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  • How to validate and entry on a datagrid that is bound to an adapter

    - by Ziv
    Hi, I've been using C# for a while and began a program now to learn WPF-which means I know almost nothing of it. I used this tutorial as a guide to do what I wanted to do (which is binding a database to a datagrid), after a hard struggle to add the adapter as the source of the datagrid I now want to enable editing with validation on some of the cells. My problem is that the data is sent straight from the adapter and not through an object collection (I had a hard time getting to this situation, see the first half of the tutorial on how to bind the adapter and dataset through the resources) but the tutorial doesn't show a way to validate the datagrid if the data is sent through an adapter-only through a collection. To make it clear-how do I validate input in a datagrid that is bound to an adapter through a resource? The relevant code: (XAML) <Window.Resources> <ObjectDataProvider x:Key="DiscsDataProvider" ObjectType="{x:Type local:DiscsDataProvider}" /> <ObjectDataProvider x:Key="Discs" ObjectInstance="{StaticResource ResourceKey=DiscsDataProvider}" MethodName="GetDiscs" /> <Style x:Key="CellEditStyle" TargetType="{x:Type TextBox}"> <Setter Property="BorderThickness" Value="0"/> <Setter Property="Padding" Value="0"/> <Setter Property="Background" Value="Yellow"/> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors)[0].ErrorContent}"/> </Trigger> </Style.Triggers> </Style> </Window.Resources> For the datagrid: <Grid Width="auto" Height="auto"> <DockPanel DataContext="{Binding Source={StaticResource ResourceKey=Discs}}"> <DataGrid Margin="12,0,0,12" Name="View_dg" HorizontalAlignment="Left" Width="533" Height="262" VerticalAlignment="Bottom" ItemsSource="{Binding}" AutoGenerateColumns="False" CanUserAddRows="False" CanUserDeleteRows="False" CanUserResizeColumns="True"> <DataGrid.Columns> <DataGridTextColumn Binding="{Binding Path=ContainerID}" CanUserReorder="False" CanUserResize="True" CanUserSort="True" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="False" Header="Container" /> <DataGridTextColumn Binding="{Binding Path=ID}" CanUserReorder="False" CanUserResize="True" CanUserSort="True" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="True" Header="ID" /> <DataGridTextColumn Binding="{Binding Path=Title}" CanUserReorder="False" CanUserResize="True" CanUserSort="True" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="False" Header="Title" /> <DataGridTextColumn Binding="{Binding Path=SubTitle}" CanUserReorder="False" CanUserResize="True" CanUserSort="False" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="False" Header="Sub Title" /> <DataGridTextColumn Binding="{Binding Path=Type}" CanUserReorder="False" CanUserResize="True" CanUserSort="True" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="False" Header="Type" /> <DataGridTextColumn Binding="{Binding Path=Volume}" CanUserReorder="False" CanUserResize="True" CanUserSort="False" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="False" Header="Volume" /> <DataGridTextColumn Binding="{Binding Path=TotalDiscs}" CanUserReorder="False" CanUserResize="True" CanUserSort="False" EditingElementStyle="{StaticResource CellEditStyle}" IsReadOnly="False" Header="Total Discs" /> </DataGrid.Columns> </DataGrid> </DockPanel> and C#: public class DiscsDataProvider { private DiscsTableAdapter adapter; private DB dataset; public DiscsDataProvider() { dataset = new DB(); adapter = new DiscsTableAdapter(); adapter.Fill(dataset.Discs); } public DataView GetDiscs() { return dataset.Discs.DefaultView; } }

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  • How can I open VLC via browser with PHP (Mac OS X)

    - by Damiqib
    I'm trying to open VLC via browser and make it instantly play the given video file on Mac OS X. This runs on my local server and is only meant to run locally - therefore I already run apache (MAMP) with my username and with group "staff" (defined in httpd.conf). YES - I do know that VLC has http interface - however that is not what I need, so do not suggest that... My current system works without any problems when I run it via Terminal: php /var/www/Movies/index.php - This leads to VLC opening and video starts playing fullscreen like intented. Problems start when I run the same PHP-page with browser. Then the VLC-process starts, but there's no GUI for it, video file won't start playing and the VLC-process takes nearly 100% of CPU. Both; terminal and browser started VLC-processes run with the same user (mine) Both have "Parent process" bash VLC-process begun with Terminal has empty "Process group" (only process id-number) and browser started has "httpd" + (id-number) VLC-process started via browser makes 1000-times more "Mach System Calls" than it's Terminal-started counterpart. Could anyone give me any pointers on how to get this thing working? index.php # $j is a file path to the videofile and is defined before exec('/var/www/Movies/vlc.sh "' . $j . '" > /dev/null 2>&1 & echo $!;'); # If I do this in the given PHP-page it tells me that apache is running # with my username and with the group "staff" like it should be... exec('whoamI'); vlc.sh #!/bin/bash # Activate VLC in 5 seconds to make it the front-most window (sleep 5; open -a VLC) & # Open video file /Applications/VLC.app/Contents/MacOS/VLC --quiet --fullscreen "$1"

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  • ASP.NET MVC 2 DisplayFor()

    - by ZombieSheep
    I'm looking at the new version of ASP.NET MVC (see here for more details if you haven't seen it already) and I'm having some pretty basic trouble displaying the content of an object. In my control I have an object of type "Person", which I am passing to the view in ViewData.Model. All is well so far, and I can extact the object in the view ready for display. What I don't get, though, is how I need to call the Html.DisplayFor() method in order to get the data to screen. I've tried the following... <% MVC2test.Models.Person p = ViewData.Model as MVC2test.Models.Person; %> // snip <%= Html.DisplayFor(p => p) %> but I get the following message: CS0136: A local variable named 'p' cannot be declared in this scope because it would give a different meaning to 'p', which is already used in a 'parent or current' scope to denote something else I know this is not what I should be doing - I know that redefining a variable will producte this error, but I don't know how to access the object from the controller. So my question is, how do I pass the object to the view in order to display its properties? (I should add that I am reading up on this in my limited spare time, so it is entirely possible I have missed something fundamental) TIA

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  • mysql prevent displaying a row ONE which has reference in another row TWO but no reference in row THREE

    - by Jayapal Chandran
    I have a table like the following id | name | pid 1 | sam | NULL 2 | sams ref | 1 3 | pam | NULL For the first time the first row gets inserted which will have pid as null I insert a row which is related to the first row and then i insert a row which is new and which may be referred by another row in future. now i want only the third row to be displayed and not the first and second row as the second row contains the reference of first row. so if any row has a reference to another row then both the rows should not be displayed. Only rows which is not having any reference should be displayed. BESIDES, IS IT A GOOD PRACTICE? PLEASE ADVICE ON THIS. Edited When i updated in server the query is always giving empty result. here is what i have and this one When pid is NULL then that row should appear but when another entry in the same table with pid as its parent id or any other rows id appears then both the rows should not appear. so if any pid has been referred then both the rows should not appear. here only one row will refer another row and not more than that. in my localhost i have mysql version 5.0.1 or something like that but when i installed xampp in another system it had 5.5 and in the live server it was 5.3 so in version around 5.0 the query is returning rows but in higher versions it is returning empty rows. so now i this case how to make a query?

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  • CI+JQuery+Ajax problem

    - by Sadat
    Calling the ajax called URL works well without ajax eg. http://localhost/ci/controller/method/param_value. But using ajax it doesnt work. Following are the code segment, i have just started with JQuery+Ajax with CI. Here is my controller: <?php class BaseController extends Controller{ public function BaseController(){ parent::Controller(); $this->load->helper('url'); } function index(){ $this->load->view('header'); $this->load->view('body'); $this->load->view('footer'); } function ajaxTest($testData=""){ $this->load->view('ajaxtest',array('test_data'=>$testData)); } } ? Here is View <?php echo $test_data; ? Ajax Call Function function testAjaxCall(){ $.get( base_url+'basecontroller/ajaxtest/test-value', function(responseData) { $("#test-div").html(responseData); } ); } Ajax Calling Page(button) <div id="test-div"></div><input type="button" onclick="testAjaxCall()" name="ajax-test" value="Test Ajax" /> JS base_url declaration <script type="text/javascript" src="<?php echo base_url();?>js/jquery.js"></script> <script type="text/javascript" src="<?php echo base_url();?>js/application-ajax-call.js"></script> <script type="text/javascript"> /* to make ajax call easy */ base_url = '<?php echo base_url();?>'; </script>

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  • JSON Serialization of a Django inherited model

    - by Simon Morris
    Hello, I have the following Django models class ConfigurationItem(models.Model): path = models.CharField('Path', max_length=1024) name = models.CharField('Name', max_length=1024, blank=True) description = models.CharField('Description', max_length=1024, blank=True) active = models.BooleanField('Active', default=True) is_leaf = models.BooleanField('Is a Leaf item', default=True) class Location(ConfigurationItem): address = models.CharField(max_length=1024, blank=True) phoneNumber = models.CharField(max_length=255, blank=True) url = models.URLField(blank=True) read_acl = models.ManyToManyField(Group, default=None) write_acl = models.ManyToManyField(Group, default=None) alert_group= models.EmailField(blank=True) The full model file is here if it helps. You can see that Company is a child class of ConfigurationItem. I'm trying to use JSON serialization using either the django.core.serializers.serializer or the WadofStuff serializer. Both serializers give me the same problem... >>> from cmdb.models import * >>> from django.core import serializers >>> serializers.serialize('json', [ ConfigurationItem.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.configurationitem", "fields": {"is_leaf": true, "extension_attribute_10": "", "name": "", "date_modified": "2010-05-19 14:42:53", "extension_attribute_11": false, "extension_attribute_5": "", "extension_attribute_2": "", "extension_attribute_3": "", "extension_attribute_1": "", "extension_attribute_6": "", "extension_attribute_7": "", "extension_attribute_4": "", "date_created": "2010-05-19 14:42:53", "active": true, "path": "/Locations/London", "extension_attribute_8": "", "extension_attribute_9": "", "description": ""}}]' >>> serializers.serialize('json', [ Location.objects.get(id=7)]) '[{"pk": 7, "model": "cmdb.location", "fields": {"write_acl": [], "url": "", "phoneNumber": "", "address": "", "read_acl": [], "alert_group": ""}}]' >>> The problem is that serializing the Company model only gives me the fields directly associated with that model, not the fields from it's parent object. Is there a way of altering this behaviour or should I be looking at building a dictionary of objects and using simplejson to format the output? Thanks in advance ~sm

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  • C sharp code cleanup : resharper

    - by Ankit Rathod
    Hello, I just used Resharper in one application and it made me feel as if i don't know how to code at all in C# :(. On every line it gave me it's suggestions :- Few of Resharper's favorite suggestions are :- 1) SomObject o = new SomeObject(); Resharper will convert to : var o = new SomeObject() 2) this.Loaded += new RoutedEventHandler(MainPage_Loaded); to this.Loaded += MainPage_Loaded; 3) convert my variables and putting _ in front of all instance variables. 4) Removing class parent's name. I tested this on Silverlight. public partial class MainPage : UserControl to public partial class MainPage EDIT :- 5) replace instance variable this.variable = somevalue to variable = somevalue Are all of these really necessary? Is it really going to affect the efficiency of my program? I mean what good is it going to do by replacing my class names with var keyword. After all var is also replaced with class name at compile time. Is it doing because it has been programmed to do or do these things really affect in some or another way? Thanks in advance :)

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  • Asp.net MVC error with custom HttpModule

    - by Robert Koritnik
    I have a custom authentication HttpModule that is pretty strait forward. But I want it to run only for managed requests (and not for static ones). Asp.net MVC automatically adds configuration section for IIS7 web server: <system.webServer> <validation validateIntegratedModeConfiguration="false" /> <modules runAllManagedModulesForAllRequests="true"> <remove name="ScriptModule" /> <remove name="UrlRoutingModule" /> <add name="ScriptModule" preCondition="managedHandler" type="System.Web.Handlers.ScriptModule,..." /> <add name="UrlRoutingModule" type="System.Web.Routing.UrlRoutingModule,..." /> </modules> <handlers> ... </handlers> </system.webServer> When I add my own module I also set its preCondition="managedHandler", but since there's runAllManagedModulesForAllRequests="true" on parent <module> element my preCondition is ignored by design (as I read on MSDN). When I try to set though: <modules runAllManagedModulesForAllRequests="false"> I get this error: [image no longer valid] What else (which other module) do I have to set in web.config to make it work with this setting: <modules runAllManagedModulesForAllRequests="false">

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  • Adding a JLabel to JLayeredPane from event listener not dragging.

    - by Cody
    Ok, So for some reason When I add components to a JLayeredPane in its constructor: JLabel label = new JLabel(); label.setSize(100,100); label.setText("This works"); add(label); It works perfectly fine, but If a add it later in the JLayeredPane's parent EDT it doesnt let me move the objects around but they let me see the objects. Adding from EDT: JLabel label = new JLabel(); label.setToolTipText(url.getHost()); label.setIcon(icon); label.setBorder(new LineBorder(null)); label.setSize(icon.getIconWidth(), icon.getIconHeight()); dressFrame.layeredPane.add(label, JLayeredPane.DRAG_LAYER); Dragging method: Component c = findComponentAt(e.getX(), e.getY()); if (c instanceof JLayeredPane) { pieceSelected = false; return; } Point parentLocation = c.getLocation(); xAdjustment = parentLocation.x - e.getX(); yAdjustment = parentLocation.y - e.getY(); movingPiece = c; movingPiece.setLocation(e.getX() + xAdjustment, e.getY() + yAdjustment); pieceSelected = true;

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  • How to route tree-structured URLs with ASP.NET Routing?

    - by Venemo
    Hello Everyone, I would like to achieve something very similar to this question, with some enhancements. There is an ASP.NET MVC web application. I have a tree of entities. For example, a Page class which has a property called Children, which is of type IList<Page>. (An instance of the Page class corresponds to a row in a database.) I would like to assign a unique URL to every Page in the database. I handle Page objects with a Controller called PageController. Example URLs: http://mysite.com/Page1/ http://mysite.com/Page1/SubPage/ http://mysite.com/Page/ChildPage/GrandChildPage/ You get the picture. So, I'd like every single Page object to have its own URL that is equal to its parent's URL plus its own name. In addition to that, I also would like the ability to map a single Page to the / (root) URL. I would like to apply these rules: If a URL can be handled with any other route, or a file exists in the filesystem in the specified URL, let the default URL mapping happen If a URL can be handled by the virtual path provider, let that handle it If there is no other, map the other URLs to the PageController class I also found this question, and also this one and this one, but they weren't of much help, since they don't provide an explanation about my first two points. I see the following possible soutions: Map a route for each page invidually. This requires me to go over the entire tree when the application starts, and adding an exact match route to the end of the route table. I could add a route with {*path} and write a custom IRouteHandler that handles it, but I can't see how could I deal with the first two rules then, since this handler would get to handle everything. So far, the first solution seems to be the right one, because it is also the simplest. I would really appreciate your thoughts on this. Thank you in advance!

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  • jQuery Validation error...

    - by Povylas
    Hi, I have been struggling with this jQuery Validation Plugin. Here is the code: <script type="text/javascript"> $(function() { var validator = $('#signup').validate({ errorElement: 'span', rules: { username: { required: true, minlenght: 6 //remote: "check-username.php" }, password: { required: true, minlength: 5 }, confirm_password: { required: true, minlength: 5, equalTo: "#password" }, email: { required: true, email: true }, agree: "required" }, messages: { username: { required: "Please enter a username", minlength: "Your username must consist of at least 6 characters" //remote: "Somenoe have already chosen nick like this." }, password: { required: "Please provide a password", minlength: "Your password must be at least 5 characters long" }, confirm_password: { required: "Please provide a password", minlength: "Your password must be at least 5 characters long", equalTo: "Please enter the same password as above" }, email: "Please enter a valid email address", agree: "Please accept our policy" } }); var root = $("#wizard").scrollable({size: 1, clickable: false}); // some variables that we need var api = root.scrollable(); $("#data").click(function() { validator.form(); }); // validation logic is done inside the onBeforeSeek callback api.onBeforeSeek(function(event, i) { if($("#signup").valid() == false){ return false; }else{ return true; } $("#status li").removeClass("active").eq(i).addClass("active"); }); //if tab is pressed on the next button seek to next page root.find("button.next").keydown(function(e) { if (e.keyCode == 9) { // seeks to next tab by executing our validation routine api.next(); e.preventDefault(); } }); $('button.fin').click(function(){ parent.$.fn.fancybox.close() }); }); </script> And here is the error: $.validator.methods[method] is undefined http://www.vvv.vhost.lt/js/jquery-validate/jquery.validate.min.js Line 15 I am completely confused... Maybe some kind of handler is needed? I would be grateful for any kind of answer.

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  • Render action return View(); form problem

    - by Roger Rogers
    I'm new to MVC, so please bear with me. :-) I've got a strongly typed "Story" View. This View (story) can have Comments. I've created two Views (not partials) for my Comments controller "ListStoryComments" and "CreateStoryComment", which do what their names imply. These Views are included in the Story View using RenderAction, e.g.: <!-- List comments --> <h2>All Comments</h2> <% Html.RenderAction("ListStoryComments", "Comments", new { id = Model.Story.Id }); %> <!-- Create new comment --> <% Html.RenderAction("CreateStoryComment", "Comments", new { id = Model.Story.Id }); %> (I pass in the Story id in order to list related comments). All works as I hoped, except, when I post a new comment using the form, it returns the current (parent) View, but the Comments form field is still showing the last content I typed in and the ListStoryComments View isn’t updated to show the new story. Basically, the page is being loaded from cache, as if I had pressed the browser’s back button. If I press f5 it will try to repost the form. If I reload the page manually (reenter the URL in the browser's address bar), and then press f5, I will see my new content and the empty form field, which is my desired result. For completeness, my CreateStoryComment action looks like this: [HttpPost] public ActionResult CreateStoryComment([Bind(Exclude = "Id, Timestamp, ByUserId, ForUserId")]Comment commentToCreate) { try { commentToCreate.ByUserId = userGuid; commentToCreate.ForUserId = userGuid; commentToCreate.StoryId = 2; // hard-coded for testing _repository.CreateComment(commentToCreate); return View(); } catch { return View(); } }

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  • ASP.NET MVC PartialView generic ModelView

    - by Greg Ogle
    I have an ASP.NET MVC application which I want to dynamically pick the partial view and what data gets passed to it, while maintaining strong types. So, in the main form, I want a class that has a view model that contains a generically typed property which should contain the data for the partial view's view model. public class MainViewModel<T> { public T PartialViewsViewModel { get; set; } } In the User Control, I would like something like: Inherits="System.Web.Mvc.ViewUserControl<MainViewModel<ParticularViewModel>>" %> Though in my parent form, I must put Inherits="System.Web.Mvc.ViewPage<MainViewModel<ParticularViewModel>>" %> for it to work. Is there a way to work around this? The use case is to make the user control pluggable. I understand that I could inherit a base class, but that would put me back to having something like a dictionary instead of a typed view model.

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  • What is Ruby's analog to Python Metaclasses?

    - by Sean Copenhaver
    Python has the idea of metaclasses that, if I understand correctly, allow you to modify an object of a class at the moment of construction. You are not modifying the class, but instead the object that is to be created then initialized. Python (at least as of 3.0 I believe) also has the idea of class decorators. Again if I understand correctly, class decorators allow the modifying of the class definition at the moment it is being declared. Now I believe there is an equivalent feature or features to the class decorator in Ruby, but I'm currently unaware of something equivalent to metaclasses. I'm sure you can easily pump any Ruby object through some functions and do what you will to it, but is there a feature in the language that sets that up like metaclasses do? So again, Does Ruby have something similar to Python's metaclasses? Edit I was off on the metaclasses for Python. A metaclass and a class decorator do very similar things it appears. They both modify the class when it is defined but in different manners. Hopefully a Python guru will come in and explain better on these features in Python. But a class or the parent of a class can implement a __new__(cls[,..]) function that does customize the construction of the object before it is initialized with __init__(self[,..]).

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  • Centering a div block without the width

    - by Vinicius
    Hi, I have a problem when I try to center the div block "products" because I don't know in advance the div width. Anybody have a solution? Update: The problem I have is I don't know how many products I'll display, I can have 1, 2 or 3 products, I can center them if it was a fixed number as I'd know the width of the parent div, I just don't know how to do it when the content is dynamic. <style> .product_container { text-align: center; height: 150px; } .products { height: 140px; text-align: center; margin: 0 auto; clear: ccc both; } .price { margin: 6px 2px; width: 137px; color: #666; font-size: 14pt; font-style: normal; border: 1px solid #CCC; background-color: #EFEFEF; } </style> <div class="product_container"> <div class="products" id="products"> <div id="product_15"> <img src="/images/ecommerce/card_default.png"> <div class="price">R$ 0,01</div> </div> <div id="product_15"> <img src="/images/ecommerce/card_default.png"> <div class="price">R$ 0,01</div> </div> <div id="product_15"> <img src="/images/ecommerce/card_default.png"> <div class="price">R$ 0,01</div> </div> </div> </div>

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  • how to write css for nth child in css

    - by steven spielberg
    <div id="boxcontent"> <div>some content this div may be missing [dynamic genrated]</div> <div class="elem"></div> <div class="elem"></div> <div class="elem"></div> </div> <div id="boxcontent"> <div class="elem"></div> <div class="elem"></div> <div class="elem"></div> </div> <div id="boxcontent"> <div class="elem"></div> <div class="elem"></div> <div class="elem"></div> </div> i want to write some css on every 3rd div who have class .elem if i try nth-child to select them then sometime they select other. How i can select 3rd .elem class div when parent div have some other div as child or not. any way to select 3rd div who have class .elem

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  • Toggle Blind Effect

    - by flipflopmedia
    Is there a way to alter this script to be used as the blind effect. // Andy Langton's show/hide/mini-accordion - updated 23/11/2009 // Latest version @ http://andylangton.co.uk/jquery-show-hide // this tells jquery to run the function below once the DOM is ready $(document).ready(function() { // choose text for the show/hide link - can contain HTML (e.g. an image) var showText=''; var hideText=''; // initialise the visibility check var is_visible = false; // append show/hide links to the element directly preceding the element with a class of "toggle" $('.toggle').prev().append(' '+showText+''); // hide all of the elements with a class of 'toggle' $('.toggle').hide(); // capture clicks on the toggle links $('a.toggleLink').click(function() { // switch visibility is_visible = !is_visible; // toggle the display - uncomment the next line for a basic "accordion" style //$('.toggle').hide();$('a.toggleLink').html(showText); $(this).parent().next('.toggle').toggle('slow'); // return false so any link destination is not followed return false; }); }); FYI- Where it says: var showText=''; var hideText=''; It was originally: var showText='Show'; var hideText='Hide'; I deleted the Show/Hide Text because I am applying the link to different areas of text. I like the Blind effect, vs. this Toggle effect, and need to know how to apply it, if possible. I cannot find a basic Blind effect script that allows the use of applying the link to ANY text, vs. a button or static text. Thanks! Hope you can help! Tracy

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  • youtube embeded player: change video link with javascript, dinamically

    - by Anthony Koval'
    here is a part of html code (video urls marked with a django-template language variables): <div class="mainPlayer"> <object width="580" height="326"> <param name="movie" value="{{main_video.video_url}}"></param> <param name="allowFullScreen" value="true"></param> <param name="allowscriptaccess" value="always"></param> <embed src="{{main_video.video_url}}" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="580" height="326"></embed> </object> </div> and JS-code (using jQuery 1.4.x) $(document).ready(function(){ ..... $(".activeMovie img").live("click", function(){ video_url = ($(this).parent().find('input').val()); $('.mainPlayer').find('param:eq(0)').val(video_url); $('.mainPlayer').find('embed').attr('src', video_url); }) ... }) such a algorithm works fine in ff 3.6.3, but any luck in chrome4 or opera 10.x., src and value are changed, but youtube player still shows an old video.

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  • Display a input type=file over another input type=file

    - by Kevin Sedgley
    WARNING: Lengthy description coming up! I have written an uploader based upon APC progress uploader for PHP. This works fine and dandy, but the script as a whole (apc etc) is intended to be used only for those with Javascript. To achieve this, I have searched for any input type=file, and replaced these with an absolutely positioned form that appears over the original area where the old file input area was. The reasons for this are so the new uploader can submit to a hidden in page IFrame has to be in a seperate <form> in order to submit to the APC reciever to display the progress upload bar. allows it to be used within any form with an input type=file throughout the site I have used JQuery to do this, with the following code: Original HTML form code: <div><input type="file" name="media" id="media" /></div> Find position of div block code: // get the parent div, and properties thereof parentDiv = $(this).closest('div'); w = $(parentDiv).width(); h = $(parentDiv).height(); loc = $(parentDiv).offset(); Locate new block over old block: $('#_sender').appendTo('body').css({left:loc.left,top:loc.top,position:'absolute',zIndex:400,height:h,width:w}).show(); This works fine, and shows over the old block OK. The problem: When other elements in the DOM before or above it change (in this case a "tree view" selector is pushing the old block down) the new upload form gets moved over other elements. Is there a JQuery (or JS) method for changing this upon DOM change? Some kind of .onchange for the page?! Or an .onmove for the original block? Thanks in advance you lovely people Before DOM change: . After: .

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  • jquery .submit live click runs more than once

    - by fxuser
    I use the following code to run my form ajax requests but when i use the live selector on a button i can see the ajax response fire 1 time, then if i re-try it 2 times, 3 times, 4 times and so on... I use .live because i also have a feature to add a post and that appears instantly so the user can remove it without refreshing the page... Then this leads to the above problem... using .click could solve this but it's not the ideal solution i'm looking for... jQuery.fn.postAjax = function(success_callback, show_confirm) { this.submit(function(e) { e.preventDefault(); if (show_confirm == true) { if (confirm('Are you sure you want to delete this item? You can\'t undo this.')) { $.post(this.action, $(this).serialize(), $.proxy(success_callback, this)); } } else { $.post(this.action, $(this).serialize(), $.proxy(success_callback, this)); } return false; }) return this; }; $(document).ready(function() { $(".delete_button").live('click', function() { $(this).parent().postAjax(function(data) { if (data.error == true) { } else { } }, true); }); });? EDIT: temporary solution is to change this.submit(function(e) { to this.unbind('submit').bind('submit',function(e) { the problem is how can i protect it for real because people who know how to use Firebug or the same tool on other browsers can easily alter my Javascript code and re-create the problem

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  • Disabling normal link behaviour on click with an if statement in Jquery?

    - by Qwibble
    I've been banging my head with this all day, trying anything and everything I can think of to no gain. I'm no Jquery guru, so am hoping someone here can help me out. What I'm trying to do in pseudo code (concept) seems practical and easy to implement, but obviously not so =D What I have is a navigation sidebar, with sub menu's within some li's, and a link at the head of each li. When a top level link is clicked, I want the jquery to check if the link has a sibling ul. If it does, the link doesn't act like a link, but slides down the sibling sub nav. If there isn't one, the link should act normally. Here's where I'm at currently, what am I doing wrong? $('ul.navigation li a').not('ul.navigation li ul li a').click(function (){ if($(this).parent().contains('ul')){ $('ul.navigation li ul').slideUp(); $(this).siblings('ul').slideDown(); return false; } else{ alert('Link Clicked') // Maybe do some more stuff in here... } }); Any ideas?

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  • Cakephp ACL authentication issue - I'm locked out

    - by Baseer
    I've followed the CakePHP Cookbook ACL tutorial And as of right now I'm just trying to add users using the scaffolding method. I'm trying to go to /users/add but it always redirects me to the login screen even though I have added $this->Auth->allow('*'); in beforeFilter() temporarily to allow access to all pages. I've done this in both the UsersController and GroupsController as the tutorial asked. Below is my code for UsersController which I think will be the most relevant of all the files. Let me know if any other piece of code is required. <?php class UsersController extends AppController { var $name = 'Users'; var $scaffold; function beforeFilter() { parent::beforeFilter(); $this->Auth->allow('*'); } function login() { //Auth Magic } function logout() { //Leave empty for now. } } ?> I think I've pretty much followed the tutorial, any ideas as to what I may be missing? Thanks. I've been stuck on this for a while. =(

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  • Jquery/YUI - Find image and set CSS to display:none

    - by danit
    I have the following image in a CMS that I want to hide, I dont really want to change source code but would like to hide a specific image which does not have a class applied. Here is the HTML: <td class="right side"> <a title="Show only topic 1" href="view.php?id=3&topic=1"> <img alt="Show only topic 1" src="http://vl3.co.uk/iphone/pix/i/one.gif"/> </a> <br/> </td> I want to hide the <a> and the <img>, bare in mind the title and alt tag can be different so cant use that as an identifier. I presume I could use .find() and then use .parent() to set the <a> to display: none; thus hiding the img? Im inlcuding the jQuery library, however the CMS has YUI included out of the box so if anyone has a YUI method it would be appreicated.

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  • Split large repo into multiple subrepos and preserve history (Mercurial)

    - by Andrew
    We have a large base of code that contains several shared projects, solution files, etc in one directory in SVN. We're migrating to Mercurial. I would like to take this opportunity to reorganize our code into several repositories to make cloning for branching have less overhead. I've already successfully converted our repo from SVN to Mercurial while preserving history. My question: how do I break all the different projects into separate repositories while preserving their history? Here is an example of what our single repository (OurPlatform) currently looks like: /OurPlatform ---- Core ---- Core.Tests ---- Database ---- Database.Tests ---- CMS ---- CMS.Tests ---- Product1.Domain ---- Product1.Stresstester ---- Product1.Web ---- Product1.Web.Tests ---- Product2.Domain ---- Product2.Stresstester ---- Product2.Web ---- Product2.Web.Tests ==== Product1.sln ==== Product2.sln All of those are folders containing VS Projects except for the solution files. Product1.sln and Product2.sln both reference all of the other projects. Ideally, I'd like to take each of those folders, and turn them into separate Hg repos, and also add new repos for each project (they would act as parent repos). Then, If someone was going to work on Product1, they would clone the Product1 repo, which contained Product1.sln and subrepo references to ReferenceAssemblies, Core, Core.Tests, Database, Database.Tests, CMS, and CMS.Tests. So, it's easy to do this by just hg init'ing in the project directories. But can it be done while preserving history? Or is there a better way to arrange this?

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  • Use of clone() and appendTo() with draggable - unexpected results with dragging

    - by Matt Gutting
    I'm constructing a UI for a doctor scheduling app. We have several doctors, each of whom can go in one of several locations on a scheduled day (M - F). I have the main day/location grid (table) in the center of the screen. At the left is a table for the doctor names. On loading, each table cell contains a span (outlined) with the doctor name. The doctor name can go in one slot for each day. I didn't want to just put 5 copies of the doctor name, because the doctor might not be available all 5 days of the week. The idea was: Drag the span and drop into the calendar table. On the drag "start" event, clone the span and append it to the table cell. Now there is another span ready to be dropped into the calendar table. One line of code does the work: $(ui.helper).clone(true).prependTo(ui.helper.parent()); This works. But when I move the cloned span, the original one moves in sync - preserving the spatial relationships as I move the clone around (no doubt there's a "position:relative;left=XX;top=YY" inserted somewhere). I'm sure there's a way to do what I'm thinking of, while keeping the two spans independent. But I'm not thinking of one. Does anyone have an idea? Thanks! Matt I posted this identical question to the jQuery forum as well.

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