 2005

    - by pencilslate
    I have a database currently in SQL Server 2008 to be moved to SQL Server 2005. I would like to backup the 2008 db to a bak file and import it to 2005, but couldn't find any options in SSMS 2008 while taking backup. Has anyone had a similar need in the past? How did you manage this through?

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  • How to retrieve last primary Id from mdb's table?

    - by William
    I got table with next columns: Id, Name, Age, Class I am trying to insert new row in db like this: INSERT INTO MyTable (Name, Age, Class) VALUES (@name, @age, @class) And get an exeption: "Index or primary key cannot contain a Null value." The question is how to add a new row without knowing next primary Id, or maybe there is a way to get this Id from the table with the help of another query ?

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  • Have to click twice to submit the form

    - by phil
    Intended function: require user to select an option from the drop down menu. After user clicks submit button, validate if an option is selected. Display error message and not submit the form if user fails to select. Otherwise submit the form. Problem: After select an option, button has to be clicked twice to submit the form. I have no clue at all.. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <style> p{display: none;} </style> </head> <script> $(function(){ // language as an array var language=['Arabic','Cantonese','Chinese','English','French','German','Greek','Hebrew','Hindi','Italian','Japanese','Korean','Malay','Polish','Portuguese','Russian','Spanish','Thai','Turkish','Urdu','Vietnamese']; $('#muyu').append('<option value=0>Select</option>'); //loop through array for (i in language) //js unique statement for iterate array { $('#muyu').append($('<option>',{id:'muyu'+i,val:language[i], html:language[i]})) } $('form').submit(function(){ alert('I am being called!'); // check if submit event is triggered if ( $('#muyu').val()==0 ) {$('#muyu_error').show(); } else {$('#muyu_error').hide(); return true;} return false; }) }) </script> <form method="post" action="match.php"> I am fluent in <select name='muyu' id='muyu'></select> <p id='muyu_error'>Tell us your native language</p> <input type="submit" value="Go"> </form>

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  • javascript check function for a html form

    - by Reteras Remus
    I'm having a problem with a HTML form (name, e-mail, subject, message), I can't validate the form if it was completed correct or not. I want to call a javascript function when the form is submitted and alert if a field wasn't completed correct. My problem is with the submit button, because my boss said that I must use he's own php function to insert a submit button. The php function looke like: function normal_button($text, $width, $param = '', $class = 'button-blue') { $content = '<div class="'.$class.'" style="width:'.$width.'px;" '.$param.'>'.$text.'</div>'; return $content; } and how I call the function: echo normal_button('Send it', '100', 'onclick="document.getElementById(\'emailForm\').submit();" '); I tried to call the js function declaring the onSubmit="return checkForm(this)" in the <form action='email.php' method='post'> HTML form, but I can't "catch" the submit. Also I tried to catch it with jquery, $(document).ready(function() { $('.normal_button').click(function() { }); ); but I can't return false if a field wasn't completed correct. I must use he's PHP function to insert the submit button, but how can I "catch" the fields, how can I validate them? Any suggestions? Thank you !

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  • iphone sqlite app startup issues

    - by Futur
    Hi All, I have 4 database catalogues in my app, i will be switching the four catalogues. When i start the app, i read the NSUserDefaults and try to load the default catalogue in the memory, but in the first time this doesnt happen. Instead i get null values returned first time just because the DB connection is not successful for some unknown reason, the debugger is unable to go there too. But the app starts up the next time, the values are fetched successfully. Please help

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  • Creating a Web Service to automatically get information

    - by Sean P
    I want to create some sort of method of creating a web service that will run automatically and run DB queries and some API calls which will then store data that I can use/call without taking the processing or time penalty of doing it every time a user access my web service. Is this possible? If so, point me in the right direction on how to implement something like this Using vb.net and ASP.net Thanks in advance!!

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  • Where should I keep my log files?

    - by ripper234
    We keep most of our logs in a dedicated database table. We have written custom appenders for log4j and log4net, have a fixed log schema with lots of handy columns, and are quite happy with it. Is that the "best practice" (for sites smaller in scale than Facebook, where a simple DB table just won't scale)?

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  • Serializable object in intent returning as String

    - by B_
    In my application, I am trying to pass a serializable object through an intent to another activity. The intent is not entirely created by me, it is created and passed through a search suggestion. In the content provider for the search suggestion, the object is created and placed in the SUGGEST_COLUMN_INTENT_EXTRA_DATA column of the MatrixCursor. However, when in the receiving activity I call getIntent().getSerializableExtra(SearchManager.EXTRA_DATA_KEY), the returned object is of type String and I cannot cast it into the original object class. I tried making a parcelable wrapper for my object that calls out.writeSerializable(...) and use that instead but the same thing happened. The string that is returned is like a generic Object toString(), i.e. com.foo.yak.MyAwesomeClass@4350058, so I'm assuming that toString() is being called somewhere where I have no control. Hopefully I'm just missing something simple. Thanks for the help! Edit: Some of my code This is in the content provider that acts as the search authority: //These are the search suggestion columns private static final String[] COLUMNS = { "_id", // mandatory column SearchManager.SUGGEST_COLUMN_TEXT_1, SearchManager.SUGGEST_COLUMN_INTENT_EXTRA_DATA }; //This places the serializable or parcelable object (and other info) into the search suggestion private Cursor getSuggestions(String query, String[] projection) { List<Widget> widgets = WidgetLoader.getMatches(query); MatrixCursor cursor = new MatrixCursor(COLUMNS); for (Widget w : widgets) { cursor.addRow(new Object[] { w.id w.name w.data //This is the MyAwesomeClass object I'm trying to pass }); } return cursor; } This is in the activity that receives the search suggestion: public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); Object extra = getIntent().getSerializableExtra(SearchManager.EXTRA_DATA_KEY); //extra.getClass() returns String, when it should return MyAwesomeClass, so this next line throws a ClassCastException and causes a crash MyAwesomeClass mac = (MyAwesomeClass)extra; ... }

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  • jquery closest dl element

    - by Sebastiaan
    HTML: <dl id="feature-list"> <dt id="basic" class="category-name"> <dd id="basic-toggle" class="category-recepient"> <div class="feature"> <div class="feature-content"> <input id="checkbox1" type="checkbox"> </div> </div> </dd> <dt id="options" class="category-name"> <dd id="options-toggle" class="category-recepient"> <div class="feature"> <div class="feature-content"> <input id="checkbox2" type="checkbox"> </div> </div> </dd> </dl> JQUERY $('input').change(function () { var value = $(this).closest("dt"); //do something with value.id }); $(this).closest("dt") returns the checkbox instead of <dt id="(category)" class="category-name"> I tried $(this).closest(.category-name), $(this).closest("dt").find(.category-name)

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  • invalid postback event instead of dropdown to datagrid

    - by rima
    I faced with funny situation. I created a page which is having some value, I set these value and control my post back event also. The problem is happening when I change a component index(ex reselect a combobox which is not inside my datagrid) then I dont know why without my page call the Page_Load it goes to create a new row in grid function and all of my parameter are null! I am just receiving null exception. So in other word I try to explain the situation: when I load my page I am initializing some parameter. then everything is working fine. in my page when I change selected item of my combo box, page suppose to go and run function related to that combo box, and call page_load, but it is not going there and it goes to rowcreated function. I am trying to illustrate part of my page. Please help me because I am not receiving any error except null exception and it triger wrong even which seems so complicated for me. public partial class W_CM_FRM_02 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if (Page.IsPostBack && !loginFail) return; InitializeItems(); } } private void InitializeItems() { cols = new string[] { "v_classification_code", "v_classification_name" }; arrlstCMMM_CLASSIFICATION = (ArrayList)db.Select(cols, "CMMM_CLASSIFICATION", "v_classification_code <> 'N'", " ORDER BY v_classification_name"); } } protected void DGV_RFA_DETAILS_RowCreated(object sender, GridViewRowEventArgs e) { //db = (Database)Session["oCon"]; foreach (DataRow dr in arrlstCMMM_CLASSIFICATION) ((DropDownList)DGV_RFA_DETAILS.Rows[index].Cells[4].FindControl("OV_RFA_CLASSIFICATION")).Items.Add(new ListItem(dr["v_classification_name"].ToString(), dr["v_classification_code"].ToString())); } protected void V_CUSTOMER_SelectedIndexChanged(object sender, EventArgs e) { if (V_CUSTOMER.SelectedValue == "xxx" || V_CUSTOMER.SelectedValue == "ddd") V_IMPACTED_FUNCTIONS.Enabled = true; } } my form: <%@ Page Language="C#" MasterPageFile="~/MasterPage.master" AutoEventWireup="true" CodeFile="W_CM_FRM_02.aspx.cs" Inherits="W_CM_FRM_02" Title="W_CM_FRM_02" enableeventvalidation="false" EnableViewState="true"%> <td>Project name*</td> <td><asp:DropDownList ID="V_CUSTOMER" runat="server" AutoPostBack="True" onselectedindexchanged="V_CUSTOMER_SelectedIndexChanged" /></td> <td colspan = "8"> <asp:GridView ID="DGV_RFA_DETAILS" runat="server" ShowFooter="True" AutoGenerateColumns="False" CellPadding="1" ForeColor="#333333" GridLines="None" OnRowDeleting="grvRFADetails_RowDeleting" Width="100%" Style="text-align: left" onrowcreated="DGV_RFA_DETAILS_RowCreated"> <RowStyle BackColor="#FFFBD6" ForeColor="#333333" /> <Columns> <asp:BoundField DataField="ON_RowNumber" HeaderText="SNo" /> <asp:TemplateField HeaderText="RFA/RAD/Ticket No*"> <ItemTemplate> <asp:TextBox ID="OV_RFA_NO" runat="server" Width="120"></asp:TextBox> </ItemTemplate> </asp:TemplateField>

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  • Oracle join query

    - by Jasim
    There are three tables in my db ITEM_MASTER, PRICE_MASTER, COMP_MASTER ITEM_MASTER STORE_CODE ITEM_CODE ITEM_DESC 011 914004 desccc PRICE_MASTER STORE_CODE ITEM_CODE COMP_CODE 011 914004 01 011 914004 02 011 914004 03 011 914004 04 COMP_MASTER COMP_CODE COMP_DESC STORE_CODE 01 comp1 011 02 comp2 011 03 comp3 011 04 comp4 011 I want to get all these for an ITEM_CODE in single query STORE_CODE ITEM_CODE ITEM_DESC COMP_DESC1 COMP_DESC2 COMP_DESC3 COMP_DESC4 011 914004 desccc comp1 comp2 comp3 comp4 How can i write a oracle SQL query for this??

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  • once again..."$ is not defined" - trying to implement sIFR

    - by supervision
    Hey Guys, my file beginning looks like this: <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>My title</title> <link rel="stylesheet" type="text/css" href="css/style.css" /> <script src="js/update.js" type="text/javascript"></script> <!-- sifr --> <link href="sifr207/sIFR-screen.css" rel="stylesheet" type="text/css" media="screen" /> <script src="sifr207/sifr.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function() { if(typeof sIFR == "function") { sIFR.replaceElement("sifr", named({sFlashSrc: "sIFR-2.0.7/corporateacon-reg.swf", sColor: "#FF0000" , sWmode: "transparent"})); }; }); </script> <!-- --> </head> I really do not understand why the '$(document).ready(function()' is not found, because I implement sifr.js BEFORE that call. Any suggestions? I would appriciate it, really! shoutz, supervision

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